What is the missing number in the solution to 978 = 10 below? 97 R8 10) 978 -90 -70 8 O A. 78 OB. 8 O C. 70 O D. 80 SUBMIT

Answers

Answer 1

In this case the answer is very simple .

We must perform the division to find the missing number.

In this case, the missing number is 78.

The answer is:

A. 78

What Is The Missing Number In The Solution To 978 = 10 Below? 97 R8 10) 978 -90 -70 8 O A. 78 OB. 8 O

Related Questions

Find the area of the smaller sector.
140°/6 in
1404
Area =
[ ? Jin2
B В
Round your answer to the nearest hundredth.

Find the area of the smaller sector.140/6 in1404Area =[ ? Jin2B Round your answer to the nearest hundredth.

Answers

Answer:

43.96

Step-by-step explanation:

3.14 x 6^2 x 140/360

Question 17 (2 points)


The following triangles are congruent by SAS. How did we know that
Question 17 options:


The angles are adjacent and share the same vertex.


The angles are vertical and share the same vertex.


There isn’t enough information to say the triangles are congruent.


The angles are linear and share the same vertex.




Question 18 (2 points)


What information is missing to show that ▲WZX ≃ ▲YZX by HL?

Question 18 options:


WX≃YX






The triangles are not congruent.

Question 17 (2 points)The following triangles are congruent by SAS. How did we know that Question 17
Question 17 (2 points)The following triangles are congruent by SAS. How did we know that Question 17

Answers

The best advice I can give is to not ask brainly questions on these subjects all questions I looked up were wrong. :/

Question 17 (2 points)The following triangles are congruent by SAS. How did we know that Question 17

Question 17

The angles are adjacent and share the same vertex.

The angles are vertical and share the same vertex.

There isn’t enough information to say the triangles are congruent.

The angles are linear and share the same vertex.

Question 18:

WX≃YX

ZXW and ZXY are right angles.

W≃Y

The triangles are not congruent.

6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.

Answers

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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1. A target is divided into 100 squares colored in dark blue, white, and light blue. Amber throws a beanbag that lands on the target.
co
9 25
dark blue
What is the probability that it will land on a dark blue square?
26
white
light blue

1. A target is divided into 100 squares colored in dark blue, white, and light blue. Amber throws a beanbag

Answers

The probability of landing on the dark blue target is 2/5.

Finding probability

Probability is the ratio of required to the total possible outcomes of an event.

The required outcome = dark blue= 25Total possible outcomes= entire sample Space = 100

P(dark blue ) = 40/100

divide through by 20

P(dark blue ) = 2/5

Therefore, the probability of landing on target is 2/5

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(CLASSKICK) HELP ASAP!!!

(CLASSKICK) HELP ASAP!!!

Answers

Answer:

  94.3

Step-by-step explanation:

You want to know how to fill in the proportion associated with the question, "What is 115% of 82?"

Proportion

The diagram is intended to help you match parts of the question to parts of the proportion. The attachment shows the intended relation.

The solution is found by multiplying both sides by 82:

  (x/82)·82 = (115/100)·82

  x = 94.3

Equation

The question can also be written as a statement:

  "what" is 115% of 82

When written as an equation, "is" means "equals", and "of" means "times":

  what = 115% × 82

Of course, you can use any variable name of your choosing in place of "what". In your diagram, that is "x". And, you know how to write a percentage as a fraction or decimal, so this becomes ...

  x = 115/100 × 82 = 1.15 × 82

All that remains is to evaluate this expression.

  x = 1.15 × 82 = 94.3

So, the answer to the question is ...

  94.3 is 115% of 82.

(CLASSKICK) HELP ASAP!!!

Explain how to plot (-5, 1).

A) From the origin, move left 5 units and up 1.
B) From the origin, move right 5 units and up 1.
C) From the origin, move right 1 unit and down 5.

Answers

I believe the answer is A

Answer:

A) From the origin, move left 5 units and up 1.

Step-by-step explanation:

You have to start with x, which is -5.To get to a negative on the x axis, you need to move 5 spaces to the left. Then the y, which is 1. To get to 1 on the y-axis, you need to go up 1 space. Therefore, the answer is A.

-Leafie

Help a friend in need

Help a friend in need

Answers

a) 4.71ft

b) 3.53ft^2

Step-by-step explanation:

Perimeter is 1/2 the circumference

1/2 Circumference = 2*pi*radius

Radius = 1/2 Diameter

Radius = 3/2 = 1.5ft

Circumference = 2*pi*1.5ft = 9.42

1/2 Circumference = 4.71

4.71ft is the perimeter.

The area is 1/2 that of a full circle

A = pi*r^2

A = 3.14*1.5*1.5

A = 7.065ft^2

1/2 A = 3.53ft^2

3х+2 / 4 - 2x+1 / 3= 5


Answers

Answer:

X= 25/6

Step-by-step explanation:

Please mark brainliest

What is the product?
2
12 64
78 30
6
32
78 30
(050
69
78 30
899
32
39 15
66 8
64
38 30

Answers

Answer:

the product is 1.32057606543E32

Evaluate – (3-5)(33).
ОА. -
Ов.
Ос. 9
OD. -9

Answers

Answer:

=−66

Step-by-step explanation:

(3−5)(33)

=(−2)(33)

=−66

plss helppppppppppppppp​

plss helppppppppppppppp

Answers

Answer:

149? I could be wrong I haven't done this type of math in a while.

Step-by-step explanation:

From B to D, that angle would be 180. so 180 - 31 = 149

It’s 64 degrees I’m pretty sure

3^x = 27^a+b and a^2-b^2/(a-b)=5 What is x?

Answers

Your answer should be 3x-x+2=4 hope this helps..

After a party, 1/3 of a pizza

remains. Rachel eats 1/2 of the

remaining pizza. What fraction of a

pizza does she eat?

Answers

1/6 because 1/3 • 1/2 is 1/6

The required fraction of the pizza Rachel eat is 1 / 6.

Given that,
After a party, 1/3 of a pizza remains. Rachel eats 1/2 of the remaining pizza. What fraction of a pizza she eat is to be determined.


What is simplification?

The technique in mathematics to perform and solve the expression to make the expression simple or more understandable is called simplifying and the process is called simplification.

What is the Ratio?

The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.


Here, remaining pizza = 1 / 3
Rachel eats 1 /2 of the remaining pizza so,
=  1 / 2 * 1 / 3
= 1 / 6

 

Thus, the required fraction of the pizza Rachel eat is 1 / 6.  

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. A TV originally priced at $799 is on sale for 30% off. There is then a 11% sales tax. Find the price after including the discount and sales tax. (3 Marks)

Answers

Answer:

$620.82

Step-by-step explanation:

799 decrease 30% =

799 × (1 - 30%) = 799 × (1 - 0.3) = 559.3

559.3 increase 11% =

559.3 × (1 + 11%) = 559.3 × (1 + 0.11) = 620.823

Which of the following equation(s) has/have slope zero?
a. x = 2
b.y = -3
c. y = 5x+2
d. x+ 5 = 0
O Both a and c
Only c
O Only b
O Both a and d

Answers

Answer:

b, only b

y = -3 has zero slope.

Step-by-step explanation:

Only a horizontal line has zero slope. A horizontal line's equation is given in the form: "y equals a number" So y=-3 is horizontal with zero slope.

Vertical lines have undefined slope. This is not the same as zero. Vertical lines have an equation in the form x= anumber. Above in the answer choices, choice a and d are both vertical with undefined slope and are not the correct answer. Choice c has slope 5, because that is the number beside the x in the form y=mx+b where m is the slope. So choice c is also not the answer.

Only choice b has zero slope.

The equation of a parabola is (x−3)2=16(y+7) . What are the coordinates of the vertex and focus of the parabola? What is the equation of the directrix?

Answers

The coordinates of the vertex of the parabola are (3, -7). The focus of the parabola is located at (3, -3). The equation of the directrix is y = -11.

The given equation of the parabola is in the form (x - h)^2 = 4p(y - k), where (h, k) represents the vertex and p represents the distance between the vertex and the focus/directrix.

Comparing the given equation with the standard form, we can see that the vertex is at (3, -7).

The coefficient 4p in this case is 16, so p = 4. Since the parabola opens upward, the focus will be p units above the vertex. Therefore, the focus is located at (3, -7 + 4) = (3, -3).

To find the directrix, we need to consider the distance p below the vertex. Since the parabola opens upward, the directrix will be p units below the vertex. Hence, the equation of the directrix is y = -7 - 4 = -11.

In summary, the coordinates of the vertex are (3, -7), the focus is located at (3, -3), and the equation of the directrix is y = -11.

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Write an equivalent expression by distributing the "-" sign outside the parentheses
-5w - (5.7x - 4.7)

Answers

An equivalent expression by distributing the "-" sign outside the parentheses is -5w - 5.7x + 4.7.

Define equation

An equation is a mathematical statement that shows the equality of two expressions, usually containing one or more variables. Equations typically include an equal sign (=) to indicate that the expressions on either side of the sign have the same value.

Equations can take many forms, from simple equations with only one variable, such as "x + 3 = 7," to more complex equations with multiple variables and exponents, such as "2x^2 + 5xy - 3y^2 = 0."

When we distribute the "-" sign outside the parentheses, we change the sign of every term inside the parentheses. So, we can write:

-5w - (5.7x - 4.7) = -5w - 5.7x + 4.7

Therefore, an equivalent expression by distributing the "-" sign outside the parentheses is -5w - 5.7x + 4.7.

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Answer:5w - 5.7x + 4.7

Step-by-step explanation:

3t−18=4(−3−
4
3

t)3, t, minus, 18, equals, 4, left parenthesis, minus, 3, minus, start fraction, 3, divided by, 4, end fraction, t, right parenthesis
t =t=t, equals

Answers

The variable t in the equation is 1.

How to find the variable in an equation?

3t - 18 = 4(-3 - 3/4t)

Open the bracket on the right side

3t - 18 = 4(-3 - 3/4t)

3t - 18 = -12 - 3t

add 3t to both sides of the equation

3t - 18 = -12 - 3t

3t - 18 + 3t = -12 - 3t + 3t

3t + 3t  - 18 = -12

6t - 18 = - 12

Add 18 to both sides of the equation

6t - 18 = - 12

6t - 18 + 18 = - 12 + 18

6t = 6

divide both sides by 6

6t = 6

6t / 6 = 6 / 6

t = 1

Therefore, the value of t is 1.

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Consider the following equation. 5x+3y=8 Step 1 of 2 : Determine the missing coordinate in the ordered pair (3,?) so that it will satisfy the given equation.

Answers

Answer: (3, -2.333) or (3, -7/3)

Step-by-step explanation:

We're given an x value (x=3) when looking at the coordinate, so we're trying to find what y is equal to given the equation. We can plug in x=3 into 5x+3y=8 and isolate for y.

\(5(3)+3y=8\\15 + 3y=8\\3y=-7\\y=-\frac{7}{3}\)

Answer:

y= -2 1/3

Step-by-step explanation:

Since you have x, you put x into the equation and work through the problem.

5(3)+3y=8

15+3y=8, then subtract 15 from both sides

3y=(-7), then divide both sides by 3

y=(-7)/3 or (-2 1/3)

ABCD~LMNO Find the value of MN if AB=12cm, BC=9.6cm and LM= 16cm

A) 13cm
B) 7.2cm
C) 12.8cm
D) 13.6cm

Answers

The answer is C

Explaining:

Yolanda scored 10 points in a basketball game. She could have scored with one‐point free throws, two‐point field goals, or three‐point field goals. In how many different ways could she have scored her 10 points?

Answers

she could have scored the 10 points in 302400 ways.

The given parameters are

n= total points =10

r1 =one-point free throw = 1

r2 = two-point field goals = 2

r3 =  three-point field goals = 3

The number of ways (k) she could have scored the points is:

k=(n!)/(r1!×r2!×r3!)

The factorial function is a mathematical formula represented by an exclamation mark "!".

k= 10!/(1!×2!×3!)

k= 3628800/(1×2×6)

k= 302400

so.. she could have scored the 10 points in 302400 ways.

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PLEASE HURRY

Let u = - 4i + 2j , v = 3i - j and w = - 6j

Find the specified scalar or vector

5u(3v - 4w)

Answers

The specified scalar or vector 5u(3v - 4w) is equal to -420i + 250j.

We can begin by distributing the scalar 5 to the vector 3v - 4w:

5u(3v - 4w) = 5u(3v) - 5u(4w)

Next, we can find the scalar multiples:

5u(3v) = 5(-4i + 2j)(3(3i - j)) = 5(-36i + 10j)

5u(4w) = 5(-4i + 2j)(4(-6j)) = 5(48i - 40j)

Now we can substitute these values back into the original expression:

5u(3v - 4w) = 5(-36i + 10j) - 5(48i - 40j)

Simplifying:

5u(3v - 4w) = -420i + 250j

Therefore, 5u(3v - 4w) = -420i + 250j.

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The graph below shows the number of free throws made by five players on a basketball team.
Weekly Free Throw Numbers for Players
#Free Throws
10+
99876543N
Player 1 Player 2 Player 3 Player 4 Player 5
Week 1 Week 2 Week 3
What was the total number of free throws made for Player 2?
24
17
23
8

The graph below shows the number of free throws made by five players on a basketball team.Weekly Free

Answers

Total number of free throws made for player 2 are 23 using histogram.

Define histogram.

A histogram is a graphical depiction of continuous or discrete data. In a histogram, the frequency is represented by the area of a bar. Frequency density, which is proportional to frequency, is plotted on the y-axis, and intervals representing the range of values are plotted on the x-axis. One common graphing tool is the histogram. It is employed to present interval-scaled summaries of discrete or continuous data. It is frequently used to conveniently depict the main characteristics of the data distribution. A histogram is a graph in which the horizontal axis represents the values of the observations, and the vertical axis represents the density of those observations.

Given,

Histogram given,

Total number of free throws made for player 2 are:

8 + 9 + 6

23

Total number of free throws made for player 2 are 23 using histogram.

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1. 3х – 4 y = 24 : (0, ) ( ,0)​

Answers

the points are (0,-6) (8,0)

Consider a completely randomized design involving four treatments: A, B, C, and D. Select a correct multiple regression equation that can be used to analyze these data. Define all variables. I. E(y) = Bo + B1 21 22 23 24, where 21 = 1 if treatment A, 21 = 0, otherwise; x2 = 1 if treatment B, 32 = 0, otherwise; 23 = 1 if treatment C, 33 = 0, otherwise; 24 = 1 if treatment D, 24 = 0, otherwise. II. E(y) = Bo + B121 + B222 + B323 + B4204, where 21 = 1 if treatment A, 21 = 0, otherwise; 22 = 1 if treatment B, 22 = 0, otherwise; 23 = 1 if treatment C, 13 = 0, otherwise; 24 = 1 if treatment D, 24 = 0, otherwise. III. E(y) = Bo + B121 + B222 + B323, where 21 = 1 if treatment B, 21 = 0, otherwise; 22 = 1 if treatment C, 22 = 0, otherwise; 23 = 1 if treatment D, 13 = 0, otherwise. Select your answer

Answers

Option III "E(y) = B₀ + B₁x₁ + B₂x₂ + B₃x₃, where x₁ = 1 if treatment B, x₁ = 0, otherwise; x₂ = 1 if treatment C, x₂ = 0, otherwise; x₃ = 1 if treatment D, x₃ = 0, otherwise." is a correct multiple regression equation that can be used to analyze these data. So the option III is correct.

Randomized design involving four treatments: A, B, C, and D.

So total number of treatments = 4(A, B, C, D)

So the number of dummy variable is required = 4 - 1

The number of dummy variable is required = 3

The three variables would be x₁ x₂ and x₃ and the fourth treatment scenario would be represented if all three were zero.

So the option III is correct because this is a correct multiple regression equation because it contains all the necessary components to define a linear regression model.

Specifically, it contains a dependent variable (y), a constant (B₀), and three independent variables (x₁, x₂, x₃). Additionally, each of the independent variables is either assigned a value of 1 or 0 depending on the treatment, which is how a linear regression model is typically constructed.

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The complete question is:

Consider a completely randomized design involving four treatments: A, B, C, and D. Select a correct multiple regression equation that can be used to analyze these data. Define all variables.

I. E(y) = B₀ + B₁ x₁ x₂ x₃ x₄, where x₁ = 1 if treatment A, x₁ = 0, otherwise; x₂ = 1 if treatment B, x₂ = 0, otherwise; x₃ = 1 if treatment C, x₃ = 0, otherwise; x₄ = 1 if treatment D, x₄ = 0, otherwise.

II. E(y) = B₀ + B₁x₁ + B₂x₂ + B₃x₃ + B₄x₄, where x₁ = 1 if treatment A, x₁ = 0, otherwise; x₂ = 1 if treatment B, x₂ = 0, otherwise; x₃ = 1 if treatment C, x₃ = 0, otherwise; x₄ = 1 if treatment D, x₄ = 0, otherwise.

III. E(y) = B₀ + B₁x₁ + B₂x₂ + B₃x₃, where x₁ = 1 if treatment B, x₁ = 0, otherwise; x₂ = 1 if treatment C, x₂ = 0, otherwise; x₃ = 1 if treatment D, x₃ = 0, otherwise.

number 5 and 6 plz help thank you

number 5 and 6 plz help thank you

Answers

Answer:

5 is B. corresponding

Step-by-step explanation:

hope this helps

Answer:

5 - B Corresponding angles

6 - a = 100°

Step-by-step explanation:

5 - Literally the definition of corresponding angles

6 - These angles add up to 360° so 360-(105+95+60)=360-260=100°

Find the domain of the inverse function w-1 (x) . Express your answer as in inequality

Answers

Answer:

ANSWER

Step-by-step explanation:

Without knowing the specific function w(x), it is impossible to determine the domain of the inverse function w^-1(x). However, in general, the domain of an inverse function is the range of the original function, and vice versa.

If we assume that w(x) is a one-to-one function (which is necessary for it to have an inverse function), we can determine the range of w(x) and use it to find the domain of w^-1(x).

For example, if we know that w(x) is a function that takes all real numbers except x=2, then the range of w(x) is (-∞,2) U (2,∞). The domain of w^-1(x) is then the same as the range of w(x), which is (-∞,2) U (2,∞). Therefore, the domain of w^-1(x) is x ≠ 2.

Without more information about w(x), we cannot determine the domain of w^-1(x) more precisely.

what fraction of the number are prime numbers from 2 to 14​

Answers

Answer:

i hope you got it.

plz mark brainliest.

what fraction of the number are prime numbers from 2 to 14

HELP Not sure how to do this. Harry starts 10 miles away from home. For each minute his distance decreases by two miles. Write and graph an equation to represent this scenario​.

Answers

Answer:

yes

Step-by-step explanation:

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The equation to represent this scenario is d(t) = -2t + 10.

What is a graph?

The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.

These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.

Given, Harry starts 10 miles away from home.

For each minute his distance decreases by two miles.

Assuming no. of minutes to be 't' and distance to be d(t).

∴ d(t) = -2t + 10.  

The graph of this is attached.

learn more about graphs here :

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HELP Not sure how to do this. Harry starts 10 miles away from home. For each minute his distance decreases

A person had $17,000 invested in to accounts One paying 7% simple interest And one paying 8% simple interest. How much was invested In each account if the interest rate after one year is $1356?

Answers

Answer:

A1 7% = $400 & A2 8% = $16,600

Step-by-step explanation:

A1 * 7% + A2 * 8% = 1356

A1 + A2 = 17000

A1 = 17000 - A2

(17000 - A2) * 0.07 + A2 * 0.08 = 1356

1190 - 0.07 A2 + 0.08 A2 = 1356

1190 + 0.01 A2 = 1356

0.01 A2 = 166

A2 = 16600

A1 = 17000 - A2

A1 = 17000 - 16600

A1 = 400

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