Answers
Answer:
The branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.
Answer:
The branch of physical science that deals with the relationship between heat and energy.
Related Questions
Speed of Sound Lab. (Please answer each question with the # it matches with.)
Answers
In air, sound travels at a computed speed of 340 m/s.
The speed of sound in air is influenced by a number of factors, including temperature, humidity, and atmospheric pressure. However, under normal atmospheric conditions—a temperature of 20 degrees Celsius or 68 degrees Fahrenheit, a relative humidity of 50%, and a pressure of one atmosphere—the speed of sound in dry air is around 343 metres per second (1,125 feet per second). This number is typically rounded to 340 m/s for convenience.
Speed is the pace at which a distance changes in relation to time. v = dx + dt, etc. Speed may also be described as a function of time and distance. Specifically, speed is equal to distance times time. Its symbol is v, and the SI unit for it is m/s. It has a scalar value. Speed is a measure of how far something can go in a given amount of time. Using the formula Speed = Distance Time, one may determine the dimension of speed. Distance is measured in units of [L1], while time is measured in units of [T1]. Dividing distance by time results in [L1] [T1] = [L1T1]. [L1T]1 is the dimension for speed.
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when the body said to be in equilibrium
Answers
Answer:
Oh! I just learned abt this
Explanation:
the body is said to be in equilibrium if it is resting or moving with uniform velocity.
Answer: The body is said to be in balance if it is at rest or moving at a uniform speed. In other words, if the body's linear and angular acceleration is zero, the body is said to be in balance. 1
if a 12 V battery is connected to the circuit shown, and R1 and R2 are EACH 2 ohm resistors; what must be the resistance of R4 be if R3 is 4 ohms and the total current is 2 amp?
Answers
Answer:
Explanation:
First find the total resistance of the combination circuit:
R = V/I = 12 V / 2 A = 6 Ω
6Ω = R1 + R2 + 1/(1/R3 + 1/R4)
6Ω = 2Ω + 2Ω + 1/(1/4 + 1/R4)
2Ω = 1/(1/4Ω + 1/R4)
2Ω(1/4Ω + 1/R4) = 1
(1/4 + 1/R4) = 1/2
1/R4 = 1/4
R4 = 4Ω
Note: R1 and R2 are in series, so you just add them together. But R3 and R4 are in parallel, so Req = 1/R3 + 1/R4
If a loading ramp is placed next to a truck, at a height of 4 feet, and the ramp is 13 feet long, what angle does the ramp make with the ground extending from the ramp to the truck? (Round your answer to one decimal place.)
Answers
Answer:
The angle that the ramp makes with the ground extending from the ramp to the truck is approximately 17.5 degrees.
Explanation:
We can start by drawing a right triangle where the hypotenuse is the ramp, the height is 4 feet, and the base is the distance from the truck to the bottom of the ramp (the horizontal distance).
Since we know the length of the hypotenuse and the height of the triangle, we can use the sine function to find the measure of the angle:
sin(θ) = opposite/hypotenuse
sin(θ) = 4/13
Now, we can solve for θ by taking the inverse sine (sin^-1) of both sides:
θ = sin^-1(4/13)
Using a calculator, we get:
θ ≈ 17.5 degrees
AP PHYSICS SYSTEM OF EQUATIONS
john and ryan are walking towards each other. john begins walking from the starting line of the 100m race at a speed of 2.1m/s. ryan starts walking 2 seconds after john starts. ryan begins walking from the finish line of the 100m race at a soeed of 1.8m/s.
a- how far from the starting line do the students meet?
b-how many seconds did it take them to meet?
i have the answers, just having troubles figuring out how to set this equation up. please show your work!! dont take advantage of the points either please
Answers
Walking at a speed of 2.1 m/s, in the first 2 s John would have walked
(2.1 m/s) (2 s) = 4.2 m
Take this point in time to be the starting point. Then John's distance from the starting line at time t after the first 2 s is
J(t) = 4.2 m + (2.1 m/s) t
while Ryan's position is
R(t) = 100 m - (1.8 m/s) t
where Ryan's velocity is negative because he is moving in the opposite direction.
(b) Solve for the time when they meet. This happens when J(t) = R(t) :
4.2 m + (2.1 m/s) t = 100 m - (1.8 m/s) t
(2.1 m/s) t + (1.8 m/s) t = 100 m - 4.2 m
(3.9 m/s) t = 95.8 m
t = (95.8 m) / (3.9 m/s) ≈ 24.6 s
(a) Evaluate either J(t) or R(t) at the time from part (b).
J (24.6 s) = 4.2 m + (2.1 m/s) (24.6 s) ≈ 55.8 m
A block of mass 2.52 kg is kept at rest
as it compresses a horizontal massless spring
(k 116 N/m) by 9.73 cm. As the block
is released, it travels 0.537 m on a rough
horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s.
Calculate the coefficient of kinetic friction
between surface and block.
Answers
By Newton's second law, the net vertical force on the block is
∑ F = N - mg = 0
so that the normal force exerted by the surface has magnitude
N = mg = (2.52 kg) (9.80 m/s²) = 24.7 N
Then as the block slides over the surface, it feels a frictional force of
f = µ (24.7 N)
where µ is the coefficient of kinetic friction.
As the block is pushed by the spring to its equilibrium position, friction performs
µ (-24.7 N) (0.0973 m) = -2.40µ J
of work (which is negative because it opposes the block's motion).
In compressing the spring by 9.73 cm = 0.0973 m, we store
1/2 (116 N/m) (0.0973 m)² = 0.549 J
of energy. This energy is released and partially converted to kinetic energy, while the rest is lost to friction.
By the work-energy theorem, the total work performed on the block as the spring pushes it towards the equilibrium position is equal to the change in its kinetic energy:
W = ∆K
0.549 J - 2.40µ J = 1/2 (2.52 kg) v ² - 0
where v is the speed of the block at the equilibrium position. Solving for v, we get
v = 0.891 √(0.549 - 2.40µ) m/s
After the block is released, the only force acting on it as it slides freely is friction. It comes to a stop after 0.537 m, so that friction performs
µ (-24.7 N) (0.537 m) = -13.3µ J
of work.
Using the work-energy theorem again, we have
W = ∆K
-13.3µ J = 0 - 1/2 (2.52 kg) v ²
Substitute the velocity we found in terms of µ, and solve for µ :
-13.3µ J = -1/2 (2.52 kg) (0.891 √(0.549 - 2.40µ) m/s)²
===> µ = 0.0350
A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (Use g = 9.8 m/s2.)
Answers
Answer:
7.0 m/s
Explanation: I just did it
Which of the following is true at the point where you reach the top of your jump on a trampoline?
The mechanical energy is zero
he potential energy is at maximum
The kinetic energy and potential energy are equal.
The potential energy is zero.
Answers
The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.
What is Potential EnergyPotential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.
This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.
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In a DC generator, the generated emf is directly proportional to the
Answers
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Starting from a location with position vector 1,=−18.7 m
and 1,=21.5 m
, a rabbit hops around for 10.7
seconds with average velocity ,=−2.17 m/s
and ,=1.71 m/s
. Find the components of the position vector of the rabbit's final location, 2,
and 2,
^ is the same as the picture
Answers
The components of the position vector of the rabbit's final location r₂, x and r₂, y is 36.77 m.
How to calculate position?To find the final location of the rabbit, calculate the displacement of the rabbit, which is given by the product of average velocity and time.
r₂, x = 1, + vx x t = -18.7 - 2.17 x 10.7 = -43.77 m
r₂, y = 1, + vy x t = 21.5 + 1.71 x 10.7 = 36.77 m
Therefore, the components of the position vector of the rabbit's final location are r2x = -43.77 m and r2y = 36.77 m.
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Using this formula Q = mcAt. A 1kg block of aluminum is increased in temperature by 75°C. how much heat energy was required? a 67,7250 b 67.728 C 65.7253 d 66.7253 Check it
Answers
Answer:
67500 J
Explanation:
Q = mcΔt.................... Equation 1
Where Q = Amount of heat, m = mass of aluminum, c = specific heat capacity of aluminium, Δt = change or increase in temperature.
From the question,
Given: m = 1 kg, Δt = 75 °C
Constant: c = 900 J/kg.K
Substitute these values into equation 1
Q = 1×900×75
Q = 67500 J
Hence the heat energy required is 67500 J
A closed vessel can sink to a depth of 41.0 m in the water before the external pressure crushes it. To what depth could this same contained be immersed in a deep vat of mercury (density = 13.6 x 10^3 kg/m^3) without it being crushed?
Answers
The vessel can be immersed to a depth of 0.3006 m in the deep vat of mercury without being crushed.
The question requires us to determine the depth to which a closed vessel that can sink to a depth of 41.0 m in water before the external pressure crushes it could be immersed in a deep vat of mercury without being crushed. We can determine this using the concept of pressure.Pressure is defined as the amount of force acting per unit area. Pressure is given by the formula:
P = F/A,
where P is pressure, F is force, and A is area. Since the area remains constant, we can say that pressure is directly proportional to force. Thus, the greater the force acting on an object, the greater the pressure exerted on the object. The pressure exerted by a liquid depends on the density of the liquid, the depth of the liquid, and the acceleration due to gravity. This can be expressed using the formula:
P = ρgh,
where P is pressure, ρ is density, g is acceleration due to gravity, and h is depth. Let us first calculate the pressure exerted by the water at a depth of
41.0 m:ρ of water = 1000 kg/m³g = 9.81 m/s²h = 41.0 m
Substituting these values in the formula, we get:
P = ρgh= (1000 kg/m³)(9.81 m/s²)(41.0 m)= 405570 Pa
Now, we need to determine the depth to which the vessel can be immersed in mercury without being crushed. Let us call this depth "d". The pressure exerted by the mercury at this depth is equal to the pressure exerted by the water at a depth of 41.0 m. Thus, we can equate the two pressure values:
ρ of mercury = 13600 kg/m³g = 9.81 m/s²P = 405570 Pa
Substituting these values in the formula, we get:ρgh = P(13600 kg/m³)(9.81 m/s²)(d) = 405570 PaSolving for d, we get:d = 0.3006 m.
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In 2012, NASA sent the 900kg Curiosity robot to Mars to study the planet. a) Recall the relationship between the weight P and the mass m. Specify the units. b) What is the weight of Curiosty on Mars? c) Compare the weight of Curiosity on Earth and on Mars. Why is it more important on Earth
Answers
(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).
(b)The weight of Curiosity on Earth is approximately 8820 Newtons.
a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).
b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.
c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.
The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.
It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.
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As water has a higher ___________________, we can assume that land will heat and cool faster than water.
Answers
Water enhance living activity, as water has a higher specific heat capacity,
we can assume that land will heat and cool faster than water.
What is water?Water is a liquid with no color, taste and odour. The sea, rivers, streams are made of water.
Water has more heat capacity, it has the tendency to absorb heat to itself and it takes a longer time to cool off, while land or soil takes a shorter time to cool.
Therefore ,As water has a higher specific heat capacity we can assume that land will heat and cool faster than water
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. Chloe performed an experiment on the amount of a certain gas that can be dissolved in water at different temperatures. Her data from the experiment is shown on the graph below. What type of function would best fit this set of data?
Answers
The values on the curve corresponding to the y axis are the y values
The values on the curve corresponding to the x axis are the x values
We would pick corresponding x and y values on the graph and compare them
On the graph, each small square represents 1 unit on both axes.
If x = 1, y = 1
If x = 4, y = 2
if x = 9, y = 3
We know that the square root of 1 is 1, the square root of 4 is 2 and the square root 9 is 3. This means that
y is the square root of x
The function is
\(y\text{ = }\sqrt[]{x}\)Thus, it is a square root function
The first option is correct
A theme park creates a new kind of water wave pool with large waves caused by constructive interference. There are two wave generators in phase with each other along either side of a pool that is 24.0 m wide. A swimmer that is 9.0 m from one generator and 14.0 m from the other notices that she is in a region with almost no wave amplitude, but there are large-amplitude waves on either side of her.
What is the longest wavelength that will produce this interference pattern?
Express your answer to three significant figures and include appropriate units.
Answers
Answer:
10.0 m
Explanation:
Since there is no amplitude at the point of the swimmer, we have destructive interference.
So, the path difference ΔL = L₂ - L₁ where L₁ = swimmer's shorter distance from one generator = 9.0 m and L₂ = swimmer's longer distance from the other generator = 14.0 m. ΔL = 14.0 m - 9.0 m = 5.0 m
Also, since we have destructive interference, ΔL = (n + 1/2)λ where n = number of wavelengths and λ = wavelength of waves
For maximum wavelength, n = 0
So, ΔL = (n + 1/2)λ
ΔL = (0 + 1/2)λ
ΔL = λ/2
λ/2 = ΔL
λ = 2ΔL
λ = 2 × 5.0 m
λ = 10.0 m
So, the longest wavelength that will produce this interference pattern is λ = 10.0 m
5. Salt is often spread on roads during winter to prevent ice from forming. Do you think sugar would
work as well? Explain your answer.
Answers
Answer:
No because sugar is more sweet and it would not have the benefits of salt. Think of it like how people used to put salt on meat to preserve it. Would they put sugar on? No they would not because salt is a combination of things that sugar does not have.
Explanation
how to find potential energy
Answers
Answer:
The formula for potential energy depends on the force acting on the two objects.
Please Help
A projectile fired over level ground has an initial total velocity of 41.3 m/s. It is in the air for 5.1 s. What is the x-component of the projectile's initial velocity?
Answers
Answer:
Explanation:
In the vertical analysis assuming launch from ground level.
0 = 0 + (41.3sinθ)(5.1) + ½(-9.8)5.1²
(41.3sinθ)(5.1) = ½(9.8)5.1²
(41.3sinθ) = ½(9.8)5.1
sinθ = ½(9.8)5.1/41.3
sinθ = 0.60508...
θ = 37.235°
vx = 41.3cos37.235
vx = 32.881452...
vx = 32.9 m/s
Consider the heaviest box of 150 pounds that you can push at constant speed across a level floor, where the coefficient of kinetic friction is 0.50, and estimate the maximum horizontal force that you can apply to the box. A box sits on a ramp that is inclined at an angle of 60 degrees above the horizontal. The coefficient of kinetic friction between the box and the ramp is 0.50. If you apply that same magnitude force, now parallel to the ramp, that you applied to the box on the floor, what is the heaviest box (in pounds) that you can push up the ramp at a constant speed?
Answers
We can deduce here that the maximum horizontal force that you can apply to the box is 150 pounds. Thus, the heaviest box that you can push up the ramp at a constant speed is 75 pounds.
How we arrived at the solution?Given the following:
Maximum horizontal force = 150 pounds
Coefficient of kinetic friction = 0.50
Weight of the box = 150 pounds
Angle of the ramp = 60°
Normal force = Weight of the box * Cosine of the angle of the ramp
= 150 pounds × Cos(60°)
= 75 pounds.
Force of friction = Coefficient of kinetic friction × Normal force
= 0.50 × 75 pounds
= 37.5 pounds
Maximum force that can be applied to the box = Weight of the box × Cosine of the angle of the ramp - Force of friction
= 150 pounds × Cos(60°) - 37.5 pounds
= 75 pounds
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. A horizontal steel spring has a spring constant of 40.0 N/m. What force must be applied to the spring in order to compress it by 10.0 cm?
Answers
Ans 4 more to be exact
Explanation:
Given values are:
Spring constant,
k = 40 N/mand,
x = 10 mThe force will be:
→ \(F = kx\)
By substituting the values, we get
\(= 40\times 10\)
\(= 400 \ N\)
Thus the above answer is right.
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Inside a stereo speaker, you will find two permanent magnets: one on the cone and one near the cone. True of false?
Answers
Answer:
false
Explanation:
3. What is the acceleration of a 50 g object pushed with a force of 0.5 N
Answers
The acceleration of a 50 g object pushed with a force of 0.5 N is 10 m/s².
To find the acceleration of the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:
F = m * a
Given:
Force (F) = 0.5 N
Mass (m) = 50 g = 0.05 kg
Substituting the given values into the equation, we have:
0.5 N = 0.05 kg * a
To find the acceleration (a), we rearrange the equation:
a = F / m
a = 0.5 N / 0.05 kg
a = 10 N/kg
Since acceleration is measured in meters per second squared (m/s²), we convert the unit of N/kg to m/s²:
1 N/kg = 1 m/s²
Therefore, the acceleration of the 50 g object pushed with a force of 0.5 N is 10 m/s².
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A commuter backs her car out of her garage with a constant acceleration of 1.20 m/s2. (a) How long in seconds does it take her to reach a speed of 1.90 m/s
Answers
The time in seconds it will take her to reach a speed of 1.9 m/s is 1.58s.
What is time?:Time can be defined as the measurable period or duration, during which an action, process, or condition exists or continue.
The time taken for the commuter to reach a speed of 1.9 m/s, can be calculated using the formula below.
Formula:
a = (v-u)/t................. Equation 1Where:
a = acceleration of the commuterv = final velocity of the commuteru = initial velocity of the commutert = time taken for the commuter to reach the speed.make t the subject of equation 1
t = (v-u)/a................. Equation 2From the question,
Given:
v = 1.90 m/sa = 1.2 m/s²u = 0 m/sSubstitute these values into equation 1.
t = (1.9-0)/1.2t = 1.58 s.Hence, The time in seconds it will take her to reach a speed of 1.9 m/s is 1.58s
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How many electrons does Gold have?
Answers
Answer:
79 I believe! don't mind the rest sjjdjdiwowjekwhfjdoaoqhenfixiwnsodjd djdjsiwuwieodjskrkf
Now find what k value would be needed to stretch the spring 0.25 m at a force value of 25 N.
Answers
Hi there!
\(\boxed{k = 100N/m}\)
Using Hooke's Law:
\(F = kx\)
F = force (N)
k = Spring Constant (N/m)
x = displacement from equilibrium (m)
Plug in the given values:
25 = k(0.25)
25 = 0.25k
Solve for k:
25/0.25 = k
k = 100 N/m
what would happened if the eagle population increased
Answers
Answer:
Bald eagles' population size is being affected by lead poisoning, according to scientists at the Department of Public and Ecosystem Health at Cornell University. A study looking at records between 1990 and 2018 found the birds are eating hunters' gunshot ammunition, decreasing their population growth by 4% to 6%.
For the study, published in the Journal of Wildlife Management, scientists looked at population regrowth numbers for bald eagle populations across the Northeast. They found that hunters who "field dress" their prey and leave the contaminated organs on site put the eagles that scavenge the remains at risk. Other species, including owls, crows, coyotes, foxes, fisher and bears, eat the remains as well, meaning they are all possibly at risk of being poisoned.
Answer:
The once dwindling bald eagle population that brought the raptor close to extinction in the United States has soared in the past decade, according to a new report by the U.S. Fish and Wildlife Service (USFWS). Eagle populations quadrupled in size since 2009 with 316,700 individual bald eagles spotted and 71,400 nesting pairs recorded during the 2019 breeding season, reports Lauren M. Johnson and Liz Stark for CNN.
You sit at the middle of a large turntable at an amusement park as it is set spinning and then allowed to spin freely. When you crawl toward the edge of the turntable, does the rate of the rotation increase, decrease, or remain unchanged? what physics principle supports your answer?.
Answers
When you move closer to the turntable's edge while crawling, the rotational speed will slow. This is because of the principle of conservation of angular momentum, according to which a system's angular momentum never changes.
What does a rolling body's angular momentum mean?The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.
How are angular momentum in spinning systems conserved?A spinning system's ability to conserve angular momentum ensures that, absent external tension, its spin will not change. To put it another way, the speed of rotation is constant as long as net torque is zero.
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Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answers
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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Say an impulse is applied opposite the go-kart's direction of travel. What happens to
the go-kart if its momentum + impulse = 0?
The go kart stops comes to a stop.
The go kart slows down but keeps moving.
The go kart speeds up.
There is no change in the speed of the go kart.
Answers
If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.
Option A is correct.
What is meant by impulse?impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.
If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.
Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.
As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.
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