what is the procedure for adding numbers in scientific notation?

As per conversion units, 45.3 grams is each person's final serving of 1 burger.

As 1 burger has a weight of 1 pound which is equal to 453 grams ,and as each burger looses 10% of it's weight while cooking .

So the weight of 1 burger after cooking is,

10/100×453=45.3 g

Thus,each person's final serving of 1 burger is 45.3 grams.

Conversion  units or unit conversion expresses the same property with a different unit of measurement.It is a numerical expression or a number that is used to change  one set of units to another.

It usually occurs through multiplicative conversion factors through which the measured quantity is changed without changing it's effects.

There are different conversion systems such as:

1) SI system

2)CGS system

3)MKS system

4) FPS system

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Answer:

S5O7

Explanation:

The half life of radioactive iodine 137 is 8 days 0.0866 iodine nuclei are necessary to produce an activity of 1.0 micro Ci

Here given data is half life of radioactive iodine 137 = 8days

Activity of iodine is = 1.0micro Ci

Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation and the material containing unstable nuclei is considered radioactive

The interconnection between the decay constant and half-life of any sample can be given by the expression are

T1/2 = (0.693/R); T1/2 = 8

8 = 0.693/R;  R=0.0866 R=0.693×1.0/t1/2 = 0.0866

0.0866 iodine nuclei are necessary to produce an activity of 1.0 micro Ci

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Answer:

1. Yes, no, no

2. No, yes, no

3. Yes, Yes, No

Explanation:

Three states of matter exist – solid, liquid, and gas. Solids have a definite shape and volume. Liquids have a definite volume, but take the shape of the container. Gases have no definite shape or volume.

Answer:

Explanation:

Ok so for the first row I believe is Yes, No, No

Second row  No, yes, No

last row i dont know

I hope this helped

(p.s I have't done this in a couple of months so it might be wrong and i am so sorry if it is.)

Explanation:

The process by which gas I directly converted to solid is called deposition (reverse sublimation)

Answer:

Deposition

Explanation:

Is the phase transition in which gas transforms into solid without passing through the liquid phase.

We must take into consideration the balance of atoms and charges in order to balance the half-reaction for the conversion of S2O3 2- to S4O6 2- in acidic solution.

Write the imbalanced half-reaction as the first step.

S2O3 S4O6 2- (aq)

Step 2: Align the atoms, with the exception of hydrogen and oxygen.

2S4O6 2-(aq) = S2O3 2-(aq)

Step 3: Add water (H2O) to balance the oxygen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq)

Step 4: Add hydrogen ions (H+) to balance the hydrogen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq)

Step 5: Add more electrons (e-) to balance the charge.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq) + 2e-

The balanced half-reaction in acidic solution is:

S2O3 2- (aq) + 4H+ (aq) + 2e- → 2S4O6 2- (aq) + H2O

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Answer: 4

Explanation: because the zero doesn't count

Answer:

Explanation:

decomposers

Many island chains were formed as a result of blank volcanism is known as hotspot volcanism.

Hotspot volcanism occurs when a mantle plume, a column of hot and buoyant rock material rising from deep within the Earth's mantle, reaches the surface. These mantle plumes are stationary relative to the moving tectonic plates on the Earth's surface.

As the tectonic plate moves over the stationary hotspot, the mantle plume melts and produces magma. This magma rises through the Earth's crust, creating a volcanic eruption. Over time, repeated eruptions build up layers of lava and volcanic material, forming a cone-shaped volcano. As the tectonic plate continues to move, the volcano becomes inactive, and a new volcano forms above the stationary hotspot.

However, in the case of island chains, the tectonic plate movement carries the volcanoes away from the hotspot. As a result, a trail of extinct volcanoes is left behind, forming a linear chain of islands. Each island in the chain represents a period of volcanic activity at that specific location as the plate moved over the hotspot.

Hotspot volcanism and the formation of island chains provide valuable insights into the dynamics of Earth's mantle and plate tectonics. By studying the age progression of islands in a chain, scientists can gain a better understanding of the movement and speed of tectonic plates and the behavior of mantle plumes deep beneath the Earth's surface.

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We can see that an atom with 14 protons, 14 neutrons, and 16 electrons is unstable, and has a -2 charge.

So the correct option is the third one.

An atom with 14 protons, 14 neutrons, and 16 electrons is not stable. The number of protons in an atom, also known as its atomic number, determines its element and its chemical properties. In this case, the atom has 14 protons, which corresponds to the element silicon (Si) on the periodic table.

For an atom to be stable, it should have a balanced number of protons and electrons. Electrons are negatively charged particles that orbit the nucleus of an atom in energy levels or electron shells. The number of electrons in a stable atom should be equal to the number of protons, resulting in a neutral charge overall.

In this case, the atom has 14 protons and 16 electrons, which means it has two more electrons than protons, resulting in a net charge of -2. This is an example of an ion.

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Answer: The vapor pressure of methanol solution at 298K is 107.12 torr

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

\(\frac{p^o-p_s}{p^o}=i\times x_2\)

where,

\(\frac{p^o-p_s}{p^o}\)= relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

\(x_2\) = mole fraction of solute  =\(\frac{\text {moles of solute}}{\text {total moles}}\)

Given : 38.5 g of urea is present in 142 g of methanol

moles of solute (urea) = \(\frac{\text{Given mass}}{\text {Molar mass}}=\frac{38.5g}{60g/mol}=0.64moles\)

moles of solvent (methanol) = \(\frac{\text{Given mass}}{\text {Molar mass}}=\frac{142g}{32g/mol}=4.4moles\)

Total moles = moles of solute  + moles of solvent  = 0.64 + 4.4 = 5.04

\(x_2\) = mole fraction of solute  =\(\frac{0.64}{5.04}=0.127\)

\(\frac{122.7-p_s}{122.7}=1\times 0.127\)

\(p_s=107.12torr\)

Thus the vapor pressure of methanol solution at 298K is 107.12 torr

The concentration of the HNO₃ solution needed to neutralize the 27.60 mL of 1.00 M NaOH is 2.76 M

The balanced equtaion is given below:

HNO₃ + NaOH —> H₂O + NaNO₃

Now, we shall obtain the concentration of the HNO₃ solution needed for the neutralization reaction. This is shown below:

CaVa / CbVb = nA / nB

(Ca × 10) / (1 × 27.6) = 1

(Ca × 10) / 27.6 = 1

Cross multiply

Ca × 10 = 27.6

Divide both side by 10

Ca = 27.6 / 10

Ca = 2.76 M

Thus, the concentration of the HNO₃ solution needed is 2.76 M

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The comparison of H1 H2 and H3 tags is that:

There are a lot of  different HTML headings and they are:  H2 and H3, H4, H5, H6, etc.

The use of H1 tags is said to be the one that is often used to show all that a person will get if they click on the title. It is seen as the main keywords that will appear in a sequence to bring in one's target audience.

Therefore, The comparison of H1 H2 and H3 tags is that:

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When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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The equilibrium constant relates the concentrations of the products and reactants in the chemical equilibrium. To calculate it we can apply the following equation.

For the reaction: aA + bB ---> cC + dD

Equlibrium constant (Ke) will be:

The letters in square brackets refer to the concentration raised to the respective coefficient. Now we replace the known values:

So, the equilibrium constant (Ke) will be 3.2M

The nucleus (plural, nuclei) houses the cell's genetic material, or DNA, and is also the site of synthesis for ribosomes, the cellular machines that assemble proteins. Inside the nucleus, chromatin (DNA wrapped around proteins, described further below) is stored in a gel-like substance called nucleoplasm.

There are approximately 2.8939 x\(10^2^4\) carbon atoms in 0.37 mol of procaine.  The molecular formula of procaine (C₁₃H₂₀N₂₀₂), one can see that there are 13 carbon atoms (C13) in one molecule of procaine.

Avogadro's number (6.022 x \(10^2^3\)) represents the number of particles (atoms, molecules, or formula units) in one mole of a substance

The number of molecules of procaine in 0.37 mol:

Number of molecules = 0.37 mol x (6.022 x\(10^2^3\) molecules/mol)

Number of carbon atoms = Number of molecules x 13 carbon atoms/molecule

Number of molecules = 0.37 mol x (6.022 x \(10^2^3\)molecules/mol)

= 2.22614 x \(10^2^3\)molecules

Number of carbon atoms = 2.22614 x \(10^2^3\) molecules x 13 carbon atoms/molecule

= 2.8939 x \(10^2^4\)carbon atoms

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The piece of evidence that best identifies the type of reaction as nuclear or chemical is: Chemical, because a new substance is formed. Option 4

In this scenario, the observation that a new substance is formed is a key characteristic of a chemical reaction. Chemical reactions involve the rearrangement of atoms to form different substances with distinct properties. The formation of a new substance indicates a chemical change has occurred.

The other pieces of evidence listed do not necessarily point to a nuclear reaction:

Chemical, because energy is released during the reaction: Energy can be released in both nuclear and chemical reactions, so this observation alone is not sufficient to determine the type of reaction.

Nuclear, because energy is released during the reaction: While energy can be released in nuclear reactions, it is not exclusive to them. Chemical reactions can also release energy, such as in exothermic reactions.

Nuclear, because the mass decreased after the reaction: This observation suggests a change in mass, which could be indicative of a nuclear reaction. However, it is important to consider that chemical reactions can also involve changes in mass, such as the formation of gases or dissolution of a solid.

Overall, the most conclusive evidence to identify the type of reaction is the formation of a new substance, which aligns with a chemical reaction.

Option 4

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Answer: yes

Explanation: it is always in a conductive state

Answer:

Explanation:

Answer: 8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution. 8 grams of glucose are needed to prepare 400.Oct 6, 2017

Answer:

8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution. 8 grams of glucose are needed to prepare 400

Explanation:

try and find a better answer or ask ur teacher please

The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group

Answer & Explanation:

The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.

Answer:

the train

Explanation:

mechanical

Answer:

Oxidation number:

3*1+ oxidation number of J+2*-2= -1

Oxidation number of J = 0

Q_w = 307.3 J

C_m = .233 J/g•K

%error = 39.95%

For simplicity's sake, I'm relabeling

Q_w as Q1

m_w as m1

C_w as c1

T_eq as T2

T_w as T1

Q_m as Q2

m_m as m2

C_m as c2

experimental value as exp

actual value as actual

Question 1

Q1 = m1•c1•(T2-T1)

Identify what you know

m1 = 124g

c1 = 4.13 J/g • K

T2 = Final temperature = 22.3°C

T1 = Initial temperature = 21.7°C

Convert Celsius to Kelvin (C+273.15=K)

T2 = 295.45 K

T1 = 294.85 K

Plug in

Q1 = 124g•(4.13 J/g•K)•(295.45K - 294.85K)

Solve

Q1 ≈ 307.3 J

Question 2

-Q1 = Q2 = m2•(c2)•(T2-100)

Ignore Q2 for a second, and you're left with

-Q1 = m2•(c2)•(T2-100)

which is the same thing.

Identify what you know

Q1 = 307.3 J

m2 = 17g

T2 = 22.3°C

Plug in

-(307.3J) = 17g • c2 • (22.3°C-100°C)

Solve

-307.3 J = (-1320.9 g•°C) • c2

c2 = .233 J/g•°C or J/g•K (I'll explain later)

Question 3

%err = ((exp - actual)/actual) • 100%

Identify what you know

exp = .233 J/g•K

actual = .388 J/g•K

Plug in

%err = ((.233 J/g•K - .388 J/g•K)/ .388 J/g•K) • 100%

Solve

%err = -39.95 %

Take the absolute value

%err = 39.95%

Referring to earlier change in units:

The reason we can not use the K value of T2 (295.45K) is because the formula provided (T2-100) does not account for T2 being in K. It only accounts for T2 being in °C.

BaSO4 (s) + Cu(NO3)2 (aq)  and KCl (s) + Mg3(PO4)2 (s) is the product of given precipitation reactions.

Ba(NO3)2 (aq) + CuSO4 (aq) → BaSO4 (s) + Cu(NO3)2 (aq)

 K3 PO4 (aq) + MgCl2 (aq) → KCl (s) + Mg3(PO4)2 (s)

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