What is the name of the compound K3N

Answer:

they bonding

Explanation:

dfffffffffffffff

Answer:

It travel's about 4,000 km through the Earth in 13 minutes.

Answer:

4,000 km is the correct answer!!!

Answer:

only compound have uniform compositiob

Answer:

Answer is A.

Explanation:

Answer:

false

Explanation:

Answer: metal turn orange and weaker as it gets oxidised

Explanation:

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:

4 5 6

Explanation:

hydrogen bonds between molecules are overcome when water boils.

Because of the relative strength of these hydrogen bonds, water is a liquid at ambient temperature. Hydrogen bonds must be broken in order to convert water from liquid to vapour (i.e., boil it).

The bonds that rupture as water boils are known as hydrogen bonds. This kind of link is substantially weaker than a covalent bond and is referred to as an intermolecular force of attraction. The molecules' increased mobility as a result of the kinetic energy addition causes this bond breaking.

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Answer::

Explanation::

Answer:

lol ok 1+1=2 2 x 2=4

have a good day :)

Explanation:

Answer:  oke

Explanation: have a goood day!

Answer:

atoms contain tiny negatively charged subatomic particles or electrons

Answer:

The new volume of the gas is 278.7 mL.

Explanation:

To solve this problem, we can use the combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

where P is the pressure, V is the volume, and T is the temperature.

We can start by plugging in the given values for the initial state of the gas:

P₁ is not given, so we can assume it remains constant.

V₁ = 325 mL

T₁ = 57°C + 273.15 = 330.15 K

Now we can solve for P₂V₂/T₂:

P₂V₂/T₂ = P₁V₁/T₁

We want to solve for V₂, so we can rearrange the equation:

V₂ = (P₁V₁/T₁) * T₂/P₂

We are given that the pressure remains constant, so P₁ = P₂.

Now we can plug in the remaining values:

V₂ = (P₁V₁/T₁) * T₂/P₂

V₂ = (P₁ * 325 mL / 330.15 K) * (10°C + 273.15) / P₁

V₂ = 278.7 mL

Therefore, the new volume of the gas is 278.7 mL.

Hope I helped you!

The instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

To find the instantaneous rate of reaction at 17 minutes, we can use the concept of differential calculus and estimate the slope of the tangent line at t=17 on the graph of rate versus time.

To do this, we can use the formula for the slope of a line

slope = (change in y) / (change in x)

In this case, the "y" values are the rates of reaction and the "x" values are the times. We want to find the slope at t=17, so we can choose two points that are very close to t=17, such as t=15 and t=20. Then, we can use these values to estimate the slope at t=17

slope = (rate at 20 min - rate at 15 min) / (20 min - 15 min)

slope = (0.135 - 0.223) / (20 - 15)

slope = -0.178

This slope represents the instantaneous rate of reaction at t=17. However, since it has a negative value, it means that the rate of reaction is decreasing at t=17.

Therefore, the instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

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Answer:

4.515 x 10^24

Explanation:

Answer:its saturated   or  unsaturaded

Explanation:

The correct answer is: K3 = 1/K1 x 1/K2

The equilibrium expression for reaction 3 may be written using the equilibrium expressions for reactions 1 and 2 and the expression for K3.

First, we need to reverse the equation for reaction 1:

CH4(g) + H2O(g) ⇆ CO(g) + 3H2(g)

Next, we need to multiply the equation for reaction 2 by 3:

3CO2(g) + 3H2(g) ⇆ 3CO(g) + 3H2O(g)

Now we can add the two equations to obtain the equation for reaction 3:

CH4(g) + 2H2O(g) ⇆ CO2(g) + 4H2(g)

Just substituting the equilibrium equations for reactions 1 and 2 into the equation for reaction 3 will yield the equilibrium expression for reaction 3:

K3 = ([CO][H2]^4)/([CH4][H2O]^2[CO2])

Therefore, the correct answer is:

K3 = 1/K1 x 1/K2

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Answer: A) Volume of a gas B) Number of molecules C) temperature &pressure

Explanation: The law also states that the Kelvin temperature and the volume will be in direct proportion when the pressure exerted on a sample of a dry gas is held constant.

While tumor marker test results can be useful, they are not conclusive. A low result does not imply that you do not have cancer or that you are in remission.

CA 15-3, for example, is raised in less than half of patients with early breast cancer and in more than 80% of those with metastatic breast cancer. Three tumor markers, cancer antigen 15-3 (CA 15-3), cancer antigen 27.29 (CA 27.29), and carcinoembryonic antigen (CEA), have been used in breast cancer care to help monitor metastatic breast cancer (advanced disease), but they have not been found to be useful in detecting a breast cancer recurrence or extending lives. If the level falls, the treatment is effective. If it rises, the cancer may be spreading.

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To determine if the piece of plastic has a density greater or less than 1 g/cm³, the piece of plastic is placed in water, if it sinks, it has a greater density, but if it floats, it has a lesser density.

The density of a substance measure how compact the substance is.

For fluids such as water, objects that are denser than water will sink in water. However, if the density is less than that of water, it will float in water.

The density of water is 1 g/cm³.

Hence, objects that have densities greater than 1 g/cm³ will sink in water, whereas objects that have densities less than 1 g/cm³ will float in water.

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Answer:

That would be 4.17742995 * 10^13 :)

Explanation:

Answer:

2.58g

Explanation:

First calculate the moles of butane used in the reaction

moles = mass÷molar mass

= 0.85÷58

= 0.0147

According to the stoichiometric ratio:

C4H10 : CO2 = 2:8

moles of CO2 =(8÷2)×0.0147

=0.0586 moles

mass of CO2 = 0.0586×44

= 2.58g

2.58g is the mass of carbon dioxide produced when 0.85 grams of butane (\(C_4H_{10}\)) reacts with oxygen according to the following balanced chemical equation:  \(2C_4H_{10} + 13O_2 - > 8CO_2 (g) + 10H_2O (g)\)

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilogram of carbon 12; its symbol is “mol”.

Firstly calculate the moles of butane used in the reaction

moles = \(\frac{mass}{molar \;mass}\)

= \(\frac{0.85}{58}\)

= 0.0147

According to the stoichiometric ratio:

\(C_4H_{10}\) : \(CO_2\) = 2:8

moles of \(CO_2\) = (\(\frac{8}{2}\)) × 0.0147

=0.0586 moles

mass of \(CO_2\) = 0.0586×44

= 2.58g

Hence, option A is correct.

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The right equation to solve for the final volume would be: P1V1/T1 = P2V2/T2, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature.

Given: V1 = 1.50 L P2 = 3.00 atm P1 = 2.00 atm

T1 = 373 K

(Temperature drop) T2 = 298 K

We may rewrite the equation to find V2:

V2 = (P2T1) / (P1V1T2)

V2 is calculated as (2.00 atm)(1.50 L)(298 K) / (3.00 atm)(373 K).

V2 = 0.751 L

As a result, the volume drops and is 0.751 L in total.

Answer: Reduce

Given:

10 L is the initial volume (Vi).

1545 g is the initial mass (mi).

1554.5 g is the final mass (mf).

Volumetric specific (v) = 0.01 L/g

The ultimate volume (Vf) must be determined usingThe equation:

Vf = mf * v

Vf = (1554.5 g) * (0.01 L/g)

Vf = 15.545 L

The ultimate volume is 15.54 L as a result.

Answer: Upgrading

Given:

5.0 L is the initial volume (Vi).

30°C = 303 K is the initial temperature (Ti).

Final temperature (Tfn) is equal to –10 °C or 263 K.

Utilising the formula: we can determine the final volume (Vf).

(Vi * Ti) / Tfn = Vf

Vf = (5.0 L * 303 K) / 263 K

Vf = 5.76 L

The total volume is 5.76 L as a result.

Answer: Upgrading

Given:

15 L is the initial volume (Vi).

4.0 atm is the initial pressure (Pi).

3.0 atm is the final pressure (Pf).

Utilising the formula: we can determine the final volume (Vf).

Pi * Vi equals Pf * Vf

(Pi * Vi) / Pf = Vf

Vf is equal to 4.0 atm x 15 L / 3.0 atm.

Vf = 20 L

Consequently, 20 is the total volume.

Answer: Upgrading

Given:

Initial volume (Vi) equals 21.0 L.

Initial temperature (Ti) is 70.0 °C, or 343 K.

45.0 L is the final volume (Vf).

We may use the following formula to determine the final temperature (Tfn):

As Vf / Tfn = Vi / Ti

Vf * Ti = Tfn / Vi

Tfn = (45.0 L * 343 K) / 21.0 L

Tfn= 733.4 K

The ultimate temperature is 733.4 K as a result.

Answer: Upgrading

Given:

2.5 L is the initial volume (Vi).

5.0 L is the final volume (Vf).

(Ti) = 273 K initial temperature

We may use the following formula to determine the final temperature (Tfn):

As Vf / Tfn = Vi / Ti

Vf * Ti = Tfinal  / Vi

Tfn = (5.0 L * 273 K) / 2.5 L

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The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.

1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.

2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.

3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.

4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.

5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.

6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.

7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.

By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.

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The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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Answer:

lungs

Explanation:

Answer: The correct answer is 5.00 moles

Explanation: