what kind of air do winds coming from land masses bring?

moist air

low pressure air

dry air

high pressure air

Answer:

D

Explanation:

The change in free energy is -24107 J. The equilibrium constant is 2.3.

We know that the change in free energy of a reaction can be used to obtain the equilibrium constant of the reaction. On the other hand, we  know that change in free energy can be obtained from the enthalpy and the entropy as follows;

ΔGo = ΔHo  - T ΔSo

ΔGo = Change in free energy

ΔHo = change in enthalpy

T = temperature change

ΔSo = Change in entropy

Then;

ΔGo = 178.3 * 10^3 - (1273 * 159)

ΔGo = 178300 - 202407

ΔGo = -24107 J

Then we have;

ΔGo = -RTlnKp

R = gas constant

T = temperature

Kp = Rate constant

Thus;

Kp = ΔGo / -RT

Kp =  -24107 /-(8.314 * 1273)

Kp = 2.3

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Answer:

\(m_{H_2O}=12.9gH_2O\)

Explanation:

Hey there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly writing out the reaction whereby butane is combusted in the presence of excess oxygen:

\(2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O\)

Thus, we can evidence a 2:10 mole ratio of butane to water, and thus, the stoichiometric setup to calculate the mass of produced water is:

\(m_{H_2O}=7.49gC_4H_{10}*\frac{1molC_4H_{10}}{52.12gC_4H_{10}} *\frac{10molH_2O}{2molC_4H_{10}}*\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=12.9gH_2O\)

Regards!

Taking into account the reaction stoichiometry, 2.14 grams of H₂O are formed when 20.0 grams of NaHCO₃ decomposes.

In first place, the balanced reaction is:

2 NaHCO₃ → H₂O + CO₂ + Na₂CO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 168 grams of NaHCO₃ form 18 grams of H₂O, 20 grams of NaHCO₃ form how much mass of H₂O?

mass of H₂O= (20 grams of NaHCO₃× 18 grams of H₂O)÷168 grams of NaHCO₃

mass of H₂O= 2.14 grams

Finally, 2.14 grams of H₂O are formed.

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For An atom in ground state with 6 total electrons. Two, four, zero,zero are the electrons in energy shell 1 , energy shell 2, energy shell 3 and energy shell 4 respectively.

We know that, Number of electrons in shell = 2n²,where, n = shell number

Number of electrons in shell 1 = 2 × 1² = 2

Number of electrons in shell 2 = 2 × 2²

= 8

Number of electrons in shell 3 = 2 × 3²

= 18

Number of electrons in shell 4 = 2 × 4²

= 32

Rule 2 : Maximum number of electrons in outer most shell is eight. Now, we have an atoms with 6 electrons, then electrons in energy shell 1 = 2

the electrons in energy shell 2 = 4

the electrons in energy shell 3 = 0

the electrons in energy shell 4 = 0.

Hence, we got the required electrons corresponding to energy shell or level.

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Complete question:

For the following atoms in their ground state, determine the number of electrons in each energy shell. If there are no electrons in the particular energy shell for an atom, enter a 0.

An atom with 6 total electrons.

electrons in energy shell 1___

electrons in energy shell 2___

electrons in energy shell 3___

electrons in energy shell 4 ___

Yes, a chain reaction can only  be carried out using just one atom.

We know that a chain reaction has to do with the type of reaction in which there is a a continuous self sustaining reaction. In this kind of reaction, there is one radioactive material that is bombarded by a particle such as a neutron. The bombardment of the particle would make the a cycle of reactions to begin which is able to sustain itself.

Given the fact that we only need to have a single radioactive atom that is bombarded for the process of radioactivity to occur tell us that it is a process that requires just one atom.

Take for instance, all we need is one Uranium fuel that would be bombarded with neutrons in order to have a chain reaction that involves  uranium.

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Answer:

• Atom B

• Atom R

• Atom A

• Atom P

Explanation:

To calculate the overall charge of each atom, it is necessary to do a subtraction between the number of protons and the number of electrons:

So, the order of the atoms from most positive to least positive is:

• Atom B

• Atom R

• Atom A

• Atom P

If 3 moles of cl reacts with 3 moles oxygen, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions.

To determine the limiting reactant and excess reactant, we need to compare the stoichiometry of the reaction to the given amounts of each reactant.

The balanced chemical equation for the reaction between chlorine (Cl2) and oxygen (O2) can be represented as follows:

2Cl2 + O2 → 2Cl2O

According to the balanced equation, it requires 2 moles of chlorine (Cl2) to react with 1 mole of oxygen (O2) to produce 2 moles of chlorine oxide (Cl2O).

Given that we have 3 moles of chlorine (Cl2) and 3 moles of oxygen (O2), we can determine the limiting reactant by comparing the ratio of moles between the two reactants.

The ratio of Cl2 to O2 required for complete reaction is 2:1. However, since we have equal amounts of Cl2 and O2 (both 3 moles), neither reactant is present in excess.

Therefore, in this scenario, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions. All of the chlorine and oxygen will be consumed in the reaction, resulting in the complete conversion to chlorine oxide (Cl2O).

It's important to note that if the amounts of Cl2 and O2 were different, the reactant present in lesser quantity would be the limiting reactant, and the reactant in greater quantity would be the excess reactant.

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Answer: \(Pb(NO_3)_2(aq)+2KI(aq)\rightarrow PbI_2(s)+2KNO_3(aq)\)

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.

The balanced molecular equation is:

\(Pb(NO_3)_2(aq)+2KI(aq)\rightarrow PbI_2(s)+2KNO_3(aq)\)

Answer:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Explanation:

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Chemical equation:

BaCl₂ + Na₃PO₄         →     Ba₃(PO₄)₂ + NaCl

Balanced chemical equation:

3BaCl₂ + 2Na₃PO₄         →     Ba₃(PO₄)₂ + 6NaCl

The cation and anion of both reactants are exchanged with each other.

Ba²⁺ react with PO₄³⁻ and form Ba₃(PO₄)₂ while Cl⁻ react with Na⁺ and form sodium chloride.  

Molecular equation:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

As a result, the ideal gas law is applied, and the pressure of the gas in the container is 1.44 atm.

The Kelvin temperature and hence the volume are going to be in direct proportion when the pressure on a sample of a dry gas is held constant, according to the definition of the Charles Law Formula. PV = k is the law's equation, and k might be a constant.

This issue can be resolved by applying the ideal gas law:

PV = nR

T = -52 °C + 273.15 = 221.15 K

n = 0.642 mol

V = 8.6 L

T = 221.15 K

\(R = 0.0821 L·atm/mol·K (gas constant for ideal gases)\)

PV = nRT

P = nRT/V

P = (0.642 mol)(0.0821 L·atm/mol·K)(221.15 K)/(8.6 L)

P = 1.44 atm

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According to ideal gas equation, the volume is 12.47 liters if the temperature changes to 300 K and the pressure increases to 200 kPa.

The ideal gas equation is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.

Substitution of values in the above equation gives V= 1×8.314×300/200= 12.47 liters.

Thus,the volume is 12.47 liters if the temperature changes to 300 K and the pressure increases to 200 kPa.

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Answer:

Yes cellular respiration is the only way to break down glucose.  Cellular respiration takes place by the cell using oxygen to break down glucose.  

The wavelength is 3.8 * 10^ -7 m

The wavelength of a wave is the distance between two consecutive points on the wave that are in phase, meaning they have the same position in their cycle. For example, the distance between two consecutive peaks or two consecutive troughs of a wave is its wavelength.

Wavelength is typically denoted by the Greek letter lambda (λ) and is measured in meters (m) or some other unit of length, depending on the type of wave being considered.

E = hc/λ

λ = hc/E

λ =  6.626 x 10-34 * 3 * 10^8/7.26 x

10^-19 J

= 2.74 * 10^-26/7.26 x

10^-19 J

= 3.8 * 10^ -7 m

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Answer:

Cells are the smallest living unit of an organism

Answer:

all living things living things have blood cells

Explanation:

this is because robert hooke did not make this apart of the theory

The oxidation half reaction is;

2F^-(aq) ----> F2 (g) + 2e. This is an oxidation because there is the loss of two electrons.

An oxidation half-reaction is a chemical reaction that involves the loss of electrons by an atom, ion, or molecule. In other words, it is a reaction where a substance undergoes oxidation by losing one or more electrons.

We can see that in the oxidation half equation that have been shown there can be seen to be the loos of about two electrons in the half equation;

2F^-(aq) ----> F2 (g) + 2e

Hence, this is the oxidation half equation.

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Answer:

120.37 g/mol is the molar mass of magnesium sulfate

There are vacant orbitals on the phosphorus atom that allows it to expand its octet.

There is a concept that we would need to consider as we are answering the question that we here and that is the idea of the octet rule. The octet rule states that it is only about eight electrons that can be found on the outermost shell of an atom and as such all of the compounds can be formed in obedience to this rule.

Now we should know that there are no vacant d orbitals that are present on the nitrogen atom and this stems from the fact that it does not have a 3d level as such there are no orbitals that can be able to help the Nitrogen atom so as to be able to expand its octet. This is the reason why its pentafluoride can be easily formed.

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The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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This problem is providing the number of molecules of nitrogen at STP and asks for the volume they take up. At the end, the result turns out to be 33.6 L according to the following.

In chemistry, gas laws are used to relate pressure, temperature, volume and moles as an indicator of the behavior of gases. Thus, since this problem provides the number of molecules of nitrogen gas at STP, standard pressure and temperature (1atm and 273K), one knows the Avogadro's law must be utilized.

In such a way, this law allows us to know that 1 mole of any substance is related to 6.022x10²³ particles and that 1 mole of the gas occupies 22.4 L at STP. Hence, we can find the volume with the following setup:

\(9x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} *\frac{22.4L}{1mol} \\\\=33.5L\)

Which can be rounded then to 33.6 L.

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Answer:Electrical Conductivity,soluble

Explanation:

Salt is a non-magnetic solid and is soluble in water. Sand is a non-magnetic solid and is insoluble in water.

Electrical Conductivity: Salt is an electrolyte and conducts electricity when dissolved in water or in a molten state. This is because salt dissociates into ions (Na+ and Cl-) that can carry electric current. In contrast, sand is a covalent compound and does not conduct electricity, as it does not dissociate into ions in the same way as salt. Sand is considered an insulator in terms of electrical conductivity.

Answer:

Carbon dioxide and oxygen

Explanation:

The structural formula of butanol is C4H9OH. It consists of a chain of four carbon atoms, with a hydroxyl (-OH) group attached to one of the carbon atoms. Butanol has several structural isomers, which have the same molecular formula but different structural formulas.

A structural isomer is a compound that has the same molecular formula as another compound but has a different arrangement of its atoms. A string of 4 C atoms are bonded above, below, left, and right to H, except the second C, which is bonded below to O, which is bonded below to H is a structural isomer of butanol.

This is called butan-2-ol. The structural formula of butan-2-ol is CH3CH(OH)CH2CH3. In this isomer, the hydroxyl group is attached to the second carbon atom in the chain, whereas in butanol, the hydroxyl group is attached to the first carbon atom in the chain.

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Concerning the distribution of marine benthic biomass, the following statement or claims about primary production are accurate.

Primary productivity is indeed the process through which organisms transform inorganic elements into straightforward organic materials. Autotrophs, or primary producers, are in charge of this phenomenon. Typical primary examples of producers include coccolithophores, dinoflagellates, and diatoms.

Water in which production is to be assessed is sealed in sealed white as well as dark containers that are painted dark to prevent light from entering. Rating scale can be estimated by the quantity of oxygen utilized by a size of water in a defined amount of time.

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