what is the oxidation number of ni in k4[ni2(cn)6]

Answers

Answer 1

The oxidation number of Ni in K_4{Ni_2[CN_(-6)]} is +1.

What is oxidation number?

Oxidation number, also known as oxidation state, is a concept used to assign a hypothetical charge to individual atoms in a compound or ion. It is a representation of the electron distribution around an atom in a molecule or ion.

Let's assign the oxidation number of Ni as x.

The oxidation number of CN is -1, and there are six CN ligands, so the total oxidation number contributed by CN is -6.

The oxidation number of K is +1, and there are four K ions, so the total oxidation number contributed by K is +4.

The compound is neutral, so the sum of the oxidation numbers should be zero.

(-6) + (2x) + (+4) = 0

Simplifying the equation:

2x - 6 + 4 = 0

2x - 2 = 0

2x = 2

x = 1

Therefore, the oxidation number of Ni in K_4{Ni_2[CN_(-6)]} is +1.

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Related Questions

1. Consider the generic reaction:A + 2BC AH = -55 kJDetermine the amount of heat emitted when each amountof reactant completely reacts (assume that there is morethan enough of the other reactant).(a) 1 mol A(b) 2 mol A(c) 1 mol B(d) 2 mol B

Answers

Answer:

(a) 55 kJ of heat are released when 1 mol of reactant A is used;

(b) 110 kJ of heat are released when 2 moles of reactant A are used;

(c) 27.5 kJ of heat are released when 1 mol of reactant B is used;

(d) 55 kJ of heat are released when 2 moles of reactant B are used.

Explanation:

The question requires us to determine the amount of heat released when the given amounts of reactants are used, considering the following balanced chemical equation:

\(A+2B\rightarrow C\text{ }\Delta H=-55kJ\)

When the enthalpy change for a reaction (or heat of reaction, ΔH) is given in units of energy, such as kilojoules (kJ), and not units of energy per mol (such as kJ/mol), we can consider that ΔH corresponds to the heat absorbed or released for the molar quantities of reactants as given in the balanced chemical equation. In the case given by the question, for example, we can say that 55 kJ of energy are released when 1 mol of A reacts with 2 moles of B.

Therefore, we can use the molar quantitites from the balanced chemical equation as a reference to determine the amount of heat released when different amounts of reactants are used.

Considering the information above, we can calculate:

(a) heat released when 1 mol of A reacts:

Note that 1 mol of A corresponds to the amount of reactant A given by the balanced chemical equation. Therefore, 55kJ of energy are released when 1 mol of A is used.

(b) heat released when 2 moles of A reacts:

Note that 2 moles of A corresponds to the double of the amount of reactant A given by the balanced chemical equation. Thus, we must multply ΔH by 2: 55 kJ x 2 = 110 kJ of energy are released when 2 moles of A are used.

(c) heat released when 1 mol of B reacts:

Note that 1 mol of B corresponds to half of the amount of reactant B given by the balanced chemical equation. Thus, we must divide ΔH by 2: 55 kJ / 2 = 27.5 kJ of energy are released when 1 mol of B is used.

(d) heat released when 2 moles of B reacts:

Note that 2 moles of B corresponds to the amount of reactant B as given by the balanced chemical equation. Therefore, 55 kJ of energy are released when 2 moles of B are used.

Help needed fast, please ?

Help needed fast, please ?

Answers

The standard reduction potential for the half-reaction of Be^2+ + 2e^- -> Be is given as E^0 = 3.83 V.

For the half-cell Hg^2+ | Hg, the standard reduction potential is not provided in the given information. To calculate the electric potential for the voltaic cell, we need the reduction potential for the Hg^2+ | Hg half-cell.

A voltaic cell, also known as a galvanic cell or an electrochemical cell, is an electrochemical device that generates electrical energy through a spontaneous chemical reaction. It consists of two half-cells connected by an external circuit and a salt bridge or porous barrier that allows the flow of ions between the two half-cells.

Each half-cell consists of an electrode immersed in an electrolyte solution. The electrode is typically made of a metal or a conductive material, and the electrolyte is a solution containing ions that can participate in the redox (reduction-oxidation) reaction.

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EXERCISE 3: WHAT DOES pCO2 CHANGE? - When pCO
2

increases, the concentration of total CO
2

dissolved in water - When pCO
2

increases, the concentration of only CO
2

dissolved in water - When pCO
2

increases, the pH - Which form of dissolved CO
2

is most common in water? Ocean acidification is the decrease in pH due to increasing atmospheric CO
2

concentration.
2
. Choose the correct word option in the statements below: - An organism that needs CO
2

is likely to fare better / worse under ocean acidification. - An organism that needs HCO
3

- is likely to fare better/worse under ocean acidification. - An organism that needs CO
3


2−
is likely to fare better/worse under ocean acidification.

Answers

pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.

When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.

In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.


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what has changed in the atmosphere that give the rock strata the appearance of rust?(red/orange color).

Answers

Answer:

Explained below.

Explanation:

What has changed in the atmosphere is that oxidation has occurred where an oxidizing chemical specie has reacted with an oxygen containing compound.

Now these chemicals when they react with rain and fall on rocks react with the rocks to weaken them in a process known as chemical weathering.

Now when this weathering from the oxidizing chemicals from the rain react with rocks that contain iron, it leads to the rock having an appearance of rust.

which describes an atom that has fewer nuetrons than protons and more electtrons than protons?

Answers

An atom that has fewer neurons than protons and more electrons than protons is an ANION

The cultures of prehistoric humans are known mostly through the excavation of stone tools and other relatively imperishable artifacts. The early tool making traditions are often referred to as being paleolithic (literally "Old Stone Age). The Oldowan and Acheulian tool traditions of the first humans were the simplest applied research basic research Scientihe thought O philosophies technologies

Answers

The cultures of prehistoric humans are primarily known through the excavation of stone tools and other durable artifacts, such as the Oldowan and Acheulian tool traditions.

Stone tools and imperishable artifacts serve as key archaeological evidence for understanding prehistoric cultures. Through meticulous excavation and analysis, archaeologists have been able to piece together the lifestyles, technological advancements, and social behaviors of early human societies. The term "paleolithic" refers to the Old Stone Age, a time when humans relied on stone tools as their primary implements.

The Oldowan tool tradition is considered the earliest stone tool industry, dating back around 2.6 million years ago. It is characterized by simple tools, such as choppers and scrapers, which were crafted by flaking off pieces from larger stones. These tools were primarily used for basic activities like butchering and processing animal carcasses.

Later, the Acheulian tool tradition emerged around 1.76 million years ago, representing an advancement in stone tool technology. Acheulian tools, such as handaxes and cleavers, were more refined and standardized, showcasing an increased level of sophistication in tool-making techniques. These tools served a wide range of purposes, including hunting, woodworking, and shaping raw materials.

By studying the Oldowan and Acheulian tool traditions, researchers gain valuable insights into the cognitive abilities, cultural development, and technological progress of early humans. The examination of these artifacts provides evidence of their adaptability, problem-solving skills, and the gradual refinement of their tool-making techniques over time.

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In Part 3 you will weigh out 3 samples of unknown sample, and titrate them to determine the exact concentration of your periodate standard to 4 significant figures. Here is your data:
Your first unknown sample weighed 1.0410 grams.
The burette starting volume was 1.92 mLs
The burette reading at the titration end point was 11.61 mLs.
Calculate your unknown concentration in units of wt%.
Your second unknown sample weighed 1.0361 grams.
The burette starting volume was 1.59 mLs
The burette reading at the titration end point was 11.24 mLs.
Calculate your unknown concentration in units of wt%.
Your third unknown sample weighed 1.0333 grams.
The burette starting volume was 2.00 mLs
The burette reading at the titration end point was 11.65 mLs.
Calculate your unknown concentration in units of wt%.
Calculate and report the average Fe wt% in your unknown sample.

Answers

Weightage percentage of all 3 unknown sample are  10.74 % ,  10.74 % ,  10.71 % and average weightage percent = 10 .73 %

Given sample mass = 1.0410 gm

volume will be =  [ 11.61 -- 1.92 ] ml

                                  = 9.69 ml

percentage of wt₁ = 1.0410 / 9.69 × 100

                                         = 10.74 %

2. second unknown sample mass  = 1.0361 gm

                   volume will be               =  [ 11.24 -- 1.59 ]

                                                            =    9.65 ml

percentage of wt₂ = 1.0361 / 9.65 × 100

                                       = 10.74 %

3. Sample mass of third unknown = 1.0333 gm

        volume of given                   =      [ 11.65 -- 2 ]

                                                           =     9.65 ml

                percentage of wt₃   = 1.0333 / 9.65 × 100

                                                         = 10.71 %

Average weightage percent of unknown sample =

                                                    =      10.74 + 10.74 + 10.71 / 3

                                                               = 10 .73 %

What percentage is the weighted average?

A weighted average can be calculated by adding the sums of its relative proportion or percentage and value in order. As a result, a portfolio's weighted average return can be calculated by multiplying the weights of 55 percent stocks, 40 percent bonds, and 5 percent cash by their annual performance.

What are weighted average and normal?

The sum of all values divided by the number of values is the average. Interestingly, the Weighted Normal is esteem duplicated by the weight, and added to track down an answer. A Normal is a numerical estimation, though the Weighted Normal is utilized in finance

Incomplete question :

In Part 3 you will weigh out 3 samples of unknown sample, and titrate them to determine the exact concentration of your periodate standard to 4 significant figures. Here is your data:

1. Your first unknown sample weighed 1.0410 grams. The Burnett starting volume was 1.92 mLs The Burnett reading at the titration end point was 11.61 mLs. Calculate your unknown concentration in units of wt%.

2. Your second unknown sample weighed 1.0361 grams. The Burnett starting volume was 1.59 mLs .The Burnett reading at the titration end point was 11.24 mLs. Calculate your unknown concentration in units of wt%.

3. Your third unknown sample weighed 1.0333 grams. The Burnett starting volume was 2.00 mLs .The Burnett reading at the titration end point was 11.65 m Ls. Calculate your unknown concentration in units of wt%. Calculate and report the average Fe wt% in your unknown sample.

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You have measured out 75.00 g of Mg(OH)2 (formula weight: 58.33 g/mol) to make a solution. What must your final volume be (in L) if you want a solution made from this mass of Mg(OH)2 to have concentration of 0.435 M

Answers

The final volume of the solution should be approximately 3.99 L if you want a solution made from 75.00 g of Mg(OH)2 to have a concentration of 0.435 M.

To determine the final volume of the solution, we can use the formula:

\(\[ \text{Concentration (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}} \]\)

First, we need to calculate the moles of Mg(OH)2 using the given mass and formula weight:

\(\[ \text{moles of Mg(OH)2} = \frac{\text{mass}}{\text{formula weight}} \]\)

Substituting the values:

\(\[ \text{moles of Mg(OH)2} = \frac{75.00 \, \text{g}}{58.33 \, \text{g/mol}} \]\)

Next, we can rearrange the formula to solve for the volume of the solution:

\(\[ \text{volume of solution (L)} = \frac{\text{moles of solute}}{\text{concentration (M)}} \]\)

Substituting the values:

\(\[ \text{volume of solution (L)} = \frac{\text{moles of Mg(OH)2}}{0.435 \, \text{M}} \]\)

Now we can calculate the volume:

\(\[ \text{volume of solution (L)} = \frac{75.00 \, \text{g} / 58.33 \, \text{g/mol}}{0.435 \, \text{M}} \]\)

\(\[ \text{volume of solution (L)} \approx 3.99 \, \text{L} \]\)

Therefore, the final volume of the solution should be approximately 3.99 L if you want a solution made from 75.00 g of Mg(OH)2 to have a concentration of 0.435 M.

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Earth is a part of the galaxy known as the-

Triangulum galaxy.

Omega Centauri.

Andromeda galaxy.

Milky Way.

Answers

Answer:

its milky way galaxy..........

a gas at constant volume has a pressure of 3.20 atm at 300. k. what will be the pressure of the gas at 290. k? 2.86 atm 3.09 atm 3.31 atm 3.56 atm

Answers

The relationship between pressure and temperature of a fixed amount of gas in a rigid container is called Charles’ Law.

According to Charles’ Law, for a given mass of gas at a constant volume, the volume of the gas varies directly with the temperature. It can be represented by the formula :V/T = constant where, V = volume of the gas T = temperature of the gas (in Kelvin)constant = proportionality constant Since pressure, volume, and temperature of the gas are interdependent, we can write:

PV/T = constant. We can use this formula to solve the problem. We know that the volume of the gas is constant. So, we can write:

P1/T1 = P2/T2 where, P1 = 3.20 atm (pressure at 300 K)T1 = 300 K (temperature at 3.20 atm)T2 = 290 K (temperature at unknown pressure)

Now, we can calculate P2 (pressure at 290 K) as:

P2 = P1 × (T2/T1) = 3.20 atm × (290 K/300 K) = 3.09 atmAnswer:3.09 atm

When the temperature of a fixed amount of gas is increased, its volume also increases. Similarly, when the temperature is decreased, the volume also decreases. This relationship between the volume of a gas and its temperature at a constant pressure is called Charles’ Law. It can be stated as:

V/T = constant, where V is the volume of the gas and T is its temperature in Kelvin. The proportionality constant in the above equation is the number of moles of the gas multiplied by the gas constant (R).

Mathematically, we can represent this relationship between pressure, volume, and temperature of a gas as: PV/T = constant.

When the volume of the gas is constant, the above equation becomes:

P1/T1 = P2/T2where P1 and T1 are the initial pressure and temperature of the gas, and P2 and T2 are the new pressure and temperature of the gas, respectively.

Using this equation, we can calculate the pressure of the gas at a new temperature, provided we know its initial pressure and temperature, and the new temperature.

Therefore, the pressure of the gas at 290 K will be 3.09 atm.

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A greater force is required to move an object with a larger mass than one with a smaller
mass.

Answers

Answer:

Explanation:

what do u need to know

The greater the force that is applied to an object of a given mass, the more the object will accelerate. The greater the mass of an object, the less it will accelerate when a given force is applied. For example, doubling the mass of an object results in only half as much acceleration for the same amount of force. Hope this helps!

Calculate the wavelength (in nm) of light with a frequency of 5.98 x 1014 s 1. What is the energy of a photon of light that has a frequency of 9.89 x 1013 Hz?

Answers

The wavelength of the light is approximately 500 nm. The energy of the photon of light is approximately 6.56 x 10-20 J.

Answer: Question 1:The formula relating wavelength, frequency, and the speed of light is given by:c = fλHere,λ = wavelength, f = frequency, c = speed of lightI. n the problem, frequency is given as 5.98 x 1014 s-1. Therefore, using the formula, the wavelength of light can be calculated as follows:λ = c/f= (3 x 108 m/s)/(5.98 x 1014 s-1)≈ 500 nm

Therefore, the wavelength of the light is approximately 500 nm.

Question 2:The formula relating energy and frequency of light is given by:E = hfwhereE = energy of photonh = Planck's constant = 6.626 x 10-34 J s (Joule seconds)f = frequency of lightIn the problem, the frequency of light is given as 9.89 x 1013 Hz. Therefore, using the formula, the energy of the photon of light can be calculated as follows:E = hf= (6.626 x 10-34 J s) x (9.89 x 1013 Hz)≈ 6.56 x 10-20 J

Therefore, the energy of the photon of light is approximately 6.56 x 10-20 J.

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List three things you wonder about bath bombs

Answers

Almost all bath bombs contain sodium bicarbonate and citric acid. These two ingredients combine to create that fizzing sensation bath bombs are famous for. More than that, though, they clean, deodorize, and repair skin, and strengthen blood vessels. These two main ingredients leave you with healthier, younger looking ...

How does temperature affect physical and chemical changes ?

Answers

hopefully this helps !!
How does temperature affect physical and chemical changes ?

How many moles are in 2.99 x 10^24 atoms of Ca? (
answer. Keep 3 sigfigs in your final answer) *

Answers

Answer:

4.97 moles

Explanation:

There are  6.022*10^23 calcium  atoms  in 1 mole of  Ca

2.99*10^24/6.022*10^23

=4.97 moles

Answer:

4.97 mol

Explanation:

Given data:

Number of atoms of Ca = 2.99×10²⁴

Number of moles of Ca = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.99×10²⁴  atoms × 1 mol  / 6.022 × 10²³ atoms

0.497×10¹ mol

4.97 mol

101. During the making of steel, iron(II) oxide is reduced to metallic iron by treatment with carbon monoxide gas.
FeO (s) + CO (g) Fe ( s)
Suppose 1.45 kg of Fe reacts. What volume of CO(g) is required, and what volume of CO2(9) is produced, each measured at STP?'

Answers

Explanation:

At a certain temperature, iron (II) oxide, FeO, can react with carbon monoxide, CO, to form elemental iron, Fe, and carbon dioxide, CO2. The value of Kp at that temperature is 0.242. What is the pressure of CO2 at equilibrium if a sample of FeO was initially in a container with CO at a pressure of 0.95 atm? The chemical reaction involved in this process is: FeO(s) + CO(g) ⟷ Fe(s) + CO2(

A scientist has discovered a new radioactive element. she finds that the radiation is able to pass through the cardboard box holding the sample, but doesn't pass through the row of steel file cabinets along her wall. is the element emitting alpha, beta, or gamma radiation

Answers

If the radiation is able to pass through the cardboard box holding the sample, but doesn't pass through the row of steel file cabinets along her wall then the element is emitting gamma radiation.

What are gamma rays?

Gamma rays are the type of high-energy electromagnetic radiation that is released from the nucleus when undergoing radioactive decay. Gamma rays have the highest energy of all types of radiation and can penetrate matter deeper than alpha and beta rays. Gamma rays are used in a variety of medical, industrial, and scientific applications such as; Cancer treatment, sterilization, scientific research, food safety. Gamma rays are also a form of ionizing radiation, meaning they can damage living tissue.

In this case, the element most likely emits gamma rays. Gamma rays are the most penetrating type of radiation, easily penetrating cardboard but not steel. Alpha and beta rays have low penetrability and cannot pass through cardboard.

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show the relationship among the number of valence electrons,electronegativity, and ionization energy?​

Answers

The relationship between the number of valence electrons, electronegativity, and ionization energy is direct proportionality.

A valence electron is an electron that is part of an atom's outer shell and can take part in the synthesis of a chemical bond if the outer shell is open. The electrons used in chemical processes are called valence electrons. The ability of an atom or functional group to draw electrons to itself is known as electronegativity in chemistry. An atom's electronegativity is influenced by both its atomic number and how far away from its charged nuclei its valence electrons are located.

Ionization energy sometimes referred to as ionization potential, is the amount of energy needed to remove an electron from an isolated atom or molecule. When the number of valence electrons increases, the electronegativity, and the ionization energy increase.

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compare the following: acid 1: hypochlorous acid , hclo acid 2: hydrogen sulfide ion , hs- acid 3: hydrofluoric acid , hf what is the formula for the strongest acid ?

Answers

The formula for the strongest acid is: HF.

To compare the strengths of the given acids, we can use their acid dissociation constants (Ka). The larger the Ka value, the stronger the acid.

The Ka values for the given acids are:

Hypochlorous acid (HClO): Ka = 3.5 × 10^-8

Hydrogen sulfide ion (HS^-): Ka = 1.0 × 10^-7

Hydrofluoric acid (HF): Ka = 6.8 × 10^-4

Comparing the Ka values, we can see that hydrofluoric acid (HF) has the largest Ka value and is therefore the strongest acid among the three given acids.

The formula for the strongest acid is: HF.

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If a gas displays a solubility of 0.00290M at a partial pressure of 125 kPa, what is the proportionality constant for this gas in this solvent and at this temperature?

Answers

Answer:

The proportionality constant ( Henry’s constant) = 2.32 * 10^-5 M/kPa

Explanation:

Here in this question, we are concerned with calculating the proportionality constant for this gas.

Mathematically, we can get this from Henry law

From Henry law;

Concentration = Henry constant * partial pressure

Thus Henry constant = concentration/partial pressure

Henry constant = 0.00290 M/125 kPa = 2.32 * 10^-5 M/kPa

When sample X'is passed through a filter paper a
white residue, Y, remains on the paper and a clear
liquid, Z, passes through. When liquid Z is
vaporized, another white residue remains. Sample
X is best classified as

When sample X'is passed through a filter paper awhite residue, Y, remains on the paper and a clearliquid,

Answers

Sample X is best classified as a heterogeneous mixture

Homogenous mixture has the same uniform composition and appearance through out the reaction and it is difficult to separate the substrates present in it.

A heterogeneous mixture contains of visibly  different phases or substances. Here separating the mixture becomes easy.

In the given question When sample X is passed through the filter paper we see that a white residue is remaining which is Y. This itself suggests that the the mixture is heterogeneous mixture.

As we initially got the residue it suggests that the solution is a homogenous mixture as we can now differentiate two substances

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BRIANLIEST!!!!!!
Use the mass to calculate the number of moles in a 347.89 g samples of ammonium

Answers

Answer:

20.46 moles

Explanation:

1 mole of NH3 contains 17gm of NH3

so 347.89 gm of ammonia is in,

347.89/17 moles

=20.46 moles

NOTE. There should be ammonia instead of ammonium in question because ammonium is an ion not a compound.

4 molecules of hydrogen (H2) react with 2 molecules of oxygen (O2) to produce some amount of water (H2O).
Complete the table below.
Chemical element Number of atoms in the reaction
-H -
-O -
During this reaction, how many molecules of water (H2O) are produced?

Answers

Answer:

2H2+ 02-->2H20

So 4H2 + 202-->4H20

so the answer is 4 water molecules.

How widespread are the trilobite fossils?

Answers

Answer:

Trilobite fossils are found worldwide, with many thousands of known species. ... Because of their diversity and an easily fossilized exoskeleton, they left an extensive fossil record with some 17,000 known species spanning Paleozoic time.

Let me know if this help

Explanation:

Depending on the area and the movement of the plates, the fossils would be kind of close to each other. Maybe about a couple feet at the farthest in one area, almost everywhere.

What is physical since ?

Answers

You mean physical science?

Answer:

Phycical science is the study of the body.

Explanation:

If 6.3 moles of O2 and 8.15 moles of N2 are placed in a 65.1 L tank at a
temperature of 348 C, what will the pressure of O2?

Answers

Answer:

Partial pressure of O2 = 4.93 atm

Explanation:

PV = n RT        R = .082057 L-atm/mol-K

n = 6.3 + 8.15 = 14.45 moles

348 C = 621.15 K

P (65.1) = 14.45 ( .082057)(621.15) = 11.31 atm

Now the fraction of pressure from Oxygen is

   6.3 / (6.3+8.15)  * 11.31 = 4.93 atm

which indicator would be best to determine the endpoint in the neutralization of a weak acid with a strong base?

Answers

To determine the endpoint in the neutralization of a weak acid with a strong base, it is best to use a pH-sensitive indicator such as phenolphthalein.

The best indicator to determine the endpoint in the neutralization of a weak acid with a strong base would be a universal indicator. This is because a universal indicator can detect a wide range of pH levels and can provide a clear indication when the solution becomes neutral. Another option could be phenolphthalein, which changes color from colorless to pink when the solution becomes basic, indicating the endpoint has been reached. However, phenolphthalein may not be as accurate in detecting the endpoint for weak acids as it requires a relatively high pH to change color. Phenolphthalein changes color around pH 8.2-10, which is suitable for detecting the endpoint in this type of reaction, as the final pH will be slightly alkaline due to the strong base.

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Someone please help will mark as brainliest

Someone please help will mark as brainliest

Answers

Answer:

a1

The main difference between SPECT and PET scans is the type of radiotracers used. While SPECT scans measure gamma rays, the decay of the radiotracers used with PET scans produce small particles called positrons. A positron is a particle with roughly the same mass as an electron but oppositely charged.

Explanation:

a2

While imaging tests such as X-rays can show what the structures inside your body look like, a SPECT scan produces images that show how your organs work. For instance, a SPECT scan can show how blood flows to your heart or what areas of your brain are more active or less active.

a3

PET and SPECT have been extensively evaluated as diagnostic procedures for dementia. Substantial progress has been made in developing radioligands that bind to amyloid deposits in the brain, which should provide new opportunities for early diagnosis and treatment monitoring in Alzheimer's disease

a4

What are the disadvantages of spect as compared to pet?

However, SPECT has issues, including long scan times and low-resolution images prone to artifacts and attenuation. Some artifacts can easily be misidentified as perfusion defects. SPECT also does not provide a quantifiable estimate of the blood flow, whereas PET does, experts say.

Calculate the volume of gas, in L, occupied by 1.74 moles of SF6 (g) at 273 K and 1 atm

Answers

The volume of gas is 3,949.31 litre, occupied by 1.74 moles of SF6 (g) at 273 K and 1 atm.

What is an ideal gas law ?

The ideal gas law is also called as perfect gas law. It is the relation between the pressure P, volume V, and temperature T of a gas.  

Given:

Volume of gas = ?

Number of moles (n) = 1.74 moles

Temperature (T) = 273K

Pressure (P) = 1 atm

R (gas constant) = 8.314

By an ideal gas equation

PV = nRT

By putting above value in ideal gas equation, we get

1 × V = 1.74 × 8.314 × 273

V = 3,949.31 litre

Thus, The volume of gas, in L is 3,949.31 litre, occupied by 1.74 moles of SF6 (g) at 273 K and 1 atm.

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For the metal Mg 109.5g solution HCl 10%. a) Case of metal b) Its properties

Answers

Answer:

Explanation:

mg +2hcl=mgcl2 +h2

mhcl=10.95g

nhcl==0.3

nmg=1/2nhcl=0.15

mMg=3.6g

m mgcl2=14.25

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