The main function of a phosphatase enzyme is to remove a phosphate group from a substrate molecule and the type of modification that it remove from a substrate is dephosphorylation.
Dephosphorylation is a type of post-translational modification, which involves the addition or removal of chemical groups from proteins or other molecules after they have been synthesized.
Phosphatase enzymes are involved in a wide range of cellular processes, including signal transduction, cell cycle regulation, and metabolism.
They help to control the activity and function of proteins by modulating their phosphorylation status, which can affect their conformation, localization, and interactions with other molecules.
By removing phosphate groups from substrates, phosphatase enzymes can reverse the effects of protein kinases, which add phosphate groups to proteins through the process of phosphorylation.
This process of phosphorylation and dephosphorylation is an important mechanism for regulating protein activity and signaling pathways within cells.
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Highlight the significant figures and write the number of significant figures in the
blank
3. 0.003005
4. 250
5. 0.0101
6. 741
7. 12
8. 0.0045 46
9. 0.025
10. 0.005670
11. 5007.00
12. 0.0058363
13. 34000.00
14. 0.00418
15. 91,600
Explanation:
3. 4
4. 3
5. 3
6. 3
7. 2
8. 4
9. 2
10. 4
11. 6
12. 5
13. 7
14. 3
15. 5
draw a flowchart to show how you would separate a mixture of benzoic acid, ethyl p- aminobenzoate, and benzophenone.
The flowchart showing how to separate a mixture of benzoic acid, ethyl p- aminobenzoate, and benzophenone is found in the attachment.
How can a mixture of benzoic acid, ethyl p- aminobenzoate, and benzophenone be separated?In order to separate a mixture of benzoic acid, ethyl p- aminobenzoate, and benzophenone, do the following:
1. Dissolve the mixture using a suitable solvent such as dichloromethane or ethyl acetate
2. Perform a liquid-liquid extraction by adding a suitable aqueous solution as follows
To extract benzoic acid: Add a dilute sodium hydroxide (NaOH) solution to convert benzoic acid to its sodium salt, which is more soluble in water. Extract the aqueous layer containing the sodium salt.To extract ethyl p-aminobenzoate: Add a dilute hydrochloric acid (HCl) solution to convert ethyl p-aminobenzoate to its hydrochloride salt, which is more soluble in water. Extract the aqueous layer containing the hydrochloride salt.Benzophenone may remain in the organic layer.
Separate the aqueous layer from the organic layer using a separation funnel or other suitable separation techniques.
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What is the main precaution to take if a gas cylinder sign is present in the lab? select one
The main precautions to take if a gas cylinder sign is present in the lab visually check that the gas cylinder is restrained, but keep a safe distance from it. The correct option is c.
What are the precautions?Precautions are the preventive steps that are taken to save yourself from any dangerous circumstances. These steps are always taken in doing experiments and other scientific procedures.
Here, the precautions are to check the gas cylinder.
Thus, the correct option is c, Visually check that the gas cylinder is restrained, but keep a safe distance from it.
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The question is incomplete. Your most probably complete question is given below:
Remove the strap from around the gas cylinder to use it in the lab.
Open the valve on the gas cylinder periodically to release pressure.
Visually check that the gas cylinder is restrained, but keep a safe distance from it.
Test out the regulator on the gas cylinder to make sure it is working properly.
The temperature at which a solid and a liquid phases of a substance coexist in equilibrium is____________
Answer:
Melting point
Explanation:
The temperature at which the solid and liquid forms of a pure substance can exist in equilibrium is called melting point. It can be also defined as the temperature at which a solid becomes a liquid at normal atmospheric pressure.
What is the formula for the compound iodine trichoride?
Answer:
Cl 3 I
Explanation:
Molecular Weight. 233.36. Appearance. Red-orange to brown powder or chunks. Melting Point. 63 °C
Which feature forms at Earth's surface from the cooling of lava?
O extrusion
fault
O intrusion
unconformity
Extrusion is the feature form at Earth's surface from the cooling of lava.
What are extrusive igneous rocks?They are the ones that originate from a sudden cooling of the incandescent magma when it comes to the surface, which means that there is no time for crystals to form, either partially or totally.
Characteristics of extrusive igneous rocksThese are rocks formed mainly by silicate minerals.Pyroclastics are the product of explosive volcanic eruptions and contain rock fragments of different origins, they can be of many shapes and sizes.Therefore, we can conclude that typical volcanic rocks are formed by the rapid cooling of lava and pyroclastic fragments.
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Answer:
A.
Explanation:
Based on the descriptions in the passage, which scientist proposed a model of the atom that matches the
diagram?
Answer:
J. J. Thomson
Explanation:
This is called the plum pudding model which was proposed by J. J. Thomson.
determine the ksp of ag2s in water using a table of thermodynamic data.
To determine the solubility product constant (Ksp) of silver sulfide (Ag2S) in water, we can use the following equation:
Ksp = [Ag+]^2[S2-]where [Ag+] and [S2-] are the equilibrium concentrations of silver and sulfide ions in water, respectively. To find these concentrations, we can use a table of thermodynamic data that gives the standard Gibbs free energy of formation (ΔGf°) for each species. The relationship between ΔGf° and the equilibrium constant (K) is:
ΔG° = -RTlnKwhere ΔG° is the standard Gibbs free energy of reaction, R is the gas constant, and T is the absolute temperature. For the dissolution of Ag2S in water, we have:
Ag2S(s) <=> 2Ag+(aq) + S2-(aq)The ΔG° for this reaction is equal to the sum of the ΔGf° of the products minus the sum of the ΔGf° of the reactants. Using the table of thermodynamic data, we can find the values of ΔGf° for each species at 25°C:
ΔGf°(Ag2S) = -32.4 kJ/molΔGf°(Ag+) = 77.1 kJ/molΔGf°(S2-) = -36.6 kJ/molPlugging these values into the equation for ΔG°, we get:
ΔG° = 2(77.1) + (-36.6) - (-32.4)ΔG° = 117.6 kJ/molThen, using the equation that relates ΔG° and K, we get:
117.6 x 10^3 = -8.314 x 298 x lnKlnK = -49.7K = 1.7 x 10^-22Since K is equal to Ksp for this reaction, we have:
Ksp = 1.7 x 10^-22About Silver sulfideSilver sulfide is an inorganic compound with the formula Ag2S. This compound is a grayish-black solid consisting of Ag+ cations and S2- anions in a 2:1 ratio. The Ag+ cation and the S2- anion stabilize each other because they are both soft ions.
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write the balanced net ionic equation for the reaction when copper(ii) sulfate and ammonium hydroxide are mixed in aqueous solution. if no reaction occurs, write only nr.
The net ionic equation for the reaction between copper(II) sulfate and ammonium hydroxide depends on whether a reaction occurs.
If a reaction occurs, the balanced net ionic equation will be provided. Otherwise, if no reaction occurs, the notation "nr" will be used to indicate no reaction.When copper(II) sulfate (CuSO4) and ammonium hydroxide (NH4OH) are mixed in aqueous solution, they may undergo a precipitation reaction if a reaction occurs.
In this case, the copper(II) ion (Cu2+) from copper(II) sulfate reacts with the hydroxide ion (OH-) from ammonium hydroxide to form a precipitate of copper(II) hydroxide (Cu(OH)2).The balanced net ionic equation for the reaction, assuming a precipitation occurs, is:
Cu2+ (aq) + 2 OH- (aq) → Cu(OH)2 (s)
On the other hand, if no reaction occurs, it means that there are no significant chemical changes taking place when the two solutions are mixed. In this case, the notation "nr" (no reaction) would be used to indicate that no reaction occurs.
It is important to note that the precise conditions, concentrations, and stoichiometric ratios of the reactants can influence whether a reaction occurs or not. Conducting the actual experiment and observing the formation or lack of formation of a precipitate would provide definitive evidence of whether a reaction takes place.
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An expanding gas does 147 j of work on its surroundings at a constant pressure of 1.04 atm. if the gas initially occupied 68.0 ml, what is the final volume of the gas? l
The final volume of the gas is 209.35 mL.
To find the final volume, we can use the formula W = P * ΔV, where W is the work done, P is the pressure, and ΔV is the change in volume.
We can rearrange the formula W = P * ΔV to solve for ΔV:
ΔV = W / P.
Substituting the given values,
ΔV = 147 J / (1.04 atm) = 141.35 mL.
To find the final volume, we add the change in volume to the initial volume:
Final volume = Initial volume + ΔV = 68.0 mL + 141.35 mL = 209.35 mL.
So, the final volume of the gas is 209.35 mL.
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Phenolphthalein turns litmus paper what color?
Litmus paper and Phenolphthalein are both indicators. This means they will change colour in the presence of an acid or a base.
Litmus paper turns blue in a base and remains red when it is in contact with an acid or neutral solution. Phenolphthalein turns pink in a base, but is coluorless in an acid or neutral solution.
What are the units for specific gravity?
Answer:
Specific gravity is a dimensionless quantity; that is, it is not expressed in units. To find the sp gr of a solid or liquid, you must know its density in kilograms per meter cubed (kg/m3) or in grams per centimeter cubed (g/cm3). Then, divide this density by the density of pure water in the same units.
Explanation:
classify each of these compounds as an arrhenius acid, an arrhenius base, or neither. drag each item to the appropriate bin. view available hint(s)for part a resethelp arhenius aciddroppable arhenius basedroppable neitherdroppable
In order to classify a compound as an Arrhenius acid or base, we need to consider its behavior in aqueous solutions. An Arrhenius acid is a compound that donates a hydrogen ion (H+) in water, while an Arrhenius base is a compound that donates a hydroxide ion (OH-) in water.
If a compound does not exhibit these behaviors in water, it is classified as "neither" an Arrhenius acid nor base.
For example:
- Hydrochloric acid (HCl) donates H+ ions in water, making it an Arrhenius acid.
- Sodium hydroxide (NaOH) donates OH- ions in water, making it an Arrhenius base.
- Carbon dioxide (CO2) does not donate H+ or OH- ions in water, so it is neither an Arrhenius acid nor base.
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what reagents are needed to convert (s)-3-methyl-3-phenylpentaoic acid to (s)-3-methyl-3-phenylpetanamine
1. SOCl2/pyridine
2. NH3
3. LiAlH4
4. H2O
SOCl2/pyridine is added to (S)-3-methyl-3-phenylpentanoic acid first in order to convert it to (5)-3-methyl-3-phenylpentanamine.
The carbonyl carbon is then reduced to an alkane by adding NH3 after which LiAlH4 is added. The mechanism is finished by the addition of water, which causes the product to form.
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A ball is dropped from 22m above the ground. Assuming gravity is −9.8ms2, what is its final velocity?
Answer:
We can use the kinematic equation that relates initial velocity, final velocity, acceleration, and displacement:
v^2 = u^2 + 2as
where
u = initial velocity (which is 0 in this case, since the ball is dropped)
v = final velocity (what we're trying to find)
a = acceleration due to gravity (-9.8 m/s^2)
s = displacement (which is the distance the ball falls, or 22 m)
Plugging in the given values, we get:
v^2 = 0 + 2(-9.8)(22)
v^2 = -431.2
Since we can't have a negative final velocity, we need to take the square root of both sides and include a negative sign to indicate that the final velocity is in the opposite direction of the initial velocity:
v = -sqrt(-431.2)
v ≈ -20.8 m/s
So the final velocity of the ball is approximately -20.8 m/s.
Answer:
The final velocity is -20.8 m/s.
Explanation:
To solve this problem, we can use one of the kinematics equations. Let's first write out which variables we know and what we are trying to figure out. (Note that acceleration due to gravity and Δy must have the same sign).
a = -9.8 m/s²
Δy = -22 m
v1 = 0
v2 = ?
Given these variables, we should use the following equation:
v2² = v1² + 2aΔy
Our next step is to substitute in the given variables and simplify.
v2² = (0) + (2)(-9.8 m/s²)(-22m)
v2² = 431.2
Our final step is to take the square root of both sides to find v2.
v2 = √431.2
v2 = -20.8 m/s
Therefore, the final velocity is -20.8 m/s. The velocity must be in the same direction as the displacement and the acceleration, so its sign should be negative.
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How many grams of molecular chlorine will be required to completely react with 0.0223 moles of sodium iodide according to the following reaction?
2Nal + Cl2 ---> 2NaCl + I2
A. 1.57 104 grams
B. 3.16 grams
C. 0.0112 grams
D. 0.791 grams
The amount of chlorine will be 0.791 gram required to completely react with 0.0223 moles of sodium iodide .
The given chemical reaction is :
2Nal + \(Cl_{2}\) → 2NaCl + \(I_{2}\)
It is given that:
Amount of sodium iodide = 0.0223 mol.
Atomic mass of chlorine = 35.45 g.
The amount of chlorine can be calculated as:
0.0223mol. NaI × (1mol. Cl₂/2mol. NaI) × (35.45g/1mol. Cl2)
=0.791 grams
Therefore, the correct answer will be option (D).
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When a scientist uses reasoning to explain or interpret the things they observe
Answer:
Inferring is when a scientist uses reasoning to explain or interpret the things they observe
1. 0 g of h_{2}o_{2} solution (30 wt%) was titrated with 22. 143 ml of kmno_{4} solution. What is the molarity of the kmno_{4} solution? Report your answer with three decimal places. Molar mass: H2O2 = 34. 01g/mol Reaction: 2MnO2 + 5H2O2 + 6H+ + 2Mn +2 +502 +8H2O Type your numeric answer and submit
The molarity of the KMnO4 solution is 0.532 M (rounded to three decimal places).
To calculate the molarity of the KMnO4 solution, we need to use the stoichiometry of the reaction and the volume of the KMnO4 solution used in the titration.
Given:
Mass of H2O2 solution = 1.0 g
Concentration of H2O2 solution = 30 wt% (weight percent)
Volume of KMnO4 solution used = 22.143 mL
Molar mass of H2O2 = 34.01 g/mol
Step 1: Calculate the moles of H2O2 in the solution.
Moles of H2O2 = (Mass of H2O2 solution) / (Molar mass of H2O2)
= 1.0 g / 34.01 g/mol
= 0.0294 mol
Step 2: Calculate the moles of KMnO4 based on the stoichiometry of the reaction.
According to the balanced equation, the ratio of KMnO4 to H2O2 is 2:5.
Therefore, moles of KMnO4 = (Moles of H2O2) * (2/5)
= 0.0294 mol * (2/5)
= 0.01176 mol
Step 3: Calculate the molarity of the KMnO4 solution.
Molarity (M) = (Moles of KMnO4) / (Volume of KMnO4 solution in liters)
= 0.01176 mol / 0.022143 L
= 0.5316 M
Therefore, the molarity of the KMnO4 solution is 0.532 M (rounded to three decimal places).
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Baking a cake is an example of(a) physical change(c) chemical change(b) irreversible change(e) both (b) and (c)
Baking a cake is an example of a chemical change and irreversible change.
A chemical change is a type of change in which the chemical composition of the substance is modified. As a result, during the chemical reaction, new chemical bonds are created or existing ones are broken. It’s typically accompanied by an alteration in color, temperature, and odor, as well as the production of energy.A physical change is a type of change that does not affect the chemical composition of the substance. The physical properties of the substance, such as size, shape, or state of matter, can change during physical changes. A physical change can be reversed without changing the chemical composition of the substance.In a chemical change, the changes are irreversible. Therefore, baking a cake is an example of a chemical change and irreversible change.In baking a cake, the ingredients, such as flour, sugar, and eggs, are mixed together and subjected to heat in an oven. During this process, a chemical reaction takes place, resulting in the formation of a cake. Hence, it is a chemical change.
A chemical change is the transformation of one substance into another, the emergence of new compounds with distinct characteristics, or any combination of these. It happens when two compounds unite to create a new substance (synthesis) or when two substances break down to create new ones.
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A gold ring cannot be broken down into any other ubtance. What kind of ubtance i gold?
Element. An element is a pure material with only one type of atom that is incapable of being physically or chemically divided into two or more simpler compounds.
As a result, when gold is broken down, gold is still the result. It is a constituent. It is a thick, soft, malleable, ductile, brilliant, somewhat orange-yellow metal in its purest form. Gold belongs to the group 11 family of elements and is a transition metal. It is one of the least reactive chemical elements and, under normal circumstances, is solid. A specific element cannot be broken down into simpler compounds at the atomic level by normal physical or chemical processes. Oxygen, carbon, helium, mercury, copper, and gold are a few examples of elements that you could be familiar with.
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How will the rate of a catalyzed reaction be affected if the solid catalyst is finely ground before it is added to the reaction mixture? A.The rate will be faster because a greater mass of catalyst will be present. B.The rate will be faster because a greater surface area of catalyst will be exposed. C.The rate will be slower because the fine catalyst particles will interfere with product formation. D.The rate will remain the same because the mass of catalyst will be the same.
The correct answer is B. The rate of a catalyzed reaction will be faster if the solid catalyst is finely ground before it is added to the reaction mixture because a greater surface area of catalyst will be exposed. This increased surface area will provide more sites for the reactant molecules to collide with and react on, leading to a higher rate of reaction.
The mass of the catalyst does not directly affect the rate of reaction, but rather the number of available active sites on the surface of the catalyst. Therefore, increasing the surface area of the catalyst by finely grinding it will lead to a higher rate of reaction. It is important to note that the fine catalyst particles must be well dispersed in the reaction mixture to avoid interference with product formation. The rate of a catalyzed reaction will be affected if the solid catalyst is finely ground before it is added to the reaction mixture. The correct option is B. The rate will be faster because a greater surface area of catalyst will be exposed. When a solid catalyst is finely ground, its surface area increases. This allows more of the catalyst to come into contact with the reactants, resulting in more active sites for the reaction to take place. This, in turn, increases the rate of the reaction. It's important to note that the mass of the catalyst remains the same, but the increased molecules surface area is the key factor in enhancing the reaction rate.
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A substance decomposes with a rate constant of 9. 05 x 10^-4 s^-1. How
long does it take for 10. 5% of the substance to decompose?
it takes approximately 49,301 seconds (or 13.69 hours) for 10.5% of the substance to decompose.
To determine the time it takes for a certain percentage of a substance to decompose, we can use the formula for first-order reactions:
t = (ln(N₀/N)) / k
where:
t = time
N₀ = initial concentration or amount of the substance
N = final concentration or amount of the substance
k = rate constant
In this case, the substance decomposes with a rate constant of 9.05 x 10^-4 s^-1, and we want to find the time it takes for 10.5% of the substance to decompose.
Let's assume the initial amount of the substance is 100 units (this is an arbitrary value that allows us to calculate the percentage more easily). Therefore, 10.5% of the substance would be 10.5 units.
Plugging in the values into the formula, we have:
t = (ln(100/10.5)) / (9.05 x 10^-4)
Calculating the natural logarithm:
t = (ln(9.52380952)) / (9.05 x 10^-4)
Using a calculator:
t ≈ 49,301 seconds
Therefore, it takes approximately 49,301 seconds (or 13.69 hours) for 10.5% of the substance to decompose.
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Why is this equation not balanced?
H2 + O2 + H2O
There are more hydrogen atoms on the reactant side than the product side
There are more oxygen atoms on the product side than the reactant side
There are more oxygen atoms on the reactant side than the product side
There are more hydrogen atoms on the product side than the reactant side
PLS HELP
when 0.224 g of sodium metal is added to an excess of hydrochloric acid, 2330 j of heat are produced. what is the enthalpy of the reaction as written? 2na(s) 2hcl(aq)⟶2nacl(aq) h2(g)
The enthalpy of the reaction as written is approximately 239,306 J/mol.
To calculate the enthalpy of the reaction, we need to use the heat released (2330 J) and the amount of sodium reacted (0.224 g) to determine the heat released per mole of sodium reacted.
The molar mass of sodium (Na) is 22.99 g/mol.
First, we need to calculate the number of moles of sodium reacted:
Number of moles of Na = Mass of Na / Molar mass of Na
Number of moles of Na = 0.224 g / 22.99 g/mol ≈ 0.00974 mol
Next, we can calculate the enthalpy change (ΔH) per mole of sodium reacted:
ΔH = Heat released / Number of moles of Na
ΔH = 2330 J / 0.00974 mol ≈ 239306 J/mol
Enthalpy (H) is a thermodynamic property that represents the total heat content of a system at constant pressure. It includes the internal energy of the system plus the product of pressure and volume. Enthalpy is often used to describe heat changes in chemical reactions, where the difference in enthalpy between the reactants and products determines whether a reaction is exothermic (releases heat) or endothermic (absorbs heat). Enthalpy is typically measured in joules (J) or kilojoules (kJ).
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Should future robots be built if they might take away jobs?
Draw the expanded structural formula for the condensed formula (CH3)2CHCH2OCH2CH3 . Draw all hydrogen atoms
We have that the Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below
From the Question
(CH3)2CHCH2OCH2CH3
Generally for the condensed formula (CH3)2CHCH2OCH2CH3
We consider that this is a single bond connecting them
We consider
Hydrogen H(1)
Oxygen(8)
Carbon(6)
In conclusion
The Complete Expanded Structure of (CH3)2CHCH2OCH2CH3 is given in the attachment below.
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100 POINTS! Please help me figure this out!
When magnesium carbonate is added to nitric acid, magnesium nitrate, carbon dioxide, and water are produced.
MgCO3(s)+2HNO3(aq)⟶Mg(NO3)2(aq)+H2O(l)+CO2(g)
How many grams of magnesium nitrate will be produced in the reaction when 31.0 g
of magnesium carbonate is combined with 15.0 g
of nitric acid?
mass of Mg(NO3)2:
g
How many grams of magnesium carbonate remain after the reaction is complete?
mass of MgCO3:
g
How many grams of nitric acid remain after the reaction is complete?
mass of HNO3:
g
Which reactant is in excess?
HNO3
MgCO3
Nitric acid weighs 15.0 g, and 31.0 g of magnesium carbonate is mixed with it to create 31.0 g of \(Mg(No_3)_2\).Nitric acid is present in excess.
What is magnesium ?The chemical element magnesium has the atomic number 12 and the letter Mg as its symbol. It is a highly reactive, silvery-white metal that plays a significant role in the composition of the Earth's crust. Magnesium is the eighth most common element in the crust of the Earth and the ninth most common element in the cosmos.
It makes up a significant portion of the Earth's mantle and is a crucial component of numerous minerals, such as dolomite, talc, and chlorite. Magnesium is necessary for life since it is involved in numerous vital biological processes, such as protein synthesis, DNA replication, and energy consumption.
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At the wavelengths included in Study 1, as the
wavelength of light increases, the reflectance of
Cyanide:
A.
increases only.
B.
decreases only.
C.
increases, then decreases.
D.
decreases, then increases.
Based on the research in Study 1, as the wavelength of light increases, the reflectance of Cyanide: C. increases, then decreases.
What is wavelength?Wavelength is simply defined as the distance (in meters) between two (2) successive crests or troughs of a wave. Thus, wavelength refers to the horizontal distance between two adjacent crests or troughs of a wave.
Generally, there is a linear relationship between the wavelength of light and reflectance. Thus, as the wavelength of light increases, the reflectance of Cyanide in Study 1 increases, before it then decreases.
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2.Which of the following compounds when dissolved in water will turn blue litmus paper red? copper oxide, calcium oxide, sulphur oxide, sodium oxide, iron oxide
Answer:
Sulphur oxide
Explanation:
All of the above oxides with the exception of sulphur oxide are basic oxides and so will not turn blue litmus paper red when dissolved in water. Sulphur oxide, SO2 on the other hand, is an acid anhydride (a non-metallic oxide which dissolves in water to produce acid) rendering it the ability of turning blue litmus paper red when dissolved in water.
Answer:sulpher oxide
Explanation:
All of the compounds except sulpher dioxide are metallic oxide which means basic oxide and base change red litmus paper to blue while acid change blue to red so the answer is the acidic oxide or sulpher dioxide
Which of the following atoms has the largest radius?
a. lithium
b. lead
C. cesium
d. fluorine
e. carbon
Explanation:
first one, a. lithium. it's the largest