what is the name of the following compound? multiple choice 2-chlorohexyl ethanoate 1-chlorohexyl ethanoate ethyl 2-chlorohexanoate ethyl 1-chlorohexanoate

Answers

Answer 1

The substance in question is called ethyl 2-chlorohexanoate.

What is chemical compound?

A chemical compound is a substance that contains atoms from multiple chemical elements held together by chemical bonds. It is made up of numerous identical molecules. Therefore, any type of  molecule made up of only 1 type of atoms isn't a compound.

So, this chemical, an ester, is presented to us. because estuaries generally consist of oxygen, C double bond oxygen, and a dash. It brings things to a close. As a result, Lester and Esther are tied, and the suffix uh is eight. Names can therefore begin with a few differences from the other side's six carbon atoms and chlorine's following presence in the second position.

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Related Questions

The hardest coal has
the most energy and
burns the cleanest.
Where do coal miners
find the HARDEST
coal?

Answers

The answer is China...........

A metal with a mass of 71.68 g occupies a volume of 8.00 cm3. Calculate the density of the metal.

Please help me work through this. <3

Answers

A metal with a mass of 71.68 g occupies a volume of 8.00 cm3. Then density of the metal 8.96 g/cm³.

Given

Mass = 71.68g

Volume = 8 cm³

Density =?

Density= Mass/Volume

= 71.68/ 8

= 8.96 g/cm³

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When the volume of a gas is
changed from m3 to 15.5 m3
the temperature will change from
159 K to 456 K.
Assume that the number of moles and the
pressure remain constant.

When the volume of a gas ischanged from m3 to 15.5 m3the temperature will change from159 K to 456 K.Assume

Answers

Charles law states that there is a directly proportional relationship between the volume and the temperature of the gas at certain pressure.

Therefore,

V1/T1 = V2/T2

V1 is unknown

T1 = 159K

V2 = 15.5m3

T2 = 456K

V1/159 = 15.5/456

V1 = (15.5*159)/456 = 5.404m3.

When the volume of a gas is changed from 5.404 m3 to 15.5 m3 the temperature will change from 159 K to 456 K.

what would happen tot eh ratio of copper percipate to iron consumed if you had let the reaction for less time?

Answers

The accepted iron:copper ratio ranges from 1:1 to 15:1. For comparison, our Optimizers have an average iron:copper ratio of 12.6.

What is the meaning of participating?

In our daily lives, many chemical reactions take place. Burning, corrosion, food preparation, and digestion are typical examples of these reactions. Precipitation reactions are a significant class of chemical reactions. Two different soluble salts that are in aqueous solutions combine in these reactions to create two products. One of these products, which is referred to as the "precipitate," is insoluble in the solution and precipitates out.

Supplemental zinc can reduce the absorption of copper and raise demand for it. Birth control, eating a lot of foods high in copper like liver, and leaching copper from copper pipes and pans can all have an adverse effect on how well zinc and iron are absorbed.

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Which job title describes a person with a career in green energy?

Answers

Answer:

Natural resource professional

Explanation:

The job title that describes a person with a career in green energy is a hydroelectric technician. The correct option is c.

What is green energy?

Green energy is renewable energy and these energies are produced by renewable resources. Renewable resources are the resources that will not be reduced, and these natural resources are present, and these energies can reproduce again by these resources.

The hydroelectric technician is the person who checks the technical problems of a hydroelectric power plant. Hydroelectricity is produced by water.

This is a renewable resource, and it does not produce any kind of pollution, So a hydroelectric technician will be a job title that describes a person with a career in green energy.

Therefore, the correct option is c., hydroelectric technician.

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The question is incomplete. Your most probably complete question is given below:

Elevator installer

sewing machine operator

hydroelectric technician

animal trainer

How much of a 200 g sample of Gold is left after 13.5 days if its half-life is 2.70 days?

Answers

Answer: 3.2

Explanation:

Microscopic interface asymmetry and spin-splitting of electron subbands in semiconductor quantum structures. Solid State Commun

Answers

The microscopic interface asymmetry of grown semiconductor heterostructures.

The dispersion of restricted electrons. beginning from a multiband envelope formulation we practice matrix perturbation theory to derive specific expressions. Interface asymmetry, which in the conduction band Hamiltonian appear as a warping and a spin-splitting term. The warping term consequences in an inequivalence of the dispersion.

The microscopic interface asymmetry of grown semiconductor heterostructures that gives upward thrust to heavy-light hole coupling even at 0 in-plane wave vector, modifies also the dispersion of restricted electrons. beginning from a multiband envelope method we practice matrix perturbation principle to derive explicit expressions as a result of this interface asymmetry, which inside the conduction band.

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Consider the two reactions of iron ions, one with thiocyanate (SCN) ions and one with chloride (Cl^-) ions. Fe^3+ +SCN^- ↹ FeSCN^2+ Fe^3+ + 4CL^- ↹ FeCl4^- If you create an equilibrium mixture from Fe^3+ and SCN^- ions, adding C^- ions will Choose... because Choose...

Answers

The equilibrium shifts towards the formation of FeCl4 ⁻ complex ions.

What happens to the equilibrium mixture of Fe³+ and SCN ⁻ ions when Cl ⁻ ions are added?

When adding Cl ⁻ ions to an equilibrium mixture of Fe³+ and SCN ⁻ ions, the equilibrium will shift towards the formation of FeCl4 ⁻  complex ions. This is because the formation of FeCl4^- is favored by the reaction Fe^3+ + 4Cl^- ↔ FeCl4^-.

The addition of Cl ⁻ ions increases the concentration of Cl ⁻  in the solution, which according to Le Chatelier's principle, will shift the equilibrium in a direction that reduces the increase in Cl ⁻ concentration. In this case, the equilibrium will shift towards the right to consume the excess Cl^- ions and form more FeCl4 ⁻ complex ions.

By forming more FeCl4^- ions, the concentration of Fe³+ ions will decrease, leading to a decrease in the formation of FeSCN ²  + complex ions. Therefore, the addition of Cl ⁻  ions will result in a decrease in the concentration of FeSCN ²  + complex ions in the equilibrium mixture.

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How many grams of si3n4 can be produced from 0.46 moles of n2 step by step?

Answers

16.14 grams of Si3N4 can be produced from 0.46 moles of N2.

To determine the number of grams of Si3N4 that can be produced from 0.46 moles of N2, we need to use the balanced chemical equation for the reaction that produces Si3N4. Let's assume the balanced equation is:

3Si + 4N2 → Si3N4

From the balanced equation, we can see that it takes 4 moles of N2 to produce 1 mole of Si3N4. Therefore, we need to convert the given moles of N2 to moles of Si3N4 and then to grams.

Step 1: Convert moles of N2 to moles of Si3N4

Since the mole ratio of N2 to Si3N4 is 4:1, we can use the ratio to convert moles of N2 to moles of Si3N4:

0.46 moles N2 × (1 mole Si3N4 / 4 moles N2) = 0.115 moles Si3N4

Step 2: Convert moles of Si3N4 to grams

To convert moles of Si3N4 to grams, we need to know the molar mass of Si3N4. The molar mass of Si3N4 can be calculated as follows:

(3 × atomic mass of Si) + (4 × atomic mass of N)

= (3 × 28.09 g/mol) + (4 × 14.01 g/mol)

= 84.27 g/mol + 56.04 g/mol

= 140.31 g/mol

Now, we can use the molar mass to convert moles of Si3N4 to grams:

0.115 moles Si3N4 × (140.31 g Si3N4 / 1 mole Si3N4) = 16.14 grams Si3N4

Therefore, approximately 16.14 grams of Si3N4 can be produced from 0.46 moles of N2.

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Calculate the atomic mass of the following elements from
the percentage of their isotopes.
78.99% of 24 Mg, 10.00% of 25 Mg, 11.01% of 26 Mg

Calculate the atomic mass of the following elements fromthe percentage of their isotopes.78.99% of 24

Answers

Answer: 24.32 AMU

Explanation:

See attachment.

Calculate the atomic mass of the following elements fromthe percentage of their isotopes.78.99% of 24

How do we know what stars are made of?
1. Add spectroscopy evidence and describe the technology of seeing spectral lines even that are NOT in the visible range of our eyes.
2. What hot gasses is our Sun made of? How do we know? Include the spectral lines from the sun and the individual gasses for a match
3. Choose another space body: a star or nebula in deep space, and identify its composition and what technology was used to view it.

Answers

These observational techniques and technologies enable astronomers to unravel the complex composition of stars and celestial objects, shedding light on the mysteries of the universe.

1. We know what stars are made of through the use of spectroscopy. Spectroscopy is a scientific technique that analyzes the interaction between light and matter. It allows us to study the unique fingerprint of light emitted or absorbed by different elements.

By using spectroscopy, scientists can examine the spectral lines, which are specific wavelengths of light that are either emitted or absorbed by different elements. These spectral lines provide crucial information about the chemical composition of stars and other celestial objects.

Spectroscopy extends beyond the visible range of our eyes. There are different types of spectroscopy, such as ultraviolet, infrared, and X-ray spectroscopy, which allow us to observe spectral lines that are not visible to us directly. These technologies use specialized detectors and instruments to detect and analyze these wavelengths of light, providing valuable insights into the composition of stars and other objects.

2. Our Sun is primarily composed of hot gases. Through spectroscopy, scientists have identified the specific elements present in the Sun's atmosphere. The prominent spectral lines observed in the Sun's spectrum correspond to elements such as hydrogen, helium, and trace amounts of other elements like oxygen, carbon, and iron.

The spectral lines from the Sun match with known spectral lines of these elements, confirming their presence in the Sun's composition. By studying the intensity and characteristics of these spectral lines, scientists can deduce the abundance and temperature of the different gases in the Sun.

3. Let's consider the Orion Nebula as an example of a deep space object. The composition of the Orion Nebula has been studied using a combination of technologies, including optical spectroscopy and infrared observations.

Optical spectroscopy helps to identify the presence of elements such as hydrogen, helium, oxygen, nitrogen, and other trace elements in the nebula. By analyzing the spectral lines emitted or absorbed by these elements, scientists can determine their abundance and temperature.

Infrared observations, on the other hand, allow scientists to probe the dust particles present in the nebula. By studying the infrared emission from the dust, scientists can gain insights into the chemical composition of the interstellar material and molecules present in the Orion Nebula.

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2-methylhexane shows an intense peak in the mass spectrum at m/z = 43. propose a likely structure for this fragment.

Answers

The m/z = 43 peak in the mass spectrum of 2-methylhexane suggests the presence of a specific fragment with that mass.

To propose a likely structure for this fragment, we need to consider the possible fragmentation patterns in 2-methylhexane.

One possible fragmentation pattern involves the loss of a methyl group (\(CH_{3}\)) from the molecule. This would result in a fragment with a mass of 15 (m/z = 43 - 15 = 28). The fragment with a mass of 28 can be attributed to a methyl cation (CH3+).

Therefore, a likely structure for the m/z = 43 fragment in the mass spectrum of 2-methylhexane is a methyl cation (CH3+). This suggests that during fragmentation, 2-methylhexane loses a methyl group, resulting in the formation of a CH3+ fragment with a mass of 43.

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Question id : 33318921

Answer:

The correct structure for the fragment with m/z = 43 in the mass spectrum of 2-methylhexane is a methyl cation (CH3+).

The intense peak at m/z = 43 indicates the presence of a fragment with a molecular ion having a charge of +1 (indicating a cation) and a mass-to-charge ratio of 43. Since 2-methylhexane has a molecular formula of C7H16, the fragment with m/z = 43 should have one fewer hydrogen atom than the molecular ion.

By removing one hydrogen atom from 2-methylhexane, we can form a methyl cation (CH3+) as the likely structure for the fragment with m/z = 43. The methyl cation consists of a single carbon atom bonded to three hydrogen atoms, and its formation can be attributed to the loss of a hydrogen atom from the methyl group of 2-methylhexane.

To summarize, the likely structure for the fragment with m/z = 43 in the mass spectrum of 2-methylhexane is a methyl cation (CH3+).

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removal with base of an acidic proton from acetophenone results in the formation of a nucleophilic species called an .

Answers

Enolate production, a nucleophilic compound that interacts with electrophiles.

An explanation of nucleophilic species

A nucleophile is a chemical entity in chemistry that establishes bonds by giving up a pair of electrons. Nucleophiles include all ions and molecules with a free pair of electrons or at least one pi bond. Lewis bases are nucleophiles because they donate electrons.

How does a nucleophile develop?

As a nucleophile, the hydroxide ion contributes two electrons to an electrophilic atom, in this case the carbon atom, to create a new covalent bond. A hydroxide ion is said to be behaving as a "base" when it transfers a pair of electrons to a (acidic) proton to create a new covalent bond, as we've seen before.

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In a 3.21g sample of the hydrate, CuSO4 • 10H2O (339.8 g/mol), how many grams of water are expected?

Answers

Therefore, 9.49 grams of water is expected in the given 3.21 g sample of CuSO4 • 10H2O.

To determine the number of water molecules in the given hydrate, CuSO4 • 10H2O, we'll need to find out the molar mass of the compound and the molar mass of water to make a comparison.

The molar mass of CuSO4 • 10H2O is calculated as:

CuSO4 → 159.6 g/mol10H2O → 180.16 g/mol (18.016 g/mol × 10)CuSO4 • 10H2O → 159.6 g/mol + 180.16 g/mol

= 339.76 g/mol (rounded to three significant figures)

Thus, we can see that the molar mass of CuSO4 • 10H2O is 339.76 g/mol.

We know that this hydrate consists of ten molecules of water, each having a molar mass of 18.016 g/mol (which is the same as the molar mass of water), and one molecule of CuSO4 with a molar mass of 159.6 g/mol.

Therefore, the number of moles of water in the sample is:

(10 × 18.016 g/mol) ÷ 339.76 g/mol = 0.527 moles

So, the mass of water is equal to its molar mass multiplied by the number of moles.

The mass of water is:

0.527 mol × 18.016 g/mol = 9.49 g

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Calculate the pOH of a solution that contains 2.4 × 10^-8 M H3O⁺ at 25°C.
A) 2.40
B) 6.38
C) 7.62
D) 5.38
E) 8.62

Answers

The pOH of the solution is 6.38 (Option B).

How to calculate the pOH of a solution?


1. First, calculate the pH of the solution. The pH is the negative logarithm of the H₃O⁺ concentration. Use the formula:
  pH = -log[H₃O⁺]

2. Plug in the given H₃O⁺ concentration:
  pH = -log(2.4 × 10^-8)

3. Calculate the pH:
  pH ≈ 7.62

4. Next, calculate the pOH using the relationship between pH and pOH at 25°C:
  pH + pOH = 14

5. Solve for pOH:
  pOH = 14 - pH

6. Plug in the calculated pH:
  pOH = 14 - 7.62

7. Calculate the pOH:
  pOH ≈ 6.38

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Identify the bases below that can be used to deprotonate a terminal alkyne.

a. NaNH
b. NaOCH
c. NaH
d. NaOH

Answers

The bases given that can be used to deprotonate a terminal alkyne include a. NaNH₂ and c. NaH.

How to find the bases that can deprotonate a terminal alkyne?

Terminal alkynes are organic compounds that contain a carbon–carbon triple bond at the end of the carbon chain. They are relatively acidic and can be deprotonated by a strong base to form an acetylide ion.

Sodium amide is a very strong base ( pKa of its conjugate acid, NH3, is ~38 ), so it can deprotonate a terminal alkyne. Sodium hydride is a very strong base ( pKa of its conjugate acid, H2, is ~35 ), so it can deprotonate a terminal alkyne.

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The above map shows the route of a car traveling from home to the parkIf the car is traveling at a constant speed, does the car accelerate at any point on the route? Yes or No, and explain your reasoning.

The above map shows the route of a car traveling from home to the parkIf the car is traveling at a constant

Answers

Yes, The car will accelerate if its velocity changes in magnitude, in direction, or both. If a car is traveling at a constant speed of 35 m/s, it can be accelerating if its direction of motion is changing.

What is the molarity of a solution of kno3 (molecular mass = 101 that contains 404 grams of kno3 in 2. 00 liters of solution? a 1. 00 b 2. 00 c 0. 500 d 4. 00?

Answers

The molarity of a solution of KNO₃ (molecular mass = 101) that contains 404 grams of KNO₃ in 2.00 liters of solution is 0.500 M. Option C is correct.

Molarity is defined as the number of moles of solute per liter of solution. To calculate the molarity of the given solution of KNO₃, we first need to calculate the number of moles of KNO₃ present in the solution.

Number of moles of KNO₃ = mass of KNO₃ / molar mass of KNO₃

                                             = 404 g / 101 g/mol

                                              = 4.00 mol

Now, we can calculate the molarity of the solution using the formula:

Molarity = number of moles of solute / volume of solution in liters

Molarity = 4.00 mol / 2.00 L

Molarity = 2.00 M

Therefore, the molarity of the solution is 0.500 M. Option C is correct.

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based on the brønsted-lowry theory of acids and bases, which of the following species can act as both a conjugate acid and a conjugate base?

Answers

Since water is amphoteric, it can function as both a Brnsted-Lowry acid and a base. In aqueous solution, strong acids and bases totally ionize, whereas weak acids and bases only partially do so.

What is the brønsted-lowry theory of acids and bases?

The acid-base theory of Bronsted-Lowry. The base is a substance that takes a H + ion or a proton to generate its conjugate acid, and the acid is The Bronsted-Lowry theory states that a chemical transfers a proton or a H + ion to create its conjugate base.

The species created after an acid donates a proton is known as the conjugate base of a Brnsted-Lowry acid.

Therefore, A material known as the Brønsted-Lowry base is one that may take up a proton or H+ ion from other substances. A base reforms when a conjugated acid donates a proton.

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Since water is amphoteric, it can function as both a Brnsted-Lowry acid and a base. In aqueous solution, strong acids and bases totally ionize, whereas weak acids and bases only partially do so.

What is the brønsted-lowry theory of acids and bases?

The acid-base theory of Bronsted-Lowry. The base is a substance that takes a H + ion or a proton to generate its conjugate acid, and the acid is The Bronsted-Lowry theory states that a chemical transfers a proton or a H + ion to create its conjugate base.

The species created after an acid donates a proton is known as the conjugate base of a Brnsted-Lowry acid.

Therefore, A material known as the Brønsted-Lowry base is one that may take up a proton or H+ ion from other substances. A base reforms when a conjugated acid donates a proton.

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discharge by the combination of Nitrogen and oxygen​

Answers

Answer:

NO2

Explanation:

N = Nitrogen

O = Oxygen

Answer:

NO. 2.

is the answer

hopes this helps

Question :-
How to balance chemical equations?

I need steps
Don't spam from Go0gle
!!!!CLASS 10 CHEMISTRY!!!!​

Answers

Answer:

the main aim of balance in an equation is making show that the total number of substances on the reactant side is equal to the total number of substances on the product side

Explanation:

so if we were to balance the equation of water water is a compound containing two molecules of hydrogen and one molecule of oxygen therefore

H+O=H2O

Step 1:

Check number of atoms on reactant side and product side

Step 2:

Make a table with elements name and their number of product and reactant side as shown in ncert

Step 3:

Multiply the numbers with a common multiple to make them same

Lets understand with some examples;

\(H+O_2= H_2O\)

Element | Reactant | Product

H | 1 × 4 | 2×2

O | 2 | 1 × 2

\(4H+O_2= 2H_2O\)

A gas in a rigid container at 25°C has a pressure of 0. 96 atm. A change in temperature causes the pressure to increase to 1. 25 atm. What is the new temperature of the gas? Use StartFraction P subscript 1 over T subscript 1 EndFraction equals StartFraction P subscript 2 over T subscript 2 EndFraction. â€""44. 2°C 32. 6°C 115°C 388°C.

Answers

The new temperature of the gas is 115 °C

From the question given above, the following data were obtained:

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K Initial pressure (P₁) = 0.96 atmNew pressure (P₂) = 1.25 atmNew temperature (T₂) =?

The new temperature of gas can be obtained as follow:

\( \frac{P_1}{T_1} = \frac{P_2}{T_2} \\ \\ \frac{0.96}{298} = \frac{1.25}{T_2} \\ \\ cross \: multiply \\ \\ T_2 \times 0.96 = 298 \times 1.25 \\ \\ divide \: both \: side \: by \: 0.96 \\ \\T_2 = \frac{298 \times 1.25 }{0.96} \\ \\ T_2 = 388 \: K \\ \\ subtract \: 273 \: from \: 388 \: to \: express \: the \: answer \: im \: \degree \: C \\ \\ T_2 = 388 - 273 \\ \\ T_2 = 115 \: \degree \: C \)

Therefore, the new temperature is 115 °C

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co2(g)+H20+148Kcal---->H2Co3 Endotérmica o exotérmica

Answers

endothermic

requires energy to occure

Which is the load?

Lever Diagram
B
E
C
D
A

Which is the load?Lever DiagramBECDA

Answers

Answer:

A is the load.

Explanation:

A is the load.

B is the resistance arm.

C is the fulcrum.

D is the effort arm.

E is the effort.

I hope this helps!

Consider the sample space S={ copper, sodium, nitrogen, potassium, uranium, oxygen, zinc }, and the events A={ copper, sodium, zinc } B={ sodium, nitrogen, potassium\} C={0oxygen} Draw the Venn diagram and list the elements of the sets corresponding to the following events: (a) A ′
(b) (A∩B ′
)∪C ′
(c) A∪C (d) A∩B∩C (e) (A ′
∪B ′
∩(A ′
∩C)

Answers

The Venn diagram can be drawn and the elements corresponding to the given events can be listed as follows:

What are the elements of the sets corresponding to the events A', (A∩B')∪C', A∪C, A∩B∩C, and (A'∪B')∩(A'∩C) based on the given sample space and events?

The Venn diagram can be drawn by representing the sample space S as a rectangle and representing each event as a circle within the rectangle. The elements within each circle represent the elements belonging to that event.

(a) A' represents the complement of event A, which includes all the elements in the sample space S except for the elements in A. Therefore, A' = {nitrogen, potassium, uranium, oxygen}.

(b) (A∩B')∪C' can be evaluated by first finding the intersection of A and the complement of B, which is {copper, zinc}. Then, taking the union of this intersection with the complement of C, which is {copper, sodium, nitrogen, potassium, uranium, zinc}. So, (A∩B')∪C' = {copper, sodium, nitrogen, potassium, uranium, zinc}.

(c) A∪C represents the union of events A and C, which includes all the elements that belong to either A or C. Therefore, A∪C = {copper, sodium, zinc, oxygen}.

(d) A∩B∩C represents the intersection of events A, B, and C, which includes the elements that belong to all three events. Since there is no common element in all three events based on the given information, A∩B∩C is an empty set (∅).

(e) (A'∪B')∩(A'∩C) can be evaluated by taking the union of the complements of A and B, which is {nitrogen, potassium, uranium, oxygen}, and finding the intersection of this union with the intersection of the complement of A and C, which is {oxygen}. Therefore, (A'∪B')∩(A'∩C) = {oxygen}.

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Staygold1967 avatar
Staygold1967
1 hour ago
Chemistry
High School
PLEASEEE HELPPPP!
1. Your original sample of Manganese-56 is 20.0 mg. How much is left after 3 half

lives? Remember to round to the correct number of significant figures and use units (mg).


2. Tritium is a radioactive form of hydrogen with a half-life of 12.3 years. How much of the 48.0 mg of tritium is still radioactive after 98.4 years?


Make sure to round to the correct number of significant figures and use units (mg).


3. How much of a 1.00 g polonium-214 sample remains after 818 microseconds? The half-life of polonium-214 is 163.7 microseconds.


Make sure to round to the correct number of significant figures and use units (g).

Answers

B the answer is I hope helps u good luck

A 50.0 mL sample of 1.00 M solution of MgSO4 is mixed with 50.0 mL of 2.00 M NaOH in a calorimeter. The temperature of both solutions was 23.2 degrees C before mixing and 29.3 degrees C after mixing. The heat capacity of the calrimeter is 15 J/degrees C. From these data, calculate the enthalphy change for the process MgSO4 + NaOH --> Mg(OH) + Na2SO4

Answers

The enthalpy change for the process MgSO₄ + NaOH → Mg(OH) + Na₂SO₄ is 132.065 J/mol.

Total volume of the solution:

= 50 + 50

= 100mL

Mass of the solution (water) = 100mL × 1gm/mL = 100gm

Heat absorbed by the solution

= 100gm ×  4.18 J/°C/gm ×  (29.3-23.2)

=2549.8 J

Heat absorbed by the calorimeter:

= 15J/°C ×  (29.3-23.2) = 91.5 J

Total heat absorbed:

= 2549.8 J + 91.5 J

= 2641.3 J

Moles of MgSO4 =1.00M/0.05 L = 20mol

Enthalpy of reaction per mole of MgSo4 reacted = 2641.3 J ÷ 20mole

= 132.065 J/mol

Thus, enthalpy change for the process  MgSO₄ + NaOH → Mg(OH) + Na₂SO₄ is 132.065 J/mol.

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four each two-carbon increase in length of a saturated fatty acid chain, how many additional moles of atp can be formed upon complete oxidation of one mole ofthe fatty acid to co2 and h2o

Answers

For each two-carbon increase in length of a saturated fatty acid chain, approximately 17 additional moles of ATP can be formed upon complete oxidation of one mole of the fatty acid to CO2 and H2O.

This is because the β-oxidation pathway breaks down the fatty acid into two-carbon units, generating acetyl-CoA, which enters the citric acid cycle (Krebs cycle) to produce ATP through oxidative phosphorylation.

During β-oxidation, each round produces one molecule of NADH, one molecule of FADH2, and one molecule of acetyl-CoA. The NADH and FADH2 subsequently enter the electron transport chain to generate ATP. Each round of β-oxidation produces 3 ATP molecules from NADH and 2 ATP molecules from FADH2, totaling 5 ATP molecules. Therefore, with each two-carbon increase in the fatty acid chain, approximately 17 additional moles of ATP can be formed.

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PLEASE HELP!! Due in a few minutes!!! BRAINLEST TO WHO ANSWERS FIRST!!!


2.2.4 Study: Reaction Rates
POSSIBLE POINTS: 1.
Collisions between reactant molecules lead to a reaction when the molecules have the correct orientation and enough kinetic energy


True
False

Answers

Answer:

True

Explanation:

Hope this isnt too late

Question 11
Which formula represents a hydrocarbon?


C₂H6
C₂H5OH
C₂H5Cl
C₂H6O

Answers

Answer:

C₂H6

Explanation:

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A

A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:

A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.

B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.

D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.

Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.

In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A

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