what is the impedance seen by the source? express your answer in ohms to three significant figures. enter your answer using angle notation. express argument in degrees.
Answers
The impedance seen by the source is 19.4 ohms with an argument of -33.7 degrees.
For the given circuit, the equivalent impedance can be found as follows: For Z1 and Z2, we know that they are both capacitive, which implies that they have an imaginary component of -j. Their resistive values are given as follows: Z1 = 3 ohms and Z2 = 5 ohms. To get their impedances, we use the formula, Z = R - jX, where R is the real component, X is the imaginary component, and j is the imaginary unit.
Therefore: \(Z1 = 3 - j(1/2)Z2 = 5 - j(1/2)\)
Next, we find the equivalent impedance between Z1 and Z2, which is done in parallel.
Therefore:\(1/Zeq = 1/Z1 + 1/Z2\)
\(⇒ 1/Zeq = 1/[(3 - j(1/2)] + 1/[(5 - j(1/2)]\)
\(⇒ 1/Zeq = [(5-j(1/2)) + (3-j(1/2))]/[(3-j(1/2)) x (5-j(1/2))]\)
\(⇒ 1/Zeq = (8-j)/(15-(1/4))⇒ 1/Zeq = [8-j]/[59/4]\)
\(⇒ Zeq = [8-j] x [4/59]⇒ Zeq = [32/59] - j[4/59]\)
Finally, we calculate the impedance seen by the source. This is equal to the series combination of the equivalent impedance and Z3.
Therefore: \(Z = Zeq + Z3⇒ Z = [32/59] - j[4/59] + j5⇒ Z = [32/59] + j[246/59]\)
From this, we can determine the magnitude and angle of the impedance.
The magnitude is given by: \(|Z| = sqrt((32/59)² + (246/59)²)⇒ |Z| = 19.4 ohms\) (rounded to 3 significant figures)
The angle is given by:
\(arg(Z) = tan⁽⁻¹⁾ (Im(Z)/Re(Z))⇒ arg(Z) = tan⁽⁻¹⁾ (246/32)⇒ arg(Z) = 77.24 degrees\)
Since the angle between the imaginary component and the real component is in the second quadrant, we know that the argument is negative. Therefore, the impedance seen by the source is 19.4 ohms with an argument of -33.7 degrees (rounded to 1 decimal place).
Therefore, the impedance seen by the source is 19.4 ohms with an argument of -33.7 degrees.
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Related Questions
In the above situation, what is the net torque on wire 2 due to wire 1?
a. Up b. Down
c. Into the screen d. Out of the screen e. Zero
Answers
In the above situation the net torque on wire 2 due to wire 1 is Zero.
Which way is the force acting on the wire?Fleming's left-hand rule identifies the force's direction on a current-carrying wire when it is placed in a magnetic field. It always runs counter to how the magnetic field and electric current are moving.
Directional torque: what is it?Torque is a vector quantity by definition. The direction is determined as part of the torque computation. The direction is parallel to both the force and the radius from the axis. It is customary to choose it along the rotational axis in the right-hand rule direction.
When rotating clockwise, is torque negative?a force that is applied that results in a positive counterclockwise torque A negative torque rotates an object in a clockwise direction.
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What is the frequency in Hz of the fundamental mode of a 1.5 m long string with linear mass density of 0.001 kg/m and a tension of 0.5 N.
Answers
The frequency in Hz of the fundamental mode of a 1.5 m long string with linear mass density of 0.001 kg/m and a tension of 0.5 N is 33.3 Hz. Here is the main answer along with an explanation:Main Answer:The frequency in Hz of the fundamental mode of a 1.5 m length of the string with linear mass density of 0.001 kg/m and a tension of 0.5 N is 33.3 Hz.
Explanation:Frequency is the number of cycles per second or vibrations per second. The linear mass density of a string is the mass of the string per unit length. The tension in a string is the force per unit area.The formula to calculate the frequency of the fundamental mode of a string is as follows:f = (1/2L) * √(T/μ)Where f is the frequency, L is the length of the string, T is the tension in the string, and μ is the linear mass density of the string.Substituting the given values in the formula,f = (1/2 × 1.5) * √(0.5/0.001)f = 0.75 * √500f = 0.75 * 22.36f = 16.77 Hz
However, the above value of frequency is the frequency of the first overtone or second harmonic. The fundamental mode corresponds to the first harmonic, which has half the wavelength and twice the frequency of the second harmonic. Therefore, the frequency of the fundamental mode of the string is:f1 = f/2 = 16.77/2f1 = 8.38 HzRounding off to one decimal place,f1 = 8.4 HzThe frequency in Hz of the fundamental mode of a 1.5 m long string with linear mass density of 0.001 kg/m and a tension of 0.5 N is 8.4 Hz.
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Billy is pulling his sister Joslyn in the sled. Based on your knowledge of F=ma, describe what would
happen to the motion of the sled if Joslyn's friend Lisa also wanted to ride.
Answers
Answer:
the motion of the sled decrease
Explanation:
the mass increase
The acceleration of the sled will is inversely proportional to the mass on it. Therefore, the motion of the sled would slow if Joslyn's friend Lisa also wanted to ride.
What is acceleration?Acceleration in mechanics can be described as the rate of change of velocity of an object with respect to time. The acceleration of an object is a vector quantities with magnitude and direction.
The S.I. unit for acceleration can be represented as m/s² the net balance of all external forces acting is equal to the magnitude of the net resulting force.
The force (F) acting on an object is equal to the product of the mass (m) of the object and acceleration (a) of an object.
F = ma
And, a = F/m
As shown in the above equation, the mass of the object is inversely proportional to the acceleration of the object, therefore, the acceleration of the sled decrease as the mass on it increases.
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During construction, a crane lifts a 2,000-newton weight to the top of a 50-meter-tall building. How much power must the crane have to perform this task in 5 seconds? Use commas where appropriate and round to the nearest tenth.
watts:
kilowatts:
horsepower:
Answers
Answer:
Work is defined as force thru a distance: W = F * S
Power is defined as Work per unit time P = W / t
So we an write: P = F * S / t = 2000 N * 50 m / 5 s = 20,000 N-m/s
Since a Joule/sec is equivalent to a Watt
The power required is 20,000 Watts or 20 Kw
Also, you can convert to Hp since 1 Hp = 746 Watts
Brady connected the lose wire to the battery and created an electromagnet as shown below. He picked up 45 thumb tacks with his electromagnet, though his goal was to pick up 50 thumb tacks. What could Brady do to increase the strength of his electromagnet and pick up more thumbtacks?
Answers
Answer:
He will have to use two batteries instead of just one.
Explanation:
The way Brady could increase the strength of his electromagnet and pick up more thumbtacks is for him to increase the current. He can achieve this either by adding a second battery or by adding more coils of wire.
This is because using 2 batteries will make the amount of current in the coils to increase and this will in turn produce a higher electromagnetic field in the nail.
32. If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t2. How long does it take for the velocity to reach 24 m/s? (a) 2 seconds (b) 4 seconds (c) 5 seconds (d) 11 seconds (e) 12 seconds
Answers
If a ball is given a push so that it has an initial velocity of 2 m/s down a certain inclined plane, then the distance it has rolled after t seconds is s = 2t + t². Then it takes 11 seconds for the velocity to reach 24 m/s. The correct option is D.
To find the time it takes for the velocity of the ball to reach 24 m/s, we need to solve for the time when the velocity function equals 24 m/s.
The velocity function is the derivative of the distance function, so we'll first find the derivative of the distance function s = 2t + t² with respect to time t:
ds/dt = d/dt(2t + t²)
ds/dt = 2 + 2t
Now we can set the velocity function equal to 24 m/s and solve for t:
2 + 2t = 24
Subtracting 2 from both sides:
2t = 22
Dividing both sides by 2:
t = 11
Therefore, it takes 11 seconds for the velocity to reach 24 m/s.
The correct answer is (d) 11 seconds.
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nd 1 follo If the length, breadth and thickness of a wooden block with density 0.8 g/cm³ are 20 cm, 15 cm and 10 cm respectively and it is partially immersed in water with density 1 g/cm³, answer the following questions. Find the volume of wood. Calculate the mass of the block. 1) ii) How much water is displaced? Find the thickness of the block above the surface of water. iv)
Answers
The mass of liquid that the wooden block will displace is 2400 g. and the thickness of the block is 0.8 cm
According to the floatation principle, the buoyant force acting on an object or body as it moves through a liquid is equal to the weight of the thing. The volume of the object submerged in the fluid is equal to the displaced volume of the fluid.
By principle of floation
Mass of wood=mass of liquid displaced.
Density of block=0.8 g/cm3
Volume of block= 20 x 15 x10=3000
mass of liquid displaced= density x volume
=0.8 x 3000
=2400 g
thickness of block= 2400/3000
=0.8 cm
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3. A model rocket is launched straight upward at 58.8 m/s.
a. How long does it take for the rocket to reach its peak height?
Answers
Let us assume that rocket only runs in initial energy and not using its own to flying.
Also , let upward direction is +ve and downward direction is -ve .
Initial velocity , u = 58.8 m/s .
Acceleration due to gravity , \(g=-9.8\ m/s^2\) .
Final velocity , v - = 0 m/s .
We know , by equation of motion .
\(v^2-u^2=2gh\\\\2gh_{max}=0^2-58.8^2\\\\h_{max}=\dfrac{0^2-58.8^2}{-2\times 9.8}\\\\h_{max}= 176.4\ m\)
Hence, this is the required solution .
PLZ HELP TIMED TEST
Which would be most useful for overcoming the disadvantage of using ores?
using public transportation
recycling aluminum products
buying paper instead of plastic
minimizing electricity usage
Answers
Answer:
recycling aluminum products
Explanation:
I I took this test hope this out and on the test I got this correct
What Determines the amount of TE of an object
Answers
Answer:
To find the volume of a rectangular object, measure the length, width and height. Multiply the length times the width and multiply the result by the height. The result is the volume. Give the result in cubic units, such as cubic centimeters.
Explanation:
Answer:
Kinetic energy is the energy possessed by an object due to its motion. If an object is moving, then it has kinetic energy. The amount of kinetic energy depends on mass and speed.
Explanation:
What part of the Milky Way allows for determination of its rotational direction? A. Celestial body B. Galactic body C. Galactic disk D. Two long tails
Answers
Answer: C. Galactic disk
Explanation:
The part of the Milky Way which allows the determination of it rotational direction is known as the Galactic disk. This disc are shaped because they contain gases which are rich and dynamically young. It is also a part of a group of a galaxies disc is a component of disc galaxies, known as spiral galaxies and lenticular galaxies.
Answer:
Galactic disk
Explanation:
Galactic disc's are composed mostly of the galaxy's stars and a gaseous component mostly composed of cool gas and dust. The stellar population of galactic discs tend to exhibit very little random motion with most of its stars undergoing nearly circular orbits about the galactic center. This circular orbit maintains the galaxy's rotation momentum.
This fossil snake and this living rat both have a structure in their skull called the quadrate bone. What best explains why both species have a quadrate bone?
Answers
The snake and rat both share the same ancestor population that had a quadrate bone, which was inherited from an ancestor population.
What is a homo-logous structure?A homo-logous structure is a trait that may or not have the same function but has a common evolutionary origin.
A homo-logous structure can be used to trace the evolutionary relationships between species.
Conversely, an analogous structure has the same function but it does not reflect an evolutionary origin.
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4. How has the development of integrated photonics helped increase network
speeds?
Answers
The development of integrated photonics has been a key factor in increasing network speeds by enabling the transmission of large amounts of data over optical fibers.
What are integrated photonics?photonics refers to the technology of creating optical devices and systems using semiconductor fabrication techniques, similar to those used in the production of electronic integrated circuits.
One of the most significant contributions of integrated photonics to increasing network speeds is the creation of photonic integrated circuits (PICs). PICs are made up of multiple optical components, such as lasers, modulators, and detectors, integrated onto a single chip. This integration enables faster and more efficient communication between the components, reducing signal loss and improving overall performance.
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pls help i will give u brianliest!
Answers
Answer:
it's c
Explanation:
is the one that looks like an example of potassium
I took the test!
Suppose you are changing a car tire and loosening a lug nut. You weigh 800N and stand on the end of a 2 m long wrench. How much torque do you exert on the lug nut?
a. 1600 J
b. 1600 N-m
c. 800 N-m
d. 2 N-m
Answers
The torque exerted by the person on log nut is 1600 N-m, if person's weight is 800 N, and the length of the wrench is 2 meter.
Torque in rotational motion is equivalent to the what force is in linear motion. As force cause a push or pull in linear motion, similarly torque causes a twist in clockwise or anticlockwise direction. It causes the change in the rotational motion of a body. Its SI unit is N-m. & It is formulates as follows:
Torque = Force × lever arm × sinθ
τ = Frsinθ
Where θ is the angle between the force and the lever arm.
Torque = 800 × 2 = 1600 N-m
Hence option B is correct.
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A block of mass 1kg is placed on an inclined plane at an angle of 30° to the horizontal. Calculate the frictional force, normal reaction, the coefficient of the static friction
Answers
Question:
A block of mass 1kg is placed on an inclined plane at an angle of 30° to the horizontal. Calculate the frictional force, normal reaction, the coefficient of the static friction
Answer:
Break the mg force into components in the plane of the inclined plank. Now force acting parallel is mgsin37°. Perpendicular force is mgcos37° which is equal to normal force.
Now calculate max value of friction force which is 0.8*mg cos37°. Since its greater than pulling force mgsin37°, the body will be at rest and acceleration is zero.
Force applied by surface is vector sum of normal force and friction force acting.
am radio station broadcasts at a frequency of 887 khz using a 520 kw antenna. how many photons per second does this antenna emit?
Answers
The number of photons emitted by the antenna was 78.47x 10^-31 photons per second
define photon?
A photon is an elementary particle that is a quantum of the electromagnetic field, including electromagnetic radiation like as light and radio waves, and the electromagnetic force's force carrier. Because photons have no mass, they always travel at the speed of light in vacuum, which is 299792458 m/s (or around 186,282 mi/s). The photon belongs to the boson class.
n=P/E
E=hf
=6.626x10^-34x10^6
=6.626x10^-28
n=520x10^3/6.626x10^-28
=78.47x10^31 photons per second
therefore the number of photons emitted by the antenna was =78.47x10^31
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An object that looks white when exposed to sunlight reflects all colors of light. What
does a white object look like when it is exposed to blue light?
Answers
What is the mass of a gold bar that has a density of 19.3 g/mL3 and a volume of 100 cm3?
Answers
Answer:
density=mass/volume
density=19.3
mass=x
volume=100
we are looking for mass so we have to change the subject formula to m=dv
which means mass is equals to density multiplied by volume
m= 19.3 x 100
which is 1930.
How deep is the floor of the ocean if a sonar sound takes 7 seconds to return back to the ship?
Answers
Evaluate cos(30°).
ОА. 1.00
ов. 0.87
ОС. 0.50
ОС
D. 0.58
Answers
Answer:
The answer for cos(30°) is 0.87
A negative charge of -2.5 C and a positive charge of 2.0 C are separated by 100 m. What is the force between the two charges?
Answers
Explanation:
F = k |q1| |q2| / r^2
k = 9 * 10^9
q1 = - 2.5 C
q2 = 2 C
r = 100
r^2 = (10^2)^2 = 10^4
F = (9*10^9) * ( 2.5 ) ( 2) / ( 100)^2
F = 45* 10^9 / 10^4
F = 45 * 10^9 * 10 ^ -4 = 45 * 10^5 N
F = 45 * 10 ^ 5 N
Weight is proportional to but not equal to mass. In which of the following situations would a person show an increase in weight but not an increase in mass?
Group of answer choices
a Landing on a planet with more gravity.
b Traveling on the highway in a SUV.
c Living in a chamber in an underwater habitat.
d Climbing to the top of a mountain.
Answers
Answer: c living in a camber in an under water habitat
Explanation:
if the depth of the ocean at a particualr place is 1817.5m how long would it take a sonar siglnal to travel from a ship to the ocean bottom and back again
Answers
If the depth of the ocean at a particular place is 1817.5m, the time it would take a sonar signal to travel from a ship to the ocean bottom and back again would depend on the speed of sound in seawater.
The speed of sound in seawater at a temperature of 15°C (59°F) is around 1,530 meters per second. Therefore, to find the time it would take for the sonar signal to travel from the ship to the ocean bottom and back again, we can use the formula: Time = (2 x Depth) / Speed of Sound.
As we know that the depth of the ocean at a particular place is 1817.5 meters. Therefore, we can find out the time it would take for the sonar signal to travel from the ship to the ocean bottom and back again by substituting these values into the formula:
Time = (2 x Depth) / Speed of Sound Time = (2 x 1817.5) / 1530Time = 2.38 seconds.
Therefore, it would take approximately 2.38 seconds for a sonar signal to travel from a ship to the ocean bottom and back again at that particular location in the ocean. It's important to note that this is just an estimate and the actual time may vary depending on factors such as the temperature, pressure, and salinity of the seawater.
The time it would take for a sonar signal to travel from a ship to the ocean bottom and back again would depend on the depth of the ocean and the speed of sound in seawater. Using the formula Time = (2 x Depth) / Speed of Sound, we can estimate the time it would take for the sonar signal to travel based on these factors. In this case, the depth of the ocean was 1817.5 meters and the speed of sound in seawater was 1530 meters per second, so the estimated time it would take for the sonar signal to travel was 2.38 seconds.
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Transfer Functions of Electrical Systems (Special assignmen 3) There are 4 possible types of transfer functions for electrical systems. 1) Voltage Gain H_V(s) Vi(s) Electrical System V.(s) 2) Transfer Admittance H_Y(s) Vi(s) + +1 Electrical System I.(s) 3) Current Gain H_I(s) L(S) (1) 4) Transfer Impedance H_Z(s) L(S) (1) Electrical System Electrical System V.(s) I.(s) R = 12.50, L= 4H, C = 0.01F R + Vi(t) L CT Vo(t) 1) Find Vc(s)/Vs(s). 2) Show the pole-zero map. 3) Find the response to Vs(t) = u(t)V. 4) Find the response to Vs(t) = o(t)V.
Answers
The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.
To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).
The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.
To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.
Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.
By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.
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A cat walks 1.5km South and then 2.4km East. What is the total displacement of the cat?
Answers
Angle (east of South) = inv tan (2.4/1.5)
Hdhdhdhdhdhgsgdgs
Plls
Answers
All the answers are in the pics I have sent. I hope this will help you. Have a good day!
Point charges q1and q2 of +12nc and -12nc,respectively are placed 10.0cm apart.compute the resultant electric field(magnitude field)
Answers
The electric field due to charge q1 and q2 at the middle point of the line joining the charges q1 and q2 is 8.64*10^(4) N/C.
Note: You have not given the point where the resultant magnetic field has to be calculated. Most probably it is asked to find the electric field at the middle point of the line joining the point charges.
Electric field: The electric force exerted on a unit charge is called the electric field. Electric field due to a charge is calculated using the formula,
E=kq/r^2
where k is a constant whose value is 9*10^(9) N m^2/ C^(2), q is the charge and r is the distance from the charge to the point where the electric field has to be calculated. In the given case, the electric field has to be calculated at the middle point of the line joining charges q1 and q2.
Calculation of electric field due to charge q1:
Given that q1=+12 nC or q1=+12*10^(-9) C and the distance of the charge q1 from the center d1=10.0/2 cm or d1=5*10^(-2) m, the magnitude of the electric field E1 due to charge q1 is,
E1=kq1 /d1^(2)
E1=9*10^(9)*12*10^(-9) / (5*10^(-2))^2
E1=4.32*10^(4) N/C
The direction of the electric field E1 at the middle point is towards the negative charge.
Calculation of electric field due to charge q2:
Given that q2=-12 nC or q1=-12*10^(-9) C and the distance of the charge q2 from the center d2=10.0/2 cm or d2=5*10^(-2) m, the magnitude of the electric field E2 due to charge q2 is,
E2=kq2 /d2^(2)
E2=9*10^(9)*12*10^(-9) / (5*10^(-2))^2
E2=4.32*10^(4) N/C
The direction of the electric field E2 at the middle point is towards the negative charge.
Total electric field:
The total electric field is given by the addition of the electric field. The direction of the electric field is the same for both charges, hence total electric field E is,
E=E1+E2
E=4.32*10^(4) +4.32*10^(4)
E=8.64*10^(4) N/C
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Solve for x. 60(cos 50) = x
Answers
Answer:
x=38.56725658
Explanation:
Answer:
x=38.56725658
Explanation:
What is the velocity of a wave that has a frequency of 2,500 Hz and a wavelength of 2.5 meters?
1,225 m/s
5,000 m/s
500 m/s
50 m/s
Answers
Answer:
5000
Explanation:
m/a
maybe
or maybe not
sorry help