what is the partial pressure of neon that's 18% by volume in a gas mixture with a total pressure of 310 kpa?

Answers

Answer 1

The partial pressure of neon that's 18% by volume in a gas mixture with a total pressure of 310 kpa is 55.8 kpa.

given that :

total pressure = 310 kpa

volume % = 18 % = 0.18

the Dalton's law of partial pressure is given as follows :

Partial pressure = mole fraction × P total

the moles of the gas is directly proportional to the volume of the gas. thus, the mole fraction equal to the volume percent.

Partial pressure = V percent × P total

partial pressure = 0.18 × 310 kpa

                          = 55.8 kpa.

the partial pressure of the neon is 55.8 kpa.

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Related Questions

How


many moles of Strontium Phosphate are in 55. 50 grams of Strontium Phosphate :


Sr3(PO4)2?

Answers

There are approximately 0.1229 moles of strontium phosphate in 55.50 grams of the compound.

To determine the number of moles of strontium phosphate \((Sr_3(PO_4)_2)\) in 55.50 grams, we need to use the concept of molar mass and Avogadro's number.  First, we calculate the molar mass of strontium phosphate by summing up the atomic masses of each element present in the compound. Strontium (Sr) has an atomic mass of approximately 87.62 grams/mol, phosphorus (P) has an atomic mass of approximately 30.97 grams/mol, and oxygen (O) has an atomic mass of approximately 16.00 grams/mol.  So, the molar mass of strontium phosphate is:

3(Sr) + 2(\((PO_4)\)) = 3(87.62) + 2(30.97 + 4(16.00)) = 261.86 + 2(30.97 + 64.00) = 261.86 + 2(94.97) = 261.86 + 189.94 = 451.80 grams/mol

Next, we use the formula:

moles = mass / molar mass

Plugging in the given mass of 55.50 grams and the molar mass of 451.80 grams/mol:

moles = 55.50 g / 451.80 g/mol ≈ 0.1229 mol

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what is the mass of iron

Answers

Atomic mass: 55.845

^ Atomic Mass of the element Iron

~theLocoCoco

The Henry's Law constant of methyl bromide, CH3Br, is k = 0.159 mol/(L atm) at 25C. What is the solubility of methyl bromide in water at 25C and at a partial pressure of 300. mm Hg? Choose one answer. a. 0.0628 mol/L b. 0.395 mol/L c. 0.403 mol/L d. 47.7 mol/L

Answers

The solubility of methyl bromide in water at 25°C and a partial pressure of 300 mm Hg can be calculated using Henry's Law. The Henry's Law constant for methyl bromide is given as 0.159 mol/(L atm) at 25°C. By applying the equation for Henry's Law, the solubility of methyl bromide in water can be determined.

Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. The equation for Henry's Law is written as:

S = k * P

Where S is the solubility of the gas in the liquid, k is the Henry's Law constant, and P is the partial pressure of the gas. In this case, we are given the Henry's Law constant for methyl bromide as 0.159 mol/(L atm) at 25°C. The partial pressure of methyl bromide is given as 300 mm Hg.

Substituting the values into the equation, we have:

S = 0.159 mol/(L atm) * (300 mm Hg)

To convert mm Hg to atm, we divide by the conversion factor of 760 mm Hg/atm:

S = 0.159 mol/(L atm) * (300 mm Hg / 760 mm Hg/atm)

Simplifying the equation, we find:

S ≈ 0.0628 mol/L

Therefore, the solubility of methyl bromide in water at 25°C and a partial pressure of 300 mm Hg is approximately 0.0628 mol/L.

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PLEASE HELP!!!!!!!! I DO NOT UNDERSTAND

PLEASE HELP!!!!!!!! I DO NOT UNDERSTAND

Answers

Answer:

A, B, C

Explanation:

Answer:A, b, c

Explanation

how many grams of sucrose (c12h22o11) contain 4.060×1024molecules of sucrose?

Answers

To find the grams of sucrose containing 4.06 × 10²⁴ molecules, you can use the following steps:

1. Calculate the molecular weight of sucrose (C12H22O11):
  Molecular weight = (12 × 12.01) + (22 × 1.01) + (11 × 16.00) = 342.3 g/mol

2. Use Avogadro's number (6.022 × 10²³) to determine the number of moles of sucrose:
  Moles of sucrose = (4.06 × 10²⁴ molecules) / (6.022 × 10²³ molecules/mol) = 6.75 mol

3. Calculate the mass of sucrose in grams:
  Mass of sucrose = (6.75 mol) × (342.3 g/mol) = 2310.525 g

So, 2310.525 grams of sucrose contain 4.06 × 10²⁴ molecules of sucrose.

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Describe Emotions in the room after “The Vote!” during July 2, 1776 U.S History

Answers

Answer:

On July 4, 1776—the day the Declaration of Independence was approved by the Second Continental Congress—the prevailing mood was trepidation and fear.

Explanation:

Differentiate liquid crystals from pure liquids and crystalline solids.
(Answer this question correctly and I will give the first correct answer brainliest)

Answers

Answer:

the difference between pure liquids and crystallines solids is pure liquids have optically active molecules forming twisted shapes whereas solids do not

Explanation:

The John Amos power plan located in Winfield, WV is a coal fired plant. The combustion of coal results in the emission of sulfur dioxide (SO 2

) into the atmosphere. SO 2

is known to cause respiratory illness and is a component of acid rain. Regulators are attempting to determine an efficient level of pollution. The following information is provided, the marginal damage costs (MDC) and marginal control costs (MCC), where Q= hundreds of tons of SO 2

and all costs are measured in hundreds of dollars. MDC=20Q
MCC=400−5Q

a. Determine the efficient quantity of SO 2

that should be released. b. Draw a model that represents the MDC and MCC. Include the efficient quantity and label the areas of total costs for damages and control.

Answers

The efficient quantity of SO2 emissions that should be released from the power plant is 16 hundred tons.

The efficient quantity of SO2 emissions that should be released from the John Amos power plant can be determined by equating the marginal damage costs (MDC) and marginal control costs (MCC). In this case, the MDC is given by 20Q (where Q is the quantity of SO2 emissions in hundreds of tons), and the MCC is given by 400 - 5Q.

To find the efficient quantity, we set MDC equal to MCC:

20Q = 400 - 5Q

Simplifying the equation, we get:

25Q = 400

Dividing both sides by 25, we find:

Q = 16

Therefore, the efficient quantity of SO2 emissions that should be released from the power plant is 16 hundred tons.

In the model representing MDC and MCC, the x-axis represents the quantity of SO2 emissions (Q in hundreds of tons), and the y-axis represents the cost (in hundreds of dollars). The MDC curve is upward-sloping, starting from the origin and increasing at a constant rate of 20. The MCC curve is downward-sloping, starting at 400 and decreasing at a constant rate of 5. The efficient quantity of 16 is labeled on the x-axis.

The areas of total costs for damages and control can be identified on the graph. The area under the MDC curve represents the total cost of damages caused by the emissions, while the area under the MCC curve represents the total cost of implementing control measures to reduce the emissions. The goal is to minimize the sum of these costs, which is achieved at the point where the MDC and MCC curves intersect, corresponding to the efficient quantity of emissions.

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If we reduce the volume in the vessel and the new pressure is measured to be 40 atm, what would the new volume be?

10 L

5 L

3.33 L (wrong alr tried it)

2.5 L

Answers

Answer:

2.5 L

Explanation:

I got the same question, I just don't remember how I got the answer. But it was right.

The new volume of the gas will be equal to 2.5 L at a pressure of 40 atm. Therefore, option (D) is correct.

What is Boyle's law?

Boyle’s law states that the pressure exerted by a given mass of gas at a constant temperature is inversely proportional to the volume occupied by it.

The pressure and volume are inversely proportional to each other as long as the temperature is kept constant.

P ∝ 1/V

or

P₁V₁ = P₂V₂                                                      ................(1)

Given, the initial pressure of the gas, P₁ = 10 atm

The final pressure of the gas,  P₂ = 40 atm

The initial volume of the gas, V₁ = 10 L

Substitute the values of volume and pressure in equation (1);

(10 atm) × (10 L) = (40 atm) × V₂

V₂ = 100/4

V₂ = 2.5 L

Therefore, the new volume of the gas will be equal to 2.5 L If we increase the pressure to 40 atm,

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Your question is incomplete but most probably complete question was,

We are studying the properties of a 10 L vessel of an ideal gas at 300 K and 10 atm of pressure inside. We can fix the volume or the pressure of the vessel as we like. If we reduce the volume in the vessel and the new pressure is measured to be 40 atm, what would the new volume be?

(A) 10 L

(B)  5 L

(C) 3.33 L

(D) 2.5 L

Which of the following are states of matter? (Select all that apply.)

liquids

atoms

compounds

solids

Please pick at least more than one, select all that apply

Answers

Answer:

liquids and solids

Explanation:

states of matter describe the physical properties of something.

atoms and compounds make up things and have the ability to exists in all states of matter depending on pressure and temperature.

the most common states of matter are solid, liquid and gas.

other types include plasma and bose-einstein condensate.

liquids and solids are distinct states of matter due to their characteristic properties and behaviors.

Option (A) & (D) are correct.

States of matter refer to the distinct physical forms in which substances can exist. Liquids and solids are two of these states.

1. Liquids: Liquids have a definite volume but take the shape of their container. Particles in liquids have enough energy to move around but not enough to break free from their attraction to one another.

2. Solids: Solids have both definite shape and volume. The particles are closely packed and vibrate around fixed positions due to strong intermolecular forces.

3. Atoms: Atoms are the fundamental units of matter, but they do not represent a state of matter by themselves. They can exist in various states when combined with other atoms or molecules.

4. Compounds: Compounds are formed by the chemical combination of atoms, and while they can exist in different states, the term "compounds" alone does not indicate a specific state of matter.

In summary, liquids and solids are distinct states of matter due to their characteristic properties and behaviors

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The complete question is:

Which of the following are states of matter? (Select all that apply.)

A) liquids

B) atoms

C) compounds

D) solids

Please pick at least more than one, select all that apply

which of the following solutions has a greater concentration of hydronium ions? solution a has a ph of 8.0. solution b has a ph of 13.5.

Answers

Solution A with pH of 8 has greater concentration of hydronium ions as compared to solution B with pH of 13.5.

pH = -log [H3O+]. By using the opposite mathematical procedure from that used to determine the pH, the hydronium ion concentration can be calculated from the pH.

The pH lowers as the hydronium content rises, making the fluid more acidic. When an acid is introduced, this happens. The solution's hydronium concentration rises when H+ ions separate from the acid and join with water to produce hydronium ions.

Any time an acid dissolves in water, the hydronium ion is created. The nearest water molecule is always where the acid's H+ moves to produce H3O+. Take the perspective of the proton (H+) to see the hydronium ion from a different angle. Hydration refers to the addition of water to anything.

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three monomers of the sugar c5h10o5 are used to make a trisaccharide by dehydration reactions. its formula is:

Answers

A trisaccharide is formed by linking three monomers of the sugar C5H10O5 through dehydration reactions.

The formula of this trisaccharide is dependent on the specific arrangement of the monomers and their glycosidic bonds.

The sugar C5H10O5, also known as pentose, can be found in many biological molecules such as nucleic acids and certain carbohydrates. When three monomers of this sugar are brought together and undergo dehydration reactions, a trisaccharide is formed. Dehydration reactions involve the removal of a water molecule to form a new bond between monomers.

The formula of the trisaccharide will depend on the specific arrangement of the monomers and the type of glycosidic bond that forms between them. Glycosidic bonds can link monomers in different orientations, resulting in different types of trisaccharides. For example, if the three monomers are linked in a linear fashion, the trisaccharide may have a formula such as C15H26O13. However, if the monomers are linked in a branched fashion, the formula may be different.

Overall, the formula of a trisaccharide made from three C5H10O5 monomers will depend on the specific arrangement of the monomers and the type of glycosidic bond formed between them.

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which molecule pair combines to directly regulate the cell cycle? group of answer choices g1 and g2 cdk and cyclin p21 and mdm2 prb and gdp e-cadherin and timp

Answers

The molecule pair that directly regulates the cell cycle is CDK (Cyclin-Dependent Kinase) and Cyclin.

CDKs are a family of protein kinases that play a crucial role in regulating the progression of the cell cycle. However, CDKs alone are inactive. Their activation requires binding to specific regulatory proteins called cyclins. Cyclins are named based on their periodic expression levels throughout the cell cycle.

During different phases of the cell cycle, specific cyclins are synthesized and bind to specific CDKs. The formation of CDK-cyclin complexes triggers a series of phosphorylation events that drive the cell cycle forward.

These complexes phosphorylate target proteins involved in cell cycle progression, such as proteins that regulate DNA replication or mitotic spindle formation.

The levels of cyclins oscillate during the cell cycle, ensuring the precise timing and coordination of cell cycle events. Once their function is complete, cyclins are degraded, and CDKs become inactive until the next phase of the cell cycle.

Therefore, the CDK-cyclin complexes are a fundamental pair of molecules directly responsible for regulating the cell cycle progression, ensuring proper cell growth and division.

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if the initial concentration of ab is 0.260 m , and the reaction mixture initially contains no products, what are the concentrations of a and b after 80 s

Answers

The concentration of A and B after 80 s  if the initial concentration of ab is 0.260 m, and the reaction mixture initially contains no products is 0.0091 M.

To find the concentrations of A and B after 80 s, we must write the kinetic data is given as follows for the reaction:

AB ⟶ A + B

Initial rate of the reaction is 1.62 x 10⁻³ mol/L/s

Order of reaction for AB is first order (n = 1). Now, using the first-order rate equation, the concentration of AB at time t, [AB]t can be calculated as follows:

ln [AB]0/[AB]t = k

tHere, [AB]0 is the initial concentration of AB, [AB]t is the concentration of AB at time t, k is the rate constant, and t is the time interval.

To determine the rate constant, we can use the initial rate of reaction.

Initial rate, ri = k[AB]n

Here, n is the order of reaction.

So, k = ri/[AB]n

Substituting the given values:

ri = 1.62 x 10⁻³ mol/L/s[AB]0

= 0.260 mk = ri/[AB]n

= 1.62 x 10⁻³ mol/L/s / (0.260 m)1

= 6.23 s-1

Now, we can use the rate constant to determine the concentration of AB at 80 seconds:

ln [AB]0/[AB]80 = kt

Here, k = 6.23 s-1, [AB]0 = 0.260 m, and t = 80 s.

Substituting the values:

ln (0.260 m)/[AB]80

= (6.23 s-1) (80 s)[AB]80

= [AB]0 e-kt

= (0.260 m) e-(6.23 s-1) (80 s)

= 0.0091 m

Now, since the stoichiometry of the reaction is 1:1, the concentration of A and B will be equal to each other. Therefore, [A]80 = [B]80 = 0.0091 m.

Thus, the final concentrations of A and B are 0.0091 M after 80 seconds.

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which coordination geometries are typical of vanadyl complexes?

Answers

The coordination geometries that are typical of vanadyl complexes are tetrahedral and octahedral.

Vanadyl complexes are a type of coordination compound that contains the vanadyl ion (VO2+). This ion typically forms complexes with a coordination number of 4 or 6, meaning that it is surrounded by either 4 or 6 ligands (atoms or molecules that are bonded to the central metal ion). In a tetrahedral geometry, the four ligands are arranged around the central metal ion in a tetrahedron, with bond angles of 109.5°. In an octahedral geometry, the six ligands are arranged around the central metal ion in an octahedron, with bond angles of 90°.

Examples of vanadyl complexes with tetrahedral geometry include VOCl4 2− and VO(acac)2, while examples of vanadyl complexes with octahedral geometry include VO(H2O)5 2+ and VO(ox)3 3−. In summary, the coordination geometries that are typical of vanadyl complexes are tetrahedral and octahedral. These geometries are determined by the number of ligands bonded to the central metal ion and the arrangement of these ligands around the ion.

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what are the percentage dissociations of h (g), o (g),and i (g) at 2000 k and a total pressure of 1 bar?

Answers

The percentage dissociation of H₂ is 0.0814%.

The percentage dissociation of O₂ is 0.0335%.

The percentage dissociation of I₂ is 94.6%.

The balanced chemical equation:

H₂(g)⇄2H(g)

ΔG0=2(106,760 J/mol)

-RT lnK=2*106,760 J/mol

-(8.3145 J/K/mol)(200 K) ln K=2*106,760 J/mol

Solving for K,

K=2.65*10^-6

On calculation, the percentage dissociation of H₂ is 0.0814%.

The balanced chemical equation:

O₂(g)⇄2O(g)

ΔG0=2(121552 J/mol)

-RT lnK=2*121552 J/mol

-(8.3145 J/K/mol)(200 K) ln K=2*121552 J/mol

Solving for K,

K=4.48*10^-7

On calculation, the percentage dissociation of O₂ is 0.0335%.

The balanced chemical equation:

I₂(g)⇄2I(g)

ΔG0=2(-29410 J/mol)

-RT lnK=2*-29410 J/mol

-(8.3145 J/K/mol)(200 K) ln K=2*(-29410) J/mol

Solving for K,

K=34.37

On calculation, the percentage dissociation of I₂ is 94.6%.

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Are crystals of different soluble solids similar?​

Answers

Crystals of different soluble solids  are not similar because they are  amorphous and   therefore  do not have definite crystals.

What are crystal solids?

A crystalline solid is a homogeneous solid in which the constituent particles, atoms, ions or molecules are arranged in a definite repeating pattern.

Most of the solid substances are crystalline in nature. The arrangement of particles in a crystalline solid is such that the total intermolecular force of attraction is at maximum.

Factors in which solubility depends are temperature, pH, and ionic strength.

Crystals of different soluble solids are not similar as they do not have definite crystals.

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HELP ME ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

HELP ME ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

Digestive

Explanation:

a 40 mg sample of phosporus reacts with 77.6 mg sample of selinum to for the cpmpound phosphourous selenide. what is the emperical formula of phosphurus

Answers

Phosphorus interacts with selenium to generate 77.6 mg of the compound from a sample of 40 mg of phosphorus. Therefore, phosphorus selenide has an empirical formula is P₃Se₁.

A compound's empirical formula is a formula that displays the ratio of the elements contained in the compound but not the precise number of atoms present in the molecule.

The molar mass of phosphorus (P) is 31 g/mol and selenium (Se) is 79 g/mol. Then, computing the moles of phosphorus, we get,

\(\begin{aligned}\text{moles of P}&=\mathrm{0.04\;g}\times\mathrm{\frac{1\;mole}{31\;g}}\\&=\mathrm{1.29\times10^{-3}\;moles}\end{aligned}\)

The total mass is 77.6 mg. Then, the mass of selenium is (77.6-40)mg=37.6 mg=0.0376 g. Computing the moles of selenium, we get,

\(\begin{aligned}\text{moles of Se}&=\mathrm{0.0376\;g}\times\mathrm{\frac{1\;mole}{79\;g}}\\&=\mathrm{0.476\times10^{-3}\;moles}\end{aligned}\)

Now, divide the mole value of smaller by the mole value of P and Se. We get,

\(\begin{aligned}\frac{1.29\times10^{-3}}{0.476\times10^{-3}}}&=2.71=3\\\frac{{0.476\times10^{-3}}}{{0.476\times10^{-3}}}&=1\end{aligned}\)

Therefore, the required answer is P₃Se₁.

The complete question is -

A 40 mg sample of phosphorus reacts with selenium to form 77.6 mg of the compound. What is the empirical formula of phosphorus selenide?

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What does the word Microbial mean?

Answers

Answer:

relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.

Explanation:

ex: "skin is a major source of microbial contamination during a surgical procedure"

◕‿↼ Hey There!

Answer → Microbial means, relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.

✨Hope This Helps!✨

i could really use some help with this question, thank you in advance!​

i could really use some help with this question, thank you in advance!

Answers

C because
Explanation Plato

T/F because oxygen-rich gas mixtures cause greater heat loss than air does, you may need additional thermal protection for nitrox diving.

Answers

Nitrox diving may require additional thermal protection since oxygen-rich gas mixes lose more heat than air does.

mixes of oxygen-rich gases

While diving with nitrox gas mixtures, more heat protection may be needed due to the gas mixture's higher oxygen concentration.

Oxygen-rich gas mixtures may cause more heat loss because oxygen molecules leave the body more often than nitrogen ones do.

This happens as oxygen molecules are smaller and more prone to leave the body's tissues.

Additionally, by breathing an oxygen-rich gas combination, the body may release less heat.

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PLEASE HELP
what is density?

Answers

What is density?

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

How to determine density

For example, unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?

We can obtain the density as follow:

Mass = 30.8 gVolume = 31.5 mL Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

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Please help! will give brainlyst to 1st answer! help ASAP!!! 30 POINTS!!!!

Please help! will give brainlyst to 1st answer! help ASAP!!! 30 POINTS!!!!

Answers

Answer:

The answer to your question is D. 4.5 seconds hope this helps ;)

Question 11
Which formula represents a hydrocarbon?


C₂H6
C₂H5OH
C₂H5Cl
C₂H6O

Answers

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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Directions: given the following pairs of words, please explain in your own words the
DIFFERENCE between them.
1) Acid and base :
2) Concentrated and diluted:
3) Neutralization and dilution :
4) Soluble and insoluble :
5) Mixture and solution :|

Answers

Answer:

acid jsh just want me there for me too I love her soooooo you know I have no money to go back home from school tomorrow morning at like midnight to go out to my in the to the population and you have to get to know what to tell u what are u

1. what are the two processes underlying this image that turn peat into coal? a. peatification and coalification b. peatification and lignitigation c. lignitigation and coalification d. petrification and coalification

Answers

Option C. Lignitigation and coalification.

Lignitigation is the process of compressing peat into lignite, and coalification is the process of further compressing and heating lignite into coal.

Transformation of Peat into Coal: The Process of Lignitigation and Coalification

The process of turning peat into coal involves two stages: lignitigation and coalification.

Lignitigation is the process of compressing peat into lignite, which is the first stage in the formation of coal. This process involves applying heat and pressure to the peat, resulting in the peat becoming denser, harder, and more brittle. The second stage of the process is coalification, in which the lignite is subjected to further heat and pressure, resulting in the formation of coal. This process increases the carbon content of the material, as well as its energy density.

The end result is a material that is much harder and more durable than the original peat, and is used for a variety of purposes, from fuel to industrial products.

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Select the correct answer.

Who pioneered the use of galvanoplastic compounds for preserving footprints and ballistics?

OA Mathieu Orfila

B. Calvin Goddard

Oc. Edmon Locard

OD. Alphonse Bertillon

O E. Dr. Joseph Bell

Answers

Biometrics was first applied to law enforcement by Alphonse Bertillon, a French police officer, and researcher who borrowed the anthropological method of anthropometry to develop a biometric identification system therefore option D. is the right choice.

The police department's use of anthropometry as a means of criminal identification was the first scientific method of its kind. In the past, authorities could only track down offenders using their names or photographs. Fingerprinting ultimately replaced the technique.

Furthermore, he created the first-ever mug shot. Before Bertillon formalized the practice in 1888, offenders had already been photographed as early as the 1840s, just a few years after the introduction of photography.

In the historic Dreyfus case, Alfred Dreyfus has wrongfully convicted thanks to his faulty evidence.

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A medical research team wished to evaluate a proposed screening test for Alzheimer's disease. The test was given to a random sample of 450 patients with Alzheimer's disease and an independent random sample of 500 patients without symptoms of the disease. The two samples were drawn from populations of subjects who were 65 years of age or older. The results are as follows: Given that 11.3 percent of the U.S. population aged 65 and over have Alzheimer's disease Solve the questions below showing your steps. 1. estimate the sensitivity of the test. 2. Estimate specificity of the test. 3. compute the predictive value positive of the test. 4. Compute the predictive value negative of the test.

Answers

The sensitivity of the test is 33.3%,

the specificity of the test is 90%,

the positive predictive value of the test is 75%, and

the negative predictive value of the test is 60%.

Given that 11.3% of the U.S. population aged 65 and over has Alzheimer's disease, we are to evaluate a proposed screening test for Alzheimer's disease with the following results:

Test Results Positive Negative Alzheimer's Disease 150300No Alzheimer's Disease50 450

a. Estimating the sensitivity of the test

Sensitivity of the test refers to the proportion of people who are genuinely positive for a disease and have tested positive.

In other words, the proportion of people with Alzheimer's who correctly test positive.

Sensitivity is calculated as follows:

Sensitivity = (Number of true positives) / (Number of true positives + Number of false negatives)

Number of true positives = 150 (as given in the table)

Number of false negatives = 300 (as given in the table)

Sensitivity = (150) / (150 + 300)

                 = 0.333 or 33.3%

b. Estimating the specificity of the test

The specificity of the test refers to the proportion of individuals who do not have the disease and test negative for it.

In other words, the proportion of people without Alzheimer's who correctly test negative.

Specificity is calculated as follows:

Specificity = (Number of true negatives) / (Number of true negatives + Number of false positives)

Number of true negatives = 450 (as given in the table)

Number of false positives = 50 (as given in the table)

Specificity = (450) / (450 + 50)

                 = 0.900 or 90%

c. Computing the positive predictive value of the test

Positive predictive value refers to the proportion of individuals who test positive for a disease and have the disease.

In other words, the probability of having the disease given that the test is positive.

Positive predictive value is calculated as follows:

Positive predictive value = (Number of true positives) / (Number of true positives + Number of false positives)

Number of true positives = 150 (as given in the table)

Number of false positives = 50 (as given in the table)

Positive predictive value = (150) / (150 + 50)

                                         = 0.75 or 75%

d. Computing the negative predictive value of the test

Negative predictive value refers to the proportion of individuals who test negative for a disease and do not have the disease.

In other words, the probability of not having the disease given that the test is negative.

Negative predictive value is calculated as follows:

Negative predictive value = (Number of true negatives) / (Number of true negatives + Number of false negatives)

Number of true negatives = 450 (as given in the table)

Number of false negatives = 300 (as given in the table)

Negative predictive value = (450) / (450 + 300) = 0.600 or 60%

Thus, the sensitivity of the test is 33.3%, the specificity of the test is 90%, the positive predictive value of the test is 75%, and the negative predictive value of the test is 60%.

Learn more about  predictive value from this link:

https://brainly.com/question/31848214

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How much heat must be added to a 12.75 g sample of gold to increase its temperature
from 32.5°C to 85.5°C? The specific heat of gold is 0.13 J/gºC.
Report your answer with the proper number of SF with a space between your numeral
answer and units.

Answers

Answer: This is a link to all of the awsers

https://pshs.psd202.org/documents/ssafe/1552416190.pdf

Explanation:

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