what is the thinnest film of mgf2 ( n = 1.39 ) on glass that produces a strong reflection for orange light with a wavelength of 615 nm ? express your answer with the appropriate units.

As we observe the Activity 1-1 we can make observations while interactions of magnetic poles with various objects using magnets.

If objects like aluminum foil or coins or paper clips can be test by a magnet and can see if they are attracted to or repelled by the magnet.

We can also observe the strength of magnetic force. To do this we will make changes in distance between the magnet and the object

If we are considering Activity 1-2 there also we can make observations while interactions of magnetic poles with various objects

We can brought the two magnets together and observe if they attract or repel each other. We can make observations.

We will observe the interaction between magnets with the distance between them.

We will observe the behavior of magnetic poles also- with opposite poles and with like poles. Similarities and differences in their interactions.

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At speed of about, 6.38 m/s, a bicycle and its rider, with a combined mass of 110 kg , will have the same momentum as a 1300 kg car traveling at 5.4 m/s.

:: Combined mass of rider and bicycle = 110 kg

:: Mass of car = 1300 kg

:: Speed of car = 5.4 m/s

:: Required speed of bicycle = V(assume)

By law of conservation of momentum,

m1 x v1 = m2 x v2,

where, m1 &m2 are masses of bodies, and v1 & v2 are their respective velocities.

Therefore, on putting values, we get,

(1300kg x 5.4m/s) = (110kg x V m/s)

V = (7020 / 110) m/s

V ≈ 6.38 m/s

Therefore, the required speed of bicycle is 6.38 m/s.

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The collision mean free path would be λ = vτ = 8.60 x \(10^{5}\) x 2.27 x \(10^{-14}\) = 1.95 x \(10^{-8}\) m.

What is collision mean free path?

The collision mean free path of electrons in copper can be calculated using data from Example 27.1. The average thermal speed of conduction electrons is given as 8.60 x 10 m/s.

Example 27.1 states that the resistivity of copper is ρ = 1.7 x \(10^{-8}\) Ωm. The resistivity is related to the electron mobility, µ, and the electron number density, n, by the formula:ρ = 1/(neµ).

Solving for n:ρ = 1/(neµ)n = 1/(eµρ): The electron mean free path, λ, is given by: λ = vτ where v is the average thermal speed of the electrons and τ is the average time between collisions. τ is related to electron mobility by:µ = eτ/m where m is the mass of the electron.

Combining the above equations: n = 1/(eµρ) = m/(\(e^{2}\)τρ). Using the value of resistivity, we get: n = m/(\(e^{2}\)τρ) = (9.1 x \(10^{-31}\))/(1.6 x \(10^{-19}\))² x (4.2 x \(10^{-8}\))/(1.7 x \(10^{-8}\)) = 8.47 x \(10^{28}\) electrons/m³.

Using the value of average thermal speed, we get: v = 8.60 x \(10^{5}\) m/s

The electron mobility is given by:µ = (ne/ρ) = (8.47 x \(10^{-8}\) x 1.6 x \(10^{-19}\))/(1.7 x \(10^{-8}\)) = 8.02 x \(10^{-4}\) m²/Vs.

Using mobility, we can find the average time between collisions:

τ = mµ/e² = (9.1 x \(10^{-31}\))/(1.6 x \(10^{-19}\))² x 8.02 x \(10^{-4}\) = 2.27 x \(10^{-14}\) s. Therefore, the collision mean free path will be equal to λ = vτ = 8.60 x \(10^{5}\) x 2.27 x \(10^{-14}\)= 1.95 x \(10^{-8}\) m.

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There are some traits of successful entrepreneurs, these are as follows:

1. He should be a highly motivated towards the work.

2. He sholud be creative in nature. He should think out of box and develop some ideas for the problem.

3. He should have clear vision for the future.

4. He should be very versatile and ready to adapt any changes.

5. He should be ready to take some risk.

6. He should have the ability of decision making and leadership quality.

Answer:

BTS was the biggest fandom in 2020

Answer:

Explanation:

gurl bye ash its def the weebs or the bts the bts wanted lady gaga ded

Answer:

reflection of the moon, or just reflection

Explanation:

when the sunlight hits the moon, it refects back to earth making the moon appear to glow          

Answer:

reflecting

Explanation:

the sun's light reflects off the moon, making the moon visible

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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Quantum computers can factor numbers using an algorithm called Shor's algorithm.

This algorithm takes advantage of the properties of quantum mechanics, specifically the ability of quantum bits (qubits) to exist in multiple states simultaneously. Shor's algorithm works by transforming the problem of factoring large numbers into the problem of finding the period of a mathematical function. The algorithm then uses a quantum Fourier transform to determine the period, which can be used to find the factors of the original number.

While classical computers would take an impractical amount of time to factor large numbers, quantum computers using Shor's algorithm can perform these calculations exponentially faster. This makes quantum computers particularly useful for cryptography and other applications that involve large numbers.

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When thrown from the balloon, the sandbag has a constant horizontal/forward velocity. As the text puts it, "the sandbag continues forward as if it had not been dropped." What this means is that the sandbag has no acceleration in the horizontal plane of motion, so it moves in this direction at a constant speed. So for any time \(t\), the horizontal velocity is given by

\(v_x(t) = 12\dfrac{\rm m}{\rm s}\)

In the vertical plane of motion, the sandbag has no vertical velocity until it's released and allowed to fall. As it's falling, however, the sandbag is being pulled down by gravity and is accelerating with magnitude \(g=9.8\frac{\rm m}{\mathrm s^2}\), so its vertical/downward velocity at time \(t\) is given by

\(v_y(t) = -gt\)

So, after 3 seconds have passed, the sandbag has horizontal velocity \(v_x = 12\frac{\rm m}{\rm s}\) and vertical velocity \(v_y = -g(3\,\mathrm s) = -29.4\frac{\rm m}{\rm s}\). If the question is specifically asking about speed you would just ignore the negative signs.

The wavelength of the signal of the state trooper's car sending a radar signal at a frequency of 14.6 GHz is 2.05 × 10⁻² m.

Wavelength is the separation between two consecutive waves corresponding points. When two points or particles are referred to be "corresponding points," it means that they are both in the same phase and have completed exactly the same portions of their periodic motion.

Wavelength is typically measured from crest to crest or from trough to trough in transverse waves (waves with points vibrating at right angles to the direction of their advance); from compression to compression or from rarefaction to rarefaction in longitudinal waves (waves with points vibrating in the same direction as their advance).

The following equation describes how a wave's frequency and speed are related to its wavelength:

λ =\(\frac{v}{f}\)

where,

λ is the wavelength

v is the speed of the wave

f is its frequency

 The radio signal of the car has a frequency of:

f= 14.6GHz = 14.6 × 10⁹ Hz

and a speed of:

v = 2.998 × 10⁻² m/s

Substituting the values:

λ = 2.02 × 10⁻² m

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yes

Explanation:

the endorsment is successful because Jordan shoe is a imported brand

According to the solving the work done by the boy against the force of gravity is mgh.

The curvature of space and time caused by huge objects is what causes gravity, which is essentially geometry. The degree to which a coordinate within space-time is invisibly bent determines the strength of something like the gravitational "field" at any given place in time or space. Massive items slide down these curves in the direction of one another.

Yes, there is gravity, but not in the way you might think of it. In other words, gravity does not interact directly, typically, or at a distance between two objects. However, gravity is a force in a more general sense since it symbolizes the interaction that takes place when two masses are close to one another.

The mass of the boy, m

The height of the stair, h

We know that :

F = mg

The displacement in the upward direction

S = -h

The work done by the force of gravity on boy.

W = Fs

  = mg(-h)

   = -mgh

According to the solving the work done by the boy against the force of gravity is mgh.

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Answer:

A mass driver or electro magnetic catapult is a proposed method of non-rocket space launch which would use a linear motor to accelerate and catapult payloads up to high speeds. All existing and contemplated mass drivers use coils of wire energized by electricity to make electromagnets.

Explanation:

may i be marked brainliest?

Answer:

The correct option is b: A solute depresses the freezing point because the solute disrupts the crystal formation of the solvent.

Explanation:

The depression of the solvent's freezing point is caused by the addition of a solute because the presence of the molecules of the solute interferes in the arrange and close up of the molecules of the solvent to form the crystal of the solid.

The attraction of the solute molecules to the solvent molecules interfere with the formation of the solid, so the solution must be cooled to a lower temperature so it can form the solid.

Hence, the correct option is b: A solute depresses the freezing point because the solute disrupts the crystal formation of the solvent. The other options are incorrect.

I hope it helps you!              

Answer:

F = Q V X B

V X B = south X downard = East - deflection is West

Since Q is negative the deflection = West

a = F / m = Q V B / m

a = 1.6E-19 * 5*E6 * 3.5E-5 / 9.1E-31

a = 1.6 * 5 * 3.5 / 9.1 * 10^13 m/s^2 = 3.1 * 10^13 m/s^2

Answer:

At 23.5 deg north of the equator this person would see the sun directly overhead at the summer solstice at noon

Answer:

force

Explanation:

Force is a push or a pull of an object that causes the object to speed up, slow down, or stay in one place. In other words, a force is what causes an object to move. Friction and gravity are two types of forces that influence how an object moves.

Drum brakes use replaceable friction material called brake shoes. Brake shoes are curved metal components that contain the friction lining or pads.

They are designed to press against the inner surface of the brake drum when the brakes are applied, creating friction and ultimately slowing down or stopping the vehicle.

The friction material on the brake shoes is typically made of heat-resistant materials such as organic compounds, metallic compounds, or a combination of both.

Over time, the friction material on the brake shoes wears down and needs to be replaced to maintain the braking performance and ensure proper function of the drum brake system.

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Answer:

¿Podrías poner la pregunta en inglés por favor?

Explanation:

Answer:

Well before every single shift.

Explanation:

I acutally learned this yesterday

Answer:

(a) The projectile takes approximately 4.420 seconds to reach the water, (b) The horizontal scope of the projectile is 1591.2 meters, (c) The remaining height to descend after 2 seconds of being launched is 63.624 meters.

Explanation:

The projectile experiments a parabolic motion, where horizontal speed remains constant and accelerates vertically due to the gravity effect. Let consider that drag can be neglected, so that kinematic equation are described below:

\(x = x_{o}+v_{o,x} \cdot t\)

\(y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}\)

Where:

\(x_{o}\), \(y_{o}\) - Initial horizontal and vertical position of the projectile, measured in meters.

\(v_{o,x}\), \(v_{o,y}\) - Initial horizontal and vertical speed of the projectile, measured in meters per second.

\(t\) - Time, measured in seconds.

\(g\) - Gravitational acceleration, measured in meters per square second.

\(x\), \(y\) - Current horizontal and vertical position of the projectile, measured in meters.

Given that \(x_{o} = 0\,m\), \(y_{o} = 80\,m\), \(v_{o,x} = 360\,\frac{m}{s}\), \(v_{o,y} = 0\,\frac{m}{s}\) and \(g = -9.807\,\frac{m}{s^{2}}\), the kinematic equations are, respectively:

\(x = 360\cdot t\)

\(y = 80-4.094\cdot t^{2}\)

(a) If \(y = 0\,m\), the time taken for the projectile to reach the water is:

\(80 - 4.094\cdot t^{2} = 0\)

\(t = \sqrt{\frac{80}{4.094} }\,s\)

\(t \approx 4.420\,s\)

The projectile takes approximately 4.420 seconds to reach the water.

(b) The horizontal scope is the horizontal distance done by the projectile before reaching the water. If \(t \approx 4.420\,s\), the horizontal scope of the projectile is:

\(x = 360\cdot (4.420)\)

\(x = 1591.2\,m\)

The horizontal scope of the projectile is 1591.2 meters.

(c) If \(t = 2\,s\), the height that remains to descend is:

\(y = 80-4.094\cdot (2)^{2}\)

\(y = 63.624\,m\)

The remaining height to descend after 2 seconds of being launched is 63.624 meters.

The bearing stress in this scenario is 2 kN/mm². To calculate the bearing stress, we need to use the formula:
Bearing Stress = Load / Contact Area

Substituting the given values:
Bearing Stress = 10 kn / 5 square mm
Bearing Stress = 2 N/mm^2

It is important to note that bearing stress is a measure of the force per unit area exerted on the contact surface between two components. In this case, the load is distributed over an area of 5 square mm, resulting in a bearing stress of 2 N/mm^2. It is important to ensure that the bearing stress is within the allowable limits to prevent failure or damage to the components.

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When the voltage and resistance is doubled the current will remain constant.

The voltage and resistance are inversely correlated, and the current is directly proportional to both. Any change in voltage will have an equal and opposite effect on current. Therefore, doubling or tripling the voltage will result in doubling or tripling the current.We know that I = V/R where I = current V = voltage and R = resistance such that

Given voltage is doubled so v2 = 2V

and resistance is also doubled so R2= 2R

I2 = V2/R2 = 2V/2R = V/R = I

Hence I2 = I

Therefore the current will remain same when both voltage and resistance are doubled.

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Answer:

To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.

The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):

W = ∫(0 to 2) (10x³ - 5) dx

Integrating the force function, we get:

W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2

Now, substituting the upper limit (2) and lower limit (0) into the equation:

W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]

 = [2.5(16) - 10] - [0 - 0]

 = 40 - 10

 = 30

Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.

Explanation:

Therefore, the largest pressure is in section 1. Therefore, the answer is Section 1.

Water flows smoothly through a pipe with various circular cross-sections of diameters 2D, 6D, and D', respectively. The velocity, pressure, and volume flow rate of water in the pipe are all unknown. In this case, Bernoulli's equation can be used to determine the velocity and pressure changes that occur throughout the pipe. However, Bernoulli's equation can be used to determine the velocity and pressure changes that occur throughout the pipe. The following is the formula for Bernoulli's equation:

p1 + (1/2)ρv1² + ρgh1 = p2 + (1/2)ρv2² + ρgh2

Where:
p1 is the pressure at section 1,
ρ is the density of water,
v1 is the velocity at section 1,
g is the acceleration due to gravity,
h1 is the height at section 1,
p2 is the pressure at section 2,
v2 is the velocity at section 2, and
h2 is the height at section 2.

Let's take the velocity ratio first. Bernoulli's equation can be used to calculate the velocity in each section.

p1 + (1/2)ρv1² + ρgh1 = p2 + (1/2)ρv2² + ρgh2

p2 = p1, h1 = h2, and ρ are all constants, and thus can be canceled. Using Bernoulli's equation, we get:

(1/2)ρv1² = (1/2)ρv2² + (1/2)ρv3²

v3/v1 = (v1² - v2²)½ / (v1² - v3²)½ = (D'² - D²)½ / (D'² - 4D²)½

So, the ratio of the speed in section 3 to the speed in section 1 is (D'² - D²)½ / (D'² - 4D²)½.

Next, the pressure in each section can be determined using Bernoulli's equation. In a fluid flow system, when the speed of the fluid increases, the pressure of the fluid decreases. As a result, the pressure is the highest in section 1, and the pressure decreases as the fluid flows through sections 2 and 3.

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Around 500 N is the size of the wind's horizontal force on the balloon.

According to Newton's second rule of motion, an object's acceleration is a function of both its mass and the net force acting on it. The formula Fnet F n e t =ma serves as the representation for this law.

cos(θ) = horizontal component of tension / tension in rope

cos(θ) = F_h / 1300

F_h = 1300 cos(θ)

sin(θ) = vertical component of tension / tension in rope

sin(θ) = 1200 / 1300

sin(θ) ≈ 0.923

cos(θ) ≈ 0.385

Plugging this into our equation for F_h, we get:

F_h = 1300 cos(θ) ≈ 500 N

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The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.

In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.

The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.

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Answer:

Water is non-polar molecule False

Water is polar molecule because the electronegativity of Oxygen is much greater than electronegativity of hydrogen and it has also a bend shape that is why it is polar molecule.

Explanation:

I hope this will help you :)

False. Water is a polar molecule.

Water (H2O) consists of two hydrogen atoms and one oxygen atom. The oxygen atom has a higher electronegativity, meaning it attracts electrons more strongly than hydrogen.

As a result, the shared electrons in the covalent bonds between hydrogen and oxygen are pulled closer to the oxygen atom, creating an uneven distribution of charge.

This leads to a partial negative charge (δ-) on the oxygen atom and partial positive charges (δ+) on the hydrogen atoms, making water a polar molecule.

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