Answer:
2/3
Step-by-step explanation:
y = 2/3x + 3
y=mx+c
3.
(03.06)
Using the completing-the-square method, rewrite f(x) = x2 − 8x + 3 in vertex form. (2 points)
f(x) = (x −8)2
f(x) = (x −4)2−13
f(x) = (x −4)2 + 3
f(x) = (x −4)2 + 16
Answer: f(x) = (x −8)2
Step-by-step explanation:
What are the solutions to the inequality —8 + 12x > 4(5 + 2x)?
Answer:
7
Step-by-step explanation:
X>=7
We distribute and then transfer to the other side
a restaurant records the number of customers they serve each week. what type of data does this describe?
The answer is that the type of data that is being described is quantitative data. This means that the data consists of numerical values that represent the number of customers served each week.
, quantitative data is numerical data that can be measured and expressed in numerical form. In this case, the number of customers served each week is being recorded, which is a quantitative variable. This data can then be analyzed and used to make decisions about the restaurant's operations, such as staffing levels, inventory management, and marketing strategies. Overall, the recording of customer numbers is an important aspect of running a successful restaurant, and the quantitative data collected can provide valuable insights into customer behavior and preferences.
Quantitative data can be further divided into two categories: discrete and continuous data. Discrete data can only take specific values, usually whole numbers (e.g., the number of customers). Continuous data can take any value within a range (e.g., the weight of a serving). In this scenario, the number of customers is an example of discrete quantitative data.
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A circle with center is shown in the figure below.
S
T
W
R
U
V
(a) Name a radius:
(b) Name a diameter:
(c) Name a chord:
(d) If the length of is units,
what is the length of ?
The names of the radius , chord and diameter of a circle are as follow,
Radius of the circle are PQ, PM , And PR.
Diameter of the circle is QM
Chord of the circle is ON.
Length of QM in the circle = 4units.
In the attached figure of the circle,
Center of the circle is P.
radius of the circle is a distance from the center of the circle to its circumference.
Radius = PQ, PM , And PR.
Diameter of the circle passing through center P is QM.
Chord of the circle representing a line segment having endpoints on the circumference of the circle.
Chords are ON and MQ.
Diameter is the longest chord.
length of PR is 2 units,
PR is radius
QM is diameter
QM = 2(PR)
length of QM = 2(2)
= 4 units.
Therefore, for the given circle we have,
Radius are PQ, PM , And PR.
Diameter is QM
Chord is ON.
Length of QM = 4units.
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The above question is incomplete, the complete question is:
A circle with center P is shown in the figure below.
(a) Name a diameter:
(b) Name a radius:
(c) Name a chord:
(d) If the length of PR is 2 units, what is the length of QM
Attached figure.
can someone help quick
Step-by-step explanation:
22+2x+8= x+20
2x+30=x+20
x+30=20
x=-10
answer is -10
why is it necessary to apply the finite population correction factor when a sample is a significant part of the population?
It necessary to apply the finite population correction factor (FPC) when a sample is a significant part of the population because for more than 5% of finite population the standard error in the estimated value will come to be too big.
The formula of FPC is
FPC =\(\sqrt{ (N-n)/(N-1)}\)
where N= population size
n= sample size
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The limit: does not exist Select one: O True O False x² - y² lim (x,y) (0,0) 4x + 4y
if g(x, y) = yln(x) - x²ln(2y + 1) then gy (1,0) = -2 Select one: O True O False
The given statements are as follows:
The limit of (x² - y²)/(4x + 4y) as (x, y) approaches (0, 0) does not exist.
If g(x, y) = yln(x) - x²ln(2y + 1), then gₓ(1, 0) = -2.
To determine the limit of (x² - y²)/(4x + 4y) as (x, y) approaches (0, 0), we can approach the origin along different paths. If the limit value is the same regardless of the path chosen, then the limit exists. However, in this case, if we approach along the x-axis (setting y = 0), the limit is 0, but if we approach along the y-axis (setting x = 0), the limit is undefined. Hence, the limit does not exist.
To find gₓ(1, 0), we differentiate g(x, y) partially with respect to x and evaluate it at (1, 0). Using the rules of differentiation, we get gₓ(1, 0) = ln(1) - 1²ln(2(0) + 1) = 0 - 0 = -2. Therefore, the statement "gₓ(1, 0) = -2" is true.
Please note that these explanations are based on the information provided, and if there are any additional or missing details, the answers may differ.
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The area of a rectangular field is 7626m2. If the length of the field is 93m, what is its width?
Answer:
The width is \(82m\)
Step-by-step explanation:
------------------------------>>>>
The formula to find the area of a rectangle is \(A=lw\)
We already know the area of the rectangular field which is \(7626m\)
We already know the length is \(93m\)
--------------->>>>
Now let's substitute \(7626\) for \(A\) because that's the area and substitute \(93\) for \(l\) because that's the length. After that, let's solve to find the width.
\(7626=93w\)
Divide both sides by 93 because that's the opposite of multiplication.
\(82=w\)
--------------->>>>
This means that the width of the rectangular field is \(82m\)
Hope this is helpful
SOLVE X PLZ!!! I NEED THE HELP.
3.18 a continuous random variable x that can assume values between x = 2 and x = 5 has a density function given by f(x) = 2(1 x)/27. find (a) p(x < 4); (b) p(3 ≤ x < 4).
For the given continuous random variable x:
(a) p(x < 4) = -8/27.
(b) p(3 ≤ x < 4) = -5/27
The continuous random variable x that can assume values between x = 2 and x = 5 has a density function given by f(x) = 2(1 x)/27.
(a) To find p(x < 4), we need to integrate the density function from x = 2 to x = 4:
p(x < 4) = ∫24 2(1 x)/27 dx
= (2/27) ∫24 (1 - x) dx
= (2/27) [(x - x2/2)]24
= (2/27) [(4 - 42/2) - (2 - 22/2)]
= (2/27) [(4 - 8) - (2 - 2)]
= (2/27) [(-4) - 0]
= (2/27) (-4)
= -8/27
So, p(x < 4) = -8/27.
(b) To find p(3 ≤ x < 4), we need to integrate the density function from x = 3 to x = 4:
p(3 ≤ x < 4) = ∫34 2(1 x)/27 dx
= (2/27) ∫34 (1 - x) dx
= (2/27) [(x - x2/2)]34
= (2/27) [(4 - 42/2) - (3 - 32/2)]
= (2/27) [(4 - 8) - (3 - 4.5)]
= (2/27) [(-4) - (-1.5)]
= (2/27) (-2.5)
= -5/27
So, p(3 ≤ x < 4) = -5/27.
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What is a rule for the translation of ARST to AR'S'T' ? Select all that apply.RSГуRISतकT-2이erA. T-7,3)B. 7 units down; 3 units rightC. 7 units right; 3 units downD. T7.-3
Given :
R'S'T' is the image of RST
we will find the rule of translation using the coordinates of :
\(\begin{gathered} R=(-4,5) \\ R^{\prime}=(3,2) \end{gathered}\)So, the rule will have the form :
\(\begin{gathered} R\rightarrow R^{\prime} \\ (x,y)\rightarrow(x+h,y+k) \end{gathered}\)\(\begin{gathered} 3=-4+h\rightarrow h=7 \\ 2=5+k\rightarrow k=-3 \end{gathered}\)So, the answer is :
T(7,-3)
7 units right ; 3 units down
the numbers 33, 55, 77, aa and bb have an average (arithmetic mean) of 1515. what is the average of aa and bb?
The average of aa and bb is 740.
Define arithmetic mean.The result of adding together and dividing by the total number of numbers or variables is the arithmetic mean, which is also known as the average or average value. In statistics, the arithmetic mean is significant. Central tendency is measured using the arithmetic mean. By giving each observation the same amount of weight, it enables us to determine the frequency distribution's center for a quantitative variable (in contrast to the weighted arithmetic mean).
Given,
Arithmetic mean = 1515
Total number of values = 5
Formula:
Sum/Total = Arithmetic mean
33 + 55 + 77 + aa + bb/ 5 = 1515
165 + aa + bb = 7575
aa + bb = 7575 - 165
aa + bb= 7410
The average of aa and bb is 740.
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Find the Principal unit normal for r(t) = sintit cost; + tk Evaluate it at t = Tyz Sketch the situation
We can plot the vector r(t) and the vector N(T) at the given value of t = T.
To find the principal unit normal for the vector-valued function r(t) = sin(t)i + tcos(t)j + tk, we need to compute the derivative of r(t) with respect to t and then normalize it to obtain a unit vector.
First, let's find the derivative of r(t):
r'(t) = cos(t)i + (cos(t) - tsin(t))j + k
Next, we'll normalize the vector r'(t) to obtain the unit vector:
||r'(t)|| = sqrt((cos(t))^2 + (cos(t) - tsin(t))^2 + 1^2)
Now, we can find the principal unit normal vector by dividing r'(t) by its magnitude:
N(t) = r'(t) / ||r'(t)||
Let's evaluate the principal unit normal at t = T:
N(T) = (cos(T)i + (cos(T) - Tsin(T))j + k) / ||r'(T)||
To sketch the situation, we can plot the vector r(t) and the vector N(T) at the given value of t = T.
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Solve using substitution.
2x - 2y = 2
5x + y =14
help
Answer:
X= 1.5 Y= 2.5
Step-by-step explanation:
Math problem giving brainly!
Answer:
can you type the question so i can answer it, i cant see the picture
Step-by-step explanation:
When x = -10, what is the value of | -6 | ?
26
10
B
24
C
Given right triangle ABC, what is the value of tan(A)?
L
On solving the provided question, we can say that value of tan(a) in right triangle ABC = sin(A)/cos(A) = B/P
What is triangle?A triangle is a polygon since it has three sides and three vertices. It is one of the basic geometric shapes. The name given to a triangle containing the vertices A, B, and C is Triangle ABC. A unique plane and triangle in Euclidean geometry are discovered when the three points are not collinear. Three sides and three corners define a triangle as a polygon. The triangle's corners are defined as the locations where the three sides converge. 180 degrees is the result of multiplying three triangle angles.
here,
we have a right triangle ABC
angle B = 90
so,
value of tan(a) = sin(A)/cos(A) = B/P
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Complete sentence.
9.5 L ≈ ___ qt
9.5 liters is approximately equal to 10.037435 quarts.
To convert 9.5 liters to quarts, we need to determine the conversion factor between the two units. The conversion factor between liters and quarts is 1 liter = 1.05668821 quarts. Therefore, to convert 9.5 liters to quarts, we can multiply 9.5 by the conversion factor:
9.5 L * 1.05668821 qt/L ≈ 10.037435 qt
Hence, approximately 9.5 liters is equal to 10.037435 quarts.
It's important to note that the conversion factor between liters and quarts may vary slightly depending on the specific context or rounding rules applied. However, using the commonly accepted conversion factor of 1 liter = 1.05668821 quarts provides a close approximation.
Therefore , 9.5 liters is approximately equal to 10.037435 quarts.
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Find all possible values of each expression if you know that 3 < a < 4
--> -a
All the possible values of a must be less than 3.75 excluding values from 3 and below
Inequalities are expressions that are not separated by an equal sign
Since we are not given the required inequality expression, Let us assume the equation below:
10 - 5a > -a
Add 5a to both sides
15 - 5a + 5a > -a + 5a
15 > 4a
4a<15
a < 15/4
a<3.75
Since the value of a is less than 3.75, hence all the possible values of a must be less than 3.75 excluding values from 3 and below.
NB: The inequality expression was assumed, the same concept can be applied to any other expression
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192=6x+10x+8x+1/2(6)(8)+1/2(6)(8)
The value of x in the equation 192 = 6x + 10x + 8x + 1/2(6)(8) + 1/2(6)(8) is 6
Evaluating the equationFrom the question, we have the following parameters that can be used in our computation:
192=6x+10x+8x+1/2(6)(8)+1/2(6)(8)
Express properly
So, we have
192 = 6x + 10x + 8x + 1/2(6)(8) + 1/2(6)(8)
When the like terms are evaluated, we have
192 = 24x + 48
When the like terms are evaluated again, we have
24x = 144
Divide bith sides of the equation by 24
x = 6
Hence, the value of x in the equation is 6
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Answer:
x=6
Step-by-step explanation:
192=6x+10x+8x+1/2(6)(8)+1/2(6)(8)
192=24x+24
144=24x
x=6
Therefore, x=6.Adam is going to a carnival that has games and rides. Each game costs $1.50 and each
ride costs $3. Adam spent $15 altogether at the carnival and the number of games he
played is 3 times the number of rides he went on. Graphically solve a system of
equations in order to determine the number of games Adam played, x, and the
number of rides Adam went on, y. And graph.
Answer:
6 games and 2 rides
Step-by-step explanation:
Start with the equation 3*1.50x+3y=15
Then plug that equation into desmos graphing calculator
Then round up
This will tell you the number of games, and rides Adam went on
Translate the sentence into an equation.
The sum of 5 times a number and 3 is 8.
Use the variable c for the unknown number.
Answer:
5c + 3 = 8
Step-by-step explanation:
variable is c
5 × c + 3
5 c + 3 = 8
write the equation of the line that is parallel to y=-4x+9 that passes through point (15,-2)
Answer:
y = -4x + 58
Step-by-step explanation:
Equation of line: y =mx + b
Here, m is the slope and b is the y-intercept.
Parallel lines have same slope.
y = -4x + 9
m = -4
Equation of the required line: y = -4x + b
The line passes through (15, -2). Substitute x and y values and find the value of 'b'.
-2 = -4*15 + b
-2 = -60 + b
-2 + 60 = b
b = 58
Equation of line:
y = -4x + 58
how would i find y in this situation
Answer:
C.) 7√2/2
Step-by-step explanation:
tan¤ = opp/adj
tan 45° = y/7√2/2
1 = y/7√2/2
1 = 2y/7√2
7√2 = 2y
2y = 7√2
y = 7√2/2
NOTE: ¤ = Theta
Write an equation that is parallel and perpendicular to the points (-2,-3)
Answer: y=2x+1
Step-by-step explanation:
Find the slope of the existing line by calculating a Rise/Run (the change in y for a change in x). Pick any two points on the existing line. I picked (-2,3) and (2,1).
Rise = 1-3 = -2
Run = 2-(-2)= 4
Rise/Run (slope) = -2/4 or -0.5
Although we don't need it, the equation for the existing line is y=-0.5x+b. B is easy to find, since it is the value of y at x=0 (the y-intercept). y=2 at x=0, so the existing line's equation is y=-0.5x+2
A line that is perpendicular to this line will have a slope that is the negative inverse of the reference line. The negative inverse of -0.5 is -1/-0.5 or 2. The new line will look like this:
y = 2x + b
To find b, use he given point (-2,-3) in the new equation and solve for b:
y = 2x + b
-3 = 2(-2) + b
b = 1
The equation of the line perpendicular to the reference line and going through (-2,-3) is
y = 2x + 1
See attached graph.
Last year, Marshall withdrew $8,000 from his RRSP under the Lifelong Learning Program to fund a one-year program at a community college. This year, he worked full-time but, he would like to pursue a university degree beginning next year. Marshall is wondering whether he can participate in the LLP again next year. What statement is true?
a) Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.
b) Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf.
c) He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.
d) He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.
Marshall is wondering whether he can participate in the LLP again next year. The statement that is true is "He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.
The Lifelong Learning Plan is a program that helps Canadian residents finance their post-secondary education through their registered retirement savings plans (RRSP). If an individual is attending school full-time, they can withdraw up to $10,000 a year from their RRSP under the program, or up to $20,000 in total. There are certain rules that must be followed by an individual participating in the LLP. For example, withdrawals must be made within four years of enrolling in an eligible educational program, and repayments must begin within the same period.
Here are the statements: Provided he repays his LLP balance in full by the end of this year, Marshall can participate in the LLP again next year.Marshall can only participate in the LLP once over his lifetime. However, his wife can make a LLP withdrawal from her RRSP on his behalf. He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000. He can only participate in the LLP a second time if he repays his LLP balance in full and waits 5 years before he returns to school.The correct statement is: He can participate in the LLP again, but only to the extent that his existing LLP balance is less than $20,000.
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About how many times greater is the volume of the cylinder than the volume of the cone?
Your answer is 3 times larger.
The volume of any cone is 1/3 the volume of the cylinder that could be formed around that cone, therefore the volume of any cylinder is 3 times larger than the volume of the cone that could fit inside.
We know this is true because the equation for the volume of a cone is (1/3) πr²h, and the equation for the volume of a cylinder is πr²h
I hope this helps!
a pilot and two passengers landed on a 2,100 foot east-west gravel strip with an elevation of 1,800 feet. the temperature is warmer than expected and after computing the density altitude it is determined the takeoff distance over a 50 foot obstacle is 1,980 feet. the airplane is 75 pounds under gross weight. what would be the best choice?
Based on the given information, the best choice would be to reduce the aircraft weight by at least 100 pounds. This would allow the aircraft to take off within the available runway distance of 2,100 feet
Based on the given information, the pilot and the two passengers landed on a 2,100 foot east-west gravel strip with an elevation of 1,800 feet. After computing the density altitude, it is determined that the takeoff distance over a 50 foot obstacle is 1,980 feet. The airplane is 75 pounds under gross weight. In this case, the best choice would be to reduce the aircraft weight by at least 100 pounds.
Here's why:
Since the takeoff distance over a 50-foot obstacle is 1,980 feet, this distance is greater than the available runway of 2,100 feet. This means that the aircraft will not be able to take off from the runway. Therefore, the pilot needs to take necessary steps to ensure that the aircraft can take off safely.
One option is to reduce the aircraft's weight, which would decrease the required takeoff distance. Since the aircraft is only 75 pounds under gross weight, the pilot would need to reduce the weight by at least 100 pounds to ensure a safe takeoff. This would allow the aircraft to take off within the available runway distance of 2,100 feet.
Therefore, reducing the weight by 100 pounds would be the best choice.
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An equation is shown below:
5(2x - 8) + 15 = -15
Write the steps you will use to solve the equation and explain each step.
Answer:
x=10
Step-by-step explanation:
do problem like image attached
what is the product of b(b^2 - 12b+1)
Answer:
depends on what B is,
Step-by-step explanation:
if you just want an equivalent equation. b^3-12b^2+b, but otherwise theres no way to answer without an inequality or equivalent equation without B