What is the relationship between potential and kinetic energy?*
As potential energy increases, kinetic energy increases.
O As potential energy increases, kinetic energy decreases.
As potential energy decreases, kinetic energy decreases.
O Potential and kinetic energy are two separate things and have no relationship.

Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

1. The % concentration is 20.7% and the molar concentration, Cm, is 1.5 M.

2. 7.8 grams of potassium sulfate will be formed.

3. 10.7 grams of ammonium chloride will be formed.

4. The volume of hydrogen gas that will be produced is 3.86 liters.

5. 21.43 grams of the 70% acetic acid is needed to prepare 500 grams of 3% acetic acid solution.

1. Mass of potassium sulfate = 1.5 moles * (174.26 g/mol) = 261.39 g

Mass of water (H₂O) = 1000 g

% = (mass of solute/mass of solution) x 100

% = (261.39 g / (261.39 g + 1000 g)) x 100

% ≈ 20.7%

Cm = moles of solute / volume of solution

Moles of potassium sulfate (K2SO4) = 1.5 moles

Volume of water (H2O) = 1000 g / (density of water) = 1000 g / 1 g/mL = 1000 mL = 1 L

Cm = 1.5 moles / 1 L

Cm = 1.5 M

2. The balanced equation for the reaction is:

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

Molar mass of sulfuric acid (H₂SO₄) = 98.09 g/mol

Moles of sulfuric acid = 10 g / 98.09 g/mol

Moles of sulfuric acid = 0.102 mol

Based on the mole ratio of the reaction, 0.102 moles of sulfuric acid will react to form 0.102 moles of potassium sulfate.

Molar mass of potassium sulfate = 174.26 g/mol

Mass of potassium sulfate = 0.102 mol x 174.26 g/mol

Mass of potassium sulfate ≈ 17.8 g

3. The balanced equation for the reaction is:

Molar mass of hydrochloric acid (HCl) = 36.46 g/mol

Moles of hydrochloric acid (HCl) = 7.3 g / 36.46 g/mol

Moles of hydrochloric acid ≈ 0.2 mol

Based on the mole ratio of the reaction, 0.2 moles of hydrochloric acid will react to form 0.2 moles of ammonium chloride.

Molar mass of ammonium chloride (NH₄Cl) = 53.49 g/mol

Mass of ammonium chloride = 0.2 mol x 53.49 g/mol

Mass of ammonium chloride ≈ 10.7 g

4. The balanced equation for the reaction is:

Molar mass of zinc (Zn) = 65.38 g/mol

Moles of zinc = 13 g / 65.38 g/mol

Moles of zinc ≈ 0.199 mol

Based on the mole ratio of the reaction, 0.199 moles of zinc will react to produce 0.199 moles of hydrogen gas.

Volume of sulfuric acid = 30 g / (density of H₂SO₄ )

The density of H₂SO₄ is 1.84 g/mL

Volume of sulfuric acid  = 30 g / 1.84 g/mL

Volume of sulfuric acid ≈ 16.3 mL or 0.0163 L

Using the ideal gas law, the volume of hydrogen gas produced will be:

V = nRT / P

V = (0.199 mol)(0.0821 L·atm/(mol·K))(273 K) / (1 atm)

V ≈ 3.86 L

5. Assuming that the concentrated original solution of acetic acid is 100% acetic acid (CH₃COOH).

Mass of acetic acid = 500 g x (3/100) = 15 g

The concentrated original solution, however, is 70% acetic acid.

70% acetic acid (mass) = 100% acetic acid (unknown mass)

0.7 * (unknown mass) = 15 g

Solving for the unknown mass:

unknown mass = 15 g / 0.7

unknown mass ≈ 21.43 g

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Answer:

i.e. mass of 1 mole of glucose, C6H12O6 = (6 × 12.01 + 12 × 1.01 + 6 × 16.00) g = 180.18 g (using atomic weight data to 2 decimals) 1 mole of carbon atoms weighs 12.01 g and there are 6 moles of C atoms in 1 mole of glucose, so the mass of carbon in 1 mole of glucose = 6 × 12.01 g = 72.06 g.

Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.

Thus, It is a colourless, poisonous irritant and sensitizer in its anhydrous form, which harms the central nervous system and causes symptoms as severe as tumours and convulsions.

In addition to having a strong reducing agent that makes it highly explosive, hydrazine has a strong smell that is similar to that of ammonia.

Given this, it appears odd that over 100,000 metric tonnes of the substance are produced annually throughout the world. But hydrazine does have an impact on our daily activities. It can save our lives, give us food and clothing, keep us warm, and even transport us to the moon. It even has the ability to go back in time.

Thus, Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.

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4 cups

33oz

2.1 liquid pints

1 quart

.26 gallon

Answer:

4 cups, 1000 mililiters

Explanation:

The area of human activity that consumes the most energy is building construction and operation. Option B.

Humans impact the physical environment in many ways including overpopulation pollution burning fossil fuels and deforestation. Such changes are causing climate change soil erosion declining air quality and undrinkable water. Human geography includes the study of all human activities and their effects on the natural environment.

The impact of early human societies on the natural environment was minimal due to the presence of a small number of nomads, mainly through hunting, fishing, and gathering. The human activity system is a fictitious system that represents goal-oriented human activity. These systems are fictitious in the sense that they are intelligent constructs and do not describe actual real-world activities.

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Given what we know, we can confirm that if while setting up a beaker you notice that the stirring is erratic and unstable, you should immediately turn off the stirring mechanism.

Therefore, we can confirm that in order to ensure the safety of all participants, if while setting up a beaker you notice that the stirring is erratic and unstable, you should immediately turn off the stirring mechanism.

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It’s a or b i think it’s b

when pressure of the reactant mixture at the equilibrium and with the fewer moles in reactant side will be increased and the equilibrium will be shift to the side in the reaction where the fewer moles of the gas.

According to the Le Chartelier, when the reaction is in the equilibrium phase and the one of the constraints which will affect the rate of the reactions, and the equilibrium will be shift to the cancel out  this effect that the constraint had.

Therefore, If the pressure of the system or the reaction is in the equilibrium is change, the equilibrium of the reaction will be change that is depending on the side of the reaction with the highest number of the molecules.

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Answer:

Explanation:

Therefore, the pH of the HCl solution is 5.

Answer:

suthu naaye mairu poda

The pH at the equivalence point in the titration of 50.0 ml of 0.300 M CH₃COOH with 0.3 M NaOH is 8.61.

At the equivalence point in the titration of CH₃COOH with NaOH, the pH is determined by the hydrolysis of the salt formed, which is CH3COO⁻ and Na+.

The equation for the hydrolysis reaction is:

CH3COO⁻ + H2O ⇌ CH3COOH + OH⁻
We can use the Ka value for CH₃COOH to find the Kb value for CH3COO⁻ using the equation:

Kw = Ka x Kb

Where Kw is the ion product constant for water (1.0 x 10⁻¹⁴).
Kb = Kw/Ka

= (1.0 x 10⁻¹⁴)/(1.8 x 10⁻⁵)

= 5.56 x 10⁻¹⁰
Now we can use the Kb value to find the concentration of OH⁻ at the equivalence point using the equation:

Kb = ([OH⁻][CH3COOH])/[CH3COO⁻].

Since the concentrations of CH3COOH and CH3COO⁻ are equal at the equivalence point, we can simplify the equation to Kb = ([OH⁻]²)/[CH₃COO⁻].
Hence,
[OH-] = \(\sqrt{Kb(CH3COO-)}\)

=\(\sqrt{5.56(10^{-10})(0.3) }\)

= 4.06 x 10⁻⁶ M
Use the concentration of OH⁻ to find the pH at the equivalence point using the equation pOH = -log[OH-] and the relationship pH + pOH = 14.
pOH = -log(4.06 x 10⁻⁶)

= 5.39
pH = 14 - 5.39

= 8.61
Therefore, the pH at the equivalence point in the titration of 50.0 ml of 0.300 M CH3COOH with 0.3 M NaOH is 8.61.

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D. only the surface material reacts, so having the entire material be made of the catalyst is not necessary.

Increasing the surface area of a catalyst increases the frequency of collisions and increases the reaction rate.

Several smaller particles have more surface area than one large particle. The more surface area that is available for particles to collide, the faster the reaction will occur.

Thus, it is important way of utilizing the catalyst because only the surface material reacts, so having the entire material be made of the catalyst is not necessary.

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Answer:

c. chemical and physical

Answer:

C

Explanation:

Mechanical weathering, also called physical weathering and disaggregation, causes rocks to crumble. Water, in either liquid or solid form, is often a key agent of mechanical weathering. For instance, liquid water can seep into cracks and crevices in rock. ... It slowly widens the cracks and splits the rock

Yes, s = u+v/2+t, where s is the displacement, u is the beginning velocity, v is the end velocity, and t is the time required, is the equation of motion for a body travelling with uniform acceleration.

The basic law of motion, which states that a body's rate of change in displacement is directly proportional to its velocity, provides the basis for this equation. The equation of motion for a body travelling with constant acceleration, s = ut + 1/2at2, may be used to derive it.

The equation of motion for a body travelling with uniform acceleration is given by replacing the value of an as (v-u)/t and getting s = u+v/2+t. This formula is only accurate when the body's acceleration is constant and uniform.

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9.00 moles of Z will be produced from 3.60 mol of A, assuming excess B.

What is Stoichiometric Coefficient?

Stoichiometric coefficient refers to the number that appears in front of a chemical formula in a balanced chemical equation, indicating the relative amount of that substance that is involved in the reaction. The coefficients are used to ensure that the law of conservation of mass is satisfied in a chemical reaction.

For example, in the balanced equation:

2H2 + O2 ⟶ 2H2O

The stoichiometric coefficient of H2 is 2, which means that 2 molecules of H2 are needed to react with 1 molecule of O2 to produce 2 molecules of H2O. The stoichiometric coefficient of O2 is 1, which means that 1 molecule of O2 is needed to react with 2 molecules of H2 to produce 2 molecules of H2O.

According to the balanced chemical equation:

2A + 3B ⟶ 4Y + 5Z

The stoichiometric coefficient of Z is 5, which means that for every 2 moles of A that react, 5 moles of Z are produced. Therefore, we can use a proportion to calculate the number of moles of Z produced from 3.60 mol of A:

2 mol A : 5 mol Z = 3.60 mol A : x mol Z

x = (5 mol Z x 3.60 mol A) / 2 mol A

x = 9.00 mol Z

Therefore, 9.00 moles of Z will be produced from 3.60 mol of A, assuming excess B.

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Answer: for question 4, the answer would most likely be movement of air, water and rock

Explanation:

Answer:

Explanation:

It is really blurry i cant really see the pic

In the following experiment, a coffee-cup calorimeter containing 100 mL of \(H_{ 2} O\) is used. The initial temperature of the calorimeter is 23.0 ∘C. If 6.60 g of \(CaCl_{2}\) is added to the calorimeter, Final temperature of the solution in the calorimeter = 11.

The first step in solving this problem is to calculate the number of moles of \(CaCl_{2}\\\) added to the calorimeter.

Moles of \(CaCl_{2}\) = mass of \(CaCl_{2}\) / molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 6.60 g / 110.98 g/mol (molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 0.0594 mol

We can use the equation for heat transfer to find the change in temperature of the solution. q = mCsΔT, where q is the heat transferred, m is the mass of the solution, Cs is the specific heat of the solution, and ΔT is the change in temperature.

We know that the initial temperature of the calorimeter is 23.0 ∘C and the mass of the solution is 100 g (since the density of water is 1 g/mL). We can solve for ΔT: ΔT = q / mCs

To find q, we can use the enthalpy change of solution (ΔHsoln) and the number of moles of\(CaCl_{2}\)added: q = ΔHsoln x moles of\(CaCl_{2}\)

q = -82.8 kJ/mol x 0.0594 mol

q = -4.92 kJ

Now we can solve for ΔT: ΔT = (-4.92 kJ) / (100 g x 4.184 J/g⋅∘C)

ΔT = -11.8 ∘C

We can find the final temperature of the solution by adding the change in temperature to the initial temperature: Final temperature = 23.0 ∘C - 11.8 ∘C =11 ∘C.

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If 60 grams of the substance are added to 100 g of water, the solution can be categorized as supersaturated.

The graph shows the number of grams that can be dissolved in 100 grams of water at different temperatures. In general, solubility increases with temperature.

According to the graph, at a temperature of 30°C, it is possible to dissolve a total of 48 to 49 grams of \(KNO_{3}\). This information implies that if we add 60 grams at this temperature not all the substance would be dissolved, and therefore the solution would be supersaturated.

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Answer:

A satellite campus or branch campus or regional campus is a campus of a university or college that is physically at a distance from the original university or college area. This branch campus may be located in a different city, state, or country, and is often smaller than the main campus of an institution.

Answer:I suppose it is mercury...

Explanation:

I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thnk me...

Explanation:

It happens because particles of gas are in constant random motion. Thus they can collide with the walls of the container causing pressure on the walls.

The empirical formula of the compound is C₂H₁₆S₂N₃O.

The moles of each element is as follows::

For CO₂:

Carbon (C) has a molar mass of 12.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of C in CO₂ = 2.08 g / 12.01 g/mol = 0.173 moles

Moles of O in CO₂ = 2.08 g / 16.00 g/mol = 0.130 moles

For H₂O:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in H₂O = 1.28 g / 1.01 g/mol = 1.27 moles

Moles of O in H₂O = 1.28 g / 16.00 g/mol = 0.080 moles

For SO₃:

Sulfur (S) has a molar mass of 32.06 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of S in SO₃ = 4.77 g / 32.06 g/mol = 0.149 moles

Moles of O in SO₃ = 4.77 g / 16.00 g/mol = 0.298 moles

For HNO₃:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Nitrogen (N) has a molar mass of 14.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in HNO₃ = 3.48 g / 1.01 g/mol = 3.45 moles

Moles of N in HNO₃ = 3.48 g / 14.01 g/mol = 0.248 moles

Moles of O in HNO₃ = 3.48 g / 16.00 g/mol = 0.217 moles

The simplest whole-number ratio of the elements will be:

Carbon: 0.173 moles / 0.080 moles ≈ 2.16

Hydrogen: 1.27 moles / 0.080 moles ≈ 15.88

Sulfur: 0.149 moles / 0.080 moles ≈ 1.86

Nitrogen: 0.248 moles / 0.080 moles ≈ 3.10

Oxygen: 0.080 moles / 0.080 moles = 1

Therefore, the empirical formula is C₂H₁₆S₂N₃O.

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Answer:

See detailed explanation.

Explanation:

Hello!

In this case, for the described chemical reaction, we can proceed as follows:

A) For the complete chemical reaction we note down every reacted and produced species as well as the proper balancing process:

\(2NaBr(aq)+Cl_2(aq)\rightarrow 2NaCl(aq)+Br_2(g)\)

In which gaseous bromine may give off.

B) The dissociated ionic equation requires the ionization of the aqueous species in ions, expect for chlorine which is not ionized:

\(2Na^+(aq)+2Br^-(aq)+Cl_2(aq)\rightarrow 2Na^+(aq)+2Cl^-(aq)+Br_2(g)\)

C) For the net ionic equation we cancel out the sodium ions as they are at both reactants and products:

\(2Br^-(aq)+Cl_2(aq)\rightarrow +2Cl^-(aq)+Br_2(g)\)

D) Based on C) we infer that the spectator ions here are the sodium ions.

Best regards!

There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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