What mass of iron (III) oxide


is produced when


3. 88 X 1025 molecules of oxygen


reacts with excess iron?


4Fe + 3O2 → 2Fe2O3

Answer:

32.0 is the answer which is divide able to 65 or -85

The molecule O=C=S is linear and has a Lewis structure analogous to that of CO2. This molecule is polar molecule.

What are polar molecules?

Polar molecules are molecules that have two oppositely charged ends. Polar molecules exist as a result of differences in the electronegativities of the atoms of the elements found in the molecule.

With two electron domains around the central atom .the electron domain & molecular geometries are linear .sinces oxygen is more electronegative than sulphur.

The bond dipole symmetrically distributed around the carbon atom , are not identical and therefore,the bond dipole do not sum to zero.

Therefore, OCS molecule is a polar molecule not a non polar.

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Protein, nucleic acid, and polysaccharide molecules will polymerize by the condensation reactions.

condensation reaction, are the reactions in which two molecules will combine, usually in the presence of a catalyst, with the elimination of water or some other simple molecules. The combination of the two identical molecules is called as self-condensation. Aldehydes, ketones, esters, alkynes (acetylenes), as well as amines are the several organic compounds that will combine with each other and, except for amines, among themselves to form a larger molecules, many of which are useful intermediate compounds in an organic synthesis. Catalysts commonly used in condensation reactions include acids, bases, the cyanide ion, as well as the complex metal ions.

The shapes of the most biological macromolecules are held in a place largely by the strong covalent bonds that will form between the different parts of the molecule.

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Answer:

Relative volume of ether to water that should be used for the extraction = 1.205

Explanation:

The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).

K = (C₁/C₂)

Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).

If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.

Let the volume of ether required be x mL.

Let the volume of water required be y mL.

Relative volume of ether to water that should be used for the extraction = (x/y)

Mass concentration of the organic substance X in ether = (0.94/x)

Mass concentration of organic substance X in water = (0.06/y)

The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.

13 = (0.94/x) ÷ (0.06/y)

13 = (0.94/x) × (y/0.06)

13 = (15.667y/x)

(x/y) = (15.667/13) = 1.205

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Answer:

The correct option is;

D. All the elements in families 1 and 2 can place all their shell electrons in the s sub-level

Explanation:

The elements in families 1 and 2 also called the group 1A and group 2A elements are known as the alkali and alkaline earth metals. The elements in the families 1 and 2 are also referred to as the s-block elements as they have their valence electrons which are 1 and 2 respectively, in the s-orbital or s sub-level

Due to their low ionization energy, and the ease with which they donate their valence electrons, elements of the families 1 and 2 are known to be very reactive, and are found in a combined state in nature.

Glyceraldehyde-3-phosphate (GAP) and dihydroxyacetone phosphate (DHAP) are two isomers of the glycolytic intermediate in cells. The ratio of GAP to DHAP is 1:1 at equilibrium conditions, but it varies significantly under nonequilibrium conditions, such as in the presence of enzymes.

Under such conditions, the GAP to DHAP dihydroxyacetone phosphate ratio can vary between 3:1 and 20:1.The two molecules, GAP and DHAP, interconvert rapidly, and thus, they exist in a rapid equilibrium in cells. In cells, DHAP is an intermediate in glycolysis, and it is converted to GAP by the enzyme triose phosphate isomerase (TPI). The interconversion of GAP to DHAP by TPI is a reversible reaction and is known to be near-equilibrium. However, in glycolysis, the DHAP is typically rapidly utilized by an enzyme called aldolase, such that the DHAP concentration remains low relative to the GAP concentration, which accumulates. Therefore, the ratio of [GAP]:[DHAP] is typically greater than 1:1 under nonequilibrium conditions.Glyceraldehyde-3-phosphate (GAP) and dihydroxyacetone phosphate (DHAP) are two isomers of the glycolytic intermediate in cells. The ratio of GAP to DHAP is 1:1 at equilibrium conditions, but it varies significantly under nonequilibrium conditions, such as in the presence of enzymes. Under such conditions, the GAP to DHAP ratio can vary between 3:1 and 20:1.The two molecules, GAP and DHAP, interconvert rapidly, and thus, they exist in a rapid equilibrium in cells. In cells, DHAP is an intermediate in glycolysis, and it is converted to GAP by the enzyme triose phosphate isomerase (TPI). The interconversion of GAP to DHAP by TPI is a reversible reaction and is known to be near-equilibrium. However, in glycolysis, the DHAP is typically rapidly utilized by an enzyme called aldolase, such that the DHAP concentration remains low relative to the GAP concentration, which accumulates. Therefore, the ratio of [GAP]:[DHAP] is typically greater than 1:1 under nonequilibrium conditions.

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complete question: What is the ratio of glyceraldehyde-3-phosphate (GAP) to dihydroxyacetone phosphate (DHAP) in cells at 37 ∘ C under nonequilibrium conditions? [GAP]:[DHAP]= __:1

Answer:

Pulling back on the plunger allows you to put in more air into the pump and the more air you have inside a fixed volume, the greater the pressure becomes. (D)

Answer:

The mass of water is expressed in grams (g) or kilograms (kg), and the volume is measured in liters (L), cubic centimeters (cm3), or milliliters (mL). Density is calculated by the dividing the mass by the volume, so that density is measured as units of mass/volume, often g/mL.

This increased energy causes the molecules to move more rapidly, which in turn increases the volume of the substance. As the volume of the substance increases, its density decreases because the same amount of matter is spread out over a larger volume.

The density decreases as the temperature increases because the molecules lose energy and slow down, so the same number of molecules occupy less space. This happens because the increase in temperature causes the molecules to move more rapidly, increasing the space between them. The density of a substance is defined as its mass per unit volume. The density of a substance depends on its temperature, as well as its pressure and composition. As the temperature of a substance increases, the kinetic energy of its molecules also increases. This increased energy causes the molecules to move more rapidly, which in turn increases the volume of the substance. As the volume of the substance increases, its density decreases because the same amount of matter is spread out over a larger volume.

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Glucose is polar and carbon tetrachloride is non polar so  it is the incorrect pair.

Water (H₂O) is the most appropriate solvent to dissolve sodium chloride (ionic). This is because sodium chloride is an ionic compound and water is a polar solvent, which means it can dissolve ionic compounds.

Acetone, methanol, ethanol, hexane, diethyl ether, toluene, and carbon tetrachloride are all non-polar solvents and are not suitable for dissolving ionic compounds like sodium chloride.

In fact, some of these solvents, like hexane and toluene, are not even soluble in water. So, to dissolve sodium chloride, it is recommended to use water as a solvent.

However, it's important to note that the solubility of sodium chloride in water decreases as the temperature decreases. At room temperature, approximately 36 grams of sodium chloride can be dissolved in 100 mL of water.

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Answer:

38 g?

Explanation:

I'm not entirely sure, but perhaps it is 49 grams x 78.25%? This gives you an answer of 38 g using significant figures.

the solute is dissolved in the solvent.

the solvent is able to dissolve other substances.

a solution is a special type of homogeneous mixture composed of two or more substances, meaning that its composition is identical in every sample.

hope i helped, good luck!

O2- Option B is correct

Explanations:

Calcium atom is a group 2 elements that gives out two electrons in order to form a stable configuration and a Ca2+ ion. These two electrons are transferred to an atom that required two electrons to complete its outer shell.

Since oxygen required 2 electron to attain its octet configuration, hence they can easily accepts the two electrons from calcium atoms to form CaO which is composed of Ca2+ and O2- ions in the ratio of one Ca2+ ion to one O2− ions.

Answer:

The capillary tube was too close to the bottom of the beaker.

The ruler may have moved.

Water got into the capillary tube.

The temperature was not allowed to equilibrate in the 2-4 minutes.

Explanation:

Answer:

Explanation:Silver nitrate, AgNO3 , will react with sodium sulfate, Na2SO4 , to produce silver sulfate, Ag2SO4 , an ionic compound that is considered insoluble in aqueous solution, and aqueous sodium nitrate.

Answer:

B) combustion as fuels

Explanation:

This combustion fuel is called natural gas which contains both methane and ethane

\(.\)

Answer:

Combustion as Fuels

Explanation:

In organic chemistry, an alkane, or paraffin, is an acyclic saturated hydrocarbon. In other words, an alkane consists of hydrogen and carbon atoms

The radius of the cylindrical can is \(\sqrt{699.682/h}\)

A cylinder's radius is equal to the distance from the cylinder's center to its edge, which are located at its top and bottom.

A three-dimensional object known as a cylinder is a hollow rod with rounded ends. This circular base's diameter can change, and the radius is equal to half of that value.

A cylinder's radius (r) is equal to \(\sqrt{V/\pi h}\), where V denotes the cylinder's volume, h its height, and π (Pi) is a mathematical constant having a value of around 3.14.

Given:

Volume = 2197\(cm^3\)

Formula:

Volume, V = π x radius, \(r^2\) x height, h

Calculations:

\(r^2\) = 2197 / 3.14 x h

\(r^2\) = 699.682 / h

Radius, r = \(\sqrt{699.682/h}\)

Result:

\(\sqrt{699.682/h}\) is found to be the radius of the cylindrical can.

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n=2 to n=5

An atom of the chemical element hydrogen is known as a hydrogen atom.

An atom of the chemical element hydrogen is known as a hydrogen atom. The Coulomb force holds a single positively charged proton and a single negatively charged electron to the nucleus of the electrically neutral atom. About 75% of the universe's total baryonic mass is made up of atomic hydrogen.

A hydrogen atom is an atom belonging to the chemical element hydrogen. There are two other hydrogen isotopes, deuterium and tritium, in addition to protium, which is the most prevalent form of the atom.

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Answer:

a. zinc because it is on top of them all in the reactive series so it reacts faster .

b. Ag because it is on the bottom of the reactive series and its reacts slow

If the rate of appearance of NO₂ is 0.560 mol/min at a particular moment, then the rate of appearance of O₂ at that moment is 0.070 mol/min.

The chemical equation for the decomposition of dinitrogen pentoxide is 2 N₂O₅(g) → 4 NO₂(g) + O₂(g).

From this equation, we can see that for every 2 moles of N₂O₅ that decompose, 1 mole of O₂ is produced.

If the rate of appearance of NO₂ is 0.560 mol/min at a particular moment, then we know that the rate of disappearance of

N₂O₅ is 0.560/4 = 0.140 mol/min (since 4 moles of NO₂ are produced for every 2 moles of N₂O₅ that decompose).

Therefore, at that particular moment, the rate of appearance of O₂ is equal to half the rate of disappearance of N₂O₅, which is 0.140/2 = 0.070 mol/min.

This is because the stoichiometry of the reaction tells us that for every 2 moles of N₂O₅ that decompose, 1 mole of O₂ is produced. So, the rate of appearance of O₂ is half the rate of disappearance of N₂O₅.

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If Jake have type 1 diabetes then he needs insulin cells because his body cannot make insulin protein.

What is diabetes?

Diabetes is a chronic, metabolic disease characterized by elevated levels of blood glucose (or blood sugar), which leads over time to serious damage to the heart, blood vessels, eyes, kidneys and nerves.

The most common diabetes symptoms experienced by many people with diabetes are increased thirst, increased urination, feeling tired and losing weight. In Type 1 diabetes, body cannot make insulin whereas in type 2 diabetes, body can make insulin but can't use it properly.

Therefore, if Jake have type 1 diabetes then he needs insulin cells because his body cannot make insulin protein.

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The time it takes to heat this water in a 1-kg steel pan sitting on a 1,500-W electric stove burner that transfers 75% of its energy output to the water and the pan is 90 seconds (rounded to the nearest whole second).

We need to calculate the time taken to heat the water in a 1-kg steel pan sitting on a 1,500-W electric stove burner that transfers 75% of its energy output to the water and the pan. The given information are as follows:

Specific heat of water, cw = 4184 J/kg °C

Specific heat of steel, cs = 450 J/kg °C

Energy supplied by the electric stove burner, P = 1,500 W (75% of which is transferred to the water and the pan)

Mass of water, mw = 250 g = 0.25 kg

Mass of steel pan, ms = 1 kg

Initial temperature of water and steel pan, T1 = 10 °C

Final temperature of water and steel pan (boiling point of water), T2 = 100 °C

Heat absorbed by the steel pan = Qs = ms × cs × (T2 - T1)Heat absorbed by the water = Qw = mw × cw × (T2 - T1)

Total heat absorbed by the water and the pan = Q = Qw + Qs = (0.25 × 4184 × 90) + (1 × 450 × 90) J= 94,140 + 40,500 J= 1,34,640 J

Time taken to heat the water and the pan = t = Q/P= 1,34,640 / 1,500 s= 89.76 or 90 s

Therefore, the time it takes to heat this water in a 1-kg steel pan sitting on a 1,500-W electric stove burner that transfers 75% of its energy output to the water and the pan is 90 seconds (rounded to the nearest whole second).

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TRUE - Asking for and receiving a paper that someone who is in another lab section wrote is an honor violation.

FALSE - An oral discussion with a classmate regarding a paper's topics and format is cheating.

FALSE - Purchasing papers from tutoring companies is allowed. False

TRUE - Sending a paper that you wrote to a student who is currently in another section is an honor violation.

TRUE - Misconduct in research or scholarship includes fabrication, falsification, or plagiarism in proposing, performing, reviewing, or reporting research. It does not include honest error or honest differences in interpretations or judgements of data.

TRUE - Discussing an exam or laboratory practical with anyone prior to the conclusion of the week that final exams and laboratory practicals are given would be considered an honor violation.

The Texas A&M University has an academic integrity statement known as the "Aggie code of honor." It outlines the rules for ethical academic conduct and responsible research. All curricula must include this code, according to instructors. It prohibits misconducts like plagiarism, falsification, and cheating and focuses on the use of the highest level of integrity in academic research.

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Question correction:

Based upon the Aggie Honor System Rules and the Academic Integrity statement on the CHEM 111/112/117 syllabus, assess whether the statements are true or false.

Answer:

cell → tissue → organ → organ system → organism

Explanation:

Answer:

The correct answer is cell → tissue → organ → organ system → organism.

Explanation:

I know this because I am smart

Answer:

1.33 moles per second

Explanation:

From the balanced equation of reaction, 3 moles of H2(g) need to disappear/be consumed before 2 moles of NH3(g) can be formed/appear.

According to reaction law, the rate of disappearance of reactants is equal to the rate of appearance of products.

Now, only 2 moles per seconds of H2 has disappeared initially;

3 moles H2 is needed for 2 moles NH3

2 moles H2 will give;        2 x 2/3 = 4/3 or 1.33 moles

Hence, if the initial rate of disappearance of H2 is 2.0 moles per second, the initial rate of appearance of NH3 would be 1.33 moles per second.

From the equation, we can see that for every 1 mole of B2H6 reacted, 2 moles of H2O are produced. We can use this relationship to determine the amount of water produced from the given amount of B2H6.

The balanced chemical equation for the reaction is:

\(B_2H_6 + 3O_2 \rightarrow 2HBO_2 + 2H_2O\)

First, we need to calculate the number of moles of  \(B_2H_6\) Present in  \(10.0\)Grams. The molar mass of  \(B_2H_6\) is:

2 × atomic mass of B + 6 × atomic mass of H

\(= 2 × 10.81 + 6 × 1.01\)

\(= 27.64 g/mol\)

So, \(10.0 g\) of  \(B_2H_6\) is equivalent to:

\(n(B_2H_6) = m/M\)

\(= 10.0 g / 27.64 g/mol\)

\(= 0.362 mol\)

According to the balanced chemical equation, 1 mole of \(B_2H_6\) reacts to produce 2 moles of \(H_2O\) . So, the number of moles of water produced is:

\(n(H_2O) = 2 × n(B_2H_6)\)

\(= 2 × 0.362 mol\)

\(= 0.724 mol\)

Finally, we can calculate the mass of water produced using its molar mass:

\(m(H_2O) = n(H_2O) × M(H_2O)\)

\(= 0.724 mol × 18.02 g/mol\)

\(= 13.04 g\)

Therefore, if you start with  \(10.0 g\) of  \(B_2H_6\)and  \(10.0 g\) of  \(O_2\), you will produce \(13.04 g\) of water.

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Answer:

flammability, toxicity, acidity, reactivity, heat of combustion, chemical composition, structure

Explanation:

↦Give 8 properties of chemical compounds.

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#Artemis_Pearl^^

Answer: Its not popping up for me *-*?