what is the maximum horizontal force that can be applied to the lower block without the upper block slipping?

Answer:

They become brighter in constructive interference because the wave paths donot cancel out, but just strengthen to give a brighter light.

No diagram

Answer:

time taken to reach maximum height is 2.548 sec and Maximum height is 31.855 m

Explanation:

Initial velocity U= 25 m/s

at maximum height velocity, V= 0 m/s

Let the time taken to reach maximum height be t and maximum height be H.

V= U-gt

so 25-9.81.t=0

therefore t= 25/9.81  = 2.548 sec

Now,

H= Ut-1/2(gt^2)

 =25x2.548-0.5x9.81x(2.548^2)

 =31.855 m

                                              Thank you

First, we have to find the number of volts requires using Ohm's Law.

Where I = 0.30 A and R = 30 ohms. Let's replace these values and solve for V

Once we have the amount of voltage, we can divide it by 1.5V to get the number of batteries

Answer:

Work is calculated as the force multiplied by the displacement in the force's direction. Work is defined as force times a displacement in the force's direction.

1)Average speed = 8y/s

2)Average velocity= 0.88y/s

Average speed depends on the distance whereas average velocity depends on the displacement . Speed is a scalar quantity while average velocity is a vector quantity.

Let us assume, L=100 yards as the length of the football field.

1)We know that average speed is the total distance covered by the player divided by the time taken.

Total distance covered to go from one goal line to the other and then back to the 20-yards line is:

s= 100y + (100-20)y

= 100y+ 80y

=180y

Given, time t=22.5 s,

Now, the average speed of the player is:

v= s/t

= 180y/22.5

= 8 y/s

2)To calculate the magnitude of average velocity, we have to consider the direction and sign of the velocity.

In the beginning, the player goes from one goal line to the other one, so he covers 100 y. But, in the second part of the motion he goes back by 80 y. Hence, the net displacement of the player is:

s= 100y-80y= 20y

now, the average velocity is:

v= s/t

=20/22.5

= 0.88 y/s.

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Answer:

To be accurate, it must be able to make measurements that are close to the actual value.

Answer: 150 metres/5 seconds/5 seconds

Explanation:

Find the acceleration/deceleration
v^2 = u^2 + 2as; v=final velocity u=initial velocity a=acceleration s=distance
0^2 = 20^2 + 2*a*50
a = -4 m/s Therefore, the particle is decelerating at 4 m/s
From there, we can work out PQ
Using the same equation, we get that
20^2 = 40^2 + 2*-4*s
s = 150 m so Distance PQ is 150 metres
Finding the time taken to cover PQ and PR uses a different equation
v = u + at; t = time and everything else is the same
20 = 40 - 4t
t = 5 s so Time taken to cover PQ is 5 seconds
0 = 20 - 4t
t = 5 s so Time taken to cover PR is also 5 seconds

26.0898 rad/s is the angular velocity of a rotor in a blender.

Given

Initial velocity (ω₁) = 55.0 rad/s

Deceleration (α) = -40.7 rad/s²

Angle (θ) = 28.8 rad

Final angular velocity (ω₂) =?

According to the angular kinematic equation

ω₂² = ω₁² + 2αθ

Put the values of ω₁, α, and θ in the equation

We get,
ω₂² = (55)² + 2(₋40.7)(28.8)

ω₂² = √680.68

ω₂ = 26.0898 rad/s

Hence, 26.0898 rad/s is the angular velocity of a rotor in a blender after turning 28.8 rad.

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a) The speed of light in the glass is the same as the speed of light in a vacuum, which is around 3x10⁸ m/s ; b) There are 1.00 mm / 4x10⁻⁷ m = 2.5 million wavelengths of the light inside the glass slide.

a.) The speed of light in glass is typically slower than the speed of light in a vacuum. The refractive index of glass is typically around 1.5, which means that the speed of light in glass is around 2x10⁸ m/s. However, we can use Snell's law to calculate the exact speed of light in this particular glass microscope slide. Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the indices of refraction of the two media. Since the incident light is coming from air, which has an index of refraction of 1, and entering the glass slide, which has an index of refraction of around 1.5, we can use the following equation:

sin(incident angle)/sin(refracted angle) = n(glass)/n(air)
sin(incident angle)/sin(refracted angle) = 1.5/1
sin(incident angle)/sin(refracted angle) = 1.5

We don't know the angle of incidence or refraction, but we do know that they are equal because the light is entering the slide perpendicular to its surface (i.e. at 90 degrees). This means that sin(incident angle) = sin(refracted angle), and we can simplify the equation to:

sin(incident angle)/sin(incident angle) = 1.5
1 = 1.5

This is obviously not true, so there must be a mistake somewhere. The mistake is that we assumed the incident angle was 90 degrees, but it is actually given by the problem as being 0 degrees (i.e. the light is entering perpendicular to the surface). This means that the incident angle is equal to the refracted angle, and we can use Snell's law again to find the speed of light in the glass:

sin(0)/sin(refracted angle) = 1.5/1
0/sin(refracted angle) = 1.5
sin(refracted angle) = 0
refracted angle = 0

This means that the light does not refract (i.e. bend) as it enters the glass, but instead continues in a straight line. Therefore, the speed of light in the glass is the same as the speed of light in a vacuum, which is around 3x10⁸ m/s.

b.) The wavelength of the incident light is given as 600 nm, or 6x10⁻⁷ m. To find how many wavelengths of the light are inside the 1.00 mm thick glass slide, we need to know the refractive index of the glass (which we already found to be around 1.5) and the angle of incidence (which we know to be 0 degrees). We can use the following equation:

wavelength inside glass = wavelength in air / refractive index of glass

wavelength inside glass = 6x10⁻⁷ m / 1.5
wavelength inside glass = 4x10⁻⁷ m

This means that there are 1.00 mm / 4x10⁻⁷ m = 2.5 million wavelengths of the light inside the glass slide.

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Answer: 2 i think

Explanation:

Answer:Im pretty sure its the second one because sound sometimes bounces back and that causes echo and it doesnt travel in one line or direction

Explanation:

the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5

Work done by a force is equal to the scalar product of the force applied and displacement. If d displacement happens on applying a force F, then work done, W by the force is

W = F. d

given:

mass, m = 25 kg

height, d = 1.50 m

work has to be done against the weight of the book, F = mg

work done W = F. d

W = mgd

W = (25) ×(9.8)×(1.50)

W = 367.5 J

This work is stored as the potential energy of the book.

Therefore, the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5J

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Answer:

Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.

Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).

Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).

Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:

\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).

With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:

\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).

Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).

All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.

It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:

\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).

Solve for the displacement of the spring, \(x\):

\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).

Answer:

Natural

Explanation:

Answer:

It's a Natural System

Explanation:

When the Solar System was formed Human didn't even exist. the planets clashed and a lot of changes happened to create earth and different planets.

Answer:

A: 2.8 * 10^(-14) J

Explanation:

Formula to find the energy is;

E = hc/λ

Where;

E is energy of a photon (E)

λ is wavelength of the light

c is speed of light

Thus;

E = (1.99 *10^(-25))/(7 * 10^(-12))

E = 2.8 * 10^(-14) J

Answer:

The change in the linear momentum is 225 kg.m/s and the force exerted on the tennis ball is 22,500 N.

Explanation:

Linear momentum is the measure of a body's motion. Every object that has mass and moves at any velocity has linear momentum. Here are some examples of everyday life: falling balls, launching rockets, driving a car etc.

Now let's attack the problem.

First, we got to write the data down:

\(\bullet \quad m=3\,kg\\\\\bullet \quad v_o=40\,m/s\\\\\bullet \quad v=35\,m/s\\\\\bullet \quad \Delta t =0.01\,s\)

We can write the change in linear momentum of the tennis ball as follows:

\(\Delta p = p-p_o\)

The ball's momentum is equal to its mass times its velocity. Hence:

\(\Delta p= m\cdot v-m\cdot v_o\)

Let's set the reference system as positive to left (see picture attached). For that purpose, when the ball bounces back its velocity changes sign.

Now, we are able to plug in the data:

\(\Delta p = 3\cdot 35 - 3\cdot(-40)\\\\\\\Delta p = 105+120\\\\\\\therefore \boxed{\Delta p =225\,kg\cdot m/s}\)

To calculate the exerted force, we must apply the impulse theorem, which states that impulse equals the change in linear momentum of an object. We get:

\(\mathbb{I}=\Delta p\)

Hence,

\(F \cdot \Delta t=\Delta p\\\\\\F\cdot 0.01=225\\\\\\F=\dfrac{225}{0.01}\\\\\\\therefore \boxed{F=22,\!500\,N}\)

Conclusion: the change in linear momentum is 225 kg . m/s and the exerted force is 22,500 N.

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That's a pretty good intuitive definition of a theory .

Answer:

\(343 \div 1000 = 0.343\)

wavelength is equivalent to the velocity divided by the frequency

Answer:

Speed is 34.5 m/s

Explanation:

From the third equation of motion:

\({ \boxed{ \sf{v {}^{2} = {u}^{2} + 2as}}}\)

v is final velocity, u is initial velocity, a is acceleration, s is displacement.

substitute:

\( {v}^{2} = {30}^{2} + (2 \times 2.4 \times 60) \\ {v}^{2} = 900 + 288 \\ {v} {}^{2} = 1188 \\ {v} = \sqrt{1188} \\ v = 34.5 \: m {s}^{ - 1} \)

When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.

Therefore, the correct answer is:

(a) There is a large increase in the magnetic induction (B)

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Transform plate tectonic boundaries slide/move past each other, rubbing along the edges causing earthquakes, tsunami, landslides

An earthquake is the shaking of the surface of the Earth resulting from a sudden release of energy in the Earth's lithosphere that creates seismic waves.

The answer is c is because when tectonic plates are rubbing against each other that’s how an earthquake is formed.

another reason the answer is C is because when the tectonic plates are moving together it can cause the land to slide.

the last reason the answer is C is because when the tectonic plates in the ocean move it can cause a tsunami.

Hence transform plate tectonic boundaries slide/move past each other, rubbing along the edges causing earthquakes, tsunami, landslides

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There is more energy with the light of wavelength 580 nm compared to 660nm as energy is inversely related to wavelength.

The energy of a radiation type is inversely proportional to its wavelength. This means energy increases with decreases in wavelength, and energy decreases with increases in wavelength. The relation between energy, wavelength, and frequency is shown by the equation E = hν = hc/λ.

where

E = energy,

h = Planck's constant,

ν = frequency,

c = the speed of light,

and λ = wavelength of the wave

Wavelength is defined as the distance measured between two adjacent crests or two adjacent troughs of a wave cycle.

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Answer:

The new force becomes 3 times of the initial force.

Explanation:

Let q₁ and q₂ are two charged particles. The force between them is given by :

\(F=\dfrac{kq_1q_2}{r^2}\ ......(1)\)

If \(q_1'=\dfrac{q_1}{4}\)

and

\(q_2'=3q_2\)

Also, r' = r/2

New force,

\(F'=\dfrac{kq_1'q_2'}{r'^2}\)

Putting all the above values,

\(F'=\dfrac{k\dfrac{q_1}{4}3q_2}{(r/2)^2}\\\\F'=3\times \dfrac{kq_1q_2}{r^2}\\\\F'=3F\)

So, the new force becomes 3 times of the initial force.

The spring is extended by 9.0 x 10⁻² m relative to its unstrained length. when a one kilogramme item is hung on a vertical spring with a 120 n/m spring constant.

y = fapplied / k

y = mg/k

y = 1.1 kg x 9.80m/s² / 120 N/m

y = 9.0 x 10⁻² m

The cable's L0 unstrained length, also known as its unstretched length, refers to the length of the cable without any tension being placed on it (cable self-weight is also ignored). L0 is the length that the cable segment AB would have if it were installed on a surface that was completely flat.

Two approaches are used to apply the unstrained length method (ULM), which is based on the unstrained lengths, to the bridge construction. Lastly, a bridge example with vertical cambers is used to illustrate that the suggested analytical approaches may in fact produce an optimum first solution by demonstrating that both designs result in an initial configuration with localised tiny bending moment distributions that is almost similar.

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Free body diagrams are used in mechanics problems to illustrate forces and moments applied to a body and to compute reactions.

The relative strength and direction of all forces operating on an object in a specific circumstance can be depicted using free body diagrams (FBDs), which are helpful tools. The careful creation of a free-body diagram is a prerequisite for the analysis and description of the majority of physical processes. In a free body diagram, the size of the arrow represents the force's magnitude, while the direction of the arrow represents the way it acts.

These diagrams are widely used to compute internal forces within a structure, as well as to determine the loading of certain structural components.

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Cage 2 will reach the bottom first. The time taken by cage one is 114.76 seconds and cage 2 is 0.32 seconds.

Given,

Mine depth Y = 2072 m

Cage speed 1 v = 65.0 km/h

Acceleration of Cage 2,

a = 4.00 102 m/s2

Solution:

We shall utilize the international system of measurements (SI) to interchange magnitudes using the unit system, which allows us to do so precisely and without the need for antiquities.

  v = 65 km / h (1000m/1Km) (1hr/3600s)

     = 18.06 m / s

The relationships between location, velocity, and acceleration can be discovered using kinematics.

Work each cage separately in this practice since there are two of them.

Cage 1

They suggest that it is moving at a constant speed, which we can determine using the laws of uniform motion.

v = d/t

v = d/v

t1 = 2072/18.06

t₁ = 114.76 s

Cage 2

Stop so that your starting velocity is zero.

y = v₀ t + ½ a t²

y = 0 + ½ a t²

\(t = \sqrt{2y/a} \\\\t2 = \sqrt{2*2072/4*10^{2} } \\\)

t₂ = 0.32 s

On comparing the time taken by cage 1 and cage 2, we can say that cage 2 will reach the ground first.

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This individual launches a ball upward at a 15 meter per second beginning speed. We'll assume that the ball is held in the guy's mouth at beginning height zero meters.

What is the speed measurement unit?

Units of speed include nautical miles per hour (kn or kt), feet per minute (symbol fps or ft/s), kilometers per hour (symbol km/h), miles an hour (symbol km in or mph), and metres per moment (symbol μ s 1 or m/s), the SI-derived unit. Speed multiplied by the sound speed is known as the dimensionless Mach number;

What does speed have a shorthand for?

L T-1. The parameters of speed are time divided by distance. The most often used measure of speed in daily life is the kilometer per hour, or miles per hour in the United States and the UK. The Si derived unit of velocity is the meter per second.

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Answer:

60

Explanation:

60secs = 1 minute

if you want to show you work further then

10 divided by 10 = 1

so each second is 1 heart beat

so then just 60 divided by 10 equals 6

so then just do 6 times 10 equals 60 beats