What is the y-intercept of the function described in the table?

Answer:

vance got the better deal

Step-by-step explanation:

Answer:

not equivalent to meteorologists ratio

Step-by-step explanation:

meteorologists ratio is

rainy days : sunny days = 2 : 5

last months weather is

rainy days : sunny days

= 10 : 20 ( divide both parts by LCM of 10 )

= 1 : 2 ← not equivalent to 2 : 5

The given sum for n = 1 to n = 15 is equal to 255, so the correct option is B.

We want to find the sum of the series whose elements are of the form:

(2n + 1)

From n = 1 to n = 15.

Then our sum will be:

(2*1 + 1) + (2*2 + 1) + ... + (2*15 + 1).

3 + 5 + ... + 31

This is the sum of all odd numbers in the interval [3, 31]

Which gives:

\(S = 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25 + 27 + 29 + 31 = 255\)

So the correct option is B.

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The real part (a) of the complex number is 2, and the imaginary part (b) is 3.

To determine the real and imaginary parts of the complex number without using a calculator, we can analyze the given polar form of the complex number c = 2; 3³0 + 3e¹454e145.

In polar form, a complex number is represented as r; θ, where r is the magnitude and θ is the angle. Here, the magnitude is 2, and we need to determine the real (a) and imaginary (b) parts.

The real part (a) corresponds to the horizontal component of the complex number, which can be found using the formula a = r * cos(θ). In this case, a = 2 * cos(30°) = 2 * 0.866 = 1.732.

The imaginary part (b) corresponds to the vertical component, which can be found using the formula b = r * sin(θ). In this case, b = 2 * sin(30°) = 2 * 0.5 = 1.

Therefore, the real part (a) of the complex number is 2, and the imaginary part (b) is 3.

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Answer: (3,-2)

Step-by-step explanation: We're reflecting to the y-axis, thus, we're going to reflect to the right.

(-x,-y) ⇒ (x,-y)

Our current coordinate is (-3,-2)...let's convert it now...

(3,-2)

I hope this helps!

Answer:

(3, -2).

Step-by-step explanation:

When you reflect across the y axis the y coordinate stays the same and the x axis changes sign : (x, y) --> (-x, y).

So B (-3, -2) --> (3, -2).

Answer:

Since the machine fills 250 bottles every 20 minutes, we can write the proportion:

250 bottles / 20 minutes = y bottles / x minutes

Simplifying this proportion, we get:

y = (x/20) * 250

This equation represents a linear relationship between the number of bottles (y) and the number of minutes (x), where the slope is 250/20 = 12.5 bottles per minute.

To create a graph, you can plot the points (0, 0) and (9, 112.5) since the y-axis only goes up to 125. This will give you a straight line that starts at the origin and goes up to about 112.5 on the y-axis at x = 9.

Step-by-step explanation:

The dropdown numbers is an illustration of combination

The smallest dropdown number is 1025

From the question, we have the following parameters:

We start counting from 1023, 1024, 1025, 1026...........

The number 1025 satisfies the given conditions

Hence, the smallest dropdown number is 1025

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Answer:

community property addition

Answer:

81 * 4 = 324.

Step-by-step explanation:

There are 81 * 4 = 324 such integers.

There are 9000 four-digit integers from 1000 to 9999. Let’s refer to the digit that occurs three times as the triplet and the digit that occurs once as the singleton.

In the first (most significant) position there are 9 possible values for the singleton, 1 through 9. In each case there are also 9 possible values for the triplet. For example if the singleton was a 1, the triplets could be anything but a 1: 1000, 1222, 1333, …, 1999. So there are 9 * 9 = 81 cases with the singleton in the first position.

A singleton in the second position can have 10 possible values, 0 through 9. If it’s a 0 there are 9 possible values for the triplet: 1011, 2022, 3033, …, 9099. If it’s anything else there are only 8 possible values for the triplet since the triplet cannot be 0: 2122, 3133, 4144, …, 9199. So there are 9 + (8 * 9) = 81 cases with the singleton in the second position.

The third and fourth positions work just like the second. So the grand total is 81 * 4 = 324.

If you plot the 9000 four-digit integers as a 100 x 90 grid of squares and color the integers with three same digits in red, an interesting pattern occurs:

There are 81 * 4 = 324 such integers.

There are 9000 four-digit integers from 1000 to 9999. Let’s refer to the digit that occurs three times as the triplet and the digit that occurs once as the singleton.

In the first (most significant) position there are 9 possible values for the singleton, 1 through 9. In each case there are also 9 possible values for the triplet. For example if the singleton was a 1, the triplets could be anything but a 1: 1000, 1222, 1333, …, 1999. So there are 9 * 9 = 81 cases with the singleton in the first position.

A singleton in the second position can have 10 possible values, 0 through 9. If it’s a 0 there are 9 possible values for the triplet: 1011, 2022, 3033, …, 9099. If it’s anything else there are only 8 possible values for the triplet since the triplet cannot be 0: 2122, 3133, 4144, …, 9199. So there are 9 + (8 * 9) = 81 cases with the singleton in the second position.

The third and fourth positions work just like the second. So the grand total is 81 * 4 = 324.

If you plot the 9000 four-digit integers as a 100 x 90 grid of squares and color the integers with three same digits in red, an interesting pattern occurs:

(If you zoom in, the four-digit number is printed inside each red square - not sure whether or not that will come through after Quora processes the image.)

Hope this helps!

Brain-List?

Answer:

81

Step-by-step explanation:

4 digit number: xxxy

x=1 y can be 0,2,3,4,5,6,7,8,9  ...9 possibility

x can be 1,2,3,4,5,6,7,8,9 ....9 too

9 x 9 = 81

My best guess, wish it's right.

The indefinite integral of arctan(x)/x can be represented as a power series with a radius of convergence of 1.

The power series representation of the indefinite integral can be obtained by integrating the Taylor series expansion of arctan(x)/x term by term. The Taylor series expansion of arctan(x)/x is known to be x - x^3/3 + x^5/5 - x^7/7 + ..., which converges for |x| < 1.

Integrating term by term, we get the power series representation of the indefinite integral as c + x^2/2 - x^4/12 + x^6/30 - x^8/56 + ..., where c is the constant of integration.

The radius of convergence of this power series is determined by the convergence of the Taylor series expansion of arctan(x)/x, which is 1. Therefore, the radius of convergence for the power series representation of the indefinite integral is R = 1.


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Answer: 6 weeks

Step-by-step explanation: $54 x 6 = $324

Answer:

Step-by-step explanation:

15x 12%=1.8

so he earns $1.80 for the raise

so 15x1.8=27

So now he earns 27 for every hour.

27x40=1080

So now he earns $1080 in 40 hours.

Answer:

34p-16

Step-by-step explanation:

Perimeter of parallelogram

= 2(9p-10)+2(8p+2)

= 18p-20+16p+4

= 34p-16

Answer:

Square root of 56 so in simplest radical form 4 root 4

Step-by-step explanation:

Answer:

The answer its A:

Step-by-step explanation:

I hope its correct.

Answer:

the 90th percentile is 9.

The 90th percentile of the distribution is 9.

The 90th percentile of the distribution in the table is 9.

To find the 90th percentile, we need to look at the values of X and their corresponding cumulative percentages (C%). The 90th percentile is the value of X at which 90% of the data falls below.

Looking at the table, we can see that the value of X at the 90th percentile is 9, as it corresponds to a cumulative percentage of 100%. This means that 90% of the data falls below the value of 9.

Therefore, the 90th percentile of the distribution is 9.

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Answer:

-1.5

Step-by-step explanation:easy

Answer:

Step-by-step explanation:

A parallelogram is a quadrilateral with four sides.

Given parallelogram ABCD, to prove that opposite sides of the parallelogram are congruent.

Join D to B, the diagonal of the parallelogram which is also a traversal.

So that;

    <ABD = <BDC (alternate angle property)

    <BAC = <ACD (alternate angle property)

Also, diagonals;

      /AC/ = /BD/ (reflexive property)

Then;

      ΔABD = ΔCBD (Angle-Side-Angle, ASA, property)

Thus;

     /AB/ ≅ /CD/ (corresponding sides of congruent triangles are congruent)

    /BC/ ≅ /AD/  (corresponding sides of congruent triangles are congruent)

Therefore, the opposite sides of the parallelogram ABCD are congruent.

The ratio of the related flanks is not identical. Then the triangles are not similar.

A triangle has three sides which are straight lines. The aggregation of the interior angle of the triangle is 180°.

If two triangles are equivalent, the ratio of the matching sides will not change.

The ratio is given as,

AE / EC = FA / FB

9 / 3 = 10 / 5

3 ≠ 2

The ratio of the related flanks is not identical. Then the triangles are not similar.

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The complete question is given below.

Answer:

x<6/7

Step-by-step explanation:

7x/3 < 2

7x < 6

x < 6/7

The answer is that the mathematician solved 2k problems on the day he drank coffee.

Let's assume that the mathematician works for x hours a day and can solve y problems per hour. Also, the mathematician drinks some coffee and discovers that he can now solve z problems per hour. So, the mathematician works for n hours that day. We are given that:x*y = number of problems solved in a dayz * n = number of problems solved on the day he drank coffee

Then, we can write the equations:x*y = n * 2*z (he still solves twice as many problems as he would in a normal day)andx = n (he only works for n hours that day)Now, we need to simplify these equations to solve for the number of problems solved on the day he drank coffee. Here is how to do it:$$x*y = n * 2*z$$$$\frac{x*y}{x} = \frac{2*n*z}{x}$$$$y = 2 * \frac{n*z}{x}$$Since x, y, n, and z are all positive integers, we can say that the expression 2*n*z/x is also a positive integer. Therefore, we can write:$$\frac{2*n*z}{x} = k$$$$y = 2k$$where k is a positive integer.

Finally, the number of problems solved on the day he drank coffee is:y = 2k Therefore, the answer is that the mathematician solved 2k problems on the day he drank coffee.

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Answer:

a

Step-by-step explanation:

hope this helps!! please mark brainliest

3 is a constant, 4 is the coefficient, 5a+3+4b is written as a sum of three terms are the true statements.

The act of combining two or more items is known as addition. The process of computing the sum of two or more numbers in mathematics is called addition. It is a fundamental mathematical procedure that is frequently used in daily life. When we work with money, figure out our food bills, or figure out the time, we frequently employ addition. Mathematicians employ the action of addition to combine numbers. The sum of the given numbers is the outcome of addition, or the total of the inputted numbers.

Given that,

5a+3+4b

Select all of the true statements below.

5a+3+4b is written as a product of three factors.

3 is a constant.

4 is a coefficient.

4b and 3 are like terms.

5a+3+4b is written as a sum of three terms.

Therefore, 3 is a constant, 4 is the coefficient, 5a+3+4b is written as a sum of three terms are the true statements.

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The correct statements are: B. There's more variability in the test scores from class B because the IQR is larger.

D. There is more variability in the test scores from class B because the overall range is larger.

In mathematics, variability refers to the degree to which a data set deviates from its mean or central value. It is a measure of how spread out or dispersed the data values are within a set.

Explanation:

A. The median test scores are not same for both classes. Class A has a median of around 85 while class B has a median of around 75.

B. The IQR (interquartile range) represents the range between the first quartile (Q1) and the third quartile (Q3), which captures the middle 50% of the data. The IQR of class B is larger than that of class A, indicating that there is more variability in the test scores of class B.

C. The distance between Q1 and Q3 (i.e., IQR) is related to the standard deviation, but it is not a direct measure of it. Therefore, this statement is not accurate.

D. Range is the difference between the maximum and minimum values in a dataset. The overall range of class B is larger than that of class A, indicating that there is more variability in the test scores of class B.

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Answer:

Step-by-step explanation:

12y =120   y : the lenght

Answer:

y=mx+b

Step-by-step explanation:

B is the y intercept and m is the slope. Use y and x for the two points.

(a) The function f(x) = 2x + 1 − 2x² is continuous on (0, 1) using the limit theorems. (b) The function f(x) = 3(∑(n=1)^∞ 1/n²) + x is continuous on (0, 1) using the limit theorems.

a- To show that f(x) is continuous on (0, 1), we need to show that it is continuous at every point in (0, 1). Let x₀ be an arbitrary point in (0, 1), and let ε > 0 be given. We need to find a δ > 0 such that |f(x) − f(x₀)| < ε whenever |x − x₀| < δ and x ∈ (0, 1).

First, note that f(x) is a polynomial, so it is continuous on (0, 1) by definition. Moreover, we have:

|f(x) − f(x₀)| = |2x + 1 − 2x² − (2x₀ + 1 − 2x₀²)| = |2(x − x₀) − 2(x² − x₀²)|

Now, using the identity a² − b² = (a − b)(a + b), we can write:

|f(x) − f(x₀)| = |2(x − x₀) − 2(x − x₀)(x + x₀)| ≤ 2|x − x₀| + 2|x − x₀||x + x₀|

Since x + x₀ < 2 for all x, we have:

|f(x) − f(x₀)| ≤ 2|x − x₀| + 4|x − x₀| = 6|x − x₀|

Thus, we can choose δ = ε/6, and it follows that |f(x) − f(x₀)| < ε whenever |x − x₀| < δ and x ∈ (0, 1). Therefore, f(x) is continuous on (0, 1).

To show that f(x) is continuous on (0, 1), we need to show that it is continuous at every point in (0, 1). Let x₀ be an arbitrary point in (0, 1), and let ε > 0 be given. We need to find a δ > 0 such that |f(x) − f(x₀)| < ε whenever |x − x₀| < δ and x ∈ (0, 1).

First, note that the series ∑(n=1)^∞ 1/n² converges, so it has a finite limit L = ∑(n=1)^∞ 1/n². Thus, we can write:

|f(x) − f(x₀)| = |3L + x − (3L + x₀)| = |x − x₀|

Thus, we can choose δ = ε, and it follows that |f(x) − f(x₀)| < ε whenever |x − x₀| < δ and x ∈ (0, 1). Therefore, f(x) is continuous on (0, 1).

C-The function f(x) = ∑(n=0)^∞ xⁿ is continuous on (0, 1) using the limit theorems.

To show that f(x) is continuous on (0, 1), we need to show that it is continuous at every point in (0, 1). Let x₀ be an arbitrary point in (0, 1), and let ε > 0 be given. We need to find a δ > 0 such that |f(x) − f(x₀)| < ε whenever |x − x₀| < δ and x ∈ (0, 1).

Note that f(x) is an infinite geometric series with common ratio x, so we can write:

f(x) = 1 + x + x² + x³ + ... = 1/(1 − x)

Since 0 < x < 1, we have |f(x)| = |1/(1 − x)| < ∞. Moreover, we have:

|f(x) − f(x₀)| = |1/(1 − x) − 1/(1 − x₀)| = |(x₀ − x)/(1 − x)(1 − x₀)|

Now, suppose we choose δ = ε/2, and let |x − x₀| < δ. Then we have:

|(x₀ − x)/(1 − x)(1 − x₀)| ≤ 2|x₀ − x|/δ²

Thus, if we choose δ small enough so that 2/δ² < ε/(2|f(x)|), we get:

|f(x) − f(x₀)| < ε

Therefore, f(x) is continuous on (0, 1).

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Hello, the graph sould be like this. Just remember, if you want to draw a graph, you should know the x and y state. x is from left and y is from right.