what is the molar concentration of cl- when 0.20 mol of zncl2 are dissolved in enough water to prepare 3.0 l of solution

Answer:

3.Test for unsaturation is carried out by either Baeyer's test or bromine water test.

(a) What is Baeyer's reagent?

Ans:

Baeyer's reagent is an alkaline solution of Potassium Permanganate \(\bold{KMnO_4}\) .

(b) How does it detect presence of double bond in organic compound? Write the reaction involved.

Ans:

When a dilute alkaline solution of \(\bold{KMnO_4}\) is added to the given unsaturated organic compound, if the purple color of permanganate solution disappears, the presence of double bond is indicated.

For example:

2\(\bold{KMnO_4}\) + 2KOH \(\longrightarrow\)\(\bold{2K_2MnO_4 + H_2O+[O]}\)

\(\bold{CH_2=CH_2(ethene) +H_2O+[O]\longrightarrow CH_2OH-CH_2OH (ethylene \:glycol :Colourless)}\)

(c) Write the product when ethyne is treated with Baeyer's reagent.

Ans:

Product will not produce as ethyne doesn't contain double bond.

(d) Benzene (an aromatic hydrocarbon) does not give Baeyer's test though it has double bonds. Why?

Ans:

As Benzene is an unsaturated compound. The structure of benzene contains 3 alternate single double bonds.

(e) Write the reaction for bromine water test for ethyne.

Ans:

Reaction:

\(\bold{CH_2CH_2(ethene)+Br_2( red \: color) \longrightarrow CH_2Br-CH_2Br}\)  

(1,2-dibromoethane (colorless}

Kolbe electrolytic method can be used to prepare alkane, alkene and alkyne.

(a) At which electrode, alkane, alkene or alkyne is obtained?

Ans:

alkane, alkene or alkyne is obtained at anode.

(b) Which electrolyte should be chosen for alkane, alkene or alkyne for the method? Suggest an example of electrolyte for each.

Ans:

alkane: Potassium or sodium salt of Carboxylic acid

alkene: Potassium or sodium salt of dicarboxylic acid

alkyne: Potassium or sodium maleate

(c) If potassium salt of dicarboxylic acid is taken for the method, which hydrocarbon is prepared?

Ans: If potassium salt of dicarboxylic acid is taken for the method, Alkene hydrocarbon is prepared.

(d) Write the detail process for the electrolysis of aqueous potassium maleate.

Ans: Attachment

(e) Suggest a demerit of the method.

Ans:

Demerits:

The partial pressure of benzene and toluene is 74.11 torr.

Generally, vapor pressure is defined as a measure of the tendency of a material to change into the gaseous or vapor state, and it basically increases with temperature. Basically the temperature at which the vapor pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is known as the boiling point of the liquid.

Pa denotes the Vapor pressure of benzene = 103.4 torr

Pb denotes the Vapor pressure of toluene = 46.9 torr

Moles of benzene can be calculated by the formula,

Number of moles of benzene = Given mass of benzene / Molar mass of benzene = 45/78 = 0.57 moles

Number of moles of toluene = Given mass of toluene/ Molar mass of toluene = 55/92 = 0.59 moles

Mole fraction of benzene (Xa) = 0.57/(0.57+0.59) = 0.57 / 1.16 = 0.49

Mole fraction of toluene (Xb) = 0.59/(0.57+0.59) = 0.50

Partial pressure = (XaPa + XbPb)

                          = 0.49 × 103.4 + 0.50 × 46.9

                          = 50.666 + 23.45 = 74.11 torr

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Answer:

58.8C of heat

Explanation:

76.9C is the current heat temperature, to decrease it to 18.1C we have to subtract the both and later find our answer

Answer:

3.56x10²³ atoms

Explanation:

To solve this question we need first to determine the moles of iron (II) chloride, FeCl₂, using its molar mass. Then, using Avogadro's number we can solve for the number of atoms:

Moles FeCl₂ - Molar mass: 126.751g/mol-

25g FeCl₂ * (1mol / 126.751g) = 0.1972 moles

Number of atoms:

1 mole of FeCl₂ are 6.022x10²³ molecules of FeCl₂, that means 0.1972moles are:

0.1972mol * (6.022x10²³ molecules / 1mol) = 1.188x10²³ molecules of FeCl₂

In 1 molecule of FeCl₂ there are 3 atoms (1 of Fe and 2 of Cl), in 1.188x10²³ molecules of FeCl₂ there are:

1.188x10²³ molecules of FeCl₂ * (3atoms / molecule) =

        A chemical reaction's rate and the concentrations of the reactants involved are correlated by an expression known as the rate law, commonly referred to as the rate equation.

       The rate equation's "orders," the exponents a and b, must be established empirically. The exponents are added to determine the reaction's overall order. In other words, the reaction is third order overall if a=1 and b=2.

       By adding together the different orders, the reaction's overall order can be determined. For instance, the overall order is 2 if the reaction is first order with regard to both A and B (a = 1 and b = 1). This is referred to as a global second order response.

Finding a Rate Law's Exponents from Initial Rates (Experimental Data)

          The molar concentrations of the reactants are used by the rate law to calculate the reaction rate. Because there are more molecules colliding and reacting with one another, reactions often proceed more quickly at higher reactant concentrations.

       The exponents of a rate law's concentration terms are added to determine its order. The rate law of a reaction can be utilized to better understand the makeup of the reaction mixture once it has been established.

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In the electrophilic aromatic substitution reaction between benzaldehyde and Br2 in the presence of FeBr3, the first step involves the generation of a carbocation intermediate. This carbocation is formed when the bromine molecule attacks the benzene ring, displacing a proton.

Since benzaldehyde is a meta-director, the carbocation intermediate will be stabilized through resonance. The resonance structures can be represented as follows:

Structure 1:

      Br

       |

Ph-C(+)-H

       |

Structure 2:

      Br

       |

Ph-C-H

  |    |

  +    Ph

Structure 3:

      Br

       |

Ph-C-H

  |    |

Ph    +

In these resonance structures, the positive charge of the carbocation is delocalized throughout the benzene ring. The presence of the electron-withdrawing aldehyde group (CHO) in benzaldehyde directs the incoming bromine atom to the meta position relative to the aldehyde group.

Please note that it's always recommended to consult reliable sources and appropriate references for accurate structural representations.

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The pressure inside the container will increase when heated from 0°C to 55°C. This is because when the temperature of a gas increases, its volume decreases and the pressure increases to maintain a constant number of molecules in a given volume.

Charles' law, which asserts that the volume of a gas is precisely proportionate to its temperature at a constant pressure, describes this phenomena.

As a result, at 55°C, the pressure within the container will be higher than the pressure at STP.

The ideal gas law, which states that the pressure, volume, and temperature of an ideal gas are related through the equation PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature, must be used to determine the precise pressure inside the container at 55°C.

By rearranging the equation and inserting the values for temperature, volume and number of moles, one can calculate the exact pressure inside the container at 55°C.

Complete Question:

A  sample of gas is trapped in a rigid container at STP. If the container is heated to 55.0 °C, what will the pressure be inside the container?

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Answer:

Noble gases

Explanation:

The noble gases are non-metals that requires the highest amount of energy to remove an electron from their shells.

The reason for this difficult is that their electronic configuration confers a stable configuration them.

Answer:

70..... I think

Explanation:

Cuz if the bus travels 35 km every 30 mins this means that it travels 70 km per hour

Answer:

232.04u is the atomic weight of Thorium.

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 250 g

density = 0.975 g/cm³

We have

\(density = \frac{250}{0.975} \\ = 256.410256...\)

We have the final answer as

Hope this helps you

Given :

Rate = 75 m 1 s×60 s 1 min×1 h 60 m.

To Find :

Correct answer after conversion.

Solution :

We know, 1 min = 60 sec.

1 hour = 60 min = 60×60 sec = 3600 sec.

Putting value of min and hour in seconds , we get :

\(R=((75\times 60) + 1 )\times ( (60 + 1)\times 60 ) \times ( 3600+3600)\ s^3\\\\R=1.186\times 10^{11} \ s^3\)

Hence, this is the required solution.

Answer:It allows us to see things so we know where we are going that’s why at night we had lamp posts

Explanation:

Gases can be defined by the  statement, gases freely flow to fill the container they are in, gases have neither a defined volume nor shape and gases are highly compressible.

Even in the existence of gravity as well as irrespective of the mass of a substance in the vessel, gas is just a sample of matter which make up the structure of the container where it is contained and achieves an uniform distribution within the container.

The term "mass" refers to the amount of material used to construct anything. The volume of a thing refers to the amount of space it occupies.

Gases can be defined by the  statement, gases freely flow to fill the container they are in, gases have neither a defined volume nor shape and gases are highly compressible.

Therefore, the correct answer will be option (D).

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To determine the ratio of H2O to glucose, C6H12O6, first you need to solve for the unknown coefficients x1, x2, x3, and x4 using matrix methods , given the chemical equation for x1 and x4.

Given the chemical equationx1C6H12O6 + x2O2 → x3CO2 + x4H2OYou can determine the unknown coefficients x1, x2, x3, and x4 by writing equations for each element:Carbon (C):6⋅x1 + 0⋅x2 = 1⋅x3 + 0⋅x4Hydrogen (H):12⋅x1 + 0⋅x2 = 0⋅x3 + 2⋅x4Oxygen (O):6⋅x1 + 2⋅x2 = 2⋅x3 + 1⋅x4The above equations can be represented in matrix form as AX=B:6 0 1 0x1 0 x3 0 | 00 12 0 2 x1 x4 0 x2 | 0 6 2 1Then, the unknown coefficients can be solved using the following MATLAB code:X = [6 0 1 0; 0 12 0 2; 6 2 0 1; 0 0 0 6];B = [0; 0; 0; 6];X = inv(X);X = X * B;x1 = X(1);x4 = X(4);Thus, x1 = 1 and x4 = 6, which means that the ratio of H2O to glucose, C6H12O6, is x4/x1 = 6/1 = 6.

To determine the ratio of H2O to glucose, C6H12O6, you need to solve for the unknown coefficients x1, x2, x3, and x4 using matrix methods in MATLAB, given the chemical equation:x1C6H12O6 + x2O2 → x3CO2 + x4H2OThe coefficients can be determined by writing equations for each element present in the reaction. The element equation for carbon (C) can be given as:6⋅x1 + 0⋅x2 = 1⋅x3 + 0⋅x4The element equation for hydrogen (H) can be given as:12⋅x1 + 0⋅x2 = 0⋅x3 + 2⋅x4The element equation for oxygen (O) can be given as:6⋅x1 + 2⋅x2 = 2⋅x3 + 1⋅x4Then, the above equations can be represented in matrix form as AX=B:6 0 1 0x1 0 x3 0 | 00 12 0 2 x1 x4 0 x2 | 0 6 2 1where A is the coefficient matrix, X is the matrix of unknowns, and B is the matrix of constants.Using MATLAB code, the solution can be obtained by: X = [6 0 1 0; 0 12 0 2; 6 2 0 1; 0 0 0 6];B = [0; 0; 0; 6];X = inv(X);X = X * B;x1 = X(1);x4 = X(4);Thus, x1 = 1 and x4 = 6, which means that the ratio of H2O to glucose, C6H12O6, is x4/x1 = 6/1 = 6.

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0.87 g of hydrogen is produced by the reaction of 7.80 g of calcium with 1.83 g of water.

To find the amount of hydrogen produced in the reaction, we need to calculate the theoretical yield of hydrogen. This is done by finding the amount of calcium and water that react and finding the amount of hydrogen that is produced from this amount.

From the given information, 7.80 g of calcium reacts with 1.83 g of water. We can use the balanced equation for the reaction to find the amount of hydrogen produced:

Ca + 2H₂O -> Ca(OH)₂ + H2

From this equation, 1 mole of calcium reacts with 2 moles of water to produce 1 mole of hydrogen.

So, the theoretical yield of hydrogen is (1.83 g/mole) x (1 mole/2 moles) = 0.92 g of hydrogen.

Finally, the actual yield of hydrogen is found by multiplying the theoretical yield by the reaction yield, which is 94.4%.

The actual yield of hydrogen = 0.92 g x 94.4% = 0.87 g

Therefore, 0.87 g of hydrogen is produced by the reaction of 7.80 g of calcium with 1.83 g of water.

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Answer:

Electrons

Explanation:

Answer and Explanation:

D. I think..

Answer:

The flame of the candle looks to go out, but the candle continues to burn. In actuality, the copper wire coil is transferring heat away from the candle flame. The flame returns after the coil of wire is removed.

Explanation:

The attraction between the nucleus and electrons decreases tends to occur in groups that results in an increase in atomic radius.

Magnesium atoms have atomic radii that are lower than those of sodium atoms. The magnesium atom's smaller radius is mainly due to the fact that it has two more electrons in its outermost energy level than the sodium atom does.The attractive interactions between the nucleus and the additional electrons in the magnesium atom make them weaker, which leads to a reduced atomic radius. An element's atomic radius serves as a gauge for the size of its atoms.

The atomic radius of atoms increases in groups of elements on the Periodic Table of the Elements. Which best describes what tends to occur in groups that results in an increase in atomic radius?

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The reaction you provided shows the oxidation of cadmium and the reduction of nickel.

To calculate the standard cell potential of a nickel-cadmium electrochemical cell, we need to use the standard reduction potentials of both elements. The standard reduction potential of nickel is -0.25 V, and the standard reduction potential of cadmium is -0.40 V.

Using the equation:

E°cell = E°reduction (cathode) - E°reduction (anode)

We can calculate the standard cell potential of the nickel-cadmium electrochemical cell as:

E°cell = -0.25 V - (-0.40 V) = 0.15 V

Therefore, the standard cell potential of a nickel-cadmium electrochemical cell is 0.15 V.

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In Groups 1 and 2 of the periodic table, the melting points of metals generally decrease as you move down the group. This trend is known as a general pattern in the relationship between a metal's position in these groups and its melting point.

Group 1 consists of alkali metals (Li, Na, K, etc.), and Group 2 consists of alkaline earth metals (Be, Mg, Ca, etc.). As we move down these groups, the number of electron shells increases, and the atomic radius of the metals also increases. This increase in atomic radius leads to weaker metallic bonding between the atoms.

The melting point of a metal is influenced by the strength of the metallic bonds. Metallic bonding occurs when metal atoms share their outer electrons freely, forming a "sea" of delocalized electrons. These delocalized electrons are responsible for the high electrical conductivity and malleability of metals. The stronger the metallic bonding, the higher the melting point of the metal.

As we move down Groups 1 and 2, the increased atomic radius results in a greater distance between the metal ions in the crystal lattice. This increased distance weakens the metallic bonding, making it easier to break the bonds and convert the solid metal into a liquid state. Therefore, metals lower in Groups 1 and 2 have lower melting points compared to metals higher up in the groups.

Additionally, the increased number of electron shells also leads to greater shielding of the outer electrons from the positive charge of the nucleus. This reduced attraction between the outer electrons and the nucleus further contributes to the weaker metallic bonding and lower melting points as we move down the groups.

In summary, the general pattern in the relationship between a metal's position in Groups 1 and 2 and its melting point is that the melting points decrease as we move down the groups due to the increasing atomic radius, weaker metallic bonding, and reduced attraction between the outer electrons and the nucleus.

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Answer:

Hydrogen(H) and Heluim(He)

Explanation:

These are the only two valennce electrons and 1 energy levels.

Answer:

Hydrogen (H) and helium (He) have a valence shell containing one and two electrons respectively. They make up the first period (row) of the periodic table. Their valence electron/s are in the first energy level (n=1) , as is denoted by 1s1 and 1s2.

Explanation:

Logic... if its wrong imma cry

Magnetic, electric, and gravitational fields are a few examples of the forces that pull you toward the center of the earth.

Every mass of stuff has an area surrounding it where other bodies may feel its gravitational pull.A gravitational field is the name given to this area of space.The gravitational field has direction, just like other electromagnetic fields like the electric and magnetic fields.It's a vector field as a result.

field is a zone in physics where each point is connected to a physical quantity.The quantity could be a vector, such as in the case for fields like the gravitational field, that are linked to a force, or it could be a number, such as in the case of scalar fields like the Higgs field.

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Answer:

Hey there!

The correct answer is "sum of 112+88 g"...

The calcium carbonate has 88g in a fine manor which goes along with 1128.

Hope this helps! Happy Holidays and stay safe!

Explanation:

Answer:

answer is "sum of 112+88 g"...

Explanation:

The calcium carbonate has 88g in a fine manor which goes along with 1128.

hope this helps and ill get brainliest im trying to rank up so i can help more people

Answer:

a)Mg(s) + 2HCl(aq) -------> MgCl2(aq) + H2(g)

b) 0.125 moles of hydrogen gas is reduced in the reaction.

C) 3.18 L

d)2.25 g of water

Explanation:

a) the equation of this reaction is;

Mg(s) + 2HCl(aq) -------> MgCl2(aq) + H2(g)

b)

Number of moles= concentration × volume= 1.0 × 250/1000 = 0.25moles of HCl

From the equation;

2 moles of HCl yields 1 mole of hydrogen gas

Hence 0.25 moles of HCl yields 0.25 × 1/2 = 0.125 moles of hydrogen gas

Thus 0.125 moles of hydrogen gas is reduced in the reaction.

c)

P= 760 mmHg (standard pressure)

V= ????

T= 298 K

n= 0.125 moles

R= 0.082 atm dm-3K-1mol-1

Since the gas is collected over water, SVP of hydrogen at 25°c is 28mmHg

Therefore; P=760-28= 732mmHg

But

1 atm =760 mmHg

Therefore 732 mmHg= 732/760= 0.96 atm

PV=nRT

V= nRT/P

V= 0.125 × 0.082 × 298/0.96

V= 3.18 L

Note 1dm-3=1L

d)

2H2(g) + O2(g) ----> 2H2O(g)

From the equation;

2 moles of hydrogen yields 2 moles of water

0.125 moles of hydrogen yields 0.125 moles of water

Mass of water = 0.125 moles × 18gmol-1 = 2.25 g of water

Answer:

Photosynthesis takes the energy of sunlight and combines water and carbon dioxide to produce sugar and oxygen as a waste product. The reactions of respiration take sugar and consume oxygen to break it down into carbon dioxide and water, releasing energy.

Explanation: