What is the slope of the line that passes through the ordered pairs (-5,-1) and (5, -7)

Answer:

bete a la her ha pir que yo no me use la reasouesta

Answer:

Step-by-step explanation:

V = w h l

V = 7.5 * 7.5 * 6

V = 337.5cubic feet * 0.05

V = 16.875Lbs

V = 17Lbs (Rounded to nearest pound)

Answer:

Answer: 27:8

Step-by-step explanation:

There are 24 + 16 + 14 = 24+16+14= 54

54 marbles in total.

The ratio of total marbles to red marbles is 54 : 16, which simplifies to 27 : 8.

Answer: 27:8

Answer:

a

Step-by-step explanation:

car is traveling faster

Answer:

23

Step-by-step explanation:

12-(9-2)+3*6

12-(7)+3*6

12-7+18

5+18

23

A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).

Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.

As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt

Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.

For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:

E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.

Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:

dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt

where M is a martingale with M(0) = 0.

Thus, X(t) can be represented as an Itô process on [0,T] of the form:

X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds

Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.

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Step-by-step explanation:

The formula of finding mean :- sum of terms

number of terms

91+90+87+79+58=405

5. 405/5=81/1.

The mean is 81/1.

Answer:

5.99696 or 6

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

because none of the lines go over each other or touch

Answer:

x=21, y= 35

Step-by-step explanation:

3x+7=5x-35

(subtract seven from -35)

3x=5x-42

(subtract 5 from 3)

-2x=-42

(-42/-2= positive number)

x=21

y+75=3y+5

(subtract 75 from 5)

y=3y-70

(subtract 3y from y)

-2y=-70

y=35

The correct answer is: A. Since each derivative of y( – t) is the opposite of each derivative of y(t), the equations y'' – ty = 0 and y'' + ty = 0 are equivalent and are both satisfied by y(t) and y(-t). To show that if y(t) satisfies y'' - ty = 0, then y(-t) satisfies y'' + ty = 0, we will find the first and second derivatives of y(-t) and plug them into the equation.

First derivative of y(-t): Let's denote y(-t) as u(t). Then, u(t) = y(-t), and the first derivative u'(t) = -y'(t).
Second derivative of y(-t): Taking the derivative of u'(t) gives us u''(t) = -y''(t).
Now, let's plug these derivatives into the equation:  u''(t) + tu(t) = -y''(t) + t*y(-t) = 0.
Since y(t) satisfies y'' - ty = 0, we can replace y''(t) with t*y(t) in the equation:  - (t*y(t)) + t*y(-t) = 0.
This simplifies to:  y'' + ty = 0, which is satisfied by y(-t).
Therefore, the correct answer is: A. Since each derivative of y( – t) is the opposite of each derivative of y(t), the equations y'' – ty = 0 and y'' + ty = 0 are equivalent and are both satisfied by y(t) and y(-t).

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The annual interest rate of the bank account is 3.1%.

Given:

After 5 years there is $673.40 in the account.

After 8 years there is $737.90 in the account.

Let x and A be the annual interest rate and Amount at first.

A(1+x)^5 = 673.40

A(1+x)^8 = 737.99

A(1+x)^8 / A(1+x)^5 = 737.99/673.40

(1+x)^3 = 1.0959

1+x = \(\sqrt[3]{1.0959}\)

x = 0.3099

x ≈ 0.031

x = 3.1%

Therefore The annual interest rate of the bank account is 3.1%.

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Answer:

  y = 1/2x -2

Step-by-step explanation:

You want the equation of a line parallel to y = 1/2x +6 that contains the point (0, -2), written in slope-intercept form.

The slope of the line you want will be the same as the slope of the line you have. That is because parallel lines have the same slope.

The equation you are given is written in slope-intercept form:

  y = mx + b . . . . . . where m is the slope and b is the y-intercept

Comparing this form to the given equation, you see that ...

  m = 1/2 . . . . . the slope of the line you want

The "intercept" in the "slope-intercept" form is the value of y when x=0. The point you are given, (0, -2), tells you that y = -2 when x = 0. So, the "intercept" in your slope-intercept equation is -2.

The equation you want is the equation of a line with slope 1/2 and a y-intercept of -2.

  y = 1/2x -2

The equation of the line that is parallel to line EF and passes through point (0, -2) is y = (1/2)x - 2.To find an equation of a line that is parallel to line EF and passes through point (0, -2), we need to use the fact that parallel lines have the same slope. The slope of line EF is 1/2, so the slope of the parallel line will also be 1/2.

We can start by using the point-slope form of the equation of a line: y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Plugging in m = 1/2 and (x1, y1) = (0, -2), we get:

y - (-2) = (1/2)(x - 0)

Simplifying this equation gives:

y + 2 = (1/2)x

To get this equation in slope-intercept form (y = mx + b), we can isolate y:

y = (1/2)x - 2

So the equation of the line that is parallel to line EF and passes through point (0, -2) is y = (1/2)x - 2. Note that this line intersects the y-axis at y = -2, which is the y-intercept.

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Answer:

y=-x-5

Step-by-step explanation:

Slope is the x, since slope is equal to -1, x=-1. For the y intercept you simply add or subtract the number given to you, since it is -5 you would add a -5 to the end of the equation

Answer:

- 6 and - 4

Step-by-step explanation:

Given

- \(\frac{1}{2}\) x + 4 ≥ 6 ( subtract 4 from both sides )

- \(\frac{1}{2}\) x ≥ 2

Multiply both sides by - 2 to clear the fraction, reversing the symbol as a result of multiplying by a negative quantity.

x ≤ - 4

The only values from the set which satisfy the inequality are

- 4 and - 6

Yes, we can fully describe the density curve for a normal distribution in terms of just the mean (μ) and standard deviation (σ).

The normal distribution is a symmetric, bell-shaped curve that is completely determined by its mean and standard deviation.

The mean (μ) determines the center or peak of the curve, and the standard deviation (σ) determines the spread or width of the curve. Specifically, the normal distribution has the following properties:

The mean, median, and mode of the distribution are all equal and located at the center of the curve.

The total area under the curve is equal to 1, which means that the curve represents the probability density function for all possible values of the random variable.

The curve is symmetric around the mean, with half of the area under the curve to the left of the mean and half to the right.

The standard deviation controls the width of the curve, with larger standard deviations resulting in wider, flatter curves and smaller standard deviations resulting in narrower, taller curves.

The mean and standard deviation of a normal distribution, we can easily calculate the probabilities associated with specific values or ranges of values using the properties of the curve.

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Answer:

I thinK it's D

it might be wrong but I think it's the right answer

Answer:

  ∠A = 44°

Step-by-step explanation:

Let b represent the measure of the exterior angle at B. Let c represent the measure of the exterior angle at C. The sum of angles in the lower triangle is ...

  b/2 +c/2 +68° = 180°

  b +c = 360° -136° . . . . . multiply by 2, subtract 136°

  b +c = 224°

__

The exterior angle b is the supplement of the interior angle there, so the interior angle B is ...

  B = 180° -b

The exterior angle c is the sum of the remote interior angles, so we have ...

  c = B +A

  c = (180° -b) +A

  A = (b +c) -180° . . . . . . . . add b-180° to both sides

  A = 224° -180° = 44° . . . . substitute for (b+c)

The measure of angle A is 44°.

_____

Additional comment

The angle naming is perhaps a little unconventional, but we wanted to use names that made the answer less cumbersome to write. We consider the angle A, B, C to be the interior angles of ΔABC, and we have named the exterior angles at B and C as 'b' and 'c'.

Conventionally, 'b' and 'c' would name the sides opposite angles B and C, respectively. We're not concerned with side lengths here, so we used those letters for an unconventional purpose.

Answer:

19th place from last

Step-by-step explanation:

If someone ranks xth place out of 35 students, then the rank from the last would (35-x)th place.

35-16=19th place

To determine the mean and variance of the random variable in Exercise 4.1.10, we first need to find the limits of the triangular distribution. Given the probability density function (PDF) f(x) = 0.0025x - 0.075 for 30 ≤ x ≤ 40, we can see that the lower limit is 30 and the upper limit is 40.

To find the mean (μ), we can use the formula:
μ = (a + b + c) / 3,
where a and c are the lower and upper limits, and b is the peak value. In this case, a = 30, b = 40, and c = 40. Plugging these values into the formula, we get:
μ = (30 + 40 + 40) / 3 = 110 / 3 ≈ 36.67.

To find the variance (σ^2), we can use the formula:
σ^2 = (a^2 + b^2 + c^2 - ab - ac - bc) / 18,
where a, b, and c are the same as before. Plugging the values into the formula, we get:
σ^2 = (900 + 1600 + 1600 - 1200 - 1200 - 1600) / 18 = 300 / 18 ≈ 16.67.

In conclusion, the mean of the random variable is approximately 36.67, and the variance is approximately 16.67.

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To find the length of the curve given by r(t) = cos(7t) i + sin(7t) j + 7 ln(cos(t)) k, 0 ≤ t ≤ π/4, we need to use the formula for arc length:

L = ∫[a,b] √[dx/dt]^2 + [dy/dt]^2 + [dz/dt]^2 dt

In this case, we have:

dx/dt = -7 sin(7t)
dy/dt = 7 cos(7t)
dz/dt = -7 sin(t) / cos(t)

So,

[dx/dt]^2 + [dy/dt]^2 + [dz/dt]^2 = 49 sin^2(7t) + 49 cos^2(7t) + 49 sin^2(t) / cos^2(t)
= 49 [sin^2(7t) + cos^2(7t) + sin^2(t) / cos^2(t)]
= 49 [1 + sin^2(t) / cos^2(t)]

Now, using the identity sin^2(t) + cos^2(t) = 1, we can rewrite this as:

[dx/dt]^2 + [dy/dt]^2 + [dz/dt]^2 = 49 cos^2(t)

Therefore, the length of the curve is:

L = ∫[0,π/4] √[dx/dt]^2 + [dy/dt]^2 + [dz/dt]^2 dt
= ∫[0,π/4] 7 cos(t) dt
= 7 [sin(t)]|[0,π/4]
= 7 sin(π/4) - 7 sin(0)
= 7 (√2/2)
= 7√2/2

So the length of the curve is 7√2/2.

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0.5133 the probability of the events \(B^{c}\) in the sample.

What is probability?

Total surveyed CBC students = n(T) = 150

Given     A = The students has children

              B = The students is enrolled in at least 12 credits

              C = The students works at least 10 hours per week

         n(A) = 44

         n( B) =73

         n (c) = 105

\(n(B)^{c}\) = n(T) - n(B)

         = 150 - 73 = 77

\(pB^{c}\)  = \(\frac{n(B)^{c} }{n(T)} }\) = 77/150 = 0.5133

Therefore, the probability of the events \(B^{c}\) in the sample  = \(p(B^{c})\) = 0.5133

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The complete question is -

A sample of 150 CBC students was taken, and each student filled out a survey. The survey asked students about different aspects of their college and personal lives. The experimenter taking the survey defined the following events: A = The student has children B = The student is enrolled in at least 12 credits C = The student works at least 10 hours per week The student found that 44 students in the sample had children, 73 were enrolled in at least 12 credits, and 105 were working at least 10 hours per week. The student also noted that 35 students had children and were working at least 10 hours per week. Calculate the probability of the event Bº for students in this sample. Round your answer to four decimal places as necessary.

Answer:

  C.  142°

Step-by-step explanation:

You want the angle between vectors u=3i+√3j and v=-2i-5j.

There are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:

  u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest

You can find the angles of the vectors individually, and subtract those:

  u = |u|∠α

  v = |v|∠β

  θ = α - β

When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:

  \(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)

This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.

A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.

__

Additional comment

The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.

The dot-product relation will work with 3D vectors as well as 2D vectors.

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Given:

Suzy ran 1/2 of a lap in 2/3 minutes.

The unit rate in minutes per lap is,

Answer: 4/3 minute per lap.

Answer:

D

Step-by-step explanation:

- Events A, B, C, and D are exhaustive.
- Events A and B, B and D are not mutually exclusive.
- Events A and C, C and D, A and D are mutually exclusive.

To determine whether the events are exhaustive or mutually exclusive, we need to understand the definitions of these terms:
1. Exhaustive events: Events are considered exhaustive if the union of all the events covers the entire sample space S. In other words, there are no outcomes in the sample space that are not included in any of the events.
2. Mutually exclusive events: Events are considered mutually exclusive if they have no outcomes in common. In other words, the events cannot occur simultaneously.
Now let's analyze the given events:
A = {1, 2, 4}
B = {1, 2, 4, 5, 6}
C = {5, 6}
D = {2, 3, 6}
To determine if the events are exhaustive, we need to check if their union covers the entire sample space S.
The union of A, B, C, and D is {1, 2, 3, 4, 5, 6}, which covers the entire sample space S. Therefore, the events A, B, C, and D are exhaustive.

To determine if the events are mutually exclusive, we need to check if any outcomes are shared between the events.
The outcomes 1, 2, and 4 are shared between events A and B. Therefore, events A and B are not mutually exclusive.
The outcomes 2 and 6 are shared between events B and D. Therefore, events B and D are not mutually exclusive.
No outcomes are shared between events A and C, C and D, or A and D. Therefore, events A and C, C and D, and A and D are mutually exclusive.

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Answer:

Spider travel in \(5ft\) in 3 minutes

Step-by-step explanation:

A spider traveled 20 feet in 12 minutes.

Speed of spider is

\(\frac{20}{12} =\frac{5}{3} ft/min\)

Now we need to find how far could it travel in 3 minutes

Distance

\(=3\times\frac{5}{3} \\\\=5ft\)