:MAIN ANSWER:
determined that the laws of physics are the same for all non-accelerating observers
Explanation:
Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.
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I need help with this question
The gardener does 5600 joules of work in pushing the wheelbarrow around the lawn.
Step-by-step calculation:
The distance traveled by the wheelbarrow is the perimeter of the lawn, which is:
Perimeter = 3 m + 4 m + 3 m + 4 m = 14 m
The net force exerted on the wheelbarrow is the sum of the force used to push it along the ground and the force used to lift it off the ground:
Net force = 100 N + 300 N = 400 N
The angle between the force and the direction of motion is 0 degrees, so the cosine of the angle is 1.
The work done by the gardener is given by:
Work = Force x Distance x cos(theta)
Substituting the values we found above, we get:
Work = 400 N x 14 m x cos(0 degrees)
Work = 5600 J
Therefore, the gardener does 5600 joules of work in pushing the wheelbarrow around the lawn.
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a child pulls a sled by a rope across at a constant speed
of the forces listed identify which act upon the sled
normal
gravity
applied
friction
tension
air resistance
Answer:
Normal, Gravitational, Applied, Friction, and Tension
Explanation:
Because the sled is on the ground, or rather because it is on the earth, it will have a force of gravity, or its weight, pulling it down.
There is a normal force because the sled is not moving into the ground, so there needs to be a force pushing on the sled from the ground. Additionally, Newton's 3rd law states that for every action there is an equal but opposite reaction, if it's in equilibrium or not moving.
There will be an applied force since the child is pulling the sled and is applying a force to do so.
There will be a friction force that is pulling the sled opposite the direction it is moving, since it is on the ground that is presumably not fricitonless.
There will be a tension force pulling on the sled by the rope. However there is also a tension force pulling on the child's hand by the rope, meaning that these are internal forces and essentially balance out, but they are still there.
There is no air resistance force, or very little of it, since the object is not falling.
A charge of 5.67 x 10^-18 C is placed 3.5 x 10^-6 m away from another charge of -
3.79 x 10^-19 C. What is the force of attraction between them?
particular analyte occurs at a wavelength of 682.0 nm. What is the frequency of this wavelength of light in Hz
the frequency of the given wavelength of light, 682.0 nm, is 4.40 x 10^14 Hz.
we can use the equation c = λν, where c is the speed of light, λ is the wavelength, and ν is the frequency. We know the wavelength (682.0 nm) and the speed of light (3.00 x 10^8 m/s), so we can solve for the frequency:
c = λν
ν = c/λ
ν = (3.00 x 10^8 m/s) / (682.0 nm x 10^-9 m/nm)
ν = 4.40 x 10^14 Hz
Therefore, the frequency of the given wavelength of light is 4.40 x 10^14 Hz.
In conclusion, the frequency of a wavelength of 682.0 nm is 4.40 x 10^14 Hz.
Main Answer: The frequency of the 682.0 nm wavelength light is approximately 4.40 x 10^14 Hz.
Explanation:
To convert the wavelength (in nm) to frequency (in Hz), you can use the equation:
Frequency (v) = Speed of Light (c) / Wavelength (λ)
First, convert the wavelength from nanometers to meters:
Wavelength (λ) = 682.0 nm × (1 m / 1,000,000,000 nm) = 6.82 x 10^-7 m
Next, use the speed of light (c), which is approximately 3.00 x 10^8 m/s:
Frequency (v) = (3.00 x 10^8 m/s) / (6.82 x 10^-7 m)
Frequency (v) ≈ 4.40 x 10^14 Hz
The frequency of the given wavelength (682.0 nm) of light is approximately 4.40 x 10^14 Hz.
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10. John has borrowed his parents car without permission and is driving without a license. He
sees them out walking and realizes that they will be home in about 45 seconds. He is 500 m
from home and driving 25 m/s. Will he get to the driveway before they do?
A computer’s hard drive spins at 7200 RPM. What is the angular velocity in rad/s? What is the
velocity in m/s of the hard drive at a radius of 0. 0889 m?
The angular velocity in rad/s is 753.9 rad/s.
The velocity in m/s of the hard drive at a radius of 0.0889 m is 67.02 m/s.
How to calculate the angular velocity?In Mathematics and Physics, the angular velocity of a physical object can be calculated by using this formula:
ω = θ/t
Where:
ω is the angular velocity.θ is the angle.t is the time.In order to convert the unit revolutions per minute (RPM) to radians per seconds (rad/s), we would multiply the value by 2π and then divide by 60 as follows;
Angular velocity in rad/s = 7200 × 2π/60
Angular velocity in rad/s = 753.9 rad/s.
At a radius of 0.0889 meters, the velocity of the hard drive in m/s can be calculated as follows;
Velocity = radius × angular velocity
Velocity = 0.0889 × 753.9
Velocity = 67.02 m/s.
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In the diagram shown above, the circles represent small balls that have
electric charges. Ball 1 has a negative charge, and ball 2 is repelled by ball 1
Next, you see that ball 2 repels ball 3 and that ball 3 attracts ball 4. What is
the electric charge on ball 4?
Ball 4 may have either a positive or negative charge,
Ball 4 has a negative charge.
Ball 4 has a positive charge.
Answer:
ball 4 has a positve charge
Explanation:
-Ball 2: is negative because it is repelled by ball one (like signs repel)
- ball 3: is also negative because it is repelled by ball one (like signs repel)
- Ball 4: is positive because it is attracted by ball 3 (opposite signes attract)
What forces cause the magnetic repulsion and attraction?
Answer:
The cause of a magnetic force are small electrical currents or moving charges: Tiny circular currents at the atomic level are responsible in a permanent magnet for it to exert a magnetic force.
Explanation:
The acceleration due to gravity on the moon is 1.62 m/s^2, approximately a sixth of the value on earth. for a given initial velocity v0, and a given launch angle θ0, the ratio of the range of an ideal projectile on the moon to the range of the same projectile on earth, rmoon/rearth, will be approximately?
The ratio of the ideal projectile distance on the moon to the same projectile distance on earth, moon/back, is approximately (the acceleration of gravity on the moon is 1.62 m/s², about one-sixth of the acceleration due to gravity on earth. for a given initial velocity v0 , and the specified launch angle θ0) is ⅙ (option B)
The initial velocity, launch angle, and acceleration due to gravity all affect a projectile's range. The formula for an ideal projectile's range is as follows:
R = v0²sin (2θ0) / g
Where,
v0 = the initial velocity (m/s)
θ0 = the launch angle
g = the acceleration due to gravity
The acceleration caused by gravity is 1.62 m/s² for the moon and 9.8 m/s² for the earth. Ranges on the moon and ranges on earth can be expressed as follows:
R moon / R earth = (1.62 sin (2θ0)) / g
sin (2θ0) = 1.62 / 9.8
Approximately ⅙
Consequently, an ideal projectile's range on the moon is around a sixth of its range on Earth.
The question is incomplete, it should be:
The acceleration due to gravity on the moon is 1.62 m/s², approximately a sixth of the value on earth. for a given initial velocity v0, and a given launch angle θ0, the ratio of the range of an ideal projectile on the moon to the range of the same projectile on earth, rmoon/rearth, will be approximately?
A. ⅓
B. ⅙
C. 1
D. 1/12
E. ⅕
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What 4 pieces of information should be included any time you give a written
description of motion?
Answer:
In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time. ... One can also speak of motion of images, shapes, and boundaries.
Explanation:
C p= 88.15J/mol.K Te [K] for ligning 1 er ΔH = 62.626 kJ og ΔSTe = 141.32 j/mol.K
Calculate the equilibrium temperature for equation (1)
C P = 88.15 J /mol. K The answer is 140 degrees, I just need an explanation J mol K
Cp=88.15J/mol.K is the molar heat capacity of the substance T is the temperature of the substance in kelvin ΔH=62.626kJ is the enthalpy change of the substance ΔSTe=141.32J/mol.
K is the change in entropy of the substance. The formula for calculating the equilibrium temperature for equation (1) can be given as:ΔH=ΔSTe*TFor the given values of ΔH and ΔSTe, we can calculate the value of temperature T as
:T=ΔH/ΔSTeT=62.626kJ/141.32J/mol.K = 442.87K = 169.72°C.
The calculated temperature is in degrees Celsius. We need to convert this to Kelvin by adding 273.15 to it.
Therefore,T=169.72+273.15 = 442.87K = 140°C
The molar heat capacity Cp is the amount of heat required to raise the temperature of one mole of a substance by one kelvin. The value of Cp depends on the nature of the substance and can be measured experimentally. In this case, Cp=88.15J/mol.K for the substance is given.The temperature of the substance is denoted by T and is given in kelvin.
The enthalpy change of the substance is denoted by ΔH and is given as 62.626kJ. Enthalpy is a measure of the heat released or absorbed during a chemical reaction. The change in entropy of the substance is denoted by ΔSTe and is given as 141.32J/mol.K. Entropy is a measure of the disorder of a system.
The formula for calculating the equilibrium temperature for equation (1) can be given as:ΔH=ΔSTe*T.
This formula relates the enthalpy change of the substance to the change in entropy of the substance and the temperature at which the reaction occurs.
The equilibrium temperature is the temperature at which the forward and reverse reactions occur at the same rate. This is the temperature at which the system is in equilibrium.
If the temperature is below the equilibrium temperature, the forward reaction is favored and if the temperature is above the equilibrium temperature, the reverse reaction is favored.
The calculated temperature is in degrees Celsius. We need to convert this to Kelvin by adding 273.15 to it. Therefore,T=169.72+273.15 = 442.87K = 140°C
Therefore, the equilibrium temperature for equation (1) is 140°C or 442.87K. This temperature is the temperature at which the forward and reverse reactions occur at the same rate.
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A NASA spacecraft measures the rate of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is: Convert to .
Answer:
\(= 4.21\times 10^{-10}J/cm^4\)
Explanation:
According to the given situation, the computation is shown below:-
\(1kPa=10^3Pa\)
So,
\(1Km = 10^5cm\)
\(1kPa=0.01Pa/Cm\)
\(1kPa=10^{-8}J/cm^4\)
Now as per the question it is given that
r = 0.0421KPa/Km
= \(0.0421KPa/Km \times \frac{10^{-8}J/cm^4}{1KPa/Km}\)
after solving the above equation we will get
= \(0.0421\times 10^{-8}J/cm^4\)
or we can write the above equation in this manner, that is
\(= 4.21\times 10^{-10}J/cm^4\)
Therefore we have solved the equation to reach the right answer.
This type of bike tire is thinner, lighter, more expensive, and punctures easily.
The scatterplot shows the distance (in feet) that a person was from a motion sensor during an experiment in math class. Use the labeled points to create a linear model. About what distance in feet (y) would a person be 8 seconds after the experiment begins? 21 ft 27 ft 30 ft 57 ft.
A person would be 30 feet (y) 8 seconds (x) after the experiment begins.
The scatterplot shows a linear relationship between the distance (in feet) from the motion sensor and the time (in seconds) since the start of the experiment.
Using the two labeled points (8 seconds, 21 feet) and (15 seconds, 57 feet), we can use the line equation y = mx + b to create a linear model. The slope (m) equals (57 feet - 21 feet)/(15 seconds - 8 seconds) = 36 feet/7 seconds, and the y-intercept (b) equals 21 feet.
Using the linear model, we can estimate that a person would be 30 feet (y) 8 seconds (x) after the experiment begins.
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help me with this one aswell, too confused and tired for this
Find the distance an object traveled if a force of 350 n acted on it to produce 0 work?
Force(F) = 350 N
Work (W)= 0 J
Apply the formula:
Work = Force x Distance
Isolate distance(d)
Distance = Work/ Force
d = W/F = 0 /350 = 0 m
The distance that the object traveled is 0 (zero)
Transverse waves are traveling on a 1.00-m-long piano string at 500 m/s. If the points of zero vibration occur at one-half wavelength (where the string is fastened at both ends), find the frequency of vibration.
The frequency of vibration of the transverse waves on the piano string is 250 Hz.
To find the frequency of vibration of the transverse waves on the piano string, use the wave equation:
v = λ * f
where:
v is the velocity of the wave,
λ is the wavelength of the wave, and
f is the frequency of the wave.
Given:
Length of the piano string (L) = 1.00 m
Velocity of the wave (v) = 500 m/s
The points of zero vibration occur at one-half wavelength.
The wavelength (λ) can be calculated using the formula:
λ = 2 * L
Substituting the given values:
λ = 2 * 1.00 m = 2.00 m
Now, rearrange the wave equation to solve for the frequency (f):
f = v / λ
Substituting the values:
f = 500 m/s / 2.00 m
Calculating the division:
f = 250 Hz
Therefore, the frequency of vibration of the transverse waves on the piano string is 250 Hz.
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Explain why the moon goes through phases.
If the model spacecraft were made ONLY out of plastic (no other materials) would it be repelled by the magnet launcher?
yes or no?
Answer:
no it wont i think
Explanation:
What is the total force on the bottom of a 2.0-m-diameter by 1.0-m-deep round wading pool due to the weight of the air and the weight of the water? (Note the pressure contribution from the atmosphere is 1.0 ´ 105 N/m2, the density of water is 1 000 kg/m3, and g = 9.8 m/s2.)
The total force on the bottom of the wading pool, considering the weight of the air and the weight of the water, is 3.47 × 10⁵ Newtons.
To calculate the total force on the bottom of the wading pool, we need to consider the weight of the air and the weight of the water.
Weight of the air:
The pressure contribution from the atmosphere is given as 1.0 × 10⁵ N/m². Since the pressure acts equally in all directions, we can assume it applies uniformly over the surface of the wading pool.
The force due to the weight of the air can be calculated using the formula:
Force = Pressure × Area
Weight of the air:
Area = π × (1.0 m)²
Area = π m²
Force_air = (1.0 × 10⁵ N/m²) × (π m²)
Force_air = 3.14 × 10⁵ N
Weight of the water:
The weight of the water can be calculated using the formula:
Weight = Mass × Acceleration due to gravity
The mass of the water can be determined using its density and the volume of the pool:
Volume = Area × Depth
Volume = π m² × 1.0 m = π m³
Mass = (1000 kg/m³) × (π m³)
Mass = 1000π kg
Weight_water = (1000π kg) × (9.8 m/s²)
Weight_water ≈ 9800π N
Total force on the bottom of the pool:
Total force = Force_air + Weight_water
Total force ≈ 3.14 × 10⁵ N + 9800π N
Total force ≈ 3.14 × 10⁵ N + 30794 N
Using the approximation π ≈ 3.14:
Total force ≈ 3.47 × 10⁵ N
Therefore, the total force on the bottom of the wading pool is approximately 3.47 × 10⁵ Newtons.
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Which of the following is true about all waves?
A. They enter the your body through your ear
B.They need matter to travel through
C. They represent the movement of energy
D.They cannot travel through empty space
If you drop a baseball and a soccer ball at the same time which will hit the ground first?
Answer:
Baseball
Explanation:
If two objects are the same size but one is heavier, the heavier one has greater density than the lighter object. The heavier object would fall and hit the floor first. In other words the baseball would hit the ground first.
HOPES THIS HELPS YOU!!! PLEASE MARK AS BRAINLIEST???
the coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834.
The greatest static resistance between the upper and lower block is f1max = f 1max = s m 1g = 0.6×2×10 = 12N.
According to Newton's second law of motion, an object's net force must equal the sum of its mass and the acceleration it experiences. In the direction of the net force is where acceleration is moving.
The force of action and reaction between two bodies is equal in magnitude but opposite in direction, according to Newton's third law of motion. The highest frictional force that prevents slippage on a surface is known as the limiting friction force.
The highest static resistance between the lower block and the ground is
f2max
=μ s (m 1 +m 2 )g=0.6(2+2)10
=24N
Assumedly, both blocks move to the right at the same speed.
Consequently, (m 1 + m 2 )a = T- μk (m1 + m2)g
or 4a = T - 0.4(2+2)10
or a = T-16 / 4
for upper block, f1 = 2a = T - 16 / 2
For just sliding, f1 = f1max
or T - 16 / 2 = 12
or T - 16 = 24 => T = 40N
The complete question is:
You are lowering two boxes, one on top of the other, down the ramp by pulling on a rope parallel to the surface of the ramp. Both boxes move together at a constant speed of 15.0 cm/s. The coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834. (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
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Which of the following are possible units for a spring constant? O A. J/m B. N/km O.C. cm/N O D. J/N
The answer is B.
We use the spring constant in Hooke's Law, which is : F = -kx
It can be rearranged so it is equal to the constant :
k = F ÷ x
Common units of Force (F) : N, kg m/s²
Common units of displacement (x) : cm, m, km
The dimensionally correct unit from the given options is :
⇒ N/km
PLEASE HELP!!! WILL MARK BRAINLIEST!! Name and define the four fundamental forces.
Answer:
Gravity - is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another.
Strong Interaction - is the mechanism responsible for the strong nuclear force
Weak Interaction - is the mechanism of interaction between subatomic particles that is responsible for the radioactive decay of atoms
Electromagnetism - is a branch of physics involving the study of the electromagnetic force, a type of physical interaction that occurs between electrically charged particles.
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which planet has a feature called the great dark spot ?
Answer:
Neptune
Explanation:
Answer:
Neptune has that feature. Hope this helped!!! ^D^
Explanation:
Which of the following is a chemical change?
A. Water vapor in the air turns to liquid water in the form of rain
B. The oxygen in the air forms ozone in presence of UV rays
C. Dust and soot particles being suspended in the air
D. Sulphur dioxide being released in the air
Answer:
B
Explanation:
To heat the water in the tank from 50°C to 58°C the immersion heater transfers
4032 kJ of energy to the water.
Calculate the mass of water in the tank.
Specific heat capacity of water= 4200 J/kg°C
Let's see
∆T=58-50=8°CSo
\(\\ \rm\Rrightarrow Q=mc\Delta T\)
\(\\ \rm\Rrightarrow 4032=4200(8)m\)
\(\\ \rm\Rrightarrow 4032/8=4200m\)
\(\\ \rm\Rrightarrow 504=4200m\)
\(\\ \rm\Rrightarrow m=0.12kg\)
\(\\ \rm\Rrightarrow m=120g\)
Question 23 of 25 Which statement describes a question that can guide the design of a scientific investigation? A. It asks about a cause-and-effect relationship between two variables. B. It asks about how the observations will be organized. C. It asks about whether a controlled variable is necessary. OD. It asks about the preferred outcome of the investigation.
Scientific investigation asks about a cause-and-effect relationship between two variables. Thus, the correct answer is (a).
Scientific investigation is intended to create a hypothesis and demonstrate its validity or lack thereof. Experiments must be conducted in order to test these hypotheses, and these experiments are planned in accordance with the discovery of a cause-and-effect relationship between the two variables under scientific investigation. In these experiments, the "cause" is variable upto various degrees, and the "effect" of the variance is noted. The experimental design, which will try to manipulate the causes to see how these manipulations impact the second variable, will thus be guided by knowledge of the cause-and-effect connection.
Observations are frequently the first step in a scientific investigation.
An observation is something that is discovered using the senses of humans or tools and measurement technologies that support the senses of humans. Important scientific discoveries may result from unintentional observations.
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The resistance of 80.0 Ωcm of constantan wire, whose diameter of cross-section is 0.457mm is 2.39 . Find the resistivity of constantan
Answer:
64
Explanation:
bc yes
The resistance of 80.0 centimeters of constantan wire, whose diameter of the cross-section is 0.457 millimeters is 2.39, then the resistivity of constantan would be 4.89 ×10⁻⁵ Ohm meters⁻¹.
What is resistance?Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for variation in resistance with length is given,
R = ρ*L/A
As given in the problem resistance of 80.0 centimeters of constantan wire, whose diameter of the cross-section is 0.457 millimeters is 2.39,
Area of the constantan wire = π/4 ×(0.000457)²
= 16.4 ×10⁻⁶ meter²
R = ρ*L/A
2.39 = ρ*0.8/ 16.4 ×10⁻⁶
ρ = 2.39×16.4 ×10⁻⁶ / 0.8
=4.89 ×10⁻⁵
Thus, the resistivity of constantan would be 4.89 ×10⁻⁵ Ohm m⁻¹.
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