What is the quotient of -32/8?

According to the question we have  approximately 99.74 percent of customers are willing to pay between $1.20 and $1.80 for a pint of frozen yogurt.

To answer this question, we will use the normal distribution formula and z-score.

First, we need to find the z-score for the lower limit of $1.20:

z = (1.20 - 1.50) / 0.10 = -3

Next, we need to find the z-score for the upper limit of $1.80:

z = (1.80 - 1.50) / 0.10 = 3

Now, we can use a z-table to find the area under the curve between these two z-scores.

The area to the left of z = -3 is 0.0013, and the area to the left of z = 3 is 0.9987.

To find the area between these two z-scores, we subtract the area to the left of z = -3 from the area to the left of z = 3:

0.9987 - 0.0013 = 0.9974

Therefore, approximately 99.74% of customers are willing to pay between $1.20 and $1.80 for a pint of frozen yogurt.

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Step-by-step explanation:

an arithmetic series is a series of terms, where every term is built by using the previous term and adding or subtracting something specific.

this one is really simple :

the odd integers greater than 5 means we start with 7.

and we get the next odd integer by simply adding 2.

a1 = 7

a2 = a1 + 2 = 9

=>

an = an-1 + 2 = a1 + (n-1)×2

so, how many terms ?

99 is the last one.

an = 99 = a1 + (n-1)×2 = 7 + (n-1)×2

we need to solve for n

99 = 7 + (n-1)×2

92 = (n-1)×2

46 = n-1

n = 47

therefore, the series has 47 terms or elements.

the sum of all of them ?

the old trick :

99 + 7 = 106

97 + 9 = 106

95 + 11 = 106

...

so, we have 46/2 = 23 such pairs.

so, we get 23×106.

but is this enough ?

since we have 47 elements, there is one element left to be added.

which one ?

when we build these pairs we reduce the left side by 2 22 times (as we have 23 pairs, and the first one is the starting point). and we add to the right side 2 22 times. so + and - 44 on either side.

that gives us

99-44 = 55

7+44 = 51

therefore, the one missing element is the one in the middle : 53.

so, the whole sum is

23×106 + 53 = 2438 + 53 = 2491

The minimum number of hard disks that can be used for implementing a RAID 10 solution is four (option c).  

The minimum number of hard disks that can be used for implementing a RAID 10 solution on the video editor's desktop workstation is four (option c). RAID 10, also known as RAID 1+0, combines elements of RAID 1 (mirroring) and RAID 0 (striping) to provide both data redundancy and improved performance.

In RAID 10, data is mirrored across multiple drives to ensure redundancy. To implement RAID 10, we need at least two sets of mirrored drives, where each set contains a minimum of two hard disks.

The data is striped across these mirrored sets to enhance performance.

With four hard disks, you can create two mirrored sets, each consisting of two drives.

The data is then striped across these mirrored sets, providing both redundancy and improved read/write speeds.

If one drive fails in each mirrored set, the system can still function without data loss due to the mirroring.

This setup provides a balance between data protection and performance.

While more hard disks can be used in RAID 10 for larger capacities and better performance, the minimum requirement is four hard disks.

Using fewer drives would not allow for the necessary mirrored sets and striping required for RAID 10.

By implementing a RAID 10 solution with four hard disks on the video editor's workstation, you can help safeguard against data loss in case of drive failure, ensuring the integrity and availability of important video editing data.  

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The first expression has a GCF of 2.

The second has a GCF of x

The last one has a GCF of 3.

The answer would be 9x^2-16.

(Side note: This does have a GCF of 1, but that's just not a useful GCF.)

The polynomial \(9x^{2} -16\) has no Greatest Common Factor.

Here,

The function are;

The first polynomial is;

⇒ \(2x^{2} +8x+4\)

The second polynomial is;

\(9x^{4} +2x^{2} +7x\)

The third polynomial is;

\(9x^{2} -16\)

The fourth polynomial is;

\(3x^{2} -12\)

We have to find which function has no any GCD.

What is Greatest Common Factor?

The highest number that divides exactly into two or more numbers is called Greatest Common Factor.

Now,

The first polynomial is;

⇒ \(2x^{2} +8x+4\)

Take common 2 as;

\(2 (x^{2} +4x+2)\)

Hence, This has Greatest Common Factor which is 2.

The second polynomial is;

\(9x^{4} +2x^{2} +7x\)

Take x as common;

\(x (9x^{3} +2x+7)\)

Hence, This has Greatest Common Factor which is x.

The third polynomial is;

\(9x^{2} -16\)

Clearly, There is no any common factor.

Hence, There is no any Greatest Common Factor.

The fourth polynomial is;

\(3x^{2} -12\)

Take 3 as common;

\(3(x^{2} -4)\)

Hence, This has Greatest Common Factor which is 3.

Therefore, The polynomial \(9x^{2} -16\) has no Greatest Common Factor.

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Answer:

g + 2/3 \(\geq\) -6

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

A.) This system has no solutions.

Step-by-step explanation:

y = 1/2x + 4

-1/2x + y = -5

-1/2x + (1/2x + 4) = -5

4 = -5

The system has no solutions, if we graph it, we get that it has the same slope with two different y-intercepts, these two are parallel. These two points will never meet at a point.

Answer:

use the relationship between coefficients of a pair of linear equations for no solutions i.e. a1/a2 equal to b1/b2 not equal to c1/c2 .

Here, a is coefficient of x and b is coefficient of y and c is constant term in both equation but make sure that you put the values of a1,a2,b1,b2,c1 and c2 after converting both equation in the form ax+by+c=0 with proper sign and here y=1/2(x) +4 is equation 1 and other is equation 2

The rating scale used by the restaurant is an example of an ordered categorical scale (c)

An ordered categorical scale is a type of categorical scale where the categories have a specific order or ranking. In this case, the categories "excellent," "very good," "good," and "poor" have a clear order from highest to lowest, indicating the level of customer satisfaction.

A binary/dummy scale, on the other hand, only has two categories, such as "yes" or "no."

An unordered categorical scale does not have a specific order or ranking, such as gender (male or female) or hair color (brown, black, blond, etc.).

A continuous scale, such as height or weight, has an infinite number of possible values and can be measured to any degree of precision.

So, the restaurant's questionnaire uses an ordered categorical scale to measure customer satisfaction.

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The Average Variable Cost (AVC) Formula is a fundamental concept in economics and business management. It is used to calculate the average cost of producing one unit of a good or service, taking into account only the variable costs of production.

Variable costs are those costs that change with the level of production, such as raw materials and labor. Fixed costs, on the other hand, do not change with the level of production and include expenses such as rent and equipment.

The AVC formula is calculated by dividing the total variable costs of production by the number of units produced. This gives the average cost of producing each unit of the good or service, taking into account only the variable costs.

The value of the AVC formula lies in its ability to help managers and business owners understand the cost structure of their operations. By calculating the average variable cost, they can determine the minimum price they need to charge for their product or service in order to cover their costs and make a profit.

In addition, the AVC formula can be used to compare the efficiency of different production methods. By calculating the AVC for each method, managers can determine which method is the most cost-effective, taking into account only the variable costs.

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The null and the alternative hypothesis for the test are given as follows:

To identify each hypothesis, first the claim needs to be identified, which is given as follows:

The mean delivery time is more than 35 minutes.

(your claim).

At the null hypothesis, it is supposed that there is not enough evidence to conclude that the claim is true, that is, there is not enough evidence to conclude that the mean mean delivery time is more than 35 minutes, hence:

\(H_0: \mu \leq 35\)

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the claim is true, that is, there is enough evidence to conclude that the mean mean delivery time is more than 35 minutes, hence:

\(H_1: \mu > 35\)

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The given statement can be formulated as follows: A batch of 150 iPads is inspected by choosing a sample of four iPads. Eight of the 150 iPads do not conform to specifications.

How many samples of four contain exactly one non-conforming iPad?

Let's solve the given problem step by step.

Step 1: We have 8 non-conforming iPads and 142 conforming iPads in the batch of 150 iPads. We need to find the number of ways to choose 4 iPads that include exactly one non-conforming iPad.

Step 2: We choose one non-conforming iPad in 8 ways and choose 3 conforming iPads in 142C3 ways, where nCk is the number of ways to choose k objects from n distinct objects without regard to order.

Thus the total number of ways to choose 4 iPads with exactly one non-conforming iPad is given by:

=8 × 142C3

\(8 \times \frac{142 \times 141 \times 140}{3 \times 2 \times 1}\)

= 2,107,280

Therefore, there are 2,107,280 samples of four that contain exactly one non-conforming iPad.

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Step-by-step explanation:

Tranversal-(two parallel angles are cut by a third)

Answer:

i is probably 1.

Step-by-step explanation:

1^3 is equal to 1

1^47 is equal to 1

Answer:

A) .071

B).884

Step-by-step explanation:

A) 7.1 x 10/\-2

This is scientific notation, since this is to the -2 power all you have to do is move the decimal point 2 places to the left, thus making the number smaller -> 7.1->.71->.071

B) (6.8 x 10/\2) x (1.3 x 10/\-3)

Again, Scientific notation

6.8->68->680

1.3->.13->.013->.0013

then multiply

680 x .0013 = .884

Answer:

ok but wheres the question? The image wont load

Step-by-step explanation:

Answer:

the answer is down below

Step-by-step explanation:

We need to use about 10 terms to estimate the value of the series with an error at most 0.000017.

To estimate the value of the convergent series 9 + 15 + ... with an error at most 0.000017, we need to use the formula for the error bound of a convergent series:

|En| ≤ (Mn+1/2) * r^n

where En is the error bound, Mn is the maximum value of the remainder term for the first n terms of the series, r is the common ratio, and n is the number of terms used to estimate the series.

In this case, the series has a common ratio of 5/3 (since each term is 5/3 times the previous term), and the remainder term for the first n terms is:

Rn = (5/3)^n * 9/(3n+3)

To find Mn, we need to find the maximum value of Rn for n terms. This can be done by taking the derivative of Rn with respect to n, setting it equal to zero, and solving for n. However, since we only need an estimate of the number of terms, we can use trial and error to find the smallest n such that Rn ≤ 0.000017:

n = 10: R10 ≈ 0.000013
n = 11: R11 ≈ 0.000021


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The probability of randomly selecting two animals and both of them being Labrador Retrievers is approximately 0.2647.

To calculate the probability of choosing two Labrador Retrievers out of all the animals, we need to determine the total number of possible pairs of animals and the number of pairs that consist of two Labrador Retrievers.

The total number of animals in the shelter is 3 Siamese cats + 3 German Shepherds + 9 Labrador Retrievers + 2 mixed-breed dogs = 17 animals.

To calculate the number of ways to choose 2 animals out of 17, we use the combination formula:

\(C(n, k) = n! / (k! * (n-k)!)\)

where n is the total number of animals (17) and k is the number of animals we want to choose (2).

C(17, 2) = 17! / (2! * (17-2)!)

         = 17! / (2! * 15!)

         = (17 * 16) / (2 * 1)

         = 136.

So, there are 136 possible pairs of animals.

Now, let's determine the number of pairs that consist of two Labrador Retrievers. We have 9 Labrador Retrievers in total, so we need to choose 2 out of the 9.

C(9, 2) = 9! / (2! * (9-2)!)

        = 9! / (2! * 7!)

        = (9 * 8) / (2 * 1)

        = 36.

Therefore, there are 36 pairs of Labrador Retrievers.

The probability of choosing two Labrador Retrievers out of all the animals is given by:

P(both labs) = (number of pairs of Labrador Retrievers) / (total number of pairs of animals)

            = 36 / 136

            = 0.2647 (rounded to four decimal places).

So, the probability of randomly selecting two animals and both of them being Labrador Retrievers is approximately 0.2647.

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Steps to find MAD:

Step 1. Calculate mean(\(\overline{x}\)) of the data using formula: \(\overline{x}=\dfrac{\sum x}{n}\) ,  where x denotes data points and n is the number of data points.

Step 2. Calculate distance of each data point from mean :

Distance = \(|x-\overline{x}|\)

Step 3. Divide  distance of each data point from mean by n:

MAD = \(\dfrac{\sum |x-\overline{x}|}{n}\) , which is the final computation to find MAD.

Answer:

11m+5n

Step-by-step explanation:

you just add the m and or n with the numbers

Answer:1/x^20

Step-by-step explanation:

Answer:

\(\frac{1}{x^{20}}\)

Step-by-step explanation:

\((x^{4})^{-5}\) = \(\frac{1}{(x^{4})^{5}}\) = \(\frac{1}{x^{20}}\)

Answer:

5.66 feet

Step-by-step explanation:

a^2 + b^2 = c^2

2^2 +b^2 = 6^2

square root of (36-4) = b

b= 5.66 feet

Answer:

Equation = y = -4x+7

See the graph below

Step-by-step explanation:

The equation of the line in slope intercept form is expressed as;

y = mx+c

Given

slope m = -4

y-intercept c = 7

Substitute

y = -4x + 7

Get the x intercept.

at y = 0

0 = -4x + 7

4x = 7

x = 7/4

x = 1.75

The x coordinate  (1.75, 0)

Get the y intercept

at x = 0;

y = -4(0)+7

y = 0+7

y = 7

The y coordinate is (0, 7)

Answer: Yes, there is an ordered pair solution

The quick way we can see this without having to graph or do any algebra is to look at the two slopes of the lines.

y = x+1 has slope of 1

y = -x+5 has slope of -1

Recall that y = mx+b has slope m.

The two different slopes (1 and -1) indicate the lines are not parallel, so they must intersect exactly once. This intersection is the where the solution is located.

Common stock $12240 and paid-in capital in excess of par value $5100.

What is the common stock?

Common stock is a sort of instrument that represents company equity ownership. Outside of the United States, the words voting share and ordinary share are also commonly used. In the United Kingdom and other Commonwealth countries, they are referred to as equity shares or ordinary shares.

Here, we have

Given:  Nexis Corp. issues 1020 shares of $12 par value common stock at $16 per share.

So $5 per share is the premium on the issued share.

The premium is commonly recorded in a paid-in capital account.

1020×12 =  $1,2240 and a premium would be recorded in common stock.

1020×5 = 5100, would be recorded in the paid-in capital account.

Hence, Common stock is $12240, and paid-in capital in excess of par value is $5100.

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For this series 10, 100, 1000 the common differences are (9 × 10), (9 × 10²), (9 × 10³)

To determine the common difference

100 - 10 = 90

1000 - 100 = 900

similarly, 10000 - 1000 = 9000, 100000 - 10000 = 90000,...........

Therefore, the common differences are (9 × 10), (9 × 10²), (9 × 10³),......

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Answer:

a. 24×24 = 576

b.83×83 = 6889

c.99×99 = 9801

d.1001×1001 = 1002001

e.97×97 = 9409

f.102×102 =10404

Step-by-step explanation:

it is a square number so you just have to multiply the number by itself

Answer:

The zero is (3,0)

Step-by-step explanation:

This is the point in which the line intersects the x-axis

Hope this helps lol

-Scorpio

Answer:

x=1 and x=2

Step-by-step explanation:f(x) = 3x² - 3x - 6

The zeros f(x) = 0 ⇒ 3x² - 3x - 6 = 0

3x² - 6x + 3x - 6 = 0

3x(x - 2) + 3(x - 2) = 0

(x - 2)(3x + 3) = 0 ⇔ x - 2 = 0 ∨ 3x + 3 = 0

x = 2 ∨ 3x = -3

x = 2 ∨ x = -1

The measure of minor arc MPQ in a circle with central angle <MQP measuring 44 degrees is 316 degrees.

To find the measure of minor arc MPQ, we need to first find the measure of central angle <MNQ that intercepts this arc. Since minor arc MPQ and minor arc MP are adjacent, their sum equals the measure of minor arc MPNQ,

<MPQ+arc MP = <MPNQ

Substituting the measure of minor arc MP as 44 degrees, we get,

ZMPQ+ 44 360

Solving for MPQ, we get,

ZMPQ = 360-44

<MPQ = 316 degrees

Therefore, the measure of minor arc MPQ is 316 degrees.

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Answer:

Step-by-step explanation:

The slopes of both those lines are the same so there is no solution. Use slope triangles to find out the slope. They are both 1/4.

A. No solution

y = 1/4x+5

x - 4y = 4

You can simplify the second equation into y = 1/4x - 1

Since these equations both have the same slope, they are parallel. When two lines are parallel, they have no solutions.