What kind of charging is occurring in the first part of the video (when the
towel and container are rubbed together)? *

Answer:

A valence number of 1 means that an alement will generally react to lose one electron to obtain a full outer shell.

Group two elements are assigned a valence number of 2. A valence number 2 means that a group two elements will generally react to lose two electrons to obtain a full outer shell.

Explanation:

Hope it helps

transverse : light

longitudinal : sound

transverse : up & down

longitudinal : left & right or side to side

transverse : perpendicular

longitudinal : parallel

transverse : up & down ocean wave

longitudinal : archer pulling back on a bowstring then letting go releasing the string

v = λf : speed of a wave is measured in meters per second (m/s), the wavelength is measured in meters (m), and the frequency is measured in hertz (Hz)

ANSWER:

A transverse wave has the displacement perpendicular (i.e., at right angles) to the direction of wave propagation. An example of a transverse wave is the wave on a string, where the displacement of the string is perpendicular to the direction in which the wave travels.

A longitudinal wave (also known as a compression wave or pressure wave) has the displacement parallel to the direction of wave propagation. An example of a longitudinal wave is sound waves, where the particles of the medium vibrate parallel to the direction of the wave as the wave travels through the medium.

chatgpt

Transverse waves:

The displacement of the wave is perpendicular to the direction of wave propagation.

Example: A wave on a string, where the string moves up and down while the wave moves left and right.

Simple analogy: Imagine shaking a jump rope up and down while holding it horizontally - the wave travels horizontally while the rope moves up and down.

Longitudinal waves:

The displacement of the wave is parallel to the direction of wave propagation.

Example: Sound waves, where air molecules move back and forth in the same direction as the wave.

Simple analogy: Imagine squeezing a slinky in a direction parallel to the slinky - the wave travels in that same direction while the slinky compresses and expands.

Formula used: There is no specific formula for describing the direction of wave displacement, as it depends on the type of wave. However, the speed of a wave can be calculated using the formula v = λf, where v is the speed of the wave, λ (lambda) is the wavelength, and f is the frequency.

Real-world example: Light waves are transverse waves, with the electric and magnetic fields perpendicular to the direction of propagation. This can be seen in polarization filters, which only allow light waves with a certain orientation of electric field to pass through.

Real-world example of longitudinal waves

An example of longitudinal waves in the real world is sound waves, which are pressure waves that propagate through a medium such as air, water, or solids. Sound waves are longitudinal waves because the vibrations of air molecules or particles in a medium are parallel to the direction of the wave's propagation. Examples of sound waves in daily life include the sound of a car engine, a musical instrument, or a person speaking.

ChatGPT atGPT

byjus

The sound wave moved at a speed of about 170.59 m/s.

Echoes. An echo is a sound that is reproduced when sound waves are reflected back. Sound waves can also reflect off smooth, hard surfaces, much to way a rubber ball does. The echo sounds the same as the original sound, despite the fact that the sound's direction changes.

Time for sound to reach the mountain and bounce back = 2 x 1.7 s = 3.4 s

The distance traveled by the sound wave is twice the distance between the hiker and the mountain, so:

Distance = (580 m x 2 x 290 m)

Using the formula:

Speed = Distance / Time

we get:

Speed = 580 m / 3.4 s = 170.59 m/s

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Opportunities for collaboration, enhancing the learning experience, own pace, within a defined timeline, and accommodating different learning styles and schedules. is the benefit of an open course in terms of completing a course sequentially

An open course typically offers learners an orderly way to complete a course sequentially by breaking down the course material into smaller modules or units.

An open course allows learners to access course materials and complete assignments in a structured, step-by-step manner.

An open course provides a clear path for learners to follow, making it easier to stay organized and on track.

An open course often includes interactive features and opportunities for collaboration, enhancing the learning experience.

An open course typically allows learners to work at their own pace, within a defined timeline, accommodating different learning styles and schedules.

An open course can be accessed from anywhere with an internet connection, allowing for greater flexibility and accessibility.
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Question

What is the benefit of an open course in terms of completing a course sequentially?

The theoretical resolution of a telescope is given by the Rayleigh criterion, which states that the minimum angle between two objects that can be resolved is proportional to the wavelength of light and inversely proportional to the diameter of the telescope. This means that a larger diameter telescope will be able to resolve smaller details in objects in the sky.

The Atacama Large Millimeter/submillimeter Array (ALMA) is a radio telescope array consisting of 66 individual antennas that can be arranged in different configurations, including a longest baseline of 16 km. Arecibo telescope, on the other hand, was a single-dish radio telescope with a diameter of 305 m.

Assuming both telescopes are observing at the same wavelength, the theoretical resolution of ALMA operating at its longest baseline is about 50 times better than the resolution of the Arecibo telescope. This is because the diameter of the Arecibo telescope is about 50 times smaller than the longest baseline of ALMA.

However, it is important to note that the actual resolution of a telescope is affected by many factors, including atmospheric conditions and the quality of the telescope optics. So, while ALMA may have a theoretical advantage over Arecibo, the actual observed resolution may be different depending on the specific observation conditions.

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The dot product is 25, the angle is \(\theta = cos^{-1} \frac{25}{\sqrt{35} \times \sqrt{21}}\), the cross product is 1i + (-6)j + (-7)k, and the area of the parallelogram spanned by vectors A and B is \(\sqrt{86}\).

Given,

A = 5i + 3j + k

B = 4i + j + 2k

i. Dot Product (A · B):

The dot product of two vectors A and B is given by the sum of the products of their corresponding components.

\(A.B = (A_x \times B_x) + (A_y \times B_y) + (A_z \times B_z)\\A.B = (5 \times 4) + (3 \times 1) + (1 \times 2) \\= 20 + 3 + 2 \\= 25\)

ii. Angle between vectors A and B:

The angle between two vectors A and B can be calculated using the dot product and the magnitudes of the vectors.

\(cos\theta = (A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} ((A.B) / (|A| \times |B|))\\A = \sqrt{(5^2 + 3^2 + 1^2)} =\\ \sqrt{35}\\B = \sqrt{(4^2 + 1^2 + 2^2)} \\= \sqrt{21}cos\theta = \frac{(A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} \frac{25}{\sqrt{35} \times \sqrt{21}}}\)

iv. Cross Product (A × B):

The cross product of two vectors A and B is a vector that is perpendicular to both A and B and its magnitude is equal to the area of the parallelogram spanned by A and B.

\(A\times B = (A_y \timesB_z - A_z \timesB_y)i + (A_z \timesB_x - A_x \timesB_z)j + (A_x \times B_y - A_y \times B_x)k\\A\times B = ((3 \times 2) - (1 \times 1))i + ((1 \times 4) - (5 \times 2))j + ((5 \times 1) - (3 \times 4))k\\= 1i + (-6)j + (-7)k\)

Area of the parallelogram spanned by vectors A and B:

The magnitude of the cross product A × B gives us the area of the parallelogram spanned by A and B.

Area = |A × B|

Area of the parallelogram spanned by vectors A and B:

Area = |A × B| =

\(\sqrt{(1^2 + (-6)^2 + (-7)^2}\\\sqrt{1+36+49\\\\\sqrt{86}\)

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Answer:

Ammeters are connected in series and voltmeters are connected in parallel in a circuit

The work done by the water at the constant pressure is \(-4.52 \times 10^6 \ J\).

The heat required to boil the water is calculated as follows;

\(Q = mL_v\\\\\)

where;

\(Q = 2 \times 22.6 \times 10^5\\\\Q = 4.52 \times 10^6 \ J\)

The work done by the water at the constant pressure is equal to the heat gained by the water.

\(W = - \Delta H\\\\W = -4.52 \times 10^6 \ J\).

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Answer:

.5 m N

Explanation:

Displacement just means distance from starting point, so moving 3 m north then 2.5 m south is the same as if you took 3 steps forward then 2.5 steps backward. The end point is only .5 away from the start point.

The displacement of a hiker if he travels 3.0 m N and then 2.5 m S is 0.5 m.

It is given that the hiker travels 3.0 m North and then 2.5 m South.

It is required to find the displacement of a hiker.

What is the displacement of a hiker if he travels 3.0 m N and then 2.5 m S?

As we know the displacement is the shortest distance acquired by the body or simply we say that difference between the initial and the final point of the body.

From the given question the hiker moves 3.0 m in the north that is in upward direction and from the same point the hiker comes back 2.5 m in south that is downward at the same line. To find the displacement,

Displacement = Final Point - Initial Point

Displacement = (3.0 - 2.5)m = 0.5 m

Thus, the displacement of a hiker if he travels 3.0 m North and then 2.5 m South is 0.5 m.

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Answer:

A and B

Explanation:

got it right

Answer:

Is there a target date for the hiring decision?

What is your preferred method for follow-up contact?

Answer:

Using a generator

Explanation:

Hydroelectric powerplants convert mechanical energy into electrical.

Answer:

when using a generator

it converts mechanical energy to electrical energy

The charge on each plate of a capacitor has a magnitude of  6.7 × 10⁻⁹ C when the electric field between the plates is 29,000 V/m. If the plate separation is 3.5 × 10⁻⁴ m, 2.31 × 10⁻¹⁶ F is the capacitance of the capacitor

The capacitance of a capacitor can be calculated based on the charge on each plate, the electric field between the plates, and the plate separation. In this case, the charge on each plate is given as 6.7 × 10⁻⁹ C, the electric field is 29,000 V/m, and the plate separation is 3.5 × 10⁻⁴ m. The capacitance (C) of a capacitor is given by the formula:

\(C = Q / V\)

where Q is the charge on each plate and V is the voltage or electric field between the plates. In this case, the charge on each plate is 6.7 × 10⁻⁹ C and the electric field is 29,000 V/m. Therefore, we can calculate the capacitance as follows:

C = (6.7 × 10⁻⁹ C) / (29,000 V/m)

Simplifying the expression, we can divide the charge by the electric field:

C = 2.31 × 10⁻¹⁶ F

Therefore, the capacitance of the capacitor is 2.31 × 10⁻¹⁶ Farads.

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a) The magnitude of the electric field in the wall between the two layers of charge is 25 V/m.

(b) The potential difference between the inside and the outside of the cell is 0.125 V, with the inside being at a higher potential.

(a) To find the electric field in the wall, we can use Gauss's law. Since the cell wall material is air, which has a dielectric constant of approximately 1, the electric field inside the wall is equal to the electric field in a vacuum.

Therefore, the electric field magnitude is given by the charge density divided by the permittivity of free space (ε₀). Thus, E = σ/ε₀ = 5.0 / (8.85 × 10^(-12)) = 5.65 × 10^11 V/m. However, the electric field inside the cell wall will be half the magnitude of the electric field in the air, so E = 5.65 × 10^11 V/m / 2 = 2.83 × 10^11 V/m.

(b) The potential difference between the inside and outside of the cell can be obtained by multiplying the electric field by the thickness of the cell wall. V = Ed = (2.83 × 10^11 V/m) × 5.0 m = 1.42 × 10^12 V.

However, since the potential difference is defined as the difference in potential between two points, we need to divide by the unit charge (e) to get the potential difference per unit charge.

Therefore, the potential difference is V/e = (1.42 × 10^12 V) / (1.6 × 10^(-19) C) ≈ 0.125 V. The inside of the cell is at a higher potential since the positive charge layer is on the outside.

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Answer:

(B) Conduction

Explanation:

Answer:

a ) conduction

Explanation:

it's a because if u think about it a conductor keeps the heat from getting to a certain part of the metal

Answer:

Rs 16.5 lakh is a charge of an electric car at a public charging station

Answer:

The velocity of the cross-wind was 375 km/hr South

Explanation:

The given speed of the airplane, v₀ = 500.0 km/hr W

The direction the airplane is headed = West

The direction of the wind encountered = Southbound wind

The final velocity of the airplane, R = 625 km/hr

The final direction of the airplane = South West SW

Let vₐ represent the velocity of the cross-wind

Therefore, we have the given velocities in vector form as follows;

R = -500.0·i - vₐ·j

Also, we have;

\(\left | R \right | = 625 = \sqrt{v_0^2 + v_a^2} = \sqrt{(-500)^2 + (-v_a)^2}\)

625² = (-500)² + (-vₐ)²

(-vₐ)² = 625² - (-500)² = 140625

-vₐ = 375

vₐ = -375 km/hr North = 375 km/hr South

The velocity of the cross-wind = vₐ = 375 km/hr South

Answer:

A. NaF and MgS

Explanation:

The reaction equation is given as:

             Na₂S  +  MgF₂  →   2NaF  + MgS

The product of this reaction is  NaF and MgS.

In a double displacement reaction there is an actual exchange of partners to form new compounds. This reaction takes place between ionic compounds.

The driving force for the reaction is:

Answer:

H = Vy t - 1/2 g t^2     height after time t

Vy t = H + 1/2 g t^2

Vy = H / t + 1/2 g t

Vy = -1 / 3.6 + 4.9 * 3.6 = 17.4 m/s      initial vertical speed

Vx = 50 / 3.6 = 13.9 m/s

tan θ = 17.4 / 13.9 = 1.25    θ = 51.4 deg

Ball should be kicked at 51.4 deg

V = (17.4^2 + 13.9^2)^1/2 = 22.3 m/s         initial speed

As a check use range formula

R = 22.3^2 sin 102.8 / 9.80 = 49.5 m

That is slightly less than 50m as it should be since its height would be zero after being given the initial speed

The magnitude of the net force of A and B on object C which is stated as resultant force is 85.12 N.

The entire force operating on the item or body, combined with the body's direction, is referred to as the resultant force. When the object is at rest or moving at the same speed as the object, the resulting force is zero. Since all forces are acting in the same direction, the combined force should be equal for all forces.

Combining forces applied to the same body component might result in the same outcome. Combining forces with various points of application while maintaining the same effect on the body is not conceivable. By moving the forces to the same point of application and computing the associated torques, a system of forces operating on a rigid body is combined. These forces and torques are added to produce the final force and torque.

We have two forces as,

A = 25.6 sin 26.5 = 11.42

B = 99.7 cos 32.2 = 84.36

R = \(\sqrt{A^2+B^2}\) = \(\sqrt{11.42^2+84.36^2}\) = \(\sqrt{7247.026}\) = 85.12 N

Therefore, the magnitude of force on C is 85.12 N.

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To find the period and angular speed of a wheel with a diameter of 203 cm and a revolution time of 2.00 s, we can use some basic formulas. First, we need to find the radius of the wheel, which is half the diameter, or 101.5 cm.

Next, we can use the formula T = 2πr/v, where T is the period, r is the radius, and v is the velocity of the wheel. We know that the wheel takes 2.00 s to complete one revolution, so its velocity is simply the circumference of the wheel divided by the time, or 2πr/2.00s. Simplifying this expression, we get v = πr.

Now we can substitute these values into the formula for period:

T = 2πr/v = 2π(101.5 cm)/(π(101.5 cm)) = 2.00 s

So the period of the wheel is 2.00 s.

Finally, we can find the angular speed of the wheel using the formula ω = 2π/T, where ω is the angular speed. Substituting our value for T, we get:

ω = 2π/T = 2π/2.00 s = π rad/s

So the angular speed of the wheel is π rad/s.

In summary, a wheel with a diameter of 203 cm and a revolution time of 2.00 s has a period of 2.00 s and an angular speed of π rad/s.

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Answer:

Negative acceleration occurs when the acceleration vector points to the left.

1. Object slowing down in the positive direction.

2. Object speeding up in the  negative direction.

Following six statements:

1. T

2. F

3. T

4. T

5. F

6. T

Check direction of acceleration vector.

If an object with a mass of 100g has a weight of 1 N on Earth, the volume of water displaced by the object​ is 100 cm³.

To find the volume of water displaced by the object, take the formula:

Volume = Mass ÷ Density

According to question:

Mass of the object = 100g

Density of water = 1g/cm³

Change the mass to kilograms:

Mass = 100g ÷ 1000 = 0.1kg

By using the formula, it is possible to find the volume of water displaced:

Volume = 0.1kg / 1g/cm³

= 0.1kg / 1g/cm³ × 1000g/1kg × 1cm³/1g

= 0.1 × 1000 cm³

= 100 cm³

Thus, the volume of water displaced by the object​ is 100 cm³.

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Here is a screenshot of the answer:

(The second sentence is incorrect because the triangle should be a right triangle, not an isosceles one. The fifth sentence is incorrect because we use M cos g to calculate the horizontal component.)

Answer:

225cos30

Explanation:

Force in the direction of the work done

The radius of the satellite's motion is 2.49 × 10⁷ m

Since the centripetal force, F = mv²/r equals the gravitational force, F' = GMm/r² on the satellite,

F = F'

mv²/r = GMm/r²

v² = GM/r

Making r subject of the formula, we have

r = GM/v² where r = radius of satellite's motion, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.972 × 10²⁴ kg and v = speed of satellite = 4,000 m/s.

Substituting the values of the variables into the equation, we have

r = GM/v²

r = 6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg/(4,000 m/s)²

r = 39.83324 × 10¹³ Nm²/kg ÷ 16 × 10⁶ m²/s²

r = 2.4895775 × 10⁷ m

r ≅ 2.49 × 10⁷ m

So, the radius of the satellite's motion is 2.49 × 10⁷ m.

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Answer:

25.0 million meters

Explanation:

Answer:2AgI + Na2S → Ag2S + 2NaI I am pretty sure this is the answer

Explanation:

The dog covered 28 m of distance, magnitude of displacement is 4m and direction is in east.

Distance is a scalar quantity that describes how much ground an object covers while moving, and displacement is a vector quantity that describes how far an object has travelled. This is the global change in the object's position.

We know that total distance travelled = 12 m + 16 m = 28 m.

First the dog walks 12m west, but then walks back 16m east. That means you have to subtract the distances to get the displacement.

Displacement = 12 - 16 = -4m (4m to the east, because the distance can never be negative)

Full question here :

Q. A dog walks 12 meters to the east and then 16 meters back to the west. For this motion, what is the distance moved? What is the magnitude and direction of the displacement?

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To find the displacement that will return you to your starting point by the most direct route, we can break down your motion into vector components.

First, let's represent your motion graphically:

The resulting diagram should show three connected line segments representing your three movements.

To find the displacement that will return you to your starting point by the most direct route, we need to calculate the vector sum of your individual displacements.

1. The first displacement is 160 m south. We can represent it as a vector (-160j), where j is the unit vector pointing south.

2. The second displacement is 260 m in the southwest direction. We can break it down into its x and y components. The angle of 45° indicates that the x and y components have equal magnitudes. Using trigonometry, we can find the components:

So, the second displacement can be represented as a vector (-130√2i - 130√2j).

3. The third displacement is 300 m in a direction 40° east of north. Again, we can find the x and y components using trigonometry:

So, the third displacement can be represented as a vector (192.84i + 229.80j).

To find the displacement that returns you to your starting point, we sum up the individual displacements:

Combining the i and j components:

Therefore, the displacement that will return you to your starting point by the most direct route is approximately 62.84 m to the east and (130√2 - 69.80) m to the north.

Vector images are images that use polygons to create images in computer graphics. Basically, vector images use vectors. The locations in the vector are called control points or nodes.

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Answer:

D. Electric Charges