What is the sum of the fractions 2/9+5/9

Answer:The mass of scheelite having one million oxygen atoms is. Explanation: We are given: Number of oxygen atoms = (million atoms). According to mole .

Explanation:

Answer:

The links are: the number of circles in the electronic configuration of an element is represented in the periodic table as the period number that element is situated in. the number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in.

Explanation:

The products of the acid-base reaction between chloric acid \((HClO_{3})\), and lithium hydroxide \((LiOH)\), are water \((H_{2}O)\) and lithium chlorate \((LiClO_{3} )\)

An acid-base reaction is a chemical reaction that occurs between an acid and a base producing salt and water. It is a double-replacement reaction where ions exchange their positions.

The general equation of an acid-base reaction is as follows.

Acid + Base → Salt + Water

The H(+) cation of the acid combines with the OH(-) anion of the base to form water. The compound formed by the cation of the base and the anion of the acid is called a salt.

For the reaction between chloric acid \((HClO_{3})\), and lithium hydroxide \((LiOH)\), the H(+) cation of the acid \((HClO_{3})\) combines with the OH(-) anion of the base \((LiOH)\) to form water. The compound formed by the cation of the base \((LiOH)\) and the anion of the acid \((HClO_{3})\) is lithium chlorate.

\(H^{+}+ ClO_{3}^{-} +Li^{+} +OH^{-} = LiClO_{3} + H_{2}O\)

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The chemical equation when aluminum metal reacts with solid sulfur to produce solid aluminum(III) sulfide would be \(2Al (s) + 3S (s) -- > Al_2S_3 (s)\)

The reaction between aluminum metal and solid sulfur to produce aluminum (III) sulfide would be as follow:

The chemical symbol of aluminum metal = Al

The chemical symbol of sulfur = S

Aluminum has a valence electron of 3 while sulfur has a valance electron of 2. In order to form a bond between them, the valence electron of one becomes the subscript of the other. In other words, aluminum receives the valence of sulfur (2) while sulfur receives the valence of aluminum (3). Thus:

\(2Al +3 S --- > Al_2S_3\)

When all the phases are considered, the equation becomes: \(2Al (s) + 3S (s) -- > Al_2S_3 (s)\)

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Aluminum metal reacts with solid sulfur to produce solid aluminum(III) sulfide. Express your answer as chemical equations. identify all the phases in your answer.

The predominant form of CH3CH2NH3 at pH = 14 will be the ionized form.

This is because at high pH, the solution is basic, and there are excess hydroxide ions. The hydroxide ions remove a proton from the ammonium ion, forming ammonia and water. The chemical equation for this reaction is as follows:CH3CH2NH3+ OH- → CH3CH2NH2 + H2O

The predominant form of CH3CH2NH3 at pH = 14 is CH3CH2NH2. This is the ionized form of the compound, which has lost a proton to become an amine. The structure of the predominant form of CH3CH2NH3 at pH = 14 is shown below:CH3CH2NH2

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Glycinate donates an electron pair so it is a bidentate ligand.

The molecular formula is C₂H₄NO₂⁻. The octahedral complex is formed between glycinate molecules and cobalt(III) and the stoichiometry of the complex is [Co(gly)₃]. The reaction is as follows;

Co₃⁺(aq) + 3C₂H₄NO₂⁻ ⇒ [Co(C₂H₄NO₂⁻](aq)

A cobalt complex is formed when 3 glycinate ions equivalents react with one Co₃⁺ ion equivalent so, it is necessary to keep the glycinate ions concentration greater than the cobalt(III) ions at least three times more.

So, taking the concentration 4 times greater can facilitate the reaction.

For a complex whose concentration is 0.015M, 0.06M glycinate ions are required to obtain the desired cobalt(III) glycinate complex.

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Answer:

Your problem is already in standard form.

Explanation:

Unless you wanted coverted to regular notation. Which is 0.0000832.

Answer: A saturated solution, by definition, contains an amount of solute equal to the amount of dissolved solute in equilibrium with an undissolved solute. We could, however, make a supersaturated solution in which the solvent contains more solute than would be in equilibrium with undissolved.

Explanation:   More solute cannot be dissolved at a given temperature in a saturated solution. This is because the solute dissolves in a solvent due to the space between the solvent particles, but with the continuous addition of solute, the space between the solvent particles is filled. As a result, no more solute particles can dissolve in the solvent.

Answer:

saturated

Explanation:

The Cl-Cl bond will react more readily because it has a lower bond energy than the C- H bond.

The bond energy refers to the energy required to break the bonds that links two atoms together in a molecule. It is equal to the energy that is evolved when the bond is formed.

In comparing the Cl-Cl bond with the C-H bond, we will find out that the Cl-Cl bond will react more readily because it has a lower bond energy than the C- H bond.

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Answer:

1.74 g/cm3

Explanation:

density=mass/volume

Explanation:

density = 1300/743

or density=1.74g/cm3

Answer:

a pure compound because mixtures are formed from two or more compounds.

The statement "the average biomass per year of rodents consumed by the owl equals 42,000 grams" can be either true or false depending on the specific owl species and its diet.

Owls are predatory birds and feed primarily on rodents and other small mammals. The amount of biomass consumed by an owl per year depends on various factors, including the owl's size, metabolism, hunting efficiency, and prey availability.

To determine the accuracy of the statement, we need to consider the average daily food intake of an owl and extrapolate it to a yearly value. For example, if an owl consumes an average of 50 grams of rodents per day, it would eat approximately 18,250 grams (50 grams x 365 days) of biomass per year, which would make the statement false. However, if the owl's average daily consumption were higher, the statement could be true.

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Atoms having greatly differing electronegativities are expected to form ionic bonds. Electronegativity is the measure of an atom's ability to attract electrons towards itself in a chemical bond.

When two atoms have a large difference in electronegativity, one atom will attract electrons more strongly than the other. This results in the transfer of electrons from one atom to the other, leading to the formation of ions with opposite charges. These oppositely charged ions attract each other and form an ionic bond. Therefore, option D, ionic bonds, is the correct answer.

Atoms having greatly differing electronegativities are expected to form ionic bonds (option D). When there is a large difference in electronegativity, one atom will attract the shared electrons more strongly, causing a transfer of electrons from the less electronegative atom to the more electronegative one. This results in the formation of positive and negative ions, which are then held together by electrostatic forces, forming an ionic bond.

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The electron pair arrangement of CH2-CH2 is linear because this molecule contains two bond pairs and no lone pairs, therefore the electron pair geometry is also linear.

A molecule is a small particle consisting of two or more atoms. Molecules are the basic building blocks of matter and are composed of atoms held together by chemical bonds. Molecules exist in all states of matter, including gases, liquids, and solids. They are essential for the formation of complex structures such as proteins, enzymes, and DNA. Molecules can be formed through a variety of processes, including chemical reactions, absorption of light, and the formation of intermolecular forces.

The molecular geometry is also linear because the molecule is composed of two atoms and the bond angles are 180 degrees.

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a) a) The Gibbs free energy change of formation for each species at the standard state of the system (1200 K, 1 bar) can be estimated using thermodynamic tables. The values are:

ΔG°f (kJ/mol): CH₄=-50.8, H₂O=-228.6, CO=-137.2, CO₂=-393.5, H₂=0.

b) At equilibrium, the system contains 0.012 moles of CH₄, 0.263 moles of H₂O, 0.369 moles of CO, 0.307 moles of CO₂, and 0.049 moles of H₂, and the total number of moles is 8.71. The Lagrange multiplier is -99.24 kJ/mol

To solve this problem using the method of Lagrange multipliers, we need to minimize the Gibbs free energy of the system subject to the constraint of constant total moles:

subject to Σνi = 7, where νi is the stoichiometric coefficient of species i and μi is the chemical potential of species i.

a) To estimate the values of the changes of Gibbs free energy of formation of all species at the standard state of the system (1200 K, 1 bar), we can use the standard Gibbs free energy of formation values (ΔGf°) and the temperature dependence of ΔGf°, which is given by:

where ΔHf and ΔSf are the enthalpy and entropy of formation, respectively.

Using this equation and the given values, we can calculate the following values of ΔGf at 1200 K and 1 bar:

b) To calculate the equilibrium composition, we need to solve the following system of equations:

where x is the mole fraction and λ is the Lagrange multiplier.

Substituting the values for the chemical potentials and stoichiometric coefficients, and using the given values for the initial moles of CH₄ and H₂O, we get the following system of equations:

Solving these equations simultaneously using numerical methods, we get:

Total moles in equilibrium = 8.71

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Answer:

the correct answer is argon: 1s 2^2s 2^2p 6^3s 2^3p^6​

Explanation:

Answer:

B. Only potential energy C. Both kinetic and potential energy D. Neither potential nor kinetic 1 See answer All molecules move and therefore have kinetic energy. They also hold bond energies which I believe count as potential energy. Advertisement Advertisement

Explanation:

Answer:

the basic unit of an ionic compound is called a formula unit and the basic unit of a covalent compound is a molecule.

There are\(1.7 * 10^-4\) mol of oxygen in the sample of potassium dichromate.

A sample of potassium dichromate, \(K_2Cr_2O_7,\)contains \(8.5 * 10^{-5\)moles of potassium. The goal is to find out how many moles of oxygen are present in the sample.

First, let us determine the number of moles of potassium dichromate present in the sample.

Mass of K2Cr2O7 = Molar mass of \(K_2Cr_2O_7,\)x Number of moles of K

Number of moles of K = \(8.5 * 10^{-5\)molMolar mass of \(K_2Cr_2O_7,\)= (2 x 39.10 g/mol) + (2 x 52.00 g/mol) + (7 x 16.00 g/mol)= 294.18 g/mol

Mass of \(K_2Cr_2O_7,\)= 294.18 g/mol x \(8.5 * 10^{-5\) mol= 0.0249813 g

Next, we can determine the number of moles of oxygen in the sample.

Number of moles of O = 2 × Number of moles of \(K_2Cr_2O_7,\)Number of moles of O = \(2 * 8.5 * 10^{-5\)mol= 1.7 × 10^-4 mol

Therefore, there are\(1.7 *10{^{-4\) mol of oxygen in the sample of potassium dichromate.

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The Ksp for the equilibrium reaction HgBr₂(s) ⇄ Hg²⁺(aq) + 2Br⁻(aq) if HgBr₂ has a molar solubility of 2.50x10⁻⁷ M is 6.25x10⁻²⁰.

The given reaction is:

HgBr₂(s) ⇄ Hg²⁺(aq) + 2Br⁻(aq)   (1)

The equilibrium constant (Ksp) for the above reaction is given by:

\(Ksp = [Hg^{2+}][Br^{-}]^{2}\)   (2)  

At the equilibrium, we have (eq 1):

HgBr₂(s) ⇄ Hg²⁺(aq) + 2Br⁻(aq)  

                    s                2s  

Where:

s: is the molar solubility = 2.50x10⁻⁷ M  

By entering the values of molar solubility into equation (2) we can find the value of Ksp

\(Ksp = [Hg^{2+}][Br^{-}]^{2} = s(2s)^{2} = 4s^{3} = 4(2.50\cdot 10^{-7})^{3} = 6.25\cdot 10^{-20}\)

Therefore, the Ksp is 6.25x10⁻²⁰.

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The answer is 0.365:100.

v/c ratio represents ratio of speed of an electron (v) to the speed of light (c).

How is the speed of an electron calculated?

\(v =\frac{1}{n}\; \frac{e^{2}}{4\pi \varepsilon _{0}}\times \frac{2\pi }{h}\)

Now, for the first excited state, n = 2.

e - Charge of electron = \(1.6\)×\(10^{-19}\) C

h - Plank's constant = \(6.6\)×\(10^{-34} J.s\)

ε₀- permittivity \(= 8.85\)×\(10^{-12}\)\(N^{-1}.C^{2}.m^{-2}\)

\(v =\frac{1}{2}\; \frac{e^{2}}{4\pi \varepsilon _{0}}\times \frac{2\pi }{h} =\frac{1}{4}\times \frac{(1.6\times 10^{-19})^{2}}{8.85\times 10^{-12}\times 6.6\times 10^{-34}}\\ \\ =0.01096\times 10^{8} \\ \\=1.096\times 10^{6}ms^{-1}\)

\(\frac{v}{c} =\frac{1.096* 10^{6}\ m/s }{3.0 *10^{8}\ m/s }\)= \(\frac{0.365}{100}\)

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Two important scientific discoveries related to cell theory that were mentioned in the video are Robert Hooke's discovery of cells and Antonie van Leeuwenhoek's discovery of single-celled organisms.

1. Robert Hooke's discovery of cells: In 1665, Robert Hooke observed thin slices of cork under a microscope and noticed small compartments that he named "cells" due to their resemblance to the cells in a monastery. This discovery was important because it provided the first evidence that living organisms were composed of individual units or cells.

2. Antonie van Leeuwenhoek's discovery of single-celled organisms: In the late 1600s, Antonie van Leeuwenhoek used a microscope to observe a variety of samples, including water, blood, and even his own saliva. He discovered tiny, single-celled organisms that he called "animalcules." This discovery was significant because it showed that living organisms could exist as single cells, which supported the idea that cells were the basic building blocks of life.

These two discoveries were related to one another because they both contributed to the development of cell theory, which states that all living organisms are composed of cells and that cells are the basic unit of life. Hooke's discovery of cells provided the initial evidence for this theory, while van Leeuwenhoek's discovery of single-celled organisms supported the idea that cells could exist independently as functional units of life. Together, these discoveries helped to establish the concept of cell theory as we know it today, which has been further refined and expanded upon by subsequent scientific research.

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The total amount of heat : 225.704 kJ

Heat of vaporization(ΔH vap) : heat needed to vaporize 1 mole of water , units : kJ/mol

For water at boiling point (100 °C) : ΔH vap = 40.66 kj/mol

mole of 100 g water :

\(\tt \dfrac{100}{18.015}=5.551\)

so total Heat :

\(\tt 40.66\times 5.551=225.704~kJ\)

Answer:

A

Explanation:

Mitosis makes 2 daughter cells so you know the answer is not b

Answer:

Morphine contains total 40 atom(s); 19 Hydrogen atom(s), 17 Carbon atom(s), 1 Nitrogen atom(s) and 3 Oxygen atom(s).

Explanation:

Explanation:

Giant Gas Cloud. A star originates from a large cloud of gas. ...

Protostar. When the gas particles in the molecular cloud run into each other, heat energy is produced. ...

T-Tauri Phase. ...

Main Sequence. ...

Red Giant. ...

The Fusion of Heavier Elements. ...

Supernovae and Planetary Nebulae

Answer:

3

Explanation:

Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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Use the conversion factor:

\(1\ atm=101.325\ kPa\)

\(=132.01\ kPa\) × \(\frac{1\ atm}{101.325\ kPa}\)

= 1.302738712 atm (round as you wish)

The path of exhaled oxygen-poor and carbon dioxide-rich air leaving the body begins in the body's cells, where oxygen is used for cellular respiration, and carbon dioxide is produced as a waste product.

When we breathe in, our body takes in oxygen-rich air through the mouth or nose. This air then travels through the trachea, or windpipe, and into the lungs. In the lungs, the oxygen is transferred to the bloodstream while carbon dioxide is released from the blood and into the air sacs of the lungs.

Next, the oxygen-rich blood is pumped by the heart to different parts of the body, where it is used for energy production. As the body uses oxygen, it produces carbon dioxide as a waste product.

This carbon dioxide is carried by the bloodstream back to the lungs, where it is released into the air sacs. Finally, when we exhale, the air travels back up the trachea and out of the mouth or nose, carrying the carbon dioxide-rich and oxygen-poor air out of the body.

This process of inhaling oxygen and exhaling carbon dioxide is known as respiration and is essential for the proper functioning of the body's cells and organs.

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