What is the significance of Isaac's name? What is the significance of Isaac's name?

Answer:

\(m=14kg\)

Explanation:

Hello.

In this case, since the force is defined in terms of the mass and acceleration by:

\(F=m*a\)

We can easily compute the mass by solving for it:

\(m=\frac{F}{a}\)

Whereas the force is 182 N (kg*m/s²) and the acceleration is 13 m/s², therefore, we obtain:

\(m=\frac{182kg\frac{m}{s^2} }{13\frac{m}{s^2}}\\\\m=14kg\)

Best regards.

The magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole is given by

|E| = |-(p * k) / r^3|

Generally, The electric field of an electric dipole at a point far away from the midpoint of the dipole is given by the following expression:

E = (p * k) / r^3 * (3 *cos(theta) * i^ + sin(theta) * j^)

where:

p is the magnitude of the dipole moment, equal to q * d (q is the charge and d is the distance between the charges)

k is the Coulomb constant (9 x 10^9 N * m^2/C^2)

r is the distance from the dipole to the point where the electric field

is being calculated theta is the angle between the vector pointing from the dipole to the point where the electric field is being calculated and the dipole moment vector (in this case, the -axis) i^ and j^ are the unit vectors in the x and y directions, respectively.

Since the dipole is oriented along the -axis and the point where the electric field is being calculated is far away in the -direction,

theta = pi and the expression for the electric field becomes:

E = (p * k) / r^3 * (3 *cos(pi) * i^ + sin(pi) * j^)

E = -(p * k) / r^3 * (i^)

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Answer:

Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.

Now length of the rod along the direction of motion

= lo cos 60°_/1-(0.8) 2/c2

= lo/2×0.6

= 0.3 lo.

Length of the rod perpendicular to the direction of motion.

= lo sin 60°

=_/3/2 lo

Length of moving rod

l = [(0.3lo)2+{lo_/3/2} 2] 1/2

= 0.916 lo.

Percentage contraction

= lo-0.916lo/lo×100

= 8.4%.

Explanation:

Answer:

The correct answer is - A matter that has an ordered arrangement of atoms, molecules, or ions.

Explanation:

In physics, a crystal is a type of solid matter in which a highly arranged molecule or atoms present to form a lattice that extended in all directions. It is a lightweight clear solid which is normally is colorless.

It can be cubic, hexagonal, triclinic, monoclinic, orthorhombic, tetragonal, and trigonal that are ordered arrangments. Its internal symmetry is visible to its surface.

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Answer:

hope this will help

Explanation:

if your title doesn't have enough information, make a list of the key words ... If you are not sure what should be included in each summary sentence, use ... Often you can present the hypothesis and the supporting reasoning in one paragraph. ... Describe specific parts of the procedure or data that contributed to your learning.  

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

The Sun's gravity pulls on the planets, just as Earth's gravity pulls down anything that is not held up by some other force and keeps you and me on the ground.

Explanation:

Hope that helps

Considering the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is the same.

The area, space, or field around it is an electric field of an isolated charge. There are mainly two types of electric fields i.e., static and dynamic. Moving charges produced dynamic electric fields whereas static electric fields are produced by stationary charges.

Direction and magnitude do not change over time for static electric fields. The direction can be positive or negative which is determined by the charge of the source.

The electric field formula is the electric field magnitude at a certain point from the charge Q, and it hangs on two factors- the distance r from the point to the origin Q and the amount of charge at the origin Q.

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The correct question is:

Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/mV/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 mm away from the positive charge (1 mm is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength.

Consider the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is________________.

Answer:

proton is positively charged changechar

Explanation:

Answer:

a. 250kg I think it's the right answer. hope it helps:)

Answer:

C.10

Explanation:

because when you divide 50 divided by 5 = 10

Answer:

4.45×10¯¹¹ N

Explanation:

From the question given above, the following data were obtained:

Mass of ball (M₁) = 4 Kg

Mass of bowling pin (M₂) = 1.5 Kg

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Distance apart (r) = 3 m

Force of attraction (F) =?

The force of attraction between the ball and the bowling pin can be obtained as follow:

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 4 × 1.5 / 3²

F = 4.002×10¯¹⁰ / 9

F = 4.45×10¯¹¹ N

Therefore, the force of attraction between the ball and the bowling pin is 4.45×10¯¹¹ N

Answer:

9.836 ms^-2

Explanation:

If

r= 3re

m= 9me

But

g= Gm/r^2

G= 6.67 × 10^-11

me= 6 × 10^24 Kg

re= 6.38 × 10^6 m

g= 6.67 × 10^-11 × 9×6 × 10^24/(3 ×6.38 × 10^6)^2

g= 9.836 ms^-2

Answer:

B

Explanation:

When you lift something you are applying Force and Movement.

The two things we use in Work formula.

The other options you don´t have any movement happening.

Lifting a bag of groceries is the best example of work being done on an object because it is the only case from the given list in which both force and displacement are present,

Therefore the correct answer is option B.

The total amount of energy transferred when a force is applied to move an object through some distance.

The SI  unit of work done by an object is Joules.

The best example of work being done on an item is lifting a bag of groceries since it is the only instance from the list given in which both force and displacement are present, and both external force and displacement are required to do any non-zero work.

Thus, the correct answer is option B.

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Answer:

this stuff hard no cap

Explanation:stop cheating cuhhh

Answer:

5N

Explanation:

We have a simple problem of momentum here.

ΔMomentum= mΔv= FΔt

Solve for F

mΔv/Δt=F

Plug in givens

1*(2-1.5)/0.1=F

F=5N

The amount of force that the wall imparts on the ball is 5.0N

According to Newton's second law, the formula for calculating the force applied is expressed as:

\(F=ma\)

m is the mass of the object

a is the acceleration of the object

Since acceleration is the change in velocity of an object, hence \(a=\frac{\triangle v}{t}\)

The applied force formula becomes \(F=\frac{m\triangle v}{t}\)

Given the following parameters

m = 1.0kg

\(\triangle v=2.0-1.5\\\triangle v=0.5m/s\)

t = 0.1sec

Substitute the given parameter into the formula

\(F=\frac{1.0\times 0.5}{0.1}\\F=\frac{0.5}{0.1}\\F=5N\)

Hence the amount of force that the wall imparts on the ball is 5.0N

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Answer:

a) ΔS = 14.46 J/k

b) ΔS = 70.76 J/k

Explanation:

The general formula to calculate the entropy change accompanied with a process is:

ΔS = ΔQ/T

where,

ΔS = entropy change for the process

ΔQ = Heat Transfer during the process

T = Absolute Temperature during the process

a)

In this case the heat transfer will be given as:

ΔQ = (ΔHfus)(N)

where,

ΔHfus = Molar Heat of Fusion of Tin = 7.029 KJ/mol

N = No. of moles of tin = 1 mol

Therefore,

ΔQ = (7.029 KJ/mol)(1 mol)

ΔQ = 7.029 KJ = 7029 J

and the absolute temperature is:

T = 213°C +273 = 486 k

using these values in the entropy formula, we get:

ΔS = 7029 J/486 k

ΔS = 14.46 J/k

b)

In this case the heat transfer will be given as:

ΔQ = (ΔHvap)(N)

where,

ΔHvap = Molar Heat of Vaporization of Carbon Dioxide = 15.326 KJ/mol

N = No. of moles of Carbon Dioxide = 1 mol

Therefore,

ΔQ = (15.326 KJ/mol)(1 mol)

ΔQ = 15.326 KJ = 15326 J

and the absolute temperature is:

T = 216.6 k

using these values in the entropy formula, we get:

ΔS = 15326 J/216.6 k

ΔS = 70.76 J/k

Answer:

In our everyday life, the deltoids take on most of the work in rotating our arms, but besides that the deltoid muscle also allows us to carry objects at a safe distance from the body. It is also responsible from stopping a dislocation or injury to the humerus when we carry something heavy.

Answer:

Lifting, pushing and pulling

Explanation:

it uses it

Answer:

W = 2100 [J]

Explanation:

We must remember that work is defined as the product of force by the distance traveled.

W = F*d

where:

W = work [Joules]

F = force = 300 [N]

distance = 7 [m]

Now replacing:

W = 300*7

W = 2100 [J]

Answer:

True

Explanation:

hope I could help :)

Answer:

true

Explanation:

i know my stuff

Answer:

Explanation:The Mass Of The Left Block M1 = 1.3 Kg And The Mass Of The Right Block M2 = 3.1 Kg. The Angle Between The String And The Horizontal Is ... (10%) Problem 8: Two blocks connected by a string are pulled across a horizontal surface by a ... m m, 50% Part (a) Write an equation for the magnitude of the force exerted by the ...

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

360000

Explanation:

Answer:

360000 milliseconds

Explanation:

I have this remembered dont worry homie i got chu

Answer:

\(39000\ \text{kg m/s}\)

West

Explanation:

m = Mass of car = \(1.3\times 10^{3}\ \text{kg}\)

t = Time = 9 seconds

u = Initial velocity = 30 m/s

v = Final velocity = 0

Impulse is given by

\(J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}\)

The magnitude of the total impulse applied to the car to bring it to rest is \(39000\ \text{kg m/s}\).

The direction is towards west as the sign is negative.

When a car is stopped, facing upwards on a hill, the friction acts in the opposite direction to the motion that the car would naturally take if it were not stopped.

In this case, the car would roll backwards down the hill due to the force of gravity. The friction between the tires and the road surface acts in the opposite direction to this motion, providing a force that opposes the car's tendency to roll backwards. Therefore, the friction acts in the forward direction, up the hill, to prevent the car from rolling backwards.

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Cube moves first, that the cube which is neutral in nature. Hence, the cube which is neutral will move.  

To solve this problem, we need to calculate the electrostatic force between the two charged cubes and compare it with the force of static friction between the cubes and the surface. The cube with the smaller force of friction will begin to move first. The parameter panel and sketch of the problem are shown below:

Parameter Panel:

Mass of cube 1 (m1) = 2.0 g = 0.002 kg

Mass of cube 2 (m2) = 4.0 g = 0.004 kg

Distance between the centers of the cubes (d) = 6.0 cm = 0.06 m

Charge rate of each cube (q) = 7.0 nC/s

Coefficient of static friction (μ) = 0.65

Sketch:

     |-----------|        |-----------|

     |     2     |        |     1     |

     |-----------|        |-----------|

           |                 |

          d=6.0 cm          d=6.0 cm

           |                 |

           |-----------------|

(a) To determine which cube moves first, we need to calculate the electrostatic force between the charged cubes and compare it with the force of static friction between the cubes and the surface. The electrostatic force between two charged objects is given by Coulomb's law:

F = (k * q1 * q2) / d^2

where k is the Coulomb constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges on the cubes, and d is the distance between them. For each cube, the charge is increasing at a rate of 7.0 nC/s, so the charge at any time t is given by:

q = 7.0 x 10^-9 C/s * t

At t = 0, the cubes are neutral and have no charge. At some later time t, the charges on the cubes are:

q1 = 7.0 x 10^-9 C/s * t

q2 = 7.0 x 10^-9 C/s * t

The electrostatic force between the cubes is then:

F = (9.0 x 10^9 N m^2/C^2) * (q1 * q2) / d^2

= (9.0 x 10^9 N m^2/C^2) * [(7.0 x 10^-9 C/s * t)^2 / (0.06 m)^2]

The force of static friction between each cube and the surface is:

Ff = μ * N

= μ * m * g

where N is the normal force, m is the mass of the cube, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.81 m/s^2).

The normal force N is the force exerted by the surface on the cube, and is equal in magnitude to the weight of the cube:

N = m * g

Plugging in the values for each cube, we get:

Ff1 = μ * m1 * g

= 0.65 * 0.002 kg * 9.81 m/s^2

= 0.0127 N

Ff2 = μ * m2 * g

= 0.65 * 0.004 kg * 9.81 m/s^2

= 0.0254 N

Comparing the electrostatic force between the cubes and the force of static friction, we find:

F - Ff1 = (9.0 x 10^9 N)

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Answer:

The speed of sound varies with the material in which the waves travel.

Explanation:

knowledge and research

It can be concluded as per the given table that the speed of sound varies with the material in which the waves travel. The correct option is A.

Speed is the pace at which an object's position changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar quantity.

It has a dimension of time-distance. As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.

According to the given table, it can be inferred that the material in which the waves travel affects the speed of sound.

Thus, the correct option is A.

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Answer:

A capacitor is formed from two square plates of edge length a and separation d, with d <

Explanation:

A capacitor is formed from two square plates of edge length a and separation d, with d <

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

We are given:

Direction of motion: 25 degrees south of the east axis

Distance covered  = 125 m

East component of the Ball:

this component is denoted by green color in the image

Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle

The magnitude of the side of the triangle on the x-axis denotes the east component of the ball

Using trigonometry, we find that the east component of the ball is:

125 * Cos(25 degrees)

125 * 0.9 = 112.5 i   (here, i denotes rightward direction on the x-axis)

North Component of the Ball:

this component is denoted by blue color in the image

Using trigonometry, we find that the North component of the ball is:

125* Sin(25 degrees)  (-j)      [j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']

125 * 0.42 (-j)

52.5 (-j) =   -52.5 j

Therefore the direction vector of the ball is 112.5 i - 52.5 j

where 112.5 i is the East Component and -52.5 is the North Component