What is the molarity when 3.4 moles of NaCl are dissolved to make a total of 5.5 liters of solution? Babe

The amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

To find the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C, we can use the equation Q = mcAT.
First, we need to find the value of m, which is the mass of the water in grams. In this case, it is given as 200 grams.
Next, we need to find the value of AT, which is the change in temperature in degrees Celsius.

This can be calculated by subtracting the initial temperature from the final temperature, which gives us 60 C - 20 C = 40 C.
The specific heat capacity of water, C, is given as 4.18 Joules per gram per degree Celsius.
Now we can plug in the values into the equation:
Q = mcAT
Q = (200 g) x (4.18 J/g°C) x (40°C)
Q = 33,440 J
Therefore, the amount of heat energy absorbed when 200 grams of water are heated from 20 C to 60 C is 33,440 Joules.

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Answer:

53.7 L

Explanation:

The volume occupied by 35.2 g of methane gas at 25 °C and 1.0 atm. is 55.9 L.

Given to us is temperature, pressure, universal gas constant, and mass of methane gas, we need to find the volume occupied by the gas.

To calculate the volume occupied by the methane gas, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure (in atm)

V = volume (in liters)

n = number of moles

R = ideal gas constant (0.08206 Latm/(Kmol))

T = temperature (in Kelvin)

First, we need to convert the given temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 25 °C + 273.15

T(K) = 298.15 K

Next, we calculate the number of moles of methane gas using its molar mass:

molar mass of CH₄ = 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol

n = mass/molar mass

n = 35.2 g / 16.04 g/mol

n = 2.19 mol

Now we can substitute the values into the ideal gas law equation:

PV = nRT

V = (nRT) / P

V = (2.19 mol × 0.08206 Latm/(Kmol) ×298.15 K) / 1.0 atm

V = 55.9 L

Therefore, the volume occupied by 35.2 g of methane gas at 25 °C and 1.0 atm is 55.9 liters.

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52.6g and 23.8mL necessary 100mL of a solution that is simultaneously 15.6 mg/mL malonic acid, 3.38 mg/mL MnSO4 • H2O, and 0.03% starch to make this solution.

What is malonic acid?

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. Because it interferes with respiration, malonic acid is extremely harmful, especially in cases of cancer and other degenerative disorders (the making of ATP in mitochondria). Malonic acid is a somewhat unstable substance with limited practical uses. Beetroot contains its calcium salt, however the acid itself is often made by hydrolyzing diethyl malonate.

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Answer:

Explanation:

·  44 g NaCl Explanation: The problem provides you with the molarity and volume of the target

The answer is rounded to two sig figs, the number of sig figs you have for the molarity of the solution.

The mass of a solute needed to prepare a solution with given volume is find by molarity. The mass of NaCl need to make a 138.1 mL solution of 0.190 M is 1.53 grams.

Molarity of a solution is a term to express its concentration. Mathematically, it is the ratio of no.of moles of solute to the volume of solution in litres.

Given that, the volume of solution is 138.1 mL. One litre solution is 1000 mL. Hence, 138.1 mL is 0.1381 L. The molarity of the solution is 0.190 M. From these data we can calculate the no.of moles of NaCl as below:

no.of moles = molarity × volume of solution in L

                    =  0.190 M × 0.1381 L

                    = 0.0262 moles.

This is the no.of moles required to make the solution.

Molecular mass of NaCl = 58.4 g/mol.

Thus mass of 0.0262 moles of NaCl = 0.0262  mol × 58.4 g/mol

                                                             = 1.53 g.

Therefore, the mass of NaCl required is 1.53 g.

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Answer:

Yes it is stable because they are both sharing electrons resulting in stability.

Explanation:

Answer:

4C2H5NH2(g) + 15O2(g) →  8CO2(g) + 14H2O(g) + 2N2(g)

Explanation:

The balanced chemical equation  for the given chemical reaction is 4 C₂H₅NH₂(g) + 15 O₂(g) →  8 CO₂(g) + 14 H₂O(g) + 2 N₂(g).

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Answer: 682 grams

Explanation:

The balanced chemical reaction is:

\(4Fe+3O_2\rightarrow 2Fe_2O_3\)

\(O_2\) is the limiting reagent as it limits the formation of product and \(Fe\) is the excess reagent.

According to stoichiometry :

3 moles of \(O_2\) produce = 2 moles of \(Fe_2O_3\)

Thus 6.40 moles of \(O_2\) will produce=\(\frac{2}{3}\times 6.40=4.27moles\)  of \(Fe_2O_3\)

Mass of \(Fe_2O_3=moles\times {\text {Molar mass}}=4.27moles\times 159.69g/mol=682g\)

Thus 682 g of \(Fe_2O_3\) will be produced from 6.40 moles of oxygen

Answer:

Ions.

Explanation:

Hello!

In this case, since iron is a metal which has lots of uses in the design of metallic alloys and materials, when it is at its ground state we say it is just Fe; however, since it is a metal, it is very likely to lose electrons and therefore getting positively charged as +2 or +3, say:

\(Fe^{2+}\\\\Fe^{3+}\)

Thus, since they are positively charged, they are classified as cations, which are ions.

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The balanced net ionic equation for the reaction between potassium sulfide and lead(II) nitrate is Pb²⁺(aq) + S²⁻(aq) → PbS(s)

From the question, we are to write the balanced net ionic equation for the given chemical reaction.

The given chemical reaction is

K₂S(aq) + Pb(NO₃)₂(aq) →

The between potassium sulfide and lead(II) nitrate will produce potassium nitrate and lead sulfide.

That is,

K₂S(aq) + Pb(NO₃)₂(aq) → KNO₃(aq) + PbS(s)

Now, balance the equation

K₂S(aq) + Pb(NO₃)₂(aq) → 2KNO₃(aq) + PbS(s)

Write the complete ionic equation

2K⁺(aq) + S²⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq)  → 2K⁺(aq) + 2NO₃⁻(aq) + PbS(s)

Cancel out the spectator ions

S²⁻(aq) + Pb²⁺(aq)   → + PbS(s)

Hence, the balanced net ionic equation is

Pb²⁺(aq) + S²⁻(aq) → PbS(s)

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Answer:

2.4 grams of ClF3

Explanation:

First let us determine the moles of Cl2 and F2,

Cl2 = (  ( 337 )( 2.05 L ) / ( 0.082 )( 298 K ) ) * ( 1 atm / 780 ),

Cl2 = ( 690 / 24.436 ) * ( 1 / 780 ),

Cl2 = ( About ) 0.036 moles of Cl2

_________________________________________________

F2 = ( ( 729 )( 2 L ) / ( 0.082 )( 298 K ) ) * ( 1 atm / 780 ),

F2 = ( 1458 / 24.436 ) * ( 1 / 780 )

F2 = ( About ) 0.078 moles of F2

Now let us identify the limiting reactant, considering the ratio between ClF3 and Cl2 / F2. In this case F2 is the limiting reactant, as it forms a smaller molar ratio;

The theoretic yield is thus performed with the limiting reactant F2,

0.078 * ( 2 / 3 ) * ( 92.45 / 2 ) = ( About ) 2.4 grams of ClF3

MnO4- + 4e- → MnO2 + 2H2O Now the half-equation is balanced in alkaline medium.

To balance the half-equation MnO4- → MnO2 in alkaline medium, we need to follow the steps for balancing redox reactions in basic solution. The goal is to balance the number of atoms and charges on both sides of the equation.

Start by balancing the atoms other than oxygen and hydrogen. In this case, we only have manganese (Mn) atoms. There is one Mn atom on both sides, so the Mn atoms are already balanced.

Balance the oxygen atoms by adding water (H2O) molecules to the side that lacks oxygen. Since there are four oxygen atoms on the left side (MnO4-) and only two on the right side (MnO2), we need to add two water molecules to the right side:

MnO4- → MnO2 + 2H2O

Next, balance the hydrogen atoms by adding hydrogen ions (H+) to the side that lacks hydrogen. In this case, the left side (MnO4-) already has sufficient hydrogen atoms, so no hydrogen ions need to be added.

Balance the charges by adding electrons (e-) to the side that has a higher charge. MnO4- has a charge of -1, while MnO2 has no charge. Since the left side has a higher charge, we need to add electrons to the right side:

MnO4- + 4e- → MnO2 + 2H2O

Now the half-equation is balanced in alkaline medium. The Mn atoms, oxygen atoms, hydrogen atoms, and charges are all balanced. The addition of water and hydrogen ions helps balance the oxygen and hydrogen atoms, while the addition of electrons balances the charges.

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The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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Answer:  There are three main types of forests: tropical rainforests, deciduous forests, and coniferous forests. Tropical rainforests are found near the equator (the center of Earth), where they are warm all year round.

Explanation:

Ecosystems are defined as a geographical region where biotic factors like animals, plants and microorganisms live together and interact with the abiotic factors.

The three forest ecosystems are temperate, boreal and tropical.

Tropical forest ecosystems have high precipitation and temperature also a high humidity rate. The plant has a twelve-month growing period and the forests are found near the equator regions.

Temperate is found in between the boreal and the tropical forests, it has a high level of rainfall and humid conditions and is covered with the deciduous type of trees.

Boreal or the taiga forest ecosystems are located in the subarctic regions with low temperatures and have long winters. They are covered majorly by the scale-leaved evergreen and the needle leaves cones.

All three forest ecosystems have great species diversity, the tropical and the temperate forest have dense vegetation and the temperate and boreal have evergreen forests.

Therefore, three forest ecosystems are temperate, boreal and tropical.

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Answer:

35.453 good luck with your work

Answer:

Sigma bonds: 10

Pi bonds: 4

Explanation:

The compound described must be CH2=CH-CO-CH≡CH. If we look at the compound closely, we will notice that there are 10 sigma bonds and 4 pi bonds.

There are three pi bonds between carbon atoms and one pi bond between a carbon and an oxygen atom (C=O). All these can easily be seen in the structure of the formula chosen in this answer.

The total number of sigma bonds in the given structure are 9. The total number of pi bonds in the given structure are 4.

The given hydrocarbon has the structure of:

\(\rm CH_2=CH-C(=O)-C\equiv CH\).

The pie bonds are the unsaturated bonds, formed by the electron clouds. The double and triple bonds are pi bonds.

In the given structure number of pi bonds are:

Thus the total number of pi bonds in the given structure are 4.

The sigma bonds are the covalent bonds, formed by the sharing of electrons. The single bonds are sigma bonds.

The number of sigma bonds are;

Thus the total number of sigma bonds in the given structure are 9.

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Turmeric is yellow in acidic and neutral solutions and red in basic solution.

Sample solution - Nature of solution - Color

(i) Amla juice - Acidic - Yellow

(ii) Lime water. - Basic. - Red

(iii) Common salt - Neutral - Yellow

(iv) Baking soda - Basic - Red

Answer: unlike, will not scatter

Explanation:

Colloids are unlike solutions because their dispersed particles are much larger than those of a solution. The dispersed particles of a colloid cannot be separated by filtration, but they scatter light, a phenomenon called the Tyndall effect.

Answer:

Fe(NO2)3

Explanation:

A poly atomic ion is an ion that contains more than one atom.

If we look at all the compounds that have been mentioned among the options; KBr and NaF are both ionic but do not contain any covalent poly atomic ion.

However, Fe(NO2)3  contains NO2^+ which is a poly atomic ion that contains the covalent bond.

Sugar cane plantation owners needed cheap labor after the enslaved were freed.

We know that in the nineteenth century the era of slave trade was actually coming to a close and the concern of many of the slave owners both in Europe and America was the future of their agricultural businesses.

The slave owners mostly used the slaves to do the work on the farm and in the absence of the slaves, the work could not be done. This is why the owners of the slaves sought for cheap labor after the slaves were freed.

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Sugar was important in the late nineteenth century for both dietary and economic reasons. It was consumed by all social classes and significantly influenced the labor practices in agriculture.

Based on the information provided, one can infer that sugar was of significant importance in the late nineteenth century. It served as a staple in people's daily diets and was enjoyed by all social classes, from shopgirls to kings. In the economic sphere, sugar cane farming was a notable industry. Sugar canes were labor-intensive to grow and harvest, which required plantation owners to seek cheap labor. This implies that the sugar industry had a substantial influence on labor practices during this era. It is therefore clear that sugar was not only a dietary necessity but also a crucial factor in the broader economic and social structure of the community.

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Answer:

\(5.5 \times {10}^{ - 5} \: cm\)

Explanation:

We know, that:

\(1nm \: = \: 1 \times {10}^{ - 7} \: cm \)

Now, we can make a proportion according to this:

1nm - 1×10^-7 cm

550 nm - x cm

\(x = \frac{550 \times 1 \times {10}^{ - 7} }{1} = 550 \times {10}^{ - 7} = 5.5 \times {10}^{ - 5} \: cm \: = 0.000055 \: cm\)

The number of moles of products based on the information given is 0.5 moles product.

It is given that each unshaded sphere represents an atom A and shaded represents B. If we look at the diagram, we have 8 unshaded doubly attached units and 4 unshaded doubly attached units on the left side which means we have 8 A2 molecules that react with 4 B2 molecules.

Whereas in the right-side diagram(which are products), 4 molecules have 4 unshaded and one shaded sphere, which means it is BA4 and 2 moles have two shaded spheres which mean it is B2. Hence, the number of moles of products based on the information given is 0.5 moles product.

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1.54 × 10²⁴ atoms He

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 2.56 moles He

[Solve] atoms He

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.54163 × 10²⁴ atoms He ≈ 1.54 × 10²⁴ atoms He

Answer:

One atom of sulfur has a mass of 32.07 AMU; one mole of S atoms has a mass of 32.07 g.

Explanation:

Therefore, the answer should be 32.07 g

Answer:

Explanation:

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is:

HCl(aq) + NaOH(s) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that one mole of hydrochloric acid reacts with one mole of sodium hydroxide to produce one mole of sodium chloride and one mole of water.

First, we need to determine which reactant is limiting, i.e., which reactant is completely consumed in the reaction. To do this, we need to compare the number of moles of each reactant, using their respective molar masses:

Molar mass of HCl = 1.008 g/mol (atomic weight of hydrogen) + 35.45 g/mol (atomic weight of chlorine) = 36.46 g/mol

Molar mass of NaOH = 22.99 g/mol (atomic weight of sodium) + 16.00 g/mol (atomic weight of oxygen) + 1.008 g/mol (atomic weight of hydrogen) = 39.99 g/mol

Number of moles of HCl = mass / molar mass = 30.0 g / 36.46 g/mol ≈ 0.823 mol

Number of moles of NaOH = mass / molar mass = 14.3 g / 39.99 g/mol ≈ 0.358 mol

Since the stoichiometric ratio between HCl and NaOH is 1:1, NaOH is the limiting reactant because it has fewer moles than HCl.

Therefore, we can calculate the maximum mass of NaCl that can be produced by the reaction using the number of moles of NaOH:

Number of moles of NaCl produced = number of moles of NaOH used in the reaction = 0.358 mol

Mass of NaCl produced = number of moles of NaCl produced x molar mass of NaCl

Molar mass of NaCl = 22.99 g/mol (atomic weight of sodium) + 35.45 g/mol (atomic weight of chlorine) = 58.44 g/mol

Mass of NaCl produced = 0.358 mol x 58.44 g/mol = 20.9 g

Therefore, the maximum mass of NaCl that can be produced by the reaction is approximately 20.9 g

The opportunity cost for the new instruments for the music department is the 10% to upgrade the computer lab hardware

The revision of the budget is that the school board had to redistribute the budget allocation for upgrading the computer lab hardware from 5% to 10%. This means that the school board had to make a trade-off in terms of allocating more budget for upgrading the computer lab hardware and less for other areas such as new instruments for the music department or new sports equipment.

This trade-off is known as the opportunity cost, as the school board had to give up the potential benefits of allocating more budget to those areas in order to allocate more budget to upgrading the computer lab hardware.

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Answer:

Explanation:

a )

m = m₀ \(e^{-\lambda t\)

m is mass after time t . original mass is m₀ , λ is disintegration constant

λ = .693 / half life

= .693 / 1590

= .0004358

m = m₀ \(e^{- 0.0004358 t}\)

b )

m = 50 x \(e^{-.0004358\times 500}\)

= 40.21 mg .

c )

40 = 50 \(e^{-.0004358t\)

.8 = \(e^{-.0004358t\)

\(e^{.0004358t\) = 1.25

.0004358 t = .22314

t = 512 years .

The new volume of the balloon after heating it to a temperature of 51 °C is approximately 2.39 L.

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Given that:

Substituting the given values and solve for V₂:

\(V_1T_2 = V_2T_1\\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{2.2\ *\ 324.15}{298.15 }\\ \\V_2 = 2.39 \ L\)

Therefore, the final volume is 2.39 litres.

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If the temperature is lowered to a dew point, condensate will be produced.

While the air temperature drops underneath its dew factor, excess moisture can be released in the form of condensation. Condensation problems are maximumly probable to occur in climates in which temperatures regularly dip to 35°F or colder over a prolonged time period.

The dew factor is the temperature to which air needs to be cooled to emerge as saturated with water vapor, assuming steady air stress and water content. while cooled beneath the dew point, moisture potential is reduced and airborne water vapor will condense to form liquid water known as dew. Both the air is cooled to its dew point or it becomes so saturated with water vapor that it can't maintain any extra water. The dew factor is the temperature at which condensation occurs

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Answer:

See explanation

Explanation:

SN2 reaction is a synchronous reaction in which the leaving group departs as the nucleophile is being attached to the substrate in a single step. This makes it imperative to use a good leaving group when carrying out an SN2 reaction such as the one shown in the question.

The addition of a small amount of NaI acts as a sort of external nucleophile which assists the departure of the leaving group thereby enabling the reaction to proceed faster. This occurs because the iodide ion is very good leaving group.

Answer:

none of the liquid is purple