what is the temperature of a gas of coz molecules whose rms speed is 329 m/s?

Given

m = 2.6 kg

h = 33m

vo = 0 m/s

g = 9.8 m/s2

Explanation

Let's solve this question using the free fall equations.

The answer would be 25.4 m/s

Answer:

BLACKPINK IN YOUR AREA MATH IS SO MUCH FUN

Explanation:

PERIOD AHH

The total internal energy of an ideal gas, monoatomic or diatomic, is a measure of the energy contained within the gas due to its molecular motion.

For a monoatomic ideal gas, the internal energy is proportional to the temperature of the gas and is given by the equation

U = (3/2) nRT

where U is the internal energy, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

This equation reflects the fact that each molecule of a monoatomic ideal gas has three degrees of freedom for translational motion, and thus contributes (1/2)kT to the internal energy of the gas, where k is Boltzmann's constant.

For a diatomic ideal gas, the internal energy is slightly more complex due to the additional degrees of freedom associated with molecular rotation. At low temperatures, the diatomic molecules cannot rotate and the internal energy is given by U = (5/2) nRT, which includes the three degrees of freedom for translational motion and two degrees of freedom for vibration.

At higher temperatures, the diatomic molecules can rotate and the internal energy is given by U = (7/2) nRT, which includes the additional two degrees of freedom for rotation.

For a non-linear ideal gas, the internal energy depends on the specific molecular structure and the number of degrees of freedom associated with molecular motion. In general, the internal energy is given by

U = (f/2) nRT

where f is the total number of degrees of freedom for motion.

For example, a triatomic gas molecule has six degrees of freedom: three for translational motion, two for vibration, and one for rotation about a specific axis.

Therefore, its internal energy would be

U = (6/2) nRT = 3nRT.

In conclusion, the total internal energy of an ideal gas depends on its molecular structure and the number of degrees of freedom for molecular motion, with monoatomic, diatomic, and non-linear gases each having a distinct formula for their internal energy.

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Answer:

It is a superordinate goal because both teams could have helped with the task.

Explanation:

If both teams pushed then they could have made it happened

Answer:

Protons and neutrons are composed of two types: up quarks and down quarks. Each up quark has a charge of +2/3. Each down quark has a charge of -1/3. The sum of the charges of quarks that make up a nuclear particle determines its electrical charge.

Answer:

Quarks

Explanation:

When we break down protons and neutrons, scientists named the building blocks of atoms "quarks". Quarks are considered in the basic basic elementary particles of the universe.

Answer:

Completion between two organism is when they fight over resources inadvertently causing the use and destruction of recourses making it more scares. if they don't adapt they die out.

Answer:Sample Response: In any ecosystem, the availability of resources is often limited due to competition. Competition results when two organisms require the same limited resource, such as food, water, shelter, or sunlight.

Explanation:

Go with this

Answer:

When sunlight shines through an orange solution, the violet, blue and green wavelengths are absorbed. The other colors pass through. The transmitted light is the light we see, and it looks orange. Colored objects look the way they do because of reflected light.

Explanation:

Answer:

im pretty sure it is C. Insulation

Explanation:

because it says reduced, and basically ur insulating the fire.

Answer: B

Explanation: Yes it is b, because the lightbulb won’t matter just the circuit and flow of the cable.

Mass is how heavy is an object is

Given data:

The mass of the ball is m=0.25 kg.

The spring constant is k=100 N/m.

The speed of the ball is v=6.8 m/s.

The amount of energy stored in the spring in the form of elastic potential energy will equal to the kinetic energy of the ball. It can be applied as,

Here, x is the compression in the spring.

Substitute the given values in above equation,

Thus, the initial compression of the spring is 0.34 m.

Answer:

20100s

Explanation:

Answer:

9/20

Explanation:

According to this question, Lucy and JoJo need to make 140 cupcakes for the school dance. Lucy made 35 of the cupcakes while JoJo made 42 cupcakes. This means that in total, (42 + 35) cupcakes has been made by both Lucy and JoJo

That is, 77 cupcakes out of 140 has been made. This is 77/140 i.e. 11/20

Since 77/140 cupcakes has been made, Lucy and JoJo still need to make;

140 - 77 = 63 cupcakes to meet up their target for the school dance.

This means that the fraction left is 63/140

63/140 in its lowest term is 9/20

Hence, 9/20 of the cupcakes still need to be made by Lucy and JoJo.

Explanation: 140 - 35 = 105 - 42 = 63

yare yare daze

I use tusk act 4 main

(a) The frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck is 2243.9Hz.

(b) The wavelength of the reflected sound waves by the listener is 0.143 m.

We use the principle of Doppler's effect to find the results.

The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.

The equation of the Doppler's effect is

f₀ = (v + v₀) fs / (v + vs)

Where

Note:

There are a truck and a fire engine emitting a siren sound moving in the same direction.

Determine the frequency and the wavelength of the sound waves heard by the listener in the front!

We have the truck is in front of the fire engine. So, the sound source moves closer and the observer moves away. Then, frequency of the sound waves heard by the observer is

f₀ = (v - v₀)/(v - vs) × fs

f₀ = (340 - 19.0)/(340 - 31) × 2160

f₀ = (321/309) × 2160

f₀ = 2243.9 Hz

The wavelength of the sound waves heard by the observer is

λ₀ = (v - v₀) / f₀

λ₀ = (340 - 19) / 2243.9

λ₀ = 321 / 2243.9

λ₀ = 0.1430545

λ₀ = 0.143 m

Hence,

(a) The observer frequency of sound is 2243.9Hz.

(b) The wavelength of the reflected sound waves by the observer is 0.143 m.

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Answer:

Explanation:I don't say you to mark my ans as brainliest but if it has really helped you plz don't forget to thank me...

Answer:

90 km/h = 25 m/ s

Explanation:

to understand

1 km = 1000 m

1 h = 60 minutes and since 1 minute = 60 s you can see that 1 h = 60 * 60 s

90 km / h = 90 1000m / 3600 s

90 *1 / 3.6

90/ 3.6

25 m/ s

so 90 km/h = 25 m/ s

(by the way 90 m/s = 3.6 * 90 = 324 km/ h )

Answer:

ok im gettin 327.23 J but i highly doubt it's right

Explanation:

Johannes Kepler's and Galileo Galilei's research on celestial motion laid the groundwork for Isaac Newton's theory of gravity, which was later confirmed by Edmund Halley's calculations and observations of Halley's Comet.

Johannes Kepler's laws of planetary motion, based on precise observations, and Galileo Galilei's discoveries in physics and astronomy paved the way for Isaac Newton's theory of gravity. Newton's law of universal gravitation, stating that all objects attract each other with a force proportional to their masses and inversely proportional to the square of the distance between them, unified celestial and terrestrial motion. Edmund Halley confirmed Newton's theory by accurately calculating and predicting the orbit of Halley's Comet, providing empirical evidence for the validity of Newton's laws. Together, these contributions revolutionized our understanding of gravity and shaped the foundation of modern physics.

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Johannes Kepler's and Galileo Galilei's research has contributed significantly to Isaac Newton's theory of gravity and Edmund Halley's confirmation of this theory. He was an astronomer and mathematician who played a significant role in the scientific revolution of the 17th century.

Kepler's first law states that the planets move in ellipses around the sun, with the sun located at one of the foci of the ellipse. Kepler's second law states that the speed of a planet varies as it moves around the sun, with the planet moving faster when it is closer to the sun. Kepler's third law relates the period of a planet's orbit to its distance from the sun. These laws were crucial in later developments in the study of gravity and planetary motion.

Galileo Galilei was a mathematician, astronomer, and physicist who made several important contributions to the study of motion and gravity. Galileo was the first person to use a telescope to observe the heavens, and he made many important discoveries, such as the phases of Venus, the moons of Jupiter, and the sunspots.

Isaac Newton was a mathematician, physicist, and astronomer who is widely regarded as one of the most influential scientists in history.

Newton's laws of motion state that objects will remain at rest or move at a constant velocity in a straight line unless acted upon by an external force. Newton's law of universal gravitation states that every object in the universe is attracted to every other object with a force that is proportional to the product of their masses and inversely proportional to the square of their distance apart.

Edmund Halley was an astronomer and mathematician who is best known for his work on comets. Halley also made several important discoveries of his own, including the orbit of Halley's Comet. Halley used Newton's laws of motion and law of universal gravitation to calculate the orbit of the comet.

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The mass of the object attached to the spring is approximately 0.119 kg.

To determine the mass of the attached object using the spring, we can utilize Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where:

F is the force exerted by the spring,

k is the spring constant, and

x is the displacement of the spring from its equilibrium position.

The frequency of the spring's motion (f) can be related to the mass (m) and the spring constant (k) using the equation:

f = (1 / (2π)) * √(k / m)

Rearranging this equation, we can solve for the mass:

m = (k / (4π² * f²))

Given:

Spring constant (k) = 3 N/m

Frequency (f) = 0.8 Hz

Substituting these values into the equation, we get:

m = (3 N/m) / (4π² * (0.8 Hz)²)

Calculating this expression:

m ≈ 0.119 kg

Therefore, the mass of the object attached to the spring is approximately 0.119 kg.

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The mass attached to the spring is approximately 0.238 kg.

To find the mass attached to the spring, we can use the formula for the angular frequency (ω) of a mass-spring system:

ω = √(k / m),

where ω is the angular frequency, k is the spring constant, and m is the mass.

Given:

k = 3 N/m (spring constant),

f = 0.8 Hz (frequency).

First, let's convert the frequency from Hz to radians per second (rad/s):

ω = 2πf = 2π(0.8) ≈ 5.03 rad/s.

Now, we can solve the formula for m:

ω = √(k / m),

m = k / ω^2,

m = 3 N/m / (5.03 rad/s)^2.

Calculating the value:

m ≈ 3 N/m / (5.03 rad/s)^2 ≈ 0.238 kg.

Therefore, the mass attached to the spring is approximately 0.238 kg.

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Einstein’s understanding of curved space-time helped him understand gravity better on Earth.

The man Albert Einstein was the person who first brought up the idea of relativity. The relativity theory drove home the assertion that there are no absolutes in the universe.

On the other hand, the works of Aristotle and Newton about gravity did not include this element of relativity. Though the work of Newton was highly empirical, the results did not incorporate the ideas of relativity.

Thus, what distinguishes Einstein from Newton and Aristotle is Einstein’s understanding of curved space-time helped him understand gravity better on Earth.

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"An important feature of atoms is that they have wave properties."

Protons, electrons, neutrons, and atoms all exhibit wave-like behaviour. In other words, matter has both wave-like and particle-like characteristics, just like light.

Both particle and wave characteristics apply to electrons. The electrons in an atom oscillate around the centre as standing waves.

When a particle's mass is low, it exhibits wave characteristics. Again, there is no boundary; all particles possess wave properties, but it is only feasible to observe them when the mass of the particle is sufficiently low.

Research has shown that atomic particles behave exactly like waves. We observe a full diffraction pattern, just as if we had been using waves, when we fire electrons at one side of a screen with two closely spaced holes and measure the distribution of electrons on the opposite side.

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Molly's experiment involved kicking a soccer ball with varying amounts of force and observing the resulting change in the ball's motion.

Newton's three laws of motion can help explain how the force of Molly's kicks affected the ball's movement.

Newton's first law of motion states that an object at rest will stay at rest and an object in motion will stay in motion with a constant velocity unless acted upon by an unbalanced force. In this experiment, the soccer ball was at rest before each kick, so the force of Molly's kicks acted as an unbalanced force, causing the ball to accelerate and move. The greater the force of her kick, the greater the acceleration and resulting distance the ball traveled.

Newton's second law of motion states that the acceleration of an object is directly proportional to the force applied and inversely proportional to its mass. In this case, the mass of the soccer ball remained constant, but the force of Molly's kicks varied. As a result, the acceleration of the ball was directly proportional to the force of her kick.

Finally, Newton's third law of motion states that for every action, there is an equal and opposite reaction. When Molly kicked the soccer ball, the ball exerted an equal and opposite force back on her foot, which is why she felt the impact of the kick.

Energy transfer also played a role in this experiment. When Molly kicked the ball, she transferred energy from her foot to the ball. The greater the force of her kick, the more energy was transferred to the ball, resulting in a greater distance traveled.

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Answer:

true

Explanation:

Just searched it

Answer:

a)  E_{z} = 0, b) E_{z} = 0, c)    z = 1.73 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)], d)   \(E_{max}\)Emax = 9.7  10¹⁰ N / C

Explanation:

For this exercise we use the expression

          E = k ∫ dq / r²

By applying this expression to our problem of a ring of radius R, with a perpendicular axis in the z direction, we can calculate the electric field for a small charge element

          dE = k dq / r²

In the attachment we can see a diagram of the electric field, it is observed that the fields perpendicular to the z axis cancel and the field remains in the direction of the axis

           d\(E_{z}\)= dE cos φ

we substitute

         E_{z} = k∫  \(\frac{dq}{r^2}\)  cos φ

let's write the expressions

          r² = R² + z²

          cos φ = z / r

we substitute in the integral, where we see that the load differential does not depend on the distance and the value of the total load is + Q

          E_{z} = k  \(\frac{1}{ (R^2 +z^2) } \ \frac{z}{ (R^2 + z^2)^{1/2} }\) ∫  dq

          E_{z} = k Q  \(\frac{z}{ (R2+z^2)^{3/2} }\)  

This is the expression for the electric field in the axis perpendicular to the ring, we analyze this expression to answer the questions

a) the magnitude of the field at z = 0

         E_{z} = 0

b) the magnitude of the field for z = inf

        when z »R the expression remains

          E_{z} = k \(\frac{z}{z^{3} }\) Q

          E_{z} = k Q \(\frac{1}{z^2}\)

therefore when the value of z = int the field goes to E_{z} = 0

c) In value of z for which the field is maximum.

    We have an extreme point when the first derivative is equal to zero

     \(\frac{dE_z}{dz } = k Q [ (R^2 +z^2)^{3/2} - z \ 3 \frac{z}{ (R^2 +z^2)^{1/2} } = 0\)

we solve

    (R² + z²)^{ 3/2} = 3 z² /(R² +z²) ^{1/2}

    (R² + z²)² = 3z²

    r² + z² = √3    z

    z² –1.732 z + R² = 0

we solve the quadratic equation

       z = [1.732 ± \(\sqrt{3 - 4R^2}\)]/ 2 = [1.73 ± 1.73 \(\sqrt{ 1 - \frac{4 R^2}{3} }\)   ] / 2

       z = 0.865 [1 ± \(\sqrt{1 - \frac{4R^2}{3} }\)]

Therefore there are two points where the field has an extreme point one, one is a maximum and the other a minimum, as we have already determined a minimum at z = 0 the maximum point must be

  z = 0.865 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)]

d) the value of Emax

         z₁ = 0.865 [1+\(\sqrt{1 - \frac{4 \ 0.04^2}{3} }\)) = 1.73 [1 + √0.99786]

          z₁ = 1.729 m

         z₂ = 0.865 [1 - √0.99786 ]

         z₂ = 0.0011 m≈ 0

for which the field has a maximum value substituting in equation 1

            \(E_{max} = 9 10^9 \ 9 \ \frac{1.729}{(0.04^2 + 1.729^{3/2})}\)

            \(E_{max}\) = 81 10⁹   \(\frac{1.729}{1.4408}\)

            \(E_{max}\)Emax = 9.7  10¹⁰ N / C

The average speed of the particles in terms of the speed of light is 0.976c. Given that, The particle-X has a lifetime of 256.2.A particle track detector is used to measure the speed of particles. On average, the particles leave 10.6 cm long tracks before they decay into other particles that are not observable by the detector.

The formula to calculate the average speed of the particles is given as;v = d / t Where,v = velocity of the particles, d = distance traveled by the particles, and t = time taken by the particles. The distance traveled by the particles before they decay is 10.6 cm = 0.106 m. The lifetime of the particle is given as 256.2 s. Therefore, time taken by the particle to decay, t = 256.2 s.

The speed of the particles can be calculated as follows; v = d / tv = 0.106 / 256.2v = 4.135 × 10^-4 m/s The speed of the particles in terms of the speed of light can be calculated as follows; Speed of light = 3 × 10^8 m/s Average speed of the particles in terms of the speed of light, v/c= (4.135 × 10^-4) / (3 × 10^8)= 0.976 × 10^-8= 0.976cTherefore, the average speed of the particles in terms of the speed of light is 0.976c.

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The angular speed in rad/s is 120.5 rad/s. The angular displacement of the airplane propeller in 4.00 s is given by 482 rad. the linear speed is 241 m/s. the linear speed of a point 1.00 m from the end of the blade is 120.5 m/s.

The chord line of an airfoil section and the propeller's plane of rotation form what is known as the blade angle. Blade angle is an angular length measurement that is expressed in degrees. A propeller section's pitch, on the other hand, measures how far it will go in one revolution, measured in inches.

The following formula may be used to get the angular speed, :

ω = 2πf

We can convert the rotational speed from rpm to Hz as follows:

120.73 rad/s = 1150 rpm * (1 min/60 s) * (2 rad/1 rev)

The following formula may be used to get the angular displacement, :

θ = ωt

where t is the time taken.

θ = (120.73 rad/s) * (4.00 s) = 482.92 rad

The following formula may be used to determine the linear speed, v, of a point on the end of the blade:

v = rω

At the end of the blade, r = L/2 = 1.00 m

120.73 m/s = v = (1.00 m) * (120.73 rad/s)

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We can see that the time required for the current to reach one-half of its final value \((\(t_{\frac{1}{2}}\))\) is directly proportional to the ratio of inductance to resistance \((\(\frac{L}{R}\))\). Therefore, the correct answer is C. Directly proportional to \(\(L/R\)\).

To analyze the circuit and find the time required for the current to reach one-half its final value, we can use the concept of the time constant in an RL circuit.

The time constant \((\(\tau\))\) of an RL circuit is given by the formula:

\(\[\tau = \frac{L}{R}\]\)

Where:

\(\(L\)\) is the inductance of the coil (in Henries, H).

\(\(R\)\) is the resistance of the circuit (in ohms, Ω).

The time constant represents the time it takes for the current in the circuit to reach approximately 63.2% of its final value.

When the switch S1 is closed, the current in the RL circuit will start to flow. The current \((\(I\))\) in the RL circuit at any time \(\(t\)\) is given by the formula:

\(\[I(t) = I_{\text{max}} \left(1 - e^{-\frac{t}{\tau}}\right)\]\)

Where:

\(\(I_{\text{max}}\)\) is the maximum current that the circuit will reach.

Now, we want to find the time \((\(t_{\frac{1}{2}}\))\) required for the current to reach one-half \((\(\frac{1}{2}\))\) of its final value \((\(I_{\text{max}}\))\).

Let's assume the final current \((\(I_{\text{max}}\))\) is 1 unit (arbitrary value for simplicity). So, we need to find \(\(t_{\frac{1}{2}}\)\) when \(\(I(t_{\frac{1}{2}})\) = \(\frac{1}{2}\)\).

\(\[\frac{1}{2} = 1 \left(1 - e^{-\frac{t_{\frac{1}{2}}}{\tau}}\right)\]\)

Now, we can solve for \(\(t_{\frac{1}{2}}\)\):

\(\[e^{-\frac{t_{\frac{1}{2}}}{\tau}} = \frac{1}{2}\]\\\\\\frac{t_{\frac{1}{2}}}{\tau} = \ln\left(\frac{1}{2}\right)\]\\\\\t_{\frac{1}{2}} = \tau \cdot \ln\left(\frac{1}{2}\right)\]\)

Now, substitute the expression for \(\(\tau = \frac{L}{R}\)\):

\(\[t_{\frac{1}{2}} = \frac{L}{R} \cdot \ln\left(\frac{1}{2}\right)\]\)

We can see that the time required for the current to reach one-half of its final value \((\(t_{\frac{1}{2}}\))\) is directly proportional to the ratio of inductance to resistance \((\(\frac{L}{R}\))\). Therefore, the correct answer is C. Directly proportional to \(\(L/R\)\).

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Even if in a piece of writing, you happen to use the author's last name in my sentence, you also need to use it in the in-text citation.

In academic writing, it is often important to quote the sources that one used in writing up the text. Failure to give accurate citation could be taken as plagiarism by the assessors.

Hence, even if in a piece of writing, you happen to use the author's last name in my sentence, you also need to use it in the in-text citation.

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Answer:

When boiling occurs, the more energetic molecules change to a gas, spread out, and form bubbles. These rise to the surface and enter the atmosphere. It requires energy to change from a liquid to a gas. In addition, gas molecules leaving the liquid remove thermal energy from the liquid. Therefore the temperature of the liquid remains constant during boiling.