What is the hydrosphere?
everything to do with land
O everything to do with water
O everything to do with air
O everything to do with rocks

Answer:

Volcanoes on Earth form from rising magma. ... Magma also rises when these tectonic plates move toward each other. When this happens, part of Earth's crust can be forced deep into its interior. The high heat and pressure cause the crust to melt and rise as magma.

Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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I believe friction is what it's called?

Answer:

The answer is . A 46.2g

Answer:

The formula is:

v = f λ

Where,

v is the velocity or speed of the wave (in m/s)

f is the frequency of the wave (in Hz)

λ is the wavelength of the wave (in m)

We can rearrange this formula to solve for the frequency:

f = v / λ

We are given the speed and the wavelength of the wave, so we can plug them into the formula:

f = 47 m/s / 25 m

f = 1.88 Hz

To give the answer to 2 decimal places, we round it to:

f = 1.88 Hz

Therefore, the frequency of the wave is 1.88 Hz.

Explanation:

Answer:

1.88 Hz.

Explanation:

The frequency (f) of a wave is related to its speed (v) and wavelength (λ) by the equation f = v/λ.

So to find the frequency of a wave with a speed of 47 m/s and a wavelength of 25 m, we just need to substitute these values into the equation:

f = 47 m/s / 25 m

f = 1.88 Hz

Rounding to 2 decimal places, the frequency of the wave is 1.88 Hz.

Answer:

\(2000\; {\rm cm^{3}}\).

Explanation:

When the ball is placed in this pool of water, part of the ball would be beneath the surface of the pool. The volume of the water that this ball displaced is equal to the volume of the ball that is beneath the water surface.

The buoyancy force on this ball would be equal in magnitude to the weight of water that this ball has displaced.

Let \(m(\text{ball})\) denote the mass of this ball. Let \(m(\text{water})\) denote the mass of water that this ball has displaced.

Let \(g\) denote the gravitational field strength. The weight of this ball would be \(m(\text{ball}) \, g\). Likewise, the weight of water displaced would be \(m(\text{water})\, g\).

For this ball to stay afloat, the buoyancy force on this ball should be greater than or equal to the weight of this ball. In other words:

\(\text{buoyancy} \ge m(\text{ball})\, g\).

At the same time, buoyancy is equal in magnitude the the weight of water displaced. Thus:

\(\text{buoyancy} = m(\text{water}) \, g\).

Therefore:

\(m(\text{water})\, g = \text{buoyancy} \ge m(\text{ball})\, g\).

\(m(\text{water}) \ge m(\text{ball})\).

In other words, the mass of water that this ball displaced should be greater than or equal to the mass of of the ball. Let \(\rho(\text{water})\) denote the density of water. The volume of water that this ball should displace would be:

\(\begin{aligned}V(\text{water}) &= \frac{m(\text{water})}{\rho(\text{water})} \\ &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \end{aligned}\).

Given that \(m(\text{ball}) = 2000\; {\rm g}\) while \(\rho = 1.00\; {\rm g\cdot cm^{-3}}\):

\(\begin{aligned}V(\text{water}) &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \\ &= \frac{2000\; {\rm g}}{1.00\; {\rm g\cdot cm^{-3}}} \\ &= 2000\; {\rm cm^{3}}\end{aligned}\).

In other words, for this ball to stay afloat, at least \(2000\; {\rm cm^{3}}\) of the volume of this ball should be under water. Therefore, the volume of this ball should be at least \(2000\; {\rm cm^{3}}\!\).

Answer:

C

Explanation: Study Island

Answer:

The Straight Line Graph

Explanation:

Answer:.pi/15 cm/s (approx .2094395 cm/s)

Explanation:

Use 2 as your radius which will make the circumference of the clock equal to 4 pi (remember the formula for circumference is pi * diameter)

Using the circuference we can use the formula Speed = distance/Time and plug in our numbers

4pi / 60 seconds = .2094395 cm/s or .002094395 m/s

Answer:

The answer is D

Explanation:

work is done when an object moves in the direction as the force is acting

work is done when an object of mass(m) is moved by a Force(F) through a distance(s) in the direction of the applied force

Answer:

i dont know sir

Explanation:

The correct declaration uses multiple pairs of brackets to represent the dimensions of the array. In this case, we have four dimensions, so we need four pairs of brackets.

To determine the number of steps needed to sort the first half of the elements using Merge sort, we need to understand the Merge sort algorithm and how it works.

Merge sort is a divide-and-conquer algorithm that recursively divides the array into smaller halves until each subarray has only one element. It then merges these subarrays back together in a sorted order.

In this case, the given array is MyArray[] = {60, 20, 21, 10, 19, 8}.

To sort the first half of the elements (i.e., {60, 20, 21}), we perform the following steps in Merge sort:

1. Divide: Split the array into two halves.

  - First half: {60}

  - Second half: {20, 21}

2. Recursively sort the first half: Since the first half has only one element (60), it is already sorted.

3. Recursively sort the second half:

  - Divide: Split the second half into two halves.

    - First half: {20}

    - Second half: {21}

  - Recursively sort the first half: Since the first half has only one element (20), it is already sorted.

  - Recursively sort the second half: Since the second half has only one element (21), it is already sorted.

  - Merge: Merge the sorted first and second halves together.

    - First half: {20}

    - Second half: {21}

    - Merged: {20, 21}

4. Merge the sorted first and second halves together.

  - First half: {60}

  - Second half: {20, 21}

  - Merged: {20, 21, 60}

In total, it takes 3 steps to sort the first half of the elements using Merge sort.

As for the second question, the proper syntax to declare a four-dimensional array of integers in Java is:

int[][][][] fourDArray;

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ACC provides an optimized tip clearance, thus aiding turbine engine efficiency.

The Active Clearance Control (ACC) portion of an EEC (Electronic Engine Control) system aids turbine engine efficiency by providing an optimized tip clearance.

Electronic Engine Control (EEC) is an automated engine control system that governs engine functions like fuel management, ignition, and other engine functions, replacing manual controls. This system aims to provide precise control of engine functions to ensure efficient operation and optimal performance.In modern EEC systems, a sophisticated feedback loop is used to detect engine parameters, including air temperature, pressure, fuel flow, and many others. The data received from these sensors is then transmitted to the EEC unit, which makes decisions about the engine's functioning, such as fuel injection and ignition timing. The EEC is an essential component of many modern gas turbine engines. Its accurate engine control results in improved efficiency, lower fuel consumption, and better emissions.The Active Clearance Control (ACC) portion of an EEC systemThe Active Clearance Control (ACC) portion of an EEC system is used to regulate turbine blade tip clearances during engine operation. The ACC regulates turbine blade tip clearances by adjusting the blade angle or moving shrouds to optimize the gap between the blades and the engine's housing. It does so by receiving data from sensors that monitor the engine's operating temperature and pressure. The ACC can modify the blade angle in response to changes in temperature or pressure, ensuring that the engine operates at maximum efficiency throughout its range of operations. Therefore, ACC provides an optimized tip clearance, thus aiding turbine engine efficiency.

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The speed of light in furlongs per fortnight is approximately 1.802 x 10¹² furlongs/fortnight.

We can start by converting meters to furlongs and seconds to fortnights.

1 meter = 1/201.17 furlongs (since 1 furlong = 220 yards and 1 yard = 0.9144 meters)

1 second = 1/1,209,600 fortnights (since 1 day = 24 hours, 1 hour = 60 minutes, 1 minute = 60 seconds, and 1 fortnight = 14 days)

Using these conversions, we have:

Speed of light = 2.998 x 10⁸ m/s

= (2.998 x 10^⁸ m/s) x (1/201.17 furlongs/m) x (86,400 s/day) x (1 day/14 fortnights)

= 1.802 x 10^¹² furlongs/fortnight

Therefore, the speed of light in furlongs per fortnight is approximately 1.802 x 10^¹² furlongs/fortnight.

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If a wave having a wavelength of 4.0 meters and an amplitude of 2.5 meters travels a distance of 24 meters in 8.0 seconds, the frequency of the wave would be 0.75 Hz.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem a wave having a wavelength of 4.0 meters and an amplitude of 2.5 meters travels a distance of 24 meters in 8.0 seconds.

The number of waves in 24 meters = 24 / 4

                                                          = 6 waves

The number of waves that travels in 8 seconds = 6

The number of waves that travel in 1 second = 6 / 8

                                                                      = 0.75

Thus, the frequency of the wave would be 0.75 Hz.

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Answer:

Respect the client’s decision

Explanation:

just took the test

Answer: Respect the client's decision

Explanation: Either way the professional would know not to do anything rash and it is the client's decision whether or not they want to move forward, it would have obviously been a touchy subject if they were that reluctant.

Answer:

t=6s

Explanation:

v=3m/s

u=12m/s

a=-1.5ms-²

t=?

v=u+at

3=12+(-1.5)t

3-12=-1.5t

t=3-12/-1.5

t=6s

I am not sure if me is correct.

EM energy is like a wave as well as a particle. The concept of wave-particle duality is accounted for in the Quantum Mechanical model.

How is EM energy like a wave?

EM energy is like a wave in a way that it travels from one place to another. This travel is similar to the waves found in a water body that travel from one place to another.

In other words, it travels as a disturbance in a medium or even vacuum that doesn’t need a medium.

In addition, EM waves have features of waves like diffraction, reflection, and interference.

How is EM energy like a particle?

EM energy is also like a particle as it can also act like a particle. An example of this is the photon. Photons are energy particles that have wave-particle duality.

These particles can have particle-like behavior such as being emitted from a source, hitting a target, and interacting with the environment like other particles.

Thus, they act like a wave as well as a particle.

What model accounts for both of these characteristics? The Quantum Mechanical model accounts for both these characteristics, the wave-like and particle-like behavior of EM energy.

It explains that the energy of EM waves is quantized and its energy comes in packets known as photons. These photons can act as particles as well as waves in different situations.

The wave-particle duality is thus accounted for in the Quantum Mechanical model.

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Answer:  

GIVEN:

v₀=0ms⁻¹

a= 8.1ms⁻²

t= 19.4s

REQUIRE:

d=?

CALCULATUION:

as we know,

d=v₀t+1/2at²

by putting values

d=0ms⁻¹×19.4s+1/2×8.1ms⁻²×(19.4s)²

d=0m+1/2×8.1ms⁻²×376.36s²

d=1/2×3048.516m

d=1524.258m

d≈1524m

When ascending from deep-sea diving to sea-level, it is necessary to follow certain methods and a time-course to prevent decompression sickness. The optional methods and time-course to follow are given below:

Optional methods:1. Safety stop: This is the process of stopping at a depth of 15 feet for a few minutes. This allows the nitrogen in the body to escape safely. This is not necessary if the dive is less than 50 feet.2. Decompression stops: If the dive is deeper than 50 feet, decompression stops should be performed. This involves stopping at various depths on the way up to allow nitrogen to escape from the body.3. Surface Marker Buoy: This is a buoy that is placed at the surface to alert boat traffic that a diver is in the area.

Time-course:

1. For dives that are less than 30 feet, there is no need to follow any specific time-course.2. For dives that are deeper than 30 feet, it is recommended to ascend slowly and steadily, at a rate of no more than 30 feet per minute.

3. For decompression stops, the diver should remain at the stop depth for the recommended time, which is usually based on the depth of the dive.

4. The ascent should be interrupted if any signs of decompression sickness are present.

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Answer:

uui 2+6=8m calculator hunny work's

Using the dot and cross product, we find that the angle between vectors A and B is 90°.

The angle between two vectors can be determined using the dot and cross product. In this case, if the dot product of vectors A and B is zero, it means that the vectors are orthogonal, and the angle between them is 90°.

The dot product of two vectors, A and B, can be calculated using the equation:

A · B = |A| |B| cos(θ)

where |A| and |B| represent the magnitudes of vectors A and B, respectively, and θ is the angle between them.

Given that the dot product A · B is zero, we have:

0 = |A| |B| cos(θ)

Since the magnitudes of vectors A and B are both non-zero, we can conclude that cos(θ) must be zero. The cosine of an angle is zero when the angle is 90° or 270°. However, we are only interested in the angle between 0° and 180°.

Therefore, the angle between vectors A and B is 90°.

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Answer:

The answer is "Observe it in the infrared"

Explanation:

The infrared observatory is a device, which helps to track but also fix thermal light from sources out and the front of Earth's atmosphere like nebulae, young stars, and dust and gas in several other galaxies.

The very center of our galaxy is like a star cluster is situated in the central of our universe across the Milky Way supermassive, and the central black hole, around 4 million times our sun's mass.

The main super black hole named the Sagittarius A-star has been located in the nucleus of the galaxy, that's why in this question "Observe it in the infrared" is the correct answer.

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Better identification of novel species is made possible by categorization.

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To determine the operating efficiency of the electric motor, we first need to calculate the mechanical power output and the electrical power input, then divide the output by the input and multiply by 100% to get the efficiency.

Mechanical power output:
P_out = m * g * v
where m = 9 kg (mass), g = 9.81 m/s² (acceleration due to gravity), and v = 0.5 m/s (velocity)

P_out = 9 * 9.81 * 0.5 ≈ 44.145 W (watts)

Electrical power input:
P_in = I * V
where I = 0.5 A (current) and V = 120 V (voltage)

P_in = 0.5 * 120 = 60 W (watts)

Efficiency:
Efficiency = (P_out / P_in) * 100%

Efficiency ≈ (44.145 / 60) * 100% ≈ 73.575%

The operating efficiency of the electric motor is most nearly:
D) 75%

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Explanation:

The expression for the magnetic field around the current carrying wire is given by :

\(B=\dfrac{\mu_o I}{2\pi r}\)

Here,

I is electric current and r is distance from the wire.

The factors affect the strength of magnetic field around current carrying wire are :

In most situations, the strong correlation usually ranges between 0.7 to 0.9. So 0.5 is not a strong correlation.

Correlation is an important concept in statics. This helps to associate the relationship between two variables. This is of two types namely positive correlation and negative correlation.

In a positive correlation, the association of two variables occurs in the same way. That is they both decrease or increase. In a negative correlation, the association of one variable occurs oppositely to another variable. That is, when one variable decreases, another variable increases.

This correlation is represented by the symbol r. This r-value range from +1 to -1. So the perfect positive correlation is +1 and the perfect negative correlation is -1.

In, the positive correlation, the values from 0.1 to 0.3 is considered weak or low correlation. The values from 0.4 to 0.6 are considered a moderate correlation and the values from 0.7 to 0.9 are considered a strong correlation.

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