What is The mass of an electron

The frequency of the object in circular motion is 0.06 Hz.

The formula to calculate the frequency is derived as follows;

The angular speed, ω is related to the frequency, f, as follows;

ω = 2πf

The linear velocity is related to angular velocity as follows:

v = r ω

ω = v/r

where;

v is the linear speed,

r is the radius, and

ω is the angular speed

Hence,

f = v/2πr

f = 7 / (18.7 * 2π)

Frequency, f = 0.06 Hz

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a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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The young's modulus in a cantilever will be 3.92 x 10¹⁰ N/m².

Young's modulus (E) is a material property that indicates how easily it can stretch and deform and is defined as the ratio of tensile stress () to tensile strain (). Where stress denotes the amount of force applied per unit area ( = F/A) and strain denotes the extension per unit length

Given that the length is 1m which is suspended by a load of 150g. The depression is found to be 4cm. The thickness of the beam is 5mm and the breath is 3cm.

The young's modulus will be calculated by the formula below,

Y = (4gl³) / (bd³) x ( M / y )

Y = ( 4 x 9.81 x 1³ x 0.150 ) / ( 0.03 x 0.005³ x 0.04 )

Y = 3.92 x 10¹⁰ N/m².

Therefore, young's modulus will be 3.92 x 10¹⁰ N/m².

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Gravity and normal forces act on the toy car.

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Cx = -105m

Cy = -88.2 m

C^2 = (-150)^2 + (-88)^2

C = √[ (-150)^2 + (-88)^2]

C = √(22,500+7,744]

C= √30244

C= 173.9 m

The ML rule has a very low error probability for these values of m1 and m0.

The ML rule for an optical on-off keyed system can be derived by using the Bayes' theorem. The ML rule is given by:

P(Y|1)P(1)/P(Y) > P(Y|0)P(0)/P(Y)

Since 0 and 1 are equally likely to be sent, P(1) = P(0) = 0.5. Therefore, the ML rule simplifies to:

P(Y|1) > P(Y|0)

The conditional probabilities P(Y|1) and P(Y|0) are given by the Poisson distribution:

P(Y|1) = (m1^Y * e^(-m1))/Y!

P(Y|0) = (m0^Y * e^(-m0))/Y!

Substituting these expressions into the ML rule and simplifying, we get:

(m1/m0)^Y > e^(m0-m1)

Taking the natural logarithm of both sides, we get:

Y > (m0-m1)/ln(m1/m0)

This is the form of the ML rule. For m1 = 100 and m0 = 10, the ML rule becomes:

Y > 52.02

The conditional error probabilities Pe∣i, i=0, 1 for the ML rule can be found by integrating the Poisson distribution over the appropriate range of Y. For i = 0, the conditional error probability is given by:

Pe∣0 = ∫_52.02^∞ (m0^Y * e^(-m0))/Y! dY

For i = 1, the conditional error probability is given by:

Pe∣1 = ∫_0^52.02 (m1^Y * e^(-m1))/Y! dY

These integrals can be evaluated numerically to find the conditional error probabilities. For m1 = 100 and m0 = 10, the conditional error probabilities are:

Pe∣0 = 1.9287498e-22

Pe∣1 = 0.0

Therefore, the ML rule has a very low error probability for these values of m1 and m0.

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Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:

It isn't moving

Explanation:

Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

Answer: headline, dateline, introduction

Explanation: its correct im not explaining

Answer:

3

Explanation:

The closer an orbit is to the nucleus the fewer energy

the diameter is the biggest line that can touch the two opposite point of a round wire(circle)

or

d= circumference/π

Using algebraic expressions, the constant acceleration is represented as 2(d/4)/t^2 and the ratio of the the average velocity is 8/t

A. To meet the puck one quarter of the distance from where you started, you need to cover one quarter of the total distance that the puck travels.

Let's call the initial distance between you and the puck "d". Then, the total distance the puck travels is d, and the distance you need to cover is d/4.

The time it takes for the puck to travel d is d/8 (since the puck's velocity is 8 m/s). The time it takes for you to cover d/4 is t.

Using the equation of motion, we can find the acceleration needed:

d = (1/2)at^2

d/4 = (1/2)(a)t^2

(1/2)(a)t^2 = d/4

a = 2(d/4)/t^2

We don't know the value of "d", so we cannot calculate the exact value of "a". But we can find it in terms of "t".

B. To calculate the ratio of your average velocity to the puck's constant velocity, we can use the equation:

v(average) = d/t

Let's call your average velocity "v". Then,

v/8 = d/(4t)

v/8 = d/4 * 1/t

v/8 = v(average)/t

v/8 = v(average)/t

v/v(average) = 8/t

Again, we don't know the value of "d" or "t", so we cannot calculate the exact value of the ratio. But we can represent it in terms of "t".

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Answer:

Explanation:

If Two cylindrical resistors are made from the same material, then their resistivity will be the same.  Formula for calculating resistivity of a material is expressed as;

\(\rho = \frac{RA}{L} \ where \ A = \frac{\pi d^2}{4}\) where;

R is the resistance

A is the cross sectional area of the material

L is the length of the material

For the shorter cylinder:

Length = L

diameter = D

\(\rho = \dfrac{R_s(\frac{\pi D^2}{4})}{L} \\\\\rho = \dfrac{R_s{\pi D^2}}{4L}\)

For the longer cylinder:

Length = 16L

diameter = 4D

\(\rho = \dfrac{R_l(\frac{\pi (4D)^2}{4})}{16L} \\\\\\\rho = \dfrac{R_l(\frac{\pi (16D^2)}{4})}{16L} \\\\\rho = \dfrac{R_l{16\pi D^2}}{16L}\\\\\rho = \dfrac{R_l{\pi D^2}}{L}\)

Since their resistivity are the same then;

\(\dfrac{R_s{\pi D^2}}{4L} = \dfrac{R_l{\pi D^2}}{L} \\\\ \dfrac{R_s}{4} = {R_l} \\\\R_s = 4R_l\\\\R_l = \frac{R_s}{4}\)

Hence the resistance of the longer resistor is a quarter of the shorter resistor.

Galileo Galilei was an Italian physicist, mathematician, astronomer, and philosopher who made significant contributions to the scientific revolution during the Renaissance. He is often referred to as the "father of modern observational astronomy" and the "father of modern science."

Galileo made a number of important discoveries and contributions to science. Some of his most significant contributions include:

1- The law of falling bodies: Galileo is credited with developing the concept of free-fall and the mathematical relationship between distance and time for objects in free-fall. He conducted a series of experiments in which he dropped objects of different masses from the Leaning Tower of Pisa to demonstrate that all objects fall at the same rate in a vacuum, regardless of their mass.

2- The telescope: Galileo is credited with building the first practical telescope, which he used to observe the heavens and make a number of important discoveries. He observed the phases of Venus, the lunar surface, and the Galilean moons of Jupiter, among other things.

3- The laws of motion: Galileo is credited with developing the concept of inertia and the laws of motion that later formed the basis of classical mechanics. He also developed the concept of momentum and introduced the idea of a mathematical relationship between force, mass, and acceleration.

4- The scientific method: Galileo is credited with pioneering the scientific method, which involves making observations, developing hypotheses, testing hypotheses through experiments, and drawing conclusions based on the results. This approach to science is still used today and is fundamental to the scientific process.

The electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

The electric potential energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

where U is the potential energy in Joules, C is the capacitance in Farads, and V is the voltage across the capacitor in Volts.

In this case, we are given that the capacitor stores 9.40 x 10^-10 C of charge at 50.0 V. However, we are not given the capacitance value. Therefore, we cannot calculate the potential energy directly using the above formula.

To find the capacitance value, we can use the formula:

C = Q / V

where Q is the charge stored in the capacitor and V is the voltage across the capacitor.

Substituting the given values, we get:

C = 9.40 x 10^-10 / 50.0

= 1.88 x 10^-11 F

Now we can use the formula for electric potential energy to find the energy stored in the capacitor:

U = (1/2) * 1.88 x 10^-11 * (50.0)^2

= 4.70 x 10^-8 J

Therefore, the electric potential energy stored in the capacitor is 4.70 x 10^-8 Joules.

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Answer:

The slopes for each of the four line segments are \(a_{A} = 6\,\frac{m}{min^{2}}\), \(a_{B} = 0\,\frac{m}{min^{2}}\), \(a_{C} = -4\,\frac{m}{min^{2}}\) and \(a_{D} = 2.667\,\frac{m}{min^{2}}\), respectively.

Explanation:

There are four line segments:

(i) Line A: \(v(0\,min) = 0\,\frac{m}{min}\), \(v(10\,min) = 60\,\frac{m}{min}\)

(ii) Line B: \(v(10\,min) = 60\,\frac{m}{min}\), \(v(15\,min) = 60\,\frac{m}{min}\)

(iii) Line C: \(v(15\,min) = 60\,\frac{m}{min}\), \(v(40\,min) = -40\,\frac{m}{min}\)

(iv) Line D: \(v(40\,min) = -40\,\frac{m}{min}\), \(v(55\,min) = 0\,\frac{m}{min}\)

The slope of each line segment represents the acceleration of the particle, which can calculated by the geometrical concept of secant line. Hence, we proceed to determine the acceleration associated with each line segment:

Line A

\(a_{A} = \frac{v(10\,min)-v(0\,min)}{10\,min-0\,min}\)

\(a_{A} = \frac{60\,\frac{m}{min}-0\,\frac{m}{min}}{10\,min-0\,min}\)

\(a_{A} = 6\,\frac{m}{min^{2}}\)

Line B

\(a_{B} = \frac{v(15\,min)-v(10\,min)}{15\,min-10\,min}\)

\(a_{B} = \frac{60\,\frac{m}{min}-60\,\frac{m}{min} }{15\,min-10\,min}\)

\(a_{B} = 0\,\frac{m}{min^{2}}\)

Line C

\(a_{C} = \frac{v(40\,min)-v(15\,min)}{40\,min-15\,min}\)

\(a_{C} = \frac{-40\,\frac{m}{min}-60\,\frac{m}{min} }{40\min-15\,min}\)

\(a_{C} = -4\,\frac{m}{min^{2}}\)

Line D

\(a_{D} = \frac{v(55\,min)-v(40\,min)}{55\,min-40\,min}\)

\(a_{D} = \frac{0\,\frac{m}{min}-\left(-40\,\frac{m}{min} \right) }{55\,min-40\,min}\)

\(a_{D} = 2.667\,\frac{m}{min^{2}}\)

The slopes for each of the four line segments are \(a_{A} = 6\,\frac{m}{min^{2}}\), \(a_{B} = 0\,\frac{m}{min^{2}}\), \(a_{C} = -4\,\frac{m}{min^{2}}\) and \(a_{D} = 2.667\,\frac{m}{min^{2}}\), respectively.

A bicycle with 26-inch diameter wheels is traveling at 20 mi/h. Find the angular speed of the wheels in rad/min.

______radians per minute

___revolutions per minuteω =  1320 rad/min, Revolution per minutes = 210.084

Diameter = 24 in

Radius r = 24/2 in = 12 in = 12 × 2.54 cm = 30.48‬ cm = 0.3048 m

Linear Speed v= 15 mi/hr = 15 * 1609.34 / 3600 m/s = 6.7056 m/s

Angular Speed ω = v / r = (6.7056 m/s) / (0.3048 m) = 21.999945

ω =  22 rad/s = 22× 60 rad/min = 1320 rad/min

∴ 1 revolution = 2π rad

⇒1 rad = 1 / 2π rev

so 1320 rad/min = 1320 / 2π  rev/min = 210.0845 rev/min

Revolution per minutes = 210.0845

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The spring constant of the spring is 178.4 N/m.

In this problem, we are given a mass of 0.25 kg that is attached to a spring and set into vibration with a period of 0.22 s.

We can use the equation for the period of a mass-spring system, which relates the period of oscillation to the mass and spring constant, to calculate the spring constant.

We can use the equation for the period of a mass-spring system:

T = 2π√(m/k)

where T is the period, m is the mass, and k is the spring constant.

Rearranging this equation to solve for k, we get:

k = \((4\pi^2m) / T^2\)

Substituting the given values, we get:

k = \((4\pi^2 \times 0.25 \:kg) / (0.22 s)^2\)

k = 178.4 N/m

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The displacement vectors in component form are A = 1.732 km i + 1 km j and B =  -2.955 km i - 0.522 km j.

The distance from home when cell phone rings is 1.309 km.

The direction from home when phone rings is 21.48° West of South.

(a) The displacement vector A can be expressed in component form as:

A = 2 km [cos(30°) i + sin(30°) j] = 2 km [√3/2 i + 1/2 j] ≈ 1.732 km i + 1 km j

The displacement vector B can be expressed in component form as:

B = 3 km [cos(280°) i + sin(280°) j] = 3 km [-0.985 i - 0.174 j] ≈ -2.955 km i - 0.522 km j

(b) The total displacement vector (C) is the sum of vectors A and B, which can be found by adding the corresponding components:

C = A + B = (1.732 - 2.955) km i + (1 - 0.522) km j = -1.223 km i + 0.478 km j

The magnitude of the resulting vector C can be found using the Pythagorean theorem:

|C| = √((-1.223)² + (0.478)²) ≈ 1.309 km

Therefore, you are about 1.309 km away from home when your cell phone rings.

(c) The direction of the resulting vector C can be found using the inverse tangent function:

θ = tan^-1(0.478/-1.223) ≈ -21.48°

Since the direction is measured with respect to the positive x axis, the direction from "home" to "you" when the phone rings is about 21.48° West of South.

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The average velocity of the car over the first second is -50 m/s.

The first option is correct.

Average velocity is the ratio of the displacement to the time interval.

The formula to calculate the average velocity is as follows;

where;

Displacement is the change in distance or position in a specified direction.

That is the difference between the final and initial distances.

Considering the graph of the automobile brake test given in the attachment;

displacement over the first second = 50 - 100 m

displacement over the first second = -50 ms

Average velocity = -50 m/ 1 s

Average velocity = -50 m/s

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Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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The sled's speed can be calculated by considering the acceleration, frictional force, and time. After substituting the given values and performing the calculations, the final speed is determined to be 12.25 m/s.

To calculate the speed of the sled after 2.50 seconds, we can use the equations of motion and consider the forces acting on the sled.

Let's denote the initial speed of the sled as v0, the final speed as vf, the acceleration as a, the time as t, and the coefficient of friction as μ.

Initially, the rocket sled is accelerating, so we can use the equation:

vf = v0 + at

Since the sled is skidding along its rails after the rocket engine stops, the only horizontal force acting on the sled is the force of friction. The frictional force can be calculated using the equation:

frictional force = coefficient of friction * normal force

Since the sled is moving horizontally, the normal force is equal to the weight of the sled, which can be calculated as:

weight = mass * gravity

Now, we can determine the acceleration of the sled using Newton's second law:

frictional force = mass * acceleration

Combining the equations and substituting the values, we have:

vf = v0 + (frictional force / mass) * t

To find the frictional force, we need to calculate the weight of the sled and then multiply it by the coefficient of friction:

frictional force = (mass * gravity) * coefficient of friction

Substituting this back into the previous equation, we get:

vf = v0 + ((mass * gravity * coefficient of friction) / mass) * t

Simplifying further, we have:

vf = v0 + (gravity * coefficient of friction) * t

Now we can substitute the given values into the equation. Assuming the acceleration due to gravity is approximately 9.8 m/s², the coefficient of friction is 0.5, the initial speed is 0 m/s (since the sled starts from rest), and the time is 2.50 s, we can calculate the final speed:

vf = 0 + (9.8 * 0.5) * 2.50

vf = 12.25 m/s

Therefore, the sled is moving at a speed of 12.25 m/s after 2.50 seconds.

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Answer:

P = 198.118 kPa

Explanation:

Given:

Atmospheric pressure = P\(_{atm\\}\) = 1.01×10⁵

depth = h = 9.91 m

To find:

Absolute pressure P\(_{abs}\)

Solution:

Density of water = ρ = 1.000x10 ³kg/m ³

acceleration due to gravity = ρ = 9.8 m/s²

P\(_{abs}\) = P\(_{atm\\}\) + ρgh

      = 1.01×10⁵ + 1.000x10 ³x 9.8 x 9.91

      = 101000 + 1000(9.8)(9.91)

      = 101000 + 97118

      = 198118 Pa

      = 198.118 kPa

P\(_{abs}\) = 198.118 kPa

The absolute pressure at a depth below the surface of this deep lake is 198.118 kPa.

Given the following data:

Scientific data:

To calculate the absolute pressure at a depth below the surface of a deep lake:

Mathematically, absolute pressure is given by this formula:

\(P_{abs} = P + \rho gh\)

Substituting the given parameters into the formula, we have;

\(P_{abs} = 1.01 \times 10^5 + 1000 \times 9.8 \times 9.91 \\\\ P_{abs} = 101000+ 97118 \\\\\)

Absolute pressure = 198118 Pa

Note: 1 kPa = 1000 Pa

Absolute pressure = 198.118 kPa

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The maximum velocity is 48π m/s.

The equation: can be used to determine the maximum velocity of a particle in simple harmonic motion.

Vmax = ω * A

Where

The following formula can be used to get the angular frequency:

ω = 2π / T

Where

T is the motion's period.

Given that the period is π/2 seconds (T = π/2) and the amplitude is 12 m (A = 12), we can find the angular frequency:

ω = 2π / (π/2) = 4π rad/s

Now we can calculate the maximum velocity:

Vmax = ω * A = (4π rad/s) * (12 m) = 48π m/s

Therefore, the maximum velocity is 48π m/s.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.

Given in the question

The volume of the liquid = Volume of the container

                                  =  120 cm³

Total Mass = 145 grams

Mass of the empty Beaker = 51 grams

To find

Mass of the liquid

The density of the liquid

Now,

Total Mass = Mass of LIquid + Mass of the empty Beaker

Mass of LIquid = Total Mass -  Mass of the empty Beaker  

Put in the value, we get

Mass of liquid = 145 - 51 grams

Mass of liquid = 94 grams

Now, Density is the ratio of the mass of the substance and the volume, the substance occupies in the space. It is not a constant value and is variable with the variation in the temperature of the substance. Its S.I. unit is Kg/m³. B ut its other commonly used unit is gram/cm³.

The density of liquid = Mass of the liquid/ Volume of the liquid

Put in the value, we get

The density of the liquid = 94/120  grams/cm³

The density of the liquid = 0.78 grams/cm³ = 780 Kg/m³

Therefore, the mass of liquid in the container is 94 grams and the density of the liquid is 0.78 grams/cm³ or 780 Kg/m³.

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A Measuring Cylinder liquid contains a volume of 120cm³ the liquid was then poured into an empty beaker of mass 51g. The total mass was then found to be 145g . Calculate the mass of the liquid and the density of the liquid.

Answer: 3m

Explanation: If he is already 2m away from the mirror then if he walks away 1m then it would equal out to 3. You could also add 1 to 2 so you could get the same results.