what is wsafe , the largest weight of the load that is safe to lift regardless of the angle of the crane's arm?express wsafe in terms of w , c , and b .

Answer:

it's ans is D because all three are wrong

Liar, not even 40 points....

Transmission fluid red is made to be red in color in order

C: To distinguish it from other fluids and prevent confusion for the user.

Therefore, option C is correct because transmission fluid doesn't have any chemical properties associated with it's red color.

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Answer:

What is 120 °F in °C ?

48.8889

120°F is equal to 48.9°C. To convert the temperature from Fahrenheit (°F) to Celsius (°C), we use the formula : °C = (°F - 32) * 5/9

Fahrenheit to Celsius formula represents the conversion of degree Fahrenheit to degree Celsius and the formula for Fahrenheit to Celsius is as °C = [(°F-32)×5]/9.

To convert temperature from Fahrenheit (°F) to Celsius (°C),  we can use this formula: °C = (°F - 32) * 5/9

Given 120 °F:

Now, °C = (120 - 32) * 5/9

°C = 88 * 5/9

So, °C = 48.9 °C

Hence, 120 °F is approximately equal to 48.9 °C.

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Answer:

i am the best star ever

Explanation:

C. 0.68

aral ng mabuti! ❤

Hi there!

This is an example of a recoil collision.

Let m1, v1 be Mary

Let m2, v2 be Jim

Utilize the conservation of momentum:

m1v1 + m2v2 = m1v1' + m2v2'

The initial velocities are zero (at rest), so:

0 = m1v1' + m2v2'

Let east be positive, so Jim recoils with a negative velocity:

0 = m1v1' - m2v2'

Set the two equal and solve:

m1v1' = m2v2'

m1v1'/m2 = v2'

(50)(2.5)/65 = v2' = 1.92 m/s to the WEST

Answer:

The initial speed of the water droplets is approximately 14.904 meters per second.

Explanation:

We can describe the water jet from archerfish as part of parabolic motion, which consists of the superposition of two different motions. First, an horizontal motion at constant velocity and, second, a free fall motion. The maximum height is reached when vertical component of speed is zero. The equation of motion is described below:

\(v^{2} = v_{o}^{2}\cdot \sin^{2} \theta + 2\cdot g \cdot (y-y_{o})\)

Where:

\(v_{o}\) - Initial speed of the water jet, measured in meters per second.

\(v\) - Current speed of the water jet, measured in meters per second.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(y_{o}\) - Initial height, measured in meters.

\(y\) - Current height, measured in meters.

Now we clear the initial speed within equation:

\(v_{o}^{2} =\frac{v^{2}-2\cdot g\cdot (y-y_{o})}{\sin^{2}\theta}\)

\(v_{o} = \sqrt{\frac{v^{2}-2\cdot g\cdot (y-y_{o})}{\sin^{2}\theta} }\)

If we know that \(v = 0\,\frac{m}{s}\), \(g = -9.807\,\frac{m}{s^{2}}\), \(y = 10\,m\), \(y=0\,m\) and \(\theta = 70^{\circ}\), the initial speed of the water droplets is:

\(v_{o} = \sqrt{\frac{\left(0\,\frac{m}{s} \right)^{2}-2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (10\,m-0\,m)}{\sin^{2}70^{\circ}} }\)

\(v_{o} \approx 14.904\,\frac{m}{s}\)

The initial speed of the water droplets is approximately 14.904 meters per second.

KE= 6,875 J.

Formula: \(KE=\frac{1}{2} mv^{2}\)

Speed(v)= 5m/s

Mass(m)= 550 kg

\(KE=\frac{1}{2} (550kg)(5m/s)^{2}\\ \\KE=(275kg)(25(m/s)^{2})\\ \\KE=6875kg*\frac{m^{2} }{s^{2} }\)

According to the definition of energy units, we can rewrite the final answer as the following:

\(KE=6875J\)

J stands for "joules", unit of energy (check the attached image).

The velocity as calculated is Option d) Velocity is (d-dot) er

As given in the question the position vector is

r = d e_r

The length d is not constant with time but varies with it

The theta is fixed hat is e_r does not rotate that is it is constant with time.

To find the velocity we use the formula

velocity v = \(\frac{dr}{dt}\)       where r is the position vector

⇒ v = \(\frac{d(de_r)}{dt}\)

⇒v = (d-dot)e_r + d( e_r - dot)         (where dot means the time derivative)

⇒v= (d-dot) er                    (e_r - dot =0 because e_r is fixed )

∴The value of velocity = (d-dot) er which is

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The required mass of the object when net force on it, distance moved and final velocity are given is calculated to be 4 kg.

The net force on the unknown mass object is 20 N.

Distance travelled is 10 m.

Final velocity is 10 m/s.

The object starts from rest, so u = 0.

Mass of the object is to be calculated.

The force is given by the expression, F = m a

Making 'm' as subject, we have,

m = F/a ---(1)

Acceleration can be found using the expression, v² - u² = 2 a s ---(2)

a = (v² - u²)/2 s = (10² - 0)/(2×10) = 100/20 = 5 m/s²

Using it in (1),

m = F/a = 20/5 = 4 kg

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As the air is compressed, the work done on the air causes its temperature to increase.

What is Thermodynamic Process?

A thermodynamic process is a physical change that occurs in a system as it exchanges heat and/or work with its surroundings. It involves a change in one or more thermodynamic variables, such as temperature, pressure, volume, or entropy. There are four main types of thermodynamic processes: isothermal, adiabatic, isobaric, and isochoric.

When we blow air with our mouth narrow open, we feel the air cool because of the adiabatic expansion of the air. Adiabatic expansion is a thermodynamic process in which the air expands rapidly without losing or gaining any heat to or from the surroundings. As the air expands, it does work against the pressure of the surrounding atmosphere, and this work causes the temperature of the air to decrease. This is known as the Joule-Thomson effect.

On the other hand, when the mouth is made wide open, we feel the air warm because of the adiabatic compression of the air. Adiabatic compression is a thermodynamic process in which the air is compressed rapidly without losing or gaining any heat to or from the surroundings.

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It swings back and forth. The given information includes the mass of the sphere \((1.5×10^−2 kg)\) and its radius \((4.5×10^−2 m).\)

When the holiday ornament is displaced from its equilibrium position and released, it behaves as a physical pendulum. The motion of a physical pendulum depends on its mass distribution and moment of inertia. In this case, the mass is concentrated on the surface of the hollow sphere.

The moment of inertia of a hollow sphere can be calculated as I = \(2/3 * m * r^2\), where m is the mass of the sphere and r is its radius. Plugging in the given values, we have I = \(2/3 * (1.5×10^−2 kg) * (4.5×10^−2 m)^2.\)

Once the moment of inertia is determined, the period of oscillation for a physical pendulum can be calculated using the formula T = 2π * √(I/mgd), where T is the period, g is the acceleration due to gravity, and d is the distance from the point of suspension to the center of mass.

By substituting the values into the formula, the period of oscillation for the holiday ornament can be determined.

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Answer:

Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom).

Warm Front. ...

Stationary Front. ...

Occluded Front.

Answer:

Front 3 is an occluded front. A cold air mass moves toward warmer air. The colder, heavier air pushes the warm air upward until it’s wedged between two cold air masses. Clouds can form from the lifting of the warm air.

Explanation:PLATO

The volume of one rubber ball and the cost of producing one ball and the profit will it make on each ball will be 20.58 cm³, $0.09261, and $0.40739 respectively.

It is concerned with the geometry, region, and density of various 2D and 3D shapes.

The given data in the problem is;

r is the Rubber balls = 1.7 cm

V is the volume

C is the cost of production

P is the profit

The volume of the rubber ball is  found as;

\(\rm v= \frac{4}{3} \pi r^3 \\\\ \rm v= \frac{4}{3} \times 3.14 (4.913)^3 \\\\ \rm v= 20.58 cm^3\)

If the price of the rubber required to make a ball is $0.0045/cm3, the ball's production cost will be $0.0045/cm3.

The cost of a ball is the multiplication of the cost of one ball and the selling price of the ball;

C = 0.0045 x 20.58

C = $0.09261

P is the profit gained and profit is the subtraction of the selling price and cost price.

P = S.P.-C.P.

P=0.5 - 0.09261

P = $0.40739

Hence the volume of one rubber ball and the cost of producing one ball and the profit will it make on each ball will be 20.58 cm³, $0.09261, and $0.40739 respectively.

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Answer:  

1: C

2: C

3: A

Explanation: just did it

Answer:

rgvy

Explanation:

urfgbv

The correct statement regarding potential energy is that "potential energy is the energy that an object has based on its position."

This means that an object has the potential to do work based on its position in relation to other objects or forces. For example, a ball at the top of a hill has potential energy due to its position at the top of the hill, and this potential energy can be converted into kinetic energy as the ball rolls down the hill.

The other statements about potential energy are not true.

Potential energy can be stored and is not immediately converted to kinetic energy.

The potential energy of an object can be determined using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

And finally, an object in motion can still have potential energy, such as a pendulum swinging back and forth.

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Answer:

size of the medium

Explanation:

Answer:

38ml

Explanation:

Answer:

38 ML

Explanation:

Answer:

mass 3.67 kg, density 600 kg/m3) is fitted

with lead (density 1.14 * 10^4 kg/m3) so that it floats in water with

0.900 of its volume submerged. Find the lead mass if the lead is fitted

to the block’s (a) top and (b) bottom.

Answer:

Ff = 7.35*10^5 N

Explanation:

To find the maximum transverse pulling force you use the following formula, for the friction force:

\(F_f=\mu N=\mu Mg\) (1)

μ: friction coefficient = 0.15

N: normal force, which is equal to the weight over the wheel

M: mass of th train = 500 ton = 500 000 kg

g: gravitational acceleration = 9.8 m/s^2

You replace the values of the variables in the equation (1):

\(F_f=(0.15)(500000kg)(9.8m/s^2)=735000 N=7.35*10^5N\)

hence, the maximum transverse pulling force is 7.35*10^5 N

The photons in the cosmic background radiation, also known as the cosmic microwave background (CMB), originated from the time of recombination.

Recombination occurred approximately 380,000 years after the Big Bang, marking the transition of the universe from a hot, dense plasma to a transparent state.

Prior to recombination, the universe was filled with a hot, ionized plasma of protons, electrons, and photons, which effectively scattered and absorbed light. As the universe expanded and cooled down, the density and temperature dropped to a point where electrons could combine with protons to form neutral hydrogen atoms. This process is called recombination.

Once recombination took place, the photons were no longer frequently scattered by charged particles, and they were able to freely travel through space. These photons have been traveling through the universe ever since, essentially unchanged, and make up the cosmic microwave background radiation that we observe today.

The photons in the CMB have been redshifted over time due to the expansion of the universe. The radiation that was originally in the ultraviolet and optical range has been stretched to longer wavelengths, specifically microwaves, hence the name "cosmic microwave background." Today, the CMB has an average temperature of about 2.7 Kelvin, corresponding to a peak wavelength of approximately 1.06 millimeters.

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Condensed water droplets collect other water droplets to form the collector drop until they fall from the clouds as rain. In this way rain is formed in the tropics where the air is warmer.

A significant volume of water evaporates and is released into the atmosphere when water bodies are heated during the day. Evaporation is the term for this. Water vapour is carried upward by the hot air as it rises. The air cools and expands as it rises. Condensation is the term for this occurrence. Clouds are created as a result of water vapour condensation. With the assistance of the wind, these clouds are transported away, and when they become heavy, they drop to the ground as rain.

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The momentum flow rate through the pipe carrying liquid ammonia is 1 × \(10^6\) kg·m/s.

The flow rate of momentum (Ṁ) through the pipe can be calculated by multiplying the mass flow rate (ṁ) by the velocity (v). The speed can be determined using the equation v = ṁ / (ρA), where ρ is the density of the liquid ammonia and A is the pipe's cross-sectional area.

Given:

ṁ = 100 kg/s

A = 0.01 m²

Assuming the density (ρ) of liquid ammonia is 700 kg/m³, we can calculate the velocity (v):

v = ṁ / (ρA)

v = 100 kg/s / (700 kg/m³ × 0.01 m²)

v = 10000 m/s

Now, we can calculate the flow rate of momentum (Ṁ):

Ṁ = ṁv

Ṁ = 100 kg/s × 10000 m/s

Ṁ = 1 × \(10^6\) kg·m/s

Therefore, the momentum flow rate through the pipe is 1 × \(10^6\) kg·m/s.

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Answer:

D) the preformence of mucles for long periods of time

The time taken for a comet to complete each orbit around the Sun depends on the eccentricity of its orbit. Kepler's laws of planetary motion provide insights into this relationship. If the eccentricity is large, each orbit may take about 2 years.

Kepler's laws of planetary motion describe the motion of objects in orbit around the Sun, including comets. In this case, the comet orbits the Sun on a highly eccentric orbit with an average distance (semimajor axis) of 1 astronomical unit (AU).

Kepler's first law (law of orbits) states that the orbit of a planet (or comet) is an ellipse with the Sun at one of the foci. This law does not directly provide information about the time taken to complete each orbit.

Kepler's second law (law of areas) states that a line connecting the Sun to a planet (or comet) sweeps out equal areas in equal time intervals. This law implies that a planet or comet moves faster when closer to the Sun (perihelion) and slower when farther away (aphelion). However, it does not directly provide information about the time taken to complete each orbit.

Since the average distance (semimajor axis) of the comet's orbit is 1 AU, we can use Kepler's third law to determine the time taken to complete each orbit. Assuming the eccentricity of the orbit is large, the period of the comet's orbit is approximately 2 years (1 year * 2).

In conclusion, the time taken for a comet to complete each orbit depends on the eccentricity of its orbit, as described by Kepler's third law. If the eccentricity is large, each orbit may take about 2 years.

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Answer:

about 3 days

It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles (386,400 kilometers) which is the distance between Earth and the Moon. The specific distance depends on the specific path chosen.

Explanation:

no explanation

Answer:

here

Explanation:

Law of inertia states that a body remains in a position of rest or motion along a straight line unless an external force is applied..

Please mark me as brainliest

Answer:

2as = v² - u²

v = √(2as + u²)

v = √(2 x 4 x 400 + 13²)

v = 58 m/s

Explanation:

Answer:

58

Explanation:

correct