What is the probability of pulling jack, queen, or king from a deck of cards?

Answers

Answer 1

Answer:

Step-by-step explanation:I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thnk me....

What Is The Probability Of Pulling Jack, Queen, Or King From A Deck Of Cards?

Related Questions

what is the equation of a line that contains the point (1,2) and is parallel to the line given by the equation y=3x+1

what is the equation of a line that contains the point (1,2) and is perpendicular to the line given by the equation y=1/2x-4

Answers

The equation of the line that passes through the parallel line is 3x-y-1=0 and the equation of the line that passes through the perpendicular line x+3y-7=0.

Given that,

The point (1,2) and the parallel line equation is y=3x+1 and the perpendicular lie equation is y=1/2x-4.

We have to find equation of the line that passes through the parallel line and the another equation of the line that passes through the perpendicular line.

First, we find the equation of the line that passes through the parallel line.

The equation of the line is (y-y₁)=m(x-x₁)

The m is slope of the line.

m=3

x₁=1 and y₁=2

The equation of the line is (y-2)=3(x-1)

y-2=3x-3

3x-y-3+2=0

3x-y-1=0

Now,

We find the equation of the line that passes through the perpendicular line.

The equation of the line is (y-y₁)=-1/m(x-x₁)

The m is slope of the line.

-1/m=-1/3

x₁=1 and y₁=2

The equation of the line is (y-2)=-1/3(x-1)

3(y-2)=-(x-1)

3y-6=-x+1

x+3y-6-1=0

x+3y-7=0

Therefore, the equation of the line that passes through the parallel line is 3x-y-1=0 and the equation of the line that passes through the perpendicular line x+3y-7=0.

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HELPPPP!!!!!!!!! ASAP !!

HELPPPP!!!!!!!!! ASAP !!

Answers

Answer:

x > 6

That is one of the answers

a standard deck is shuffled and placed on a table. what is the expected number of cards that are next to another card of the same value? (in a standard deck there are 52 cards. there are 13 values (ace, two, three, . . . , nine, ten, jack, queen, king). each value appears on 4 different cards in the deck)

Answers

The expected number of cards that are next to another card of the same value in a shuffled standard deck is approximately 0.1698.

To calculate the expected number of cards that are next to another card of the same value in a shuffled standard deck, we can consider the probability of each card being next to another card of the same value.

Let's break down the calculation:

For each card in the deck, there are two adjacent cards (one on each side) that can potentially be of the same value. However, the first and last cards only have one adjacent card each.

For the inner cards (excluding the first and last cards), there are three possibilities for each card:

The card is of the same value as the card to its left and the card to its right.

The card is of the same value as the card to its left but not the card to its right.

The card is of the same value as the card to its right but not the card to its left.

Since each card value appears on four cards in the deck, the probabilities for each of these three possibilities are:

Probability of both adjacent cards having the same value = (3/51) × (3/51) = 9/2601

Probability of only the left adjacent card having the same value = (3/51) × (48/51) = 144/2601

Probability of only the right adjacent card having the same value = (48/51) × (3/51) = 144/2601

Now, let's calculate the expected number of cards next to another card of the same value:

Expected number = (1/52) + (1/52) + (50/52) × (9/2601 + 144/2601 + 144/2601) + (1/52) = 441/2601 ≈ 0.1698

Therefore, the expected number of cards that are next to another card of the same value in a shuffled standard deck is approximately 0.1698.

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what is the correlation

what is the correlation

Answers

Answer: moderate, C, B

Step-by-step explanation:

A)  A shows a moderate negative correlation.  It is moderate because the scattered points are sort of close to the line so it has moderate/medium correlation.  It is also negative because it has a negative slope

B) C shows the strongest correlation because the points around the line are tight and close.

C)  B should not have been drawn.  The  correlation is very weak.  You do know where the line should be because the points are all over the place.

On the graph below, draw any line with a slope of *positive* 2 and draw any line with a slope of *negative* 2.

Answers

Refer to the image for the graph of the lines.

The common form of the equation of a line is y = mx + c, where m is the slope of the line and c is a constant.

We need to draw any line with a slope m = 2, and

another line with a slope m = -2.

Disclaimer: Let us assume that the constant c = 0.

Then the equation to the line with a slope of "positive" 2 is given by

y = 2x

Then the equation to the line with a slope of "negative" 2 is given by

y = -2x

Refer to the attached image for the graph of the lines with the slope of "positive" 2 and "negative" 2.

f: green line indicates a line with a slope of "positive" 2.

g: blue line indicates a line with a slope of "negative" 2.

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On the graph below, draw any line with a slope of *positive* 2 and draw any line with a slope of *negative*

The sum of three x and four y equals 10

Answers

Answer:

3x+4=10

Step-by-step explanation:

three x = 3x

and four = 4

equals 10 = 10

3x+4=10

Nathan is organizing textbooks on his bookshelf. He has a Spanish textbook, a math

textbook, and a history textbook. How many different ways can he line the textbooks

up on his bookshelf?

Answers

Answer:

6 ways

Step-by-step explanation:

Given:

Books: Spanish, Maths and History textbooks (1 each)

Required

Determine the number of arrangements

In total, Nathan has 3 books.

The number of arrangements (n) is as follows:

The first book can be lined in 3 ways

The second book can be lined in 2 ways

The third book can be lined in 1 way

So,

\(n = 3 * 2 * 1\)

\(n = 6\)

Answer:

6 ways

Step-by-step explanation:

took edge test

Omar owns a sandwich shop, and his best selling sandwich is the BLT. When making BLT sandwiches, it takes
3
4
of a pound of bacon to make 4 sandwiches. He uses
1

1
20
pounds of bacon for every 2 tomatoes used and 5 tomatoes for every full head of lettuce used.
If Omar is making enough BLT sandwiches to use 2 full heads of lettuce, then he is going to use pounds of bacon and will make a total of BLT sandwiches.
Reset Next

Answers

by using multiplication, we get that 28 BLT sandwiches can be made by Omar.

We are given that:

For every full head of lettuce used,

Number of tomatoes used = 5

Now, we will use multiplication.

2 full heads of lettuce used = 5 × 2 = 10 tomatoes used

Now, we also have:

2 tomatoes used = 1 1/20 pounds of bacon  used.

= 21/20 pounds of  bacon used.

1 tomato = (21 / 20) × (1 / 2) = 21 / 40 pounds bacon

10 tomatoes = (21 / 40) × 10 = 21 / 4 pounds bacon

Also,

3 / 4 pounds of bacon = 4 sandwiches

1 pound of bacon = 16 / 3 sandwiches.

21 / 4 pounds of bacon = (16 / 3) × (21 / 4) = 28 sandwiches

Therefore, by using multiplication, we get that 28 BLT sandwiches can be made by Omar.

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3n + 2 =
24
17
5
i had to put extra letters

Answers

Answer:

17 is your answer

Step-by-step explanation:

Gretta is 1 1/2 meters tall. Which of the following is equivalent to 1 1/2 meters?


Answers

The answer would be one of the following in the photo below....if not do you have a picture you could show me of the possible answers?
Gretta is 1 1/2 meters tall. Which of the following is equivalent to 1 1/2 meters?

A Peice of cable is 8.5 cm long and weighs 51 grams. what will a 10cm legth weight?

Answers

Determine an average rate for the wire.

52 grams / 8.5 cm = 6.12 grams/cm

6.12 grams/cm * 10 cm = 61.2 grams
There’s your answer

Suppose that rising productivity increases potential output in each period by 4%. What kind of monetary policy would be needed to maintain a zero rate of inflation at full employment?.

Answers

When rising productivity increases potential output in each period by 4%, the kind of monetary policy that would be needed to maintain a zero rate of inflation at full employment is that it should increase money supply by 4% per period. (Option C)

Potential output is defined as the maximum amount or output the economy can produce on a constant basis. It is an important concept in both macroeconomics and monetary policy. When the economy approaches production at nearly full capacity, the increased demand results in pressure on input cost including wages. As productivity increases the potential output by 4% each period, the type of monetary policy that maintains a zero rate of inflation at full employment is to increase the money supply by 4% per period.

Note: The question is incomplete as it is missing options. The options are A. It should keep money supply constant. B. It should increase money supply by 4% in the first period and thereafter, hold money supply constant. C. It should increase money supply by 4% per period. D. t should decrease money supply by 4% each period.

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given x=8x=8, μ=22.3μ=22.3, and σ=3.9σ=3.9, indicate on the curve where the given x value would be.

Answers

Here, x value of 8 would be located on the left tail of the normal distribution curve, 3.67 standard deviations below the mean (μ=22.3) and with a very low value in terms of percentile or probability (0.015%).

To indicate where the given x value of 8 would be on the curve, we need to plot it on a normal distribution curve with a mean (μ) of 22.3 and a standard deviation (σ) of 3.9.
First, we need to convert the given x value of 8 into a z-score by using the formula:  z = (x - μ) / σ
Plugging in the values, we get: z = (8 - 22.3) / 3.9 = -3.67
This means that the value of 8 is located 3.67 standard deviations below the mean.
Next, we need to find this point on the normal distribution curve. We can use a z-score table or a graphing calculator to find the corresponding area under the curve.
If we use a z-score table, we can look up the area to the left of -3.67, which is 0.00015. This means that only 0.015% of the data falls below this point.
To plot this on the curve, we can locate the mean (μ) and mark it as the center of the curve. Then, we can count 3.67 standard deviations to the left of the mean and mark this as the point where the value of 8 would be located.

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If 1/5 of my money is $80, what is 50% of my money? ​

Answers

80 x 5 = 400

400/2 = 200

$200

Answer:

$200

Step-by-step explanation:

So 1/5 of th3 money is $80 so you would multiply 80 by 5 you would get 400

then it asks what is 50% of 400 so you would divide 400 by 2 which gives you 200

200 is your answer

f(x) = 4x + 2; Find f (8)​

Answers

Answer:

f(8) = 34

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 4x + 2

f(8) is x = 8

Step 2: Evaluate

Substitute:                    f(8) = 4(8) + 2Multiply:                        f(8) = 32 + 2Add:                              f(8) = 34

2 |3x-5| - 4 = 12

Solve for x
Show work

Answers

Isolate the absolute-value term:

2 |3x - 5| - 4 = 12

2 |3x - 5| = 8

|3x - 5| = 4


Recall the definition of absolute value:

\(|x| = \begin{cases}x & \text{if }x \ge0\\-x&\text{if }x<0\end{cases}\)

We consider two cases:

• If 3x - 5 ≥ 0, then |3x - 5| = 3x - 5, and the equation resolves to

3x - 5 = 4

3x = 9

x = 3

• Otherwise, if 3x - 5 < 0, then |3x - 5| = -(3x - 5) = -3x + 5, hence

-3x + 5 = 4

-3x = -1

x = 1/3

Is the value used in the denominator of In calculating you typically first need to calculate the t statistic for the independent-measures t test. Suppose you conduct a study using an independent-measures research design, and you intend to use the independent-measures t test to test whether the means of the two independent populations are the same. The following is a table of the information you gather. Fill in any missing values. Sample Size Degrees of Freedom Sample Mean Standard Deviation Sums of Squares Sample 1 n: - 31 M. = 9.8 S1 = 6.1 Sample 2 na = 16 M2 = 9.4 SS2 = 777.6 n The pooled variance for your study is . (Note: You are being asked for this value to three decimal places, because you will need to use it in succeeding calculations. For the most accurate results, retain these three decimal places throughout the calculations.) The estimated standard error of the difference in sample means for your study is The t statistic for your independent-measures t test, when the null hypothesis is that the two population means are the same, is The degrees of freedom for this t statistic is

Answers

a) The pooled variance for your study is 171.38 (rounded to three decimal places).

b) The estimated standard error of the difference in sample means for your study is 1.526 (rounded to three decimal places).

c) The t statistic for your independent-measures t test, when the null hypothesis is that the two population means are the same, is 0.261 (rounded to three decimal places).

d) The degrees of freedom for this t statistic is 45.

a) The pooled variance for your study is calculated using the formula:

pooled variance \(= [(n1 - 1) * S1^2 + (n2 - 1) * S2^2] / (n1 + n2 - 2)\)

Using the given values:

pooled variance = \([(31 - 1) * (6.1^2) + (16 - 1) * (777.6)] / (31 + 16 - 2)\)

pooled variance = 171.38 (rounded to three decimal places)

b) The estimated standard error (SE) of the difference in sample means is calculated using the formula:

\(SE = \sqrt{(s1^2 / n1) + (s2^2 / n2)}\)

Using the given values:

\(SE = \sqrt {(6.1^2 / 31) + (171.38 / 16)}\)

SE = 1.526 (rounded to three decimal places)

c) The t statistic for the independent-measures t test is calculated as:

t = (M1 - M2) / SE

Using the given values:

t = (9.8 - 9.4) / 1.526

t = 0.261 (rounded to three decimal places)

d) The degrees of freedom for this t statistic is 45.

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(a) If sup A < sup B, show that there exists an element b ∈ B that is an upper bound for A.
(b) Give an example to show that this is not always the case if we only assume sup A ≤ sup B.

Answers

(a) We have shown that there exists an element b ∈ B that is an upper bound for A.

(b) The statement in part (a) is not always the case if we only assume sup A ≤ sup B.



(a) If sup A < sup B, show that there exists an element b ∈ B that is an upper bound for A.

Proof:
1. By definition, sup A is the least upper bound for set A, and sup B is the least upper bound for set B.
2. Since sup A < sup B, there must be a value between sup A and sup B.
3. Let's call this value x, where sup A < x < sup B.
4. Now, since x < sup B and sup B is the least upper bound of set B, there must be an element b ∈ B such that b > x (otherwise, x would be the least upper bound for B, which contradicts the definition of sup B).
5. Since x > sup A and b > x, it follows that b > sup A.
6. As sup A is an upper bound for A, it implies that b is also an upper bound for A (b > sup A ≥ every element in A).

Thus, we have shown that there exists an element b ∈ B that is an upper bound for A.

(b) Give an example to show that this is not always the case if we only assume sup A ≤ sup B.

Example:
Let A = {1, 2, 3} and B = {3, 4, 5}.
Here, sup A = 3 and sup B = 5. We can see that sup A ≤ sup B, but there is no element b ∈ B that is an upper bound for A, as the smallest element in B (3) is equal to the largest element in A, but not greater than it.

This example shows that the statement in part (a) is not always the case if we only assume sup A ≤ sup B.

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food determine whether the data are qualitative or quantitative and identify the data​ set's level of measurement.

Answers

To determine whether the data are qualitative or quantitative and identify the data set's level of measurement, you need to consider the type of information being collected.

Qualitative data refers to non-numerical information that describes qualities or characteristics. Examples of qualitative data include colors, textures, or opinions.

Quantitative data, on the other hand, involves numerical information that can be measured or counted. Examples of quantitative data include measurements, counts, or scores.

To identify the level of measurement, you need to determine the scale or precision of the data. There are four levels of measurement: nominal, ordinal, interval, and ratio.

1. Nominal level: Data at the nominal level are categorical and cannot be ranked or ordered. They represent different categories or groups. Examples include colors of fruits or types of animals.

2. Ordinal level: Data at the ordinal level can be ranked or ordered, but the differences between values are not necessarily equal. Examples include rating scales, such as movie ratings or survey responses with options like "strongly agree," "agree," "disagree," and "strongly disagree."

3. Interval level: Data at the interval level have equal intervals between values, but there is no meaningful zero point. Examples include temperature scales like Celsius or Fahrenheit.

4. Ratio level: Data at the ratio level have equal intervals between values and a meaningful zero point. Examples include measurements like height, weight, or time.

By analyzing the nature of the information and the level of measurement, you can determine whether the data set is qualitative or quantitative and identify its level of measurement.

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Which matrix multiplication is possible?
o [o 3]-[1 -4
o
:I::
T:
11:40
30

1
4

Which matrix multiplication is possible?o [o 3]-[1 -4o:I::T:11:403014

Answers

Answer: D

Step-by-step explanation:

dim A=(a,b), dim B=(c,d), in order to multiply, c=b

1) dim A=(1,2) , dim B=(1,2) but 2≠1

2) dim A=(2,1) , dim B=(2,2) but 1≠2

3) dim A=(2,2) , dim B=(1,2) but 2≠1

4) dim A=(2,1) , dim B=(1,2) 1=1: result (2,2)

The price of Stock A at 9 A.M. Was ​$12.39. Since​ then, the price has been increasing at the rate of ​$0.06 each hour. At noon the price of Stock B was ​$12.89. It begins to decrease at the rate of ​$0.12 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

Answers

Answer:

2.78 hours

Step-by-step explanation:

Let the number of hours be represented by x

The price of Stock A at 9 A.M. Was ​$12.39. Since​ then, the price has been increasing at the rate of ​$0.06 each hour.

$12.39 + $0.06 × x

12.39 + 0.06x

At noon the price of Stock B was ​$12.89. It begins to decrease at the rate of ​$0.12 each hour.

$12.89 - $0.12 × x

12.89 - 0.12x

If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

We equate the 2 stocks together

12.39 + 0.06x = 12.89 - 0.12x

Collect like terms.

0.06x + 0.12x = 12.89 - 12.39

= 0.18x = 0.5

x = 0.5/0.18

x =2.77777777778hours

The prices of the two stocks be the​ same in 2.78 hours

Solve for all values of x by factoring.
x^2-x-8=-3x

Answers

Answer:

The roots are {-4, 2}.

Step-by-step explanation:

It seems strange to have x terms on both sides of your equation.  If this is indeed the correct equation, then

x^2-x-8=-3x becomes x^2 +3x - x - 8= 0, and this latter result simplifies to

x^2 + 2x - 8 = 0.  

One set of factors of -8 is {-2, 4} and another is {1, -8).  Hence we could try evaluating this quadratic at x = 4:

4^2 + 2(4) - 8 = 16 (since this is not zero, 4 is not a root and (x - 4) is not a factor.  

Try x = -4 instead:

(-4)^2 + 2(-4) - 8 = 0 simplifies to 16 - 8 - 8 = 0, which is true.

Then x + 4 is a factor and x - 2 is another.  Multiplying these two together as a check results in the given x^2- x - 8 = -3x.

The roots are {-4, 2}.

two variables that move in opposite directions are: a. said to have a positive correlation. b. called independent variables. c. said to have zero correlation. d. said to be inversely related.

Answers

Two variables that move in opposite directions are said to be inversely related.

A negative correlation is a relationship between two variables that move in opposite directions. In other words, when variable A increases, variable B decreases. A negative correlation is also known as an inverse correlation.

The concept of negative correlation is important for investors or analysts who are considering adding new investments to their portfolio. When market uncertainty is high, a common consideration is re-balancing portfolios by replacing some securities that have a positive correlation with those that have a negative correlation.

Here are some common examples of a negatively correlated relationship between assets:

1. Oil prices and airline stocks

2. Gold prices and stock markets (most of the time, but not always)

3. Any type of insurance payoff

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What are objects that are 1 kg

What are objects that are 1 kg

Answers

Answer:

One liter of water.

A Pineapple.

A Bunch of Bananas.

A 1 liter bottle of water

Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value ta/2, (b) find the critical value za/2, or (c) state that neither the normal distribution nor the t distribution applies.


Here are the summary statistics for randomly selected weights of newborn girls: n=180, x=28. 1 hg, s=6. 2 hg. The confidence level is 90%

Answers

The confidence interval then takes the form of x ± margin of error, which in this example is 28 ± 1.9, or (26.1, 29.9). This means that we are 90% confident that the true population mean of newborn girl's weights lies between 26.1 and 29.9 hg. the critical value t0.05/2, which is 1.699.

To construct a confidence interval with a 90% confidence level, we need to find the critical value t0.05/2. This critical value is found by using the t-distribution with a confidence level of 90% (0.90) and degrees of freedom equal to the sample size minus 1 (180 - 1 = 179). We can then use this critical value to calculate the margin of error of the confidence interval, which is equal to the critical value multiplied by the standard error (s/√n). In this example, that results in a margin of error of 1.699*(6.2/√180) = 1.9.

To construct a confidence interval with a 90% confidence level, we need to find the critical value t0.05/2. This critical value is found by using the t-distribution with a confidence level of 90% (0.90) and degrees of freedom equal to the sample size minus 1 (180 - 1 = 179). The t-distribution is used instead of the normal distribution because it is better suited to smaller sample sizes. We can then use this critical value to calculate the margin of error of the confidence interval, which is equal to the critical value multiplied by the standard error (s/√n). In this example, that results in a margin of error of 1.699*(6.2/√180) = 1.9. The confidence interval then takes the form of x ± margin of error, which in this example is 28 ± 1.9, or (26.1, 29.9). This means that we are 90% confident that the true population mean of newborn girl's weights lies between 26.1 and 29.9 hg.

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Type the expression that results from the following series of steps:
Start with 6 and subtract
z

Answers

6-z

Z-6 would be wrong because the question said start with 6

X^2 + _x + 100
Find all possible values for the missing number that make the expression the square of a binomial.

X^2 + _x + 100Find all possible values for the missing number that make the expression the square of

Answers

Answer: The expression X^2 + _x + 100 is the square of a binomial if the missing number is -b/2 and b^2 - 4ac = 0.

Step-by-step explanation: The general form of the square of a binomial is (x + b)^2 = x^2 + 2bx + b^2.

In this case, the missing number is -b/2, and the expression becomes X^2 - x + 100.

Now to find the value of x, we can use the equation b^2 - 4ac = 0

The equation becomes x^2 - 41100 = 0

Which gives x^2 - 400 = 0

So x = ± 20.

So the possible values for the missing number that make the expression the square of a binomial is -20/2 = -10 and 10.

Answer:

To find the missing number in the given expression, we will see the operation used. Step 1: Recall the concept of addition. We need to find the first addend. Step 2: Think of the number which when added to 3 gives the sum equal to 8. Step 3: 5 + 3 = 8. So, the missing number is 5. Step 4: Write the missing number: 5 + 3 = 8.

Step-by-step explanation:

A farm stand sells oranges in three LB for 375 what equation represents the cost of C4P pounds of orange

Answers

Answer:

The cost of  4 pound of oranges is 500 and  equation represents the cost of C4P pounds of orange is \(y=\frac{375}{3} \times 4\)

Step-by-step explanation:

Let the cost of 1 pound oranges be x

Cost of 3 pound oranges = 3x

We are given that Cost of 3 lb oranges = 375

So, 3x=375

So, x =\(\frac{375}{3}\)

So, Cost of 1 pound of oranges = \(\frac{375}{3}\)

Let y be the cost of 4 pound oranges

Cost of 4 pound of oranges y =\(\frac{375}{3} \times 4\)

Cost of 4 pound of oranges y = 500

Hence The cost of  4 pound of oranges is 500 and  equation represents the cost of C4P pounds of orange is \(y=\frac{375}{3} \times 4\)

Using the formula find the slope of a line with these two points (2,10) and (5,15).

Answers

Answer:

Step-by-step explanation:

\(\left(x_{1},y_{1} \right) = (2,10)\\\\(x_{2},y_{2}) = (5 ,15}\\\\\\Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\\=\dfrac{}15-10{5-2}=\dfrac{5}{3}\\\\\\= \dfrac{5}{3}\)

Answer:

slope = \(\frac{5}{3}\)

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (2, 10 ) and (x₂, y₂ ) = (5,  15 )

m = \(\frac{15-10}{5-2}\) = \(\frac{5}{3}\)

40 pts & Brainliest to first Correct. PLZ HELP ASAP

40 pts &amp; Brainliest to first Correct. PLZ HELP ASAP

Answers

Answer: \(16x^4y^2a^6\)

Step-by-step explanation:

just apply to the power of 2 to every term

-4 times -4 is 16

x^2 to power of 2 is 2 times 2 so x^4

y^2 is y^2

a^3 to power of 2 is 3 x 2 = 6 so a^6

16x^4y^2a^6

Answer:

16x^4y^2a^6

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16x^4y^2a^6

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