What is the value of x ?

The domain and the range of the function F(x) = \(e^x\) will be domain is all real numbers and the range is y > 0. The correct option is C.

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x).

A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values.

Given function  \(e^x\) when we plot the graph of the function it is observed that all the graph of the function varies in the positive part of y. The ranges of the function lie at y > 0 and the domain will be all the real numbers.

Therefore the domain and the range of the function F(x) = \(e^x\) will be domain is all real numbers and the range is y > 0. The correct option is C.

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The first step is converting both the velocity and the wind in vector form, as follows:

Then the true speed of the plane is given by the addition of these two vectors, as follows:

\(\vec{v_1} + \vec{v_2} = \sqrt{|v_1|^2 + |v_2|^2 + 2 \cdot |v_1| \cdot |v_2| \cdot \cos(\theta)}\)

The magnitudes of each vector are given as follows:

The angle between these two vectors is given as follows:

\(\theta = 100^\circ - 42^\circ = 58^\circ\)

Thus the resulting speed is obtained as follows:

\(\vec{v_1} + \vec{v_2} = \sqrt{180^2 + 30^2 + 2 \cdot 180 \cdot 30 \cdot \cos(58^\circ)} = 197.54\)

The resulting angle of the plane is then obtained as follows:

\(\angle = \arctan\left(\frac{|v_1| \cdot \sin(\theta) + |v_2| \cdot \sin(\theta_2)}{|v_1| \cdot \cos(\theta) + |v_2| \cdot \cos(\theta_2)}\right)\)

Hence:

\(\angle = \arctan\left(\frac{180 \cdot \sin(58^\circ) + 30 \cdot \sin(42^\circ)}{180 \cdot \cos(58^\circ) + 30 \cdot \cos(42^\circ)}\right)\)

\(\angle = 59.87^\circ\)

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Answer:

  197.5 km/h

Step-by-step explanation:

You want the resultant speed with an airplane at a speed of 180 km/h at 100° is acted upon by a wind at a speed of 30 km/h at 42°. Angles are bearings CW from north.

A vector calculator makes short work of this. The resultant speed is ...

  197.5 km/h at 92.6°

The law of cosines can be used to find the side opposite the known angle in the triangle with sides 30 km/h and 180 km/h. The known angle is ...

  180° -(100° -42°) = 122°

So, the resultant speed is ...

  c = √(a²+b²-2ab·cos(C))

  = √(30² +180² -2(30)(180)·cos(122°)) ≈ √39023.13

  c ≈ 197.543

The true speed of the plane is about 197.5 km/h.

__

Additional comment

You will notice that we used bearing angles directly in the calculator computation. As long as angles are consistently measured, it doesn't matter how they're measured.

When plotting the vectors on the Cartesian plane, we need to subtract the bearing angles from 90° to make them correspond to the vectors plotted on a map with north at the top.

a) The zero rates for the five maturities are: 1 year is 2.01%, 2 years is 2.48%, 3 years is 2.77%, 4 years is 1.73%, and 5 years is 4.32%.

b) The price of the security is $128.31.

a) To find the zero rates for all 5 maturities, we can use the formula for the present value of a bond:

PV = C / \((1+r)^n\)

where PV is the present value,

C is the coupon payment,

r is the zero rate, and

n is the number of years to maturity.

We can solve for r by rearranging the formula:

r = \((C/PV)^{(1/n) }\)- 1

Using the bond data given in the question, we can calculate the zero rates for each maturity as follows:

For the 1-year bond, PV = 98 and C = 0, so r = 2.01%.

For the 2-year bond, PV = 101, C = 2.48, and n = 2, so r = 2.48%.

For the 3-year bond, PV = 103, C = 2.91, and n = 3, so r = 2.77%.

For the 4-year bond, PV = 101, C = 2, and n = 4, so r = 1.73%.

For the 5-year bond, PV = 103, C = 5, and n = 5, so r = 4.32%.

Alternatively, we can use linear algebra to find the zero rates. We can write the present value equation in matrix form:

PV = A × x

where A is a matrix of coefficients, x is a vector of unknowns (the zero rates), and PV is a vector of present values.

To solve for x, we can use the equation:

x = (\(A^{-1}\)) x PV

where (\(A^{-1}\)) is the inverse of matrix A.

Using this method, we can solve for the zero rates as follows:

[2.01% ]

[2.48% ]

[2.77% ] = x

[1.73% ]

[4.32% ]

PV = \(A^{-1}\) x  [98]

                   [101]

                   [103]

                   [101]

                   [103]

PV =   [-0.0201]

          [ 0.0248]

          [ 0.0277]

          [-0.0173]

          [ 0.0432]

b) To find the price of the security which pays cash flows of $10 in one year, $25 in two years, and $100 in four years, we can use the formula for the present value of a series of cash flows:

PV = \(C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^4\)

where PV is the present value, C1, C2, and C3 are the cash flows, r is the zero rate, and the exponents correspond to the number of years until each cash flow is received.

Using the zero rates calculated in part (a), we can calculate the present value of each cash flow:

PV1 = $10 /(1+2.01 % \()^1\) = $9.80

PV2 = $25/(1+2.48%\()^2\) = $22.15

PV3 = $100/(1+1.73%\()^4\) = $81.36

Then, the price of the security is the sum of the present values:

PV = $9.80 + $22.15 + $81.36 = $128.31

Therefore, the price of the security is $128.31.

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Answer:

3/10  yds ^2

Step-by-step explanation:

To find the area, multiply the length times the width

A = l*w

   = 3/8 * 4/5

Rearranging

   = 3/5 * 4/8

Simplify

   = 3/5 * 1/2

   = 3/10  yds ^2

To find the median d of set M, we first need to arrange the numbers in ascending order and then determine the middle value. Set M contains the numbers 37, 45, 7, 12, 21, 22, and n. We know n is a positive integer.

First, arrange the known numbers: 7, 12, 21, 22, 37, 45. Next, consider the position of n in the sorted sequence:

1. If n ≤ 7, the sorted sequence becomes: n, 7, 12, 21, 22, 37, 45.
2. If 7 < n ≤ 12, the sorted sequence becomes: 7, n, 12, 21, 22, 37, 45.
3. If 12 < n ≤ 21, the sorted sequence becomes: 7, 12, n, 21, 22, 37, 45.
4. If 21 < n ≤ 22, the sorted sequence becomes: 7, 12, 21, n, 22, 37, 45.
5. If 22 < n ≤ 37, the sorted sequence becomes: 7, 12, 21, 22, n, 37, 45.
6. If 37 < n ≤ 45, the sorted sequence becomes: 7, 12, 21, 22, 37, n, 45.
7. If n > 45, the sorted sequence becomes: 7, 12, 21, 22, 37, 45, n.

Since there are 7 numbers in the set, the median d will be the 4th value. In all cases, the 4th value remains 21. Therefore, the value of d is 21.

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The population of Pakistan is calculated as; 1.82 × 10⁸

The parameters for the population are;

Japan Population; J = 1.30 × 10⁸

Brazil Population; B = 1.95 × 10⁸

Now, the ratio of J:B = x : x + 5

Thus;

(1.30 × 10⁸)/(1.95) × 10⁸ = x/(x + 5)

Solving this gives x = 10

Now, we are told that;

J:P = x : x + 4

Where P is pakistan population

Thus;

(1.30 × 10⁸)/P = 10/(10 + 4)

(1.30 × 10⁸)/P = 10/14

P = 14(1.30 × 10⁸)/10

P = 1.82 × 10⁸

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Answer:

3.3m each day.

Step-by-step explanation:

The equation will be 18.2 = 5 + 4m18.2=5+4m

Solve for m to get 4m = 13.24m=13.2

m = 3.3m=3.3

She would have to ride 3.3 miles each day to meet her goal.

Answer: 3.3 miles per day

Step-by-step explanation: 13.2/ 4=3.3

Answer:

d

Step-by-step explanation:

Using the probability distribution, the probability that x exceeds 4 is 0.51

To find the probability that x exceeds 4, we need to sum the probabilities of all the values in the distribution that are greater than 4.

Given the discrete probability distribution:

x |  3  4  7  9

P(X)| 0.18 ? 0.22 0.29

We can see that the probability for x = 4 is not specified (?), but we can still calculate the probability that x exceeds 4 by considering the remaining values.

P(X > 4) = P(X = 7) + P(X = 9)

From the distribution, we can see that P(X = 7) = 0.22 and P(X = 9) = 0.29.

Therefore, the probability that x exceeds 4 is:

P(X > 4) = 0.22 + 0.29 = 0.51

Hence, the probability that x exceeds 4 is 0.51, or 51%.

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Answer: directrix.

hoped this helped lmk if it did

Answer:

She earned $288 this week

Step-by-step explanation:

x = 12

Work = 2(12) + 8

24 + 8 = 32 hours

Earned = (12) - 3 = 9 per hour

32 × 9 = $288

I hope this helps!

The explicit formula for the nth term of the sequence 14,16,18,... is aₙ = 2n + 12.

What is an explicit formula?

The explicit equations for L-functions are the relationships that Riemann introduced for the Riemann zeta function between sums over an L-complex function's number zeroes and sums over prime powers.

Here, we have

Given:  the sequence 14,16,18,….

First term a₁ = 14

Common difference d = 16 - 14 = 2

Now, plug the values into the above formula and simplify.

aₙ = a₁ + d( n - 1 )

aₙ = 14 + 2( n - 1 )

aₙ = 14 + 2n - 2

aₙ = 14 - 2 + 2n

aₙ = 2n + 12

Hence,  the explicit formula is aₙ = 2n + 12.

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Answer:

-5.5.

Step-by-step explanation:

The negative numbers are less than the positive and -5.5 is less than -5.

Answer:

Area of sector DFE = 177.79cm²

Area of sector DGE = 437.65cm²

Step-by-step explanation:

Find the diagram attached;

Area of the sector is expressed according to the formula;

Area of the sector = theta/360 * πr²

theta is the central angle = 360 - 256

theta = 104°

r is the radius = 14cm

Substitute into the formula as shown;

Area of the sector = theta/360 * πr²

Area of the sector DFE = 104/360 * 3.14(14)²

Area of the sector DFE = 0.289 * 615.44

Area of the sector DFE = 177.79cm²

Hence the area of the sector <DFE to the nearest hundredth is 177.79cm²

For sector DGE:

Area of the sector DGE = 256/360 * 3.14(14)²

Area of the sector DGE = 0.7111 * 615.44

Area of the sector DGE = 437.65cm²

Hence the area of the sector <DGE to the nearest hundredth is 437.65cm²

у вас всё правильно вы молодцы

the required probability is 0.5668

Given that the distribution of the time it takes for the first goal to be scored in a hockey game is known to be extremely right-skewed with population mean 12 minutes and population standard deviation 8 minutes.

We need to find the probability

that in a random sample of 36 games, the mean time to the first goal is more than 15 minutes.To find this probability, we will use the z-score formula.z = (x - μ) / (σ / √n)wherez is the z-scorex is the sample meanμ is the population meanσ is the population standard deviationn

is the sample sizeGiven that n = 36, μ = 12, σ = 8, and x = 15, we havez = (15 - 12) / (8 / √36)z = 1.5Therefore, the probability that in a random sample of 36 games, the mean time to the first goal is more than 15 minutes is P(z > 1.5).We can find this probability using a standard normal table or a calculator.Using a standard normal table, we can find the area to the right of the z-score of 1.5. This is equivalent to finding the area between z = 0 and z = 1.5 and subtracting it from 1.P(z > 1.5) = 1 - P(0 < z < 1.5)Using a standard normal table, we find thatP(0 < z < 1.5) = 0.4332Therefore,P(z > 1.5) = 1 - 0.4332 = 0.5668Therefore, the probability that in a random sample of 3games, the mean time to the first goal is more than 15 minutes is 0.5668 (rounded to four decimal places).

Hence, the required probability is 0.5668.

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The probability that in a random sample of 36 games, the mean time to the first goal is more than 15 minutes is approximately 0.0122 or 1.22%.

The probability that in a random sample of 36 games, the mean time to the first goal is more than 15 minutes can be determined using the Central Limit Theorem (CLT).

According to the CLT, the distribution of sample means from a large enough sample follows a normal distribution, even if the population distribution is not normal. In this case, since the sample size is 36 (which is considered large), we can assume that the sample mean follows a normal distribution.

To find the probability, we need to standardize the sample mean using the population mean and standard deviation.

First, we calculate the standard error of the mean, which is the population standard deviation divided by the square root of the sample size. In this case, it would be 8 / √36 = 8 / 6 = 4/3 = 1.3333.

Next, we calculate the z-score, which is the difference between the sample mean and the population mean divided by the standard error of the mean. In this case, it would be (15 - 12) / 1.3333 = 2.2501.

Finally, we use the z-table or a calculator to find the probability associated with a z-score of 2.2501. The probability is the area under the standard normal curve to the right of the z-score.

Using a z-table, we find that the probability is approximately 0.0122. This means that there is a 1.22% chance that the mean time to the first goal in a random sample of 36 games is more than 15 minutes.

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Answer:

y=5x

Step-by-step explanation:

If y is 25 and x is 5

25 = 5 (5)

25=25

Answer:

18 inches of ribbon

Step-by-step explanation:

that is the procedure above

Answer:

it depends on the choices

Step-by-step explanation:

The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .

The charge at which anything happens is referred to as the velocity at which it happens.

The required details for mean rate :

(a) H0: µ = 21.62

Ha: µ ≠ 21.62

(b) t = -1.231

p-value = 0.2253

(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.

(d) H0: µ = 21.62

Ha: µ ≠ 21.62

t = -1.231

check statistic ≥ 2.020

Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.

The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.

The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.

The crucial values for t at this level of significance are t=2.019.

Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.

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Answer:

y = 4x-9

Step-by-step explanation:

The slope is 4

To find the (change in y) divided by the (change in x) or (\(\frac{rise}{run}\))

which is 4/1

Next, find the y-intercept which is -9

then put those numbers into the equation

[Answer] y = 4x-9

PLEASE RATE!! I hope this helps!!

(If you have any questions comment below)

Answer:

w+8²

p+30÷p²

4(9+y)

Step-by-step explanation:

Answer:

Answers are below.

Step-by-step explanation:

1. \(C^{3}\)

2. A + C / 3

Second exercise:

1. w + (8 x 2)

2. 30 + p / p

3. 4 (9 + y)

hope this helps and is right :) p.s. i really need brainliest.

if my answers are wrong, then i am incredibly sorry!

Answer:

you must be so stiupid that you have to use answers ff a website to cheat for school

Step-by-step explanation:

She just run 25 miles in the 4th week

Since the runner wants to have an average of 22 miles per week in 4 weeks, then the total miles that she must run will be:

= 22 × 4

= 88 miles

We will then add the total number of miles for the first 3 weeks. This will be:

= 20 + 22 + 21

= 63 miles

Then, the number of miles needed for the 4th race will be:

= 88 miles - 63 miles

= 25 miles

Therefore, she must run 25 miles in the 4th week.

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Answer:

None of the above if there is that answer because one is 4 times and the other is 4 to the x power which is exponential

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

lol I'll take the hottie bit XDDDD

the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

To write the system of ordinary differential equations (ODEs) for the transition probabilities Pᵢⱼ(t) of the given continuous-time Markov chain, we need to consider the rate at which the system transitions between different states.

Let Pᵢⱼ(t) represent the probability that the Markov chain is in state j at time t, given that it started in state i at time 0.

The ODEs for the transition probabilities can be written as follows:

dP₁₂(t)/dt = q₁₂ * P₁(t) - q₂₁ * P₂(t)

dP₁₃(t)/dt = q₁₃ * P₁(t) - q₃₁ * P₃(t)

dP₂₁(t)/dt = q₂₁ * P₂(t) - q₁₂ * P₁(t)

dP₂₃(t)/dt = q₂₃ * P₂(t) - q₃₂ * P₃(t)

dP₃₁(t)/dt = q₃₁ * P₃(t) - q₁₃ * P₁(t)

dP₃₂(t)/dt = q₃₂ * P₃(t) - q₂₃ * P₂(t)

where P₁(t), P₂(t), and P₃(t) represent the probabilities of being in states 1, 2, and 3 at time t, respectively.

Now, let's consider the second part of the question: Suppose that the initial state is 1. We want to find the probability that after the first transition, the process X(t) enters state 2.

To calculate this probability, we need to find the transition rate from state 1 to state 2 (q₁₂) and normalize it by the total rate of leaving state 1.

The total rate of leaving state 1 can be calculated as the sum of the rates to transition from state 1 to other states:

total_rate = q₁₂ + q₁₃

Therefore, the probability of transitioning from state 1 to state 2 after the first transition can be calculated as:

P(X(t) enters state 2 after the first transition | X(0) = 1) = q₁₂ / total_rate

In this case, the transition rate q₁₂ is 1, and the total rate q₁₂ + q₁₃ is 1 + 2 = 3.

Therefore, the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

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Answer:

Step-by-step explanation:

Yes, it is equal

2 (5y - 2) =

2 x 5y - 2 x 2 -

10y -4

Hope that helps!