Explanation:
ultraviolet radiation
Bombarded with energy
They stored the seeds in a single layer on the outside of the ISS behind a special kind of glass that let in ultraviolet radiation only at wavelengths between 110 and 400 nanometers
a 10.00mf parallel-plate capacitor is connected to a 24.0v battery. after the capacitor is fully charged ,the
battery is disconnected without loss of any of charge on the plates.
a) a voltmeter is connected across the two plates without discharging them.what does it read
b)what would the voltmeter read if the plate separationwere doubled?
The answer to the first part of the question is 24 V and the answer to the second part of the question is 48 V.
The formula which relates Charge, Capacitance and Voltage is
Charge = Capacitance × Voltage
Q = CV
where Q denotes the charge, C denotes the capacitance and V denote the voltage.
Using the above formula the charge on the capacitance will be
Q = CV
C = 10 mF
V = 24 V
Q = 240 mC
Charge on capacitance is 240 mC.
Now after we disconnect the battery
C = 10 mF (will remain same)
Q = 240 mC
V = Q/C
V = 240/10 V
V = 24 V
So after we removed the battery, The voltage will remain same.
Now we know that parallel plate capacitor formula is
C = ε(A/d)
from here
C ∝ 1/d, and as there is no loss of charge we can say that V ∝ 1/d
Form C ∝ 1/d and V ∝ 1/C we can state that
V ∝ d {where d is the measurement of separation between the plates}
so if we double the distance between the plates then, the voltage will also get double.
Previously our voltage was 24 V, now if we double the distance between the plates the voltage will also get double, and it will become 48 V.
So, the voltmeter will take a reading of 24 V if voltmeter is connected across the two plates without discharging them, and if we double the plate separation then it will take 48 V as reading.
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An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
A body is travelling with a velocity 30 m/s².what will be its velocity after 4s?
Answer:
70m/s²
Explanation:
we will use the first equation of Dalton to find it
A man stands by a railway track.
A train travelling at 40 m/s takes 2.0 s to pass the man.
What is the length of the train?
40 m
D
80m
A 20m
B 38 m
Answer:
length of train is 80m
Explanation:
40*2
5. A Car of mass 1000kg is driven from it's initial
state with uniform acceleration and reaches a
Speed of 30km/h in 10 second find
1 ). Force exerted by the engine.
2). the power in killo watts (kw)
If the law allows abortion based on sex, should we also allow abortion based on race, ethnicity, or skin color? Briefly explain why you believe this is right or wrong.
Answer:
No because you don't have to be black or white you don't have to be a pacific race to just get it like lets say for example a asian person come in and they want to get a abortion but the doctor say no then that person can end up killing her self or when the baby is born she could end you know doing something bad. But no you do not have to be a pacific person to just get it
Explanation:
John drove a truck for one hour at a rate of 80 kilometers per hour (km/hr). The next hour, he drove at 100 km/hr. What was his average speed during those two hours?
km/hr
Please i have asked a.question please help.me
Explanation:
Please i have asked a question in math please help me
A 1kg cannon ball.is fired horizontally with an initial velocity of 5m/s. If the cannon was atop a wall 20m above the ground, what is the total
change in KE?
Answer:
Ek = 196.2 [J]
Explanation:
The question concerns the KE kinetic energy.
That is, we must find the kinetic energy at the moment the cannon is fired and the kinetic energy of when the ball hits the ground after having fallen 20 meters.
At the moment when the ball is fired it is 20 meters above ground level. If the ground level is taken as the reference level of potential energy, where it is equal to zero, in this way when the ball is at the highest (20 meters) you have the maximum potential energy.
In this way, the energy in the initial state is equal to the sum of the kinetic energy plus the potential energy. As the energy is conserved this same energy will be present when the ball hits the ground, where the potential energy is zero and will have only kinetic energy.
\(E_{1}=E_{2}\\E_{k1}+E_{p1}=E_{k2}\\\frac{1}{2} *m*v^{2} +m*g*h=E_{k2}\\E_{k2}=0.5*1*(5)^{2} +1*9.81*20\\E_{k2}=208.7[J]\)
The kinetic energy in the initial state can be easily calculated by means of the following equation.
\(E_{k1}=\frac{1}{2} *m*v^{2}\\E_{k1}=0.5*1*(5)^{2}\\E_{k1}=12.5 [J]\)
Therefore the change in KE
\(E_{k} = 208.7 - 12.5\\E_{k} = 196.2 [J]\)
who is the first president of the United States
A. George Washington
B. Donald Trump
C.Joe Biden
Answer:
A. George Washington
Explanation:
The other two are the former and current presidents.
Hope this helps! :)
A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures
Explanation:
You want N/m
N = 66 * 9.81
m = 2.3 x 10^-2 m
66* 9.81 / 2.3 x 10^-2 = 28150 = 28 000 N/m to two S D
19
Sonya says her interest in reality competition shows is waning. What is the state of her interest in these shows?
A.
B.
C.
D.
it's in decline
it's growing
it's stable
it's nonexistent
Answer:
a. its in decline
Explanation:
waning means decreasing
car bumpers are designed to limit the extent of damage to the car in the case of low-velocity collisions. consider a 3600 lb passenger car impacting a concrete barrier while traveling at a speed of 4.0 mph. model the car as a particle, and consider two types of bumpers: (1) a simple linear spring with constant k and (2) a linear spring of constant k in parallel with a shock-absorbing unit generating a nearly constant force of 700 lb over 0.25 ft.
k = _____ x 10^4 lb/ft
k = 2.8 x 104 lb/ft. is a constant-length linear spring that is parallel to a 700 lb over force-generating shock absorber.
A velocities simple definition is what?The main determinant of an object's position and rate of motion is its velocity. It can be explained as the distance an object travels in one unit of time. The dispersion of the objects in a given amount of time is referred to as velocity. Vector sum (v) squared is equal to the sum of the beginning velocity (u) squared and the acceleration (a) times the displacement times two (s). In order to find v, we solve for v such that final velocity (v) = numerator of speed (u) divided plus two times accelerated (a) twice displacement (s).
To calculate kinetic energy of the car KE = (1/2)mv^2
to convert the mass of the car he velocity from mph to ft/s (1 mph = 1.47 ft/s), we get :KE = (1/2)(3600/32.2)(4.0 x 1.47)^2
KE = 13325 ft-lb, the potential energy will be calculated as PE = (1/2)kx^2
since the displacement of the spring is unknown, we can express it in terms of k and solve for k using the given information
we know that constant force of 700 lb is generated over a displacement of 0.25 ft.W = Fd
W = 700 lb x 0.25 ft
W = 175 ft-lb
e can equate the two expressions for potential energy and solve for k:
(1/2)kx^2 = 175
For the bumper with the shock-absorbing unit, the displacement x is 0.25 ft, so we get:
1/2)k(0.25)^2 = 175
k = 280000 Ib/ft
Therefore, the value of k for the simple linear spring is k = 2.8 x 10^4 lb/ft.
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9. If the mass of a 200 N object is cut in half, what would happen to its weight in Newtons?
Answer:
as we know that weight = mass ×gravity (earth's gravity 9.8m.s²)the weight will be also be cut in halfmass is directly proportional to the weightExplanation:
let's say our mass is 50 kgour gravity is 9.8m.s²therefore 50×9.8=490Nnow cut the mass in half therefore 25×9.8=245NA tank holds a 2.38-m thick layer of oil that floats on a 1.24-m thick layer of brine. Both liquids are clear and do not intermix. Point O is at the bottom of the tank, on a vertical axis. The indices of refraction of the oil and the brine are 1.27 and 1.81, respectively. A ray originating at O reaches the brine-oil interface at the critical angle. What is the distance of this point from the axis?
Answer:
1.22m
Explanation:
Since
sinθ = refraction-of-the-oil/refraction-of-the-brine =1.27/1.81 = 0.702
θ = \(sin^-^1\)(0.702)
Hence
Critical angle = θ = 44.58°
tan(θ) = d/1.24
tan(44.58°) = d/1.24
Hence, 0.98 = d/1.24
The distance d = 0.98 x 1.24 = 1.22m
if a 50.0 kg mass weighs 554 n on the planet saturn, calculate saturn's radius
Answer:
this is impossible unless im doing my math wrong sorry
Explanation:
Consider two blocks that are attached bv a string. Block 1 (mass of 2 ko) lavs on a flat dlane. Block ? (mass of 3 kg) hangs freely off the edge of the plane. In the absence of friction, Block 2 would fall and the string would pull Block 1 towards the edge. Find the static coefficient of friction needed to keep Block at its starting position.
With no friction, block 1 would be pulled to the edge of the table as block 2 falls. By Newton's second law, the net horizontal force on block 1 is
∑ F[1, h] = T = (2 kg) a
where T = magnitude of tension and a = acceleration of the blocks, while the net force on block 2 is
∑ F[2] = (3 kg) g - T = (3 kg) a
where (3 kg) g = weight of block 2 and g = 9.8 m/s². Notice that we take the downward fall of block 2 to be the positive direction.
Eliminate T and solve for a :
T + ((3 kg) g - T) = (2 kg) a + (3 kg) a
(3 kg) g = (5 kg) a
a = 3g/5
Solve for T :
T = (2 kg) (3g/5) = 6g/5 kg = 11.76 N
Now, taking friction into account, block 1 would have net force
∑ F[1, h] = T - sf = 0
so that the maximum magnitude of static friction is sf = 11.76 N. The net vertical force on block 1 is
∑ F[1, v] = n - (2 kg) g = 0
where n = magnitude of the normal force. Let µ be the coefficient of static friction. It follows that
n = (2 kg) g = 19.6 N
sf = µ n ⇒ µ = (11.76 N) / (19.6 N) = 0.6
. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
If you push twice as hard against a stationary brick wall, the amount of work you do A.Doubles B.is cut in halfC.remains constant but non - zeroD.remains constant at zero
work done remain constant at zero is correct statement If you push twice as hard against a stationary brick wall.
amount of work done = force*displacement
if u increase the force but there is no displacement , then amount of work done will remain zero
The definition of work done includes both the forces applied to the body and the total displacement of the body.
Positive Work: A force does positive work when it moves an object in that direction. The motion of a ball falling toward the earth, where the displacement of the ball is in the direction of the force of gravity, serves as an illustration of this type of work.
Negative Work: The work is thought to be negative when the force and displacement are in the opposite directions.
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A body of mass 80kg moving with a velocity of 6m/s hits a stationary body
of mass of 40kg. If the two bodies stick after the impact, calculate their
common velocity.
Answer:
4 m/s
Explanation:
Conservation of momentum , mv
Before collision 80 kg * 6 m/s = 480 kg-m/s
after the collision,
the momentum is the same but the mass is 80+40 kg =120 kg
mv = 480
120 * v = 480
v = 4 m/s
What order does energy flow: sun prodecer consumer?
Energy flows from the Sun to producers, then to primary consumers, secondary consumers, and potentially to tertiary consumers, forming a pyramid-shaped structure that represents the transfer of energy through different trophic levels in an ecosystem.
Energy flows in a specific order through various components of an ecosystem, starting with the Sun and progressing through producers and consumers. This flow of energy is known as the energy pyramid or trophic levels.
At the base of the energy pyramid is the Sun, which is the ultimate source of energy for most ecosystems on Earth. Sunlight provides the energy needed for photosynthesis, a process carried out by plants, algae, and some bacteria, collectively known as producers. These organisms convert solar energy into chemical energy through photosynthesis, using carbon dioxide and water to produce glucose and oxygen. This process captures and stores energy in the form of organic compounds.
The next level in the energy pyramid consists of primary consumers, also known as herbivores. These are animals that feed directly on producers, such as grazing animals or insects that consume plants. Herbivores obtain energy by consuming plant material and breaking down the organic compounds present in the plants into simpler forms, such as sugars and amino acids, through digestion.
Above the primary consumers are the secondary consumers, which are carnivores or omnivores that feed on herbivores. They obtain energy by consuming primary consumers and breaking down the organic compounds in their prey through digestion. This energy transfer continues up the trophic levels, with each level consuming the one below it.
At the top of the energy pyramid are tertiary consumers, which are typically apex predators. They are carnivores that consume other carnivores. Tertiary consumers obtain energy by consuming secondary consumers and breaking down the organic compounds in their prey.
It's important to note that energy is not efficiently transferred between trophic levels. Only a fraction of the energy consumed at each level is converted into biomass and passed on to the next level. This inefficiency is due to processes such as respiration, heat loss, and incomplete digestion.
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What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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A plane mirror is placed to the right of an object. The image formed by the mirror will be a
real image that appears to be on the right of the mirror.
real image that appears to be on the left of the mirror.
virtual image that appears to be on the right of the mirror.
virtual image that appears to be on the left of the mirror.
Hamish is studying what happens when he sends a sound wave through different mediums, and he records his data in a table.
A 2-column table with 4 rows titled Hamish's Waves. The first column labeled Wave has entries 1, 2, 3, 4. The second column labeled Information has entries liquid, solid, gas, liquid.
Which statement could made about the data collected in Hamish’s table?
Wave 1 will move the fastest.
Wave 2 will move the slowest.
Wave 3 will move the slowest.
Wave 4 will move the fastest.
What is common between transverse waves and longitudinal waves?
Both include an amplitude, crest, and rarefactions
Both move faster at higher temperatures
Both move slower through densely packed molecules
Both include a wavelength from compression to compression
An angle of refraction is the angle between the refracted ray and the
incident ray.
normal.
medium.
boundary.
Answer:
A plane mirror is placed to the right of an object. The image formed by the mirror will be a virtual image that appears to be on the left of the mirror.
Explanation:
a current of a 6 flows through a light bulb for 12 s, how many coulombs of charge pass through the light bulb during this time
A current of a 6 flows through a light bulb for 12 s. The total charge that passes through the light bulb during the given time is 72 coulombs.
To calculate the total charge that passes through the light bulb, we need to use the formula Q = I * t, where Q represents the charge in coulombs, I represents the current in amperes, and t represents the time in seconds.
Step 1: Identify the known values:
Current (I) = 6 amperes
Time (t) = 12 seconds
Step 2: Calculate the charge using the formula:
Q = I * t
Step 3: Substitute the known values into the formula:
Q = 6 amperes * 12 seconds
Q = 72 coulombs
Therefore, the total charge that passes through the light bulb during the given time is 72 coulombs.
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The human eye is very sensitive to light having a wavelength of 5.51 ✕ 10-7 m, which is in the green-yellow region of the visible electromagnetic spectrum. What is the frequency of this light?
Answer:
\(F = 5.44 * 10^{14}\ Hz\)
Explanation:
Given
\(Wavelength = 5.51 * 10^{-7}m\)
Required
Determine the Frequency (F)
Represent the wavelength with W
The relationship between W and F is:
\(F = \frac{c}{W}\)
Where
c = Speed of Light
\(c = 3 * 10^8 m/s\)
Substitute values for c and W
\(F = \frac{3 * 10^8}{5.51 * 10^{-7}}\)
\(F = \frac{3 * 10^{8+7}}{5.51}\)
\(F = 0.5444646098 * 10^{8+7}\)
\(F = 0.5444646098 * 10^{15}\)
\(F = 5.444646098 * 10^{14}\)
\(F = 5.44 * 10^{14}\ Hz\)
what happened in my room
Answer:
A GHOST CAME! Booooo!!!!!!Hah lol
A tsunami originatig near the Alaska coast had a wavelength of 470 miles and traveled 2300 miles in 5.3 h. Determine the wave’s (a) speed in miles/hour and in m/s, (b) frequency and (c) period (in seconds and in minutes).
Answer:
a) 433.96 miles/hr
193.98 m/s
b) 3899.3 Hz
c) 2.56 x 10^-4 \(s^{-1}\)
0.015 \(m^{-1}\)
Explanation:
wavelength of the tsunami = 470 miles
Distance traveled = 2300 miles
time taken to travel this distance = 5.3 h
a) wave's speed = distance/time
==> 2300/5.3 = 433.96 miles/hr
1 miles/hr = 0.447 m/s
433.96 miles/hr = 433.96 x 0.447 = 193.98 m/s
b) frequency of a wave f = speed/wavelength
for wavelength, 470 miles = 470 x 1609.34 = 756389.8 m
frequency = 756389.8/193.98 = 3899.3 Hz
c) Period T = 1/frequency
T = 1/3899.3 = 2.56 x 10^-4 \(s^{-1}\)
60 sec = 1 min
Period T in sec = 2.56 x 10^-4 x 60 = 0.015 \(m^{-1}\)
If an automobile with a velocity of 4.0 m/s accelerates at a rate of 4.0 m/s2
for 2.5 s, what is the final velocity?
Answer:
V=u+at
=4+4*2.5
=14m/s
Explanation:
Initial velocity =4m/s
acceleration =4m/(second) squared
time =2.5 seconds
v=u+at
v=4+4*2.5
v=14m/s
A rotating heavy wheel is used to store energy as kinetic energy. If it is designed to store 1.00 x 106 J of kinetic energy when rotating at 64 revolutions per second, find the moment of inertia (rotational inertia) of the wheel. (Hint: Start with the expression for rotational kinetic energy.)
We know, \(1\ rpm = \dfrac{2\pi}{60} \ rad/s\) .
\(64\ rpm\ is = \dfrac{2\pi}{60}\times 64\ rad/s\\\\= \dfrac{32\pi}{15}\ rad/s\)
We know, kinetic energy is given by :
\(K.E = \dfrac{I\omega^2}{2}\\\\I = \dfrac{2(K.E)}{\omega^2}\\\\I = \dfrac{2\times 10^6}{\dfrac{32}{15}\times \pi}\\\\I = 298415.52 \ kg \ m^2\)
Hence, this is the required solution.
Write two or three sentences to describe the conductivity of a conductor. Explain its conductivity in terms of the electrons in it.
The conductivity of a conductor refers to its ability to conduct electrical current.
A material that has high conductivity allows electrical charges to flow through it easily and with little resistance, while a material with low conductivity does not allow electrical charges to flow as easily and has more resistance.
The conductivity of a conductor is determined by the number of free electrons in the material, as well as how easily these electrons can move through the material.
In a conductor, the atoms are closely packed together and the electrons are not tightly bound to the atoms, allowing them to move freely through the material and carry an electrical charge. This facilitates the flow of electrical current through the material, resulting in high conductivity.
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