What is the length of the x-component of the vector shown below?
A. 72.5
B. 8.1
C. 23.6
D. 34.1

Answer:

Explanation:

Answer: I never said anything to them but if i did it would be "I need a break from you, i love you but sometimes I have to find the path on my own." i would say this if i wasn't scared to hurt them.

Explanation:

Answer:

Explanation:

Answer:

Genetic Engineering:

Benefits: More nutritious food, less use of pesticides, increased supply of food with reduced cost and longer shelf life, faster growing plants and animals

Risk: Creating foods that can cause allergic reaction or that are toxic, Unexpected ir harmful genetic changes, genes moving from one GM plant or animal to anotherplant or animal that is not genetically engineered

Cloning:

Benefits: accelerated reproduction of farmers productive livestock to better produce safe and healthy foods, reproduction of the healthiest animals, minimizing the use of antibiotics, growth hormones and chemicals

Risks: Unwantedhealty effects, defects, premature aging and problems with the immune system

Artificial Selection:

Benefits: no safety issues as those brought by genetic engineering, cheap for agricultural businesses, morally accepted, produce crops with higher yield

Risks: Removes variation, makes organism susceptible to diseasesor changes in environment, unable to control genes inherited by offspring

Answer:

Genetic Engineering  

Benefits  

-Ability to create food that is resistant to pests, cold, and disease.  

-Greater food production volume and increased vitamins.  

Risks  

-Concerns about long-term health risks.  

-Lack of regulation.  

Cloning  

Benefits  

-Ability to increase endangered animal populations.  

-Possibility of eliminating diseases and defective genes.  

Risks  

-Shorter lifespan for cloned animals.  

-Greater chance of health issues for cloned animals.  

Artificial Selection  

Benefits  

-Allows for selection of desired traits.  

-Ability to create better versions of organisms.  

Risks

-Loss of genetic diversity.  

-Increased chance of diseases that can shorten lifespan.

Explanation:

Answer: Gravity creates stars and planets by pulling together the material from which they are made.

Explanation:

Gravity is what holds the planets in orbit around the sun and what keeps the moon in orbit around Earth. The gravitational pull of the moon pulls the seas towards it, causing ocean tides.

The correct statement about the predictions of the gravity model includes "If country A trades more with country B than with country C, B is definitely closer to A than C."

The Gravity Model of International Trade predicts that trade is proportional to the size of economies, measured by their Gross Domestic Product (GDP), and inversely proportional to the distance between them. The distance between countries plays a crucial role in predicting the trade volume between two countries. Distance is more crucial than GDP in determining trade volume.

This statement is true and is an essential prediction of the gravity model.

An increase in the distance between countries results in a reduction of trade between countries. This reduction is due to the increase in the cost of transportation and other costs incurred when doing business with countries that are far away. It also predicts that small countries tend to be more remote from each other than large countries, so the distance between countries is a crucial factor in determining trade volume.

Countries that are not alike will trade with each other if the distance between them is small enough to make trade profitable. The gravity model assumes that countries will engage in trade if the transaction cost of doing so is less than the benefits that would be derived from trading. This model has been widely used to forecast the future direction of trade, to estimate the potential of different markets, and to evaluate the impact of trade policy on economic growth and development.

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The horizontal distance travelled by the football is 3.1 m.

The angle of projection of the football is calculated as follows;

tan ( θ ) = Vy / Vx

where;

tan ( θ ) = 5 / 3

tan ( θ ) = 1.667

θ = arc tan (1.667)

θ = 59⁰

The resultant velocity of the ball is calculated as follows;

v = √ (Vx² + Vy²)

v = √ (3² + 5²)

v = 5.83 m/s

The horizontal distance travelled by the football is calculated as follows;

x = v² sin(2θ) /g

where;

x = [ (5.83)² sin(2 x 59) /9.8 ]

x = 3.1 m

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Answer:

20m/s^2

Explanation:

F=ma, therefore 10N = 0.5kg * a. Solve for a.

a) $$E_1 = \frac{(9.0 \times 10⁹ N m²/C²)(2.6 \times 10⁻⁶C)}{(3.0 m)²} \approx 7.80 \times 10⁵ N/C$$, direction is to the right ; b) $$E_2 = \frac{(9.0 \times 10⁹ N m²/C²)(1.4 \times 10⁻⁶ C)}{(4.0 m)²} \approx 3.94 \times 10⁵ N/C$$, electric field is directed towards point charge so, direction is to the left  c) $$|\vec{E}| = \√{E_1² + E_2²} \approx 8.86 \times 10⁵ N/C$$ and its direction is up.

Charge that exists in a body that has fewer electrons than protons is known as positive electrons.

a. To find the electric field at the origin due to charge Q1, we can use the formula for the electric field due to point charge:

$$E_1 = \frac{k Q_1}{r_1²}$$

k is Coulomb constant (k = 9.0 × 10⁹ N m²/C²), Q1 is the charge, and r1 is the distance from the charge to the point where we want to find the electric field.

Q1 = 2.6 μC and r1 = 3.0 m (since x1 = -3.0 m is the distance from Q1 to the origin).

$$E_1 = \frac{(9.0 \times 10⁹ N m^2/C²)(2.6 \times 10⁻⁶C)}{(3.0 m)²} \approx 7.80 \times 10⁵ N/C$$

The electric field is directed away from point charge, so direction of the electric field at the origin due to Q1 is to the right (positive x direction).

b. Similarly, to find the electric field at the origin due to charge Q2, we use the same formula:

$$E_2 = \frac{k Q_2}{r_2²}$$

where Q2 = 1.4 μC and r2 = 4.0 m (since x2 = 4.0 m is the distance from Q2 to the origin).

$$E_2 = \frac{(9.0 \times 10⁹ N m²/C²)(1.4 \times 10⁻⁶ C)}{(4.0 m)²} \approx 3.94 \times 10⁵ N/C$$

The electric field is directed towards point charge, so direction of the electric field at the origin due to Q2 is to the left.

c. $$\vec{E} = \vec{E_1} + \vec{E_2}$$

$\vec{E_1}$ is the electric field due to Q1 and $\vec{E_2}$ is the electric field due to Q2.

net electric field at the origin is: $$|\vec{E}| = \√{E_1² + E_2²} \approx 8.86 \times 10⁵ N/C$$ and its direction is up.

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The flywheel will not come to rest as the given frictional torque of 4.0 N·m is not enough to stop it from rotating.

The rate of change of angular momentum (L) of the flywheel is equal to the net torque (τ) acting on it. Mathematically,

τ = dL/dt

Since the flywheel is initially rotating with an angular velocity of 400 rad/s, its angular momentum is given by:

L = Iω

where I is the moment of inertia of the flywheel and ω is its angular velocity. The moment of inertia of a solid disk is given by (1/2)MR², where M is the mass of the disk and R is its radius. Therefore, the moment of inertia of the flywheel is:

I = (1/2)MR²

Substituting the given values, we get:

I = (1/2)(1.0 x \(10^6\))/(π(0.2)²) = 79577.47 kg·m²

So, the angular momentum of the flywheel is:

L = Iω = 79577.47 x 400 = 31,831,888 kg·m²/s

The frictional torque acting on the flywheel is 4.0 N·m, so we have:

τ = 4.0 N·m

Setting these two equations equal to each other, we get:

dL/dt = τ

d(Iω)/dt = 4.0

I(dω/dt) + ω(dI/dt) = 4.0

Since the moment of inertia of the flywheel is constant, dI/dt = 0. So we have:

I(dω/dt) = 4.0

Substituting the values of I and τ, we get:

79577.47 x (dω/dt) = 4.0

dω/dt = 5.03 x \(10^-^5\) rad/s²

The flywheel will come to rest when its angular velocity becomes zero. Using the equation of motion for rotational motion:

ω = ω0 + αt

where ω0 is the initial angular velocity, α is the angular acceleration, and t is time.

Substituting the values of ω, ω0, and α, we get:

0 = 400 + (5.03 x \(10^-^5\))t

t = -400/(5.03 x \(10^-^5\))

t = -7.96 x \(10^6\) s

Since time cannot be negative, the flywheel cannot come to rest in this case. This means that the frictional torque of 4.0 N·m is not enough to stop the flywheel from rotating.

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Four views of a horseshoe magnet and a current-carrying wire are shown in the drawing. The wire is perpendicular to the screen, and the current is directed out of the screen towards you.

The magnetic force acting on a current-carrying wire is influenced by the direction of the current flow and the direction of the magnetic field, which is decided by the magnetic pole it is near. The magnetic field lines created by a bar magnet, for example, run from the north to the south pole.In the given figure, the magnetic field lines are moving from north to south, as shown by the white arrow.

When the direction of the current is perpendicular to the direction of the magnetic field, a magnetic force is exerted on the current-carrying wire. According to the right-hand rule, the magnetic force on the wire will be perpendicular to both the current-carrying wire and the direction of the magnetic field.

According to the right-hand rule, magnetic force will be directed north in the first view (A), and magnetic force will be directed east in the third view (C).

Therefore, magnetic force on the current points due north in the first view (A).Hence, the answer is the first view (A).

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Process costing and job-order costing are two instances of costing systems.

April 1 DR Raw Material - Fabric 338,400

DR Raw Material - Polyester filling 470,400

DR Raw Material - Lumber 902,400

DR Raw Material - Glue 32,400

CR Accounts Payable 1,743,600

April 3 DR Work in Process 1,726,400

CR Raw Material - Fabric 315,800

CR Raw Material - Polyester filling 424,400

CR Raw Material - Lumber 986,200

April 3 DR Manufacturing Overhead 34,800

CR Raw Material - Glue 34,800

April 30 Balances in Raw Materials Accounts:

Fabric: 67,500 + 338,400 - 315,800 = $90,100

Polyester filling: 20,200 + 470,400 - 424,400 = $66,200

Lumber: 150,000 + 902,400 - 986,200 = $66,200

Glue: 6,550 + 32,400 - 34,800 = $4,150

The complete question is,

Eclectic Ergonomics Company manufactures designer furniture. Eclectic Ergonomics uses a job order cost system Balances on April 1 from the materials ledger are as follows:

Fabric $67,500

Polyester filling 20, 200

Lumber 150,000

Glue 6,550

The materials purchased during April are summarized from the receiving reports as follows:

Fabric $338,400

Polyester filling 470,400

Lumber 902,400

Glue 32,400

Materials were requisitioned to individual jobs as follows:

Fabric Polyester Filling Lumber Glue Total

Job 81 $127,400 $160,800 $401,200  $689,400

Job 82 97,200 145,200 375,000  617,400

Job 83 91,200 118,400 210,000  419,600

Factory overhead-indirect materials    $34,800 34,800

Total $315,800 $424,400 $986,200 $34,800 $1,761,200

The glue is not a significant cost, so it is treated as indirect materials (factory overhead).

Required:

a. Journalize the April 1 entry to record the purchase of materials in April.*

b. Journalize the April 3 entry to record the requisition of materials in April.*

c. Determine the April 30 balances that would be shown in the materials ledger accounts.

∗Refer to the Chart of Accounts for exact wording of account titles.

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Two examples of costing systems are workflow costing and job-order costing.

Companies will choose a costing system based on the nature of the manufactured goods. Two examples of costing systems are process accounting and job-order costing.

Job-order costing is used because the products being made are bespoke and have unique manufacturing needs. Process costing is used when the consumer products are homogeneous and have equal manufacturing requirements.

Actual direct costs on both labor and materials will often be used because these prices could be related to a particular product. However, since the availability of actual overhead expenses won't be until the conclusion of the term, applied.

Briefing:

April 1 DR Raw Material - Fabric 338,400

DR Raw Material - Polyester filling 470,400

DR Raw Material - Lumber 902,400

DR Raw Material - Glue 32,400

CR Accounts Payable 1,743,600

April 3 DR Work in Process 1,726,400

CR Raw Material - Fabric 315,800

CR Raw Material - Polyester filling 424,400

CR Raw Material - Lumber 986,200

April 3 DR Manufacturing Overhead 34,800

CR Raw Material - Glue 34,800

April 30 Balances in Raw Materials Accounts:

Fabric: 67,500 + 338,400 - 315,800 = $90,100

Polyester filling: 20,200 + 470,400 - 424,400 = $66,200

Lumber: 150,000 + 902,400 - 986,200 = $66,200

Glue: 6,550 + 32,400 - 34,800 = $4,150

The complete question is,

Eclectic Ergonomics Company manufactures designer furniture. Eclectic Ergonomics uses a job order cost system Balances on April 1 from the materials ledger are as follows:

Fabric $67,500

Polyester filling 20, 200

Lumber 150,000

Glue 6,550

The materials purchased during April are summarized from the receiving reports as follows:

Fabric $338,400

Polyester filling 470,400

Lumber 902,400

Glue 32,400

Materials were requisitioned to individual jobs as follows:

Fabric Polyester Filling Lumber Glue Total

Job 81 $127,400 $160,800 $401,200  $689,400

Job 82 97,200 145,200 375,000  617,400

Job 83 91,200 118,400 210,000  419,600

Factory overhead-indirect materials    $34,800 34,800

Total $315,800 $424,400 $986,200 $34,800 $1,761,200

The glue is not a significant cost, so it is treated as indirect materials (factory overhead).

Required:

a. Journalize the April 1 entry to record the purchase of materials in April.*

b. Journalize the April 3 entry to record the requisition of materials in April.*

c. Determine the April 30 balances that would be shown in the materials ledger accounts.

∗Refer to the Chart of Accounts for exact wording of account titles.

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Answer:

Measurement scales are used to categorize and/or quantify variables. This lesson describes the four scales of measurement that are commonly used in statistical analysis: nominal, ordinal, interval, and ratio scales.

Hope I helped let me know if I didn't

The stopper travels approximately 4.5 meters horizontally before hitting the ground.

We can use conservation of energy to solve this problem. At the highest point of the stopper's motion, all of its energy is in the form of potential energy, and at the lowest point (when it hits the ground), all of its energy is in the form of kinetic energy.

The potential energy of the stopper at the highest point is:

Ep = mgh

where m is the mass of the stopper, g is the acceleration due to gravity, and h is the height above the ground. Plugging in the values given in the problem, we get:

Ep = (0.150 kg) * (9.81 m/s²) * (2.3 m) ≈ 3.2 J

At the lowest point, all of the potential energy has been converted to kinetic energy:

Ek = (1/2) * mv²

where v is the speed of the stopper just before it hits the ground. Since the stopper is released from rest, we can use conservation of energy to equate the potential energy at the highest point to the kinetic energy just before hitting the ground:

Ep = Ek

mgh = (1/2) * mv²

Solving for v, we get:

v = √(2gh)

where h is the height from which the stopper was released. Plugging in the values given in the problem, we get:

v = √(2 * 9.81 m/s² * 2.3 m) ≈ 6.6 m/s

Now we can use the time it takes for the stopper to fall to the ground to calculate the horizontal distance it travels. The time is given by:

t = √(2h/g)

Plugging in the values given in the problem, we get:

t = √(2 * 2.3 m / 9.81 m/s²) ≈ 0.68 s

During this time, the stopper travels a horizontal distance given by:

d = vt

Plugging in the values we just calculated, we get:

d = (6.6 m/s) * (0.68 s) ≈ 4.5 m

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Answer:

x = 5 + 8.3

x = 13.3

x = 13

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The radius of curvature (R) of the convex security mirror can be calculated by using the mirror formula is found to be 2.40 m.

We can use the mirror formula, which relates the object distance (p), image distance (q), and focal length (f) of a spherical mirror as follows:

1/f = 1/p + 1/q

For a convex mirror, the focal length is negative, so we can write:

1/f = -1/p + 1/q

We also know that the magnification (M) of an image formed by a spherical mirror is given by:

M = -q/p

where a negative sign indicates that the image is inverted.

Using the given information, we can write:

M = -q/p = 0.26 and p = 3 m

Substituting these values in the magnification equation, we get:

q = M × p = 0.26 × 3 m = 0.78 m

Now, using the mirror formula, we can solve for the focal length as follows:

1/f = -1/p + 1/q = -1/3 m + 1/0.78 m

Simplifying this expression, we get:

1/f = -0.447 + 1.282

1/f = 0.835

Therefore, the focal length of the convex mirror is:

f = 1/0.835 m ≈ 1.20 m

The radius of curvature (R) of the mirror is twice the focal length, so we have:

R = 2f ≈ 2 × 1.20 m ≈ 2.40 m

Therefore, the radius of curvature of the convex security mirror is approximately 2.40 meters.

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The magnitude of its total momentum after the collision is 124.8 kg-m/sec.

The definition of momentum is the quality that a moving body possesses due to its mass and motion, and it is determined by multiplying the body's mass by its speed.

Given that the x-momentum of an object is 8.0 × 103 kilogram meters/second, and its y-momentum is 1.2 × 104-kilogram meters/second the resultant momentum after collision is 124.8 kg-m/sec.

The magnitude of its total momentum after the collision is 124.8 kg-m/sec.

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Answer:

Centripetal force

Explanation:

The force that keeps outside the bicycle is centripetal force.

The following information should be considered:

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The discovery of a new concept or theory that revolutionized the way one thinks about a subject, leading to a new understanding of the topic.

Learning about a new technology or methodology that can improve efficiency, productivity, and accuracy in a given field of study.

The realization that a previously held belief or assumption was incorrect, and that one needs to rethink their approach to the subject area.

Discovering a new research study that challenges the established theories or introduces new methods of conducting research.

The discovery of new tools, techniques, and resources that can enhance one's learning experience and improve their ability to apply what they have learned in real-world situations.

In conclusion, the most interesting discovery made during a module is subjective and depends on the individual's interest and experiences.

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If there are both electric and magnetic fields in the room and their effects on the charged particle cancel, and the electric field points upward, then the direction of the magnetic field is downwards.

The electric force on a charged particle is provided by an electric field, whereas the magnetic force is provided by a magnetic field. The effect of the electric and magnetic fields on the motion of the particle is a function of the relative directions and magnitudes of the two fields.

If the magnetic field is perpendicular to the electric field and the particle's velocity, the magnetic force is at right angles to both the electric force and the velocity, and it does not adjust the particle's speed. If the electric and magnetic forces on a charged particle are equal and opposite, they cancel each other out, resulting in no acceleration of the charged particle. Since the electric field is pointing upward, the magnetic field should be pointing downward.

In conclusion, the direction of the magnetic field is downward if the electric field is pointing upward, according to the given condition.

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Answer:

a stone rock

Explanation:

The metamorphic rock is produced by great heat and pressure and is never melted.  

• The rock, which get changed from one kind to another is known as the metamorphic rock.  

• It is produced from either sedimentary rock or igneous rock, the majority of the Earth's crust is formed of metamorphic rock.  

• The sedimentary and igneous rock turn into metamorphic rock due to intense heat from magma and pressure from tectonic shifting.  

• The rock in spite of becoming extremely hot and under a lot of pressure does not get melt. If it gets melt it is not a metamorphic rock, it is an igneous rock.  

• The metamorphism makes the composition and texture of the mineral to change. The formation of new textures takes place due to the process known as recrystallization.  

Thus, the rock is the metamorphic rock.

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Simplifying the square root: √(705600 kg² - 268800 kg² * cm²) ≈ √436800 kg² ≈ 661.83 kg

To find the position on the x-axis where the net gravitational force on a small mass would be zero, we need to consider the gravitational forces exerted by the two spheres.

Let's denote the mass of the small mass as "m", and we want to find the x-position where the net gravitational force on it is zero.

The gravitational force between the small mass and the 21.0 kg sphere is given by Newton's law of universal gravitation:

F₁ = (G * m * M₁) / r₁²

where G is the gravitational constant, M₁ is the mass of the 21.0 kg sphere, and r₁ is the distance between the small mass and the 21.0 kg sphere.

Similarly, the gravitational force between the small mass and the 13.0 kg sphere is:

F₂ = (G * m * M₂) / r₂²

where M₂ is the mass of the 13.0 kg sphere and r₂ is the distance between the small mass and the 13.0 kg sphere.

To have a net gravitational force of zero, the magnitudes of these two forces should be equal:

F₁ = F₂

Substituting the expressions for the forces:

(G * m * M₁) / r₁² = (G * m * M₂) / r₂²

Canceling out the common factors and rearranging the equation:

(M₁ / r₁²) = (M₂ / r₂²)

To find the position on the x-axis, we need to consider the distance between the small mass and each sphere. Let's denote the x-coordinate of the position we're looking for as x.

Therefore, the distances r₁ and r₂ can be calculated as follows:

r₁ = x

r₂ = |x - 20 cm|

Now, we can rewrite the equation:

(M₁ / x²) = (M₂ / (x - 20 cm)²

Substituting the known values:

(21.0 kg / x²) = (13.0 kg / (x - 20 cm)²

Now, we can solve this equation to find the position on the x-axis where the net gravitational force is zero.

By cross-multiplying and simplifying, the equation becomes:

13.0 kg * x² = 21.0 kg * (x - 20 cm)²

Expanding and rearranging the equation:

13.0 kg * x² = 21.0 kg * (x² - 40 cm * x + 400 cm²)

Simplifying further:

13.0 kg * x² = 21.0 kg * x² - 840 kg * x + 8400 kg * cm²

Now we have a quadratic equation. We can bring all terms to one side and solve for x using the quadratic formula:

8.0 kg * x² - 840 kg * x + 8400 kg * cm² = 0

Using the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a)

Here, a = 8.0 kg, b = -840 kg, and c = 8400 kg * cm².

Calculating the values under the square root: √(b² - 4ac) ≈ √((-840 kg)² - 4 * 8.0 kg * 8400 kg * cm²)

Simplifying the square root: √(705600 kg² - 268800 kg² * cm²) ≈ √436800 kg² ≈ 661.83 kg

Using the quadratic formula:

x = (-(-840 kg) ± 661

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Kayla stands on her trampoline, it sags by 0.23 m. Now she starts bouncing, it takes approximately 1.89 seconds for Kayla to pass the same point on the trampoline's surface after bouncing up from it.

Let's assume that Kayla's motion can be modeled by simple harmonic motion. In this case, the time elapsed between successive passages through the same point is given by

T = 2π√(m/k)

Where m is the mass of the object and k is the spring constant of the trampoline.

Assuming Kayla has a mass of 50 kg, we can estimate the spring constant of the trampoline using Hooke's Law

F = -kx

Where F is the force applied by the trampoline, x is the displacement from equilibrium, and k is the spring constant. Since the trampoline sags by 0.23 m when Kayla stands on it, the force applied by the trampoline can be estimated as

F = mg + kx = (50 kg)(9.81 m/\(s^{2}\)) + k(0.23 m)

Where g is the acceleration due to gravity. Solving for k, we get

k = (mg + F)/x = [(50 kg)(9.81 m/\(s^{2}\)) + (50 N)]/0.23 m ≈ 2.61 × \(10^{3}\) N/m

Substituting this value into the equation for the period of simple harmonic motion, we get

T = 2π√(m/k) = 2π√(50 kg)/(2.61 × \(10^{3}\) N/m) ≈ 1.89 s

Therefore, it takes approximately 1.89 seconds for Kayla to pass the same point on the trampoline's surface after bouncing up from it.

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The spring constant of the spring is 19.6 N/m.

The correct answer is option D.

The spring constant of the spring is calculated by applying the following equation as shown below.

Mathematically, the formula of Hooke's law is given as;

F = kx

where;

k = F / x

the extension of the spring when the 250 g mass was hung on it is calculated as;

x = 30 cm - 25 cm

x = 5 cm = 0.05 m

The spring constant of the spring is calculated as;

k = ( mg ) / x

where;

k = ( 0.1 x 9.8 ) / ( 0.05 )

k = 19.6 N/m

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As a result, the arrows in the free-body diagram that indicate the forces operating on the object will be balanced, equal in magnitude, and pointing in the opposite direction.

Arrows used in free body diagrams to depict the various forces acting on an item. Force is a vector, as was previously stated. As a result, every force on a free body diagram has a value and a direction.

Newton's rule states that if the net force acting on an object is not zero, then the object's acceleration will also not be zero. Therefore, we will analyse the total force using the free body diagram.

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The net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.

The net force direction can be determined by finding the net vector sum of the forces acting on it.

Since the first person pulled the cart to the right with a force of 10n,

Assuming the right direction as positive, this force can be represented as a vector ⇒(+)10n

Similarly, as the second person pulls the cart to the left, the force can be represented as a vector ⇒ (-)3n,

∴ Net force = Net vector sum of the forces

                   =(+10n) + (-3n)

⇒Net force = +7n

Thus, the net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.

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Answer: 7n

Explanation:

I agree with the application of such offenses where criminal responsibility is imposed on strict liability offenses because it is needed to protect public welfare, promote safety, and deter potential harm.

Strict liability offenses are those in which liability is imposed without requiring proof of intent or guilty mind. These offenses focus on the act itself rather than the mental state of the offender. The rationale behind strict liability offenses is often rooted in the need to protect public welfare, promote safety, and deter potential harm.

An argument in favor of strict liability offenses is that they ensure accountability for certain actions that pose a significant risk to society, even in the absence of intent or mens rea. By placing the burden on individuals to adhere to certain standards or regulations, strict liability offenses can help prevent accidents, protect public health, and maintain order.

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Answer:0.060

Explanation:

The mass of the tennis ball is equal to 0.23 Kg.

According to the law of conservation of linear momentum, the sum of the momentum of the bodies which are collided with each other must be equal before and after the collision.

m₁ .u₁ + m₂.u₂ = m₁ .v₁ + m₂.v₂

where m₁ and m₂ is the masses, u₁ and u₂ are initial speed while v₁ & v₂ is their final speed of the collieded objects.

Linear momentum can be defined as the product of the mass times the velocity of that object.

Given, the initial velocity of the baseball is u₁ = 15 m/s

The initial velocity of the tennis ball u₂ = 22 m/s.

The mass of baseball, m₁ =0.15 Kg

From the law of conservation of momentum, find the  mass of the tennis ball:

m₁ u₁ + m₂ u₂ = m₁.v₁ + m₂.v₂

0.15 × 15 + m ×22 = 0.15 × 1.2 + m × 13

2.25 + 22 m = 0.18 + 13 m

9 m = 2.25

m = 0.23 Kg

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The rotational kinetic energy of the airplane propeller is approximately 1.98 x 10⁶Joules

The rotational kinetic energy of the airplane propeller can be determined using the formula:

Rotational Kinetic Energy = 1/2 * Moment of Inertia * Angular Velocity²

To calculate the moment of inertia, we need to know the shape and mass distribution of the propeller. However, since the propeller is modeled as a slender rod, we can use the formula for the moment of inertia of a rod about its center:

Moment of Inertia = (1/12) * Mass * Length²

Substituting the given values, we get:

Moment of Inertia = (1/12) * 117 kg * (1.99 m)² = 47.39 kg*m²

Next, we need to convert the angular velocity from rpm to rad/s: Angular Velocity = (2600 rpm) * (2*pi/60) = 273.15 rad/s

Finally, substituting these values into the formula for rotational kinetic energy, we get:

Rotational Kinetic Energy = 1/2 * 47.39 kg*m²* (273.15 rad/s)² = 1.98 x 10⁶Joules

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