What is the horizontal asymptote

900 millimeters is equivalent to 35.433070866 inches.

Inches and millimeters are both units of measurement for length. To convert from millimeters to inches, we can use the conversion factor that 1 inch is equal to 25.4 millimeters. To convert 900 millimeters to inches, we can multiply 900 by the conversion factor.

The formula for converting millimeters to inches is:

inches = millimeters / 25.4

So in this case:

inches = 900 / 25.4

After doing the calculation, we find that 900 millimeters is equivalent to 35.433070866 inches.

It's important to note that the conversion factor is a constant value which is used multiple times during the conversion process.

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The equation that he used to find n, the number of gallons of water he should remove is 3.52 / (22 - n) = 24 / 100. Option C is correct.

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

Amount of ammonia in the solution 16%  x 22 gallons  =  3.52 gallons

The proportion of ammonia remains the same as the water evaporates, but the total composition of the solution is decreased by the amount of water that evaporates.

Quantity of ammonia = 3.52 gallons

Quantity of water after evaporation = 22 - n

Composition of ammonia after evaporation of water, 24% = 24/100

Now the percentage of ammonia after evaporates
Quantity of ammonia / Remaining water = 24%
3.52 / (22 - n) = 24 / 100

Thus, the equation that he used to find n, the number of gallons of water he should remove is 3.52 / (22 - n) = 24 / 100.

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In constructing a transversal city map by applying the knowledge of transversal and parallel lines, a map named California City Map has been drawn as shown in the image attached below.

(See attachment).

Recall:

Using the knowledge of all these, an map named, "California City Map" has been drawn as shown in the image attached below.

The details are as follows:

1. Title for the map is:

2. The three streets that are parallel are:

The street (transversal) that intersects the three is:

3. St. Michael Hospital is alternate exterior to Baptist Model School

4. Baptist Model School and Living Well Drug Store are in corresponding locations to each other.

5. Living Well Drug Store and Vik Pet Store are at vertical locations.

6. Vik Pet Store and Elite Gas-station are at alternate interior locations.

7. St. Michael Hospital and Livingstone Park are at same-side exterior locations.

8. Elite Gas-station and Richie Grocery Store are at same-side interior locations.

9. Richie Grocery Store and Beautyjay Nail salon are at vertical locations.

10. Beautyjay Nail salon and Retro Bank Plc are at corresponding locations.

11. Retro Bank Plc and Tessy's Fast Food Restaurant are at same-side interior locations.

12. California City Mall and Remis Bookstore are at corresponding locations.

In summary, in constructing a transversal city map by applying the knowledge of transversal and parallel lines, a map named California City Map has been drawn as shown in the image attached below.

(See attachment).

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The probability of getting tails on the coin and an even number on the number cube is 1/4

Probabilities are used to determine the chances, likelihood, possibilities of an event or collection of events

The sample space of a coin is:

S = {H, T}

The sample space of a die is:

S = {1, 2, 3, 4, 5, 6}

The above means that:

A coin has 2 faces, one of which is the tail.

So, we have:

P(Tail) = 1/2

A number cube has 6 numbers, 3 or which are even.

So, we have

P(Even) = 3/6

The required probability is

P = P(Tail) * P(Even)

This gives

P = 1/2 * 3/6

Evaluate

P = 1/4

Evaluate the quotient

P = 0.25

Hence, the probability of getting tails on the coin and an even number on the number cube is 1/4 or 0.25

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Answer:

uhm okay my dude

Answer:

cool poem

Step-by-step explanation:

Answer:

To do this we will substitute each one in

6, 1 =

4(6) - 3(1) = 5

24 - 3 = 5

21 = 5

so its not that one

0,6 =

4(0) - 3(6) = 5

0 - 18 = 5

18 = 5 not that one!
5, 5 =

4(5) - 3(5) = 5

20 - 15 = 5

5 = 5

(5,5) is one of the solutions

-3, -4 =

4(-3) -3(-4) = 5

-12 + 12 = 5

0 = 5

not that one

-1, -3 =

4(-1) - 3(-3) = 5

-4 + 9 = 5

5 = 5

(-1, -3) is also a solution

-5, 3 =

4(-5) - 3(3) = 5

-20 - 9 = 5

-29  = 5

The two solutions are (-1,-3) and (5,5)

Step-by-step explanation:

The order of a in (z/(pq))× is exactly (p-1)(q-1), as desired.

To prove that (z/(pq))× has order (p − 1)(q − 1), we need to show that the least positive integer n such that (z/(pq))×n = 1 is (p − 1)(q − 1).

First, let's define (z/(pq))× as the set of all integers a such that gcd(a,pq) = 1 (i.e., a is relatively prime to pq) and a mod pq is also relatively prime to pq.

Now, we know that the order of an element a in a group is the smallest positive integer n such that a^n = 1. Therefore, we need to find the order of an arbitrary element a in (z/(pq))×.

Let's assume that a is an arbitrary element in (z/(pq))×. Since gcd(a,pq) = 1, we know that a has a multiplicative inverse modulo pq, denoted by a^-1. Therefore, we can write:

a * a^-1 ≡ 1 (mod pq)

Now, let's consider the order of a. Since gcd(a,pq) = 1, we know that a^(p-1) is congruent to 1 modulo p by Fermat's Little Theorem. Similarly, we can show that a^(q-1) is congruent to 1 modulo q. Therefore, we have:

a^(p-1) ≡ 1 (mod p)
a^(q-1) ≡ 1 (mod q)

Now, we can use the Chinese Remainder Theorem to combine these congruences and get:

a^(p-1)(q-1) ≡ 1 (mod pq)

Therefore, we know that the order of a must divide (p-1)(q-1).

To show that the order of a is exactly (p-1)(q-1), we need to show that a^k is not congruent to 1 modulo pq for any positive integer k such that 1 ≤ k < (p-1)(q-1).

Assume for contradiction that there exists such a k. Then, we have:

a^k ≡ 1 (mod pq)

This means that a^k is a multiple of pq, which implies that gcd(a^k, pq) ≥ pq. However, since gcd(a,pq) = 1, we know that gcd(a^k, pq) = gcd(a,pq)^k = 1. This is a contradiction, and therefore our assumption must be false.

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The order of a in (z/(pq))× is exactly (p-1)(q-1), as desired.

To prove that (z/(pq))× has order (p − 1)(q − 1), we need to show that the least positive integer n such that (z/(pq))×n = 1 is (p − 1)(q − 1).

First, let's define (z/(pq))× as the set of all integers a such that gcd(a,pq) = 1 (i.e., a is relatively prime to pq) and a mod pq is also relatively prime to pq.

Now, we know that the order of an element a in a group is the smallest positive integer n such that a^n = 1. Therefore, we need to find the order of an arbitrary element a in (z/(pq))×.

Let's assume that a is an arbitrary element in (z/(pq))×. Since gcd(a,pq) = 1, we know that a has a multiplicative inverse modulo pq, denoted by a^-1. Therefore, we can write:

a * a^-1 ≡ 1 (mod pq)

Now, let's consider the order of a. Since gcd(a,pq) = 1, we know that a^(p-1) is congruent to 1 modulo p by Fermat's Little Theorem. Similarly, we can show that a^(q-1) is congruent to 1 modulo q. Therefore, we have:

a^(p-1) ≡ 1 (mod p)
a^(q-1) ≡ 1 (mod q)

Now, we can use the Chinese Remainder Theorem to combine these congruences and get:

a^(p-1)(q-1) ≡ 1 (mod pq)

Therefore, we know that the order of a must divide (p-1)(q-1).

To show that the order of a is exactly (p-1)(q-1), we need to show that a^k is not congruent to 1 modulo pq for any positive integer k such that 1 ≤ k < (p-1)(q-1).

Assume for contradiction that there exists such a k. Then, we have:

a^k ≡ 1 (mod pq)

This means that a^k is a multiple of pq, which implies that gcd(a^k, pq) ≥ pq. However, since gcd(a,pq) = 1, we know that gcd(a^k, pq) = gcd(a,pq)^k = 1. This is a contradiction, and therefore our assumption must be false.

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The distance, d, in feet from Kim t seconds after Max started riding his scooter is given by the equation d = st, where s is the constant speed at which Max is riding his scooter.

To find the distance, d, we need to multiply the speed, s, by the time, t. Since Max passes Kim at a constant speed, the distance he travels is directly proportional to the time elapsed.

Therefore, the equation d = st represents this relationship, where d is the distance, s is the speed, and t is the time.

The equation d = st allows us to calculate the distance, d, from Kim t seconds after Max started riding his scooter, provided we know the constant speed, s, at which Max is traveling. By multiplying the speed by the time, we can determine how far Max has traveled from Kim at any given moment. This equation assumes that Max maintains a constant speed throughout his journey and that the speed does not change.

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The lengths of the line segments seen in the table are listed below:

In this problem we find six cases of line segments (\(\overline{AC}\), \(\overline{BC}\), \(\overline{DE}\), \(\overline{AB}\), \(\overline{EF}\), \(\overline{FG}\)), whose length have to be computed. Every length can be found by Pythagorean theorem:

l = √[(Δx)² + (Δy)²]

Where l is the length of the line segment between two ends.

Now we proceed to determine the length of each line segment:

Line segment AC

AC = √(8² + 3²)

AC = √73

Line segment BC

BC = √[(- 2)² + 6²]

BC = √40

Line segment DE

DE = √[(- 3)² + (- 1)²]

DE = √10

Line segment AB

AB = √[10² + (- 9)²]

AB = √181

Line segment EF

EF = √(5² + 3²)

EF = √34

Line segment FG

FG = √(11² + 15²)

FG = √346

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A control chart is a visual representation of the various states in a process. The answer is b. True. Control charts are used in quality control and process improvement to monitor and analyze the performance of a process over time.

b. True. A control chart is a graphical tool used to monitor the performance of a process over time. It is a visual representation of the data collected from the process and helps in identifying any patterns or trends that may occur. The chart typically consists of a central line representing the average or target value, and upper and lower control limits representing the acceptable range of values for the process. The data is plotted on the chart, and any points that fall outside the control limits indicate a process that is out of control and may require further investigation. Control charts are commonly used in industries such as manufacturing, healthcare, and finance to ensure that processes are running smoothly and to identify any potential issues early on. Overall, control charts provide a powerful way to monitor and manage processes in a systematic manner.

They help to identify trends, patterns, and variations that may indicate potential issues, allowing for timely corrective actions to be taken.

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If the steps are shaped like rectangular prism, then the expression that can be used to find the volume is option (B)  (6×16×6)+(14×16×7)

The steps are shaped like rectangular prism

The length of the rectangular prism = l×w×h

Where l is the length

w is the width

h is the height

First we have to separate the given steps in to two rectangular prism and find the volume of each prism

The volume of the top prism = l×w×h

= 6×16×6 cubic inches

The volume of the bottom prism = l×w×h

= 14×16×7 cubic inches

The total volume = (6×16×6)+(14×16×7) cubic inches

Hence, if the steps are shaped like rectangular prism, then the expression that can be used to find the volume is option (B)  (6×16×6)+(14×16×7)

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To find the area of the region below the curve y = x^2 + 2x - 2 and above the line y = 5, we need to determine the intersection points of the two curves and then calculate the area between them.

Step 1: Find the intersection points. Set the two equations equal to each other: x^2 + 2x - 2 = 5. Rearrange the equation to bring it to the standard quadratic form: x^2 + 2x - 7 = 0. Solve this quadratic equation for x using factoring, completing the square, or the quadratic formula. Let's use the quadratic formula:x = (-2 ± √(2^2 - 41(-7))) / (2*1)

x = (-2 ± √(4 + 28)) / 2

x = (-2 ± √32) / 2

x = (-2 ± 4√2) / 2

x = -1 ± 2√2. So the two intersection points are: x = -1 + 2√2 and x = -1 - 2√2. Step 2: Calculate the area. To find the area between the two curves, we integrate the difference between the two curves with respect to x over the interval where they intersect.

The area can be calculated as follows: Area = ∫[a, b] (f(x) - g(x)) dx. In this case, f(x) represents the upper curve (y = x^2 + 2x - 2) and g(x) represents the lower curve (y = 5). Area = ∫[-1 - 2√2, -1 + 2√2] [(x^2 + 2x - 2) - 5] dx. Simplify the expression: Area = ∫[-1 - 2√2, -1 + 2√2] (x^2 + 2x - 7) dx. Integrate the expression: Area = [(1/3)x^3 + x^2 - 7x] evaluated from -1 - 2√2 to -1 + 2√2. Evaluate the expression at the upper and lower limits:Area = [(1/3)(-1 + 2√2)^3 + (-1 + 2√2)^2 - 7(-1 + 2√2)] - [(1/3)(-1 - 2√2)^3 + (-1 - 2√2)^2 - 7(-1 - 2√2)]. Perform the calculations to obtain the final value of the area. Please note that the calculations involved may be quite lengthy and involve simplifying radicals. Consider using numerical methods or software if you need an approximate value for the area.

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The blanks can be filled as: 1) union, 2) 120, 3) Mutually exclusive, Independent.

1- The union of two events A and B is the event in which either A or B or both occur.

The union of two events A and B includes all outcomes that belong to either A or B or both.

2- Calculate 5! (5 factorial) which is 5 x 4 x 3 x 2 x 1 = 120.

To calculate factorial of a positive integer n, multiply n by all positive integers less than n and greater than 0; alternatively, recursively multiply n by (n-1)!

3. Two events are said to be:

Mutually exclusive if they cannot occur at the same time.

Independent if the occurrence of one does not influence the probability of occurrence for the other..

Mutually exclusive events cannot occur together, while independent events can occur together but their occurrence does not affect each other.

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Answer:

A: 6/13 cups of flour.

Step-by-step explanation:

Answer: 108ft^2

Step-by-step explanation:

First, at the top we have two triangle rectangles.

The area of a triangle rectangle is equal to the product of their cathetus divided by two.

We know that one common cathetus for both triangles is 6ft.

And both share the bottom line that is 14ft long, so half of that corresponds to each triangle.

14ft/2 = 7ft

Then each triangle has a cathetus of 6ft and one of 7ft.

Then the area of each triangle rectangle at the top is:

6ft*7ft/2 = 21ft^2

And we have two of them, so the area for now is:

A1 = 21ft^2 + 21ft^2 = 42ft^2.

Now let's look at the bottom part, we can divide this into two triangle rectangles and one rectangle.

First, bottom side is 8ft, then the difference between this side and the 14ft one is:

14ft - 8ft = 6ft

(We calculate this because we are making a rectangle, then the bottom side length must be equal than the top one).

Then we have a surpass of 6ft, which we will divide into both triangle rectangles (3ft for each, this is one of the cathetus).

And we can see that the cathetus shown of this triangle rectangle is 6ft (this is also the other side of our rectangle)

Then we have two triangles with cathetus 6ft and 3 ft, the area is:

A = 6ft*3ft/2 = 9ft^2

And we have two of them, then A2 = 18ft^2.

And the rectangle is 8ft by 6ft, the area is:

A3 = 8ft*6ft = 48ft^2

Then if we add all the areas that we found, we have:

A1 + A2 + A3 = 42ft^2 + 18ft^2 + 48ft^2 = 108ft^2

Arrange the data in ascending order,

The mean is ,

The mean is 98.6.

The median is,

The median is 96.5.u

The mode is the value that appears most often in a set of data values.

The range is determined as the difference between the maximum and minimum value.

Answer:

Y=16

Step-by-step explanation:

Becasue if you substitute 2 in for x, you get 8 times 2=16

Answer:

y=8 and

x=2

If x=2, then

8x=8*2=16

so therefore , y=8x i.e 16

y=16

SIMPLE AS THAT !!

Step-by-step explanation:

Answer:

37.50 square centimeters

Step-by-step explanation:

The computation of the area of the sector is as follows:

As we know that

Area of the circle is

= πr^2

Since the radius is 10 cm so the area of total circle is

= 3.14 × 100

= 314

Also it is 360 degrees  

So, the area of the sector is

= 135 ÷ 360 × 1200

= 37.50 square centimeters

Answer:

3p - q = 3(2-5) - (8x3) = -9 - 24 = -33. Therefore, 3p-q=-33.

The given data are:N = 600; G = 24; S = 4 m/s; Up-peak interval = 32 s; Expected up-peak demand = 20%; h = 8 m; Door opening time = 2 s; Door closing time = 2 s; Passenger loading time = 0.8 s;

Passenger unloading time = 0.8 s; Single floor flight time = 5 s; Hence, the minimum up-peak handling capacity (UPPHC) is 20% of 600 persons as per the question. Thus, UPPHC = (20/100) × 600=120 persons.

(a) Minimum up-peak handling capacity (UPPHC): UPPHC = 120 persons.

(b) Minimum contract capacity (CC): The formula for CC is given byCC = [(UPPHC × 3600)/Up-peak hours] = [(120 × 3600)/4] = 10800 persons/hr.

Hence, the minimum contract capacity is 10800 persons/hr.

(c) Average highest call reversal floor (H) and the average number of stops (S):

The formula for the average highest call reversal floor isH = [n/(n – 1)] × [∑f/(n × P)].

Where, n = number of lifts; ∑f = sum of the products of the number of floors served and the corresponding number of calls; and P = ∑f/number of floors served. Thus, H = [n/(n – 1)] × [∑f/(n × P)]For S, the formula is given by

S = ∑f/(n × P).

Thus, for calculating H and S, the traffic calculation is done, and the calculations are provided below:

For traffic design, let n = 3. Then, Np = UPPHC/up-peak hour= (120 × 3600)/3600=120 persons/hr.

Let the average number of stops be S. Then the number of floors served on the average during the up-peak hour is given by 24/S.

From the traffic flow diagram, the average highest call reversal floor is (3/2) H

= [3/(3 – 1)] × [((1 × 2) + (2 × 4) + (3 × 7) + (4 × 8) + (5 × 9) + (6 × 10) + (7 × 10) + (8 × 9) + (9 × 8) + (10 × 7) + (11 × 6) + (12 × 5) + (13 × 4) + (14 × 2))/(3 × 12)] = (3/2) × 7.63 = 11.45 ≈ 11 th floor.

∴ Average highest call reversal floor, H = 11th floor.∴ The average number of stops,

S = ∑f/(n × P)= [(1 × 2) + (2 × 4) + (3 × 7) + (4 × 8) + (5 × 9) + (6 × 10) + (7 × 10) + (8 × 9) + (9 × 8) + (10 × 7) + (11 × 6) + (12 × 5) + (13 × 4) + (14 × 2)]/3 × 12 × 1= 526/36= 14.61 ≈ 15.

(d) Round trip time (RTT):The formula for RTT is given by RTT = 2 × [L × (h/S) × Single floor flight time + Door open and closing time + Passenger loading and unloading time].

Where, L = number of lifts required to provide the UPPHC during the up-peak hour.

Thus, the calculation for L is done first as:

L = UPPHC/[(h/S) × Single floor flight time × 3600/up-peak hour]Now, substituting the given values in the above formula, we get,L = 120/[(8/4) × 5 × 3600/240] = 5 lifts(approx.)

Now, substituting the above value of L in the formula for RTT, we get

RTT = 2 × [5 × (8/4) × 5 + 2 + 0.8 + 0.8] = 94 s(approx.).Thus, the round trip time (RTT) is 94 s.

(e) Number of lifts required (L): We have already calculated the value of L, which is equal to 5 lifts.

(f) Real up peak interval (UPPINT):The formula for the real up-peak interval is given by:

Real up peak interval = (RTT × Number of cycles per hour)/(60 × Number of lifts required)Where the number of cycles per hour is given by 3600/RTT.

Hence, the value of the number of cycles per hour is equal to 3600/94, which is approximately equal to 38.298.

Now, substituting all the above values in the formula, we get

Real up peak interval = (94 × 38.298)/(60 × 5) = 30.06 s(approx.).Hence, the real up-peak interval (UPPINT) is 30.06 s.

The quality of the lift system is excellent since the real up-peak interval is less than the up-peak interval of 32 s, which was the expected value.

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The average rate of change of f(x) = -11√x + 14 over the interval [-10, -9]. is 0.7

The average Rate of Change of the function f(x) can be calculated as;

\(f(x) = \dfrac{f(b) - f(a)}{b-a}\)

We have been given the function as; f(x) = -11√x + 14 over the interval [-10, -9].

i.e. a = -10 and b = -9

Therefore,  f(x) = -11√x + 14

f(-9) = -11√(-9) + 14

f(-9) = -33 + 14

f(-9) = -19

Also,  f(-10) =  -11√(-10) + 14

f(-10) = - 34.7 + 14

f(-10) = 20.7

Now, substitute the values;

\(f(x) = \dfrac{f(b) - f(a)}{b-a}\\f(x) = \dfrac{f(-9) - f(-10)}{-9+ 10}\\f(x) = \dfrac{-19-20.7}{1}\\f(x) = 0.7\)

Hence, the average rate of change of f(x) = -11√x + 14 over the interval [-10, -9]. is 0.7

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Answer:

2/5

Step-by-step explanation:

The slope of the line

y=2/5x-4

is 2/5 since it is in the form y = mx+b where m is the slope

Parallel lines have the same slope so a line that is parallel to  y=2/5x-4 has a slope of 2/5

Answer:

7+2g

Step-by-step explanation:

7 increased by means 7 +

twice Gali's height =2g

everything now becomes 7+2g

Answer:

B

Step-by-step explanation:

The solution to the initial value problem is √x = (1/3) \(y^{\frac{3}{2} }\) + 2/3.

Given: dx/dy = -2y, y = 3 when x = 0

To solve this, we'll separate the variables and integrate:

dx = -2y dy

Integrating both sides:

∫ dx = ∫ -2y dy

x = - \(y^{2}\) + C

Now we can apply the initial condition y = 3 when x = 0:

0 = - \(3^{2}\) + C

C = -9

Therefore, the solution to the initial value problem is x = - \(y^{2}\) - 9.

Given: dx/dy = xy, y = 1 when x = 0

We'll again separate the variables and integrate:

dx = xy dy

Integrating both sides:

∫ dx = ∫ xy dy

x = (1/2)\(y^{2}\) + C

Applying the initial condition y = 1 when x = 0:

0 = (1/2) \(1^{2}\) + C

C = -1/2

Thus, the solution to the initial value problem is x = (1/2)\(y^{2}\) - 1/2.

Given: dx/dy = \(e^{x+y}\), y = 0 when x = 0

Separating the variables and integrating:

dx = \(e^{x+y}\) dy

∫ dx = ∫ \(e^{x+y}\) dy

x = \(e^{x+y}\) + C

Using the initial condition y = 0 when x = 0:

0 = \(e^{0+0}\) + C

C = -1

Hence, the solution to the initial value problem is x = \(e^{x+y}\) - 1.

Given: dx/dy = √(y/x), y = 1 when x = 1

Again, separating the variables and integrating:

dx/√x = √y dy

Integrating both sides:

2√x = (2/3)\(y^{\frac{3}{2} }\) + C

Simplifying:

√x = (1/3)\(y^{\frac{3}{2} }\) + C

Applying the initial condition y = 1 when x = 1:

1 = (1/3)\(1^{\frac{3}{2} }\) + C

C = 2/3

Therefore, the solution to the initial value problem is √x = (1/3) \(y^{\frac{3}{2} }\) + 2/3.

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The expression for  d=rt in terms of the time is t = d/r; t = 5.

Therefore,

In the equation d=rt

                          t = d/r

when distance is 40 and the rate is 8

                          t = d/r

Replace d with 40 and rate with 8

                          t = 40/8

                          t = 5

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Answer:

554 N

Step-by-step explanation:

We're looking for the magnitude of the force - angles don't matter.

We need to resolve the two forces.

As you can see in the attached drawing, this basically just becomes Pythagoras.

\( {f}^{2} = {355}^{2} + {425}^{2}\)

\(f = \sqrt{ {355}^{2} + {425}^{2} } \)

\(f = 553.76\)