what is the percent yield when a reaction vessel that initially contains 65.5 kg ch4 and excess steam yields 15.0 kg h2?
Answers
The percent yield when a reaction vessel that initially contains 65.5 kg ch4 and excess steam yields 15.0 kg h2 is 45%.
Percent yield is a calculation that compares how an awful lot product we surely produce with how an awful lot product that we calculate that we need to produce. In each response in a actual lab, we can usually produce a piece much less product than we calculate. The kw required is calculated by the calculation of power needed.
Percent yield measures how near we will get.The percentage yield is 45 %.
CaCO₃ →CaO + CO₂
First, calculate the theoretical yield of CaO.
Theor. yield = 60 g CaCO3×1 mol CaCO3100.zero g CaCO3×1 mol CaO1 mol CaCO3×56.08 g CaO1 mol CaO=33.6 g CaO
Now calculate the percentage yield.
% yield = real yieldtheoretical yield×100%=15 g33.6 g×100%=45%.
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Related Questions
Which gas would occupy more volume at a constant temperature and pressure, 1.5 g of n2 gas or 1.5 g of o2 gas?
Answers
The 1.5 g of \(N_{2}\) would occupy more volume at a constant temperature and pressure .
Calculation ,
So, to find volume occupy by the 1.5 g of nitrogen gas or 1.5 g of oxygen gas we have to calculate number of moles of each first .
Number of moles of nitrogen gas = given mass/molar mass = 1.5 g/14 g/mol
Number of moles of nitrogen = 0.107 mole
Number of moles of oxygen gas = given mass/molar mass = 1.5 g/16 g/mol
Number of moles of oxygen gas = 0.093 mole
According to ideal gas equation,
PV = nRT
Where , P is pressure of the gas
V is volume of the gas
n is number of moles of the gas
R is gas constant of the gas
T is temperature of the gas
According to ideal gas equation, at constant temperature and pressure the volume is directly proportional to the number of moles of the gas .
So , number of moles of nitrogen is greater than oxygen .
Therefore , nitrogen gas would occupy more volume at a constant temperature and pressure.
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Use the following steps to balance the redox reaction using half-reactions. Zn(s) + Fe3+ Zn2+ + Fe(s) (unbalanced) a. Write balanced oxidation and reduction half-reactions. Indicate which is the oxidation reaction and which is the reduction reaction. (6 points) b. Balance the charge in the two half-reactions by multiplying the half-reactions by the correct multiplication factors. (4 points) c. Add the equations and simplify to get the balanced equation.
Answers
Answer:
Explanation:
a )
Zn = Zn²⁺ + 2e ( oxidation reaction )
Fe³⁺ + 3e = Fe( s ) ( reduction reaction )
b )
[ Zn = Zn²⁺ + 2e ] x 3
[ Fe³⁺ + 3e = Fe( s ) ] x 2
-------------------------------------------------------------------
3 Zn + 2 Fe³⁺ + 6e = 3 Zn²⁺ + 2 Fe ( s ) + 6e
3 Zn + 2 Fe³⁺ = 3 Zn²⁺ + 2 Fe ( s )
How many molecules are in 1.3 moles of water?
Answers
Answer:
7.8286e+23
Explanation:
Use Avogadro's number
list of five compound and properties
Answers
Answer:
Compounds :
Water,acid,chloride,hydroxide, and sulfate
Properties :
Density, color, mass, volume, length, malleability, melting point, hardness, odor, and temperature
Explanation:
Hope this helps!!! :))
PLS HELP!!
Which of these processes are catabolic reactions? Check all that apply.
conversion of glycogen to glucose
conversion of glucose to stored lipid
bone growth
reduction reactions
breakdown of ATP to form ADP
Answers
Answer:
It's A) and E)
Explanation:
Did the assignment
Answer:
A. conversion of glycogen to glucose and
E. breakdown of ATP to form ADP
Explanation: I also did the assignment.
How many oxygen atoms are there in 3 molecules of CH3FO?
Answers
Answer: There should be 3.
Explanation:
as the temperature of a gas decreases is volume
Answers
Answer:
it's volume also decrease
would dissolving sugar in water be a physical or chemical change
Answers
Answer:
Physical!!!!!
Good Luck!
what does removing energy from water at 25c do to the temp of the water?
Answers
Removing energy from water at 25 °C the temp of the water will decreases.
When we remove the heat from water the temperature of water will falls and water will cool down. The water is cool; down when we remove the heat from it and the kinetic energy decreases of the particles. once the temperature recaches to the freezing point then there will be no further change in temperature. This is the phase transition from liquid to solid. By the removal of heat will cause the particle of water to locking up into place.
Thus, Removing energy from water at 25 °C the temp of the water will decreases.
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Which physical property of aluminum allows it to be formed into thin sheets?
O A. Electrical conductivity
O B. Thermal conductivity
O C. Malleability
O D. Density
Answers
Answer:
C. Malleability
Explanation:
The malleability of aluminum allows it to be formed into thin sheets.
Physical properties tells us about what a substance is when no change is occurring to its constituents.
Aluminum like some other metals can be drawn into sheets. This is due to the metallic bonds joining atoms of metals and alloys together. The physical properties of metals are due to metallic bonds. The metallic bond is actually the attraction between the positive nuclei of all closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by losing their outermost shell electrons.Answer:
C
Explanation:
Starting is one operational condition that a carburetor must be able to supply the proper fuel mixture for. What are the other four?
Answers
Starting is one operational condition that a carburetor must be able to supply the proper fuel mixture for. The other four are Idle, , Accelerator, variable load and speed operation.
Carburetor is the device that is used to mix fuel and air in an internal combustion engine. Its main objective is to provide quality air fuel for special operational requirements such as starting, idling, acceleration, adjusting variable load and speed operation.
The main disadvantage of float-type carburetor is its susceptibility to icing which occurs when there is fuel vaporization and decrease in air pressure in the venturi, which causes a sharp temperature drop in the carburetor. This fuel vaporization occurs within the cylinder of a fuel-injected engine and makes fuel injection system less susceptible to icing.
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what is the atomic number of an element based on
Answers
Answer:
The atomic number is the number of protons in the nucleus of an atom . The number of protons define the identity of an element
1 Mg (s) + 2 HCl (aq) --> 1 MgCl2 + 1 H2 If 2.50 mol of hydrochloric acid is reacted, how many moles of magnesium chloride is produced?
Answers
Answer:
1.25 moles of magnesium chloride are produced
Explanation:
Based on the reaction:
Mg(s) + 2HCl (aq) → MgCl₂(s) + H₂(g)
1 mole of magnesium, Mg, reacts with 2 moles of hydrochloric acid, HCl, to produce 1 mole of magnesium chloride, MgCl₂ and 1 mole of hydrogen gas.
To solve this question we have to tak, from the chemical equation:
2 mol HCl = 1mol MgCl₂
That means, the moles of MgCl₂ produced from 2.50mol HCl are:
2.50 mol HCl * (1mol MgCl₂ / 2mol HCl) =
1.25 moles of magnesium chloride are producedhydrogen is a diatomic molecule, h2. the bond holding the hydrogen atoms together is
Answers
The bond holding the two hydrogen atoms together in a hydrogen molecule (H2) is a covalent bond.
Specifically, it is a type of covalent bond called a "single covalent bond" because each hydrogen atom shares one electron with the other, forming a stable H2 molecule.
1. Molecular Formula: The molecular formula of hydrogen gas is H2, indicating that it consists of two hydrogen atoms bonded together.
2. Diatomic Nature: Hydrogen is a diatomic molecule, meaning it naturally occurs as a pair of atoms chemically bonded together. In its pure elemental form, hydrogen exists predominantly as H2.
3. Bonding: The bond between the two hydrogen atoms in H2 is a covalent bond. Covalent bonds involve the sharing of electrons between atoms, allowing them to achieve a more stable electron configuration. In the case of hydrogen, the two atoms share a pair of electrons, resulting in the formation of a single covalent bond.
4. Stability: The formation of H2 molecules through covalent bonding provides stability to hydrogen atoms. By sharing electrons, the two hydrogen atoms achieve a filled outer electron shell, resembling the stable electron configuration of helium. This shared electron pair holds the atoms together in a stable H2 molecule.
5. Physical Properties: Hydrogen gas is a colorless, odorless, and highly flammable gas. It is the lightest and simplest element, with a low boiling point and melting point. Hydrogen has a low density, and at standard temperature and pressure, it exists as a diatomic gas (H2).
6. Abundance: Hydrogen is the most abundant element in the universe. However, on Earth, it is typically found in compounds such as water (H2O) or hydrocarbons, rather than in its pure diatomic form.
7. Various Applications: Hydrogen gas has several important applications, including its use as a fuel in fuel cells and hydrogen-powered vehicles. It is also used in various industrial processes, such as ammonia production and hydrogenation reactions in the chemical industry. Hydrogen gas is even utilized in the production of certain metals and as a reducing agent in various chemical reactions.
These are some key points regarding hydrogen as a diatomic molecule. If you have any more specific questions or need further information, feel free to ask!
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This is the process that cells reproduce and replace old or damaged cells.
Question 5 options:
Mitosis
Meiosis
Ribosomes
Cytokinesis
Answers
Didnndxbdbdn
1) For the precipitation reaction of calcium oxalate below, the Ks = 3.7x10 Note: For this question, do not apply the small x approximation. A) If excess calcium oxalate were added to 100.0 mL of pure water, what concentration of calcium ions and oxalate ions would be expected when the solution is saturated? B) If 1.00 mg of calcium chloride were then added to the mixture (assume no solution volume change and complete dissolution and dissociation of CaCl2), what would be the expected concentrations of calcium ions and oxalate ions once equilibrium is reestablished? Ca2+(aq) + C2042(aq) ⇄ CaC204(s)
Answers
A) In precipitation reaction when the solution is saturated, the expected concentration of both calcium ions and oxalate ions would be approximately 0.0192 mol/L.
B) After equilibrium is reestablished, the expected concentrations of calcium ions and oxalate ions are approximately 2.498 × 10⁻⁴ mol/L and 0.0192 mol/L, respectively.
To answer the given questions about the precipitation reaction of calcium oxalate, let's break it down into two parts:
A) The concentration of calcium ions and oxalate ions in the saturated solution can be determined when an excess amount of calcium oxalate is added to 100.0 mL of pure water.
Since excess calcium oxalate is added, it means that the solution will contain more calcium oxalate than what can dissolve. At saturation, the solution is in equilibrium with the solid calcium oxalate.
Let's assume the concentration of calcium ions and oxalate ions in the saturated solution is represented by "x" (in mol/L).
The equilibrium expression for the reaction is:
Ks = [Ca²⁺][C₂O₄²⁻]
Given that the equilibrium constant Ks = 3.7 × 10⁻⁴, we can set up the equation:
3.7 × 10⁻⁴ = x * x
Solving for "x," we find:
x = √(3.7 × 10⁻⁴) ≈ 0.0192 mol/L
Therefore, when the solution is saturated, the expected concentration of both calcium ions and oxalate ions would be approximately 0.0192 mol/L.
B) If 1.00 mg of calcium chloride (CaCl2) were added to the mixture, what would be the expected concentrations of calcium ions and oxalate ions once equilibrium is reestablished?
Since calcium chloride (CaCl₂) dissociates completely into calcium ions (Ca²⁺) and chloride ions (Cl⁻) in solution, the addition of 1.00 mg of CaCl₂ will result in the addition of 1.00 mg of calcium ions.
First, we need to convert the mass of calcium ions from mg to mol:
1.00 mg = 0.001 g
0.001 g / (molar mass of Ca²⁺) = 0.001 g / 40.08 g/mol ≈ 2.498 × 10⁻⁵ mol
Since the solution volume is assumed to be unchanged, the concentrations of calcium ions and oxalate ions will change but not the molar amounts.
The concentration of calcium ions is the molar amount (2.498 × 10^(-5) mol) divided by the total solution volume (100.0 mL or 0.100 L):
Concentration of calcium ions = (2.498 × 10⁻⁵ mol) / 0.100 L ≈ 2.498 × 10⁻⁴ mol/L
The concentration of oxalate ions remains the same as in part A since the addition of calcium chloride does not affect the concentration of oxalate ions.
Therefore, after equilibrium is reestablished, the expected concentrations of calcium ions and oxalate ions are approximately 2.498 × 10⁻⁴ mol/L and 0.0192 mol/L, respectively.
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For the oxidation-reduction reaction equation given here,4Al + 3O2 --> 2Al2O3indicate how many electrons are transferred in the formation of 1 formula unit of product.
Answers
Answer:
In the formation of 1 formula unit of Al2O3 in the reaction 4Al + 3O2 → 2Al2O3, a total of 12 electrons are transferred, with each aluminum atom gaining 3 electrons through oxidation and each oxygen molecule gaining 4 electrons through reduction.
Explanation:
In the oxidation-reduction reaction equation: 4Al + 3O2 → 2Al2O3, the reaction involves the oxidation of aluminum (Al) and the reduction of oxygen (O2). The formation of 1 formula unit of the product Al2O3 involves the transfer of a specific number of electrons.
To determine the number of electrons transferred, we need to look at the change in oxidation states of the elements involved. In this case, aluminum (Al) is oxidized from an oxidation state of 0 to +3, while oxygen (O) is reduced from an oxidation state of 0 to -2.
Each aluminum atom gains three electrons during the oxidation process, as its oxidation state increases from 0 to +3. Considering that there are four aluminum atoms in the reaction, a total of 4 × 3 = 12 electrons are transferred due to the oxidation of aluminum.
On the other hand, each oxygen molecule (O2) gains four electrons during the reduction process, as its oxidation state decreases from 0 to -2. Since there are three oxygen molecules in the reaction, a total of 3 × 4 = 12 electrons are transferred due to the reduction of oxygen.
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A 22 g sample of water is heated until it reaches a temperature of 73 °C. This sample
is placed in a calorimeter that contains 23 mL of H20 at 41 °C (use dH20 = 1.0 g/mL).
If the Cs of water is 4.18 J/g°C what is the final temperature of the water? (assume
that all the heat of the hot water goes into heating up the cold water until the two are
at thermal equilibrium and no heat is lost to the environment)
Answers
Answer:
56.64°c
Explanation:
its obtained from facts that heat gained by water=heat lost by calorimeter
Select the statement that explains why the trend in atomic radii for main-group elements is not observed in transition elements.
As protons are added to the nuclei of the transition elements when moving from left to right across a period, electrons are added to the (−1)(n−1)d subshell. The number of electrons in the outermost shell (n) remain constant. This results in a roughly constant effective nuclear charge.
As protons are added to the nuclei of the transition elements when moving from left to right across a period, electrons are added to the outermost energy level (n). This results in a decrease in the effective nuclear charge experienced by the outermost electrons, resulting in a weaker force of attraction between the nucleus and electrons.
As protons are added to the nuclei of the transition elements when moving from left to right across a period, electrons are added to the (−1)(n−1)d subshell. The number of electrons in the outermost shell (n) remain constant. This results in a decrease in the effective nuclear charge.
As protons are added to the nuclei of the transition elements when moving from left to right across a period, electrons are added to the (−1)(n−1)d subshell. The number of electrons in the outermost shell (n) remain constant. This results in an increase in the effective nuclear charge.
As protons are added to the nuclei of the transition elements when moving from left to right across a period, electrons are added to the outermost energy level (n). This results in an increase in the effective nuclear charge experienced by the outermost electrons, resulting in a stronger force of attraction between the nucleus and electrons.
Answers
The correct explanation for why there is no trend in atomic radii across a period for transition elements is:
As protons are added to the nuclei of the transition elements when moving from left to right across a period, electrons are added to the (−1)(n−1)d subshell. The number of electrons in the outermost shell (n) remain constant. This results in a roughly constant effective nuclear charge.
The key reason is that the number of electrons in the outermost shell remains constant. Therefore, as more protons are added to the nucleus, the effective nuclear charge experienced by the outermost electrons also remains roughly constant. This results in relatively similar atomic radii across the period.
The other options are incorrect:
Options 2 and 5: The effective nuclear charge decreases/increases, which is contrary to the constant charge in transition elements.
Options 3 and 4: The effective nuclear charge decreases/increases, which does not explain the constant radii. The charge should remain roughly constant.
So in summary, the constant number of outermost electrons and effective nuclear charge across a period explains the lack of any trend in atomic radii for transition elements.
The trend in atomic radii for main-group elements is not observed in transition elements because the electrons are added to the (−1)(n−1)d subshell instead of the outermost shell.
The trend in atomic radii for main-group elements is based on the number of electrons in the outermost energy level (n), which determines the size of the atom. However, in transition elements, the electrons are added to the (−1)(n−1)d subshell as protons are added to the nuclei when moving from left to right across a period.
This means that the number of electrons in the outermost shell (n) remains constant, resulting in a roughly constant effective nuclear charge and no significant change in atomic radii. Therefore, the trend in atomic radii for main-group elements is not observed in transition elements due to the unique electronic configurations and properties of the (−1)(n−1)d subshell.
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What do we call the stars whose properties follow the patterns?
Answers
Answer:
It is called Asterism.
Explanation:
It is Asterism because Asterism refers to a pattern of stars that are seen in night sky and are very distinctive and identifiable. These group of starts have patterns. It visually seen collection of stars and it's indicate their properties and the lines that connect the stars together. It actually range from small shapes of stars to more complex stars that cover segment of the sky. The stars may be bright naked or have similar brightness.
When turgor pressure is high enough in a cell, the cell walls become _____
Answers
Answer:
the answer is "Firm".
Explanation:
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2. How many atoms of zinc are present in 0.48 mol of zinc?
(show solution)
Answers
Answer:
2.89 × 10²³ atoms of zincExplanation:
The number of atoms of zinc can be found by using the formula
N = n × Lwhere n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.48 × 6.02 × 10²³
We have the final answer as
2.89 × 10²³ atoms of zincHope this helps you
Answer:
2.89× 10²³ atom
Explanation:
Given data:
Number of atoms of Zn = ?
Number of moles of Zn = 0.48 mol
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole = 6.022 × 10²³ atom
0.48 mol × 6.022 × 10²³ atom / 1mol
2.89× 10²³ atom
the specific heat of hydrogen gas is 102 times larger than the specific heat of liquid mercury. the specific heat of hydrogen gas is 12 times larger than the specific heat of elemental sodium. we have equal masses of hydrogen gas, liquid mercury, and elemental sodium that have the same initial temperature. the same amount of heat is added to all three substances. which substance ends up the hottest?
Answers
Hydrogen gas will become the hottest when the same amount of heat is applied to all three substances with the same starting temperature and equal masses.
The specific heat of a substance is the amount of heat required to raise the temperature of one unit of mass of that substance by one degree Celsius. The higher the specific heat, the more heat energy is required to raise the temperature of the substance.
Given that the specific heat of hydrogen gas is 102 times larger than the specific heat of liquid mercury and 12 times larger than the specific heat of elemental sodium, we can conclude that hydrogen gas requires the most heat energy to raise its temperature by the same amount compared to mercury and sodium.
Therefore, when the same amount of heat is added to all three substances with the same initial temperature and equal masses, hydrogen gas will end up the hottest because it requires more heat energy to increase its temperature by the same amount compared to mercury and sodium. In other words, the heat added to hydrogen gas will result in a greater temperature increase than the same amount of heat added to mercury or sodium.
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What does the oxidation number for elements of first transition series range between ?
Answers
The range of the of the oxidation number of the first transition series is +2 to +6.
What is transition metal?
Transition elements or transition metals are elements or metals that have partially filled d orbitals.
Examples of first transition metalsThe first main transition series begins with either;
scandium (Sc, atomic number 21)titanium (Ti, atomic number 22) chromium (Cr, atomic number 24) and ends with zinc (Zn, atomic number 30)Range of oxidation number of transition metalsscandium - oxidation number = +3titanium - oxidation number = +2, +3, and +4Chromium - oxidation number = + 6zinc - oxidation number = +2Thus, the range of the of the oxidation number of the first transition series is +2 to +6.
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Consider a two step synthetic sequence to generate the chiral cyclopropane. provide the alkyne starting material a, intermediate organic product b, and identify the reagents.
Answers
The formed cyclopropane has cis stereochemistry.
Chiral cyclopropane rings are important pharmacophores in pharmaceutical drugs and bioactive natural products, so libraries of these building blocks are an important resource for drug research and development campaigns.
A synthesis is a set of two or even more reactions that are designed to produce a specific end product. A synthetic step is a single reaction that has to be carried out independently of the other reactions in a synthesis.
The number of steps inside a synthetic sequence equals the number of reactions that need to be performed separately, i.e. the number of reactions that comprise the sequence.
By stereospecific addi-tion of singlet carbenes, cis cyclopropane could be synthesized from cis alkene. Using a Lindlar catalyst, cis alkene could be synthesized from alkynes.
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Propane is a gas used for cooking and heating. How many atoms are in 2.12 mol of propane (C₂H₂) Hint: 1 molecule C,H, 11 atoms (3 C and 8 H)
Answers
Answer:
Explanation:
First, let's determine the formula for propane. Propane has 3 carbon atoms and 8 hydrogen atoms.
CH₃CH₂CH₃
Second, use the number of moles of propane given in the problem (2.12 moles) and the formula for propane.
2.12 mol CH₃CH₂CH₃
Third, take 2.12 times the number of carbon atoms and the number of hydrogen atoms in propane.
There are 3 carbon atoms and 8 hydrogen atoms in propane.
2.12 x 3 carbon atoms = 6.36 carbon atoms
2.12 x 8 hydrogen atoms = 16.96 hydrogen atoms
A gas at STP has a volume of 1.00 L. If the pressure is doubled and the temperature remains constant, what is the news of the gas?
Answers
Answer: PV = nRT
A gas at STP... This means that the temperature is 0°C and pressure is 1 atm.
R is the gas constant which is 0.08206 L*atm/(K*mol)
Rearranging for volume
V = nRT/P
The temperature and number of moles are held constant. This means that this uses Boyle's Law. (The ideal gas law could be manipulated to give us this result when T and n are held constant.)
PV = k
where k is a constant.
This means that
P₁V₁ = k = P₂V₂
P₁V₁ = P₂V₂
(1 atm) * (1 L) = (2 atm) * V₂
V₂ = 0.5 L
The new volume of the gas is 0.5 L.
Explanation:
1.33 dm3 of water at 70°C are saturated by 2.25
moles of lead(II) trioxonitrate(V), Pb(NO3)2, and
1.33 dm3 of water at 18°C are saturated by 0.53
mole of the same salt\If 4.50 dm3 of the saturated
solution are cooled from 70°C to 18°C, calculate
the amount of solute that will be deposited in
(a) moles,
(Pb = 207, N = 14,0 = 16)
(b) grams.
Answers
Given that 4.50 dm³ of Pb(NO₃)₂ is cooled from 70 °C to 18 °C, the
amount amount of solute that will be deposited is 1,927.413 grams.
How can the amount of solute deposited be found?
The volume of water 1.33 dm³ of water 70 °C.
The number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water at 70 °C = 2.25 moles
At 18 °C, the number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water = 0.53 moles
Therefore;
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C is therefore;
1.33 dm³ contains 2.25 moles.
\(Number \ of \ moles \ in \ 4.50 \ dm^3 = \dfrac{2.25}{1.33} \times 4.50 \approx \mathbf{7.613 \, moles}\)
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C ≈ 7.613 moles
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C is therefore;
1.33 dm³ contains 0.53 moles
\(Number \ of \ moles \ in \ 4.50 \ dm^3 = \dfrac{0.53}{1.33} \times 4.50 \approx \mathbf{1.79 \, moles}\)
Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C ≈ 1.79 moles
The number of moles that precipitate out = The amount of solute deposited
Which gives;
Amount of solute deposited = 7.613 moles - 1.79 moles = 5.823 moles
The molar mass of Pb(NO₃)₂ = 207 g + 2 × (14 g + 3 × 16 g) = 331 g
The molar mass of Pb(NO₃)₂ = 331 g/mol
The amount of solute deposited = Number of moles × Molar mass
Which gives;
The amount of solute deposited = 5.823 moles × 331 g/mol = 1,927.413 g
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How is the bond between carbon and hydrogen in methane DIFFERENT from the bond
between potassium and hydrogen in potassium hydride?
Answers
Answer:
How is the bond between carbon and hydrogen in methane DIFFERENT from the bond
Explanation:
Which is a product of photosynthesis and a reactant of cellular respiration?
Multiple choice question.
carbon dioxide
water
glucose
Answers
B) Carbon Dioxide
Cellular respiration is the process by which plant and animal cells break down sugars, convert them to energy, and then use them to do work at the cellular level. The purpose of cellular respiration is simple. It provides cells with the amount of energy they need to function. It would be absolutely useless if a living being could not obtain the necessary energy from food. All living things eventually die, regardless of the quality or quantity of food.
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Carbon dioxide: a colourless, odourless gas produced by burning carbon and organic compounds and by respiration. It is naturally present in air (about 0.03 per cent) and is absorbed by plants in photosynthesis.