What is the mass of 3.15 moles of calcium sulfate, CaSO4?

When 325 grams of CHCl3 is produced, approximately 297.54 grams of HCl are also produced.

To determine the amount of HCl produced when 325 grams of CHCl3 (chloroform) is produced, we need to use the balanced chemical equation for the reaction:

CH4 + 3Cl2 -> CHCl3 + 3HCl

From the balanced equation, we can see that the stoichiometric ratio between CHCl3 and HCl is 1:3. This means that for every 1 mole of CHCl3, 3 moles of HCl are produced.

To calculate the number of moles of CHCl3, we need to divide the given mass (325 grams) by its molar mass:

Molar mass of CHCl3 = 12.01 g/mol (C) + 1.01 g/mol (H) + 3 x 35.45 g/mol (Cl) = 119.38 g/mol

Moles of CHCl3 = 325 g / 119.38 g/mol = 2.72 mol

Since the stoichiometric ratio between CHCl3 and HCl is 1:3, the number of moles of HCl produced is three times that of CHCl3:

Moles of HCl = 2.72 mol x 3 = 8.16 mol

To calculate the mass of HCl, we multiply the number of moles by its molar mass:

Molar mass of HCl = 1.01 g/mol (H) + 35.45 g/mol (Cl) = 36.46 g/mol

Mass of HCl = 8.16 mol x 36.46 g/mol = 297.54 g

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Answer:

By breaking down glucose into an energy molecule (ATP), so by producing energy which is necessary for the cell's survival.

Explanation:

Molarity of household ammonia is 0.499 M (rounded to three significant figures).

What is Molarity?

Molarity is a measure of the concentration of a solution and is defined as the number of moles of solute dissolved per liter of solution.

The molarity of household ammonia can be calculated using the formula:

Molarity (M) = moles of solute / liters of solution

First, we need to calculate the number of moles of NH3 in 4.25 grams:

moles of NH3 = mass / molar mass = 4.25 g / 17.03 g/mol = 0.2494 mol

Next, we need to calculate the volume in liters of the solution:

volume of solution = 0.500 L

Finally, we can use the formula to calculate the molarity:

Molarity (M) = moles of solute / liters of solution

M = 0.2494 mol / 0.500 L = 0.499 M

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After the complete neutralization reaction occurs, excess hydroxide ion is left unreacted and concentration of the hydroxide ion, [OH-] is 0.02 M.

The hydroxide ion concentration is the amount in moles of hydroxide ion in a solution.

The hydroxide ion concentration is written as [OH-].

The equation of the reaction is given below:

\(HBr(aq) + KOH(aq) \rightarrow KBr(aq) + H_2O(l) \\ \)

1 mole of HBr reacts with 1 mole of KOH

Moles of HBr = 40 mL × 0.1 M = 4 mmmoles

Moles of KOH = 60 mL × 0.1 M = 6 mmoles

Moles of [OH-] = 6 - 4 = 2 mmoles

Volume of solution = 100 mL

[OH-] = 2mmoles/100 mL = 0.02 M

Therefore, the concentration of the hydroxide ion, [OH-] is 0.02 M.

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Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes.

Sediment refers to any material that is transported and deposited by water, wind, ice, or gravity. Sediments can be composed of various materials, such as minerals, rocks, organic matter, and even human-made debris.

Sediments can accumulate in different environments, such as rivers, lakes, oceans, and deserts, and can be deposited in layers over time.

Subaquatic soil can be classified as sediment or soil based on its geological properties and formation processes. If it has primarily formed through sediment deposition, it is more appropriate to classify it as sediment.

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9. The specific heat capacity of the metal is approximately 0.47 J/g°C, 10. The specific heat of the metal is approximately 0.52 J/g°C.

9-To determine the specific heat capacity of the metal, we can use the formula:

q = mmetal × cmetal × ΔTmetal + mwater × cwater × ΔTwater

where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

cmetal = q/(mmetal × ΔTmetal)

q = mwater × cwater × ΔTwater = (250.0 g) × (4.184 J/g°C) × (27.2°C - 24.3°C) = 3111.8 J

mmetal = 125.0 g

ΔTmetal = 27.2°C - 100.0°C = -72.8°C

cmetal = 3111.8 J/(125.0 g × -72.8°C) ≈ 0.47 J/g°C

10- To solve for the specific heat of the metal, we need to account for the heat capacity of the calorimeter as well. The heat transferred from the metal to the water is given by:

q = (mmetal × cmetal + Ccalorimeter) × ΔT + mwater × cwater × ΔT

cmetal = (q - Ccalorimeter × ΔT)/(mmetal × ΔT)

q = (1000.0 g) × (4.184 J/g°C) × (26.5°C - 24.9°C) = 1253.44 J

Ccalorimeter = 1101 J/°C

mmetal = 750.0 g

ΔT = 26.5°C - 100.0°C = -73.5°C

cmetal = (1253.44 J - 1101 J/°C × -73.5°C)/(750.0 g × -73.5°C) ≈ 0.52 J/g°C

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Answer:

Metallic character refers to the level of reactivity of a metal. Non-metallic character relates to the tendency to accept electrons during chemical reactions. Metallic tendency increases going down a group. Non-metallic tendency increases going from left to right across the periodic table.

Explanation:

I hope this helps :)

Answer:

Explanation:

Non metals increases in reactivity!

The property of water that causes polar water molecules to surround ions, reducing the likelihood of them interacting with other ions, is known as its solvation or hydration ability.

This solvation property is a result of water's high polarity, which arises from its asymmetrical molecular structure and the presence of polar covalent bonds. Water molecules have a partially positive (+) and partially negative (-) end due to the electronegativity difference between oxygen and hydrogen atoms. This polarity enables water molecules to form hydrogen bonds with other water molecules and with polar solutes, such as ions. When ions dissolve in water, the partially positive hydrogen atoms of water molecules are attracted to the negatively charged ions, and the partially negative oxygen atoms of water molecules are attracted to the positively charged ions.

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Answer:

because time is independent and distance is dependent . time goes on if distance is not there but if distance is covered it is covered in certain time . that's why distance is taken on y axis while displacement on x axis

Answer:

49 Newtons

Explanation:

The weight of the rock is the product of it's mad and the acceleration due to the earth's gravity(which is 9.8 meters per squared second)

So 5.0kg times 9.8 equals 49 Newtons.

Humidity refers to the amount of moisture present in the air or atmosphere. It is a crucial atmospheric parameter that impacts various aspects of our environment and daily lives.

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Answer:

Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry

The limiting reactant, given that 0.30 moles of BF₃ reacted with 0.90 moles of H₂ is BF₃

We'll begin by writing the balanced equation for the reaction. This is given below:

2BF₃ + 3H₂ → 2B + 6HF

From the balanced equation above,

2 moles of BF₃ reacted with 3 moles of H₂

With the above information, we shall determine the limiting reactant as follow:

From the balanced equation above,

2 moles of BF₃ reacted with 3 moles of H₂

Therefore,

0.3 mole of BF₃ will react with = (0.3 × 3) / 2 = 0.45 mole of H₂

From the above calculation, only 0.45 mole of H₂ out of 0.9 mole given, reacted with 0.3 mole of BF₃.

Thus, BF₃ is the limiting reactant

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Answer:Thermal energy transfer involves the transfer of internal energy.

Explanation:

Three types of thermal energy transfer are conduction, convection and radiation.

They contain Carbon, Nitrogen, Hydrogen, Oxygen, and Sulfur

Answer:

C

Explanation:

We can use heat stoichiometry. Thus, convert from grams of Ba to moles of Ba; and use the ΔH value to calculate the amount of heat released. Hence:

\(\displaystyle 5.75\text{ g Ba}\cdot \frac{1\text{ mol Ba}}{137.33\text{ g Ba}} \cdot \frac{1\text{ mol}_{rxn}}{2\text{ mol Ba}} \cdot \frac{-1107\text{ kJ}}{1\text{ mol}_{rxn}} =-46.4 \text{ kJ}\)

Therefore, about 46.4 kJ of heat was released.

In conclusion, our answer is C.

Answer:

\(296.05\ \text{K}\)

Explanation:

\(m_w\) = Mass of water = 100 g

\(c_w\) = Specific heat of water = \(4.184\ \text{J/g K}\)

\(m_c\) = Mass of copper = 20 g

\(c_c\) = Specific heat of copper = \(0.385\ \text{J/g K}\)

\(\Delta T_w\) = Temperature change in water = \((T-295)\)

\(\Delta T_c\) = Temperature change in cooper = \((353-T)\)

T = Final temperature of the system

The heat balance of the system is given by

\(m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}\)

The final temperature of the water is \(296.05\ \text{K}\).

The final temperature of the water when placed in a calorimeter is 296.05K

HOW TO CALCULATE FINAL TEMPERATURE:

Where;

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The number of moles of carbondioxide that can fill the sealed container is 0.261moles.

The number of moles of an ideal gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

According to this question, a sealed container can hold 6.28L carbondioxide at 1.00 atm and 293 K. The number of moles of the gas can be calculated as follows:

1 × 6.28 = n × 0.0821 × 293

6.28 = 24.0553n

n = 6.28 ÷ 24.0553

n = 0.261moles

Therefore, 0.261moles is the number of moles of the gas that can fill the container.

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The student's method for preparing pure crystals of copper sulfate contains errors and does not produce the desired outcome.

Use copper oxide instead of calcium carbonate: The student should add copper oxide (CuO) to the hydrochloric acid instead of calcium carbonate. Copper oxide reacts with hydrochloric acid to form copper chloride, which can then be converted to copper sulfate through a subsequent reaction with sulfuric acid.

Add sulfuric acid to the copper chloride solution: After the copper chloride solution is formed, the student should add sulfuric acid to it. This reaction between copper chloride and sulfuric acid will yield copper sulfate and hydrochloric acid. The student should ensure that the correct stoichiometric ratio is maintained to maximize the yield of copper sulfate crystals.

Crystal formation: The student should allow the solution to cool slowly after the reaction with sulfuric acid. This promotes the formation of larger, well-defined copper sulfate crystals.

Filtration and drying: Once the crystals have formed, the student should filter the solution to separate the solid crystals from the remaining liquid. The filtered crystals should then be thoroughly dried to remove any remaining water, resulting in pure copper sulfate crystals.

By following these improvements, the student can obtain pure crystals of copper sulfate.

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By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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Answer: I Think It's D) The change of solubility with temperature is the same for all substances.

Answer:

The same amount of two different liquids you used in the container will have different densities because they have different masses. The liquids that weigh more (a higher density) will sink below the liquids that weigh less (a lower density).

Material: Density (g/cm3)

Light Corn Syrup: 1.33

Vegetable Oil: 0.92

Explanation:

Science

Answer:

is B

Explanation:

7.11 × 10⁻⁴ is the solubility (in M) of PbCl\(_2\) in a 0.15 M solution of HCl. The Ksp of PbCl\(_2\) is 1.6 x 10⁻⁵.

The capability of a material, the solute, to combine with another material, the solvent, is known as solubility in chemistry. Insolubility, or the solute's inability to create such a solution, is the opposite attribute.

The amount of each of the solute within a saturated solution—a solution whereby no more solute is able to be dissolved—is typically used to gauge the degree of a substance's solubility in a particular solvent.

PbCl\(_2\) ⇌ Pb\(_2\)⁺(x) + 2Cl⁻ (2x)

HCl ⇌H⁺ (0.15M) + Cl⁻ (0.15M)

Ksp = {Pb\(_2\)⁺} {Cl⁻}²

Ksp = {x} {2x+ 0.15}²

2x<0.15

Ksp = {x} {0.15}²

x = 7.11 × 10⁻⁴

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Answer:

1 sulfur

Explanation:

1 mole is equal to 1 moles Sulfur, or 32.065 grams

Answer:

\(\boxed {\boxed {\sf 1.24727159 \ moles \ of \ sulfur }}\)

Explanation:

To convert from grams to moles, we must use the molar mass found on the Periodic Table of Elements.

1. Molar Mass

This is a sample of sulfur, so look for S on the table.

2. Convert from Grams to Moles

Use the molar mass as a ratio.

\(\frac { 32.07 \ g \ S}{ 1 \ mol \ S }\)

Multiply by the given number of grams: 40

\(40 \ g \ S * \frac { 32.07 \ g \ S}{ 1 \ mol \ S }\)

Flip the fraction so the grams of sulfur will cancel each other out.

\(40 \ g \ S * \frac {1 \ mol \ S }{ 32.07 \ g \ S}=40* \frac {1 \ mol \ S }{ 32.07 }\)

\(\frac {40 \ mol \ S } { 32.07 } = 1.24727159 \ mol \ S\)

There are 1.24727159 moles of sulfur.

Sugar water is a homogeneous mixture. Therefore, option A is correct.

A mixture can be described as made up of two or more different substances which are physically combined in a mixture. A mixture of two or more substances can break down into their original components.

The composition of a heterogeneous mixture can not be uniform entire the mixture while the composition of a homogeneous mixture can be always the same.

Pure substances cannot be broken down into simple substances that have only one kind of atom in the entire composition.

A pure substance can be described as made up of two or more elements that are chemically combined together and has a set composition such type of pure substance is called a compound.

As the sugar completely dissolved in water so it is a homogeneous mixture.

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Your question is incomplete, the complete question was,

Which of the following is a homogeneous mixture

A ) sugar solution

B) Mud

C) dirt

D) salsa

According to molar concentration, 19.5 ml of  0.300 M NaOH solution is required to neutralize 32.5 cm³ of a 0.180 M HCI solution.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

In the given problem, volume of NaOH is found out by the formula M₁V₁=M₂V₂ substitution in the given formula gives, V₁=0.180×32.5/0.3=19.5 ml.

Thus, 19.5 ml of  0.300 M NaOH solution is required to neutralize 32.5 cm³ of a 0.180 M HCI solution.

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Arginine formula empirical is C3H7NO2.

One of the amino acids that makes up protein is arginine. It is classified as semi-essential, which means that even though the body can generate it, there are some situations where extra intake from dietary sources may be necessary. Arginine is involved in a variety of body processes, including the production of nitric oxide, which aids in controlling blood pressure and blood flow, as well as wound healing.

The smallest whole number ratio of the atoms in a compound must be identified in order to obtain the empirical formula for the compound. The substance has the chemical formula C6H14N4O2.

Divide all the subscripts by their biggest common component, in this case 2, to obtain the smallest whole number ratio. The result of multiplying each subscript by two is C3H7N2O1. The substance's empirical formula is C3H7NO2.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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