what is the vapor pressure (in torr) of a subtance at 36 c, whose normal boiling point is 84 c and has a delta hvap of 22.1 kj / mo

Answers

Answer 1

The vapor pressure of a substance is 241 Torr that can be calculated using Clausius-Clapeyron relation.

The Clausius-Clapeyron relation is used to characterize a discontinuous phase transition between two phases of the same constituent such as ice. The plot is drawn between 1/T vs ln P.

This equation can be expressed as follows:

ln(P2/P1) = (-ΔHvap/ R)*((1/T2) - (1/T1))

Where T1 is initial temperature, in our case it is normal boiling point = 84oC = 357 K

T2 is final temperature, in our case it is 36oC = 309 K

We know that at normal boiling point the vapor pressure of the substance become equal to the atmospheric pressure = 1 atm.

So P1 = 1 atm. according to our approach to the question.

Now enthalpy of vaporization is given = 22.1 kJ = 22100 J

Now put it in Clausius Clapeyron equation and we will get

ln(P2/ 1 atm.) = (-22100 J / 8.314 J/K-mole)*((1/309 K) - (1/357 K))

P2 /0.317 atm=0.317 x 760 torr = 241 torr

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Related Questions

Which of the following is an ethical question?
A. Do clones have the same rights as humans?
B. Can we clone humans?
C. How do we clone humans?
D. Will cloning technology be useful?

Answers

Answer:

Do clones have the same rights as humans?

Explanation:

This is a question about ethics

The statement that is an ethical question is "Do clones have the same rights as humans?". That is option A.

What is an ethical question?

An ethical question is a type of question that seeks for what the law says about a particular issue.

For example the question:

Do clones have the same rights as humans?: Here, the person wants to know according to the law if clones have the same right as humans.

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Select the answer that best describes an aqueous solution made from each of the following substances:
solid sodium carbonate (Na 2CO 3)
acidic
basic
neutral
cannot tell
none of these (A-D)

Answers

An aqueous solution made from solid sodium carbonate (Na2CO3) would be basic.

The best description for an aqueous solution made from solid sodium carbonate (Na2CO3) is:

Your answer: basic

Sodium carbonate is a salt of a strong base (sodium hydroxide) and a weak acid (carbonic acid). When it dissolves in water, it undergoes hydrolysis and forms sodium hydroxide (NaOH) and carbonic acid (H2CO3). Since sodium hydroxide is a strong base and carbonic acid is a weak acid, the resulting solution will be more basic than acidic, making the aqueous solution basic.

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Which of the following cannot be classified as a mixture
A. Stainless steel
B. Rubbing alcohol
C. Table salt (NaCI
D. Granite

Answers

Answer:

B) Rubbing alcohol

Explanation:

It is a solution

how can you describe the specific heat of olive oil if it takes approximately 420 j of heat to raise the temperature of 7 g of olive oil by ?group of answer choicesgreater than the specific heat of waterless than the specific heat of waterequal to the specific heat of waternot enough information is given.

Answers

The specific heat of olive oil (2 J/g·°C) is less than that of water (4.18 J/g·°C). This indicates that olive oil requires less heat energy to raise its temperature compared to an equal mass of water.

To describe the specific heat of olive oil compared to water, we can use the given information that it takes approximately 420 J of heat to raise the temperature of 7 g of olive oil by 30°C.

The specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius (or Kelvin).

In this case, we can calculate the specific heat of olive oil by dividing the amount of heat (420 J) by the mass (7 g) and the temperature change (30°C):

Specific heat of olive oil = (Amount of heat)/(Mass * Temperature change)

                          = 420 J / (7 g * 30°C)

                          ≈ 2 J/g·°C

Comparing this specific heat value to the specific heat of water (which is approximately 4.18 J/g·°C), we can conclude that the specific heat of olive oil (2 J/g·°C) is less than the specific heat of water. This means that olive oil requires less heat energy to raise its temperature compared to an equal mass of water.

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How can you describe the specific heat of olive oil compared to water if it takes approximately 420 J of heat to raise the temperature of 7 g of olive oil by 30°C?

Study the image.



Which phrase describes this plate boundary?

does not occur in oceans
may form rift valleys
is a type of convergent boundary
is a region where earthquakes occur

Answers

The phrase that describes the plate boundary shown is D. is a region where earthquakes occur .

What is the plate boundary shown ?

A transform boundary is the name given to this tectonic plate boundary. Two or more plates slip past one another in such a border. This shift is typically accompanied by some highly active earthquakes.

At a transform plate border, the grinding motion between the plates causes shallow earthquakes, significant lateral rock displacement, and a wide zone of crustal deformation. Essentially While no new crust is produced, subducted, or formed, and no volcanoes are formed, the fault produces earthquakes.

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Study the image.Which phrase describes this plate boundary?does not occur in oceansmay form rift valleysis

is the smallest non-metal other than noble gases.

Answers

Answer:  T is the smallest non-metal other than noble gases.

Explanation:

How do scientists classify matter
according to their physical and
chemical makeup ?

Answers

Answer:

Matter can be classified according to

physical and chemical properties. Matter is anything that occupies space and has mass. The three states of matter are solid, liquid, and gas. ... Pure substances can be either chemical compounds or elements.

Which phrase describes air pressure?

Which phrase describes air pressure?

Answers

Answer: atmospheric pressure

Explanation:

i hope it helps :)

Answer:

The answer B: decreases as altitude decreases

Hope this helps

how should you write the volume dispensed by a 5 ml volumetric pipet?

Answers

When writing the volume dispensed by a 5 ml volumetric pipet, it should be written as 5.00 mL.

A volumetric pipet is a laboratory instrument utilized to dispense very accurate and precise volumes of liquid. It is commonly used in analytical chemistry to make up solutions or to dilute stock solutions. Volumetric pipettes, also known as transfer pipettes or bulb pipettes, are single-volume liquid measuring instruments. They are meant to deliver a precise volume of liquid at a fixed temperature when the tip is slightly below the liquid surface.

It is important to write the volume with two decimal places to indicate the precision of the pipette.

Volumetric pipettes are utilized to prepare and dilute solutions. They are made of glass, with a round or conical end. They are intended to provide a precise volume of liquid, such as a certain number of milliliters or milligrams of a substance. Because of its accuracy, a volumetric pipet is used to create a standard solution.

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explain with steps plz ​

explain with steps plz

Answers

The given molecule C_12 H_22 O_11 is sucrose.

Sucrose of not dissociable in water hence Vant Hoff factor is 1

i.e

i=1molality=m=0.3k=freezing point constant (As we don't need to find the perfect freezing point let's keep it constant)

\(\boxed{\sf T_f=kmi}\)

T_f is freezing point

For Sucrose

\(\\ \sf\longmapsto T_f=1(0.3)k=0.3k\)

Now.

Let's check Vant Hoff factor of each compound.

AlCl_3=4CuCl_2=3NaCl=2C_6H_12O=1

Let's count Freezing point of each compound.

AlCl_3

m=0.075

\(\\ \sf\longmapsto T_f=0.075(4)k=0.3k\)

CuCl_2

m=0.15

\(\\ \sf\longmapsto T_f=0.15(3)k=0.75k\)

NaCl:-

m=0.3

\(\\ \sf\longmapsto T_f=0.3(2)k=0.6k\)

Glucose:-

m=0.6

\(\\ \sf\longmapsto T_f=0.6k\)

Hence option A is correct

25,000 cg is equal to ___g. (Only input whole number answer.

Answers

Answer:

\(250g\)

Explanation:

Here, we want to convert 25,000 cg to g

Mathematically:

\(1\text{ cg = 0.01 g}\)

Thus, we have it that:

\(\begin{gathered} 25000\text{ cg will be:} \\ 25000\times\text{ 0.01 = 250 g} \end{gathered}\)

In an induced-draft gas furnace, the first component to energize on a call for heat is?

Answers

Answer:

induced draft blower

Explanation:

quizlet

A certain radioactive isotope has a half-life of 5 days. Estimate the percentage of the original amount of the isotope released by the explosion that remains 3 days after the explosion.

Answers

The half-life of a certain radioactive isotope is 5 days. After 3 days, we need to estimate the percentage of the original amount of the isotope that remains.

To find the percentage remaining, we can use the formula: Percentage remaining = (1/2)^(number of half-lives) * 100%
In this case, since 3 days have passed and the half-life is 5 days, we can determine the number of half-lives as: Number of half-lives = 3 days / 5 days = 0.6 half-lives

Plugging this into the formula, we get: Percentage remaining = (1/2)^(0.6) * 100%
Using a calculator, we find that (1/2)^(0.6) is approximately 0.796, so: Percentage remaining = 0.796 * 100% = 79.6%
Therefore, approximately 79.6% of the original amount of the isotope released by the explosion remains 3 days after the explosion.

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The nucleus of a typical atom is 5. 0 fm (1fm=10^-15m) in diameter. A very simple model of the nucleus is a one-dimensional box in which protons are confined. Estimate the energy of a proton in the nucleus by finding the first three allowed energies of a proton in a 5. 0 fm long box

Answers

Therefore, the estimated energies of a proton in a 5.0 fm long box are approximately:

E1 = 1.808 x 10^-13 J

E2 = 7.234 x 10^-13 J

E3 = 1.631 x 10^-12 J

The allowed energies of a particle in a one-dimensional box are given by:

E = (n^2 * h^2) / (8 * m * L^2)

Where:

E is the energy of the particle

n is the quantum number (1, 2, 3, ...)

h is the Planck's constant (approximately 6.626 x 10^-34 J*s)

m is the mass of the particle (mass of a proton = 1.673 x 10^-27 kg)

L is the length of the box (5.0 fm = 5.0 x 10^-15 m)

For n = 1:

E1 = (1^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

For n = 2:

E2 = (2^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

For n = 3:

E3 = (3^2 * (6.626 x 10^-34 J*s)^2) / (8 * (1.673 x 10^-27 kg) * (5.0 x 10^-15 m)^2)

Now we can calculate the values:

E1 ≈ 1.808 x 10^-13 J

E2 ≈ 7.234 x 10^-13 J

E3 ≈ 1.631 x 10^-12 J

Therefore, the estimated energies of a proton in a 5.0 fm long box are approximately:

E1 = 1.808 x 10^-13 J

E2 = 7.234 x 10^-13 J

E3 = 1.631 x 10^-12 J

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HELP PLSSSS!!!



A 3. 0 ml sample of helium gas at STP is


expanded to 6 ml at constant temperature,


What is the new pressure of the gas?



1 atm



2 atm



3 atm



5 atm

Answers

The correct answer is option 2: 2 atm.

To solve this problem, we can use the combined gas law, which states that the ratio of the initial pressure (P1) to the final pressure (P2) is equal to the ratio of the initial volume (V1) to the final volume (V2).

According to the problem, the initial volume (V1) is 3.0 ml, and the final volume (V2) is 6 ml. Since the temperature is constant, the combined gas law simplifies to:

P1 / P2 = V1 / V2

Substituting the given values into the equation, we have:

P1 / P2 = 3.0 ml / 6 ml

Simplifying further, we get:

P1 / P2 = 0.5

To find the new pressure of the gas (P2), we need to determine the reciprocal of the ratio obtained:

P2 = 1 / (P1 / P2) = 1 / 0.5 = 2

Therefore, the new pressure of the gas is 2 atm.

So, the correct answer is option 2: 2 atm.

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Name and title:include your name, instructor's name, date, and name of lab.objectives(s):in your own words, what is the purpose of this lab?hypothesis:in this section, please include the if/then statements you developed during your lab activity. these statements reflect your predicted outcomes for the experiment.if the mass of the sun is 1x, at least one planet will fall into the habitable zone if i place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.if the mass of the sun is 2x, at least one planet will fall into the habitable zone if i place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.if the mass of the sun is 3x, at least one planet will fall into the habitable zone if i place a planet in orbits___, ____, ____, and ____, and all planets will orbit the sun successfully.procedure:the materials and procedures are listed in your virtual lab. you do not need to repeat them here. however, you should note if you experienced any errors or other factors that might affect your outcome.using the summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.data:record your observation statements from space academy.when the mass of the sun is larger, earth moves around the sun at a ______ (faster, slower) pace.when the mass of the sun is smaller, earth moves around the sun at a ______ (faster, slower) pace.when earth is closer to the sun, its orbit becomes _____ (faster, slower).when earth is farther from the sun, its orbit becomes _____ (faster, slower).for each trial, record the orbit number of each planet from the sun. be sure to indicate the number of planets in the habitable zone after each trial. create a different configuration of planets for each trial. an example has been supplied for you. orbit numberplanet one orbit numberplanet two orbit numberplanet three orbit numberplanet four number of planets in the habitable zone number of planets left in successful orbitexample: sun's mass 1x 135612sun's mass 1x—trial one sun's mass 1x—trial two sun's mass 2x—trial one sun's mass 2x—trial two sun's mass 3x—trial one sun's mass 3x—trial two conclusion:your conclusion will include a summary of the lab results and an interpretation of the results. please answer all questions in complete sentences using your own words.using two to three sentences, summarize what you investigated and observed in this lab.you completed three terra forming trials. describe the how the sun's mass affects planets in a solar system. use data you recorded to support your conclusions.in this simulation, the masses of the planets were all the same. do you think if the masses of the planets were different, it would affect the results? why or why not?how does this simulation demonstrate the law of universal gravitation?it is the year 2085, and the world population has grown at an alarming rate. as a space explorer, you have been sent on a terraforming mission into space. your mission to search for a habitable planet for humans to colonize in addition to planet earth. you found a planet you believe would be habitable, and now need to report back your findings. describe the new planet, and why it would be perfect for maintaining human life.

Answers

If the mass of the sun is 1x, at least one planet will fall into the habitable zone if I place a planet in orbits 2, 6, and 75, and all planets will orbit the sun successfully.

If the mass of the sun is 2x, at least one planet will fall into the habitable zone if I place a planet in orbits 84 , 1, and 5, and all planets will orbit the sun successfully.

If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits 672 and 7, and all planets will orbit the sun successfully.

When the mass of the sun is larger, Earth moves around the sun at a faster pace.When the mass of the sun is smaller, Earth moves around the sun at a slower pace.When Earth is closer to the sun, its orbit becomes faster.When Earth is farther from the sun, its orbit becomes slower.

What would occur if the Earth was closer to the sun?

When Earth is closer to the sun, there will be hotter climate. A little movement that takes one closer to the sun could lead to a huge impact.

Due to the fact that there is warming that can make the glaciers to melt, there is an increase in the sea levels and flooding occurs in a lot of areas of the planet and when there is no land to absorb some of the sun's heat, the temperatures on Earth would tend to rise more.

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Name and title:include your name, instructor's name, date, and name of lab.objectives(s):in your own
Name and title:include your name, instructor's name, date, and name of lab.objectives(s):in your own
Name and title:include your name, instructor's name, date, and name of lab.objectives(s):in your own
Name and title:include your name, instructor's name, date, and name of lab.objectives(s):in your own
Name and title:include your name, instructor's name, date, and name of lab.objectives(s):in your own

If the scientists conclude greater cloud cover will reflect more incoming solar radiation, then the result will be decreased temperatures on Earth. According to the diagram, what type of feedback mechanism is this?

A. Positive
B. Negative

Answers

Answer:

Positive feedback

Explanation:

If the temperature on Earth starts to lower then a "positive feedback" will start to begin trying to make Earth heat up.

Clouds can trap that heat from the Sun therefore the clouds wrap Earth in a blanket. Therefore clouds have both a cooling effect as well as a warming effect.

What are solar radiations?

Solar radiation makes it from our sun to the Earth and through the atmosphere. Solar radiation refers to electromagnetic waves or light. Solar radiation comes in three major classes: visible light, infrared light, and ultraviolet light.

The full electromagnetic spectrum features 7 types of light from lowest frequency to highest: radio waves, microwaves, infrared light, visible light, UV light, X-rays, and γ-rays. The ozone layer in the atmosphere prevents the passage of UV light through it.

The human eyeball can only detect visible light. The ultraviolet, "beyond violet," is invisible. The solar radiation coming from the sun can increase the temperature of the earth. The clouds prevent them to reach the surface. Therefore, it is positive feedback.

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invented by Bernard Launy and Jeremie Metz, and identify the flaws in the system in terms of energy inputs and outputs.

Answers

Invented by Bernard Launy and Jeremie Metz, flaws in the system in terms of energy inputs and outputs is the overbalanced wheel in which spokes are attached

Energy is the ability to do work to cause changes in matter

The overbalanced wheel perpetual motion machine is one of the most commonly proposed perpetual motion machine designed and wheel is designed to turn clockwise just after the weighted spoke reaches the top of the wheel and the spoke flip outward to the right exerting the force downward toward the ground and some energy will be lost from friction as the mechanism rub on the inner spoke and more energy will be lost when it transferred into sound and thermal energy

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Use the solubility curve to answer to answer the following question. Determine the solubility of KCl at 60 °C in 100g of H2O?

45 g

100 g

24 g

39 g

Answers

a unique set of solubility curves is used to illustrate the relationship between a substance's solubility and temperature or pressure. solubility curves are employed in sectors like food, pharmaceuticals, and chemical manufacture.

A graph illustrating the relationship between a substance's solubility and temperature or pressure is called a solubility curve. The solubility (measured in grammes of solute per 100 grammes of solvent) is often plotted versus temperature (or pressure) on the x-axis in solubility curves, which are particular to each solute and solvent system. The solubility of a substance changes with temperature or pressure, and this fact makes solubility curves crucial in the study of chemistry and related subjects. They can be used to forecast how a solution will behave under certain situations, such as whether a solute will dissolve or precipitate out of solution. Moreover, solubility curves are employed in sectors like food, pharmaceuticals, and chemical manufacture.

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Answer: 24g

Explanation: bc

An ethylene glycol solution contains 30.8 g of ethylene glycol (C2H6O2) in 96.6 mL of water. (Assume a density of 1.00 g/mL for water.) Determine the freezing point of the solution. Determine the boiling point of the solution

Answers

The freezing point of the solution is -11.8 °C.

The boiling point of the solution is 103.31 °C.

To determine the freezing point of the solution, we can use the equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression,

Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),

m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the solution:

Molar mass of ethylene glycol (C2H6O2):

C = 12.01 g/mol

H = 1.01 g/mol (x 6) = 6.06 g/mol

O = 16.00 g/mol (x 2) = 32.00 g/mol

Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol

Number of moles of ethylene glycol (C2H6O2) = mass / molar mass

Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol

Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g

Now, let's calculate the molality:

Molality (m) = moles of solute / mass of solvent (in kg)

Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg

Now we can calculate the freezing point depression (ΔTf):

ΔTf = Kf * m

ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C

To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):

Freezing point = 0 °C - 11.8 °C = -11.8 °C

To determine the boiling point of the solution, we can use the equation:

ΔTb = Kb * m

where:

ΔTb is the boiling point elevation,

Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),

m is the molality of the solution (same value as calculated before: 6.36 mol/kg).

ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C

To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):

Boiling point = 100 °C + 3.31 °C = 103.31 °C

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for the titration of 50.0 ml of 0.020 m aqueous salicylic acid with 0.020 m koh(aq), calculate the ph after the addition of 55.0 ml of koh(aq). for salycylic acid, pka = 2.97.

Answers

In the titration of 50.0 ml of 0.020 M aqueous salicylic acid with 0.020 M KOH(aq), the pH after the addition of 55.0 ml of KOH(aq) can be calculated.

Salicylic acid is a weak acid with a pKa value of 2.97.  After the addition of 55.0 ml of KOH(aq), the solution will contain an excess of OH- ions due to the neutralization reaction between salicylic acid and KOH. The OH- ions will react with the weak acid, converting it to its conjugate base, salicylate. The pH of the resulting solution will depend on the relative concentrations of the acid and its conjugate base, as well as the pKa value.

To calculate the pH, we need to determine the concentrations of the acid and its conjugate base. The initial moles of salicylic acid can be calculated using the given volume and concentration. Since the acid and base react in a 1:1 ratio, the moles of KOH added will be equal to the moles of salicylic acid at the equivalence point.

Next, we calculate the moles of salicylic acid remaining after the reaction. Since 55.0 ml of KOH(aq) is added to the initial 50.0 ml of salicylic acid, the total volume becomes 105.0 ml. We subtract the moles of KOH added from the initial moles of salicylic acid to find the moles of salicylic acid left.

Using the moles of salicylic acid and its conjugate base, we can determine their concentrations. The concentration of the acid is obtained by dividing the moles of acid remaining by the final volume of the solution. The concentration of the conjugate base is determined in a similar manner.

Finally, we can calculate the pH using the Henderson-Hasselbalch equation:

pH = pKa + log10([conjugate base]/[acid])

Substituting the calculated values, we can find the pH of the solution after the addition of 55.0 ml of KOH(aq) to the titration of salicylic acid.

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The number of electrons in ATOM 1 is ______

The number of electrons in ATOM 1 is ______

Answers

3 electrons because electrons are negative and theirs 3 negative signs

There are 25 elements found in living things. How many of these elements are found in some organisms but not all?
O1
O 6
O 19
O 25

Answers

I think 25 is the solve
I think 25..........

What volume of oxygen will react with 50cm^3 of nitrogen monoxide?

Answers

Answer:

GIVE BRAINLIEST PLEASE!!!  Answer - 50cm^3 of oxygen

Explanation:

They need (almost) equal amounts of substance to react

hope this helps <3

A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?​

Answers

Answer:

0.14 kg

Explanation:

The mass of the ball can be found by using the formula

\(m = \frac{2k}{ {v}^{2} } \\ \)

v is the velocity

k is the kinetic energy

From the question we have

\(m = \frac{2(3.10)}{ {6.70}^{2} } = \frac{6.20}{44.89} \\ = 0.138115...\)

We have the final answer as

0.14 kg

Hope this helps you

Element m reacts with fluorine to form an ionic compound with the formula mf4. the m cation has 18 electrons. element m is:____.

Answers

Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

What is Ionic Compound ?

An ionic compound is defined as the compound made up of ions that formed charge particles when an atom loses or gains electrons.

What is Cation ?

Cations are positively charged ions. It forms when an element lose one or more electrons.

The cation which has 18 electrons is Sn. Sn react with fluorine to form an ionic compound with the formula SnF₄ because Sn is large and F is very small in size.

Thus from the above conclusion we can say that Element M reacts with fluorine to form an ionic compound with the formula MF₄. The M cation has 18 electrons. Element M is Sn.

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Urgent!! will give brainliest!!

define an arrhenius acid and describe the properties of acids. use an example to explain how an arrhenius acid will behave when dissolved in water.

Answers

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons.

What is an Arrhenius acid?

An Arrhenius acid increases the number of\(H^+\) ions in the water.

According to the Arrhenius theory, a substance which has hydrogen atom and can easily give hydrogen ion or proton in its aqueous solution is called as Arrhenius acid.

For example, when hydrochloric acid is dissolved in water, it forms chloride ion (\(Cl^-\)) and hydronium ion (\(H_3O^+\)).

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In the reaction 2Li(s) + 2H2O(I) -> 2LiOH(aq) + H2(g), which compound is in the aqueous state?

A. Li

B. H2O

C. LiOH

B. H2

Answers

Answer:

LiOH

Explanation:

LiOH has the tag "aq" which stands for aquatic.

Our answer is LiOH.

What is a way in which nuclear fusion is used?

Answers

Answer:It is a nuclear process, where energy is produced by smashing together light atoms. It is the opposite reaction of fission, where heavy isotopes are split apart.

Explanation Fusion is the process by which the sun and other stars generate light and heat.

It’s most easily achieved on Earth by combining two isotopes of hydrogen: deuterium and tritium. Hydrogen is the lightest of all the elements, being made up of a single proton and a electron. Deuterium has an extra neutron in its nucleus; it can replace one of the hydrogen atoms in H20 to make what is called “heavy water.”

How does the larvae and pupae survive in water?


Please I need an answer immediately.​

Answers

Larvae and pupae of aquatic insects have adapted to living in water through a variety of mechanisms that enable them to breathe, feed, and protect themselves from predators. Here are some ways that larvae and pupae survive in water:

1. Respiration: Many aquatic insects have specialized structures called gills or tracheal gills that allow them to extract oxygen from the water. These structures can be external or internal and are adapted to the specific needs of each species.

2. Feeding: Aquatic insect larvae and pupae have adapted to feeding on a variety of food sources in the water, including algae, detritus, and other small organisms. Some species have specialized mouthparts or appendages that help them capture and consume their prey.

3. Movement: Larvae and pupae of aquatic insects have adapted to move through water using a variety of mechanisms, including swimming, crawling, and burrowing. Some species have specialized structures such as hooks or suction cups that enable them to move through the water more efficiently.

4. Protection: Aquatic insect larvae and pupae have developed a variety of mechanisms to protect themselves from predators, including camouflage, spines, and the ability to release noxious chemicals.

Overall, larvae and pupae of aquatic insects have adapted to living in water through a variety of mechanisms that enable them to survive and thrive in their aquatic environments.
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