What is the mass number of platinum 

The strawberry DNA looks like snot under a microscope. Strawberry DNA will look like a stringy white substance. But if you carefully stretch it out you can see more of the details of those strands of DNA.

Ripe strawberries are an excellent source for extracting DNA because they are easy to pulverize and contain enzymes called pectinases and cellulases that help to break down cell walls. And most important, strawberries have eight copies of each chromosome (they are octoploid), so there is a lot of DNA to isolate.

Deoxyribonucleic acid extracted from cells has been variously described as looking like strands of mucus; limp, thin, white noodles; or a network of delicate, limp fibers. Under a microscope, the familiar double-helix molecule of DNA can be seen.

It lives in a cells nucleus in pairs called chromosomes. Humans have 46 chromosomes arranged in 23 pairs.

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Answer:

A variety of household products are hazardous. Motor oil, pesticides, oil-based paints, mothballs, flea collars, weed killers, and some household cleaners

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Non polar: A bon in which neither atom takes more than its share of electrons

Metallic : A type of bond that allows valence electrons to move freely among its ions

Polar: A bond with a negative end and a positive end

Electronegativity: Determines what type of bond will form

Diatomic: Composed of two atoms

It will take approximately 49,580 years for 80% of the plutonium-239 isotope to decay.

To determine the time required for 80% of the plutonium-239 isotope to decay, we can use the concept of half-life. The half-life of a radioactive isotope is the time it takes for half of the initial amount of the isotope to decay.

Given that the half-life of plutonium-239 is 24,360 years, we can calculate the number of half-lives required for 80% decay. Since each half-life reduces the amount of the isotope by half, we need to find how many times we need to divide 10 g (the initial amount) by 2 to reach 80% of the original amount.

Let's calculate:

Initial amount = 10 g

Amount after one half-life = 10 g / 2 = 5 g

Amount after two half-lives = 5 g / 2 = 2.5 g

Amount after three half-lives = 2.5 g / 2 = 1.25 g

Amount after four half-lives = 1.25 g / 2 = 0.625 g

We can see that after four half-lives, the amount remaining is less than 20% of the initial amount. Since each half-life is 24,360 years, the time required for four half-lives is approximately 97,440 years. Therefore, it will take approximately 49,580 years (97,440 years - 47,880 years) for 80% of the plutonium-239 isotope to decay.

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Answer:

nucleus

Explanation:

the nucleus is made of protons and neutrons that make up the mass of the atoms, electrons have negligible masses

Answer:

the nucleus

Explanation:

The protons and neutrons in the center of the atom are about 2,000 times heavier than the electrons orbiting around it. Because the electrons are so light by comparison, they represent only a tiny fraction of a percent of the atom's total weight.

The standard reaction free energy for the chemical reaction 4\(PCl_{3}\)(g)→\(P_{4}\)(g)+6\(Cl_{2}\)(g) is 1151 kJ/mol.

The standard free energy of a reaction (ΔG°) is a thermodynamic quantity that represents the change in Gibbs free energy for a chemical reaction under standard conditions.

To calculate the standard reaction free energy of the chemical reaction 4\(PCl_{3}\)(g)→\(P_{4}\)(g)+6\(Cl_{2}\)(g), we need to use the thermodynamic information provided in the ALEKS Data tab.

First, we need to find the standard free energy change (∆G°) of formation for each compound involved in the reaction.

∆G\(^{o}_{f}\) for \(PCl_{3}\)(g) = -287.7 kJ/mol
∆G\(^{o}_{f}\)for \(P_{4}\)(g) = 0 kJ/mol
∆G\(^{o}_{f}\)for \(Cl_{2}\)(g) = 0 kJ/mol

Next, we use the formula:
∆G\(^{o}_{rxn}\) = Σ∆G\(^{o}_{f}\)(products) - Σ∆G\(^{o}_{f}\)(reactants)

Plugging in the values:
∆G\(^{o}_{rxn}\)= [(0 kJ/mol) + (6 x 0 kJ/mol)] - [(4 x -287.7 kJ/mol)]
∆G\(^{o}_{rxn}\) = 1151 kJ/mol

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In a carbon monoxide molecule, the C=O bond has a bond polarity of (δ+)C-O. Option 5 is Correct.

This means that the electron density is more concentrated around the oxygen atom (δ+) than around the carbon atom (δ-), causing the oxygen atom to be slightly negatively charged and the carbon atom to be slightly positively charged. The electronegativity difference between C and O (3.5 - 2.5 = 0.5) is the source of this polarity. The electronegativity difference between carbon and oxygen in a carbon monoxide molecule is 0.5.

This means that oxygen is more electronegative than carbon. As a result, the electrons in the C=O bond are pulled slightly closer to the oxygen atom, creating a slight negative charge on the oxygen atom and a slight positive charge on the carbon atom. It's worth mentioning that the concept of electronegativity is based on the ability of atoms to attract electrons in a covalent bond, and it's a relative scale, where the difference between two atoms is measured in comparison to all other atoms in the periodic table.  

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Correct Question:

Given the electronegativity values of C (2.5) and O (3.5), illustrate the bond polarity in a carbon monoxide molecule, CO, using delta notation.Group of answer choices

1. (δ-) C-O

2. (δ+)(δ+) C-O

3. (δ-)(δ+) C-O

4. (δ+)(δ-) C-O (δ-)

5. none of the above.

The molar solubility of C2D3 is calculated to be equal to 9.67 x 10^-3 mol/L .

The solubility of a substance is measured by the number of moles of the solute that dissolve in one liter of solution, or molar solubility. The quantity of ions dissolved per liter of solution is measured by molar solubility. In this case, solubility refers to how many ions can be dissolved in a specific volume of solvent.

As, C2D3 = (2x)^2 * (3x)^3= 108 x^5

Given, solubility product constant - 9.14×10−9

SO, 9.14 x 10^-9 = 108 x^5

Now, x = 9.67 x 10^-3

Hence,  the molar solubility is 9.67 x 10^-3 mol/L.

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Answer:

395.84cm³

Explanation:

V= π r² h

V= 3.14 6² 3.5

V= 3.14 36 3.5

V= 395.84

The volume of the air inside the cylinder is 395.64 cubic centimeters.

Given:

A cylinder container is filled with air. Its radius is 6.00 cm and its height is 3.50 cm.

To find:

The volume of the air inside the cylinder.

Solution:

The radius of cylinder = r = 6.00 cm

The height of the cylinder = h = 3.50 cm

The volume of the cylinder = V

The volume of the cylinder is given :

\(V=\pi r^2 h\\\\V=3.14\times (6.00 cm)^2\times 3.50 cm\\\\V=395.64 cm^3\)

The volume of the air in cylinder = V = \(395.64 cm^3\)

The volume of the air inside the cylinder is 395.64 cubic centimeters.

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Answer:

B and D

Explanation:

Answer D, look like you're missing (g) which stands for gas

so answer B (which is aq) and answer D (which is g) are correct.

Grams and litters are not used in the chemical equations but used in calculation of the quantities of reactants and products.

The role of cytotoxic T cells is to attack body cells that have been infected with specific viruses and bacteria, in order to prevent the spread of infection.

These T cells are able to recognize and target cells that display fragments of the virus or bacteria on their surface, and then release toxic substances that destroy the infected cells. This helps to limit the damage caused by the invading pathogen and also triggers the production of antibodies to help clear the infection.

The role of cytotoxic T cells is to attack body cells that have been infected by specific viruses and bacteria. They play a crucial role in the immune response by eliminating harmful pathogens and protecting the body.

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When solid converts to gas then heat is required to break the intermolecular forces of attraction between the particles. In this process heat increase but temperature remains the same. Therefore, the correct option is option B.

Phase transition is a process in which transition takes place from one state to another of a medium on changing temperature or pressure. Phase transition is a physical process as there is no breaking of old bond and forming of new bonds takes place.

During phase transition temperature remain constant as the extra heat that is given to the system that goes into breaking of intermolecular forces of attraction between the particles. So overall temperature remains same but heat keeps on increasing.

Therefore, the correct option is option B that is energy is absorbed by the substance to cause a phase change.

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Apollo boasted to Cupid about how much larger his bow was. Apollo was offended, and Cupid hit him with a golden love arrow in retaliation, leading him to fall in love with the first person he saw.

Who was punished by Apollo for having a human lover?

Daphne, in her effort to escape him, was changed into a laurel, his sacred tree; Coronis was shot by Apollo's twin, Artemis, when she proved unfaithful; and Cassandra rejected his advances and was punished by being made to utter true prophecies that no one believed.5 days ago

Apollo unexpectedly advised Eros to leave warlike weapons to powerful gods like him and stick to magic instead after defeating Python, a terrible earth-dragon that lived near Delphi.

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The final pressure in the vessel will be three times the initial pressure, or 3P1.

Since the reaction goes essentially to completion, we can assume that all of the CH₃OH(g) will be converted into CO(g) and 2 H₂(g). Therefore, the total number of moles of gas in the vessel will increase from 1 to 3.

Using the ideal gas law, we can calculate the final pressure in the vessel:

P1V1/T1 = nRT/V2

where P1 is the initial pressure, V1 is the initial volume (which we can assume is negligible), T1 is the initial temperature (600 K), n is the initial number of moles (1), R is the gas constant, and V2 is the final volume.

Solving for P2 (the final pressure):

P2 = (n + 2)RT1/V1

Substituting the values we know:

P2 = (1 + 2)RT1/V1

P2 = 3P1

Therefore, the final pressure in the vessel will be three times the initial pressure, or 3P1.

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COMPLETION QUESTION:

CH₃OH(g) —> CO(g) + 2 H₂(g)

DH° = +91 kJ/molrxn

The reaction represented above goes essentially to completion. The reaction takes place in a rigid, insulated vessel that is initially at 600 K A sample of CH3OH(g) is placed in the previously evacuated vessel with a pressure of P1 at 600 K. What is the final pressure in the vessel after the reaction is complete and the contents of the vessel are returned to 600 K?

The compound that cannot form hydrogen bonds with water is (CH₃CH₂)₃N. Hydrogen bonding occurs between a hydrogen atom bonded to an electronegative atom (such as oxygen or nitrogen) and another electronegative atom.

Hydrogen bonding occurs between a hydrogen atom bonded to an electronegative atom (such as oxygen or nitrogen) and a lone pair of electrons on another electronegative atom. In the given compounds, CH₃CH₂OH (ethanol) and CH₃CH₂NH₂ (ethylamine) have oxygen and nitrogen atoms, respectively, that can act as hydrogen bond acceptors. Therefore, they can form hydrogen bonds with water. (CH₃CH₂)₃N (triethylamine) and (CH₃CH₂)₂NH (diethylamine) do not have hydrogen atoms bonded to electronegative atoms that can serve as hydrogen bond acceptors. Instead, the nitrogen atom in (CH₃CH₂)₃N and (CH₃CH₂)₂NH only has hydrogen atoms bonded to it. As a result, these compounds do not have the necessary hydrogen bond acceptors to form hydrogen bonds with water. Thus, (CH₃CH₂)₃N is the compound that cannot form hydrogen bonds with water.

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A single Lewis structure that obeys the octet rule for so2 is

.. .. ..

: O = S - O :

..

Lewis structure of SO2 can be drawn if we know the valence electrons of both sulphur and oxygen atom. As we know they both belong to the same group i.e. 16th but different periods. Sulphur has 6 valence electrons and 6 valence electrons from each Oxygen atom i.e. 6x2=12. Total valence electrons of SO2= 18. S is the central atom and has 2 O atoms attached to it. The sulphur has 1 lone pair as one of the oxygen atom is double bonded to the S atom and the other atom of Oxygen is singly bonded to the S atom. The oxygen atom which is double bonded has 2 lone pairs and the one which is singly bonded has 3 lone pairs and all the atoms obey the octet rule.

.. .. ..

: O = S - O :

..

we can also draw the same structUre with the double bonded Oxygen on the other Oxygen, so we can have 2 resonance structures.

Formal charges:- To calculate the formal charge of an atom substract the no. of non- bonding electrons and half the no. of bonded electrons from the no. of its valence electrons.

Formal charge = VE - NBE - BE/2

so, zero on the O that is double bonded to S.

+1 on the S.

-1 on the O that is single bonded to S.

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The molality of the solution made by dissolving 14.7g of c6h12o6 into 250.0 ml of aqueous solution is 0.326 mol/kg.

The molality of a solution is defined as the number of moles of solute per kilogram of solvent. In this case, we need to first convert the mass of solute (c6h12o6) into moles.
The molar mass of c6h12o6 is 180.16 g/mol.
14.7 g / 180.16 g/mol = 0.0815 mol c6h12o6
Next, we need to convert the volume of the solution from milliliters to kilograms.
250.0 mL = 0.25 L = 0.25 kg (assuming the density of the aqueous solution is 1 g/mL)
Now we can calculate the molality:
molality = moles of solute / kilograms of solvent
molality = 0.0815 mol / 0.25 kg = 0.326 mol/kg

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Answer:

A

Explanation:

Answer:A

Explanation:

If the KHP has not been dried before weighing, the calculated molarity of the NaOH would be higher than the actual value, since water is included in the apparent mass of KHP.

The KHP is Potassium hydrogen phthalate. It is commonly used as a primary standard in pure form for sodium hydroxide titrations because it is stable in air making it easy to weigh.

However, if KHP is not dried very well, the mass of water is included as part of the mass of KHP and this will make calculated molarity of KHP to be higher than the actual value.

Again, the reaction between KHP and NaOH has a 1:1 molar ratio so if the molarity of KHP is higher than its actual value, the molarity of the NaOH would also be higher than the actual value.

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The empirical formula for the ccompound, given the data is C₇H₈

The mass OC carbon in the compound can be obtained as follow:

Mass of C = (12 / 44) × 4.10

Mass of C = 1.118 mg

Mass of H = (2 / 18) × 0.959

Mass of H = 0.107 mg

The empirical formula can be obtained as follow:

Divide by their molar mass

C = 1.118 / 12 = 0.093

H = 0.107 / 1 = 0.107

Divide by the smallest

C = 0.093 / 0.093 = 1

H = 0.107 / 0.093 = 1.15

Multiply through by 7 to express in whole number

C = 1 × 7 = 7

H = 1.15 × 7 = 8

Thus, the empirical formula of the compound is C₇H₈

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The equation that represents a single replacement reaction given the various options is 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

A single replacement reaction, also known as single displacement reaction is a reaction in which elements higher in the electro-chemical series displace or replace elements lower in the electro-chemical series displace from a solution.

The following example illustrates single replacement reaction:

A + BC -> AC + B

From the above reaction, we can see that A has replace/displace B to from AC.

With the above information, we can determine the equation that represents single replacement reaction. Details below:

Equation from the questions:

From the above, we can see that only 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) conform to single replacement reaction.

Thus, the correct answer to the question is: 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)

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Answer:

The answer is

Explanation:

To find the number of moles of an element given the number of entities contained in that element , we use the formula

\(n = \frac{N}{L} \\\)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.204 × 10²⁴ lithium atoms

We have

\(n = \frac{1.204 \times {10}^{24} }{6.02 \times {10}^{23} } \\ \)

We have the final answer as

Hope this helps you

The numbers in the powers are the number of electrons in a specific orbital. so you can add them to find the atomic number

The answer is C.

The reactants are charcoal that is unlit + oxygen and the products are the burnt charcoal + energy.

So for every combustion reaction like this one, CxHy is the wood. So before you light the wood, it is actally a reactant together with oxygen, because without oxygen the wood will not burn. So under the influence of heat, wood produces substances like carbon dioxide and heat, the moment you see wood burning it it already producing products, CO2 and heat (which is the fire). This is a combustion reaction.

Combustion reaction is exothermic because it releases energy.

Answer:

diselenium heptachloride

Explanation:

Se2Cl7

Se = selenium

Cl = chlorine

Don't forget the "-ide"

Diselenium heptachloride

The chemical equations given would be balanced below

The balanced equation of the various given chemical equations can be determined only when the number of atoms on the product part is the same with the number of atoms on the reactant side.

For 1.)

\(N_{2} + 3H_{2} ----- > 2NH_{3}\)

For 2.)

\(2KCl_{3} ----- > 2KCl + 3O_{2}\)

For 3.)

\(2NaCl + F_{2} ----- > 2NaF + Cl_{2}\)

For 4.)

\(2H_{2} + O_{2} ----- > 2H_{2} O\)

For 5.)

\(Pb(OH)_{2} + 2HCl ----- > 2H_{2} O +PbCl_{2}\)

For 6.)

\(2AlBr_{3} + 3K_{2}SO{4} ---- > 6KBr + Al_{2}(SO_{4})_{3}\)

For 7.)

\(CH_{4} + O_{2} ----- > CO_{2} + 2H_{2} O\)

For 8.)

\(C_{3} H_{8} + 3O_{2} ----- > 3CO_{2} + 4H_{2} O\)

For 9.)

\(C_{8} H_{18} + 8O_{2} ----- > 8CO_{2} + 9H_{2} O\)

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False.

It won’t become one if it’s not proven true.

Answer:

143 parts I think probably not

Answer: true

Explanation: