top I think he or she is right
The length of the AB in the given right triangle is √3/6
Given that, a right triangle with the base measure 6 units and an acute angle 30°,
We need to find the measure of side AB,
So, we will use the concept of trigonometric ratios,
Tan 30° = AB / AC
Tan 30° = AB / 6
1 / √3 = AB / 6
AB = √3/6
Hence the length of the AB in the given right triangle is √3/6
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Points A and B are on opposite sides of a lake. Another point, C. is 94.4 meters from Angle A. The measure of Angle A is 72° and the measure of Angle C is 30°. Find the distance between A and B.
To find the distance between points A and B, we can use trigonometry and the given information.
Let's label the distance between A and B as "d". We know that point C is 94.4 meters away from point A. From angle A, we have the measure of 72°, and from angle C, we have the measure of 30°.
Using trigonometry, we can use the tangent function to find the value of "d".
tan(72°) = d / 94.4
To solve for "d", we can rearrange the equation:
d = tan(72°) * 94.4
Using a calculator, we can evaluate the expression:
d ≈ 4.345 * 94.4
d ≈ 408.932
Therefore, the distance between points A and B is approximately 408.932 meters.
there are 107 girls at hockey camp. The coach is reserving rinks for games. There can only be 12 girls on each rink. How many rinks should the coach reserve?
During the championship football game, quaterback A threw for 220 yards. Quaterback B threw 15% mor yards than quarterback A. What is the total number of yards that both quarterbacks threw in the championship game
The solution is, the total number of yards that both quarterbacks threw in the championship game is 473 yards.
What is addition?Addition is a way of combining things and counting them together as one large group. ... Addition in math is a process of combining two or more numbers.
here, we have,
given that,
quaterback A threw for 220 yards.
Quaterback B threw 15% mor yards than quarterback A.
i.e. B threw = 220 + 220*15%
= 220 + 33
=253
so, we get,
the total number of yards that both quarterbacks threw in the championship game = 220 + 253
=473 yrd
Hence, The solution is, the total number of yards that both quarterbacks threw in the championship game is 473 yards.
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the distance between 1 - 10 1/4
The distance between 1 - 10 1/4
____________________
1 - 10 1/4 = -9 1/4
_________________________
Answer
-9 1/4
9 1/4 (in absolute value)
3 Jack walk from Santa Clara to Polo Allo. Il took I hour 25 min to walk from Santa Clot to Los Altos. Than it took 25 minute of wal from los altos to Palo buto. He arrived in Palo alto at 2:45 P.M. of what time die Santa Clara ? he leave Santa clara
The time Jack left Santa Clara is 1 : 55 pm
What is word problem?A word problem in math is a math question written as one sentence or more. These statements are interpreted into mathematical equation or expression.
The time for Jack to walk to lose Altos is 25 min and he uses another 25mins to work to Palo alto.
Therefore, the total time he spent is
25mins + 25 mins = 50 mins
He arrived Palo at 2 :45 pm, therefore the time he left Santa Clare will be ;
2:45 pm = 14 :45
= 14:45 - 50mins
= 13:55
= 1 : 55pm
Therefore he left at 1:55 pm
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Given: m∠9 = 50° and m∠5 = 42°. Find the m∠14. Just type the number of the answer in the answer box.
Answer:
138°Step-by-step explanation:
∡5 = 42°
find: ∡ 14
solution:
since ∡5 = ∡13 = 42°
∡14 = 180 - ∡13
= 180 - 42
= 138°
Which of these describes an angle?
Extends in both directions with no end
The amount of turn between two straight lines that have a common endpoint, or vertex
A part of a line that connects two endpoints
Has a start point but no endpoint
find the missing area.
about 1 2 of the population has red hair if 800 people were ramdomly sampled about how many of them would you expect to be read heads
Answer:
10-12
Step-by-step explanation:
1.5% of 800 is 12
MAX POINTS PLEASE HELP Will make Brainliest
What is the period and frequency of the function graphed and how would the equation be written as a function
\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)
The required equation is :
\(\qquad \rm \dashrightarrow \:y =a \cos(bx) + k\)
Now, let's find the required values :
period (p) = 6
[distance between any successive Crest or trough]
a = - 4 (flipped)
b = 2π/p = 2π/6 = π/3
k = -2
Distance of starting position from origin = k
Now, plug in the values ~
\(\qquad \rm \dashrightarrow \: - 4 \cos( \frac{\pi}{3} x) - 2\)
Find the length if the two missing sides in the parallelogram below
The value of the missing sides in the parallelogram are x = 3 and y = 6
Interpreting the parallelogram givenIn other to solve the question posted, we use the law which relates to the sides of a parallelogram which establishes that opposite sides of a parallelogram are of equal length.
This means that the side opposite length of 3 will also be 3 and vice-versa
side x = 3
side y = 6
Therefore, the missing sides of the parallelogram are 3 and 6 for sides x and y respectively.
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for the right triangle below, find the measures of the angle.
Given the right-angled traingle as shown in the question
Let the unknown angle be x
\(\cos x=\frac{13}{16}\)\(\begin{gathered} \cos x=0.8125 \\ x=\cos ^{-1}(0.8125) \\ x=35.66^0 \end{gathered}\)Hence, the measured angle is 35.66°
What is the difference (2 x minus 3) minus (x minus 1)?
Answer:
2x - 3 - (x-1)
2x - 3 -x +1
x-2
Answer:
x-2 or B. if you're on edgState the segment that represents the image, based on the information given.
The clockwise rotation of ΔAPG about 90 degree gives ΔCPA.
What is Rotation?Each point in a figure is transformed into a rotation by rotating it a specific amount of degrees around another point.
Given:
We have ΔAPG.
Now, we have to rotate about 90 clockwise rotation.
Then, ΔAPG will overlap on ΔCPA
Hence, the clockwise rotation of ΔAPG about 90 degree gives ΔCPA.
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The zookeeper mentioned that the scale used to weigh some of the larger animals can be off by 12 pounds. The scale read 438.2 lbs. for one of the larger animals. If the animal’s actual weight is x pounds, write an expression to represent the number of pounds the weight on the scale is from the actual weight of the animal. Then explain the range of values in which the actual weight might be.
The actual weight of the animal is between 450.2 and 426.2 pounds
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Inequality can be used to show that two variables or numbers are not equal to each other.
The weight of the larger animals can be off by 12 pounds. Let x represent the actual weight of the animal. If the scale reads 438.2 lbs, hence:
|x - 438.2| = 12
x - 438.2 = 12; or -(x - 438.2) = 12
x = 450.2; or x = 426.2
The actual weight of the animal is between 450.2 and 426.2 pounds
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The radius of a circle is 8 miles. What is the circle's area?
Answer:
\(\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}\)
Given - radius of circle = 8 milesTo calculate - area of circleThis can be easily calculated by substituting the value of radius in the formula of area ~
\(Area \: = \pi \: r {}^{2} \\ \\ \implies \: \frac{22}{7} \times 8 \times 8 \\ \\ \implies \: \frac{1408}{7} \\ \\ \implies \: 201.14 \: miles {}^{2} \)
hope helpful ~
\(\huge\color{pink}\boxed{\colorbox{Black}{♔︎Answer♔︎}}\)
200.96 miles²
Step-by-step explanation:
\( \textsf{\underline{\large{To find :-}}}\)
The area of circle
\( \textsf{\underline{\large{Given :-}}}\)
radius of circle (r) = 8 miles
\( \textsf{\underline{\underline{\huge{Solution :-}}}}\)
\( \sf \blue {Area \: of \: circle = \pi {r}^{2} }\)
now we will substitute the value of r
\( \sf \implies Area = \pi {8}^{2} \\ \\ \sf \implies Area = \pi \times 8 \times 8\)
\( \sf \pi = \frac{22}{7} \: or \: 3.14 \\ \sf here \: we \: will \: use \: \pi = 3.14\)
\( \sf \implies Area = 3.14 \times 8 \times 8 \\ \\ \sf \implies { \green{ Area = 200.96 \: {miles}^{2} }}\)
A bank manager wants to encourage new customers to open accounts with principals of at least $3500. He decides to make a poster advertising a simple interest rate of 3%. What must the principal be if the bank manager also wants to advertise that one can earn $10 the first month?
The principal if the bank manager also wants to advertise that one can earn $10 the first month is $4000.
How to calculate the principal?From the information, the simple interest is $10 and the rate is illustrated as 3%.
The formula for the simple interest in a month is illustrated as:
S = (p × r × t/12 / 100)
r = rate
t = time
S = interest
Place the values in the formula:
10 = p × 3 × 1 / 100 × 12
10 = 3p/1200
Cross multiply
3p = 12000
Divide
p = 12000/3
p = 4000
The principal is $4000.
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The radius of the base of a cylinder is expanding at a constant rate of 3 mm/min. If the height of
the cylinder is a constant 20 mm, find the rate at which the VOLUME of the cylinder is changing at the
moment when the radius of the base of the cylinder is 10 mm. Also find the rate at which the SURFACE
AREA of the cylinder is changing at this same moment.
(V = r²h, SA=2лrh+2rr²)
I’m getting 1800pi mm^3/min for volume and 360pi mm^2/min for surface area but I’m not sure if it’s correct
The rate at which the volume of the cylinder is changing is 600 mm^3/min, and the rate at which the surface area is changing is 240π mm^2/min.
To find the rate at which the volume and surface area of the cylinder are changing, we can use the given formulas for volume and surface area and differentiate them with respect to time. Let's calculate the rates at the moment when the radius of the base is 10 mm.
Given:
Radius rate of change: dr/dt = 3 mm/min
Height: h = 20 mm
Radius: r = 10 mm
Volume of the cylinder (V) = \(r^2h\)
Differentiating with respect to time (t), we have:
dV/dt = 2rh(dr/dt) + \(r^2\)(dh/dt)
Since the height of the cylinder is constant, dh/dt = 0.
Substituting the given values:
dV/dt = 2(10)(20)(3) + (10^2)(0)
dV/dt = 600 + 0
dV/dt = 600 mm^3/min
Therefore, the rate at which the volume of the cylinder is changing at the given moment is 600 mm^3/min.
Surface area of the cylinder (SA) = 2πrh + 2π\(r^2\)
Differentiating with respect to time (t), we have:
dSA/dt = 2πr(dh/dt) + 2πh(dr/dt) + 4πr(dr/dt)
Again, since the height of the cylinder is constant, dh/dt = 0.
Substituting the given values:
dSA/dt = 2π(10)(0) + 2π(20)(3) + 4π(10)(3)
dSA/dt = 0 + 120π + 120π
dSA/dt = 240π mm^2/min
Therefore, the rate at which the surface area of the cylinder is changing at the given moment is 240π mm^2/min.
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if i compare 0.10__0.01 what would the answer be?
The answer will be 0. 10 > 0. 01 . Option B
How to compare the valuesGiven the values as;
0.100.01Turn the values into proper fractions
a. 0. 10 = 10/ 100
Reduce to simpler terms
= 10/ 100
= 1/ 10
b. 0. 01 = 1/ 100
a = 1/ 100
b = 1/ 100
This means that both decimals are not of equal proportion and thus a is greater than (>) b
Thus, the answer will be 0. 10 > 0. 01 . Option B
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plssss can someone help
Answer:
Step-by-step explanation:
Please solve this
∫ (log(1 + x ^ 2))/((x + 1) ^ 2) dx
The final result of the integral is:
∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,
where Li(x) is the logarithmic integral function and C is the constant of integration.
We have,
To solve the integral ∫ (log(1 + x²) / (x + 1)²) dx, we can use the method of substitution.
Let's substitute u = x + 1, which implies du = dx. Making this substitution, the integral becomes:
∫ (log(1 + (u-1)²) / u²) du.
Expanding the numerator, we have:
∫ (log(1 + u² - 2u + 1) / u²) du
= ∫ (log(u² - 2u + 2) / u²) du.
Now, let's split the logarithm using the properties of logarithms:
∫ (log(u² - 2u + 2) - log(u²)) / u² du
= ∫ (log(u² - 2u + 2) / u²) du - ∫ (log(u²) / u²) du.
We can simplify the second integral:
∫ (log(u²) / u²) du = ∫ (2 log(u) / u²) du.
Using the power rule for integration, we can integrate both terms:
∫ (log(u² - 2u + 2) / u²) du = log(u² - 2u + 2) / u - 2 ∫ (log(u) / u³) du.
Now, let's focus on the second integral:
∫ (log(u) / u³) du.
This integral does not have a simple closed-form solution in terms of elementary functions.
It can be expressed in terms of a special function called the logarithmic integral, denoted as Li(x).
Therefore,
The final result of the integral is:
∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,
where Li(x) is the logarithmic integral function and C is the constant of integration.
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What percentage of 3 is 4?
Answer:
133.33% of 3 is 4.
Step-by-step explanation:
x% of 3 = 4
x/100 × 3 = 4
3x/100 = 4
3x = 400 [cross multiplication]
x = 400/3
x = 133.33%
_______
Hope it helps ⚜
x percentage of 3 is 4.
to find:the unknown ( x ).
solution:let the unknown be x.
\( \frac{100\%}{x\%} = \frac{3}{4} \)
\( \frac{x\%}{100\%} = \frac{4}{3} (reciprocal)\)
\(x = 133.33\%\)
hence, 4 is 133.33% of 3.
Solve the proportions 18/27=60/m
ANSWER
m = 90
EXPLANATION
To find m first we have to multiply both sides by m:
\(\begin{gathered} \frac{18}{27}m=\frac{60}{m}m \\ \frac{18}{27}m=60 \end{gathered}\)Then multiply both sides by 27:
\(\begin{gathered} \frac{18m}{27}\cdot27=60\cdot27 \\ 18m=1620 \end{gathered}\)And finally divide both sides by 18:
\(\begin{gathered} \frac{18m}{18}=\frac{1620}{18} \\ m=90 \end{gathered}\)Como se hace este tipo de perímetro para álgebra ?
The perimeter of this geometric figure is equal to 84x² + 2y units.
How to calculate the perimeter of a rectangle?Mathematically, the perimeter of a rectangle can be calculated by using this mathematical expression;
P = 2(L + W) or P = 2L + 2W
Where:
P represents the perimeter of a rectangle.L represents the length of a rectangle.W represents the width of a rectangle.In this scenario, we would determine the perimeter of this geometric figure by adding all of the side lengths as follows;
Perimeter of this figure = 31x² + y + 14x² - y + 23x² + 5y + 16x² - 3y
Perimeter of this figure = 84x² + 2y units.
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Complete Question:
How to do this type of perimeter for algebra?
Convert 2.38 km to dm.
Answer:
Step-by-step explanation:
2.38 km x 10^4 = 23,800 decimeters
4 friends buy 16 pizzas. Each pizza is cut into
12 pieces. Each person eats the same number
of pieces.
How many pieces does each person eat?
Merge onto Highway 40 and drive 3/5
mile. Stop and pay the toll. Then
continue on Highway 40 for twice this.
distance. How much longer will you be
on Highway 40 after you pay the foll?
Distance traveled after toll payment is 1.2 miles on highway 40.
What is Distance ?The distance may be calculated using a curved route. Displacement measurements can only be made along straight lines. Distance is path-dependent, meaning it varies depending on the direction followed. Displacement simply depends on the body's beginning and ending positions; it is independent of the route.
Distance is the sum of an object's movements, regardless of direction. Distance may be defined as the amount of space an item has covered, regardless of its beginning or finishing position.
The size or extent of the displacement between two points is referred to as distance. Keep in mind that the distance between two points and the distance traveled between them are not the same. The entire length of the journey taken between two points is known as the distance traveled. Travel distance is not a vector.
Distance traveled before toll payment =3/5 miles on highway 40
Distance traveled after toll payment =2*3/5 = 6/5 =
1.2 miles on highway 40.
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pls answer this, yada yada yada.
last option 41/3 ir 13/3
How do you determine the vertex from the vertex from of a quadratic equation
Answer:
it it the highest or lowest point of a parabola
One thousand dollars is deposited into an ordinary annuity after each 6 month period for 2 years. The account pays 4 percent interest compounded semiannually.what is the future value of the account in 2 years ??
Answer:
$4121.61
Step-by-step explanation:
Use the formula for the balance of an ordinary annuity.
A = P((1 +r/n)^(nt) -1)/(r/n)
A = $1000((1 +.04/2)^(2·2) -1)/(.04/2) ≈ $4121.61
The future value of the account is $4121.61.