What is the relationship between the magnetic force and the distance between the magnets?
Answers
The strength of the magnetic force is inversely proportional to the square of distance between the magnets. Thus, as the distance increases, force between the magnets decreases.
What is magnetic force?Magnetic force, is the force generated by magnetic flux lines arised from a magnetic field. A magnet have a south pole and north pole. There will be repulsive force between two like poles and attractive force between two unlike pole.
The force between two objects is always in inverse proportion with the distance and this is well explained by Coulomb's law of forces.
Thus, F ∝ 1/r² where, r is the distance.
Therefore, as the distance between two magnets increases the magnetic force between them decreases.
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Related Questions
A tortoise can move with a speed of 10.0cm/s, while a rabbit can move 10 times faster. In a race, both of them started at the same time, but the rabbit stopped to rest for three minutes. The tortoise wins by a distance of 10cm from the rabbit. How long is the race?
A. 125.2s
B. 159.8s
C. 199.9s
D. 205.7s
Answers
Answer:
C. 199.9 s
Explanation:
3 minutes = 3×60 = 180 seconds.
the turtle moves in that time 180×10 = 1800 cm.
in other words the rabbit gave it that much head-start (it does not matter if that was at the begin of in the middle of the race).
the rabbit moves with 10×10cm/s = 100cm/s.
the rabbit needs therefore 1800/100 = 18 seconds for the
1800 cm.
at that time the turtle has added another 18×10 = 180 cm.
for which the rabbit needs 180/100 = 1.8 seconds.
during that time the turtle has added 1.8×10 = 18 cm.
and so on.
in formal mathematics this looks like this :
1800 + 10x = 100x
after x seconds of the rabbit running both will have run the same distance, and it is a tie.
1800 = 90x
x = 20 seconds
so, at that point, the rabbit was actively running for 20 seconds and raced 20×100 = 2000 cm
and the turtle was actively running for 180 + 20 = 200 seconds, and also covered 200×10 = 2000 cm.
but our question tells us that the turtle won by 10 cm.
so, the race was over a little bit before these 200 seconds (for a tie).
this means, the rabbit could not run the last 10 cm for the tie (because the race was over and the turtle had won).
the rabbit would have needed 10/100 seconds for these 10 cm.
as speed = distance/time
we need to divide distance by speed
distance/1 / distance/time
to get time.
so,
10cm/1 / 100cm/s = 10s/100 = 1/10 s
so, we need to deduct this 1/10 s from the 200 seconds of the turtle (and also from the 20 seconds for the rabbit).
the race lasted of course the whole time the turtle was running (while the rabbit was resting, officially still participating in the race with speed 0 for 3 minutes).
and so, the race was 199.9 s long.
Objects 1 and 2 attract each other with an electrostatic force of 8 units. If the charge of Object 1 is multiplied by 1 AND the charge of object 2 is multiplied by 3 AND the distance separating Objects 1 and 2 is divided by 4, then the new electrostatic force will be _____ units.
Answers
The new electrostatic force will be 384 units.
The electrostatic force of attraction between two charges \(q_{1} \\\)(charge of object 1) and \(q_{2}\)(charge of object 2) separated by a distance d is given by
\(F = \frac{q_{1} q_{2}}{4\pi E_{0} d^{2} } \\\)
\(E_{0} = 8.854 * 10^{-12} C^{2} N^{-1} m^{-1}\) is the permittivity of free space.
Initially, we have,
\(\frac{q_{1} q_{2}}{4\pi E_{0} d^{2} } =F_{1} = 8 units\)
Now, if the charge of object 1 is multiplied by 1, the charge of object 2 is multiplied by 3, and the distance separating objects 1 and 2 is divided by 4, we have, \(q_{1} =q_{1}, q_{2} =3q_{2} , d=\frac{d}{4}\).
The new electrostatic force will be,
\(F_{2} = \frac{q_{1} 3q_{2}}{4\pi E_{0} (\frac{d}{4} )^{2} } \\\\\) units.
We have, \(F_{1} = 8 units= \frac{q_{1} q_{2}}{4\pi E_{0} d^{2} } \\\)
Hence,
\(F_{2} =\frac{8*3}{(\frac{1}{4}) ^{2} } units= 384 units.\)
Hence, the new electrostatic force will be 384 units.
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which situation would result in interference? group of answer choices a wave bouncing off an object a wave bending as it moves through an object a wave scattering as it moves through an object a wave increasing in energy as it hits another wave
Answers
Interference occurs when two or more waves meet and interact with each other. These interactions can be constructive or destructive, depending on how the waves are aligned with each other.
Constructive interference occurs when waves are aligned in phase with each other, resulting in an increase in amplitude, while destructive interference occurs when waves are aligned out of phase, resulting in a decrease in amplitude. Of the group of answer choices given, the situation that would result in interference is when a wave bounces off an object and interferes with another wave in the same space.
When the wave is reflected off an object, it produces a new wave that interacts with the original wave, resulting in interference. This can lead to constructive interference if the waves are aligned in phase, or destructive interference if they are aligned out of phase.
Interference occurs when two waves meet and interact with each other. These interactions can be either constructive or destructive, depending on the alignment of the waves with each other. When waves are aligned in phase, constructive interference occurs, resulting in an increase in amplitude. On the other hand, when waves are aligned out of phase, destructive interference occurs, resulting in a decrease in amplitude.
The situation that would result in interference is when a wave bounces off an object and interferes with another wave in the same space. This can lead to either constructive or destructive interference, depending on how the waves are aligned.
Therefore, the answer is wave bouncing off an object.
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A capacitor is made by taking two sheets of aluminum foil, each 0.022 mm thick and placing between them a sheet of paper which comes from a ream of 500 sheets, the ream being 5.5 cm thick with sheets measuring 216 mm by 279 mm. What is the capacitance of the capacitor made this way if the dielectric constant of the paper is 3.7?
THE ANSWER SHOULD BE (18nF)
Answers
The capacitance of the capacitor if the dielectric constant of the paper is 3.7 : 18 nF
Given data :
Thickness of aluminium capacitor = 0.022 mm
Number of sheets = 500
Thickness of ream = 5.5 cm = 0.055 m
measurement of sheets = 0.216 m by 0.279 m
dielectric constant ( k ) = 3.7
Determine the capacitance of the capacitorwe will apply the capacitance formula below
C = Kε₀A / d
= 3.7 * 8.85*10⁻¹² * 0.216 *0.279 / ( 0.055 / 500 )
= 1.8 * 10⁻⁸F ≈ 18nF
Hence we can conclude that The capacitance of the capacitor if the dielectric constant of the paper is 3.7 : 18 nF
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a series circuit has one 10 ohm resistor and 15 ohms of inductive reactance in a single inductor. what is the apparent power (total volt-amps) of this circuit.
Answers
The result is ,(a) Z = sqrt((10^2) + (15^2)) = 18.03 ohms.
(b) the apparent power would be S = (120 V) x (1 A) = 120 VA.
To find the apparent power (total volt-amps) of a series circuit with a 10 ohm resistor and 15 ohms of inductive reactance in a single inductor, we first need to calculate the impedance of the circuit.
Impedance is the total opposition to current flow in an AC circuit and is a combination of resistance and reactance. In this case, we can use the formula Z = sqrt(R^2 + XL^2), where R is the resistance and XL is the inductive reactance.
To find the apparent power (S) of the circuit, we use the formula S = Vrms x Irms, where Vrms is the root mean square voltage and Irms is the root mean square current. Since we are not given any values for voltage or current, we cannot find the exact value of apparent power.
However, we can make some assumptions based on typical values for household circuits. For example, if the voltage is 120 volts (typical in the US) and the current is 1 amp,
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A small asteroid is moving in a circular orbit of radius R0about the sun. This asteroid is suddenly struck by another asteroid. (We won't worry about what happens to the second asteroid, and we'll assume that the first asteroid does not acquire a high enough velocity to escape from the sun's gravity). Immediately after the collision, the speed of the original asteroid is V0, and it is moving at an angle ? relative to the radial direction, as shown in the figure. (Figure 1) Assume that the mass of the asteroid is m and that the mass of the sun is M, and use G for the universal gravitation constant. Since the asteroid does not reach escape velocity, it must remain in a bound orbit around the sun, which will be an ellipse. Take the following steps to find Ra and Rp, the aphelion and perihelion distance of the asteroid after the collision. (The aphelion is the point in the orbit farthest from the sun, and the perihelion is the point in the orbit closest to the sun.) As in most orbit problems, the most fundamental principles involved are energy and angular momentum conservation.
Part A Find a quadratic equation of the form 0=Re2+bRe+c that relates Re to the known quantities L, E, m, M, and G. In the space provided, write b, the co-efficient of Re. Express your answer in terms of one or both of the known quantities E and L, and some or all of the fixed constants M, m, and G. Construct your equation such that the coefficient of the Re2 term is 1.
Answers
The coefficient of Re is - (G M m). The quadratic equation of the form that relates Re to the known quantities L, E, m, M, and Gravitational constant (G) is (L² / (2 m)) * (1 / (Re²)) - (G M m / Re).
First, we consider energy and angular momentum conservation to form a quadratic equation.
The total mechanical energy (E) of the asteroid is given as the sum of its kinetic energy (KE) and potential energy (PE),
E = KE + PE
The kinetic energy (KE),
KE = (1/2) mv²
where v is the speed of the asteroid.
The potential energy (PE) is given by:
PE = -G M m / R
where, M and m is the mass of the Sun and asteroid, R is the separation between the asteroid and the Sun, and G is the universal gravitational constant.
From the conservation of Angular momentum,
L = m V R
To eliminate v and express E in terms of R:
KE = (1/2) mv²
KE = (1/2) (L² / (m²R²))
KE = L² / (2 m² R²)
PE = -G M m / R
E = KE + PE
E = (L² / (2 m² R²)) - (G M m / R)
To rewrite this equation as a quadratic equation of the form 0 = Re²+ bRe + c.
where, Re represents the distance R, and b is the coefficient of Re.
0 = (L² / (2 m)) * (1 / (Re²)) - (G M m / Re)
Multiplying through by 2 m² Re²
0 = (L² / (2 m)) - (G M m Re)
bY comparing the equation with the quadratic form 0 = Re^2 + bRe + c, the coefficient of Re is:
b = - (G M m)
Hence, the coefficient of Re is - (G M m).
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An elephant weighs 3700 newtons. What’s his mass rounded to the nearest kilogram? Assume that acceleration due to gravity is 9.8 N/kg.
A. 3709.8
B. 377.6
C. .0026
D. 362,600
Answers
The maximum speed around a level curve is 30. 0 km/h. What is the maximum speed around a curve with twice the radius? (assume all other factors remain unchanged. ).
Answers
The maximum speed around a level curve is 30. 0 km/h. What is the maximum speed around a curve with twice the radius is 42.4 km/h.
Meaning of the maximum speed curve:
You might travel at a maximum speed of around 1.4 times as fast on a curve with a radius of 60 meters (twice as much), according to the equation, which also states that your maximum speed is proportional to the square root of the curve's radius.
According to that,
30 km/hr is the maximum speed.
New radius equals 2 r
In all scenarios, the centripetal force will be the same.
Calculating the new top speed around a curve is necessary.
Using the centripetal force formula:
\(\frac{mv^{2} }{r} = \frac{mv^{2}}{r}\)
Fill out the formula with the value
\(\frac{v^{2} }{2r} = \frac{30^{2} }{2r}\)
\(v= 30\sqrt{2} \ Km/h\)
\(v = 42.4 Km/h\)The maximum speed around a curve is therefore 42.4 km/h.
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The electric resistance of the element in a platinum resistance thermometer at 100°C, 0°C and room temperature are 75. 000, 63. 000 and 64. 992 ohms respectively. Use these data to determine the room temperature
Answers
The room temperature is approximately 0.95°C.
Rt = Ro[1 + A(Tt - To) + B(Tt - To)2]
75,000 = Ro[1 + A(100 - To) + B(100 - To)2]
64,992 = Ro[1 + A(25 - To) + B(25 - To)2]
Dividing the two equations, we can eliminate the unknown constant Ro and obtain an expression for the ratio of A/B:
75,000 / 64,992 = [1 + A(100 - To) + B(100 - To)2] / [1 + A(25 - To) + B(25 - To)2]
Simplifying and rearranging, we get:
A/B = [1 + (100 - To)(64,992/75,000) - (25 - To)] / [(100 - To)2 - (25 - To)2(64,992/75,000)]
Using the given resistance values, we can evaluate the ratio of A/B to be approximately 0.00386.
63,000 = Ro[1 + 0.00386(0 - To) + B(0 - To)2]
Simplifying and solving for To, we get:
To ≈ 0.95°C
Resistance is a property of materials that opposes the flow of electrical current. It is a measure of the degree to which an object resists the passage of electrons through it. Resistance is caused by collisions between the electrons and the atoms that make up the material. These collisions cause the electrons to lose energy and slow down, reducing the flow of current.
The unit of resistance is the ohm (Ω), and it is defined as the ratio of voltage to current. Materials with high resistance have a low conductivity, while materials with low resistance have a high conductivity. This property is important in designing electronic circuits, where different components need to have different levels of resistance to perform specific functions. Resistors, for example, are components that are designed specifically to provide a certain level of resistance to a circuit.
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The electric potential at the origin of an xy-coordinate system is 40 v. a -8.0-μc charge is brought from x = [infinity] to that point. what is the electric potential energy of this charge at the origin?
Answers
Electric potential energy of that charge at origin = 40 V
Electric potential, the amount of work needed to move a unit charge from a reference point to a specific point against an electric field.
The electric potential energy of any given charge or system of changes is termed as the total work done by an external agent in bringing the charge or the system of charges from infinity to the present configuration without undergoing any acceleration.
Electric potential energy is defined as the total potential energy a unit charge will possess if located at any point in the outer space.
Potential energy at a point = change in electric potential to bring it from infinity to that point
Potential energy = Potential at that point - Potential at infinity
conventionally , potential at infinity is taken as zero
Potential energy = Potential at that point
hence , Potential energy of that charge at origin = Electric Potential at the origin
Potential energy of that charge at origin = 40 V
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As A Plant Grows, it gains mass Which of the following provides the most matter that a plant uses for its growth?
Answers
As a plant grows, what provides the most matter that a plant uses for its growth is carbon from the air.
The correct option is C.
What are the requirements for the growth of a plant?
The requirements for the growth of a plant are those things that a plant needs in order to grow.
In order to thrive, plants require nutrients such as carbon from air, water, light, warmth, and air. One of these criteria may prevent a plant from growing or possibly cause it to perish. For instance, a plant left in a dark environment may grow tall and spindly in search of light before deteriorating and dying.
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Complete question:
As A Plant Grows, it gains mass Which of the following provides the most matter that a plant uses for its growth?
Minerals and nutrients from the soil
Light from the sun
Carbon from the air
Which atom is involved in giving your heart energy to beat?
carbon
gold
oxygen
Iron
Answers
the _____ an object moves, the ______ it has
Answers
Answer:
1st blank is (faster)
2nd blank is (more kinetic energy it has)
Find the force of gravity acting on the following object 1.2 kg rabbit
Answers
The force of gravity which is the same as weight of the object is 11.8 N
What is Weight ?Weight can be defined as a gravitational pull on any object in space under the influence of acceleration due to gravity. The force of gravity acting on an object is also known as weight.
To find the force of gravity acting on the 1.2 Kg rabbit, let us use the formula below
W = mg
Where
Weight W = ?Mass m = 1.2 KgAcceleration due to gravity g = 9.8 m/s²Substitute all the parameters
W = 1.2 × 9.8
W = 11.76 N
Therefore, the force of gravity acting on the 1.2 kg rabbit is 11.8 N approximately.
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HELPPP RNNN PLSSSS
An airplane whose airspeed is 200 km/1 flies parallel to the direction of a wind with a speed of
90.0 km/h. What are the two possible speeds of the plane relative to the ground?
Answers
Answer:
110 km/h
Explanation:
"Headwind" means, that the velocity of the wind is opposite to the velocity of the airplane. Thus, in order to find the resultant speed, one should subtruct those velocities
Please help with this, Im a little stuck!!
Answers
Answer:
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how long ago (in seconds) was that galaxy right next door to our own galaxy if it has always been receding at its present rate? since the universe began when all galaxies were very close together, this number is a rough estimate for the age of the universe.
Answers
According to the Statement it always was receding at its current rate, that galaxy was just next to our own galaxy, moving at 8000 km/s.
Which galaxy contains Earth?Astronomy The Universe The Nebula Galaxy. Did you know that, in conjunction to our light, the Sun, the Milky Way Cluster, a large expanse of space, includes millions and billions of other stars? Its Milky Way is distinguished by a phenomenal number of stars, infinitesimal particles, and gas.
Briefing :Since V = H x d, the velocity of a galaxy at a distance of 400 x 10⁶ light-years = 8000 km/s
For H = 20 km/s per million light-years. The time required to travel
4 x 10⁸ light - years at 8000 km/s is given by :
T = (4x10⁸ light - years ) (9.46 x 10¹² km /light-year) ÷ 8 x 10³
= 4.7 x 10¹⁷ = 15 billion year
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Complete question : Consider a galaxy at a distance of 400 million light-years receding from us at a velocity, v. If the Hubble constant is 20 km/s per million light-years, what is its velocity? How long ago was that galaxy right next door to our own Galaxy if it has always been receding at its present rate?
What is heat?What are it's units?
Answers
Answer:
As a form of energy, heat has the unit joule (J). The standard unit for the rate of heat transferred is the watt (W), defined as one joule per second.
heat is a form of energy therefore the unit of heat is the same as that of energy has the CGS unit of heat is erg and its SI unit is Joule
relationship between Joule and erg is --
\(10 J = 10⁷ erg\)
other unit of heat are calories kilocolries
\(relationship \: between \: calorie \: and \: joule
1 calorie = 4 .18 \: j(or \: nearly \: 4.2 \: j \: ) \\ \\ 1 \: kilocalorie \: = 4.18 \: \times 10 \: cube \: j\)
Sunaina made an electric circuit to lit up an electric bulb. But to her astonishment the bulb did not glow. Help Sunaina to find out the various possibilities of the bulb not glowing.
Answers
Answer:
See the explanation below.
Explanation:
There are several options so that the bulb does not work in the electrical circuit, we will analyze the possible causes and explain them.
For the circuit to work it must consist of the following elements, power supply, connection wiring, and electrical bulb or lamp. These elements should work in a closed-loop, as we can see in the attached picture below.
The voltage source (battery) does not work
There is a possibility that the voltage source is discharged or does not work properly in this way the current necessary to make the bulb illuminate can not be generated.
The connection wiring is damaged
One of the most common possibilities is that at some point in the circuit, the cable is cut. In this way the current can not flow freely in the electrical circuit, without current it is not possible for the bulb to illuminate or work.
The bulb is damaged
When the bulb is damaged, the circuit is open i.e. it works as if the connection cable was open.
What should scientists do when they see that the data collection or analysis
from their experiment has limitations?
A. Describe the limitations in detail in their final report,
B. Repeat the experiment to see if it still has limitations,
C. Ignore the limitations when they draw conclusions,
D. Decide not to report any of the experimental results.
SUBMIT
Answers
Answer:
Describe the limitations in detail in their final report
Explanation:
just did test
what is the magnitude of the force needed to stretch a spring with a constant of 200 n/m so the spring stretches 10 cm? group of answer choices 2000n 2 n 200 n 20 n
Answers
The magnitude of the force needed to stretch the spring by 10 cm is 20 N.
To find the magnitude of the force needed to stretch a spring, you can use Hooke's Law, which states that the force is equal to the spring constant multiplied by the displacement. In this case, the spring constant is 200 N/m and the displacement is 10 cm (which is equal to 0.1 m).
Using the formula F = k * x, where F is the force, k is the spring constant, and x is the displacement, we can calculate the magnitude of the force:
F = 200 N/m * 0.1 m
F = 20 N
Therefore, the magnitude of the force needed to stretch the spring by 10 cm is 20 N.
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when an apple is resting on top of a table, how many force pairs (number of pairs not individual forces)act on the apple?
Answers
The draw of the earth on the apple and the pull of the apple on the earth are forces operating in pairs (number of pairs, not individual forces).
What forces are at work while something is at rest?Since there is no net force acting on the item while it is resting , the downward force (weight) must counterbalance the force acting upward (normal force). Weight travels downhill, therefore it is always negative. For an item to be at rest, all of the forces must be equal to 0.
Can an object at rest be affected by a force?According to Newton's first rule, in order to have no net force exerted on an object, it must be at rest. Because if there is a total force acting on the object, it will change velocity. It will accelerate.
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TL A torsional member must in order to apply the relationship o = Select all that apply. JG Obe made of a ductile material be homogeneous have a constant diameter Obe made of two or more materials have a constant internal torque
Answers
In order to apply the relationship o, a torsional member must be made of a ductile material, be homogeneous, and have a constant diameter.
A torsional member is subject to torsional or twisting forces. The relationship "o" represents the angle of twist or torsion in the member. To ensure this relationship holds, the following conditions must be met:
Ductile material: The torsional member should be made of a material that exhibits ductility. Ductility is the ability of a material to deform plastically without breaking. Ductile materials can withstand the twisting forces without fracturing, allowing for a reliable measurement of the angle of twist.
Homogeneity: The torsional member must be homogeneous, meaning it has uniform properties throughout its cross-section. If the member has varying material properties, such as different stiffness or strength, it can lead to uneven distribution of torsional forces and affect the accuracy of the relationship o.
Constant diameter: The torsional member should have a constant diameter along its length. This ensures that the distribution of torsional stresses remains uniform throughout the member. If the diameter varies, it can cause stress concentration points and lead to inaccurate measurements of the angle of twist.
In summary, a torsional member must be made of a ductile material to withstand the twisting forces, be homogeneous to maintain uniform properties and have a constant diameter to ensure accurate measurements of the angle of the twist.
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What's the largest number of beats per second that will be heard from which pair of tuning forks?
Answers
The largest number of beats per second that will be heard from 763 and 774 Hz pair of tuning fork .
The beat frequency is equal to the complete value of the alteration in the frequency of the two waves. The count of beats per second is equivalent to the difference in frequencies of two waves is called beat frequency.
A tuning fork is a two-pronged metal fork that can be used as an acoustic resonator. Traditionally, this tool has been used to tune musical instruments. Tuning forks work by releasing a perfect wave pattern to match a musician's instrument.
The largest number of beats per second that will be heard from 763 and 774 Hz pair of tuning fork .
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what is kinetic energy used for in our everyday lives
Answers
Explanation: Anything at home that moves is an example of kinetic energy. This could be a cue ball rolling on a billiards table, a fan circulating air on a warm day, or glass shattering on the floor after it falls from the counter. Electrical devices that are turned on use kinetic energy as do people moving about the house.
Complete the following Water enters a 200L tank at a rate of 32g/s and is withdrawn at a rate of 10g/s. The tank is initially half full. Write a mass balance for this process and solve the balance equation to determine how long it will take the tank to drain completely in minutes. The density of water conversion is 1000g/1L an Engineering Connect
Answers
It will take the time to drain completely in minutes when The density of water conversion is 1000g/1L is 75.76 minutes.
To write a mass balance for this process, we need to consider the inflow of water into the tank and the outflow of water from the tank. The mass balance equation for this process can be written as follows:
dM/dt = Q_in - Q_out
where dM/dt is the rate of change of the mass of water in the tank over time, Q_in is the inflow of water into the tank, and Q_out is the outflow of water from the tank.
In this case, the inflow of water into the tank is 32 g/s, and the outflow of water from the tank is 10 g/s. The initial mass of water in the tank is 200L * 1000 g/L = 200,000 g, and the tank is half full, so the initial mass of water in the tank is 200,000 g/2 = 100,000 g.
Substituting these values into the mass balance equation, we get:
dM/dt = 32 g/s - 10 g/s = 22 g/s
To determine how long it will take the tank to drain completely, we can solve the mass balance equation for t. The mass of water in the tank at any time t is given by:
M(t) = M(0) + dM/dt * t
where M(0) is the initial mass of water in the tank and t is the time in seconds.
Substituting the values for M(0) and dM/dt, we get:
M(t) = 100,000 g + 22 g/s * t
To drain the tank completely, the mass of water in the tank must be zero, so we can set M(t) = 0 and solve for t:
0 = 100,000 g + 22 g/s * t
t = -100,000 g / 22 g/s
t = -4545.45 s
Since there are 60 seconds in a minute, the time it will take the tank to drain completely in minutes is t/60 = -4545.45 s / 60 s/min = 75.76 minutes.
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the cutoff wavelength associated with a particular metal is 349 nm. what is the maximum kinetic energy of electrons emitted from a surface of this metal when illuminated by light of wavelength 237 nm?
Answers
The maximum kinetic energy of the electrons emitted from the surface of the metal is approximately \(3.19 * 10^{-18\)J.
The cutoff wavelength associated with a particular metal is the minimum wavelength of light that the metal can absorb. In this case, the cutoff wavelength of the metal is 349 nm.
The maximum kinetic energy of electrons emitted from a surface of the metal when illuminated by light of wavelength 237 nm depends on several factors, including the intensity of the light, the duration of the illumination, and the work function of the metal. The work function is the minimum energy required to remove an electron from the surface of the metal.
To calculate the maximum kinetic energy of the electrons, we can use the formula:
K = h - W
K = \((6.626 * 10^{-34} J s) * (237 ( 10^{-9 }m) - (4.178 * 10^{-19} J)\)
K = \(3.19 * 10^{-18\)J.
Therefore, the maximum kinetic energy of the electrons emitted from the surface of the metal is approximately \(3.19 * 10^{-18\)J.
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Indicate the range of back pressure for which the flow will (a) be subsonic everywhere in the nozzle; (b) have a shock wave inside the nozzle; (c) have oblique shock waves outside the exit; and (d) have supersonic expansion fans outside the nozzle.
Answers
The stagnation pressure, and γ is the ratio of specific heats of the gas, The pressure on the shock wave is \(P0\times[2/(\gamma+1)]^(\gamma/(\gamma-1))\), The pressure at the exit is \(P0\times2/(\gamma+1)]^{(\gamma/(\gamma -1))\) and the nozzle for supersonic expansion fans to exist outside the nozzle.
What is pressure?Pressure is a force per unit area applied in a direction perpendicular to the surface of an object. It is typically measured in units of Pascals (Pa). Pressure is a fundamental concept in physics and is integral to many natural phenomena, such as fluid flow, mechanical strength, and thermodynamics. It can be used to measure the force exerted by a gas, liquid, or solid as it interacts with its environment.
(a) The back pressure should be greater than or equal to the critical pressure for subsonic flow everywhere in the nozzle. This is given by: \(Pc = 2 \times P0 \times [(\gamma+1)/(2\times\gamma)]^{(\gamma/(\gamma-1))\), where Pc is the critical pressure, P0 is the stagnation pressure, and γ is the ratio of specific heats of the gas.
(b) The back pressure should be between the critical pressure and the pressure on the shock wave in the nozzle. The pressure on the shock wave is given by: \(Ps = P0\times 2/(\gamma+1)]^{(\gamma/(\gamma-1))\).
(c) The back pressure should be between the pressure on the shock wave and the pressure at the exit of the nozzle. The pressure at the exit is given by: \(Pe = P0\times[(\gamma-1)/(\gamma+1)]^{(\gamma/(\gamma-1))\).
(d) The back pressure should be less than the pressure at the exit of the nozzle for supersonic expansion fans to exist outside the nozzle.
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Cart 1 of mass 3.0 kg moving to the right at 2 m/s and collides with a Cart 2 of mass 2.0 kg moving to the left at
4 m/s. The two carts stick together. What is the velocity of the carts after the collision?
Answers
Answer:
V = -0.4 m/s
Explanation:
Given that,
Mass of cart 1, m₁ = 3 kg
Speed of cart 1, v₁ = 2 m/s
Mass of cart 2, m₂ = 2 kg
Speed of cart 2, v₂ = -4 m/s (left)
aWe need to find the velocity of the carts after the collision if they stick together. Let the common speed be V. Using the law of conservation of momentum to find it such that,
\(m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\)
Put all the values,
\(V=\dfrac{3\times 2+2\times (-4)}{(3+2)}\\\\=-0.4\ m/s\)
So, the velocity of the carts after the collision is equal to 0.4 m/s to the left.
Which visual impairment involves fluid buildup in the eye in which the resulting pressure can damage the optic nerve?
Answers
The visual impairment that involves fluid buildup in the eye, leading to increased pressure and potential damage to the optic nerve, is called glaucoma.
Glaucoma is a group of eye conditions characterized by elevated intraocular pressure (IOP) due to a disruption in the normal flow and drainage of fluid (aqueous humor) within the eye. The increased pressure can cause damage to the optic nerve, which is responsible for transmitting visual information from the eye to the brain. If left untreated or uncontrolled, glaucoma can progressively lead to vision loss and eventual blindness. It is often referred to as the "silent thief of sight" because the symptoms are not always apparent in the early stages. Regular eye examinations and early detection are crucial in managing glaucoma, as various treatment options, including medication, laser therapy, or surgery, can help lower the intraocular pressure and preserve vision.
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