A 250.0-mL flask contains 0.2500 g of a volatile oxide of nitrogen. The pressure in the flask is 760.0 mmHg at 17.00°C. How many moles of gas are in the flask?
Answer:
0.0104 moles of gas in the flask.
Explanation:
To calculate the number of moles of gas in the flask, you can use the ideal gas law equation: PV = nRT. Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is temperature.
First, you need to convert the pressure from mmHg to atm and the temperature from Celsius to Kelvin. The pressure in atm is 760.0 mmHg / 760 mmHg/atm = 1 atm. The temperature in Kelvin is 17.00°C + 273.15 = 290.15 K.
Next, you need to convert the volume from mL to L. The volume in L is 250.0 mL / 1000 mL/L = 0.2500 L.
Now you can plug all the values into the ideal gas law equation and solve for n: (1 atm)(0.2500 L) = n(0.08206 L·atm/mol·K)(290.15 K). Solving for n gives n = 0.0104 mol.
So there are approximately 0.0104 moles of gas in the flask.
please due friday but want to do today
Answer: 3.44%
Explanation: try it for math
What type of reactions are the following problems?
10) 12 Al + 1 S8→ 4 Al₂S3
a. Single replacement
b. double replacement.
c. Synthesis/combination
d. Decomposition
e. Combustion
Answer: a
Explanation:
6. How many moles are in 8.30 x 1023 molecules of CO₂?
a.
b.
C.
d.
1.37
2.8
55.5
100
Electron-dot diagrams Show all the electrons in an element?
Answer:
flase
Explanation:
i got the answer from khan
a. How many moles of CO2 are produced in 19.63 grams of CO2?
Answer:
0.44604005953260284 moles
Explanation:
or you could round it to 0.446 moles
mol CO₂ = mass : molar mass CO₂
mol CO₂ = 19.63 : 44 g/mol = 0.446
A headline for a newspaper in a small town reads: "Sheriff Killed by a Poison that has Killed More People Than Any
Other Poison." How was the sheriff poisoned?
thallium
cyanide
arsenic
strychnine
The sheriff was poisoned by the use of the arsenic poison.
How does arsenic poison work?Arsenic is a toxic substance that can be deadly if ingested or inhaled in high concentrations. It works by disrupting important cellular processes and functions within the body.
When arsenic is ingested, it is absorbed through the digestive system and enters the bloodstream. From there, it is transported to various organs and tissues throughout the body, including the liver, kidneys, and lungs.
Arsenic interferes with the enzymes and proteins that are essential for cellular metabolism, DNA synthesis, and other important cellular processes. This disruption can cause a range of symptoms, including abdominal pain, diarrhea, vomiting, and dehydration.
Arsenic can also cause damage to the nervous system, leading to neurological symptoms such as confusion, seizures, and numbness or tingling in the extremities.
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aqueous lead (ii) chloride reacts with aqueous sodium sulfate to produce a lead(ii) sulfate precipitate and aqueous sodium chloride
The equation of the reaction leading to the formation of the precipitate is; \(PbCl_{2}(aq) + Na_{2} SO_{4} (aq) ---- > PbSO_{4}(s) + 2NaCl(aq)\)
What is the precipitate?We define a precipitate as a compound that can be formed as a solid when we mix two aqueous solutions. An aqueous solution is a solution of a substance that have been dissolved in water.
Thus, when we have a mixture of two liquid reactants and then one of the products does separate itself out of the solution then we say that a precipitate has been formed.
In this case, we are to write down the equation of the reaction between aqueous lead (ii) chloride reacts with aqueous sodium sulfate to produce a lead(ii) sulfate. The solid would separate out of the system and we can see the white color of the lead(ii) sulfate.
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A sample of oxygen was collected over water at 25.00°C and 0.886 atm. If the total sample volume was 2.92 L, how many moles of O2 were collected?
0.128 moles of O2 were collected.
What is the purpose of collecting the oxygen over water in this experiment?The purpose of collecting the oxygen over water is to prevent any other gas from entering the collection vessel. The water acts as a barrier to keep out other gases.
To determine the moles of O2 collected, we need to correct for the presence of water vapor in the sample. At 25.00°C, the vapor pressure of water is 23.76 mmHg or 0.0313 atm.
First, we can calculate the partial pressure of oxygen:
P(O2) = total pressure - vapor pressure of water
P(O2) = 0.886 atm - 0.0313 atm
P(O2) = 0.8547 atm
Next, we can use the ideal gas law to calculate the moles of O2:
n = PV/RT
where P is the partial pressure of O2, V is the volume of the sample, R is the gas constant (0.08206 L·atm/(mol·K)), and T is the temperature in Kelvin (25.00°C + 273.15 = 298.15 K).
n = (0.8547 atm)(2.92 L)/(0.08206 L·atm/(mol·K))(298.15 K)
n = 0.107 mol
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For the following reaction, 41.0 grams of sulfuric acid are allowed to react with 36.5 grams of zinc hydroxide. What is the maximum amount of zinc sulfate that can be formed? Mass = g What is the FORMULA for the limiting reactant? What amount of the excess reactant remains after the reaction is complete? Mass = g
The FORMULA for the limiting reagent is \(ZnOH_2\).
4.27 grams of reactant remains after the reaction is complete.
What is a limiting reagent?The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops.
Given data:
Mass of sulfuric acid = 41.0 grams
Molar mass of sulfuric acid = 98.08 g/mol
Mass of zinc hydroxide = 36.5 grams
Molar mass of zinc hydroxide = 99.424 g/mol
Step 1:moles sulfuric acid = mass sulfuric acid / molar mass sulfuric acid
moles sulfuric acid = 41.0 grams / 98.08 g/mol
moles sulfuric acid = 0.41 moles
Step 2: moles of zinc hydroxide
moles zinc hydroxide = 36.5 grams / 99.424 g/mol
moles zinc hydroxide =0.367 moles
Step 3: Calculate limiting reactant
zinc hydroxide is the limiting reactant. It will completely be consumed.
There will remain 0.41 moles - 0.367 moles = 0.043 moles
This is 0.043 moles x 99.424 g/mol
= 4.27 grams
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Draw a formula for Thr-Gly-Ala (T-G-A) in its predominant ionic form at pH 7.3. You may assume for the purposes of this question that the pKa values of the acidic groups of amino acid residues in the peptide are the same as in the amino acid itself.
Answer:
gggggggggg
Explanation:
gggggggg
The tripeptide formed from threonine, glycine and alanine is neutral at the pH of 7.3. The carboxylic end is negative charged by donating its proton to form the NH₃⁺ group.
What is peptide?Peptides are protein units formed from two or more amino acids bonded through peptide bonds. There are essential and non-essential amino acids. Essential amino acids have to be uptake from food and non-essential amino acids are synthesized inside the body.
Threonine is an essential amino acid with a CH₃CHOH side group. Glycine has the simplest side group hydrogen and alanine has CH₃ side chain. Both glycine and alanine are non-essential amino acids.
Each amino acids are represented with a three letter code or one letter symbol. Thus threonine is T, G for glycine and A for alanine. At a pH of 7.3 the peptide formed from these amino-acids contains a negatively charged carboxylic end.
A positively charged amino end made by protonation from the acid group make the overall charge zero. The structure of the peptide is given in the uploaded image.
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Hydrazine, N2H4, is used as a rocket fuel. In the reaction below, if 93.1 g of N2H4 and 105.7 g of N2O4 are allowed to react, how many grams of excess reactant remain at the end of the reaction?
2 N2H4 + N2O4 → 3 N2 + 4 H2O
Answer: 19.54 grams H2H4 remain
Explanation:
The moles of each reagent are calculated by dividing the mass of each by its molar mass (g/mole).
N2H4: (93.1g/(32.0 g/mole) = 2.908 moles
N2O4: (105.7g/92.0 g/mole) = 1.149 moles
The balanced equation says we need one mole N2O4 per 2 moles N2H4. This means the 1.149 moles of N2O4 will consume 2*(1.149 moles) = 2.298 moles of N2H4. Since we start with 2.908 moles, (2.908 - 2.298) = 0.611 moles N2H4 will remain unreacted. Bummer. Multiply by the molar mass of N2H4 to obtain 19.55 grams unreacted N2H4.
If gas is cooled from 323.0K to 273K and the volume is kept constant, what final pressure would result if the original pressure was 750.0 mmHg?
Step 1
Gay-Lussca's Law is used here.
It states that the pressure of a given mass of gas varies directly with the absolute temperature when the volume is kept constant.
------------
Step 2
Mathematically:
P1/T1 = P2/T2 (1)
Data provided:
Conditions 1 => P1 = pressure 1 = 750.0 mmHg; T1 = absolute temperature = 323.0 K
Conditions 2 => P2 = unknown; T2 = 273 K
-----------
Step 3
P2 is cleared from (1):
P1/T1 x T2 = P2
(750.0 mmHg/323.0 K) x 273 K = 634.0 mmHg
Answer: P2 = 634.0 mmHg
MULTIPLE CHOICE QUESTION
How many grams of Al203 were
decomposed?
287.13
200g
888g
1148.52g
287.13 grams of Al₂O₃ were decomposed. Therefore, option A is correct.
What is molar mass ?The term molar mass is defined as the mass in grams of one mole of the compound. A mole of any substance is 6.022 × 10²³ molecules. It is called as Avogadro's number. The molar mass is a bulk property, it is not molecular, property of a substance.
2Al₂O₃ ⇒ 4Al + 3O₂
Thus, 4 mol of Al combine with 3 mol of oxygen to form 2 mol of Al₂O₃.
2 mol of Al corresponds to 2 × 27 = 54g
Thus, the weight of Al used in the reaction is 108 g.
Molar mass of Al₂O₃ is 101.96g/mol.
5.63 moles of Al = 5.63 × 54 / 101.96
= 287.13 grams
Thus, 287.13 grams of Al₂0₃ were decomposed, option A is correct.
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Which formula represents a nonpolar molecule containing polar covalent bonds?
Answer:
Figure 2 represents a nonpolar molecule containing polar covalent bonds
Explanation:
The CO2 molecule is linear, formed by 3 atoms and the electronegativity variations are equal, so its dipolar moment will be null, and this molecule will be nonpolar, however, it has polar covalent bonds.
Experiment 4: A chemist mixes aqueous solutions of sodium hydroxide and aluminum chloride in a double-displacement reaction, which forms a white solid precipitate and a clear solution. Write the complete, balanced molecular equation for the reaction. Include physical states.
balanced equation:
The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)
In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.
The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.
The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.
In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.
It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.
Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.
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The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride(NaCl) mined from ancient salt deposits. The number of kilowatt-hours of electricity required to produce 5.50kg of metallic sodium from the electrolysis of molten NaCl(s) is_________when the applied emf is 5.00V
The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride(NaCl) mined from ancient salt deposits. The number of kilowatt-hours of electricity required to produce 5.50kg of metallic sodium from the electrolysis of molten NaCl(s) is 4.58 kWh when the applied emf is 5.00V
The reaction equation is given as:
Na⁺ +e⁻ ⇒ Na
So moles of Na equals moles of electrons used
So the number of moles of sodium can be calculated as:
number of moles = mass ÷ molar mass
Moles = 5500 g ÷ 23 g/mol (1 kg = 1000 g)
Number of moles = 239.13 moles
Q = n × F; where F represents the Faraday constant
Q = 239.13 moles × 96500 C
Q = 23,976,045 mol C
The relationship between electrical energy and Q is
E = Q x V
Now we can substitute the given value into the above formula and calculate the current value as follows:
E = 23,976,045 × 5 .50
E = 126,918,248 J
As 1 J = 2.77 × 10⁻⁷ kWh
For this reason;
126,918,248 J ÷ 2.77 × 10⁻⁷ kWh =4.58 kWh
From this we can conclude that 4.58 kWh of power is required to produce 5.50 kg of metallic sodium from the electrolysis of molten NaCl(s).
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If you were an element, what element are you and in what another element would you like to bind with and why?
Answer:
If I were an element, I would want to be Carbon. I would want to combine with oxygen. It would create carbon dioxide. It has daily life uses. For heat, and for refridgment and more.
Explanation:
Answer fast please!!
A calorimeter contains 600 g of water at 25°C. You place a hand warmer containing 300 g of liquid
sodium acetate inside the calorimeter. When the sodium acetate finishes crystallizing, the temperature of
the water inside the calorimeter is 36.4°C. The specific heat of water is 4.18 J/g-°C. What is the enthalpy
of fusion (AH) of the sodium acetate? (Show your work.) Where necessary, use q = mH₁.
The enthalpy of fusion of sodium acetate is approximately -93.64 J/g.
To calculate the enthalpy of fusion (ΔH) of sodium acetate, we can use the principle of energy conservation. The heat lost by the hand warmer during the crystallization process is equal to the heat gained by the water in the calorimeter.
First, let's calculate the heat gained by the water in the calorimeter using the formula q = m × c × ΔT, where q is the heat gained or lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
q_water = m_water × c_water × ΔT_water
Given:
m_water = 600 g
c_water = 4.18 J/g-°C
ΔT_water = 36.4°C - 25°C = 11.4°C
q_water = 600 g × 4.18 J/g-°C × 11.4°C
q_water = 28092 J
Since the heat lost by the hand warmer during crystallization is equal to the heat gained by the water, we can write:
q_water = q_handwarmer
Now, let's calculate the heat lost by the hand warmer using the same formula:
q_handwarmer = m_handwarmer × c_handwarmer × ΔT_handwarmer
Given:
m_handwarmer = 300 g
c_handwarmer = unknown (specific heat capacity of sodium acetate)
ΔT_handwarmer = 36.4°C - initial temperature of sodium acetate
Since the sodium acetate undergoes crystallization, its temperature remains constant during this phase change. The temperature at which crystallization occurs is known as the freezing point of sodium acetate, which is approximately 58°C. Therefore:
ΔT_handwarmer = 36.4°C - 58°C = -21.6°C
Now, we can substitute the known values into the equation:
q_water = q_handwarmer
28092 J = 300 g × c_handwarmer × -21.6°C
To solve for c_handwarmer, we rearrange the equation:
c_handwarmer = -28092 J / (300 g × -21.6°C)
c_handwarmer ≈ 5.47 J/g-°C
The specific heat capacity of sodium acetate (c_handwarmer) is approximately 5.47 J/g-°C.
The enthalpy of fusion (ΔH) can be calculated using the equation ΔH = q_handwarmer / m_handwarmer:
ΔH = -28092 J / 300 g
ΔH ≈ -93.64 J/g
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A rigid, 26-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. Heat is now added until the quality inside the cooker is 40 percent. Determine the exergy.
The minimum entropy change of the heat-supplying source is -0.87 kJ/K.
Initial entropy of the systemIn this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.
at initial pressure of 175 kPaS₁ = 1.485 + (0.1)(5.6865) = 2.0537 kJ/kg K
Final entropyThe entropy at the final state given the new 40-% quality:
pressure inside the cooker = 150 kPaS₂ = 1.4337 + (0.4)(5.7894) = 3.7495 kJ/kg K
Mass of the steam at specific volumem₁ = 0.026/(0.001057 + 0.1 x 1.002643) = 0.257 kg
m₂ = 0.026/(0.001053 + 0.4 x 1.158347) = 0.056 kg
minimum entropy change of the heat-supplying sourceΔS + S₁ - S₂ + S₂m₂ - S₁m₁ - sfg(m₂ - m₁) > 0
ΔS + 2.0537 - 3.7495 + (3.7495 x 0.056) - (2.0537 x 0.257) - 5.6865( 0.056 - 0.257) > 0
ΔS > -0.87 kJ/K
Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.
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A rate constant obeys the Arrhenius equation, the factor A being 2.2 10^13 s-1 and the
activation energy being 150. kJ mol-1. What is the value of the rate constant at 227C, in
s-1?
4.743 x \(10^{-3}\) s-1 is the value of the rate constant.
What is an Arrhenius equation?The Arrhenius equation describes the relationship between the rate of reaction and temperature for many physical and chemical reactions.
As per Arrhenius equation,
k = Ae-Ea÷RT
T = 227 = 500.15 K
R = 0.008314 kJ/K mol
Ea = 150 kJ/mol
Ea÷RT
= 150÷(0.008314 x 500.15)
= 36.073
k = Ae-36.073 = (2.2 x \(10^{13}\) s-1) (2.156 x \(10-{16}\))
k = 4.743 x \(10^{-3}\) s-1
So, the correct answer is option d) i.e. 4.7 x \(10^{-3}\) s-1
As per Arrhenius equation,
k = Ae-Ea/RT
T = 227 = 500.15 K
R = 0.008314 kJ/K mol
Ea = 150 kJ/mol
Ea÷RT = 150÷(0.008314 x 500.15) = 36.073
k = Ae-36.073 = (2.2 x \(10^{13}\) s-1)(2.156 x \(10^{-16}\))
k = 4.743 x \(10^{-3}\) s-1
Hence, 4.743 x \(10^{-3}\) s-1 is the value of the rate constant.
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Which of the following explains why a longer bond is also a weaker bond? Help plz
Answer:
Longer bonds have lower attractive force
Which of the following terms would you use to describe Mg²+. Select all that apply.
Subatomic particle
lon
Element
Molecule
The correct term to describe Mg²+ is "ion."
An ion is an atom or molecule that has gained or lost electrons, resulting in a positive or negative charge. In the case of Mg²+, it indicates that the magnesium atom has lost two electrons, leading to a positive charge of +2. The term "subatomic particle" refers to particles that are smaller than an atom, such as protons, neutrons, and electrons. While Mg²+ does involve subatomic particles (protons and electrons), the term itself is not directly applicable to Mg²+. The term "element" refers to a pure substance composed of only one type of atom. Magnesium (Mg) is an element, but Mg²+ specifically refers to the ionized form of the magnesium atom. The term "molecule" refers to a combination of two or more atoms held together by chemical bonds. Since Mg²+ is an ion and does not involve bonding with other atoms, it is not considered a molecule. Therefore, the correct term to describe Mg²+ is "ion."
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Which of the following energy does NOT travel as a wave?
A)Sound
B)Light
C)Earthquakes
D)Wind
Answer:
Wind
Explanation:
It's impossible for them to travel in a wave.
A vial of Ancef 1 g is reconstituted with 5 mL of normal saline to yield 125mg / m * L How many mL of the medication should be given if a patient is prescribed 250 mg of the medication?
Ancef (Cefazolin) is a first-generation cephalosporin antibiotic that is used to treat bacterial infections. Cefazolin is available in several formulations, including injectable, intravenous, and powder for injection.
A vial of Ancef 1 g is reconstituted with 5 mL of normal saline to yield 125mg / m * L. We need to determine how many milliliters of the medication should be given if a patient is prescribed 250 mg of the medication.To begin with, let us first calculate the concentration of the reconstituted solution using the given data.1 gram of Ancef (Cefazolin) = 1000 milligrams (mg)5 mL of normal saline = 5000 milligrams (mg)Therefore, the total volume of the reconstituted solution = 5 mL + the volume of Ancef (Cefazolin)1 g of Ancef (Cefazolin) = 125 mg/mL (Given)Therefore, the volume of Ancef (Cefazolin) = (250 mg)/(125 mg/mL) = 2 mLTherefore, the total volume of the reconstituted solution = 5 mL + 2 mL = 7 mLThus, the amount of medication that should be given to the patient is 2 mL.For such more question on antibiotic
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Below is a reaction of calcium chloride solution (CaCl2) and potassium carbonate (K2CO3). Draw the reactant
with the appropriate amount of K2CO3, particles in the empty box. The product calcium carbonate (CaCO3)
forms a precipitate. Draw the appropriate example of the precipitate and the ions that remain in the solution.
Add two water molecules around each ion in the solution.
The chemical reaction is shown by \(CaCl_{2} (aq) + K_{2} CO_{3} (aq) ----- > CaCO_{3}(s) + 2KCl(aq)\). The solvation of the KCl is shown in the image attached.
What is the reaction taking place?We know that a reaction is taking place when there is a change in the arrangement of the atoms that surround the reactants and then the products are formed. It is clear that there is a cleavage of the bods that surround the reactants and there is a recombination of these atoms as the products are formed. This recombination of the atoms now takes place in a different way so that we can be able to get new substances at the end of the reaction.
In this case we are looking at the kind of reaction that occurs between potassium carbonate and calcium chloride. One of the reactants is going to separate out of the solution and we would call it the precipitate. The other product is solvated by the water molecules.
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Use this reaction to answer the questions and explain :
CO(g)+2H2(g)-CH3OH(g) DeltaH= -91.8kJ
1- if the temperature of the system increases , will the value of the equilibrium constant k increase, decrease or stay the same?
2- Will the concentration of H2 increase, decrease or stay the same ?
1) If the temperature of the system increases, the equilibrium constant k decreases.
2) the concentration of H₂ increases.
The reaction is given as :
CO + 2H₂ ⇄ CH₃OH ΔH = -91.8 KJ ( exothermic reaction)
1) Temperature is the only factor that changes the equilibrium constant for the given reaction. As temperature increases equilibrium constant decreases because the reaction is exothermic reaction.
K = [ CH₃OH ] / [CO] [H₂]²
2) If the temperature increases the position of equilibrium moves to the left and concentration of H₂ increases.
Thus, 1) If the temperature of the system increases, the equilibrium constant k decreases.
2) the concentration of H₂ increases.
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Write a balanced nuclear equation for the beta decay of Pb-212
Answer:
Explanations:
Beta decay is a type of radioactive decay in which a beta particle is emitted from the nucleus. A beta particle is written as:
\(^0_{-1}\beta\)The required balanced nuclear equation for the beta decay of Pb-212 will be expressed as:
\(^{212}_{82}Pb\rightarrow^0_{-1}\beta+^{212}_{83}Bi\)From the reaction, you can see that the beta decay of Pb-212 produces the Bismuth element with atomic number 83 and mass number 212.
PLEASE HELP ILL MARK BRAINEST!!! 35 POINTS!! THANK YOU
This chart above compares the reaction rate of a naturally occurring chemical reaction vs. the same reaction when an enzyme is involved.
a. Compare the differences between the two reactions, but also note what they have in common.
b. Explain the role the enzyme plays in the second reaction
c. Explain what the three bumps in the second reaction means and why the original reaction only has one bump.
In the image given, the difference in the activation energy is observed on addition of a catalyst in the same reaction.
Activation energy is the minimum initial energy needed for a reaction to start. It is denoted as \(E_a\).
a) The difference between the reactions is that on addition of a catalyst, the activation energy is reduced to form the same product.
The similarity is that these peaks are basically the transition states where the energy is highest, and the reactant molecules are highly unstable and immediately get converted to the products.
b) Enzymes in the second reaction are the catalysts which increase the rate of the reaction and reduce the activation energy required for the reaction to happen. Not only do the enzymes reduce the activation energy, but they also introduce a multiple energy reaction pathway which must be fulfilled in order to form the products.
c) The second reaction is a multi-step reaction and occurs in a series of collisions, where each collision produces an intermediate molecule which collides further until the final product molecules are formed. Thus, each collision step has its own activation energy peak.
The original reaction has only one activation energy peak as the reactants collide once and form the products immediately thereby consuming a lot of energy.
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The reaction Na3PO4 + 3HCl → 3NaCl + H3PO4 produces 42.7 g of NaCl. How many grams of Na3PO4 are needed?
Answer:
14.23
Steps given below in the picture
I hope my answer helps you.