What is the relationship between heat, temperature, thermal
energy within a system?

Answer:

2 moles!

Explanation:

Hi i hope this helped! I researched it and 2 moles was what came up first.

Answer:

53.5gram.

Explanation

Explanation: number of moles = number of molecule ÷ avogadro's number. => moles = 6.022 × 10²³ ÷ 6.022 × 10²³ = 1 mole. mass of 1 mole of NH4Cl = 1 × molar mass.

The beakers that we can see that electrolysis is going on are in beakers B and C

Electrolysis is a process in which an electric current is passed through a substance to produce a chemical reaction. The substance being electrolyzed is usually an electrolyte, which is a liquid or solution that contains ions.

The electric current causes the ions in the electrolyte to move towards the electrodes (conducting surfaces) where they either gain or lose electrons, depending on the nature of the electrode and the ions. This causes chemical reactions to occur at the electrodes, leading to the formation of new substances.

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Answer:

combining 2 grams of copper and 4 grams of sulfur to make 6 grams of copper sulfate

Explanation:

The Law of Conservation of Mass states that matter cannot be created or destroyed in chemical reactions. It posits that the mass of a substance remains unchanged after undergoing a chemical process.

Therefore, according to the question, the procedure that best demonstrates the law of conservation of mass after the chemistry student conducted different procedures is option D.

This is because, the mass of copper and sulfate did not change but merely combined to form a compound.

7.54 *\(10^8\) meters is  75.4 nanometers.

To convert 7.54 *  \(10^8\) meters to nanometers, you can multiply the value by \(10^9\)

as,  \(10^9\)nanometers = 1  meter.

7.54 * \(10^8\) m * \(10^9\) =  7.54 x \(10^1\) nm

Therefore, 7.54 *\(10^8\) meters is equal to 75.4 nanometers.

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To convert 7.54 x 10^-8 meters to nanometers, you multiply 7.54 x 10^-8 by 1 x 10^9 to get 75.4 nanometers.

To convert meters to nanometers, you need to know that 1 meter is equivalent to 1 x 109 nanometers. Therefore, if you were to convert 7.54 x 10-8 m to nanometers, you would multiply 7.54 x 10-8 by 1 x 109.

Here's how you'd do it: 7.54 x 10-8 m * 1 x 109 nm/m = 75.4 nm. So, 7.54 x 10-8 meters is equivalent to 75.4 nanometers.

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If you have 2.60 x 10²³ molecules of (NH₄)₃PO₄, you have 64.7 grams of it.

The number of particles contained in a sample is measured in terms of the mole. One mole of a compound is the quantity of that substance that has a mass in grams equal to its relative atomic or molecular mass (atomic weight).To find the number of moles of (NH₄)₃PO₄, we'll need to use the Avogadro constant, which is 6.02 x 10²³. We can use the formula:moles = particles ÷ Avogadro constantThe number of particles is given as 2.60 x 10²³. Substituting the values:moles = 2.60 x 10²³ ÷ 6.02 x 10²³moles = 0.432Molar massNow that we have the number of moles of (NH₄)₃PO₄, we can compute its mass. The molecular mass of (NH₄)₃PO₄ is 149.0 g/mol. We can use the formula:mass = moles x molecular mass Substituting the values:mass = 0.432 x 149.0mass = 64.7 grams

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Answer:

The study of the inorganic world

Explanation:

That is, it does not study living things. (Those are studied in biological, or life, science.) The four main branches of physical science are astronomy, physics, chemistry, and the Earth sciences, which include meteorology and geology.

Answer:

physics is matter and energy. it explores mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms.

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

The answer is option A.

I hope this helps you.

Answer:

Macro Algae

Explanation:

probz

Answer

Formulas: Ag₂O (silver oxide), oxygen (O₂ ), and elemental silver (Ag)

Equation with labeled phases

Procedure

Silver oxide can be produced by allowing silver to react with oxygen at temperatures lower than its decomposition point (195 °C).

The chemical formula for silver oxide (product) is

Ag₂O

Where the reactants are molecular oxygen (O₂ )and elemental silver (Ag).

The chemical equation with labels will be

The final balanced equation is

where you will find 4 silver atoms and 2 oxygen atoms in both reagents and products sides of the chemical equation.

Answer:

Explanation:

16.540 + 9.32 by rounding each number to the nearest tenth

so 16.540 the number in the tenth place is 5, if its 5 then you have to round up because 1-4 you need to round down, and 5-9 you would have to round up. if you round 16.540 to the nearest tenth would be 17.

Next, if 9.32 the number in the tenth place is 3, since is 5 below you would have to round down which rounds down to 9

So its 17+9 which your answer would be 26.

Answer:

Hydrogen H

Transition metals & non metals

Explanation:

Transition metals : think rust & copper turning green

non metals : think water H2O

Transition metals are in the "d-block", of the periodic table. ex like iron (Fe), copper (Cu), silver (Ag), & gold (Au)

chatgpt

There are approximately 6.13 grams of O2 in the 14.0 L balloon at 0.25 atm and 73⁰C.

First we can use the Ideal Gas Law equation:

PV = nRT

Where

First, we need to convert the temperature from Celsius to Kelvin:

T = 73⁰C + 273.15 = 346.15 K

Next, we can solve for the number of moles:

n = (PV) / (RT)

n = (0.25 atm × 14.0 L) / (0.0821 L·atm/mol·K × 346.15 K)

n = 0.1915 mol

Finally, we can calculate the mass of O2 using the molar mass of O2, which is 32.00 g/mol:

mass = n × molar mass

mass = 0.1915 mol × 32.00 g/mol

mass = 6.13 g

Therefore, there are approximately 6.13 grams of O2 in the 14.0 L balloon at 0.25 atm and 73⁰C.

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The mass of the NO that can be produced is given as 210 g from the calculation.

When we talk about a thermochemical reaction, we are talking about the kind of reaction that we have to write the reactants and the products in the same line as we have to write the heat of reaction.

In this case, we have the reaction that is taking place and it has to occur between nitrogen and oxygen. The product of the reaction in this case is given as NO. We can see that the equation as it is written is an example of a thermochemical reaction.

If 2 moles of NO is produced when 180.6 kJ of energy is used

x moles of NO is produced when 634 kJ of energy is used

x = 2 * 634/ 180.6

x = 7 moles

If the molar mass of NO is 30 g/mol

The mass of NO = 7 mol * 30 g/mol

= 210 g

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Answer:

holaholaholaholaholaholaholahola

The volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C is 0.126 liters, rounded to three significant figures.

To calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C, we can use the ideal gas law equation:

PV = nRT

where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:

T = 50°C + 273.15 = 323.15 K

Next, we rearrange the ideal gas law equation to solve for volume:

V = (nRT) / P

To find the number of moles (n), we can use the answer from question 27, which is the mass of oxygen gas:

m = 32 g

Using the molar mass of oxygen (O₂) which is approximately 32 g/mol, we can calculate the number of moles:

n = m / M = 32 g / 32 g/mol = 1 mol

Now we have all the values needed to calculate the volume:

V = (1 mol * 8.314 J/(mol*K) * 323.15 K) / 210,000 Pa

Using the ideal gas constant (R) of 8.314 J/(mol*K) and the pressure of 210 kPa (which is equivalent to 210,000 Pa), we can substitute these values into the equation and solve for volume.

V = 0.126 liters.

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i believe its B

Explanation:

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

Answer:

An alloy is a mixture of two or more metals which is produced with a specific proportion between metals. So, if the proportion is changed the physical characteristic would be changed as well. For example, brass musical instruments are made of brass which is a mixture (an alloy) of zinc and copper in a specific proportion. If you change a proportion, you will change the physical characteristic of brass musical instruments, and a sound they produce will be different.

Explanation:

Answer:

Explanation:

The percentage error of a certain measurement can be found by using the formula

\(P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ \)

From the question

actual density = 19.30g/L

error = 20.9 - 19.3 = 1.6

We have

\(p(\%) = \frac{1.6}{19.3} \times 100 \\ = 8.290155440...\)

We have the final answer as

Hope this helps you

Answer:

Copper (i) iodide

Cu is copper and I is iodine

Answer: C. investigations are usually wrong

Explanation: Because investigation are usually wrong and then that leads to more  and more questions

Answer:

Sunlight

Explanation:

A producer include green plants, small shrubs, fruit, phytoplankton, and algae. None are which are "sunlight".

a. The rate law for this reaction is: Rate = k[Cl] [H₂]. This means that the rate of the reaction is directly proportional to the concentrations of both Cl and H₂ molecules.

Rate law is an equation that describes the rate of a chemical reaction as a function of the concentrations of reactants. The rate law allows us to describe how the rate of a reaction changes when the concentrations of reactants are changed. It is derived from the rate equation, which is a mathematical expression that can be used to calculate the rate of a reaction from the concentrations of the reactants and the rate constant.

b. The rate law for this reaction is: Rate = k[O] [Os]. This means that the rate of the reaction is directly proportional to the concentrations of both O and Os molecules.
c. The rate law for this reaction is: Rate = k[NO₂]₂. This means that the rate of the reaction is directly proportional to the square of the concentration of NO₂ molecules.

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Complete Question:

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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ANSWER

Acidic

EXPLANATION

Ammonium chloride is an acidic salt prepared the combination of a strong acid and a weak base

The strong acid is the hydrochloric acid and the weak base is the ammonium hydroxide.

Below is the reaction between hydrochloric acid and ammonium hydroxide

Therefore, the pH of NH4Cl in solution is acidic.

No, 48 ounces are not enough. For making a small robot we need 64 ounces which is equal to 4 pounds.

Pound is a unit for measuring weight. 16 ounces makes one pound.

Ounce is also a unit for measuring weight. 16 ounces is equal to 1 pound

So, for making one small robot we need 4 pounds.

1 pound = 16 ounces

4 pounds = 64 ounces

But, we have 48 ounces

We need more = 64 - 48 = 16 ounces or 1 pound

No, 48 ounces are not enough. For making a small robot we need 64 ounces which is equal to 4 pounds.

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Answer:

1.) 0.619 M

2.) 6.34 L

3.) 12.7 moles

Explanation:

Part 1: To find the molarity, you first need to convert grams to moles using the molar mass.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

143 grams NaCl               1 mole
-------------------------  x  ------------------------  =  2.45 moles NaCl
                                    58.443 grams

Molarity = moles / volume (L)

Molarity = 2.45 moles / 3.95 L

Molarity = 0.619

Part 2: To find the volume, you need to use the given moles and the previously calculated molarity.

Molarity = moles / volume (L)

0.619 M = 3.93 moles / volume

(0.619 M) x volume = 3.93 moles

volume = 6.34

Part 3: To find the moles, you need to use the given volume and the previously calculated molarity.

Molarity = moles / volume (L)

0.619 M = moles / 20.55 L

12.7 = moles

This problem is asking for the consumption of silver ions when silver nitrate is reacted with copper. In such a case, since no masses are given, we can use the following from similar problems:

Mass of empty beaker: 110.000 g

Mass of beaker with silver nitrate (after all additions) and copper: 331.634 g.

Mass of beaker with silver: 113.395 g.

This means we can write the following chemical equation:

\(Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag\)

And thus calculate the mass of silver nitrate that will produce the following mass of silver:

\(m_{Ag}^{produced}=113.395g-110.000g=3.395g\)

Next, we use the 2:2 mole ratio of silver to silver nitrate (silver ions source):

\(3.395gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg} *\frac{169.87gAgNO_3}{1molAgNO_3} = 5.35gAgNO_3\)

The step will be defined for the given mass of available silver nitrate which will be compared to 5.35 g (consumed mass) to see if they are the same (all consumed) or different (partial consumption).

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where ur question at???

Empirical formula of Carbon dioxide :