what is the result of seafloor spreading?

Answers

Answer 1

Answer:

Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.

Explanation:

eventually the crust cracks.


Related Questions

Car A travels with speed v around curve number one, which has a radius r. Car B travels with speed 2v around curve number two, which has a radius 2r. The acceleration will be ?
1-greater for car A.
2-greater for car B.
3-zero for both cars.
4-the same for both cars.
chose one

Answers

The acceleration will be greater for car B.

What is Acceleration ?

Acceleration is a physical quantity that describes the rate at which an object's velocity changes over time. It is defined as the change in velocity per unit of time, and it is a vector quantity, meaning it has both magnitude and direction.

When an object experiences acceleration, its velocity changes either in speed, direction, or both. If the acceleration is in the same direction as the velocity, the object's speed increases. If the acceleration is in the opposite direction as the velocity, the object's speed decreases. If the acceleration is perpendicular to the velocity, the object's direction changes.

The standard unit of acceleration is meters per second squared (m/s^2). A positive acceleration indicates that an object is speeding up, while a negative acceleration indicates that an object is slowing down. If the acceleration is zero, then the object's velocity is constant.

According to the given information:

To calculate the acceleration of each car around its respective curve, we can use the following formula:

a = v^2 / r

where a is the centripetal acceleration of the car, v is its speed, and r is the radius of the curve.

For car A, traveling at speed v around curve number one with radius r, the acceleration is:

a_A = v^2 / r

For car B, traveling at speed 2v around curve number two with radius 2r, the acceleration is:

a_B = (2v)^2 / (2r) = 4v^2 / (2r) = 2v^2 / r

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In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?

In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O is

Answers

The point through which this ray will pass, after refraction by the lens is point D.

What is refraction of light?

The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.

From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.

Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.

So point D is the correct answer.

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Balance the following equation:
H3B03 →_B203 +_H20
a. 1, 3,2
b. 2,4,6
C. 4, 2, 6
d. 6, 4,2

Answers

It's c I think ( 4 , 2 , 6 , )

A pendulum with a mass of 4.0 kg is released from a height of 2.9 cm above the height of its resting position. How fast will the pendulum be moving when it passes through the lowest point of its swing?

Answers

The pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

To determine the speed of the pendulum when it passes through the lowest point of its swing, we can use the principle of conservation of mechanical energy.

At the highest point (2.9 cm above the resting position), the pendulum has gravitational potential energy. As it swings down, this potential energy is converted into kinetic energy, given by the equation:

Potential Energy (PE) = Kinetic Energy (KE)

The highest point's potential energy is given by:

PE = mgh

Where:

m = pendulum mass (4.0 kg).

g = acceleration due to gravity (9.8 m/s^2)

h = height above the resting position (2.9 cm = 0.029 m)

Substituting the values, we have:

PE = 4.0 kg * 9.8 m/s^2 * 0.029 m = 1.1356 J

Since energy is conserved, this potential energy will be completely converted into kinetic energy at the lowest point. Thus, the kinetic energy is also 1.1356 J:

KE = 1.1356 J

The following equation gives the kinetic energy:

KE = (1/2)mv^2

Where:

m = pendulum mass (4.0 kg).

v = velocity of the pendulum at the lowest point

Rearranging the equation to solve for v:

v^2 = (2KE) / m

v^2 = (2 * 1.1356 J) / 4.0 kg

v^2 = 0.5678 m^2/s^2

Taking the square root of both sides results in the following:

v ≈ 0.754 m/s

Therefore, the pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

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two solid spheres of radius R made os same steel is placed in contact and exerts a force of f1. if the radius is 3R, what will be the magnitude of gravitational force

Answers

The magnitude of the gravitational force 0f two solid sphere of radius R is 81F₁ newton.

Gravitational force :

Any two bodies' mutual attraction is directly proportional to the sum of their masses and inversely proportional to the square of their separation.

Force is given as :

F₁ =  (G x m x m )/ (2r)²

To calculate gravitational force :

F₂ = G  x  [27m x 27m]/ [6r]²

F₂ = (G x27)² m² / 36r²

F₂ = (81 G  x m²) / 4r²

F₂ = 81F₁

The magnitude of the gravitational force of two solid sphere of radius R is 81F₁ newton.

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Owen decides he wants to be cool. And what is cooler than playing an instrument? Not just any instrument,but THE instrument! Of course he is referring to the tuba. He just loves the note B4 (f = 494 Hz). And thetuba is one of the few instruments that can play it. He practices the Ba note over and over and forgets topractice anything else! If the tuba is an air column that is closed at the one end and the air temperature is22°C, calculate the length of the air column for the second resonant length. Include a diagram.

Answers

Answer:

L = 0.34 m/s

Explanation:

The frequency of sound in the air column closed at one end is given by

\(f_n=\frac{nv}{4L}\)

where n = harmonic number, v = velocity of sound, and L = length of the pipe.

Now,

\(v=331\sqrt[]{\frac{T}{273}}\)

First, we calculate the sound velocity at T = 22 celsius.

Putting in T = 22 + 273 k into the above equation gives

\(v=331\sqrt[]{\frac{22+273}{273}}\)\(\boxed{v=344.1m/s\text{.}}\)

With the value of v in hand, we calculate the length of the air column for the second resonant length.

Solving for L in the first equation gives

\(f_n=\frac{nv}{4L}\Rightarrow\boxed{L=\frac{nv}{4f_n}}\)

Piutting in n = 2, v = 344.1 m/s, and f_n = 494 m/s gives

\(L=\frac{2\cdot344.1}{4(494)}\)\(\boxed{L=0.35m\text{.}}\)

Hence, the length of the air column for the second resonant length is 0.35 m.

You can not exert force on a wall unless

Answers

unless...the wall simulaneiously exerts the same amount of force on you.

You can not exert force on a wall unless the wall is exerting an equal and opposite force on you. The correct option is D.

For every action, there is an equal and opposite response, states Newton's third rule of motion.

When you push against a wall, the wall responds by applying an equal and opposite force to you. The reaction force is referred to as this.

You couldn't apply force to the wall if it weren't for the wall's reaction force. Therefore, in order for you to exert force on the wall, the wall must be there and exert an equal and opposite force.

Thus, the correct option is D.

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Your question seems incomplete, the probable complete question is:

You can not exert force on a wall unless:

A. The wall is made of a soft material.

B. The wall is moving towards you.

C. The wall is inclined at an angle.

D. The wall is exerting an equal and opposite force on you.

what is mean by combination reaction ?​​

Answers

\( \underline{\purple{\large \sf Combination \: reaction :-}} \)

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.

\( \underline{\green{\large \sf For\: example :}} \)

\( \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o\)

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

(a) how would the pattern of bright and dark fringes produced in a young's double-slit experiment change if the light waves coming from both slits had their phases shifted by an amount equivalent to a half wavelength? (b) how would the pattern change, if the light coming from only one of the slits had its phase shifted by an amount equivalent to a half wavelength?

Answers

a)  In a young's double-slit experiment when the light waves emanating from both slits have their phases altered by a half wavelength, destructive interference becomes constructive interference and vice versa.

b) The pattern would change by half a fringe if the light from only one of the slits had its phase altered by an amount comparable to a half wavelength.

In the case where the light waves coming from both slits have their phases shifted by an amount equivalent to a half wavelength, the pattern of bright and dark fringes produced in Young's double-slit experiment would change. It is because the crest from one wave is always falling on the trough of another wave, and hence the destructive interference becomes constructive interference and vice versa.

In the case where the light coming from only one of the slits had its phase shifted by an amount equivalent to a half wavelength, the pattern would shift by half a fringe. Because the path difference between the two rays originating from the two slits will not be equal for all points in space along with the screen. Hence, the bright and dark fringes pattern will be shifted in this case.

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Callisto is a moon of Jupiter
(mass= 1.90 x 1027 kg), which orbits
the planet with a period of 16.9 days.
What is the radius of its orbit?
[?] x 10¹ m
Coefficient (green)
Exponent (yellow)
Enter

Answers

8.27 x 1013 meres is the orbital radius.

Additional details:-

Jupiter's mass, 1.9 x 1027 kg, and the time interval, 16.9 days, are equal to 1.46 x 106 seconds. The radius is needed, thus r. Solution

The moon must be held in its orbit by a gravitational force equal to the centripetal force between Jupiter and the moon.

6.67 x 10⁻¹¹ N/m²kg

2 x 1.9 x 10/27 x 1.46 x 10'6 / 4 r = 6.85 x 102'7 G = 6.67 x 10'11 N/m2kg2 r = 8.27 x 10'7

What distinguishes Callisto, a huge moon orbiting Jupiter, from all other large moons in the solar system?

The second-largest moon in Jupiter's orbit and the third-largest moon in the solar system is called Callisto. Of all the objects in our solar system, its surface has the most craters.

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Two trains ‘A’ and ‘B’ leave the same station on parallel lines. Train ‘A’ starts with a uniform acceleration of 1/6 m/s2 and attains the speed of 24 km/hr, then stem is reduced to keep the speed constant. Train ‘B’ leaves 40 seconds after, with uniform acceleration of 1/3 m/s2 to attain the maximum speed of 48 km/hr. When will it overtake the train ‘A’?

Answers

Answer:

Explanation:

Let's first convert the speeds of the trains from km/hr to m/s:

Train A: 24 km/hr = (24 x 1000) / (60 x 60) = 6.67 m/s

Train B: 48 km/hr = (48 x 1000) / (60 x 60) = 13.33 m/s

Now, let's find the distance covered by train A until it reaches its constant speed:

v = u + at

where

u = initial velocity = 0

a = acceleration = 1/6 m/s^2

t = time taken to reach constant speed

At constant speed, v = 6.67 m/s

So, 6.67 = (1/6)t + 0

t = 40 seconds

Using the formula for distance covered during uniform acceleration:

s = ut + (1/2)at^2

The distance covered by train A during the acceleration phase is:

s = (1/2)(1/6)(40^2) = 133.33 m

Now, let's find the equation of motion for train B:

s = ut + (1/2)at^2

where

u = initial velocity = 0

a = acceleration = 1/3 m/s^2

t = time taken to overtake train A

At the time of overtaking, both trains will cover the same distance. Let's call this distance "d". So we have:

d = 133.33 + 6.67t (distance covered by train A + distance covered by train B)

Setting the equations for both trains equal to each other, we get:

133.33 + 6.67t = (1/2)(1/3)t^2 + (1/3)t^2

Simplifying and solving for t, we get:

t = 180 seconds

Therefore, train B will overtake train A after 180 seconds or 3 minutes.

A block of weight 5 N is placed on a horizontal turntable. The maximum friction that can be developed between the block and the turntable is 2 N. If the turntable is rotating at 0.6 revolution per second, what is the greatest distance of the block from the center of rotation so that it does not slip? ​

Answers

The greatest distance of the block from the center of rotation so that it does not slip is approximately 0.089 meters or 8.9 centimeters.

In order for the block to remain on the turntable without slipping, the frictional force between the block and the turntable must be equal to or less than the maximum friction that can be developed, which is 2 N in this case. The maximum frictional force is given by the product of the coefficient of friction and the normal force.The normal force is equal to the weight of the block, which is 5 N. Therefore, the maximum frictional force is 2 N.

To find the greatest distance of the block from the center of rotation without slipping, we need to consider the centrifugal force acting on the block due to the rotation of the turntable. The centrifugal force is given by the product of the mass of the block, the acceleration due to the rotation (which is equal to the square of the angular velocity times the radius), and the coefficient of friction.

Since the weight of the block is 5 N, the mass can be calculated as 5 N divided by the acceleration due to gravity (approximately 9.8 m/s^2), which gives us a mass of approximately 0.51 kg.

Given that the turntable is rotating at 0.6 revolution per second, the angular velocity can be calculated as 2π times the frequency, which gives us approximately 3.77 rad/s.

Let's assume the greatest distance of the block from the center of rotation is "r" meters.

The centrifugal force is then given by m * (ω^2) * r, and this force must be equal to or less than the maximum frictional force, which is 2 N.

Therefore, we can write the equation:

m * (ω^2) * r ≤ 2 N

Substituting the values we calculated:

0.51 kg * (3.77 rad/s)^2 * r ≤ 2 N

Simplifying the equation, we find:

r ≤ 0.089 m

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a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south, and finally flies 550 m in the direction 35 degrees north of east. Use the analytical method to find the resultant displacement of the drone (magnitude and direction)

you can help with a​

a) a drone flies 150 m to southwest (directly between south and west), then flies 85 m directly south,

Answers

The resultant of the displacement is 336.5m

What is resolution of vectors?

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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2. A 2.0-kg block slides down an incline surface from point A to point B. Points A and B are 2.0 m apart. If the coefficient of kinetic friction is 0.26 and the block is starting at rest from point A. What is the work done by friction force

Answers

Answer:a

Explanation:

calculate the electric potential energy in a capacitor that stores 9.40 x 10 to the negative 10 C of charge at 50.0 V

Answers

The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

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Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion

Answers

Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

What is Newton's first law of motion?

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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A reducing agent ____

accepts electrons

donates electrons

is reduced

neutralizes

Answers

Answer:

A reducing agent accepts electrons

cheese is made of cheese

Answers

Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.

What is a dairy product?

Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.

Hence, cheese is made up of casein proteins that are present in the milk.

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What is Emmy's velocity at a time of 3.73 s?

What is Emmy's velocity at a time of 3.73 s?

Answers

Answer:

Below

Explanation:

From the top graph her acceleration is -3 m/s^2 at the point in question

From the lower graph at time t = 3 s  her velocity = 5 m/s

vf = vo + at

   =  5 m/s  + (-3)(.73)          <====3.73 s is .73 s past the 3 s mark

   =  2.81 m/s

A Swimmer makes a turn at a pool wall which answer choice best describes the direction the swimmer accelerates when she pushes against the wall?

Answers

Answer:

a

Explanation:

away from

The direction the swimmer accelerates when she pushes against the wall is away from the wall.

What is Newton's third law ?

Newton's third law states that, for every action, there is an equal and opposite reaction.

Here,

Given that, the swimmer is making a turn at the pool wall.

In order to take a turn, the swimmer have to exert a push against the wall with her feet, such that it is the action and she turning back is the reaction of it.

According to Newton's third law, for every action, there is an equal and opposite reaction. So, the wall exerts equal force back to the swimmer. As a result, the swimmer will be accelerated towards the opposite direction of the wall, thus making a turn.

Hence,

The direction the swimmer accelerates when she pushes against the wall is away from the wall.

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Please help

4. What are the lowest points on a transverse wave called?
a. Crests
b. troughs
C. compressions
d. rarefractions


5. Any substance that a wave moves through is called a
a. medium
b. vibrate
C. crest
d. frequency

Answers

Answer:

Explanation:

the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m

4. Low points are called troughs

5. Medium: substance through which a wave can travel

Three objects are moving along a straight line as shown in Figure 8.1. Taking the positive direction to be to the right, what is the total momentum of this system?

Three objects are moving along a straight line as shown in Figure 8.1. Taking the positive direction

Answers

Taking the positive direction to be to the right,  the total momentum of this system is - 14kg-m/s

Option B is correct.

What is momentum?

momentum is described as the product of the mass and velocity of an object and a vector quantity possessing a magnitude and a direction.

momentum = mass x velocity

momentum 1  = 5 x 8kg = 40 kg-m/s

momentum 2 = 4 x 15 kg = 60 kg-m/s

momentum 3 = 2 x 3kg = 6 kg-m/s

Taking the positive direction to be to the right,  the total momentum of this system is momentum 1  - momentum 2 + momentum 3

total momentum =  40 kg-m/s - 60 kg-m/s + 6 kg-m/s

total momentum  = -20kg-m/ + 6 kg-m/s

total momentum =  - 14 kg-m/s

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PLEASE NEED HELP ASAP

PLEASE NEED HELP ASAP

Answers

Answer:

My youngins heartless, so they ain't playin' no games

We really want 'em dead, he got hit up close range

He fuc__ked up in the head, he wanna see some more brains

On that corner, I couldn't stay up out that do_0pe game

My cousin got indicted dealin' coc__aine

She an Insta>:gram addict, she want more fame

I used to starve, now I'm blowing up like pro__pane

Told my inner self, "I promise you I won't change"

Explanation:

The picture shows two different species of mammals that use wings to glide among tree tops. However, scientists theorize that these mammals are not closely related.



Which best explains why these two animals look so similar if they are not closely related?

They have analogous structures that developed for different functions.
They have homologous structures that developed for different functions.
They live in similar environments and have analogous structures adapted to them.
They live in similar environments and have homologous structures adapted to them.

Answers

Answer:

c

Explanation:

Answer:

c

Explanation:

csCA

4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.

Answers

Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.

What are the birds?

The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.

In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.

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A bullet of mass m is fired horizontally into a wooden block of mass M lying on a table. The bullet remains in the block after the collision. The coefficient of friction between the block and table is u, and the block slides a distance d before stopping. Find the initial speed v0 of the bullet in terms of M, m, u, g, and d

Answers

Answer:

\(\displaystyle \frac{M + m}{m}\, \sqrt{2\, x\, u\,g}\).

Explanation:

This question can be solved in the following steps:

Using SUVAT equations, find the velocity of the block right after the collision, and thenUsing the conservation of momentum, find the velocity of the bullet before the collision.

Assume that the table is level. The normal force on the block would be equal to the weight of the block in magnitude \((M + m)\, g\), but opposite in direction. As the block slows down, the only unbalanced force on the block would be friction \((-u\, (M + m)\, g)\) (negative since this force is opposite to the direction of motion.)

The acceleration of the block would be:

\(\begin{aligned} a &= \frac{(\text{net force})}{(\text{mass})} \\&= \frac{-u\, (M + m)\, g}{M + m} \\ &= (-u\, g)\end{aligned}\).

Apply the following SUVAT equation to find the velocity \(v_{i}\) of the block right after the collision:

\(\displaystyle {v_{2}}^{2} - {v_{1}}^{2} = 2\, a\, x\),

Where:

\(v_{2} = 0\) is the velocity after the acceleration,\(v_{1}\) is the velocity at the beginning of the acceleration, which is right after the collision, \(a = (-u\, g)\) is the acceleration, and\(x = d\) is the displacement during the acceleration.

Rearrange and solve for \(v_{1}\), the velocity right after collision:

\(\begin{aligned}v_{1} &= \sqrt{{v_{2}}^{2} - 2\, a\, x} \\ &= \sqrt{0^{2} - 2\, (-u\, g)\, x} \\ &= \sqrt{2\, x\, u\, g}\end{aligned}\).

Apply the conservation of momentum to find the velocity of the bullet before the collision. Right after the collision, sum of momentum would be:

\((M + m)\, \sqrt{2\, x\, u\, g}\).

Right before the collision, sum of momentum would be:

\(m\, v_{0}\).

By the conservation of momentum:

\(m\, v_{0} = (M + m)\, \sqrt{2\, x\, u\, g}\).

Rearrange and solve for \(v_{0}\):
\(\displaystyle v_{0} = \frac{M + m}{m}\, \sqrt{2\, x\, u\, g}\).

The initial speed v0 of the bullet in terms of M, m, u, g, and d is identified by the equation v0 = (M + m) * \(\sqrt{((2 * u * g * d * m) / (M + m))} /m\).

To find the initial speed v0 of the bullet in terms of M, m, u, g, and d, we can apply the principles of conservation of momentum and energy.

First, let's consider the conservation of momentum. Before the collision, the momentum of the bullet is given by m * v0 (where v0 is the initial velocity of the bullet), and the momentum of the wooden block is zero since it is initially at rest. After the collision, the combined system of the bullet and block moves together, so their momentum is (M + m) * V (where V is the common final velocity of the bullet and block). Since momentum is conserved, we have:

m * v0 = (M + m) * V

Next, let's consider energy conservation. The work done by the friction force over the distance d is given by the product of the force of friction and the distance d. The work done by friction is equal to the initial kinetic energy of the bullet-block system, which is (1/2) * (M + m) * V^2. Thus, we have:

(1/2) * (M + m) * V² = u * (M + m) * g * d

Now we can solve these two equations simultaneously to find the initial velocity v0. Rearranging the first equation, we have:

v0 = (M + m) * V / m

Substituting this expression for v0 into the second equation, we get:

(1/2) * (M + m) * [(M + m) * V / m]² = u * (M + m) * g * d

Simplifying and solving for V, we obtain:

V = \(\sqrt{((2 * u * g * d * m) / (M + m))}\)

Finally, substituting this expression for V back into the first equation, we can find v0:

v0 = (M + m) * \(\sqrt{(2 * u * g * d * m) / (M + m)}\) / m

Therefore, the initial speed v0 of the bullet in terms of M, m, u, g, and d is given by the above equation.

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Two blocks of equal mass are connected by a string that passes over a pulley, as shown in the figure. Block 1 hangs from the string, and block 2 can slide on a table. The system is released from rest. Using conservation of energy, a student derives an expression for the speed v of block 1 when it has fallen a distance h after the system has been released from rest and obtains the equation v=gh−−√ . Question The figure presents a diagram of a pulley system at the edge of a table. A block labeled Block 1 is hanging off the table. Two other blocks are on the table. The block on the left is labeled Block 3 and the block on the right is labeled block 2. Block 1 is connected to a string that passes through a pulley. The left end of the string is connected to the right side of Block 2. Another string connected the left side of Block 2 to the right side of Block 3. A third block of the same mass as blocks 1 and 2 is attached to block 2 on the table, as shown in the figure. Using conservation of energy, the student repeats a derivation for the speed v of block 1 when it has fallen a distance h . Which of the following is a correct expression for v ? Responses gh√3 the fraction with numerator the square root of g h, and denominator 3 gh√2

Answers

Block y will experience a stronger pull from gravity and fall more quickly than block x since it has more mass than block x is 29.4 md

To complete this task, we will apply Newton's second law. Assume that a block with mass m is moving up.

T-W₁ = m a

W₃ - T = M a

w₃ - w₁ = (m + M) a

g = a = (3m - m) / (3m + m)

a = 2/4 g

a = ½ g

The blocks move at a pace of

v² = v₀² + 2 ½ g x

v = √ g x

b) As work is a scalar, it adds to other quantities.

luminous blocks

W1 = W d = mg

d = -a 3 m hefty block

W2 = 3m g d = W d

the entire project is

W = W₁ + W₂

W = 2 m g d

c) When all external pressures are applied to the centre of mass, they relate to it being

a = ½ g

T = 2m1m2g/(m2 + m1)

= 2x mx3x3mg/ 4m

= 14.7 m

Work done in moving by distance by tension on both masses d

= 2 x 14.7 m x d ( 2 x force x displacement ) ( 2 x force x displacement )

= 29.4 md .

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When throwing a ball upwards, the velocity is positive, and the acceleration is negative. True of False?

Answers

Answer:

The velocity & acceleration will be taken as negative when a ball is thrown upward because work is done against the gravity.

Explanation:

Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.

Answers

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

What is hydrostatic pressure?

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case​

Answers

Answer:

Explanation:

In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.

So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.

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