solve for x : 13x + 7 = -227
Answer:
-18
Step-by-step explanation:
1. Subtract 7 from both sides:
13x = -234
2. Divide 13 from both sides:
13x/13 = -234/13
x = -18
hope this helps!
Roxy is multiplying 18 by 43.
Use the drop-down menu to complete the statement.
1
4
1
The product × will be
.
8
3
8
Answer:
774,
Step-by-step explanation:
x-y=3. what is y-x
PLS HELP
Answer:
Step-by-step explanation:
y-x=3 so basically x=3 and y= -3
If a component has a normally distributed strength with a standard deviation of 2.5, what is the standard deviation of the equivalent z-distribution? (
The standard deviation of the equivalent z-distribution is 0.25.
The standard deviation of the equivalent z-distribution can be calculated by dividing the standard deviation of the original distribution by the square root of the sample size.
In this case, since the strength of the component is normally distributed with a standard deviation of 2.5, we need to determine the standard deviation of the equivalent z-distribution.
To calculate this, we need to know the sample size. The z-distribution is used when we have a large sample size, typically considered to be 30 or greater.
Let's assume we have a sample size of 100.
The formula to calculate the standard deviation of the equivalent z-distribution is:
Standard deviation of the z-distribution = Standard deviation of the original distribution / √(sample size)
Substituting the values into the formula:
Standard deviation of the z-distribution = 2.5 / √(100)
Simplifying the expression:
Standard deviation of the z-distribution = 2.5 / 10
Standard deviation of the z-distribution = 0.25
Therefore, the standard deviation of the equivalent z-distribution is 0.25.
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when comparing the means of samples from two normally distributed populations that the samples are independent and the population variances are known a z test can be used
When comparing the means of samples from two normally distributed populations, with independent samples and known population variances, a z-test can be used.
The z-test is a statistical test used to compare means when certain assumptions are met. In this case, the populations from which the samples are drawn are assumed to be normally distributed. The samples being compared should be independent of each other, meaning that the values in one sample are not related to or influenced by the values in the other sample. Additionally, it is assumed that the population variances are known, which is not always the case in practice.
The z-test relies on the calculation of a test statistic called the z-score, which measures the difference between the sample means in terms of standard deviations. The z-score is calculated by subtracting the mean of one sample from the mean of the other sample, and then dividing by the standard deviation of the sampling distribution of the difference in means. The resulting z-score is compared to a critical value from the standard normal distribution to determine the statistical significance of the difference between the means.
If the absolute value of the z-score exceeds the critical value, it indicates that the difference between the sample means is statistically significant, suggesting that the population means are likely to be different. On the other hand, if the z-score is not statistically significant, it suggests that the difference between the sample means may be due to chance, and there is not enough evidence to conclude that the population means are different.
Overall, when comparing the means of samples from normally distributed populations with known variances and independent samples, a z-test provides a way to assess the statistical significance of the difference between the means.
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How do i solve this paper?
I feel like my answers are gone and i need help.
Answer:
you have it correct sir
Step-by-step explanation:
Simplify each and state the excluded values.
40x^2/72x
Answer:
5x/9
Step-by-step explanation:
i hope and think its correct!! ^^
Find the distance (-4,6) and (3,-7)
Answer:
Distance ≈ 14.8
Step-by-step explanation:
Calculate the distance (d) using the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 4, 6) and (x₂, y₂ ) = (3, - 7)
Hope this helps!!!!
A clothesline rope is 8 feet long. Which of these is another way to express 8 feet?
answer choices
A/F
B/G
C/H
D/J
As per the concept of unitary method, the another way to express 8 feet is 2 ²/₃ yards.
In math, unitary method is known as a way of finding out the solution of a problem by initially finding out the value of a single unit, and then finding out the essential value by multiplying the single unit value.
Here we have given that a clothesline rope is 8 feet long.
Now we need to find another way to express 8 feet.
We know that the formula to convert the measurement it to divide the length by the conversion ratio.
As we know that one yard is equal to 3 feet, then we can use this simple formula to convert is written as
=> yards = feet ÷ 3
Here the equivalent yard measurement is written as,
=> yards = 8 ÷ 3
Then we have to convert the improper fraction into mixed fraction form, then we get,
=> 2 ²/₃ yards.
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the z-score associated with the 99 percent confidence interval is
This z-score is commonly used to determine the critical value for constructing a 99 percent confidence interval.
What does the z-score represent in statistics?The z-score associated with the 99 percent confidence interval is approximately 2.576. In statistics, the z-score represents the number of standard deviations a data point is from the mean of a distribution.
A 99 percent confidence interval indicates that we want to capture 99 percent of the data within the interval. Since the normal distribution is symmetric, we can divide the remaining 1 percent (half on each tail) by 2, giving us 0.5 percent.
Using a standard normal distribution table or a calculator, we can find the z-score that corresponds to this cumulative probability, which is approximately 2.576.
This z-score is commonly used to determine the critical value for constructing a 99 percent confidence interval.
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The picture below shows the graph of which inequality?
The graph shows the inequality x² ≤ 16
How find the inequality for the graph?An inequality is a relationship that makes a non-equal comparison between two numbers or other mathematical expressions e.g. 2x > 4.
Inequalities are often used to describe conditions or constraints in real-world problems.
You will notice that the values represented in the graph ranges from -4 to 4. Thus, solving x² ≤ 16 will produce these values. That is:
x² ≤ 16
x ≤ ±√16
x ≤ ±4
x ≤ -4 or x ≤ 4
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How do you dilate a triangle by 2?
Step-by-step explanation:
To dilate the figure by a factor of 2, I will multiply the x and y-value of each point by 2. I plotted all the new points to find the new triangle. To dilate the figure by a factor of 2, I will multiply the x-value of each point by 2.
Select the domain and range of F.
F={(x, y) Ix+y=10].
1. Set F is not a function and does not contain a domain or range
2. Domain: [10] Range: (10)
3. Domain: All Real Numbers Range: All Real Numbers
The domain and range of F is F={(x, y) Ix+y=10] is: 3. Domain: All Real Numbers Range: All Real Numbers
The given set F={(x, y) | x+y=10} represents a linear equation where the sum of x and y is always equal to 10.
To determine the domain and range of F, we need to consider the
possible values of x and y that satisfy the equation.
Domain: The domain represents the set of all possible values for the independent variable, which in this case is x. Since there are no restrictions on the value of x, the domain is All Real Numbers.
Range: The range represents the set of all possible values for the dependent variable, which in this case is y. By rearranging the equation x+y=10, we can solve for y to get y=10-x. Since x can take any real value, y can also take any real value. Therefore, the range is also All Real Numbers.
The correct answer is: 3. Domain: All Real Numbers Range: All Real Numbers
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What is 9x^-1 as a fraction
identify the irrational numbersselect all that apply1. 0.7292. 0.01953473. -124. \( \sqrt[]{18} \)
The options are analyzed as follows:
1: The overline 0.729 means:
\(0.729729729\ldots\)This is a non- terminating recurring decimal hence it is rational.
2: The nuumber 0.0195347... is a non terminating and non recurring decimal hence it is irrational.
3. The number -12 is rational since it is an integer.
4.The number 4.565656... is a non terminating recurring decimal hence it is rational.
5. The number given by:
\(\sqrt[]{18}=3\sqrt[]{2}=4.242640687\ldots\)Since square root of 2 is irrational and 3 is rational the product is irrational.
Also the decimal is non terminating non recurring hence it is irratonal.
So the options 2 and 5 are irrational.
I need help with this ASAP and can you explain so i can understand?!
Answer:
Adult tickets sold = 225
Student Tickets sold = 375
Step-by-step explanation:
Let:
Adult tickets sold = x
Student Tickets sold = y
Total tickets sold = 600
So, we can write: x+y = 600
Total money collected = 3037.50
Cost of 1 Adult ticket = $6.00
Cost of one Student ticket = $4.50
So, we can write: 6x+4.5y=3037.50
Now, we get a system of equations, that if solved we can find values of x and y
Let:
\(x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)\)
We can solve using substitution method.
Finding value of x from eq(1) and putting it in eq(2)
\(We\:have\\x+y=600\\x=600-y\)
Put in eq(2)
\(6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375\)
So, we get value of y = 375
Now put value of y in eq(1) to find value of x
\(x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225\)
So, we get value of x = 225
The Tickets sold will be:
Adult tickets sold = x = 225
Student Tickets sold = y = 375
What is the first step in evaluating the expression below?
3 x [9 – (4 + 2) = 2]
-)) dividing 2 by 2
» multiplying 3 and 9
1)) adding 4 and 2
d)) subtracting 4 from 9
Answer:
brackets, then Parenthesis then the FIRST Multiplication then the division and then math and sub and so on a so for
Step-by-step explanation:
» What is the value of s?
S
Answer:
s = 6
Step-by-step explanation:
Answer:
\( \huge \boxed{s=6}\)
\( \boxed {\frak{Step \: by \: step \: explanation:}}\)
\(Given,3(s+4)=30\)
\(3s + 12 = 30\)
\( \boxed{Subtract 12 from \: both \: sides \: of \: the \: equation}\)
\(3s + 12 - 12 = 30 - 12\)
\(3s = 18\)
\( \boxed{Divide \: both \: sides \: of \: the \: equation \: by \: the \: same \: term}\)
\( \large{ \frac{3s}{3} = \frac{18}{3} }\)
\( \boxed{s = 6}\)
\( \frak{EtherealMistress}\)
Find the solution to the system of equations by graphing.
(Use the answer box with the graph) y = -2x+4 and 6x+3y = 12
Answer:
To graph the system of equations:
1. Rewrite the equations in slope-intercept form (y = mx + b):
y = -2x + 4
3y = -6x + 12
y = -2x + 4
2. Plot the y-intercept of the first equation, which is (0, 4). Then use the slope of -2 (rise of -2 and run of 1) to plot additional points and draw the line.
3. Plot the y-intercept of the second equation, which is (0, 4). Then use the slope of -2 (rise of -2 and run of 1) to plot additional points and draw the line.
The solution to the system of equations is the point where the two lines intersect. From the graph, we can see that the lines intersect at the point (2, 0).
Therefore, the solution to the system of equations by graphing is:
x = 2
y = 0
Answer box: (2, 0)
An equation is shown.
8 + x = 32
What value of x makes the equation true?
4
24
40
256
The value of x which will make the equation 8 + x = 32 true will be 24 thus, option (B) is correct.
What is the equation?There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
The equation must be constrained with some constraints.
As per the given equation,
8 + x = 32
Put x = 4
8 + 4 = 12 ≠ 32
Put x = 24
24 + 4 = 32 (so it will be the solution)
Hence "The value of x which will make the equation 8 + x = 32 true will be 24".
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help for good luck !!
Answer:
third and the first one
Step-by-step explanation:
Answer:
ddddd
Step-by-step explanation:
dddddddd
HELPPPPP PLEASEEEEE!!!
Answer:
The height of right circular cone is h = 15.416 cm
Step-by-step explanation:
The formula used to calculate lateral surface area of right circular cone is: \(s=\pi r\sqrt{r^2+h^2}\)
where r is radius and h is height.
We are given:
Lateral surface area s = 236.64 cm²
Radius r = 4.75 cm
We need to find height of right circular cone.
Putting values in the formula and finding height:
\(s=\pi r\sqrt{r^2+h^2}\\236.64=3.14(4.75)\sqrt{(3.75)^2+h^2} \\236.64=14.915\sqrt{(3.75)^2+h^2} \\\frac{236.64}{14.915}=\sqrt{14.0625+h^2} \\15.866=\sqrt{14.0625+h^2} \\Switching\:sides\:\\\sqrt{14.0625+h^2} =15.866\\Taking\:square\:on\:both\:sides\\(\sqrt{14.0625+h^2})^2 =(15.866)^2\\14.0625+h^2=251.729\\h^2=251.729-14.0625\\h^2=237.6665\\Taking\:square\:root\:on\:both\:sides\\\sqrt{h^2}=\sqrt{237.6665} \\h=15.416\)
So, the height of right circular cone is h = 15.416 cm
Solve using Elimination
3x+y=-9
y=5x+7
Answer
x=-2 and y=-3
Step-by-step explanation:
Step: Solvey=5x+7for y:
Step: Substitute5x+7 for y in 3x+y=−9:
3x+y=−9
3x+5x+7=−9
8x+7=−9(Simplify both sides of the equation)
8x+7+−7=−9+−7(Add -7 to both sides)
8x=−16
8x/8=−16/8
(Divide both sides by 8)
x=−2
Step: Substitute−2 for x in y=5x+7:
y=5x+7
y=(5)(−2)+7
y=−3(Simplify both sides of the equation)
Assume a 30-day month to calculate your average daily balance for your credit card bill. Your daily balance for the first 10 days was $500, for the next 10 days was $1,000, and for the last 10 days was $1,500. What will your average daily balance be at the end of the month? A) $ 800.00 B) $ 900.00 C) $1,000.00 D) $1,500.00 2) Assume a 31-day month to calculate your average daily balance for your credit card bill. Your daily balance for the first 10 days was $1,900, for the next 20 days was $2,500, and for the last 1 day was $2,800. What will your average daily balance be at the end of the month? A) $1,800.00 B) $1,927.50 C) $2,050.00 D) $2,316.12 3) Assuming the APR on your credit card is 18% and your average daily balance this month was $5,000, what will your interest or finance charges for the month (30 days) be? A) $50.60 B) $60.70 C) $70.50 D) $73.50
The average daily balance at the end of the month will be $1,000.00 (option C).
To calculate the average daily balance, we need to determine the total balance over the 30-day period and divide it by the number of days (30) to get the average.
The daily balance for the first 10 days is $500, for the next 10 days is $1,000, and for the last 10 days is $1,500.
To find the total balance, we can multiply each daily balance by the number of days it was held:
Total balance = (10 days * $500) + (10 days * $1,000) + (10 days * $1,500)
Total balance = $5,000 + $10,000 + $15,000
Total balance = $30,000
Now we divide the total balance by the number of days (30) to find the average daily balance:
Average daily balance = Total balance / Number of days
Average daily balance = $30,000 / 30
Average daily balance = $1,000
Therefore, the average daily balance at the end of the month will be $1,000.00 (option C).
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Which is the graph of x - y = 1
Answer: its is the third one C.)
Step-by-step explanation:
What does this problem equal? -2/3x-3-3
Answer:
-1
Step-by-step explanation:
-2/3*-3-3
2-3
= -1
Answer + method / explanation please
The expressions for the lengths of the segments obtained using vectors notation are;
a. i. \(\overrightarrow{LA}\) = q - (1/2)·p ii. \(\overrightarrow{AN}\) = (2/7)·(p - q)
b. The expressions for \(\overrightarrow{MN}\), \(\overrightarrow{LA}\), and \(\overrightarrow{AN}\) indicates;
\(\overrightarrow{MN}\) = (1/84)·(46·q - 11·p)
What are vectors?A vector is a quantity that has magnitude and direction and are expressed using a letter aving an arrow in the form, \(\vec{v}\)
a. i. \(\overrightarrow{LA}\) = \(\overrightarrow{BA}\) - \(\overrightarrow{LB}\) = \(\overrightarrow{BA}\) - (1/2) × \(\overrightarrow{CB}\)
\(\overrightarrow{BA}\) - (1/2) × \(\overrightarrow{CB}\) = q - (1/2)·p
\(\overrightarrow{LA}\) = q - (1/2)·p
ii. \(\overrightarrow{AC}\) = \(\overrightarrow{BC}\) - \(\overrightarrow{BA}\)
\(\overrightarrow{AN}\) = (2/7) × \(\overrightarrow{AC}\)
\(\overrightarrow{AN}\) = (2/7) × \(\overrightarrow{BC}\) - \(\overrightarrow{BA}\)
\(\overrightarrow{AN}\) = (2/7) × (p - q)
b. \(\overrightarrow{MN}\) = \(\overrightarrow{MA}\) + \(\overrightarrow{AN}\)
\(\overrightarrow{MA}\) = (5/6) × \(\overrightarrow{LA}\)
\(\overrightarrow{LA}\) = q - (1/2)·p
\(\overrightarrow{AN}\) = (2/7) × (p - q)
Therefore;
\(\overrightarrow{MN}\) = (5/6) × ( q - (1/2)·p) + (2/7) × (p - q)
\(\overrightarrow{MN}\) = (1/84) × ( 70·q - 35·p + 24·p - 24·q) = (1/84)(46·q - 11·p)
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A ranger wants to estimate the number of tigers in Malaysia in the future. Suppose the population of the tiger satisfy the logistic equation dt/dP =0.05P−0.00125P^2
where P is the population and t is the time in month. i. Write an equation for the number of the tiger population, P, at any time, t, based on the differential equation above. ii. If there are 30 tigers in the beginning of the study, calculate the time for the number of the tigers to add up nine more
The equation for the number of the tiger population P at any time t, based on the differential equation is \(P = (5000/((399 \times exp(-1.25t))+1))\).
Given that there are 30 tigers at the beginning of the study, the time for the number of tigers to add up to nine more is 3.0087 months. To solve this problem, we need to use the logistic equation given as, dt/dP = 0.05P − 0.00125P². Now, to find the time for the number of tigers to add up to nine more, we need to use the equation derived in part i, which is \(P = (5000/((399 \times exp(-1.25t))+1))\).
We know that there are 30 tigers at the beginning of the study. So, we can write: P = 30.
We also know that the ranger wants to find the time for the number of tigers to add up to nine more. Thus, we can write:P + 9 = 39Substituting P = 30 in the above equation, we get:
\(30 + 9 = (5000/((399 \times exp(-1.25t))+1))\).
We can simplify this equation to get, \((5000/((399 \times exp(-1.25t))+1)) = 39\). Dividing both sides by 39, we get \((5000/((399 \times exp(-1.25t))+1))/39 = 1\). Simplifying, we get:\((5000/((399 \times exp(-1.25t))+1)) = 39 \times 1/(39/5000)\). Simplifying and multiplying both sides by 39, we get \((399 \times exp(-1.25t)) + 39 = 5000\).
Dividing both sides by 39, we get \((399 \times exp(-1.25t)) = 5000 - 39\). Simplifying, we get: \((399 \times exp(-1.25t)) = 4961\). Taking natural logarithms on both sides, we get \(ln(399) -1.25t = ln(4961)\).
Simplifying, we get:\(1.25t = ln(4961)/ln(399) - ln(399)/ln(399)-1.25t \\= 4.76087 - 1-1.25t \\= 3.76087t = -3.008696\)
Now, the time for the number of tigers to add up to nine more is 3.0087 months.
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I need help with this
Prove that if f is differentiable at a, then |f| is also differentiable at a, provided that f(a)≠0
If a function f is differentiable at a point a and f(a) is not equal to zero, then the absolute value function |f| is also differentiable at that point.
The proof involves considering two cases based on the sign of f(a) and showing that the limit of the difference quotient exists for |f| at point a in both cases. However, it is important to note that |f| is not differentiable at the point where f(a) equals zero.
To prove that if f is differentiable at a, then |f| is also differentiable at a, provided that f(a) ≠ 0, we need to show that the limit of the difference quotient exists for |f| at point a.
Let's consider the function g(x) = |x|. The absolute value function is defined as follows:
g(x) = {
x if x ≥ 0,
-x if x < 0.
Since f(a) ≠ 0, we can conclude that f(a) is either positive or negative. Let's consider two cases:
Case 1: f(a) > 0
In this case, we have g(f(a)) = f(a). Since f is differentiable at a, the limit of the difference quotient exists for f at point a:
lim (x→a) [(f(x) - f(a)) / (x - a)] = f'(a).
Taking the absolute value of both sides, we have:
lim (x→a) |(f(x) - f(a)) / (x - a)| = |f'(a)|.
Since |g(f(x)) - g(f(a))| / |x - a| = |(f(x) - f(a)) / (x - a)| for f(a) > 0, the limit on the left-hand side is equal to the limit on the right-hand side, which means |f| is differentiable at a when f(a) > 0.
Case 2: f(a) < 0
In this case, we have g(f(a)) = -f(a). Similarly, we can use the same reasoning as in Case 1 and conclude that |f| is differentiable at a when f(a) < 0.
Since we have covered both cases, we can conclude that if f is differentiable at a and f(a) ≠ 0, then |f| is also differentiable at a.
Note: It's worth mentioning that at the point where f(a) = 0, |f| is not differentiable. The proof above is valid when f(a) ≠ 0.
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