What is the HCF of 8 and 12?

The broad sense heritability (H2) for tail length in the population of peacocks is approximately 0.5547, indicating that genetic factors contribute to about 55.47% of the observed phenotypic variance in tail length.

The broad sense heritability (H2) is defined as the proportion of phenotypic variance that can be attributed to genetic factors in a population. It is calculated by dividing the genetic variance by the phenotypic variance.

In this case, the phenotypic variance is given as 2.56 cm², which represents the total variation in tail length observed in the population. The environmental variance is given as 1.14 cm², which accounts for the variation in tail length due to environmental factors.

To calculate the genetic variance, we subtract the environmental variance from the phenotypic variance:

Genetic variance = Phenotypic variance - Environmental variance

                 = 2.56 cm² - 1.14 cm²

                 = 1.42 cm²

Finally, we can calculate the broad sense heritability:

H2 = Genetic variance / Phenotypic variance

   = 1.42 cm² / 2.56 cm²

   ≈ 0.5547

Therefore, the broad sense heritability (H2) for tail length in the population of peacocks is approximately 0.5547, indicating that genetic factors contribute to about 55.47% of the observed phenotypic variance in tail length.

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Answer:

2

Step-by-step explanation:

9-5/0-(2)=4/2=2

The equation of the tangent line to the parabola at the point (1,5) is y = 4x + 1.

To find the slope of the tangent line to the parabola at the point (1,5), we need to find the derivative of the equation y = 6x - x² and evaluate it at x = 1.

Taking the derivative of y with respect to x:

dy/dx = d(6x - x²)/dx

= 6 - 2x

Now, we can substitute x = 1 into the derivative to find the slope at that point:

slope = 6 - 2(1)

= 6 - 2

= 4

So, the slope of the tangent line to the parabola at the point (1,5) is 4.

To find the equation of the tangent line, we need to use the point-slope form of a line.

The equation is given by:

y - y₁ = m(x - x₁)

Substituting the values we have:

y - 5 = 4(x - 1)

Expanding and simplifying:

y - 5 = 4x - 4

Moving the constant term to the other side:

y = 4x + 1

Therefore, the equation of the tangent line to the parabola at the point (1,5) is y = 4x + 1.

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Complete question =

Find the slope of the tangent line to the parabola at the point (1,5). y = 6x-x². find an equation of the tangent line.

Answer:

555 and 565

Step-by-step explanation:

The area under the standard normal curve between (a) z = -0.24 and z = 0.24 is 0.1886, (b) z = -1.47 and z = 0 is 0.4292, and (c) z = 0.13 and z = 0.62 is 0.1800.

To determine the area under the standard normal curve between two z-values, we can use a standard normal distribution table or a statistical software. The standard normal distribution is a continuous probability distribution with a mean of 0 and a standard deviation of 1. The area under the curve represents the probability of a random variable falling within a certain range.

Steps to calculate the area under the standard normal curve:

(a) Area between z = -0.24 and z = 0.24:

To calculate the area between these two z-values, we need to find the cumulative probability for each z-value and then subtract the smaller cumulative probability from the larger one. The cumulative probability represents the area under the curve to the left of a given z-value.

Using a standard normal distribution table or a statistical software, we find:

P(z < -0.24) = 0.4052

P(z < 0.24) = 0.5938

The area between z = -0.24 and z = 0.24 is:

P(-0.24 < z < 0.24) = P(z < 0.24) - P(z < -0.24) = 0.5938 - 0.4052 = 0.1886

(b) Area between z = -1.47 and z = 0:

Using the same approach, we find:

P(z < -1.47) = 0.0708

P(z < 0) = 0.5

The area between z = -1.47 and z = 0 is:

P(-1.47 < z < 0) = P(z < 0) - P(z < -1.47) = 0.5 - 0.0708 = 0.4292

(c) Area between z = 0.13 and z = 0.62:

Again, using the same approach, we find:

P(z < 0.13) = 0.5524

P(z < 0.62) = 0.7324

The area between z = 0.13 and z = 0.62 is:

P(0.13 < z < 0.62) = P(z < 0.62) - P(z < 0.13) = 0.7324 - 0.5524 = 0.1800

Therefore, the area under the standard normal curve between (a) z = -0.24 and z = 0.24 is 0.1886, (b) z = -1.47 and z = 0 is 0.4292, and (c) z = 0.13 and z = 0.62 is 0.1800.

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Answer:

Andy's Shoe Palace

Step-by-step explanation:

I did it and got it right :)

N(x, y, z) = [-1, √3, 2] . [x - √3/2, y + 1/2, z - √3] = 0and O(x, y, z) = [-2√3, -2, 4√3] . [x - √3/2, y + 1/2, z - √3] = 0 respectively.

The equations of the normal plane and osculating plane of the curve at the given point are given by N = 0 and O = 0.

Here is the step-by-step explanation for finding equations of the normal plane and osculating plane of the curve at the given point for X= sin 2t, y=-c0s 2t, z =(0, 1, 2x) and 150:

Given that X= sin 2t, y=-c0s 2t, z =(0, 1, 2x) and t = 150.

Let us first find the first derivative of the given function.

f (t) = [X(t), Y(t), Z(t)] = [sin 2t, -cos 2t, 2 sin 2t]f'(t) = [2 cos 2t, 2 sin 2t, 4 cos 2t]

Again, let us find the second derivative of the given function.

f''(t) = [-4 sin 2t, 4 cos 2t, -8 sin 2t]At t = 150, we have

f'(t) = [2 cos 300, 2 sin 300, 4 cos 300] = [-1, √3, 2]f''(t) = [-4 sin 300, 4 cos 300, -8 sin 300] = [-2 √3, -2, 4 √3]

At the given point [X(150), Y(150), Z(150)] = [sin 300, -cos 300, 2 sin 300] = [√3/2, -1/2, √3]

The equation of the normal plane can be found as

N(x, y, z) = [f'(150)] . [x - X(150), y - Y(150), z - Z(150)] = 0[-1, √3, 2] . [x - √3/2, y + 1/2, z - √3] = 0

The equation of the osculating plane can be found as

O(x, y, z) = [f''(150)] . [x - X(150), y - Y(150), z - Z(150)] = 0[-2√3, -2, 4√3] . [x - √3/2, y + 1/2, z - √3] = 0

Hence, the equations of the normal plane and osculating plane of the curve at the given point are given by

N(x, y, z) = [-1, √3, 2] . [x - √3/2, y + 1/2, z - √3] = 0and O(x, y, z) = [-2√3, -2, 4√3] . [x - √3/2, y + 1/2, z - √3] = 0 respectively.

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The polynomial with degree 4 and the given zeros is f(x) = ((x+2)² + 25)(x-4)²

If a polynomial has complex zeros with non-zero imaginary parts, then the complex conjugate of each complex zero must also be a zero of the polynomial with the same multiplicity.

Therefore, the zeros of the polynomial with degree 4 are:

-2-5i, -2+5i, 4, and 4 (with multiplicity 2).

To find the polynomial, we can start by writing out the factors corresponding to each zero:

(x - (-2-5i))(x - (-2+5i))(x - 4)²

Simplifying the factors, we get:

((x+2)+5i)((x+2)-5i)(x-4)²

Expanding the factors, we get:

((x+2)² - (5i)²)(x-4)²

((x+2)² + 25)(x-4)²

Thus, the polynomial with degree 4 and the given zeros is:

f(x) = ((x+2)² + 25)(x-4)²

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Answer:

use photomath bestie

Answer:

13 yards

Step-by-step explanation:

1 yard = 3 feet

39 ÷ 3 = 13 yards

The cloth is 13 yards.

Hope this helps!

Answer:

13 yards

Step-by-step explanation:

The correct option are-

A) Triangle CEG

B) Triangle AEH

C) Triangle CFG

E) Triangle BFG

The right triangles that can be formed using a diagonal through the interior of the cube.

A triangle is said to be right-angled if one of its inner angles is 90 degrees, or if any one of its angles is a right angle. The right triangle and 90-degree triangle is another name for this triangle.

Now according to the question,

From the shown figure it is seen that;

A) Triangle CEG:

In this triangle CEG, CG is perpendicular on GE. So, they for right angle at G.

B) Triangle AEH:

In this triangle AEH, AE is perpendicular on EH. So, they for right angle at E.

C) Triangle CFG:

In this triangle CFG, CG is perpendicular in FG. So, they for right angle at G.

E) Triangle BFG:

In this triangle BFG, BF is perpendicular on FG. So, they for right angle at F.

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The correct question is-

A cube. the top face has points A, B, C, D and the bottom face has points E, F, G, h. Which are right triangles that can be formed using a diagonal through the interior of the cube? Select all that apply.

A) Triangle CEG

B) Triangle AEH

C) Triangle CFG

D) Triangle BCH

E) Triangle BFG

F) Triangle DEG

Answer:

B) Triangle AEH

C) Triangle CFG

E) Triangle BFG

F) Triangle DEG

Step-by-step explanation:

Edge 2023

The reason for the statement "L || k, t is perpendicular to l at s" is that line L is parallel to line k, and line t is perpendicular to line l at the point of intersection s.

The reason for the statement "L || k, t is perpendicular to l at s" can be explained using basic geometric concepts:

Therefore, the reason for the statement "L || k, t is perpendicular to l at s" is that line L is parallel to line k, and line t is perpendicular to line l at the point of intersection s

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Answer:

f(x)=10-x/4

Step-by-step explanation:

this is the answer

Answer:

he runs for 39 min in 10 kilometres

Step-by-step explanation:

if he runs 10 kilometres

u add 4 10 times add if and u will find 39 min for 10 kilometres running

Answer:

1. y = 3/2z

Step-by-step explanation:

1. ,2y-3z + 3z =0 + 3z ,2y=3z, 2y/2 =3z/2=3/2z

Answer:

B

Step-by-step explanation:

The answer to the equation is \(x=2.2\)

First, you must subtract 0.33 on both sides.

\(-0.45x=-0.99\)

Then, you must divide -0.45 on both sides.

\(x=2.2\)

Your answer is \(x=2.2\)

A system of linear equations: y + 2x = -5 and 8x + 4y = -20  has infinitely many solutions.

The 3 possible solutions of a linear system are:

- Unique or one solution

- Infinite solutions

- No solution

If the linear equations are exactly (or can be transformed to exactly) the same equations, the solution is infinite.

The given linear system is:

y + 2x = -5           ....... (equation 1)

8x + 4y = -20     ..........(equation 2)

Rearrange equation 1 to:

2x + y = -5

Multiply both sides by 4:

8x + y4 = -20

Hence, equation 1 is equivalent to equation 2. Hence, the given linear system has infinitely many solutions.

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The money market account earns 8/4 = 2% interest per quarter.

In one year, there are 4 quarters.

so, the formula to calculate the balance after 8 years is:

A = P (1 + r/n)^(nt)

where A is the final balance, P is the principal (initial investment), r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years the money is invested for.

Substituting in the given values,

A = 1000 (1 + .02)^(4*8)

A = 1000 (1.02)^32

A = 1000 (1.8587)

A = 1858.7

So after 8 years, Ed will have earned $1858.7.

A  homogeneous linear differential equation with constant coefficients has the form a_

n y^{(n)} + a_{n-1} y^{(n-1)} + ... + a_1 y' + a_0 y = 0,

where a_n, a_{n-1}, etc. are all constants. The general solution of this equation is given by y = c_1 e^{\lambda_1 t} + c_2 e^{\lambda_2 t} + ... + c_n e^{\lambda_n t}, where c_1, c_2, etc. are constants and \lambda_1, \lambda_2, etc. are the roots of the characteristic equation a_n \lambda^n + a_{n-1} \lambda^{n-1} + ... + a_1 \lambda + a_0 = 0.

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Answer:

1) x= -2.5

2) x= -0.4

Step-by-step explanation:

1)

x=3x+5

-5.    -5

x-5=3x

-x.    -x

-5=2x

/2.  /2

-2.5=x

2)

2=5x+4

-4.    -4

-2=5x

/5. /5

-0.4=x

Hopes this helps please mark brainliest

Answer:

1) x = -5/2

2) x = 6/5

Step-by-step explanation:

x = 3x + 5

Subtract x from both sides

0 = 3x - x + 5

0 = 2x + 5

Subtract 5 from both sides

-5 = 2x

Divide 2 to both sides

-5/2 = x

2 = 5x - 4

Add 4 to both sides

2 + 4 = 5x

6 = 5x

Divide 5 to both sides

6/5 = x

\(\rule[225]{225}{2}\)

Answer:

12 books

Step-by-step explanation:

Lets set aside $25 for dinner first.

Amount left = $230 - $25 = $205

Number of books able to buy = amount left ÷ cost per book

= $205 ÷ $17

= 12.058 books

Of course, you cant buy .058 books , that wont make sense, so you take the highest possible WHOLE number, which in this case, is 12 books.

The distance between the given points is 13 units.

We have two coordinate points  A(8, -4) and B(3, 8).​

We have to determine the distance between these two points.

The distance between two points -

\(d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }\)

According to the question, we have -

Coordinates of 1st point -  A(8, -4)

Coordinates of 2nd point -  B(3, 8)

Using the distance formula given -

d = \(\sqrt{(3-8)^{2} + (8-(-4)^{2} }\)

d = \(\sqrt{(-5)\times (-5) + (12)\times (12)}\)

d = \(\sqrt{25 + 144}\)

d = \(\sqrt{169}\)

d = 13 units

Therefore, the distance between the given points is 13 units.

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The hydroxide-ion concentration or pOH of HNO₃ solution comes to be 8.02.

The pOH of a solution is the negative logarithm of the hydroxide-ion concentration.

or pOH = -log[OH⁻]

The hydroxide-ion concentration OH⁻ of HNO₃ solution = 9.5 * 10⁻⁹ million.

So, the pOH of the HNO₃ solution =-log[9.5* 10⁻⁹] = 8.02

Therefore, the hydroxide-ion concentration or pOH of HNO₃ solution comes to be 8.02.

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Answer:

8.02

Step-by-step explanation:

trust

Answer:

192m

Step-by-step explanation:

6m x 4m x 8m = 192m

The graph of the function x^2/9 - y^2/49 = 1 is graph (d)

From the question, we have the following parameters that can be used in our computation:

x^2/9 - y^2/49 = 1

The above equation is an hyperbola

An hyperbola that has its center at the origin is represented as

x^2/a^2 - y^2/b^2 = 1

Using the above as a guide, we have the following:

a^2 = 9

b^2 = 49

Evaluate

a = ±3

b = ±7

This means that the semi-major axis is a = 3 and the semi-minor axis is b = 7.

The graph with the above feature is graph (d)

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