what is the word that describes a substance which reacts with both strong bases and strong acid
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16.52 milliliters of 8.54×10⁻² M Ba(OH)2(aq) are required to titrate 54.90 mL of 5.14×10⁻² M HNO₃

A titration is a procedure that uses a known solution to determine the concentration of an unknown solution. Until the reaction is finished, the titrant (the known solution) is typically supplied from a buret to a known volume of the analyte (the unknown solution).

Titration is an essential technique in analytical chemistry, and it is also known as volumetric analysis.

n-factor for Ba(OH)₂ =2

Thus, dilution equation becomes:

n × M₁V₁= M₂V₂

2 x 8.54 x 10⁻² x V₁ = 5.14 x 10⁻² x (54.90/1000)

V₁= 16.52 × 10⁻³¹

V₁   = 16.52 ml

Thus, 16.52 milliliters of 8.54×10⁻² M Ba(OH)2(aq) are required to titrate 54.90 mL of 5.14×10⁻² M HNO₃

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We frequently observe kids playing with polythene bags filled with water that have little holes drilled into them at various locations so they can sprinkle water on other kids. Through this experiment, we can say that pressure acts in all directions in liquids.

Since both liquids and gases may flow, they are both referred to as fluids. Fluids under rest pressure behave uniformly in all directions.

Weather forecasts can be made using barometers. They track the evolution of atmospheric pressure throughout time.

On weather forecast maps, pressure variations appear as an isobar pattern. Predictions are made using these changes in pressure, and they are fairly accurate when combined with wind observations.

As you go away from a liquid's surface, pressure rises. for instance: A bucket has three holes that are all the same size. Since there is more pressure at the bucket's bottom, the water spills out more forcefully. Dams are thicker at the bottom for this reason.

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Answer:

It's a liquid when it has changed from solid to a liquid state. (You take ice out from the freezer and it turns to water)

Explanation:

Basic chemistry

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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1. The amount of water produced by the reaction is 0.359 g.

2. The amount of water produced by the reaction is 0.219 g.

To calculate the number of moles of acid neutralized by the tablet, subtract the number of moles of acid neutralized in the titration from the initial solution's moles of acid. Understand and explain standardization in the context of acidic and basic solutions used as reagents in experiments.

1. The neutralization reaction,

HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)

we have to calculate the number of moles of HCl that react,

moles of HCl = volume of HCl x concentration of HCl

= 7.98 mL x 2.50 mol/L / 1000 mL/L

= 0.01995 mol

Since NaOH is in excess,

As a result, the amount of water produced will be equal to the amount of HCl that reacts:

moles of water = moles of HCl = 0.01995 mol

we can use the molar mass of water (18.015 g/mol)

mass of water = moles of water x molar mass of water

= 0.01995 mol x 18.015 g/mol

= 0.359 g

2. The neutralization reaction between H2SO4 and NaOH is:

H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O (l)

we have to calculate the number of moles of H2SO4 that react,

moles of H2SO4 = volume of H2SO4 x concentration of H2SO4

= 2.43 mL x 2.50 mol/L / 1000 mL/L

= 0.00608 mol

Now, we have to calculate the number of moles of NaOH that react:

moles of NaOH = volume of NaOH x concentration of NaOH

= 2.51 mL x 3.00 mol/L / 1000 mL/L

= 0.00753 mol

we need to use the stoichiometry of the balanced equation,

moles of water = moles of H2SO4 x (2 moles of water / 1 mole of H2SO4)

= 0.00608 mol x 2

= 0.01216 mol

we can use the molar mass of water (18.015 g/mol)

mass of water = moles of water x molar mass of water

= 0.01216 mol x 18.015 g/mol

= 0.219 g

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In the solid state of matter, particles, such as atoms, ions, or molecules, are closely packed and held together by strong intermolecular forces, such as ionic bonds, metallic bonds, or covalent bonds.

In a solid, particles have enough energy to vibrate around fixed positions but do not have enough energy to overcome the attractive forces between them. These attractive forces, also known as cohesive forces, arise from the electrostatic interactions between particles or the sharing of electrons in covalent bonds.

The energy of the particles in a solid is typically much lower than in the liquid or gaseous states, resulting in a fixed arrangement of particles.

The movement of particles in a solid is characterized by vibrations or oscillations around their equilibrium positions.

These vibrations occur due to the thermal energy present in the solid, but the particles remain relatively fixed in their positions due to the strong attractive forces. The amplitude of the vibrations increases with increasing temperature, as the particles gain more thermal energy.

However, the particles in a solid do not have enough energy to break the intermolecular bonds and move freely throughout the entire solid. Instead, they can only move within their local vicinity or lattice positions.

This restricted movement is what distinguishes the solid state from the liquid or gaseous states, where particles have enough energy to overcome intermolecular forces and move more freely.

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For the reaction of combustion of 74.3 g of butane with 132 kg of oxygen, we have:

a. The limiting reactant is butane

b. The mass of carbon dioxide obtained by heating butane is 225.33 grams.

c. 131734.8 grams or 131.73 kilograms of oxygen remains unreacted.

a. The balanced reaction is the following:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O     (1)  

To find the limiting reactant, we need to calculate the initial number of moles of butane and oxygen

\( n_{C_{4}H_{10}}_{i} = \frac{m_{C_{4}H_{10}}}{M_{C_{4}H_{10}}} = \frac{74.3 g}{58.12 g/mol} = 1.28 \:moles \)

\( n_{O_{2}}_{i} = \frac{m_{O_{2}}}{M_{O_{2}}} = \frac{132000 g}{31.99 g/mol} = 4126.3 \:moles \)

From equation (1) we have that 2 moles of C₄H₁₀ react with 13 moles of O₂, so the number of oxygen moles needed to react with 1.28 moles of C₄H₁₀ is:

\( n_{O_{2}}_{r} = \frac{13\:moles\:O_{2}}{2\:moles\:C_{4}H_{10}}*1.28\:moles\:C_{4}H_{10} = 8.32\:moles \)

We need 8.32 moles of O₂ to react with butane and initially we have 4126.3 moles, so the limiting reactant is butane.

b. The mass of CO₂ can be found with the limiting reactant

From equation (1), 2 moles of C₄H₁₀ react with oxygen to produce 8 moles of  CO₂, so the number of moles of CO₂ produced is:

\( n_{CO_{2}} = \frac{8\:moles\:CO_{2}}{2\:moles\:C_{4}H_{10}}*1.28\:moles\:C_{4}H_{10} = 5.12\:moles \)

Then, the mass of CO₂ is:

\( m_{CO_{2}} = n_{CO_{2}}*M_{CO_{2}} = 5.12 \:moles*44.01 g/mol = 225.33 g \)

Hence, the mass of CO₂ obtained is 225.33 grams.

c. The number of moles of the excess reagent can be calculated as follows

\( n_{O_{2}} = n_{O_{2}}_{i} - n_{O_{2}}_{r} = (4126.3 - 8.32) \:moles = 4118 \:moles \)  

Now, the mass of oxygen that remains after the reaction is:

\( m_{O_{2}} = 4118\:moles*31.99g/mol = 131734.8 g = 131.73 kg \)

Therefore, 131734.8 g or 131.73 kg of oxygen remains unreacted.

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I hope it helps you!

Answer:

b. vapor

Explanation:

When a liquid substance is heated sufficiently, the energy from the heat causes the molecules to gain enough kinetic energy to break the intermolecular bonds and escape into the air as individual gas molecules. This process is called evaporation, and the substance in this gaseous form is known as a vapor. The term "vapor" refers to the gaseous form of a substance that was originally in a liquid state, and it typically refers to the mixture of gas molecules that are in constant motion and in contact with the air.

Answer:

A. Steep hillside, little vegetation, strong downpours

Explanation:

between a steep hill and a flat valley, the hill is more likely to be affected because of gravity. with a valley theres less places for the dirt to actually move to. So C and D are not correct

a lack of vegetation and heavy downpour is the perfect condition for erosion. plants' root system makes dirt and rock more stable. without a lot of roots to hold the dirt in place and absorb water before it runs over the rocks and breaks them down, heavy rain would be a lot more likely to erode the area. so B isnt right either

Answer:

0.0123 mol

Explanation:

Step 1: Convert 34.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 34.0 + 273.15 = 307.2 K

Step 2: Convert 148 cm³ to L

We will use the conversion factors:

\(148cm^{3} \times \frac{1mL}{1cm^{3}} \times \frac{1L}{1000mL} = 0.148L\)

Step 3: Convert 212 kPa to atm

We will use the conversion factor 1 atm = 101.325 kPa.

212 kPa × 1 atm / 101.325 kPa = 2.09 atm

Step 4: Calculate the moles of nitrogen gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 2.09 atm × 0.148 L / (0.0821 atm.L/mol.K) × 307.2 K = 0.0123 mol

Answer:

The sodium ion has a stronger affinity for the electron, so more energy is required to move the electron. ... The anion can affect the result of the flame test. For example, a copper(II) compound with a non-halide produces a green flame, while a copper(II) halide yields a blue-green flame

Explanation:

Answer:

Exothermic Reaction

Product  = Calcium hydroxide + hydrogen

Explanation:

The heat required is 2347 J

The heat required for a change of state depends on the substance, the amount of the substance, and the specific change of state involved.

When a substance undergoes a change of state, such as melting or boiling, heat is added or removed to cause the particles in the substance to gain or lose energy and rearrange themselves into a new physical state. The amount of heat required to effect this change is known as the heat of transformation, or the heat of fusion

We know that;

H1 = 25.0 *  0.235 * (962 - 950)

= 70.5 J

H2 = 25 g * 88 J/g

= 2200 J

H3 = 25 * 0.278  * (972 - 962)

=76. 5 J

Then we have that;

70.5 J + 2200 J + 76. 5 J

=2347 J

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The mass of Zn that would be required to completely react with 1.70 L of 0.550 M HCl in the given chemical reaction is 30.38g.

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows;

mass = no of moles × molar mass

According to this question, the following chemical equation is given: Zn(s) + 2HCl(aq) → ZnCl₂ (aq) + H₂(g)

moles of HCl = 1.70 × 0.55 = 0.94 moles

If 1 mole of Zn reacts with 2 moles of HCl, then 0.94 moles of HCl will react with 0.94/2 = 0.47 moles of Zn.

mass of Zn = 0.47 moles × 65g/mol = 30.38g

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1. The IUPAC name of N is nitrogen.

2. Nitrogen dioxide

3.The IUPAC name of O is oxygen

4.The IUPAC name of OH is hydroxyl.

The IUPAC name of ·0 is a radical. It is commonly found in organic chemistry and plays an important role in many reactions.

IUPAC names for the given compounds are:1.1. N: Nitrogen

The IUPAC name of N is nitrogen.

It is a non-metal and belongs to group 15 in the periodic table. It has an electronic configuration of 1s2 2s2 2p3.1.2. NO2: Nitrogen dioxide

Explanation: NO2 is a chemical compound that is formed by the combination of nitrogen and oxygen. It is a reddish-brown gas that has a pungent odor.

The IUPAC name of NO2 is nitrogen dioxide.1.3. O: Oxygen

Explanation: The IUPAC name of O is oxygen.

It is a non-metal and belongs to group 16 in the periodic table. It has an electronic configuration of 1s2 2s2 2p4.

X: UnknownExplanation: No IUPAC name can be given to an unknown compound as the structure and composition are not known.

Y: Hydroxyl Explanation: The IUPAC name of OH is hydroxyl.

It is a functional group that is composed of an oxygen atom and a hydrogen atom (-OH). It is commonly found in alcohols and phenols. ·0: RadicalExplanation: A radical is a molecule or an ion that contains an unpaired electron.

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Note: The complete question is given below

Provide the IUPAC names for the following compounds:

\(CH_3CH_2CH(CH_3)CH_2CH_2CH_2CH_3\)

C6H5CH(CH3)2

H2NCH2CH2CH2CH2CH2NH2

CH3CH2CH2CH2CH2OH

CH3CH2CH2CHOHCH3

The concentration of the H2SO4 solution is 0.080 M.

The concentration of 50.0 ml of a solution of H2SO4 can be found by titrating the acid with a standardized solution of Ba(OH)2. This can be achieved by first preparing a 0.20M solution of Ba(OH)2 by dissolving a known mass of the reagent in distilled water and diluting to the mark. The end point is reached when all the H2SO4 has reacted with Ba(OH)2 and no more acid is left to react with the reagent.When 40.0 ml of 0.20M Ba(OH)2 titrant was added, we can calculate the amount of moles of Ba(OH)2 that reacted with the H2SO4 and use this value to find the concentration of H2SO4. To do this, we can use the following balanced equation:H2SO4 + 2Ba(OH)2 → BaSO4 + 2H2OFrom the balanced equation, we can see that one mole of H2SO4 reacts with two moles of Ba(OH)2. Thus, the number of moles of Ba(OH)2 used in the titration is given by:(40.0/1000) L × (0.20 mol/L) = 0.008 molWe can use the number of moles of Ba(OH)2 used to calculate the number of moles of H2SO4 present in the original solution. Since one mole of H2SO4 reacts with two moles of Ba(OH)2, the number of moles of H2SO4 in the solution is given by:0.008 mol Ba(OH)2 × (1 mol H2SO4 / 2 mol Ba(OH)2) = 0.004 mol H2SO4.The concentration of H2SO4 is then given by dividing the number of moles of H2SO4 by the volume of the solution in liters:0.004 mol / (50.0/1000) L = 0.080 M.

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Answer:

H2SO4(acid), NaOH(base)

Explanation:

By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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ANSWER

The theoretical yield of Fe is 109.64 grams

EXPLANATION

Given that;

The mass of Fe2O3 is 192 grams

The mass of CO is 82.5 grams

Follow the steps below to find the theoretical yield of Iron

Steps 1; Find the number of moles of Fe2O3 and CO using the below formula

Recall, that the molar mass of Fe2O3 and CO are 159.69 g/mol and 28.01 g/mol

Step 2; Determine the limiting raectant of the reaction

To determine the limiting reactant, divide the number of moles by the co-efficient of each reactant

From the calculations, the limiting reactant of the reaction is CO

Step 3; Find the number of moles of Fe using a stoichiometry ratio

Let x represents the number of moles of Fe

The number of moles of Fe is 1.963 moles

Step 4; Find the theoretical yield of Fe

Recall, molar mass of Fe is 55.845 g/mol

Therefore, the theoretical yield of Fe is 109.64 grams

Hi just wanted to say thank you for answering my question and I wanted to help so I believe the answer is A.

Answer:

What are the following substances?

Explanation:

Answer:

since,hydrogen bonding requires a strongly electronegative atom bonded to a hydrogen atom,only HF willexhibit hydrogen bonding,as afluorine is sufficiently partially positive hydrogen that can form bondwith a lone pair an oxygen in water .

Hope this help u

Answer:

a mole is the number of molecules in 22.4 dm³ for all gases at all temperatures and pressures

Answer:

where is the question

Explanation:

Answer:

proton :

a particale or atom containing a postive charge

nuutron

a particale or atom that contains a negative charge

electron :

a particale or atom with a negative chrage.

Explanation:

proton:

a stable subatomic particle occurring in all atomic nuclei, with a positive electric charge equal in magnitude to that of an electron, but of opposite sign.

nuetron:

a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.

elcetron:

a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.

Answer:

The philosophical view of man implies that we are moral as well as intelligence beings. It provides the framework to discover the nature of human excellence embodied by the perennial virtues towards which all men of good will tend.

The difference between the numbers,

(2.260×104)−(8.098×103) = 598.539.

Subtraction is a mathematic operation. Which is used to remove terms or objects in an expression.

Given:

Two numbers,

(2.260×104) and (8.098×103).

First, we simplify the numbers,

(2.260×104) = 235.04

And  (8.098×103) = 833.579.

The difference between the numbers,

(2.260×104)−(8.098×103) = 833.579 - 235.04.

(2.260×104)−(8.098×103) = 598.539

Therefore, then value is 598.539.

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Answer:

0.229 cm³.

Explanation:

The following data were obtained from the question:

Volume (in in³) = 0.014 in³

Volume (in cm³) =?

1 in = 2.54 cm

Next, we shall determine a conversion scale to convert from in³ to cm³. This can be obtained as follow:

1 in = 2.54 cm

Therefore,

1 in³ = 2.54³ cm³

1 in³ = 16.387 cm³

Finally, we shall convert 0.014 in³ to cm³. This can be obtained as follow:

1 in³ = 16.387 cm³

Therefore,

0.014 in³ = 0.014 in³ × 16.387 cm³ / 1 in³

0.014 in³ = 0.229 cm³

Thus, 0.014 in³ is equivalent to 0.229 cm³.