What is the mass of the oxygen used during the reaction? Iron (19.43) and iron oxide (20.91).

The volume of the air when the breath is warm to body temperature (37.0°C) in the lungs is 530.4 mL

First, we shall list out the given parameters from the question. This is given below:

The volume of the breath when it is warm to body temperature (37.0°C)    can be obtained by using Charles' law equation as shown below:

V₁ / T₁ = V₂ / T₂

450 / 263 = V₂ / 310

Cross multiply

263 × V₂ = 450 × 310

263 × V₂ = 139500

Divide both side by 263

V₂ = 139500 / 263

V₂ = 530.4 mL

Thus, the volume is 530.4 mL

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With ammonia bicarbonate, calcium, and hydrochloric acid, the word equation for processes 3 and 4 is. 2NH4Cl + H2O + CO2 = 2HCl + (NH4)2CO3.

Chloride, carbon dioxide gas, and water are the byproducts of the reaction between calcium and hydrochloric acid. The unbalanced equation reads like this.

When its hydrogen ion interacts with the carbonate ions, carbonic acid is created. However, because carbonic acid is very unstable at standard atmospheric pressure and breaks down into both water and carbon dioxide, carbonate drinks release gas when they are opened. The metal ions then undergo a reaction with the chloride ions to create salts.

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Answer:

Explanation:

sory i dont know

Answer:

the elephant toothpaste would go everywhere

Volume ..........is the answer

The ocean is not a part of Earth's layers.

Answer:

Ocean

Explanation:

One mole of chlorine gas reacts with 2 mol sodium metal to give 2 mol sodium chloride.

Therefore, the concentration of HAc is 0.342 M

The pH of the solution is 2.28

We assume that the density of glacial acetic acid is 1.05 g/mL, the mass of the 20.0 mL of glacial acetic acid can be calculated as:

mass = volume x density = 20.0 mL x 1.05 g/mL = 21.0 g

n(HAc) = mass / molar mass = 21.0 g / 60.05 g/mol = 0.349 mol

The concentration of Ac- (in mol/L) is also x, and the concentration of HAc (in mol/L) is:

[HAc] = [HAc]initial - [H3O+] = 0.349 mol / 0.250 L - x

Ka = [H3O+][Ac-] / [HAc]

1.8 x 10^-5 = x^2 / (0.349/0.250 - x)

We then find X

x = [H3O+] = 0.0052 M

[HAc] = 0.349 mol / 0.250 L - 0.0052 M = 0.342 M

We calculate the pH using,

pH = -log[H3O+]

pH = -log(0.0052) = 2.28

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The final value for the enthalpy change of the formation of CO2 and 2H2O from their elements (C, H2, and O2) would be -1410 kJ per mole of CO2 and 2 moles of H2O formed.

The enthalpy change (ΔH) for the reaction CO2 + 2H2O → H2CO3 can be calculated by multiplying the stoichiometric coefficients of the balanced equation by the enthalpy values of the corresponding compounds involved in the reaction.

In the given reaction, the enthalpy change is -1410 kJ. However, it's important to note that this enthalpy change corresponds to a specific reaction and may not directly apply to the formation of CO2 and 2H2O from another reaction or process.

If we assume that the reaction is the formation of one mole of CO2 and two moles of H2O, we can say that the enthalpy change for this specific formation reaction is -1410 kJ.

Therefore, the final value for the enthalpy change of the formation of CO2 and 2H2O from their elements (C, H2, and O2) would be -1410 kJ per mole of CO2 and 2 moles of H2O formed.

It's worth mentioning that the enthalpy change can vary depending on the specific conditions (temperature, pressure, etc.) and the reactants involved in the reaction. Therefore, it's crucial to specify the conditions and reaction context when referring to enthalpy values.

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The identity of a cation solution that produces a mix of red and yellow colors in a flame test, but appears red when viewed through a cobalt filter, can be attributed to the presence of the strontium (Sr) cation.

During a flame test, different metal cations emit characteristic colors due to the excitation of electrons and their subsequent emission of light. Strontium, in particular, is known to produce a vibrant red color in flame tests.

The presence of both red and yellow colors indicates the possibility of multiple metal cations in the solution. While the specific metal responsible for the yellow color is uncertain, it could potentially be sodium or another metal that emits a yellow flame.

When the flame is viewed through a cobalt filter, which absorbs yellow wavelengths of light, the yellow color is filtered out, resulting in only the red color being observed. Since strontium is known for its distinctive red flame color and its emission is not affected by the cobalt filter, it is likely the metal cation responsible for the observed red color. Therefore, based on these characteristics, the identity of the cation solution is most likely strontium (Sr).

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Explanation:

The question gives us the following balanced equation:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

The equation tells us that 1 mole of H2SO4 react with 2 mole of NaOH producing 1 mole of Na2SO4 and 2 moles of H2O.

It is important to know the ratio between sodium sulfate and water: 1:2.

Also, the question tells us the quantity in grams of Na2SO4. We need to transform it to moles, using the following formula:

n = m/MM

MM of Na2SO4 = 142.04 g/mol

so:

n = 2/142.04

n = 0.0014 moles of Na2SO4

The ratio between Na2SO4 and H2O is:

1 mole of Na2SO4 ---- 2 moles of H2O

0.0014 moles of Na2SO4 ---- y

y = 0.0028 moles of H2O

Answer: It is produced 0.0028 moles of H2O.

Answer:

\(Q=-71.1kJ\)

Explanation:

Hello!

In this case, since the formation of ammonia by starting with nitrogen and therefore hydrogen is:

\(N_2+3H_2\rightarrow 2NH_3\)

Which has an energy of reaction of:

\(\Delta _fH_{NH_3}=-45.90 \frac{kJ}{molNH_3}\)

We can compute the energy required for this reaction by first computing the moles of ammonia yielded by 21.7 grams of nitrogen (28.02 g/mol) via stoichiometry:

\(n_{NH_3}=21.7gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=1.55molNH_3\)

Thus, the energy turns out:

\(Q=n_{NH_3}\Delta _fH_{NH_3}=1.55molNH_3 * -45.90 \frac{kJ}{molNH_3}\\\\Q=-71.1kJ\)

Best regards!

Answer: 71.1 (Edmentum)

Explanation:

Answer:

48.9 or 49.0 g of sulfuric acid

Explanation:

The electromagnetic spectrum shown in the diagram is describing radiant energy.

The electromagnetic spectrum shows the total range of frequencies or wavelengths that electromagnetic radiation covers or occurs.

The electromagnetic spectrum usually arranges all forms of electromagnetic radiation from that having the shortest wavelength or highest frequency to that having the longest wavelength or lowest frequency or vice versa.

The electromagnetic spectrum shown arranges electromagnetic radiation from gamma rays to radio waves.

All forms of electromagnetic radiation possess radiant energy.

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Answer:

I WILL ACHIEVE GREATNESS

Explanation:

Answer:

.

Explanation:

A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option  C, E

The two correct answers that are made from renewable resources are:

C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.

E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.

The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:

A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.

B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.

D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.

Option C and E.

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Answer:

Matter is classified into two broad categories, namely, pure substances and mixtures. Mixtures can be separated into pure substances by physical methods. Pure substances are further divided into categories as elements and compounds. ... A pure substance can be either an element or a compound.

Explanation:

Answer:

A and C

Explanation:

so D

Answer: 177.23 g.

Explanation:

the volume of the aluminum bar is

1.7 cm x 3.0 cm x 12.9 cm

= 65.61 cm^3

2.7 g/cm^3 x 65.61 cm^3

177.23g

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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The volume of the titanium is 15.3 cm^3.

We have to know that the only way that we can use the mass of the titanium to be able to obtain the volume of the titanium is when we consider the density of the titanium and that is the approach that we are going to use in the problem that we have in this case.

If we look at the problem we know that;

Mass of the titanium = 68.9186 grams

Density of the titanium = 4.5 grams per cm3

Volume of the titanium = ?

We would then have in this case that;

Volume of the titanium = Mass/Density

= 68.9186 grams/4.5 g/cm^3

= 15.3 cm^3

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The total number of electrons  Al+3. Fe¹3 Mg² Sn¹² Co²Co³ Lit¹ Cr+3,  Rb Pt+2 are 3, 3, 2, 12, 2, 3, 0, 3.0,2 electrons

Electrons are subatomic particles that have a negative charge and are found outside the nucleus of an atom. They orbit the nucleus in shells or energy levels and are involved in chemical bonding and electricity. Electrons are much smaller in size compared to protons and neutrons, which make up the nucleus of an atom.

Al+3 has 10 electrons (13 protons - 3 electrons).

Fe¹3 has 20 electrons (26 protons - 3 electrons).

Mg² has 10 electrons (12 protons - 2 electrons).

Sn¹² has 50 electrons (50 protons - 12 electrons).

Co² has 27 electrons (27 protons - 2 electrons).

Co³ has 26 electrons (27 protons - 3 electrons).

Li¹ has 3 electrons (3 protons - 0 electrons).

Cr+3 has 21 electrons (24 protons - 3 electrons).

Rb¹ has 37 electrons (37 protons - 0 electrons).

Pt+2 has 76 electrons (78 protons - 2 electrons).

Therefore,  The number of electrons in an atom determines its chemical behavior and the way it interacts with other atoms.

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Answer:

Silicon atoms have 14 protons.

Silicon atoms will react with other atoms in order to gain stability.

Silicon atoms have 14 electrons.

The structure given in question is hydrogen bonding. Hydrogen bonding is a special type of dipole-dipole attraction between molecules.

Hydrogen bond is an electrostatic force of attraction between hydrogen atom which is covalently bound to a more electronegative "donor" atom/ group and another electronegative atom bearing lone pair of electrons— hydrogen bond acceptor.

Hydrogen bonding is a special type of dipole-dipole attraction between molecules and not a covalent bond to hydrogen atom. It results from attractive force between hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.

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a. The Mass of water driven off = 0.15 g

b. Moles of anhydrate = 0.00257 moles

c. Moles of water driven off is 0.00833 moles

d. There are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. The molecular formula of the hydrated salt will be X.3H₂O

a. The mass of water driven off from the hydrated salt is:

Mass of water driven off = 0.5 g - 0.35 g

Mass of water driven off = 0.15 g

b. Molecular mass of salt = 136 g/mol

moles of anhydrate = 0.35/136

Moles of anhydrate = 0.00257 moles

c. Moles of water driven off = mass/molar mass

molar mass of water = 18 g/mol

Moles of water driven off = 0.15/18

Moles of water driven off = 0.00833 moles

d. Moles of water within the crystalline structure of one molecule of the hydrated salt is determined by converting to whole number mole ratio by dividing with the smallest ratio,

Salt to water ratio = 0.00257 /0.00257  :  0.00833/0.00257

Salt to water ratio = 1 : 3

Therefore, there are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. Assuming the anhydrous salt is X, the molecular formula of the hydrated salt will be X.3H₂O

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Answer:

green gemstone

Explanation:

hope this helps someone

The molecular formula for the compound is 3 times the empirical formula NO₂, which gives us N₃O₆.

6. In the molecular formula for a compound with an empirical formula of NO₂ and a molar mass of 138.015 g/mol,

The empirical formula tells us the simplest whole-number ratio of atoms in the compound, which in this case is NO₂. The molar mass of the empirical formula NO₂ can be calculated by adding the atomic masses of nitrogen (N) and two oxygen (O) atoms:

Molar mass of NO₂ = (1 × atomic mass of N) + (2 × atomic mass of O)

Molar mass of NO₂ = (1 × 14.01 g/mol) + (2 × 16.00 g/mol)

Molar mass of NO₂ = 46.01 g/mol

Molecular formula units = Molar mass of the compound / Molar mass of the empirical formula

Molecular formula units = 138.015 g/mol / 46.01 g/mol

Molecular formula units ≈ 3

7. a. To determine the empirical formula of nicotine given the mass percentages of carbon (C), hydrogen (H), and nitrogen (N), we can assume a 100 g sample of nicotine.

Mass of C in 100 g of nicotine = 74.1 g

Mass of H in 100 g of nicotine = 8.6 g

Mass of N in 100 g of nicotine = 17.3 g

To find the moles of each element, divide the mass by their respective atomic masses:

Moles of C = 74.1 g / atomic mass of C ≈ 74.1 g / 12.01 g/mol ≈ 6.17 mol

Moles of H = 8.6 g / atomic mass of H ≈ 8.6 g / 1.008 g/mol ≈ 8.53 mol

Moles of N = 17.3 g / atomic mass of N ≈ 17.3 g / 14.01 g/mol ≈ 1.23 mol

To obtain the simplest ratio between the elements,  divide the number of moles by the smallest number of moles, which in this case is 1.23 mol:

C ≈ 6.17 mol / 1.23 mol ≈ 5

H ≈ 8.53 mol / 1.23 mol ≈ 7

N ≈ 1.23 mol / 1.23 mol ≈ 1

Therefore, the empirical formula of nicotine is C₅H₇N.

b. To determine the molecular formula of nicotine, its molar mass, which is given as approximately 160 g/mol.

The empirical formula of nicotine is C₅H₇N, with a molar mass of:

(5 × atomic mass of C) + (7 × atomic mass of H) + (1 × atomic mass of N)

(5 × 12.01 g/mol) + (7 × 1.008 g/mol) + (1 × 14.01 g/mol)

60.05 g/mol + 7.056 g/mol + 14.01 g/mol

≈ 81.116 g/mol

To find the molecular formula,  the molar mass of nicotine (160 g/mol) by the

Molecular formula ratio = 160 g/mol / 93.131 g/mol

≈ 1.717

Therefore, the molecular formula of nicotine is 2 times the empirical formula: C₁₀H₁₄N₂.

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P Ar = 1.5

P Xe = 0.5

P tot = 2 atm

Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases  

Can be formulated:  

P tot = P1 + P2 + P3 ....  

The partial pressure is the pressure of each gas in a mixture  

3 L Argon , P = 1 atm and 1 L Xe, P=1 atm⇒assume T = 273 K

mol Argon :

\(\tt n_{Ar}=\dfrac{PV}{RT}=\dfrac{1\times 3}{0.082\times 273}=0.134\)

mol Xenon :

\(\tt n_{Xe}=\dfrac{1\times 1}{0.082\times 273}=0.045\)

\(\tt P_{Ar}=\dfrac{nRT}{V}=\dfrac{0.134.0.082.273}{2}=1.5\)

\(\tt P_{Xe}=\dfrac{nRT}{V}=\dfrac{0.045.0.082.273}{2}=0.5\)

P tot = 1.5 + 0.5 = 2 atm