what is the system's potential energy when its kinetic energy is equal to 34e ? view available hint(s)for part a what is the system's potential energy when its kinetic energy is equal to ? ka2 ka22 ka24 ka28

Answer:

\(a=0.276\)

Explanation:

From the question we are told that:

Mass \(m=98.kg\)

Radius \(r=0.335\)

Angular velocity \(\omega=100rpm\)

Radial force of \(F_r=23.6 N.\)

Kinetic coefficient of friction  \(\mu=0.192\)

Generally the equation for Kinetic Force is mathematically given by

 \(F_k=\mu.F_r\)

 \(F_k=0.192*23.6\)

 \(F_k=4.5312\)

Generally the equation for Torque on Center is mathematically given by

 \(Ia=f_k*r\)

Where

 \(I=\frac{Mr^2}{2}\)

Therefore

 \(a=\frac{2f_k}{Mr}\)

 \(a=\frac{2*4.5312}{98*0.335}\)

 \(a=0.276\)

Therefore Angular acceleration of the grindstone is

\(a=0.276\)

Answer:

80 to 150 years

Explanation:

hope I helped

Answer: 80-150 years and some over 150 years

Explanation:

There are different types of Tortoise in earth everyone eith different lifespan. So basically normal ones have 80-150 while some other like giant tortoise even have over 150 years.

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A materiel that allows electricity to flow easily is called an conductor

Answer:

A liquid becomes a gas.

Explanation:

I hope this helps a bit.

Answer:

(a) 0 (b) \(F=1.67\times 10^9\ N\)

Explanation:

Given that,

Mass of a supertanker, \(m=1.7\times 10^8\ kg\)

The engine of a generate a forward thrust of, \(F=7.4\times 10^5\ N\)

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

F = mg

\(F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N\)

Hence, this is the required solution.

Answer: 5. On the Moon.

Explanation: Weight is a measure of the force of gravity acting on an object.  The weight of an object depends on the mass of the object and the strength of the gravitational force at a particular location.

On Earth, the weight of an object is determined by the mass of the object and the strength of Earth's gravitational force. At the equator, the weight of an object is slightly less compared to the poles due to the centrifugal force caused by the Earth's rotation. This force counteracts a small portion of the gravitational force, resulting in a slightly lower weight.

At the North and South poles, the weight of an object is slightly higher compared to the equator due to the shape of the Earth. The Earth is not a perfect sphere but slightly flattened at the poles, which causes objects at the poles to be closer to the center of the Earth and experience a slightly stronger gravitational force.

However, on the Moon, the weight of an object is significantly less compared to Earth.  The Moon has a much smaller mass and weaker gravitational force than Earth, resulting in objects weighing less on the lunar surface.

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Answer:5.45X10^3m

Explanation:So use the formula,v= fλ

3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer

Answer:

5.45X10^3m

Explanation:

The frequency of the beam of light with a wavelength of 420 nm is 7.14×10¹⁴Hertz (2nd option)

Frequency of light wave is related to wavelength and speed of the light according to the following formula:

Velocity (v) = wavelength (λ) × frequency (f)

From the question given above, the following data were obtained:

The frequency can be obtained a as follow:

Velocity (v) = wavelength (λ) × frequency (f)

3×10⁸ = 420×10⁻⁹ × frequency of light wave

Divide both sides by 420×10⁻⁹

Frequency of light wave = 3×10⁸ / 420×10⁻⁹

Frequency of light wave = 7.14×10¹⁴Hertz

Thus, from the calculation, it is evident that the frequency is 7.14×10¹⁴Hertz (2nd option)

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Answer:

50 x 3000 = 150000/4000 = 37.5

37.5 I think.

Explanation:

Hope this helps!

A 3000 kg truck travelling at 50km/hr strikes a stationary 1000 kg car, locking the two vehicles together, the final velocity of the two vehicles after the collision is approximately 10.43 m/s.

We may use the concept of conservation of momentum to calculate the final velocity of the two vehicles after the collision.

The total initial momentum (P_initial) is given by:

P_initial = (mass of truck) * (initial velocity of truck) + (mass of car) * (initial velocity of car)

P_initial = (3000) * (50) + (1000) * (0)

The velocity:

Vt = 50 * (1000/3600) = 13.9 m/s

Vc = 0 = 0 m/s

P_initial = (3000) * (13.9) + (1000) * (0 )

P_initial = 41700 kg·m/s

P_initial = P_final

41700 kg·m/s = (3000 kg + 1000 kg) * Vf

41700 kg·m/s = 4000 kg * Vf

Now Vf:

Vf = 41700 kg·m/s / 4000 kg

Vf ≈ 10.43 m/s

Therefore, the final velocity of the two vehicles after the collision is approximately 10.43 m/s.

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Answer:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

Kinetic Energy. Energy is transferred from one object to another when a reaction takes place. Energy comes in many forms and can be transferred from one object to another as heat, light, or motion, to name a few. For the blue ball to move to the position of the green ball, energy must be given to the blue ball.

Answer:

DMs are not accessible anymore. I assume Zuka is a staff member? the only way to talk to a staff member anymore is to report something, but even then, the probably won't even look at what they're deleting :/

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The expansion of both will be the same. Then the correct option is C.

Thermal expansion, which often excludes phase transitions, is the propensity of matter to alter its form, area, volume, and concentration in response to a variation in heat.

The same metal is used to create two identically sized spheres, but only one is solid and the other is hollow. The same rate of warming is applied to the spheres.

The formula for the thermal expansion is given as,

\(\rm \alpha _L = \dfrac{1}{L} \cdot \dfrac{dL}{dT}\)

\(\alpha_{L}\) = thermal expansion

L = particular length measurement

dL = change in length

dT = change in temperature

If the material of the sphere is the same, then the coefficient of the expansion of the sphere is the same, then the expansion of both will be the same.

Both will expand at the same rate. Then, C is the right answer.

The complete question is attached below.

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Answer:

147N

Explanation:

pressure = 7pa

area= 21m

force=?

now,

p = f/a

7 = f/21

f = 21×7

therefore, f = 147N.

Performance behaviour is the total set of work-related behaviors that the organization expects the individual to display.

What are Performance behaviors?

Performance behavior refers to the establishment of a quantifiable link between the desired outcome and the behavior needed to get there. It identifies and quantifies the behavior required to produce the intended outcome.

What are examples of performance behaviors?

In addition to Interpersonal abilities, Customer Service Orientation, includes:

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Answer:

The plane would need to travel at least \(8,\!580\; {\rm ft}\) (\(8.58 \times 10^{3}\; {\rm ft}\).)

The \(10,\!000\; {\rm ft}\) runway should be sufficient.

Explanation:

Convert unit of the the take-off velocity of this plane to \(\rm ft\cdot s^{-1}\):

\(\begin{aligned}v &= 180\; {\rm mph} \\ &= 180\; {\rm mi \cdot hrs^{-1}} \times \frac{1\; {\rm hrs}}{3600\; {\rm s}} \times \frac{5280\; {\rm ft}}{1\; {\rm mi}} \\ &= 264\; {\rm ft \cdot s^{-1}}\end{aligned}\).

Initial velocity of the plane: \(u = 0\; {\rm ft \cdot s^{-1}}\).

Take-off velocity of the plane \(v =264\; {\rm ft\cdot s^{-1}}\).

Let \(x\) denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation \(x = ((u + v) / 2) \, t\).

Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration \(t\) times average velocity \((u + v) / 2\).

The distance that the plane need to cover would be:

\(\begin{aligned}x &= \left(\frac{u + v}{2}\right)\, t \\ &= \frac{0\; {\rm ft \cdot s^{-1}} + 264\; {\rm ft \cdot s^{-1}}}{2} \times 65.0\; {\rm s} \\ &= 8.58\times 10^{3}\; {\rm ft}\end{aligned}\).

Answer:

In the NBA that's true

=====================================================

Explanation:

Problem 1

Focus on the y axis which is the distance axis.

Point B has a y coordinate of 2

Point E has a y coordinate of 5

The displacement is 5-2 = 3, which means the person has moved 3 km.

--------------------------

Problem 2

Both D and E have the same y coordinate. So the displacement is 0 (since 5-5 = 0). No change in distance has occurred. During segment DE, the person is resting. By the way it is impossible to go back to D since it's impossible to go back in time.

Answer:

Answer is in attached photo.

Explanation:

Solution is in the attached photo, do take note that this question requires multiple formulas, such as Power and Work Done, which are:

1) Work Done =

Force x Distance or F x D

2) Power =

\(\frac{Work \ Done }{Time}\)

Scientists believe that light is made of streams of particles, called photons, because of their observed behavior. In certain experiments, such as the photoelectric effect, it was found that light behaves more like a particle than a wave. For example, light can knock electrons out of atoms, which would require a particle-like behavior. Additionally, the energy of each photon is directly proportional to its frequency, which is a characteristic of particles. The behavior of light in other experiments, such as the double-slit experiment, can also be explained by the wave-like behavior of photons. Therefore, scientists have concluded that light has both particle and wave-like properties, known as wave-particle duality.

While this answer may provide helpful information for your assignment, it is important to remember that using it verbatim could be seen as plagiarism. To avoid this, it is best to use your own words and properly cite any sources used. This will ensure that you are giving credit to the original author and presenting your own unique perspective on the topic.

~~~Harsha~~~

When using parallax, astronomers calculate distance from the sun and not earth to improve on the accuracy of their measurement, since parallax angle decreases as star distance increases.

Parallax enables astronomers to measure the distances of far away stars by using trigonometry.

As the distance of star increases, the parallax angle decreases, and great degree of accuracy is required for its measurement.

So taking a refence from the earth instead of the sun will impact the accuracy of their measurement.

Thus, when using parallax, astronomers calculate distance from the sun and not earth to improve on the accuracy of their measurement, since parallax angle decreases as star distance increases.

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the splitting of a large nucleus into smaller nuclei is the phrase that describes radioactive decay

The process through which an unstable atomic nucleus loses energy through radiation is known as radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration. A substance with unstable nuclei is regarded as radioactive decay

The complete question is

Which phrase describes radioactive decay? (1 point)

the triggering of one reaction by the products of another

the joining of small nuclei into a laroid nucleus

o the splitting of a large nucleus into smaller nuclei

o the spontaneous emission of radiation

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Answer:

Although the wave slows down, its frequency remains the same, due to the fact that its wavelength is shorter. When waves travel from one medium to another the frequency never changes.

Answer:

Explanation:

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Answer:

A thats answer thankyou

Answer:

4 m/s

Explanation:

you moved 140 meters in 35 seconds

v = 140 / 35 = 4 m/s

The push on a stationary crate increases, the friction force also increases and is opposite in direction to the push.

When you push a stationary crate, the friction between the crate and the ground resists the motion. This friction force is proportional to the normal force acting on the crate and is given by the equation F_friction = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force.

Initially, when the push on the crate is small, the friction force is also small, and the crate remains stationary. However, as the push on the crate increases, the friction force also increases, up to a maximum value called the maximum static friction force. At this point, the crate is on the verge of moving, but still remains stationary.

If the push on the crate exceeds the maximum static friction force, the crate will start to move, and the friction force will decrease to a lower value called the kinetic friction force. The coefficient of kinetic friction μ_k is usually smaller than μ_s, so the crate will be easier to move once it starts to slide.

Therefore, as the push on a stationary crate increases, the friction force also increases and is opposite in direction to the push.

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