Explanation:
the SI unit of force is newton(N)
but i am not really sure of acceleration
A train is running smoothly along a curved track at the rate of 50 m/s. a passenger standing on a set of scales observes that his weight is 10% greater than when the train is at rest, the track is banked so that the force acting on the passenger is normal to the floor of the train. what is the radius of the curvature of the track?
By using components of the centripetal force, it can be calculated as Radius of the curvature of the track is 557.5 m
According to the centripetal force, the force is
\(F_{c} = \frac{mv^{2} }{r}\)
where m is the mass of the object , v is the velocity and r is the radius of the curvature.
This Fc will have two components, FccosФ and FcsinФ.
FccosФ = mg
1.1 mgcosФ = mg
cosФ = \(\frac{1}{1.1}\)
so, sinФ = 0.416
Now, FcsinФ = \(\frac{mv^{2} }{r}\)
1.1mgsinФ = \(\frac{mv^{2} }{r}\)
r = 557.478
r = 557.5 m
Hence the radius of the curvature is 557.5 m.
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10. Jared and Claire are climbing the stairs. Jared gets tired and stops halfway to the fourth floor. Claire makes it to the fourth floor without a problem. If Jared is twice as heavy as Claire, who has more gravitational potential energy? Explain your answer.
Answer:
They both have the same GPH
Explanation:
GPE = mgh
m = mass of Claire
2m = mass of Jared
h = height of Claire
h/2 = height of Jared
GPE-jared = (2m)(g)(h/2) = mgh
GPE-claire = mgh
They both have the same GPH
What is the final velocity of the ball at its highest point?
The final velocity of the ball at its highest point of a projectile's trajectory is zero, because the object is at the highest point of its trajectory and it's not moving.
When an object is projected into the air, it is subject to the force of gravity pulling it downward. This force causes the object to follow a parabolic trajectory, where the velocity of the object changes constantly. As the object reaches the highest point of its trajectory, it has reached its maximum height and its upward velocity is zero. The object is at the highest point of its trajectory and it's not moving, so the final velocity is zero. It's important to note that at this point, the net force acting on the object is also zero, the force of gravity is pulling it downward. It is worth mentioning that this is true for a projectile under the effect of gravity only. If there were other forces acting on the projectile, like air resistance, the final velocity at the highest point would not be zero.
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Water flows at the rate 1.17 along a level channel of width 1.7 m with a depth of 149 mm. An hydraulic jump occurs. Calculate the critical depth in mm. Answer:
The critical depth in the hydraulic jump can be calculated using the specific energy equation. In this case, with a flow rate of 1.17 m³/s, channel width of 1.7 m, and a depth of 149 mm, the critical depth can be determined.
To calculate the critical depth in the hydraulic jump, we can use the specific energy equation, which relates the flow rate, channel dimensions, and water depth. The equation can be written as:
E = (Q² / (2g)) + (y² / (2g)) + (A² / (P * g))
Where:
E is the specific energy,
Q is the flow rate,
g is the acceleration due to gravity,
y is the water depth,
A is the cross-sectional area of flow,
P is the wetted perimeter of the channel.
In this case, we have a flow rate of 1.17 m³/s, a channel width of 1.7 m, and a depth of 149 mm (or 0.149 m). We need to find the critical depth, which occurs at the hydraulic jump. At the critical depth, the specific energy reaches its minimum value.
To determine the critical depth, we need to set the derivative of the specific energy equation with respect to the water depth equal to zero and solve for y. This will give us the critical depth. However, calculating the critical depth requires knowing additional parameters such as the cross-sectional area and wetted perimeter, which are not provided in the given information. Without these values, it is not possible to calculate the critical depth accurately.
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What is the measure, in degrees, of the acute angle formed by the minute hand and the hour hand on a standard clock when it indicates $9$:$40$
Answer:
9.666666º
Explanation:
In this exercise we must transform from hexadecimal units and decimal units.
For this we must take into account that in the sexagesimal system the base is 60 and in the decimal system the base is 10. This means that by taking 60 minutes we have a degree
transform
9º 40 ’a Aº
we use a direct proportion rule, where 60 minutes is equivalent to 10 decinal minutes
40 ’[hexadecimals] = 40‘ (10/60) = 6,666 ’[decimals]
let's take these pleasant decimal minutes
6.666 ’= 6.6666 (1/10) = 0.66666º
we already have all the units in degrees, we can add them
9º + 0.666666º = 9.666666º
SCIENCE QUESTIONS
An inflated negatively charged balloon is moved toward a stream of water form a faucet. What will happen to the water molecules?
a) The protons in the water will repel the balloon so the water moves away from the balloon
b) The protons in the water will attract the balloon so the water moves toward the balloon
c) The electrons in the water will repel the balloon so the water moves toward the balloon
d) The electrons in the water will attract the balloon so the water moves away from the balloon
An inflated negatively charged balloon moved toward a stream of water from a faucet will produce the following effect in the water molecules:
The protons in the water will attract the balloon so the water moves toward the balloon; the correct option is B.What is static electricity?
Static electricity is defined as the study of charges at a point or charges that are not free to move.
Positive charges (due to protons) are separated from negative charges (due to electrons). Like charges repel while opposite charges attract.
In static electricity, the charges that accumulate in a substance result in the substance either repelling or attracting other substances.
Charges are acquired by induction of contact in static electricity.
A device that is used to determine the nature of charges acquired by a body in static electricity is the Gold Leaf Electroscope.
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200N=75N/130M , What is the acceleration of the man which is 80kg and the box which is 50kg given the mass of 130kg and the force of 75N? friction force=125N, Box= 50 kg, Man= 80kg, Applied force= 200N, sum of forces=75N
We can calculate the acceleration of the man and the box using Newton's second law of motion. The applied force is 200 N, and the friction force opposing the motion is 125 N.
The man has a mass of 80 kg, and the box has a mass of 50 kg. The combined mass of the man and the box is 130 kg. Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration: F net = m*a. The net force (sum of forces) in this scenario is the difference between the applied force and the friction force: F net = 200 N - 125 N = 75 N.
Now we can use the combined mass of the man and the box (130 kg) and the net force (75 N) to find the acceleration:
75 N = 130 kg * a
To solve for acceleration (a), we can divide both sides by 130 kg:
a = 75 N / 130 kg ≈ 0.58 m/s²
So, the acceleration of the man and the box is approximately 0.58 m/s².
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While exploring a cave, a spelunker starts at the entrance and moves the following distances in a horizontal plane. She goes 83.6 m north, 274.0 m east, 144.6 m at an angle θ=40° north of east, and 169.3 m south. Figure suggests the situation but is not drawn to scale._________Find her resultant displacement from the cave entrance. _________
According to the situation given in the question, the restaurant displacement from the cave entrance is 21.5° from east.
The spelunker's resultant displacement can be found using vector addition.
First, we can find the magnitude of the vector representing the 144.6 m north of east displacement. Using the Pythagorean Theorem, we may accomplish this:
= c^2
= a^2 + b^2
here c is the magnitude of the vector, and a and b are the components of the vector along the north and east axes, respectively.
=> a = 144.6 x cos(40°)
= 121.5 m
=> b = 144.6 x sin(40°)
= 95.2 m
=> c = √(121.5^2 + 95.2^2)
= 153.1 m
Next, we can add up all the vector displacements to find the resultant displacement:
=> north = 83.6 m
=> east = 274.0 m
=> north of east = 153.1 m
=> south = -169.3 m
=> resultant
= north + east + north of east + south
= 83.6 + 274.0 + 153.1 - 169.3
= 342.4 m
The magnitude of the resultant displacement is 342.4 m.
To find the direction of the resultant displacement, we can use the tangent function:
=> θ
= tan^-1(north/east)
= tan^-1(83.6/274.0)
= 21.5°
So the direction of the resultant displacement is 21.5° from east.
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When water vapor (a gas) starts to cool, it can
become a liquid. What causes this change in the
state of matter in water?
Answer:
This process is CONDENSATION
Explanation:
Condensation occurs when water vapour loses some of its kinetic energy to a colder body and changes into liquid state.
when you ride your scooter you have momentum When you ride twice as last you have Select one: a.almost twice the momontum- b.nonc ol the above c.twice the momentum d. four times the momentum
When you ride your scooter, you have momentum which is determined by your mass and velocity. Momentum is a vector quantity, meaning it has both magnitude and direction.
When you ride twice as fast, you have twice the velocity, which results in a change in momentum.The relationship between velocity and momentum is direct. Therefore, when you ride twice as fast, you have twice the momentum. This means that the correct answer is option c. You will have twice the momentum when you ride twice as fast on your scooter.It is important to note that momentum is conserved in a closed system, which means that the total momentum before and after the event remains the same.
Therefore, if you were to ride your scooter into a wall, your momentum would be transferred to the wall, causing you to stop abruptly. When you ride your scooter, you have momentum. Momentum is the product of an object's mass and velocity (p = mv). If you ride twice as fast, your velocity doubles. In this case, your momentum also doubles, since the mass remains the same. Therefore, the correct answer is c. twice the momentum.
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At the end of 3N force acts on the object during time interval of 1.5seconds with force acting towards right. A constant force of 4N to left is applied for 3seconds. What is the velocity at the end of the 3seconds ?
Answer:
v_f = -7.5 m / s
Explanation:
Let's analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is
we assume that the direction to the right is positive
I = I₁ + I₂
I = F₁ Δt₁ - F₂ Δt₂
I = 3 1.5 - 4 3
I = -7.5 N s
now let's use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)
I = Δp
I = m (v_f - v₀)
v_f = I / m
v_f = -7.5 / m
to finish the calculation we must assume a mass m = 1 kg
v_f = -7.5 m / s
the negative sign in the body is moving to the left
your friend, who is in a field 70 meters away from you, kicks a ball towards you with an initial velocity of 18 m/s. assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2, how long does it take for the ball to reach you?
With the use of formula, the time taken for the ball to reach you is 31.6 s
What is Acceleration ?Acceleration can be defined as velocity change per time taken. It is a vector quantity.
Given that your friend, who is in a field 70 meters away from you, kicks a ball towards you with an initial velocity of 18 m/s. assuming the grass causes the ball to decelerate at a constant rate of 1.0 m/s2, to know how long it takes for the ball to reach you, we will use the formula
s = ut - 1/2at² where
v = 0
u = 18 m/s
a = 1 m/s²
s = 70 m
t = ?
70 = 18t - 1/2 × 1 × t²
70 = 18t - 0.5t²
Multiply all by 2
140 = 36t - t²
t² - 36t + 140 = 0
Using completing the square method
t² - 36t + 18² = 18² - 140
( t - 18 )² = 324 - 140
( t - 18 )² = 184
t - 18 = √184
t = 18 + 13.6 or 18 - 13.6
t = 31.6 s or 3.4 s
Therefore, the ball will reach you in the next 31.6 s
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HELP ASAP!!!
which statements below best describes colors, Check all that apply
black pigment is the absorption of red, green, and blue light.
black pignment is the reflection of red, green, and blue light
white light is the combination of red, green, and blue light
white pigment is the absorption of red, green, and blue light
Answer:
1)Black pigment is the absorption of red, green, and blue light.
3)White light is the combination of red, green, and blue light
Select the correct answer.
Mary pushes a crate by applying force of 18 newtons. Unable to push it alone, she gets help from her friend, Anne. Together they apply a force of
43 newtons, and the crate just starts moving. If the coefficient of static friction is 0.11, what is the value of the normal force?
OA. 2.0 x 102 newtons
OB.
2.6 x 10² newtons
O C.
O D.
OE.
3.9 x 10² newtons
4.0 x 10² newtons
4.3 x 10² newtons
The value of the normal force is 3.9 x 10² newtons.
The correct answer is option C.
The coefficient of static friction between the crate and the floor is 0.11. The crate just starts moving after the force of 43 N is applied by Mary and Anne. Therefore, the force of friction that acts on the crate is equal to the maximum value of static friction, which is given by the product of the coefficient of static friction and the normal force.
The force of friction is given by: f = μN
where f is the force of friction, μ is the coefficient of static friction and N is the normal force acting on the crate.
Since the crate just starts moving, the applied force must overcome the maximum force of static friction.
Therefore, we have:
f = μNmax
and F applied = F required to overcome friction
= μNmax= 0.11 N
Thus, the maximum value of the normal force acting on the crate is given by:
Nmax = F/f = 43/0.11 = 390.9 N ≈ 3.9 x 10² N
Therefore, the value of the normal force is 3.9 x 10² newtons.
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Two persons (each on a skateboard) are initially standing still and facing each other before pushing off of each other. One person (50 kg) moves backwards at 1.1 m/s. Calculate the velocity of the second person (65 kg).
Answer:
The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.
Explanation:
Law Of Conservation Of Linear Momentum
The total momentum of a system of bodies is conserved unless an external force is applied. The formula for the momentum of a body with mass m and velocity v is:
P=mv.
If we have a system of bodies, then the total momentum is the sum of them all
\(P=m_1v_1+m_2v_2+...+m_nv_n\)
If a collision occurs, the velocities change to v' and the final momentum is:
\(P'=m_1v'_1+m_2v'_2+...+m_nv'_n\)
In a system of two masses, the law of conservation of linear momentum is:
\(m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\)
According to the conditions of the problem, two persons standing on a frictionless surface are initially at rest (v1=0, v2=0). Their masses are m1=50 Kg and m2=65 Kg. After the push, one person (say m1) moves backward at v1'=-1.1 m/s. We can calculate the speed of the other person by solving for v2':
\(\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2)\)
Substituting:
\(\displaystyle v'_2=\frac{50*0+65*0-50(-1.1)}{65)\)
\(\displaystyle v'_2=\frac{55}{65}\)
\(v'_2=0.85 \ m/s\)
The second person will have a velocity of 0.85 m/s in the opposite direction of the first person.
What volume of silver metal will have a mass of exactly 2500.0 g? The density of silver is 10.50 g/cm3.
*Include your units!
Round your answer to the nearest tenth.
Explanation:
The density of silver is 10.5g/cm3
=2500.0g/10.5g/cm3
=238.09cm3
238.1cm3 to nearest tenth.
I hope my answer helps. Please mark as brainliest.
What energy transformations take place from the outlet charger to the ringing phone?
Explain how the Law of Conservation of Energy applies to the energy
transformations that occur from the outlet charger to the ringing phone.
Answer:
Chemical energy transformations take place from the outlet charger to the ringing phone.
Explanation:
chemical energy
While charging the mobile electrical energy gets transformed into chemical energy. Most of the contemporary mobile phone batteries are lithium-ion batteries where the power is saved by the chemical transformations in the ionic structure of the battery. When the power gets into the mobile phone it is transformed and collected as chemical energy inside of the battery and when we utilize the mobile the earlier saved chemical energy is again transformed into electrical energy.
The energy transformation that takes place from the outlet charger to the
ringing phone is electrical energy from the outlet is converted to chemical
energy and back to electrical energy and sound energy when the phone is
being used and ringing.
The charger provides a source of electrical energy which gets converted to
chemical energy stored in the battery. During use, the chemical energy gets
converted to electrical energy to power the phone and to sound energy
when it rings with heat energy being dissipated also.
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What is one way that nuclear fission and nuclear fusion are similar? A. Nuclei are split into smaller nuclei. B. Atoms are altered in both processes. C. Small nuclei combine to form larger nuclei. D. They are both used to produce electrical power.
Answer:
B. Atoms are altered in both processes
Explanation:
Answer: B. Atoms are altered in both processes
Explanation:
Based on astronomy from space-based telescopes, select all of the correct statements from the following list.a. Most types of electromagnetic waves are not visible to ground-based telescopes.b. There would be no limit to what an optical telescope in space could see.c. Enough infrared energy gets to Earth's surface that infrared telescopes do not need to be put in orbit.d. The Chandra and Spitzer telescopes are all in space.
Statements which are correct are (a) i.e. Telescopes on the ground cannot see the majority of electromagnetic waves. & (d) The Chandra and Spitzer telescopes are all in space.
(a) Most types of electromagnetic waves, such as X-rays and gamma rays, are not visible to ground-based telescopes due to the absorption of these waves by the Earth's atmosphere. Therefore, to detect these types of electromagnetic waves, space-based telescopes are needed.
(d) This statement is correct. The Chandra X-ray Observatory and the Spitzer Space Telescope are both space-based telescopes designed to observe X-rays and infrared radiation, respectively. Since X-rays and infrared radiation are not visible to ground-based telescopes due to the Earth's atmosphere, space-based telescopes are necessary to detect them.
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Why can water dissolve some ionic compounds, like NH4Cl, as well as some nonionic compounds, like methanol?
Answer:
Water is polar molecule. ... The ionic compounds are dissolved as these ions attract the hydrogen( negative charge attraacts them) and oxygen (positive charge attracts them) whereas methanol is a polar molecule and forms hydrogen bond with water molecules and hence dissolves.
Explanation:
6-The ideal-gas equation of state relates absolute pressure. P (atmi); gas volume, V(liters); number of moles of gas, n. Mol. ; and absolute temperature, T K) : [10] PV=0. 08206nT (a) Convert the equation to one relating P. Psig. ,Hf3),n. Lb-mole. , and T∗ F2. (b) A 30. 0 molec; CO and 70. 0 molete N gas mixture is stored in a cylinder with a volume of 3. 5 fts at a temperature of 85∘F. The reading on a Bourdon gauge attached to the cylinder is 500psi. Calculate the total amount of gas ( b-mole) and the mass of CO. Lb. In the tank. (c) Approximately to what temperature ("F) would the cylinder have to be heated to increase the gas pressure to 3000 pig, the rated safety limit of the cylinder? (The estimate would only be approximate because the ideal gas equation of state would not be accurate at pressures this high. )
To convert the ideal-gas equation to relate Ppsig, Vft³, nlb-mole, and T°F and the total amount of gas is calculated by converting the moles of CO and N to lb-mole and to estimate the temperature needed to increase the gas pressure to 3000 psig, Convert the obtained temperature in K to °F.
The equation relating P (psig), V (ft³), n (lb-mole), and T* (°F) is:
P = 14.7 * P(atm), V = 28.3168 * V(L), n
= 2.20462 * n(mol), and T*
= (9/5) * T(K) - 459.67 and to calculate the total amount of gas in lb-mole, multiply the number of moles of CO by its molar mass and convert to lb-mole and to estimate the temperature in °F required to increase the gas pressure to 3000 psig.
(a) To convert the equation, we need to apply the following conversions:
- To convert P from atm to psig, multiply by 14.7 (since 1 atm = 14.7 psig).
- To convert V from liters to ft³, multiply by 28.3168 (since 1 liter = 0.0353 ft³).
- To convert n from mol to lb-mole, multiply by 2.20462 (since 1 mol = 2.20462 lb-mole).
- To convert T from K to °F, use the conversion formula:
T* = (9/5) * T(K) - 459.67.
(b) To calculate the total amount of gas in lb-mole, multiply the number of moles of CO by its molar mass (using the periodic table) and convert to lb-mole by multiplying by the molar mass of CO (28.01 lb/lb-mol). To calculate the mass of CO in lb, multiply the number of moles of CO by its molar mass (28.01 g/mol) and convert to lb by dividing by 453.59237 g/lb.
(c) To estimate the temperature in °F required to increase the gas pressure to 3000 psig, rearrange the ideal gas equation to solve for T*. Substitute the known values: P = 3000 psig (pressure limit), V = 3.5 ft³ (volume), n = 30.0 mole (number of moles), and solve for T*. Note that this estimate may not be accurate at high pressures.
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Answer:
a on edge
Explanation:
A pen contains a spring with a constant of 216 N/m. When the tip of the pen is in its retracted position, the spring is compressed 4.10 mm from its unstrained length. In order to push the tip out and lock it into its writing position, the spring must be compressed an additional 6.10 mm. How much work is done by the spring force to ready the pen for writing? Be sure to include the proper algebraic sign with your answer.
Answer:The spring force is conservative, so the work done by the spring force is equal to the negative of the potential energy stored in the spring:
U = -1/2 k x^2
where k is the spring constant and x is the displacement from the unstrained length.
The initial compression of the spring is 4.10 mm = 0.00410 m, and the additional compression is 6.10 mm = 0.00610 m. The total compression of the spring is therefore x = 0.00410 m + 0.00610 m = 0.0102 m.
The potential energy stored in the spring when it is compressed by a distance x is:
U = -1/2 k x^2
Substituting the given values, we get:
U = -1/2 (216 N/m) (0.0102 m)^2
U = -0.0112 J
The work done by the spring force to ready the pen for writing is equal to the change in potential energy:
W = U_final - U_initial
where U_initial is the potential energy of the spring when it is compressed 4.10 mm, and U_final is the potential energy of the spring when it is compressed an additional 6.10 mm.
U_initial = -1/2 (216 N/m) (0.00410 m)^2 = -0.000090 J
U_final = -1/2 (216 N/m) (0.0102 m)^2 = -0.0112 J
W = U_final - U_initial
W = (-0.0112 J) - (-0.000090 J)
W = -0.0111 J
The negative sign indicates that the work done by the spring force is done on the pen (i.e. the pen gains potential energy), consistent with our intuition that the spring force is providing the energy needed to push the pen tip out and lock it into place. Therefore, the proper algebraic sign for the work done by the spring force is negative.
Explanation:
A sinusoidal electromagnetic wave with frequency 3.7x1014Hz travels in vacuum in the +x direction. The amplitude of magnetic field is 5.0\times{10}^{-4}T. Find angular frequency \omega, wave number k,\ and amplitude of electric field. Write the wave function for the electric field in the form E = Emaxsin (\omega t-kx).
The angular frequency (ω) of the electromagnetic wave is \(2.32x10^15 rad/s\), the wave number (k) is \(7.34x10^6 rad/m\), and the amplitude of the electric field (Emax) is \(1.66x10^10 V/m\). The wave function for the electric field is E = Emaxsin(\(ωt - kx\)). where ω is the angular frequency, k is the wave number, t is time, and x is the position along the wave
The angular frequency (ω) of a sinusoidal wave is related to its frequency (f) by the equation ω = 2πf. Therefore, we have:
\(ω = 2π(3.7x10^14 Hz) = 2.32x10^15 rad/s\)
The wave number (k) is related to the wavelength (λ) by the equation k = 2π/λ. Since the wave is traveling in vacuum, the speed of light (c) can be used to relate frequency and wavelength, c = fλ. Therefore, we have:
\(k = 2π/λ = 2π/(c/f) = 2πf/c = 2π(3.7x10^14 Hz)/(3x10^8 m/s) = 7.34x10^6 rad/m\)
The amplitude of the electric field (Emax) can be obtained from the amplitude of the magnetic field (Bmax) using the equation Emax = cBmax, where c is the speed of light. Therefore:
\(Emax = (3x10^8 m/s)(5.0x10^-4 T) = 1.50x10^5 V/m\)
Finally, the wave function for the electric field is given by E = Emaxsin(ωt - kx), where ω is the angular frequency, k is the wave number, t is time, and x is the position along the wave.
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you are traveling west on the highway. At 1:00 you pass kilometer marker 485. At 4:30 you pass kilometer marker 154. What has your average velocity been.
Technically a question for physical science but i didn't know what to label it.
Your average velocity for the journey has been 94.57 km/h.
What is the average velocity of an object?The average velocity of an object is the ratio of total displacement to the total time of motion of an object.
V = ( total displacement ) / ( total time )
The total displacement of your journey is calculated as;
x = 485 km - 154 km
x = 331 km
The total time of the motion is calculated as;
t = 4:30 - 1:00 = 3:30 = 3.5 hours
v = x / t
v = ( 331 km ) / ( 3.5 hr )
v = 94.57 km/h
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two pennies lie on the surface of a turntable. as the turntable spins faster, which penny slides first?
As the turntable spins faster, the penny that is furthest from the turntable's centre will slide first.
Centripetal force increases as the turntable spins faster, exerting more force on the pennies. The centripetal force is proportional to the angular velocity squared and the angle of deflection from the turntable's centre. In other words, the penny that is farther away from the turntable's centre experiences a stronger centripetal force than the penny that is closer to it.
With the centripetal force, the frictional force between the pennies and the turntable likewise grows. Nevertheless, the coefficient of static friction—a feature of the surface where the pennies and turntable are placed—limits the frictional force. For the penny that is nearer to the turntable's centre than for the coin that is farther away, the coefficient of static friction
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certain atom has 86 protons. Assume that the nucleus is a sphere with radius 6.98 fm and with the charge of the protons uniformly spread through the sphere. At the nucleus surface what are (a) the magnitude and (b) direction (radially inward or outward) of the electric field produced by the protons?
Answer:
a. \(2.54 \times 10^{21} NC^{-1}\)
b. Outwards
Explanation:
The computation is shown below:
a. The magnitude could be computed by applying the following formula
Electric field, E is
\(= \frac{kq}{r^{2}} \\\\ = \frac{9\times10^{9} \times86\times1.6\times10^{-19}}{(6.98\times10^{-15})^2}\)
\(= 2.54 \times 10^{21} NC^{-1}\)
b. As we can see that there is a positive charge so the direction would be in the outward direction in the electric field i.e. produced by the protons
Basically we applied the above formula for the first part
A concave lens creates a virtualimage at -47.0 cm with amagnification of +1.75. What isthe object distance?(Mind your minus signs.)(Unit = cm)
Object distance = 26.86 cm
Explanation:Given:
Image distance, v = -47.0 cm
Magnification, M = 1.75
Object distance, u = ?
\(\begin{gathered} M=\frac{|v|}{|u|} \\ \\ 1.75=\frac{47.0}{u} \\ \\ u=\frac{47.0}{1.75} \\ \\ u=26.86\text{ cm} \\ \end{gathered}\)Object distance = 26.86 cm
Is the equation balanced?
2H2O + O2 = 4MgO + 3Fe
Answer:
no
Explanation:
the equation can't be balanced because it doesn't have the same elements on each side of the equal sign.
The given equation is not a balanced chemical equation because it does not contain the same elements on both sides of the equation.
What is the balanced chemical equation?A chemical equation can be explained as the representation of a chemical reaction in terms of symbols of the substances. A balanced equation containing the same number of atoms of each element on either side of the equation.
The law of mass conservation is followed by every balanced chemical equation. By obeying this law, the total mass on the reactant side should be equal to the total mass on the product side in a balanced equation.
On both sides of the chemical equation, the same elements as well as an equal number of elements are present as the chemical reaction does not alter the identity of the elements. Therefore, the given equation is not a balanced chemical equation.
Learn more about the balanced chemical equation, here:
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Question 5. One 1,5V battery runs a portable MP3 player that draws 5,7mA of current
for about six hours before it runs out.
a) What is the resistance If the portable MP3 player?
b) How much power is dissipated in the portable MP3 player?
c) Find the energy delivered by the portable MP3 player?
A proton moves with a speed of 0.54c. Find the speed of an electron that has the same momentum and kinetic energy. (Express the answer as the quantity of one minus a num…
A proton moves with a speed of 0.54c. Find the speed of an electron that has the same momentum and kinetic energy. (Express the answer as the quantity of one minus a number times c.) same momentum(1 − ? ) ✕ c same kinetic energy(1 − ? ) ✕ c
The final answer expressed as the quantity of one minus a number times c is: same momentum(1 − 0.1013) ✕ c same kinetic energy(1 − 0.1013) ✕ c
To find the speed of an electron that has the same momentum and kinetic energy as a proton moving at 0.54c, we need to use the formulas for momentum and kinetic energy:
Momentum: p = mv
Kinetic energy: K = 0.5mv²
Where p is momentum, m is mass, v is velocity, and K is kinetic energy.
Since we are looking for the speed of an electron that has the same momentum and kinetic energy as a proton moving at 0.54c, we can set the equations for the proton and electron equal to each other:
Proton momentum: pp = mpvp
Electron momentum: pe = meve
Proton kinetic energy: Kp = 0.5mpvp²
Electron kinetic energy: Ke = 0.5meve²
Setting the equations equal to each other:
mpvp = meve
0.5mpvp² = 0.5meve²
Solving for ve:
ve = (mpvp)/me
ve² = (mpvp²)/me
Substituting in the values for the proton:
ve = (1.67 × 1\(0^{-27}\) kg)(0.54c)/(9.11 × 1\(0^{-31}\) kg)
ve² = (1.67 × 1\(0^{-27}\) kg)(0.54c)²/(9.11 × 1\(0^{-31}\) kg)
Solving for ve:
ve = 9.87c
ve² = 97.56c²
Taking the square root of ve²:
ve = 9.87c
Therefore, the speed of an electron that has the same momentum and kinetic energy as a proton moving at 0.54c is 9.87c.
Expressing the answer as the quantity of one minus a number times c:
ve = (1 - 0.1013) × c
So the final answer is: same momentum(1 − 0.1013) ✕ c same kinetic energy(1 − 0.1013) ✕ c
More on momentum: https://brainly.com/question/28457745
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