What is the function of a buffer?

Answer:

The theoretical yield of sulfur trioxide is 88.0 Litres

Explanation:

The chemical reaction occurring between oxygen and sulfur dioxide is given in the chemical equation below :

2SO₂ + O₂ ----> 2SO₃

From the equation of reaction, 2 moles of sulfur dioxide reacts with 1 mole of oxygen to produce 2 moles of sulfur trioxide.

Volume of 1 mole of a gas at STP is 22.4 L

Number of moles of gas in 44.0 L = 44.0/22.4 moles

1 mole of oxygen reacts with 2 moles sulfur dioxide to produce 2 moles of sulfur trioxide;

44/22.4 moles of oxygen will react with excess sulfur dioxide to produce 2 × 44/22.4 moles of sulfur trioxide = 88/22.4 moles of sulfur trioxide

88/22.4 moles of sulfur trioxide will have a volume of 88/22.4 × 22.4 Litres = 88.0 Litres

Therefore, the theoretical yield of sulfur trioxide is 88.0 Litres

The selenate ion, SeO₃²⁻, is classified as a. polyatomic anion. Polyatomic ions are composed of two or more atoms covalently bonded together and carry a charge.

In the case of the selenate ion, it consists of one selenium (Se) atom and three oxygen (O) atoms bonded together, with an overall charge of -2. A cation refers to a positively charged ion, whereas an anion refers to a negatively charged ion. Since the selenate ion carries a negative charge, it is an anion.

Furthermore, it is not monoatomic because it consists of more than one atom. Thus, the correct classification for the SeO₃²⁻ ion is a polyatomic anion (option c).

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The solubility of caco3 (formula weight 100.1) is 0.0095 g in 1800 ml, The ksp is  8.6x10-8

Ksp is the solubility product constant, which is the equilibrium constant for a saturated solution of an ionic compound at a given temperature. To calculate the Ksp, we need to know the molar solubility of the compound.  The molar solubility of caco3 can be calculated from the given solubility, which is 0.0095 g in 1800 ml. To calculate molar solubility, we need to convert the solubility of caco3 into moles. 0.0095 g of caco3 is equal to 0.00094 moles.   Now, we can use the equation for Ksp, which is Ksp = [Ca2+][CO32-]. Substituting the molar solubility of caco3, we get Ksp = 0.00094 x 0.00094 = 8.6x10-8.

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Precipitation reactions are commonly employed in industry to remove specific substances from wastewater. Hence option C) is the correct answer.

Option c. remove some substances from wastewater. Precipitation reactions are commonly employed in industry to remove specific substances from wastewater. In these reactions, insoluble salts are formed when certain ions in the wastewater react with specific reagents or chemicals. The formed precipitate can then be separated from the solution, effectively removing the targeted substances. This process is particularly useful for removing heavy metals, such as lead, mercury, or cadmium, from wastewater. By introducing a precipitating agent that forms insoluble metal salts, the heavy metal ions can be converted into solid precipitates. These precipitates can be filtered or settled out, allowing for the separation and disposal of the heavy metal contaminants. Overall, precipitation reactions offer an effective method for the removal of certain substances, including heavy metals, from wastewater, helping to mitigate environmental pollution and safeguard water quality.

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Answer: Calcium

Hope this helps

There is more traffic between 8 and 9 in the morning because most people start work at 9. this would be a(n) hypothesis.

A hypothesis is a tested assertion about the relationship between two or more variables or a proposed justification for an observed phenomenon in a scientific context. It helps make a connection to the guiding idea and specific study topic.

It supports data processing and evaluates the study's validity and reliability. It provides a base or further proof to back up the study's validity.

A hypothesis can be categorised as being straightforward, complex, or direction-based.

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Answer:

If Carbon Dioxide levels go up then so does air temperature

Answer:

There are legal and ethical restrictions regarding human cloning.

Explanation:

Answer:

Scientists clone banana plants and not humans because there are legal and ethical restrictions regarding human cloning.

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Answer:

which parts electrical charges you are asking ??

Answer: A

Explanation:

Answer:

The answer is A

Explanation:

Answer:

D) Matter

Explanation:

The answer shows that at equilibrium, the curves are horizontal with a slope of 0, meaning that the concentrations of the reactants and products are not changing.

Even after equilibrium has been attained, the forward and reverse reactions still happen. However, for a reaction that is at equilibrium, there is no change in the relative concentrations of reactants and products because the reaction rates are the same.

The reverse reaction will accelerate as the advanced reaction slows until they are moving at the same speed. The equilibrium posture is this. The concentration of the reactant and product are equal but not always equal at equilibrium.

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Answer:

0.833 moles of Phosphorus

Explanation:

100 g C * \(\frac{1 mol C}{12g C}\) * \(\frac{1 mol P}{10 mol C}\) = 0.833 mol P

Absorbance is measured using a spectrophotometer or microplate reader, which is an instrument that shines light of a specified wavelength through a sample and measures the amount of light that the sample absorbs.

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Answer:

The law of heat conduction, also known as Fourier's law, states that the time rate of heat transfer through a material is proportional to the negative gradient in the temperature. As the temperature difference is bigger, the rate of temperature change will be bigger.

Explonation:

sorry if doesnt

help

Answer:

A. Almost all of the mass is concentrated in the nucleus.

Explanation:

Because when he shot the alpha particles towards the atoms, most passed through (which meant atom is mostly empty space), but some bounced back and such (which meant mass is concentrated in the nucleus.)

The reason they bounced is because alpha particles are postive and nucleus is positive as well, and we know positives don't attract, rather they repel thus they bounced.

If 1.50 g of H₂C₂O₄.2H₂O were heated to drive off the water of hydration, 1.071 g of anhydrous H₂C₂O₄ would remain.

The balanced chemical equation of reaction is :

           H₂C₂O₄.2H₂O  →  H₂C₂O₄ + 2H₂O

First calculate the molecular weight of hydrated H₂C₂O₄ -

Using the molecular masses of -

O = 16 g/mol, C = 12 g/mol, and H = 1 g/mol

Total mass of compound = 126 g/mol

Molecular mass of H₂C₂O₄ = 90 g/mol

and, molecular mass of water of hydration = 36 g/mol

The percentage of H₂C₂O₄ in H₂C₂O₄.2H₂O is -

% H₂C₂O₄ = 90 g/mol = 0.714 %

                    126 g/mol

To calculate remainingIf 1.50 g of H₂C₂O₄.2H₂O were heated to drive off the water of hydration, 1.071 g of anhydrous H₂C₂O₄ would remain.

The balanced chemical equation of reaction is :

           H₂C₂O₄.2H₂O  →  H₂C₂O₄ + 2H₂O

First calculate the molecular weight of hydrated H₂C₂O₄ -

Using the molecular masses of -

O = 16 g/mol, C = 12 g/mol, and H = 1 g/mol

Total mass of compound = 166 g/mol

Molecular mass of H₂C₂O₄ = 126 g/mol

and, molecular mass of water of hydration = 36 g/mol

% H₂C₂O₄ = 126 g/mol = 0.7590

                    166 g/mol

75.90 % of 1.50 g = 0.714

To calculate remaining amount of anhydrous H₂C₂O₄,

we take percentage of anhydrous H₂C₂O₄ with the mass of hydrous compound which is heated.

71.4% of 1.50 g = 1.071 g

Therefore,

The anhydrous H₂C₂O₄ remaining is 1.071 g.

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Explanation:

Difference between pulley and wheel and axle are:

pully = A pulley is a circular disc that has a groove around the circumference over which a rope or string can move. In the pulley, load is connected to one end of the rope and effort is applied on the other ends . The pulley that does not move up and down is called the fixed pulley.

Wheel and axle= Wheel and axle consists of two cylinders of different radii. The cylinder of large radius is called wheel and the cylinder radius is called axle . Both wheel and axle move together under the application of effort.

I have send you a photo of wheel and axle, pulley.

I hope it will help you so.

The mass of oxygen is 16 g

The mass of oxygen is 2.4 g

We know from the balanced reaction equation that;

\(CH_{4}\)+ 2\(O_{2}\) ---> \(CO_{2}\) + 2\(H_{2} O\)

Number of moles of\(CH_{4}\) = 4.06 g/16 g/mol

= 0.25 moles

If 1 mole of \(CH{4}\) reacts with 2 moles of\(O_{2}\)

0.25 moles of \(CH_{4}\) reacts with 0.25 * 2/1

= 0.5 moles

Mass of the oxygen = 0.5 moles * 32 g/mol

= 16 g

The balanced reaction equation is;

2S\(O_{3}\)(g)⇋2S\(O_{2}\)(g)+\(O_{2}\)(g)

Number of moles of sulfur trioxide = 12.3 g/80 g/mol

= 0.15 moles

If 2 moles of S\(O_{3}\) produces 1 mole of oxygen

0.15 moles ofS\(O_{3}\)will produce 0.15 * 1/2

= 0.075 moles

Mass of oxygen = 0.075 moles * 32 g/mol

= 2.4 g

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Explanation:

D=m÷v

D=146÷(3×4.5×7)

D=146÷94.5

D=1.54g/cm^3

The most penetrating kind of radiation that can be shielded with aluminum foil is beta particles.

Beta particles are high-energy electrons or positrons emitted during radioactive decay. They have greater penetrating power compared to alpha particles (helium nuclei) but less than gamma rays and high-energy photons.

Aluminum foil is effective at stopping or attenuating beta particles because it is relatively thin and has a high atomic number. As beta particles interact with matter, they undergo multiple scattering and ionization processes, losing energy and becoming increasingly attenuated.

On the other hand, gamma rays and high-energy photons have much higher penetrating power and require denser shielding materials such as lead or concrete to effectively attenuate them. Gamma rays are electromagnetic radiation, while high-energy photons refer to energetic X-rays or gamma rays. These forms of radiation can pass through aluminum foil relatively easily and require more substantial barriers for effective shielding.

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Answer:

uno

Explanation:

uno uno unooo no no Bruno capaso

Answer: 3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL

Answer:

B. The solubility of a gas in a liquid decreases with decreased pressure.

Explanation:

When the pressure is released by opening the soda container, the liquid cannot hold as much carbon dioxide, so the excess bubbles out of the solution. If the soda is left open, additional carbon dioxide will slowly escape into the air. Under warm conditions, the carbon dioxide leaves the solution faster

The chest electrode placed on the fifth intercostal space on the mid-clavicular line is known as the V4 electrode. V4 is part of the precordial electrodes used in a standard 12-lead electrocardiogram (ECG) to assess the electrical activity of the heart.

The placement of these electrodes is crucial for obtaining an accurate ECG, which helps healthcare professionals diagnose and monitor various cardiac conditions.
The V4 electrode is positioned on the left side of the chest in line with the middle of the clavicle (collarbone), at the level of the fifth intercostal space. To locate this space, one should palpate the ribcage and count down from the first rib until the fifth rib space is found. Proper electrode placement ensures that the ECG will accurately capture the electrical signals originating from the heart.
Other precordial electrodes, such as V1, V2, V3, V5, and V6, are also strategically placed on specific areas of the chest to obtain a comprehensive view of the heart's electrical activity. Collectively, the information from all 12 leads provides a detailed picture of the heart's functioning, assisting in the diagnosis of heart conditions and guiding treatment decisions.
In conclusion, the V4 electrode plays a vital role in electrocardiography, as its placement on the fifth intercostal space on the mid-clavicular line enables healthcare professionals to monitor the heart's electrical activity and make informed decisions about patient care.

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To solve this problem, let's use the definition for molarity:

Replacing the values of the problem:

Now, to find the mass, we multiply by the molecular weight of NaCl. (Which is about 58.44g/mol)

The answer is approximately 22.2g of NaCl

False. Infants do need omega-3 sources for their development, particularly for the growth and development of their brain and eyes. Omega-3 fatty acids are essential for healthy brain function and development in infants.

Breast milk is a rich source of omega-3 fatty acids, and it is recommended that mothers consume enough omega-3 fatty acids during pregnancy and breastfeeding to support their infant's development. Omega-3 fatty acids can also be found in some infant formulas. While omega-3 fatty acids are important for preventing cardiovascular disease in adults, they serve many other functions in the body, including supporting healthy brain development in infants.
In conclusion, it is false that infants don't need omega-3 sources. Omega-3 fatty acids are essential for the development of their brain and eyes. Mothers should ensure they consume enough omega-3 fatty acids during pregnancy and breastfeeding, and some infant formulas contain omega-3 fatty acids as well. While omega-3 fatty acids are also important for preventing cardiovascular disease in adults, they serve many other vital functions in the body.

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We are told that starch consists of glucose polymer, so we can assume that the caloric value of starch will be equal to the caloric value of glucose, that is, 3.9kcal/g.

Now to determine the kcal and kJ there were in the potato we must calculate the mass of starch present in that potato. We are told that it is 92% starch, therefore the mass of starch in the potato will be:

We have that in the potato there are 160.08 grams of starch. By multiplying it by the caloric value we will have the kcal that were in the potato, assuming that the rest of the ingredients do not contribute caloric value, or it is insignificant.

To calculate the kJ we must make the conversion using the relationship that 1 cal is equal to 4.184 joules:

In the potato, there were 624 kcal of energy or 2612kJ of energy.

Answer:

The mass of solid object is 20.52 g.

Explanation:

Given data:

Volume of water = 36.1mL

Volume of water with metal cylinder = 43.7 mL

density of metal cylinder = 2.70 g/mL

Mass of solid object  = ?

Solution:

First of all we will calculate the volume of solid object.

Volume of solid object = Volume of water with metal cylinder  - Volume of water

Volume of solid object =  43.7 mL - 36.1mL

Volume of solid object =7.6 mL

Density:

density = mass/ volume

2.70 g/mL = mass / 7.6 mL

mass =  2.70 g/mL × 7.6 mL

mass = 20.52 g

The mass of solid object is 20.52 g.