what is the point of doing an experiment. Help thank you​

The equation  in the question is: H+H → H + H Complete the equation by filling in the missing parts. missing part is  1 → H+H-2 → →3 → He.

The atomic number of hydrogen is 1, which means it has only one proton in the nucleus and one electron in its shell. Two hydrogen atoms react with each other to form helium. Helium has 2 protons and 2 neutrons in its nucleus and two electrons in its shell. Therefore, the equation is:

H + H → HeIt can be seen that:1. H + H (Reactants)

2. → (Yields or Reacts to form)

3. He (Product)Therefore, the tiles will be arranged as shown below: 1 → H+H-2 → →3 → He

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Answer:

B) The family car

Explanation:

I hope this helps :)

The complete Lewis electron-dot diagram for ethyne is shown in the attached diagram below:

A lewis electron dot structure can be utilized to represent the number of bonds, the lone pairs left in the atoms, and the bonding atoms in the molecule.

Solid lines are used to represent the bonds between atoms that are directly bonded to one another and excess electrons are denoted as dot pairs and are represented next to the atoms.

As the valence electrons of each carbon atom are equal to 4 from the electronic configuration of the carbon atom. First, the total number of valence electrons in a molecule is 4 + 1 + 1 + 4 = 10.

As each carbon atom needs only 4 electrons to complete its octet. As the octet completes, the rest of the electrons are assigned as the lone pairs of atoms. But there are no lone pairs in the molecule of the ethyne.

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Answer:

371.2

Explanation:

Answer:

since the modern periodic table is made in ascending order by the atomic number fluorine has the most protons.

The highlighted element that has the greatest number of protons is Iron, Fe. Thus, the correct option for this question is B.

Protons may be defined as a type of subatomic particles which are generally present in the centermost part of an atom known as the nucleus along with neutrons. These subatomic particles are positively charged in nature. Ernest Rutherford was known to discover these particles.

According to the question, the number of protons is generally governed by an atomic number of a chemical element. For example, fluorine has an atomic number of 9. It has the same number of protons in its nucleus. The number of protons in Iron is 26, while the number of protons in Calcium is 20. And the number of protons in aluminum is 13.

Therefore, an iron is the highlighted element that has the greatest number of protons. Thus, the correct option for this question is B.

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Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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Answer:

Chemistry is the science of matter, its properties, structure, changes or reactions and the energy that accompanies these changes.

Answer:

There both true.

Explanation:

Hope this helps

Answer:

The first one is True

The second one is false

Explanation:

Answer:

\(P=3.33atm\)

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

\(n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr\)

Next, we add them up to obtain the total moles:

\(n_T=0.981mol+0.654mol=1.635mol\)

Now, the total volume:

\(V_T=4.00L+8.00L=12.00L\)

Finally, the total pressure is computed by using the ideal gas equation:

\(P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm\)

Best regards!

The equation of the reaction leading to the formation of the precipitate is; \(PbCl_{2}(aq) + Na_{2} SO_{4} (aq) ---- > PbSO_{4}(s) + 2NaCl(aq)\)

We define a precipitate as a compound that can be formed as a solid when we mix two aqueous solutions. An aqueous solution is a solution of a substance that have been dissolved in water.

Thus, when we have a mixture of two liquid reactants and then one of the products does separate itself out of the solution then we say that a precipitate has been formed.

In this case, we are to write down the equation of the reaction between aqueous lead (ii) chloride reacts with aqueous sodium sulfate to produce a lead(ii) sulfate. The solid would separate out of the system and we can see the white color of the lead(ii) sulfate.

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The type of chemical reaction takes place when magnesium metal is added to a solution of iron(ll) sulfate is displacement reaction.

Magnesium sulfate in large doses may be toxic.

A catalyst is a substance that speeds up a chemical reaction, or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.

A universal indicator is a pH indicator made of a solution of several compounds that exhibits several smooth colour changes over a wide range pH values

A displacement reaction is a type of reaction in which part of one reactant is replaced by another reactant. A displacement reaction is also known as a replacement reaction or a metathesis reaction.

Single displacement reactions are reactions where one reactant replaces part of the other:

AB + C → AC + B

An example is the reaction between iron and magnesium sulfate to produce iron sulfate and copper:

Fe + MgSO₄ → FeSO₄ + Mg

Therefore,

The type of chemical reaction takes place when magnesium metal is added to a solution of iron(ll) sulfate is displacement reaction.

Magnesium sulfate in large doses may be toxic.

A catalyst is a substance that speeds up a chemical reaction, or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.

A universal indicator is a pH indicator made of a solution of several compounds that exhibits several smooth colour changes over a wide range pH values

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Answer:

3.54 L

Explanation:

To find the new volume, we'll use this formula: \(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

V₁ = Liters (5.6)

T₁ = Volume in kelvin (273 + 35 = 308)

V₂ = New liters (?)

T₂ = New temperature (273 - 78 = 195)

\(\frac{5.6}{308} = \frac{V_2}{195}\)

First, cross multiply

1092 = V₂308

Divide both sides by 308

1092/308 = V₂308/308

V₂ = 3.54

35.453 amu is the correct answer

Answer:

1. 0.0700M barium hydroxide.

2. HCl + NaOH → H₂O + NaCl

3. 0.0590M HCl

4. H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

5. 0.01967M H₃PO₄

Explanation:

1. Based on the reaction:

Ba(OH)₂(aq) + 2KHC₈H₄O₄(aq) → BaC₈H₄O₄(aq) + K₂C₈H₄O₄(aq) + 2H₂O(l)

To find the molarity we have to convert the KHP to moles. With moles and volume we can find the molarity of the basrium hydroxide as follows:

Moles KHP -Molar mass: 204.22g/mol-

1.190g * (1mol / 204.22g) = 5.827x10⁻³ moles KHP

Moles Ba(OH)₂:

5.827x10⁻³ moles KHP * (1mol Ba(OH)₂ / 2mol KHP) = 2.91x10⁻³ mol Ba(OH)₂

Molarity:

2.91x10⁻³ mol Ba(OH)₂ / 0.04165L =

2. An acid reacts with a base to produce water and the salt. When HCl, reacts with NaOH, the reaction is:

3. The moles of NaOH added are:

34.21mL = 0.03421L * (0.0431mol / L) = 1.474x10⁻³ moles NaOH = Moles HCl

The molarity is:

1.474x10⁻³ moles HCl / 0.02500L =

4. The phosphoric acid, H₃PO₄, reacts with NaOH as follows:

5. The moles of NaOH added are:

34.21mL = 0.03421L * (0.0431mol / L) = 1.474x10⁻³ moles NaOH

The moles of phosphoric acid are:

1.474x10⁻³ moles NaOH * (1mol H₃PO₄ / 3mol NaOH) =

4.91x10⁻⁴ moles H₃PO₄. In 25.00mL = 0.02500L:

4.91x10⁻⁴ moles H₃PO₄ / 0.02500L =

31.7 g of water formation in the given reaction releases 783.02 kJ of heat energy.

The change in heat in the given equation is -890.8 kJ/mol. This means that when one mole of CH4 reacts with 2 moles of O2, it produces one mole of CO2 and 2 moles of H2O while releasing 890.8 kJ of heat energy.Now, we have to find out how much heat energy will be released when 31.7 g of water is formed. To do this, we need to first calculate the number of moles of water formed from 31.7 g of H2O.Molar mass of H2O = 2 × 1.008 + 15.999 = 18.015 g/molNumber of moles of H2O = 31.7 g / 18.015 g/mol = 1.759 molNow we know that 2 moles of H2O are formed when 1 mole of CH4 reacts. Therefore, the number of moles of CH4 required to produce 1.759 mol of H2O will be:1 mole of CH4 : 2 moles of H2Ox moles of CH4 : 1.759 moles of H2Ox = 1.759/2 = 0.8795 molSo, 0.8795 moles of CH4 are required to produce 1.759 moles of H2O. And the heat released during the reaction of 0.8795 mol CH4 can be calculated using the given change in heat.ΔH = -890.8 kJ/molHeat released during the reaction of 0.8795 mol CH4= ΔH × number of moles= -890.8 kJ/mol × 0.8795 mol= -783.02 kJ.

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Answer:

  MCl₂

Explanation:

The formula for boiling point elevation can be used to find x. The "complete dissociation" means there will be an ion of M and x ions of Cl in the solution. The number of moles of solute will be 30.2 grams divided by the molecular weight of MClx, where x is the variable we're trying to find.

  \(\Delta T=imK_b\qquad\text{where i=ions/mole, m=molality, $K_b\approx 0.512$}\\\\376.81-373.15=(x+1)\dfrac{\text{moles}}{\text{kg solvent}}(0.512)\\\\\dfrac{3.66}{0.512}=(x+1)\dfrac{\dfrac{30.2}{56+35.45x}}{0.1}=\dfrac{302(x+1)}{56+35.45x}\\\\\dfrac{3.66}{0.512\cdot 302}(56+35.45x)=x+1\\\\\dfrac{3.66\cdot 56}{0.512\cdot 302}-1=x\left(1-\dfrac{3.66\cdot 35.45}{0.512\cdot 302}\right)\\\\x=\dfrac{50.336}{24.877}\approx 2.023\)

Then the formula for the salt is MCl₂.

The balanced equation of the reaction is:C5H12 + 8O2 → 5CO2 + 6H2OFrom the equation, it shows that 8 moles of oxygen is needed to burn 1 mole of pentane. The volume of oxygen needed for the entire burning process of 18 grams of pentane in normal conditions is 44.86 L.

First, let's convert 18 grams of pentane to moles using the molar mass of pentane (C5H12) as follows:Mass of pentane = 18 g Molar mass of pentane (C5H12) = 5(12) + 12(1) = 72 g/molNumber of moles of pentane = Mass/Molar mass = 18/72 = 0.25 moles

Now, to find the volume of oxygen needed for its entire burning process in normal conditions, we'll use the Ideal Gas Law equation as follows: n = PV/RT where :n = number of moles of the gas V = volume of the gas (in liters)P = pressure of the gas (in atmospheres)R = Universal Gas Constant = 0.0821 L· atm /K· molT = temperature of the gas (in Kelvin)From the equation, we know that 8 moles of oxygen are needed to burn 1 mole of pentane.

Therefore, the number of moles of oxygen needed to burn 0.25 moles of pentane will be: n = 8 × 0.25 = 2 moles The temperature and pressure are normal conditions, which is 0°C and 1 atm respectively. Let's convert the temperature to Kelvin:T = 0 + 273 = 273 K Substituting the values into the Ideal Gas Law equation gives: P × V = nRT Rearranging the equation gives: V = nRT/P  Substituting the values, we get: V = 2 × 0.0821 × 273/1V = 44.86 L

Therefore, the volume of oxygen needed for the entire burning process of 18 grams of pentane in normal conditions is 44.86 L.

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Answer:

The Correct answer is B

activation energy of the reaction

or

speeds up the reaction

Answer:

Explanation:

From the information above:

The equation for the reactor volume of CSTR is given by the formula:

\(V = \dfrac{C_{Ao}V_o - C_A V_o }{-rA}\)

\(V = \dfrac{C_{Ao}V_o (1 - 0.01)}{KC_A^2}\)

The reaction rate of A is:

\(-r_A = kC_A^2\) and k = 3 dm³/mol.h

replacing the values in the above equation to solve for v;

∴

\(V = \dfrac{(0.5 \ mol/dm^3) (10 \ dm^3/h) (1 - 0.01)}{ ( 3 \ dm^3/mol.h) (0.01 \times 0.5 \ mol/dm^3)^2}\)

V = 66,000 dm³

Thus, the reactor volume of CSTR is 66000 dm³

Taking the differential mole balance equation for PFR is as follows:

\(\dfrac{d(C_AV_o)}{dV} = -r_A\)

\(\dfrac{d(C_AV_o)}{dV} = Kc^2A\)

Taking the integral between initial and final concentrations;

\(\dfrac{v_o}{k} \int ^{C_A}_{C_{Ao}} \dfrac{dC_A}{C^2A}= - \int ^V_o \ dV\)

\(V = \dfrac{V_o}{K} \Big [\dfrac{1}{C_A}- \dfrac{1}{C_{Ao}} \Big ]\)

replace the values in the above equation;

\(V= \dfrac{(10 \ dm^3/h) }{(3 \ dm^3/mol.h)}\Big [ \dfrac{1}{0.01(0.5 \ mol/dm^3)} - \dfrac{1}{0.5 \ mol/dm^3} \Big ]\)

\(\mathbf{V = 66 0 \ dm^3}\)

Thus, the reactor volume of PFR is 660 dm³

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 \(\frac{J}{gC}\)× m× (100 °C -34 °C)

92.048 kJ = 4.186 \(\frac{J}{gC}\)× m× 66 °C

m= 92.048 kJ ÷ (4.186 \(\frac{J}{gC}\)× 66 °C)

m= 0.333 grams

Being the molar mass of water 18 \(\frac{g}{mole}\), that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as:

\(amount of moles=0.333 gramsx\frac{1 mole}{18 grams}\)

amount of moles= 0.0185 moles

Finally, 0.0185 moles of water are required.

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Answer:

d

Explanation:

yes

Answer:

a substance that tends to bring about reduction by being oxidized and losing electrons.

Answer:

a substance that reduces a chemical compound usually by donating electrons.

Answer:

Explanation:

Let the products in the outlet streams be P(i.e. CH₃OH), Q(i.e. C₂H₅OH) and R(i.e. C₃H₇OH) respectively

Then the mass balance for CO, H and C₂H₅OH can be computed as follows:

For CO, The mass balance is;

100 - P - 3Q - 5R = 30    --- (1)

For H₂, The mass balance is;

100 - 2P - 3Q - 4R = 30    --- (2)

For C₂H₅OH, The mass balance is;

Q = 5    --- (3)

Replacing the value of equation(3) into equation (1) and (2); we have:

From equation (1):

100 - P - 3(5) - 5R = 30    --- (1)

100 - 15 - P - 5R = 30

85 - P - 5R = 30

85 - 30  = P + 5R

P + 5R = 55    ----- (4)

From equation (2):

100 - 2P - 3Q - 4R = 30    --- (2)

100 - 2P - 3(5) - 4R = 30

100 - 15 - 30 = 2P +4R

55 = 2P + 4R

2P + 4R = 55     ----- (5)

From equation (4) and (5); we have:

P + 5R = 55    ----- (4)

2P + 4R = 55     ----- (5)

From equation (4);

Let P = 55 - 5R

Then, replace P = 55 - 5R in equation (5)

2(55 - 5R) + 4R = 55  

110 - 10R + 4R = 55

110 - 6R = 55

6R = 110 - 55

6R = 55

R = 55/6

R = 9.17

Substitute, the value of R in equation (5); we have:

2P + 4R = 55

2P + 4(9.17) = 55

2P  = 55 - 4(9.17)

2P  = 55 - 36.68

2P  =  18.32

P = 18.32/2

P = 9.16

Therefore, the outlet stream rates are as follows:

                  Mass Feed Rate   ( mol/hr)               Molar ratio

CO                  30                                                    0.281

H₂                    30                                                   0.281              

CH₃OH            9.16                                                0.085

C₂H₅OH            5                                                   0.047

C₃H₇OH           9.17                                                0.086

CO₂                 23.34                                              0.219

Total:                106.67

The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.

Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.

The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is determined as;

2S₈ + 16O₂ → 16SO₃

From the reactants side we can see that sulfur is 16 and also 16 in the product side. The number of oxygen in the reactant side is 32 and also 32 in the product side.

Thus, the balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.

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